a ball of mass m is dropped from rest at a height h and collides elastically with the floor, rebounding to its original height. what is the magnitude of the net impulse on the ball during the collision with the floor? (a) zero (b) mgh
(c) m2gh
(d) m4gh
(e) m8gh

Answers

Answer 1


During an elastic collision, the total momentum of the system is conserved. In this case, the ball is dropped from rest, so its initial momentum is zero. When it collides with the floor, the momentum of the ball is transferred to the floor momentarily, before the ball rebounds back up.

Since the collision is elastic, the ball rebounds to its original height, which means that its final momentum is also zero. Therefore, the net change in momentum of the ball is equal to its initial momentum, which is zero.
According to the impulse-momentum theorem, the net impulse on an object is equal to the change in its momentum. Since the ball's net change in momentum is zero, the magnitude of the net impulse on the ball during the collision with the floor is also zero.
Therefore, options (c), (d), and (e) can be eliminated. Option (a) is incorrect since the ball does experience a force during the collision, even though the net impulse is zero. The correct answer is option (b) mgh, which represents the potential energy of the ball when it was dropped from height h.

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Answer 2

Option (b) mgh. The magnitude of the net impulse on the ball during the collision with the floor can be found using the principle of conservation of energy. Since the collision is elastic, the total mechanical energy of the ball is conserved before and after the collision. Initially, the ball has potential energy mgh and zero kinetic energy.

After colliding with the floor and rebounding to its original height, the ball has zero potential energy and kinetic energy equal to mgh. Thus, the change in kinetic energy of the ball is mgh - 0 = mgh. The net impulse on the ball is equal to the change in momentum, which is mgh/2, since the velocity changes direction during the collision. Therefore, the answer is (b) mgh.

The correct answer is (e) m8gh. When the ball of mass m drops from height h, it gains kinetic energy (KE) before the collision, KE = mgh. During the elastic collision, the ball's velocity changes direction, effectively doubling its change in momentum. The impulse-momentum theorem states that impulse (J) equals the change in momentum (∆p), so J = ∆p. Since the ball rebounds to its original height, the velocity after collision has the same magnitude but opposite direction. Therefore, ∆p = 2mv, where v = √(2gh). So, J = 2m√(2gh) = m8gh.

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Related Questions

.Which has the greater momentum, a heavy truck at rest or a moving roller skate?
Select one:
a. Cannot tell from the information given
b. the heavy truck
c. the roller skate
d. The momenta are equal
e. none of above

Answers

The roller skate has greater momentum than the heavy truck at rest. Momentum is equal to mass times velocity, and since the roller skate is in motion, it has a non-zero velocity. The heavy truck at rest has zero velocity, so its momentum is also zero. The correct option is C.


Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. In other words, momentum is a measure of how hard it is to stop an object from moving. The greater an object's momentum, the harder it is to stop. Momentum is conserved in a closed system, meaning that the total momentum of all objects in the system remains constant.

To determine which object has greater momentum, we need to calculate the momentum of both the heavy truck at rest and the moving roller skate. The heavy truck has a large mass, but its velocity is zero since it is at rest. Therefore, its momentum is also zero. The roller skate, on the other hand, has a smaller mass but is in motion. Even though its velocity may be relatively low compared to the speed of the truck, it still has a non-zero value. As a result, the roller skate has a greater momentum than the heavy truck.

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an fm radio station broadcasts with a power of 10 kw at a frequency of 101 mhz. a) how many photons does the antenna emit each second?

Answers

The FM radio station emits 1.51 x 10^19 photons per second. To determine the number of photons emitted by the antenna of the FM radio station each second, we need to use the equation that relates energy, frequency, and the number of photons.

The equation is E = hf, where E is energy, h is Planck's constant, and f is frequency.

We can rearrange the equation to solve for the number of photons: N = E/hf.

We know that the power of the FM radio station is 10 kW, which means it emits 10,000 joules of energy per second. We also know that the frequency is 101 MHz, or 101 x 10^6 Hz. Planck's constant is 6.626 x 10^-34 joule-seconds.

Plugging in these values, we get:

N = (10,000 J/s)/(6.626 x 10^-34 J·s x 101 x 10^6 Hz)
N = 1.51 x 10^19 photons/s

Therefore, the FM radio station emits 1.51 x 10^19 photons per second.


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two identical rooms in a house are connected by an open doorway. the temperatures in the two rooms are maintained at different values. which room contains more air? hint: you can make a reasonable assumption regarding the air.

Answers

Answer:

The colder room will contain more air.

Explanation:

Assuming that there are no other sources of heating or cooling we can answer this question.

Under the assumption we can conclude that the room that has the lower temperature contains more air than the room at the higher temperature.

This is because when air is heated, it expands and becomes less dense. Contrarily, when air is cooled, it contracts and becomes more dense. Thus, if one room is maintained at a higher temperature than the other, the air in that room will be less dense and occupy a larger volume compared to the air in the cooler room.

When two identical rooms in a house are connected by an open doorway and the temperatures in the two rooms are maintained at different values, the room that contains more air is the one with the lower temperature

This is because of the principle of density and temperature.The air in the cooler room is denser than the air in the warmer room. Because the air is denser, there are more air molecules packed into the same space. As a result, there is more air in the cooler room than in the warmer room.

Temperature has an effect on air density, which influences the amount of air in a room. As temperature increases, air molecules gain kinetic energy and move around more quickly. This causes the air to expand and become less dense. So therefore when two rooms with different temperatures are connected, the room with the lower temperature has more air because its air is more dense.

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a man has amass of 70kg.calculate his weight on earth where gravitational strength is 10N/kg

Answers

a man has a mass of 70kg. then calculated weight on earth where Gravity strength is 10N/kg is 700N

Gravity, which derives from the Latin word gravitas, which means "weight"[1], is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between things and governs the motion of planets, stars, galaxies, and even light.

Weight W = mg = 70*10 =  700 N

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for an object in simple harmonic motion with amplitude a, the kinetic energy will equal the potential energy when the displacement is

Answers

The kinetic energy will equal the potential energy when the displacement is equal to the amplitude a, i.e., at the points where the object is farthest from the equilibrium position.

For an object in simple harmonic motion, the potential energy and kinetic energy are given by:

Potential energy (PE) = (1/2) kx²

Kinetic energy (KE) = (1/2) mv²

where k is the spring constant, x is the displacement from the equilibrium position, and v is the velocity.

At any point during the motion, the total mechanical energy (the sum of kinetic and potential energy) remains constant.

At the equilibrium position (where x = 0), all the energy is kinetic, and there is no potential energy.

At the maximum displacement (where x = a), all the energy is potential, and there is no kinetic energy.

Therefore, the kinetic energy will equal the potential energy when the displacement is equal to the amplitude a, i.e., at the points where the object is farthest from the equilibrium position.

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A pole vaulter runs, plants their pole, bends the pole, and barely clears the bar as seen in the following figure. Describe the energies at each location indicated.

Answers

In the process of pole vaulting,  at starting point the pole vaulter converts kinetic energy into elastic potential energy when it reaches the top of their jump and then vaulter descends back towards the ground with gravitational potential energy.

At the starting point, the pole vaulter has kinetic energy as they run towards the bar. As the pole vaulter plants the pole, some of this kinetic energy is transferred to the pole as it bends and stores elastic potential energy. The pole vaulter's body also gains some elastic potential energy as they begin to bend and flex the pole.

As the pole vaulter reaches the top of their jump, they have converted most of their kinetic energy into elastic potential energy and gravitational potential energy. The pole has straightened out and released its stored elastic potential energy, propelling the vaulter upwards and over the bar. At this point, the vaulter has gained significant gravitational potential energy as they reach the highest point of their jump.

As the vaulter descends back towards the ground, they begin to lose gravitational potential energy as it is converted back into kinetic energy. The pole, which had been straightened out, begins to bend again as the vaulter's weight pulls on it, converting the remaining elastic potential energy back into kinetic energy.

In summary, the pole vaulter converts their kinetic energy into elastic potential energy and gravitational potential energy during the pole vaulting process, before converting it back into kinetic energy as they descend back towards the ground.

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A solenoid with 400 turns has a radius of 0.040 m and is 40 cm long. If this solenoid carries a
current of 12 A, what is the magnitude of the magnetic field near the center of the solenoid? (μ0 = 4π × 10-7 T · m/A)
A) 16 mT
B) 4.9 mT
C) 15 mT
D) 6.0 mT
E) 9.0 mT

Answers

The magnitude of the magnetic field near the center of the solenoid is 4.8 mT, which is closest to option B).

The magnetic field near the center of a solenoid is given by the equation:

B = μ0 * n * I

where μ0 is the permeability of free space, n is the number of turns per unit length, and I is the current. For a solenoid with a uniform magnetic field along its central axis, the number of turns per unit length is given by:

n = N / L

where N is the total number of turns and L is the length of the solenoid. Substituting these values, we get:

n = 400 / 0.4 = 1000 turns/m

B = μ0 * n * I = 4π × 10-7 * 1000 * 12 = 4.8 mT

Therefore, the magnitude of the magnetic field near the center of the solenoid is 4.8 mT, which is closest to option B).

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A particle of mass 1 MeV/c2 and kinetic energy 2 MeV collides with a staionary particle of mass 2 MeV/c2. After the collision, the particles stick together. Find:
a) the speed of the first particle before the collision
b) the total energy of the first particle before the collision
c) the initial total momentum of the system
d) the total kinetic energy after the collision
e) the mass of the system after the collision

Answers

The speed of the first particle before the collision is 2 m/s. The total energy of the first particle before the collision is 4.64 x 10^-13 J.

(1/2)mv² = 3.2 x [tex]10^{-13[/tex] J

v² = (2 x 3.2 x[tex]10^{-13[/tex]J) / (1 MeV/c²)

v² = 6.4 x[tex]10^{-13[/tex] J / (1 MeV/c²)

v² = 6.4 x [tex]10^{-13[/tex] J / (1.6 x [tex]10^{-13[/tex] J)

v² = 4

v = √4 = 2 m/s

E = (1 MeV/c²)(3 x [tex]10^8[/tex] m/s)²

E = (1 x 1.6 x [tex]10^{-13[/tex] J)(9 x[tex]10 ^{16[/tex]m²/s²)

E = 1.44 x [tex]10^{-13[/tex]J

The total energy of the first particle before the collision is the sum of the kinetic energy and the rest energy:

Total energy = Kinetic energy + Rest energy

Total energy = 3.2 x[tex]10^{-13[/tex]J + 1.44 x [tex]10^{-13[/tex] J

Total energy = 4.64 x[tex]10^{-13[/tex] J

Collision refers to the interaction between two or more objects that exert forces on each other for a brief period of time. It is a fundamental concept used to understand the behavior of particles and objects in motion.

During a collision, the objects involved experience a change in their velocities and sometimes their shapes. Collisions can be categorized into two types: elastic and inelastic. In an elastic collision, kinetic energy and momentum are conserved, meaning that the total energy and momentum before the collision are equal to the total energy and momentum after the collision. In an inelastic collision, kinetic energy may be lost due to deformation or the formation of new objects, but momentum is still conserved.

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Complete Question:

A particle of mass 1 MeV/c2 and kinetic energy 2 MeV collides with a stationary particle of mass 2 MeV/c2. After the collision, the particles stick together. Find:

a) the speed of the first particle before the collision

b) the total energy of the first particle before the collision

Correct statements about a constant magnetic field acting on a charged particle include which of the following? I. The field can accelerate the particle. II. The field can change the kinetic energy of the particle. III. The field can do positive work on the particle. (A) I only (B) III only (C) I and II only (D) II and [II only
(E) I, II, and III

Answers

In a constant magnetic field, a charged particle will experience a force that is perpendicular to both the magnetic field and the particle's velocity. This force can cause the particle to move in a circular path, with a radius determined by the particle's velocity and the strength of the magnetic field.

However, the magnetic field itself cannot directly change the kinetic energy of the particle or do positive work on it. This is because the magnetic force is always perpendicular to the particle's velocity, so it does not do any work in the direction of the particle's motion.
Therefore, the correct statement about a constant magnetic field acting on a charged particle is only I, which is that the field can accelerate the particle. Statements II and III are incorrect.
In summary, a constant magnetic field can cause a charged particle to move in a circular path, but it cannot directly change the particle's kinetic energy or do positive work on it.

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Two cars each have a mass of 1050 kg. If the gravitational force between them is 2.27 question text :Two asteroids are 75,000 m apart. One has a mass of 8 kg and the other 10 kg. If the force of gravity between them is 1.14 N, what is the mass of the other asteroid? 10-7 N, how far apart are they? G = 6.67 × 10-11 N⋅(m/kg)2

A.
18 m

B.
5.6 m

C.
21 m

D.
33 m

Answers

The mass of the other asteroid is approximately 1.96 × 10^19 kg and the two objects are 5.6 meters (Option B) apart.

The gravitational force equation can be used to resolve this issue:

F = G * (m1 * m2) / r^2

where m1 and m2 are the masses of the two objects, r is the separation between them, and F is the gravitational force. G is the gravitational constant, which has a value of 6.67 10-11 N(m/kg)2.

We have two automobiles with a combined mass of 1050 kg and a gravitational force of 2.27 N for the first portion of the question. The equation can be changed in order to account for r:

G*m1*m2/F is equal to sqrt(r).

We obtain the following by plugging in the values: r = sqrt(6.67 10-11 * 1050 * 1050 / 2.27) = 1.52 metres

As a result, the two cars are 1.52 metres apart.

We have two asteroids with a total mass of for the second portion of the query. mass of 8 kg and 10 kg, respectively, and a force of gravity between them of 1.14 N. We can rearrange the equation to solve for the mass of the other asteroid:
m2 = F * r^2 / (G * m1)
Plugging in the values, we get:
m2 = 1.14 * (75000)^2 / (6.67 × 10-11 * 8) = 1.96 × 10^19 kg
So the mass of the other asteroid is approximately 1.96 × 10^19 kg.
For the last part of the question, we have a force of gravity between two objects of 10^-7 N and we need to find the distance between them. We can rearrange the equation to solve for r:
r = sqrt(G * m1 * m2 / F)
Plugging in the values, we get:
r = sqrt(6.67 × 10-11 * 8 * 10 / 10^-7) = 5.6 meters
So the two objects are 5.6 meters apart. Therefore, the answer is option B.

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a 55.0-kg lead ball is dropped from the leaning tower of pisa. the tower is 55.0 m high. how far does the ball fall in the first 3.00 s of its flight?

Answers

The distance that the lead ball falls in the first 3.00 seconds of its flight can be calculated using the equation d = 1/2gt^2, where d is the distance, g is the acceleration due to gravity (9.81 m/s^2), and t is the time.
               First, we need to calculate the velocity of the lead ball when it hits the ground after falling from the tower. We can use the equation v^2 = 2gh, where v is the velocity, g is the acceleration due to gravity, and h is the height of the tower. Plugging in the values, we get v = sqrt(2gh) = sqrt(2 x 9.81 m/s^2 x 55.0 m) = 35.2 m/s.

Next, we can calculate the distance that the ball falls in the first 3.00 seconds using the equation d = 1/2gt^2. Plugging in the values, we get d = 1/2 x 9.81 m/s^2 x (3.00 s)^2 = 44.1 m. Therefore, the lead ball falls 44.1 meters in the first 3.00 seconds of its flight

In summary, the lead ball dropped from the leaning tower of Pisa falls 44.1 meters in the first 3.00 seconds of its flight. This can be calculated using the equations v^2 = 2gh and d = 1/2gt^2.

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Which layer creates a magnetic field around earth for protection?.

Answers

The layer that creates a magnetic field around the Earth for protection is the Outer Core.

Earth's magnetic field arises from the electric currents that produce magnetic fields deep within our planet's core. It is created by the motion of molten iron and nickel present in the outer core, which forms a magnetic dynamo. It extends out from the Earth's interior and envelopes our planet.

The Earth's magnetic field acts as a shield, which protects the planet from harmful cosmic rays and solar wind. These cosmic rays can cause damage to our atmosphere, and also affect electronic devices like communication systems, satellites, and even airplanes and astronauts. Therefore, the magnetic field plays a vital role in sustaining life on Earth.

The Earth's magnetic field has been in existence for millions of years. It has been observed that the magnetic field has reversed polarity several times over the course of Earth's history. This reversal occurs due to changes in the flow of the molten iron and nickel in the outer core.

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F. A concave lens has a focal length of -20 cm. Completely describe the image formed when a 10
di, hi, erect or inverted, magnified or reduced, real or virtual)
cm tall object is: (calculate/specify:
a. 40 cm
b. 70 cm

Answers

a. The magnification is 0.33.  Thus, the image height is 3.3 cm.

b. The magnification is calculated as 0.22, resulting in an image height of 2.2 cm.

How to solve

a. When a 10 cm tall object is placed 40 cm in front of a concave lens with a focal length of -20 cm, the image formed is virtual, erec t, and reduced.

By using the lens formula (1/f = 1/do + 1/di), we can calculate the image distance (di) as -13.3 cm.

Using the lens formula:

1/f = 1/do + 1/di

1/di = -0.075 cm⁻¹

Solving for di, we get:

di = 1 / -0.075 cm⁻¹ = -13.3 cm

M = -di/do = -(-13.3 cm) / (40 cm) = 0.3325

Now, we can find hi:

hi = M * h o = 0.3325 * 10 cm = 3.325 cm

Thus, the image height is 3.3 cm.

b. For a 10 cm object placed 70 cm in front of the concave lens, the image is also virtual, er e ct, and reduced.

Using the lens formula, we find di to be -15.6 cm.

The magnification is calculated as 0.22, resulting in an image height of 2.2 cm.

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The lift sling is used to hoist a container having a mass of 500 kg. Determine the force in each of the cables AB and AC as a function of θ. If the maximum tension allowed in each cable is 5 kN, determine the shortest lengths of cables AB and AC that can be used for the lift. The center of gravity of the container is located at G.

Answers

The tension forces in cables AB and AC for lifting a 500 kg container are found as functions of θ, and the shortest lengths of cables satisfying a maximum tension of 5 kN are 4408.5 m and 1886.5 m.

Assuming the container is being lifted vertically, we can draw a free-body diagram of the container and apply Newton's second law to find the tension forces in cables AB and AC.

Let T_AB and T_AC be the tensions in cables AB and AC respectively, and let W be the weight of the container. Then we have

T_AC * cos(θ) = T_AB * cos(θ) = W

T_AC * sin(θ) = T_AB * sin(θ)

Dividing the first equation by the second, we get

tan(θ) = T_AC / T_AB

Solving for T_AC and T_AB in terms of θ, we get

T_AC = W / cos(θ)

T_AB = W / (cos(θ) * tan(θ))

Substituting W = 500 kg * 9.81 m/s² = 4905 N, we get:

T_AC = 4905 / cos(θ)

T_AB = 4905 / (cos(θ) * tan(θ))

To find the shortest lengths of cables AB and AC that can be used for the lift, we need to make sure that the tension in each cable does not exceed 5 kN. Since the tensions are functions of θ, we can find the maximum value of θ that satisfies this condition.

For cable AB

T_AB = 4905 / (cos(θ) * tan(θ)) <= 5 kN

cos(θ) * tan(θ) >= 4905 / (5 kN) = 0.981

Using a calculator or a table of trigonometric functions, we can find that the minimum value of cos(θ) * tan(θ) that satisfies this inequality is approximately 0.739. Therefore, we have

cos(θ) * tan(θ) >= 0.739

Solving for θ, we get

θ <= atan(0.739 / cos(θ)) = 51.4°

Similarly, for cable AC

T_AC = 4905 / cos(θ) <= 5 kN

cos(θ) >= 4905 / (5 kN) = 0.981

Solving for θ, we get

θ >= acos(0.981) = 11.2°

Therefore, the shortest lengths of cables AB and AC that can be used for the lift are given by

L_AB = 500 / sin(θ) <= 4408.5 m

L_AC = 500 / sin(θ) >= 1886.5 m

where we have used the maximum and minimum values of θ obtained above. These lengths assume that the cables are perfectly vertical, and in practice there may be some additional length required to account for the angle at which the cables are attached to the container.

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The light from an object moving tangentially (to your left or right) will exhibit: Select one: A. no shift. B. a blueshift. C. a shift in peak wavelength towards the blue. D. a redshift. E. a shift in peak wavelength towards the red.

Answers

If the light from an object moving tangentially (to your left or right) will exhibit  a shift in peak wavelength towards the red.   Thus the correct option is E.

The component of the object's velocity that is parallel to the observer causes the Doppler shift. If the object is moving towards the observer, the wavelength of the light will be compressed, resulting in a blueshift. If the object is moving away from the observer, the wavelength of the light will be stretched out, resulting in a redshift.

A shift in peak wavelength towards the red if the object is moving away from the observer, and a shift in peak wavelength towards the blue if the object is moving towards the observer.Therefore, the correct option is E.

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grant jumps 3.80 m straight up into the air to slam-dunk a basketball into the net. with what speed did he leave the floor?

Answers

Grant left the floor with a speed of approximately 8.67 meters per second to jump 3.80 meters into the air and slam-dunk the basketball.

To calculate Grant's initial speed, we can use the following kinematic equation: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement.

In this case, Grant's final velocity (v) is 0 m/s at the peak of his jump, the acceleration (a) is -9.81 m/s^2 due to gravity, and the displacement (s) is 3.80 meters.

Rearranging the equation to solve for u, we get u = sqrt(v^2 - 2as).

Plugging in the values, we find u = sqrt(0 - 2 * -9.81 * 3.80) ≈ 8.67 m/s.

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which of the following lines of evidence supported the hypothesis that the cathode-ray was a subatomic particle?multiple select question.the mass of the cathode-ray particle was nearly 2000 times less than that of hydrogen.the cathode-ray particle behaved identically regardless of the metal used to make it.the color of the cathode-ray glow depended on the type of gas.all cathode-ray particles had the same mass to charge ratio.

Answers

The correct options are:

All cathode-ray particles had the same mass to charge ratio.

The cathode-ray particle behaved identically regardless of the metal used to make it.

The discovery of subatomic particles was a major milestone in the development of modern physics, and the cathode-ray experiments played a significant role in this discovery. The cathode-ray experiments were conducted in the late 19th century by scientists such as J.J. Thomson, who demonstrated that cathode rays were composed of negatively charged particles that were much smaller than atoms. This discovery led to the development of the first subatomic particle model of the atom, in which electrons orbit a positively charged nucleus.

The lines of evidence that supported the hypothesis that the cathode-ray was a subatomic particle were crucial in demonstrating the existence of these tiny particles. The fact that all cathode-ray particles had the same mass-to-charge ratio suggested that they were a fundamental particle rather than a complex mixture of atoms. Similarly, the fact that the cathode-ray particle behaved identically regardless of the metal used to make it supported the hypothesis that the particle was a fundamental constituent of matter.

Overall, the cathode-ray experiments provided important insights into the nature of matter and paved the way for further discoveries in subatomic physics. They demonstrated that the atom was not the smallest particle of matter and helped to establish the idea of subatomic particles as the building blocks of matter.

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a 56.0 kg bungee jumper jumps off a bridge and undergoes simple harmonic motion. if the period of oscillation is 11.2 s, what is the spring constant of the bungee cord, assuming it has negligible mass compared to that of the jumper?

Answers

Answer:

[tex]k=17.62 \ N/m[/tex]

Explanation:

Using the following formula for period we can find the spring constant of the spring.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Formula for Period:}}\\\\T=2 \pi \sqrt{\frac{m}{k} } \end{array}\right}[/tex]

Where...

"T" is the period"m" is the mass of the object attached to the spring (in this case, the bungee jumper)"k" is the spring constant.

[tex]\hrulefill[/tex]

Given:

[tex]m=56.0 \ kg\\T=11.2 \ s[/tex]

Find:

[tex]k= \ ?? \ N/m[/tex]

(1) - Manipulate the above formula and solve for "k"

[tex]T=2 \pi \sqrt{\frac{m}{k}} \\\\\Longrightarrow \frac{T}{2 \pi}=\sqrt{\frac{m}{k} } \\\\\Longrightarrow (\frac{T}{2 \pi})^2=\frac{m}{k} \\\\\Longrightarrow k(\frac{T}{2 \pi})^2=m\\\\\therefore \boxed{k=\frac{4m \pi^2}{T^2}}[/tex]

(2) - Plug in the known values and find the value of "k"

[tex]k=\frac{4m \pi^2}{T^2}\\\\\Longrightarrow k=\frac{4(56.0) \pi^2}{(11.2)^2}\\\\\therefore \boxed{\boxed{k=17.62 \ N/m}}[/tex]

Thus, the problem is solved.

If a 56.0 kg bungee jumper jumps off a bridge and undergoes simple harmonic motion. if the period of oscillation is 11.2 s, the spring constant of the bungee cord is 99.2 N/m.

In the given problem, the period of oscillation is 11.2 s and the mass of the bungee jumper is 56.0 kg. We are asked to find the spring constant of the bungee cord. Here, the spring constant k can be found using the formula as follows;

T = 2π √(m/k)

where T is the period of oscillation

m is the mass of the jumper and k is the spring constant

We are given, T = 11.2 sm = 56.0 kg

Let's substitute the given values in the above formula:

T = 2π √(m/k)11.2 = 2π √(56/k)

Squaring both sides we get;

125.44 = 4π² × (56/k)

On simplifying the above equation, we get; k = 4π² × 56/125.44

k = 99.2 N/m

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wind blowing across suspended power lines may cause the power lines to vibrate at their natural frequecny. this often produces audible sound waves. this phenomenon, often called an aeolian harp, is an example of

Answers

The phenomenon of wind blowing across suspended power lines causing them to vibrate at their natural frequency and producing audible sound waves is commonly referred to as an aeolian harp.

When wind flows across a power line, it sets up alternating areas of high and low pressure on either side of the line. These pressure differences can cause the line to vibrate back and forth, much like a guitar string being plucked. If the frequency of the wind-induced vibration matches the natural frequency of the power line, resonance can occur, resulting in a sustained and amplified sound wave.

The sound produced by an aeolian harp can vary in pitch and volume depending on the wind speed and direction, the size and shape of the power line, and other environmental factors. In some cases, the sound can be loud enough to be heard from a significant distance away, leading to complaints from nearby residents.

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For an RLC ac circuit, the rms current is 10 A. If the impedance is 12 kΩ when the voltage
leads the current by 39°, find the average power of the circuit.
A) 930 kW
B) 47 kW
C) 93 kW
D) 190 kW

Answers

For an RLC AC circuit, the rms current is 10 A and the impedance is 12 kΩ when the voltage leads the current by 39°, the average power of the RLC circuit is 93 kW.

We can use the formula P = I^2Rcos(θ) to find the average power of the circuit, where P is power, I is rms current, R is impedance, and θ is the phase angle between voltage and current. Plugging in the given values, we get P = (10)^2 x 12,000 x cos(39) = 93,049.98 W or 93 kW (rounded to nearest whole number).

The positive value of power indicates that energy is being delivered to the circuit. It's worth noting that the phase angle of 39° indicates that the circuit is capacitive, meaning that the capacitor in the circuit is causing the current to lead the voltage. This can be confirmed by the fact that the impedance is a pure resistor, which would not cause a phase shift, and the phase angle is positive, indicating a leading current.

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at approximately what number of protons, or neutrons, does the 1:1 ratio of protons to neutrons start to produce unstable nuclei?

Answers

The 1:1 ratio of protons to neutrons generally starts to produce unstable nuclei for elements with atomic numbers greater than 20. However, this is a general trend and not an absolute rule.

The stability of a nucleus depends on many factors, including the number of protons and neutrons, their arrangement within the nucleus, and the presence of isotopes with longer half-lives. Additionally, certain isotopes may be more or less stable depending on the specific properties of the nucleus, such as its shape and energy levels. Therefore, it is difficult to give an exact number of protons or neutrons at which the 1:1 ratio becomes unstable, and each element must be evaluated on a case-by-case basis.

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A 1000-turn toroidal solenoid has a central radius of 4.2 cm and is carrying a current of 1.7 A.
What is the magnitude of the magnetic field inside the solenoid at the central radius? ( μ0 = 4π
× 10-7 T · m/A)
A) 8.1 mT
B) 51 mT
C) 16 mT
D) 81 mT
E) zero

Answers

The magnitude of the magnetic field inside the solenoid at the central radius is 81 mT, which is answer choice D.

The magnetic field inside a toroidal solenoid can be calculated using the formula:

B = (μ0 * N * I) / (2 * π * r)

where B is the magnetic field, μ0 is the permeability of free space (μ0 = 4π × 10^-7 T·m/A), N is the number of turns of the solenoid, I is the current, and r is the radius of the toroid.

Plugging in the given values, we get:

B = (4π × 10^-7 T·m/A * 1000 turns * 1.7 A) / (2π * 0.042 m)

B = 0.081 T = 81 mT

So the magnitude of the magnetic field inside the solenoid at the central radius is 81 mT, which is answer choice D.

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A. A sealed container with gas at 2.00 at is heated from 20.0 K to 40.0 K. The new pressure is?
a. 2.14 atm
b. 1.87 atm
c. 4.00 atm
d. 1.00 atm
e. 0.500 atm

Answers

The new pressure is is c. 4.00 atm.

To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas. The formula for the ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Since the container is sealed, the volume remains constant, and we can assume that the number of moles and the gas constant also remain constant. Thus, we can simplify the ideal gas law to P1/T1 = P2/T2, where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure, and T2 is the final temperature.

Plugging in the given values, we get P1/T1 = P2/T2 = 2.00 atm/20.0 K = P2/40.0 K. Solving for P2, we get P2 = 4.00 atm.

This result makes sense because heating the gas increases the temperature, which in turn increases the pressure. The increase in pressure is proportional to the increase in temperature, as long as the volume and number of moles remain constant. This is known as Gay-Lussac's law of pressure temperature.

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The product of a force and the time during which it acts defines what?
A. momentum
B.velocity
C.acceleration
D.impulse

Answers

Answer:

The product of a force and the time during which it acts defines as Impulse.

Explanation:

Momentum refers to quantity of motion of a moving object.

Momentum = Mass (m). Velocity (v)

Velocity refers to rate at which object changes its position.

Velocity = Distance travelled (d)/ Time taken (t)

Acceleration refers to rate at which velocity changes with respect to time.

Acceleration = Change in velocity/ Change in time

Impulse refers to product a force and the time of application of the force.

Impulse = Force (F). Time (t)

Thus, Option D is correct.

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A 2-kg blob of putty moving at 3 m/s slams into a 2-kg blob of putty at rest.
a) calculate the speed of the two stuck together blobs of putty immediately after colliding.
b) calculate the speed of the two blobs if the one at rest was 4 kg.

Answers

a) the velocity of the two stuck together blobs of putty immediately after colliding is 1.5 m/s.

b)  The velocity of the two stuck together blobs of putty immediately after colliding is 1 m/s if the one at rest was 4 kg.

a) The total momentum of the system is conserved during the collision. Before the collision, only one of the blobs has momentum, which is given by:

p = m1v1 = (2 kg)(3 m/s) = 6 kg·m/s

After the collision, the two blobs stick together and move with a common velocity v. Therefore, the total momentum of the system after the collision is:

p' = (m1 + m2)v

where m1 = 2 kg and m2 = 2 kg. Using conservation of momentum, we have:

p = p'

6 kg·m/s = (2 kg + 2 kg) v

v = 6 kg·m/s ÷ 4 kg

v = 1.5 m/s

Therefore, the velocity of the two stuck together blobs of putty immediately after colliding is 1.5 m/s.

b) Following the same method as above, we can find the velocity of the two blobs if the one at rest was 4 kg. Before the collision, the momentum of the moving blob is:

p = m1v1 = (2 kg)(3 m/s) = 6 kg·m/s

After the collision, the two blobs stick together and move with a common velocity v. Therefore, the total momentum of the system after the collision is:

p' = (m1 + m2)v

where m1 = 2 kg and m2 = 4 kg. Using conservation of momentum, we have:

p = p'

6 kg·m/s = (2 kg + 4 kg) v

v = 6 kg·m/s ÷ 6 kg

v = 1 m/s

Therefore, the velocity of the two stuck together blobs of putty immediately after colliding is 1 m/s if the one at rest was 4 kg.

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the best way to protect yourself from excessive exposure to radiation is to . question 33 options: not get x-rays wear a film badge limit the length of your exposure increase your distance from the source

Answers


One of the best ways to protect yourself from excessive exposure to radiation is to avoid unnecessary exposure. If possible, avoid getting X-rays or other types of radiation when they are not medically necessary. However, if you do need to get an X-ray, make sure it is done by a licensed professional who will take the necessary precautions to limit your exposure.


Radiation can be harmful to the human body, and exposure to excessive radiation can lead to serious health problems such as cancer and radiation sickness. Therefore, it is essential to protect yourself from excessive exposure to radiation.



Finally, increasing your distance from the source of radiation can also help protect you from excessive exposure. The further away you are from the source of radiation, the less exposure you will receive. Therefore, if you work in an environment where you are exposed to radiation, try to keep as much distance between yourself and the source as possible.

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Which scientist ended up under house arrest because of his support of the heliocentric model?
Galileo Galilei
Isaac Newton
Johannes Kepler
Tycho Brahe

Answers

Galileo Galilei, the Italian astronomer, physicist, and mathematician, was a proponent of the heliocentric model of the solar system, which placed the sun at the center instead of the Earth.

This theory was contrary to the widely accepted geocentric model at the time, which placed the Earth at the center of the universe.

Galileo's observations of the phases of Venus and the moons of Jupiter supported the heliocentric model, but he faced fierce opposition from the Catholic Church, which saw his ideas as a threat to religious doctrine.

In 1633, Galileo was summoned to Rome to stand trial for heresy. He was found guilty and placed under house arrest for the rest of his life.

Despite this, his work continued to have a profound impact on science, and his support of the heliocentric model paved the way for the eventual acceptance of the Copernican system, which placed the sun at the center of the solar system.

Galileo's legacy as a pioneer of modern science continues to be celebrated today.

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which type of microphone is thus typically more sensitive, a dynamic or a capacitor microphone? why?

Answers

Answer:Condenser mics

Explanation:

(10\%) Problem 6: Three charges are located as shown in the figure, with values q1​=4.6×10−16 C,q2​=−1.2×10−16C,q3​=5.5×10−16C. The charges are separated by d1​=2.1×10−6 m and d2​= 2.9×10−6 m What is the force of q3 on q1 in the y direction, Fy? Give your answer in newtons.

Answers

The force of q3 on q1 in the y direction is 2.15 * 10^-23 N.

To calculate the force of q3 on q1 in the y direction, Fy, we need to use Coulomb's law, which states that the force between two charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, it is expressed as F = k * (q1 * q2) / r^2, where F is the force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

In this case, we need to consider the forces between q1 and q3, and between q2 and q3. The force between q1 and q3 is attractive, as they have opposite charges, while the force between q2 and q3 is repulsive, as they have the same charge.

Using the values given in the problem, we can calculate the force between q3 and q1 as follows:
Fy = k * (q1 * q3) / d1^2 * sinθ

where θ is the angle between the y-axis and the line joining q1 and q3. Since the charges are arranged in a straight line, θ is 90 degrees, so sinθ = 1. Plugging in the values, we get:
Fy = (9 * 10^9 Nm^2/C^2) * (4.6 * 10^-16 C * 5.5 * 10^-16 C) / (2.1 * 10^-6 m)^2 * 1
Fy = 2.15 * 10^-23 N

Therefore, the force of q3 on q1 in the y direction is 2.15 * 10^-23 N.

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how high would the level be in a ethyl alcohol barometer at normal atmospheric pressure? The density of alcohol is 0.79×10^3kg/m3 and 1 atm = 1.013×10^5 N/m2.

Answers

If the density of alcohol is 0.79×10^3kg/m3 , pressure  is  1 atm = 1.013×10^5 N/m2,acceleration due to gravity ( g=9.81 m/s^2) then  the height of the level in an ethyl alcohol barometer at normal atmospheric pressure would be approximately 13.07meters.

To calculate the height of the level in an ethyl alcohol barometer at normal atmospheric pressure, we need to use the formula:
h = P / (ρg)

where h is the height of the column, P is the atmospheric pressure, ρ is the density of the alcohol, and g is the acceleration due to gravity.
Substituting the given values, we get:
h = (1.013×10^5 N/m2) / (0.79×10^3 kg/m3 × 9.81 m/s^2)
h = 13.07meters

Therefore, the height of the level in an ethyl alcohol barometer at normal atmospheric pressure would be approximately 13.07meters.

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