A ball A of mass 0.5 kg moving with a Velacity of 10 m/s a head on Collision with a ball B of mass 2kg moving with a Velocity of 1ms in the oppoite direction. If A and B stick together after Collision, Calculate the Common Velocity in the direction of A

Answer:

Their common velocity after the collision will be 5.5m/s

Explanation:

look at the attachment above ☝️

Answer:

A

Explanation:

As you go deeper, the pressure increases because the water is going farther away from the air and atmosphere

The distance from the rounded tip of the plate to the center of mass is 1.87 m.

The center of mass is a point inside or outside the mass where all of the mass is concentrated.

The y-coordinate of the centroid is given by the ratio of two definite integrals;

Yc = ∫ydm/∫dm,

where dm is a density function

For the uniform plate, δ does not change with position in the plate.

Yc = ∫yδdA/∫δdA

Yc = ∫ydA/∫dA.

dA is a horizontal slice of the plate with dimensions xdy.

Solving the parabola for x,

y = 0.5x²

x = ± √(y/0.50), where the negative value corresponds to the left half of the parabola and the positive to the right half.

dA = (√(y/0.50)

     = √(y/0.50))dy

     = 2(√(y/0.50))dy

The limits of integration are from zero to 1.870, the top of the plate.

∫ydA = ∫2y√(y/0.50)dy = 7.232 m³

∫dA = ∫2√(y/0.50)dy = 3.868 m²

∫ydA/∫dA =  7.232 m³/3.868 m²

∫ydA/∫dA =  1.869700 m

∫ydA/∫dA =   1.87 m

Thus, the distance from the rounded tip of the plate to the center of mass is 1.87 m.

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Answer:

i think the answer is 20.......

Wave I stands for a wave with an equal frequency as wave II. Option c is correct.

Frequency is defined as the number of repititions of a wave occurring waves in 1 second. Its unit is Hz.

Frequency is given by the formula as,

[tex]\rm f = \frac{1}{t}[/tex]

Where,

f is the frequency

t is the period of the wave

From the digrame it is observed that both the wave has the same period. So that they will have the same frequency.

Hence option c is correct.

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Greek terms psyche, which means "soul" or "mind," and logos, which means "the study of," are combined to form the english word psychology. The assertion is true.

Psychology is the name given to the scientific study of the mind and behavior. Psychologists are actively interested in researching and comprehending how the mind, the brain, and behavior work.

Psychology is a combination of the Greek words psyche, which means “soul” or “mind,” and logos, which means “the study of.”The given statement is corect.

Hence the best answer from the choices provided will be true.

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The is organic compound with the correct chemical formula C4H9O2.

A model is a representation of reality. A model serves the purpose of prediction as well as explanation.

Looking at the model of the molecule we can see that it is the organic compound with the correct chemical formula C4H9O2. The molecule is shown in the image attached to this answer.

Missing parts:

There are several ways to model a compound. One type of model is shown.

What is the chemical formula for the molecule represented by the model?

CHO

C4H9O2

C4H8O

C3H8O2

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Answer:

Discrimination is the worst thing in the world you can't even do a thing so you will do such a physical thing or do a mathematics problem ok done it's ok

The answer to this question is Initial velocity of plane will be 34236 m/s and 92437.2 Km is the distance travelled by it.

Three equation of motion are:-

Where v is final velocity, u in initial velocity, s is the displacement by the object, a is the acceleration and t denotes the time.

In question we have given deceleration as 6.34 m/s² and time as 1.5 hour which is equal to 5400 seconds.

Applying equation 1 to find the initial speed of plane

v = u + at

0 = u + (-6.34 × 5400)   {v=0 as plane will stop after 5400 sec}

u =  6.34 × 5400

u = 34236 m/s

Initial velocity of plane is 34236 m/s

Applying equation 2 to find the displacement of plane in that time period

s = ut + (1/2)at²

s = ( 34236 × 5400 )  - ( (1/2) × 6.34 × 5400² )

s = 5400 × ( 34236 - ((1/2) × 6.34 × 5400) )

s = 5400 × ( 34236 - 17118 )

s = 5400 × 17118 metres

s = 5.4 × 17118 Km

s = 92437.2 Km

Distance travelled by plane is 92437.2 Km

So, the initial velocity of plane will be 34236 m/s and the displacement of plane in that time period will be 92437.2 Km.

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The merits of and problems with the manager’s statement are explained below.

Extension of the social identity of the individual in groups such as working in company or studying in college is called as the stereotyping in organizations.

Merits of Stereotypes in organizations:

Demerits of Stereotypes:

Thus, the merits and demerits of stereotypes in organizations are explained above.

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Based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

From the standpoint of  brain lateralization, differences do exist such as based on experience such as handedness or specific skills such as playing a guitar.

Note that Left-handers are said to have reduced or little lateralized brains, which tells us that the two halves of the brain are little different than as seen in the right-handers.

Therefore, I can say that based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

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Answer:

Explanation:

Hope I give all correct answer please mark as brainlest answer

The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.

Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h

We have to find the magnitude of the angular momentum

Let,

ρ = Density of air = 1.29 kg/m^3

v = Speed of wind = 73.0 mi/h = 0.032 km/s

M = angular momentum of air

Let the volume of air be 1 m^3

Mass = Volume x ρ = 1 x 1.29 = 1.29 kg

Momentum = M = mass x velocity

Momentum = 1.29 x 0.0032

Momentum = 4.128 x 10^(-3) kg·m^2/s

Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

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The rod is stretched due to the force of gravitational attraction.

The magnitude of the deformation force on the rod is  -GMm×((1/r² + 1/(L+r)²)

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given are two small (green) objects, each of mass m, are separated by a solid, massless rod of length L. They are located so that one of the objects is located at a distance of r away from the center of a uniform spherical planet with mass M.  Assume that m is very small so that you can ignore the gravitational force between the two small (green) objects.

Let the mass closer to the planet is A and the other is B

FA = Force on planet A = -GMm/r²

FB = Force on planet B = -GMm/(L+r)²

Net Force on the rod is given by the addition of the individual forces.

Fnet= FA + FB = -GMm/r² -GMm/(L+r)²

Fnet = -GMm×((1/r² + 1/(L+r)²)

Thus,  the magnitude of the deformation force on the rod is derived above.

A experience more force than B, so A will stretch out from B. Hence the force is stretching the rod.

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The impulse given to the ball by the floor is 0.2865 kg.m/s.

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

Impulse F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

A ball of mass 500g is dropped from a height 1.5m . It rebounds the floor and reached the height 1.2m.

The initial velocity u = √2x 9.81 x 1.5 = 5.425 m/s

The final velocity v = √2x 9.81 x 1.2 = 4.852 m/s

Substitute the values into the expression, we get

Impulse = m(v- u)

Impulse=0.5 x (4.852- 5.425 )

Impulse = - 0.2865 kg.m/s

Thus, the magnitude of impulse given to the ball by the floor is 0.2865 kg.m/s.

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The distance of the Image will be -33.75 cm

A concave mirror has an inward-curving reflecting surface that faces away from the light source. Unlike convex mirrors, a concave mirror's image forms a variety of images based on the object's proximity to the mirror.

Given that, an object placed 27 cm from a concave mirror having the focal length of 15 cm

We have to find distance of the Image

Using Mirror Formula:

1/f = 1/v + 1/u

Where,

f = focal length

v =  Image distance from the mirror

u = object distance from the mirror (concave)

Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.

1/(-15) = 1/v + 1/(-27)

1/(-15) = 1/v - (1/27)

1/v = -0.029

v = -33.75 cm

Therefore the distance of the Image will be -33.75 cm

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Answer:

12.9m/s^2

Explanation:

As, a=(v^2)/r

=(58^3)/260

=12.9

The mass and tension due to the system are as follows:

Tension is a type of pulling force due transmitted by means of a string or cable.

a) The mass of the child and scale = 104/9.81 = 10.6 kg

b) The tension T, in the cord attaching the child to the scale = scale reading = 104N

c) The tension T', in the cord attaching the scale to the ceiling = scale reading + weight of scale

T' = 104 + (0.5 * 9.81)

T' = 108.9 N

d) The sketch is attached in the picture

In conclusion, the tension is force exerted on the cord due to the weight of the scale and the baby.

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So, the complete sentence is If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.

When the mass of the sun is larger, Earth moves around the sun at a faster pace and When the mass of the sun is smaller, Earth moves around the sun at a slower pace.

When Earth is closer to the sun, its orbit becomes faster and When Earth is farther from the sun, its orbit becomes slower.

When Earth is closer to the sun, there will be a hotter climate. A little movement that takes one closer to the sun could lead to a huge impact, as the sun is very hot.

So, it can be concluded that If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.

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10¹¹ is the approximate number of atoms in a bacterium.

The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu).

Given,

Mass of a bacterium atom = 10⁻¹⁵ kg.

Mass of a hydrogen atom  = 10⁻²⁷ kg.

From the above observation ,

The average mass of an atom of the bacterium is ten times the mass of a hydrogen atom.

Atomic mass 1 bacterium atom = 10 x mass of hydrogen atom

                                                  = 10 x 10⁻²⁷ kg.

                                                  = 10⁻²⁶ kg.

Thus,

The number of atoms in a bacterium

=  [tex]\frac{Total mass}{Atomicmass of 1 bacterium}[/tex]

= [tex]\frac{10^{-15} }{10^{-26} }[/tex]

=  [tex]10^{11}[/tex]

The approximate number of atoms in a bacterium  is [tex]10^{11}[/tex].

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Answer:

r= 1.09×10^-4

Explanation:

Given

V=speed=4.0×10^5 m/s

B= magnetic field= 0.040 T

©=angle= 35°

m= mass of electron= 9.11×10^-31

q= charge of electron= 1.60×10^-19

solution

qv×B= mv²/r

qvBsin©=mv²/r

qBsin©=mv/r

r=mv/qBsin©

r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)

r= 1.09×10^-4 m

a) r = 1.09 * [tex]10^{-4}[/tex] m

b) Distance travelled : 6.845 *  [tex]10^{-4}[/tex] m    

An electron is a  stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

given

charge of electron : 1.6 * [tex]10^{-19}[/tex] C

mass of electron = 9.11 * [tex]10^{-31}[/tex] kg

v = 4.0 x 10 m/s

B =  0.040 T

theta = 35 degrees

since ,

force in magnetic field on electron = centripetal force

a) q(v*B) = m [tex]v^{2}[/tex] / r

q v B sin(theta) =  m [tex]v^{2}[/tex] / r

r =m v /q B sin(theta)

r =  9.11 * [tex]10^{-31}[/tex] * 4.0 x [tex]10^{5}[/tex]/ 1.6 * [tex]10^{-19}[/tex] sin (35)

r = 1.09 * [tex]10^{-4}[/tex] m

b)  far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr

 = 2 * 3.14 * 1.09 * [tex]10^{-4}[/tex] m  = 6.845 *  [tex]10^{-4}[/tex] m  

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C. The Densities are equal.

Density is mass per unit volume or mass of a unit volume of a material substance.

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

[tex]V_{1} = 3V_{2} , m_{2} = \frac{1}{3} (m_{1} ) \\ \\= m_{1} = 3m_{2}[/tex]

Therefore,

[tex]\frac{D_{1} }{D_{2} } = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{3m_{2} }{3V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 1[/tex]

Hence, D1 = D2

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Answer:

the 1 gram wasp

Explanation:

To start off with this problem, write down every piece of information and do neccessary conversions.

mass of bee = 2 grams = 0.002 kg

speed of bee = 1 m/s

mass of wasp = 1 gram = 0.001 kg

speed of wasp = 2 m/s

now, we will use the kinetic energy formula and compare the answers

KE BEE = 0.5 (0.002 kg)(1 m/s)^2 = 0.001 Joules

KE WASP = 0.5(0.001 kg)(2 m/s)^2 = 0.002 Joules

0.002 J > 0.001 J

a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b.21,835 J work, in joules, is done by the rope on the sled this distance.

c. 23,170 J   the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.

The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

a. How much work is done by friction as the sled moves 28m along the hill?

ans. We use the formula:

friction work = -µ.mg.dcosθ

  = -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60

= -1337.3 J

-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b. How much work is done by the rope on the sled in this distance?

We use the formula:

Rope work = -m.g.d(sinθ - µcosθ)

rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)

                     = 26,754 (0.816)

                     = 21,835 J

21,835 J work, in joules, is done by the rope on the sled this distance.

c.  What is the work done by the gravitational force on the sled?

By using  the formula:

Gravity work = mgdsinθ

                    = 97.5 kg * 9.8 m/s² * 28 m * sin 60

                    = 23,170 J

23,170 J   the work, in joules done by the gravitational force on the sled .

D. What is the total work done?

By adding all the values

work done =  -1337.3 + 21,835 + 23,170

                 = 43,670 J

The net work done on the sled, in joules is 43,670 J.

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Option C. The measurement with the most significant number is 6.600 cm.

Significant numbers are numbers that have significance or meaning and give more precise details about the value of the entire numbers.

Thus, the measurement with the most significant number is 6.600 cm.

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Answer:

He has a hangover.

Explanation:

Just something I know.

Answer:

6800

Explanation:

100 x 0.68=6800

Answer: 68

Explanation:

Answer:horse

Explanation:

The speed of the first car just before the collision is 26.73 km/h.

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.

m₁u₁ +m₂u₂ =(m₁ +m₂) v

Given a 808 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 632 kg. The two cars lock up and slide together with a speed of 15.0 km/h.

Second car is parked, so its velocity will be zero.

808 x u +632 x 0 = (808 +632 ) x 15

u  = 26.73 km/h

Thus, the speed of the first car just before the collision is 26.73 km/h

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