a ball is projected with initial velocity 40m/s at angle of 27° from a building 60meters high.find total time the ball is in the air​

Answer:

T=80

Explanation:

soln

v=0.25ms

d=20m

t=?

therefore; velocity=distance/time taken

equating the valuables we have

0.25=20/t

making t the subject formula we have

t=20/0.25 => 80s

The magnitude and direction of the hiker's resultant displacement is 42.7 km, 64.6° north of east.

To find the magnitude and direction of the hiker's resultant displacement, we can use vector addition.

First, we need to convert the given magnitudes and directions into x and y components. We can use trigonometry to do this:

x component of the first displacement = 27.0 km * cos(35°) = 21.5 km

y component of the first displacement = 27.0 km * sin(35°) = 15.5 km

x component of the second displacement = 41.0 km * cos(65°) = 17.6 km

y component of the second displacement = 41.0 km * sin(65°) = 30.6 km

Now we can add the x and y components of each displacement to find the x and y components of the resultant displacement:

x component of the resultant displacement = 21.5 km + 17.6 km = 39.1 km

y component of the resultant displacement = 15.5 km + 30.6 km = 46.1 km

To find the magnitude of the resultant displacement, we can use the Pythagorean theorem:

magnitude of the resultant displacement = sqrt(39.1 km^2 + 46.1 km^2) = sqrt(1820.81 km^2) = 42.7 km

Finally, we can use the arctangent function to find the direction of the displacement:

direction = arctan(46.1 km / 39.1 km) = 64.6° north of east.

So the magnitude and direction of the hiker's resultant displacement is 42.7 km, 64.6° north of east.

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To convert 26 miles and 385 yards to kilometers, we first need to convert miles and yards to the same unit.

1 mile = 1760 yards

26 miles = 26 x 1760 = 45600 yards

Then add the yards of the distance, so the total distance in yards is 45600+385 = 45985 yards

Now we can convert yards to kilometers.

1 yard = 0.9144 meters

45985 yards = 45985 x 0.9144 = 42.195 kilometers

So 26 miles and 385 yards is approximately 42.195 kilometers.

At a mass that is 2 times the current earth and a radius 5 times its value, your weight will be 52.8 N.

In general, we can assume a gravitational force of the following magnitude for any planet or mass:

[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

where G = 6.67 x 10⁻¹¹m³/kgs², a universal gravitational constant.

m = masses of objects

r = radius of objects.

Given that W = 660 N

m₁ = 2Me, new mass of earth

r = 5re, new radius of earth

Then [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

Since [tex]F = \frac{GM m}{r^{2} }[/tex]

Substituting both new mass and radius;

[tex]F = \frac{G(2M_{E}) m}{(5r_{E})^{2}}[/tex]

[tex]F = \frac{2}{25} \frac{GM_{E} m}{r^{2}_{E}}[/tex]

Using the equation that  weight is [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

[tex]F = \frac{2}{25}(660 N)[/tex] = 0.08 x 660 N

F = 52.8 N

Since the earth is 5 times its radius and twice its mass a weight of 650N will become 52.8 N.

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Answer:

d. 16 kg-m/s

Explanation:

The new momentum of the swimming fish after eating the stationary fish can be calculated by adding the momentum of the initial swimming fish and the momentum of the stationary fish. Since momentum is a vector quantity, the direction of the momentum is the same as the direction of motion of the fish. If the fish continues to swim with the same velocity after eating the stationary fish, then the new momentum is the sum of the initial momentum of the swimming fish and the momentum of the stationary fish.

Initial momentum of swimming fish = 8 kg-m/s

Momentum of stationary fish = 2 kg * 0 m/s = 0 kg-m/s

New momentum = Initial momentum of swimming fish + Momentum of stationary fish = 8 kg-m/s + 0 kg-m/s = 8 kg-m/s + 2 kg-m/s = 10 kg-m/s.

So, the correct answer is (d) 16 kg-m/s.

Answer:

C

Explanation:

Using law of conservation of momentum of the system

Momentum before = momentum after

         8 kg m/s       = 8 kg m/s

The second fish has zero momentum, so after eating it the system still has momentum of 8 kg m/s

The displacement at which the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm is 1.5cm.

The amplitude of simple harmonic motion affects the ratio of kinetic to potential energy at a specific displacement in the following way: as the amplitude increases, the ratio of kinetic to potential energy decreases. This is because the amplitude represents the maximum displacement from the equilibrium position, and as the amplitude increases, the potential energy of the particle increases, while the kinetic energy remains constant. Therefore, at a specific displacement, a particle with a larger amplitude will have a greater proportion of its energy in the form of potential energy, while a particle with a smaller amplitude will have a greater proportion of its energy in the form of kinetic energy.

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The amount of work the engine can do in 1.0 hour, given that the engine generates 56 MegaWatts is 2016×10⁸ Joules

Work is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = force (F) × distance (d)

Power is defined as the rate at which work is done:

Power = Work / time

Using the power-work relationship formula above, we can detertmine the work the engine will do in 1.0 hour as follow:

Power = Work / time

Cross multiply

Work = Power × time

Work = 56×10⁶ × 3600

Work = 2016×10⁸ Joules

Therefore, we can conclude from the above calculation that the work the engine will do is 2016×10⁸ Joules

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If the crane can carry a maximum weight of 768 N, the maximum torque it can generate is 2383.4 N

The axis of rotation is the point at which the item rotates, and torque is the twisting force that causes rotation. Due to the fact that it causes an object to rotate along an axis, torque is a rotating force.

The perpendicular component of the force multiplied by the distance is torque.

T = F _|_ T

Part One

T = (768 N cos 13.9°) (16.0 m)

T = 10,368 Nm

Part Two

10368 Nm = (F cos 27.0°) (16.0 m)

F = 2383.4 N

Hence, maximum torque can the crane with-stand if the maximum load the crane can handle is 768 N is 2383.4 N

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( 1) The net gravitational force between the 74.8 kg mass is  8.09 x 10⁻⁵ N.

( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.

The net gravitational force acting on the middle mass is calculated by applying Newton's law of universal gravitation as shown below.

F = ( GmM ) / ( R² )

where;

The force between the first mass and the middle mass is calculated as;

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )

F' = 1.8 x 10⁻⁵ N

The force between the third mass and the middle mass is calculated as;

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )

F'' = 6.29 x 10⁻⁵ N

The net gravitational force on the middle mass;

F (net)  = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N

F ( net ) = 8.09 x 10⁻⁵ N

Let the distance of zero net force from the 141 kg mass = d.

then the distance from the 494 kg mass = 0.396 m - d

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )

F' = 0.704 x 10⁻⁶ / d²

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²

F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²

for zero net force, the two forces must be equal

0.704 x 10⁻⁶ / d²  = 2.47 x 10⁻⁶ / ( 0.396 - d )²

0.704 (0.396 - d )² = 2.47d²

(0.396 - d )²  = ( 2.47d² ) / ( 0.704 )

(0.396 - d )²  = 3.51d²

0.396 - d = √ ( 3.51d² )

0.396 - d = 1.87d

1.87d + d = 0.396

d (1.87 + 1) = 0.396

d (2.87) = 0.396

d = 0.396 / 2.87

d = 0.138 m

The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m

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Answer:

I need this message as well so please ket me know when you have it

The coefficient of  static friction between the tires and the road is 1.987.

Radius of the track, r =  516 m, Tangential Acceleration =  3.89 m/s^2 and Speed,v =  32.8 m/s

The radial Acceleration is given by, Now the total acceleration is The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of  static friction is, From (1) and (2), Substituting the values, we get friction is 1.987.

Therefore, The coefficient of  static friction between the tires and the road is 1.987.

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The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.

This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.

The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.

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Several vectors in the x-y plane are shown in the figure with their tails at the origin of the coordinate system and with a label at their heads.The value of M = (P+Q) is

3.65 meters

Generally, To calculate the magnitude of the vector M = P + Q, we need to use the Pythagorean theorem.

M = P + Q

M= (2.80i + 2.30j) + (-3.90i + 1.20j)

M= (-1.10i + 3.50j)

The magnitude of the vector M is the square root of the sum of the squares of the x and y components of the vector.

|M| = √((-1.10)^2 + (3.50)^2)

= √(1.21 + 12.25)

= √13.46

≈ 3.65 meters

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Answer:

1.5 minutes

Explanation:

To find out how long it will take to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle, we can use the equation:

Q = mcΔT

Where Q is the heat energy added, m is the mass of the water, c is the specific heat capacity of water and ΔT is the change in temperature.

The heat energy added to the water can be calculated as:

Q = (5 kg) x (400 J/kg·K) x (88°C - 28°C) = (5 kg) x (400 J/kg·K) x (60°C) = 120000 J

The power of the electric kettle can be calculated using the formula:

P=VI

where P is the power, V is the voltage and I is the current,

P = (220 V) x (6 A)

= 1320 W

Now we can calculate the time it takes to heat the water by dividing the heat energy added by the power:

time = Q/P = 120000 J / 1320 W

= 90.909 seconds or 1.5 minutes

It will take 1.5 minutes to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle taking 6 amperes from a 220 volt supply.

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Answer:

Relative permittivity describes the ability to polarize a material subjected to an electrical field.

Explanation:

This polarization originates from a number of sources:

- electron cloud displaced relative to nucleus

- relative displacement of charged ions

- alignment of dipoles in electric field

- movement of charge carriers trapped by interfaces in heterogeneous systems

- movement of ionic charges

In simple terms, relative permittivity tells us how well a material can hold an electric charge. A material with a high relative permittivity can hold more electric charge than a material with a low relative permittivity.

Answer:

Substance       ΔH (kJ/g)

Coal               -40.23

Hydrogen           -242.82

Methanol           -252.45

Octane               -43.99

Propane             -214.46

Explanation:

Methanol made the worst fuel because it has the lowest ΔH value of -252.45 kJ/g, which means that it releases the lowest amount of energy when used as a fuel. The other substances have higher ΔH values, so they produce more heat energy when burned.

Answer:

as far as I know they use chemistry to build pyramids block with reaction that why pyramids still exists

Answer: I hope this answer your question

Explanation:

The Egyptians were known in the ancient world as experts in many applied chemistry fields such as metallurgy, wine and beer making, glass making, paper manufacture, paint pigments, dyes, cosmetics, perfumes, and pharmaceuticals.Egyptians performed tasks that ranged from metallurgy to the production of dyes and pottery.They developed ways to measure time and distances , and applied their knowledge to monumental architecture.Used to build structures, manage the food supply and compute the flood levels of the Nile, math was vital to everyday life in Ancient Egypt. A remnant of their impressively sophisticated mathematical system, the Rhind Papyrus illustrates how Egyptians approached geometry, arithmetic and algebra.

Acceleration is the rate of change of velocity. It can be calculated using the formula:

a = (vf - vi) / t

Given:

vi = 25 m/s (initial velocity)

vf = 10 m/s (final velocity)

t = 3 s (time interval)

a = (vf - vi) / t = (10 m/s - 25 m/s) / 3 s = -15 m/s^2

The acceleration of the roller coaster is -15 m/s^2.

Negative acceleration indicates that the roller coaster is slowing down. This means that the roller coaster is losing speed as it reaches the top of the hill. The roller coaster is decelerating (negative acceleration) while it climbs the hill, so that it can move with a lower velocity at the top of the hill.

The mountain slope is 585.0 W multiplied by 62.25 min, which is 36,378.75 joules.

Slope is a measure of the steepness of a line. It is calculated by finding the ratio of the vertical change to the horizontal change between any two points on a line. Slope is represented by the letter m and is calculated by the equation m= (y2-y1)/(x2-x1). If the line is going up from left to right, the slope is positive. If the line is going down from left to right, the slope is negative. Slope is an important concept in mathematics, especially in calculus and linear algebra. It is used to find the rate of change between two points, as well as to determine the equation of a line.

The amount of work done is equal to the power developed multiplied by the time elapsed. Therefore, the work done by Reginald Esuke during his descent down the mountain slope is 585.0 W multiplied by 62.25 min, which is 36,378.75 joules.

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Answer:

Light waves do not need a medium in which to travel but sound waves do. Explain that unlike sound, light waves travel fastest through a vacuum and air, and slower through other materials such as glass or water.

Explanation:

Light travels in a straight line as a wave. It does not require any medium or material to travel like sound waves which means it can travel in vacuum.The speed of the light  from the special theory of relativity is a constant value of 38x10^8m/second

Answer:

Option a. The baton's center of mass is closer to the larger sphere, making the lever arm distance between your hand and the center of mass longer in option a than in option b. The longer lever arm distance gives you finer control.

Answer:

Explanation:

bxvbrzfbd

The electric field strength in volts per meter is 380 V. Option D is the correct answer.

This refers to the physical field that encloses electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It can also be called the physical field for a system of charged particles or ( E-field).

The electric field strength (E) can be calculated using the  b the formula:

E = V / d,

where,

V = the potential difference (in volts)

d = the distance (in meters) between the plates.

Calculating the electric:

V = 15.0 V

d = 0.04 m (4.0 cm converted to meters).

Hence,

E = 15.0 V

      0.04 m

= 375 V/m.

E ≈ 380 V

Hence The electric field strength (E) is 380 V.

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Answer:

Explanation:

______?

Net forces always result in an acceleration. Newton's Second Law of Motion states that a net force (the sum of all forces acting on an object) will cause an object to accelerate in the same direction as the net force. The acceleration is proportional to the magnitude of the net force and inversely proportional to the mass of the object.

Answer:

A net force always result in a acceleration

The car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve

The maximum speed at which a car can take a curved road without skidding outward is given by the formula:

v = √(g * r * (cos(theta) + (mu * sin(theta))/mu_s))

where:

v = velocity of the car

g = acceleration due to gravity (9.8 m/s^2)

r = radius of curvature of the road (36 m)

theta = angle of banking of the road (25 degrees)

mu = coefficient of friction between the tires and the road (0.87)

mu_s = coefficient of static friction between the tires and the road (0.87)

So the maximum speed at which the car can take this curve without skidding is:

v = √(9.8 * 36 * (cos(25) + (0.87 * sin(25))/0.87))

v = √(9.8 * 36 * (0.9063 + 0.4696))

v = √(9.8 * 36 * 1.376)

v = √(352.48)

v = 18.8 m/s

Therefore, the car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve.

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The momentum of the ball is

(-0.18, -0.40, 0.20)m

Generally, The momentum principle, also known as Newton's second law of motion, states that the rate of change of momentum of an object is equal to the force applied to it. Mathematically, this can be expressed as:

F = d(mv)/dt

where

To determine the position of the ball 0.1 seconds later, we need to know the force acting on the ball due to the elastic band. This force is given by Hooke's Law, which states that the force acting on an object due to a spring is equal to the spring constant (k) multiplied by the displacement of the spring from its relaxed position. In this case, the spring constant is 0.9 N/m, and the displacement is the difference in length between the relaxed length (0.3 m) and the current length of the elastic band.

We know that the ball is at location (-0.2, -0.61, 0)m relative to the point where the elastic band is attached to the paddle. We can find the length of the elastic band by using the distance formula:

√((x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2 ) = √((-0.2 - 0)^2 + (-0.61 - 0)^2 + (0 - 0)^2 )

= √(0.04 + 0.3721 + 0)

= √0.4121

= 0.63874m

The displacement of the spring is the relaxed length (0.3 m) minus the current length of the elastic band (0.63874 m), which is -0.33874 m. The force acting on the ball due to the elastic band is

-0.9 * -0.33874 = 0.30486 N.

We can use the force to find the acceleration of the ball using Newton's second law,

F = ma.

Since the mass of the ball is 0.015 kg, the acceleration of the ball is

0.30486 N / 0.015 kg = 20.324 m/s^2

We can use this acceleration to find the final velocity of the ball using the equation vf = vi + at.

Since the initial velocity of the ball is

(-0.02, -0.01, -0.02) kg-m/s, the final velocity of the ball is

(-0.02, -0.01, -0.02) + (20.324, 20.324, 20.324) * 0.1 s = (-0.02, -0.01, -0.02) + (2.0324, 2.0324, 2.0324)

= (2.0124, 2.0224, 2.0124) m/s

The final position of the ball can be found using the equation

xf = xi + vt.

The initial position of the ball is (-0.2, -0.61, 0)m and the final velocity is (2.0124, 2.0224, 2.0124) m/s, so the final position of the ball after 0.1 s is

(-0.2, -0.61, 0) + (2.0124, 2.0224, 2.0124) * 0.1 s

= (-0.2, -0.61, 0) + (0.20124, 0.20224, 0.20124)

= (-0.18, -0.40, 0.20)m

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Answer:

1.98×1020 N 1.98 × 10 20 N

Explanation:

The gravitational force between the Earth and the Moon is 1.98×1020 N 1.98 × 10 20 N.

Answer:

Explanation:

(a) Q=ap^n

Function of p and q:

p = q^(1/n)

(b) Q^m=ap^n

Function of p and q:

p = (q^(1/m))^(1/n)