A ball rolls down a hill. it starts with velocity of 2 ms. after 2 seconds, the ball has a velocity of 12 ms. what is the acceleration of the ball? responses 2 ms2 2 m per s squared, 4 ms2 4 m per s squared, 5 ms2 5 m per s squared, 7 ms2

Answers

Answer 1

The acceleration is the change in velocity over time of the ball. Here in this case, when the ball rolls down the hill with initial velocity 2m/s and velocity after 2s is 12 m/s, then the acceleration will be 5m/s².  

Acceleration is the change in velocity/ change in time.

Here it is given that the ball starts with a velocity of 2m/s. So at t=0, v = 2m/s.

 So initial velocity = 2 m/s

The velocity after 2 seconds is given as 12 m/s  

So final velocity = 12 m/s

The change in time = 2 s

Acceleration, a = change in velocity/ change in time

                          = final velocity - initial velocity / change in time

                           = (12 m/s - 2m/s)/ 2s = 5 m/s²

So the acceleration after 2 seconds will be 5 m/s².

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Related Questions

a bicycle completed the first 500.0 m of a ride in 80.9 s. what was the bicycle's average speed in kilometers per hour?

Answers

The bicycle's average speed was 54.43 kilometers per hour. the bicycle's average speed in kilometers per hour.

what is speed ?

Speed is a measure of how quickly an object moves or changes its position over time. It is a scalar quantity, which means it is described by a magnitude only and does not have a direction. Speed is measured in units such as meters per second (m/s), kilometers per hour (km/h), and miles per hour (mph). The faster an object moves, the greater its speed.

Speed is often confused with velocity, which is a vector quantity that includes both magnitude and direction. Acceleration is the rate at which an object's speed changes over time. An object with a constant speed will have an acceleration of zero, while an object increasing its speed will have a positive acceleration and an object decreasing its speed will have a negative acceleration.

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a 30kg child sits 2.0 m from the fulccrum of a seasaw how far form the fulccrum must an 18 kg child sit

Answers

The 18 kg child must sit 3.3 meters from the fulcrum to balance the system.

To determine the distance from the fulcrum at which an 18 kg child must sit on a seesaw to balance a 30 kg child sitting 2.0 m away from the fulcrum, you can use the principle of moments.

The principle of moments states that for a system to be in equilibrium (i.e., balanced), the clockwise moments (force x distance) must be equal to the counterclockwise moments.

We know the weight of the 30 kg child is 30 x 9.8 = 294 N (Newtons), and it is 2.0 m away from the fulcrum. Therefore, the clockwise moment is 294 x 2 = 588 Nm.

The weight of the 18 kg child is 18 x 9.8 = 176.4 N.

To balance the system, the counterclockwise moment must also be 588 Nm. Therefore, the distance from the fulcrum at which the 18 kg child must sit is:

588 Nm = 176.4 N x d

d = 588/176.4 = 3.3 meters

So, the 18 kg child must sit 3.3 meters from the fulcrum to balance the system.

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A spring-loaded toy is released, and the force from the spring accelerates a 1 kg ball from rest to a velocity of 200 m/s.


What was the impulse experienced by the ball?

Answers

The impulse experienced by an object is the force applied to it multiplied by the time during which the force is applied. In this case, the impulse experienced by the ball is equal to the force exerted by the spring on the ball multiplied by the time over which the force is applied. Since the force is equal to the mass of the ball multiplied by the acceleration of the ball, we can use the following equation to calculate the impulse:

Impulse = Force x time = (mass x acceleration) x time

We know that the mass of the ball is 1 kg, and the final velocity of the ball is 200 m/s, but we don't know the time of the acceleration, so we need more information to calculate the impulse.

Another way to calculate the impulse is using the change of momentum principle. The impulse is equal to the change in momentum. The change in momentum = final momentum - initial momentum = m * vf - m * vi = m * (vf - vi)

Since the initial velocity was 0 and the final velocity is 200 m/s, the impulse is equal to m * vf = 1 kg * 200 m/s = 200 Ns

So, the impulse experienced by the ball is 200 Ns

I hope this helps :)

a bullet with mass 60.0 g is fired with an initial velocity of 575 m/s from a gun with mass 4.50 kg. the speed of the recoil of the gun is (2 points)

Answers

A bullet with mass is fired with an initial velocity from a gun with a mass of 4.50 kg the speed of the recoil of the gun is -7.67 m/s.

Given information:

Mass, (m) = 60.0 g,

velocity, (v) = 575 m/s,

Mass, (M) = 4.50 kg,

The speed of the recoil of gun V is calculated by the conservation of momentum:

momentum conservation:

0 = mv + MV

Rearrange:

V = (-mv) ÷ M

V = (-60 × 575) ÷ (4500)

V = -7.67 m/s

Here negative means the direction is opposite to v.

Therefore, The speed of the recoil of the gun is -7.67 m/s.

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if you walked at an average speed of 1.2 m/s, how long would it take to cross a road that is 16-m wide?

Answers

If you walked at an average speed of 1.2 m/s, 13.3 s  long would it take to cross a road that is 16-m wide.

What is speed ?

The rate of a directionally changing object's location. The distance travelled divided by the time required to travel that distance is the definition of speed. Speed is a scalar quantity because it only has an angular component and no magnitude.

What is velocity ?

An object's velocity is a key factor in determining its position and rate of motion. It is comprehensible as the distance an object moves in a single interval of time. The term "velocity" describes how far an object travels in a predetermined length of time.

T = D/S = 16m/1.2m/s = 13.3 s

Therefore, If you walked at an average speed of 1.2 m/s, 13.3 s  long would it take to cross a road that is 16-m wide.

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The length of a diagonal of a square is given by the function d(s) = 2s2 , where s is the length of a side of the square. Find the distance from home plate to second base on a softball diamond and on a baseball diamond. The illustration gives the dimensions of each type of infield. (Round your answers to one decimal place.)

Answers

The distance from home plate to second base on a softball diamond is 84.85 m and on a  baseball diamond is 127.28 m.

What is the illustration?

The illustration is a stylized drawing of a group of people gathered together in a circle, their arms linked together in a gesture of solidarity. The figures are all various shades of blue, and their faces are uplifted and smiling. The image conveys the idea of collective strength and unity. It is a powerful visual representation of coming together to support each other, and of the strength that can be found in community.

Using the Pythagorean Theorem

c = [tex]\sqrt{a^2 + b^2}[/tex]

Diagonal = c =  d(s) = √2s2

d(s) = [tex]\sqrt{2s^2}[/tex]

d(s) = [tex]\sqrt{s^2 + s^2}[/tex]

The function represents Pythagorean theorem

Given s is 90m

d(90) = [tex]\sqrt{90^2 + 90^2}[/tex]

d(90) = 127.28 m

In the same way

d(60) = [tex]\sqrt{60^2 + 60^2}[/tex]

d(60) = 84.85 m

Thus, The distance from home plate to second base on a softball diamond is 84.85 m and on a  baseball diamond is 127.28 m.

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Determine the resultant couple moment acting on the beam.400 N
400 N
200 N
0.2 m
200 N
-3 m
-2 m-
300 N
300 N

Answers

The resultant couple moment acting on the beam is found to be 740Nm.

What does a beam's moment mean?

When a force is applied perpendicular to a point at a specific distance from that point, a moment is a rotational force that results. It is computed by multiplying the perpendicular force by the separation from the point. A bending moment is just the bend brought on by a moment in a beam.

M resultant couple moment = F x d

                         = (300 x 5 + 200 x 0.2 - 400 x 2)

                                 => 740Nm.

What does beam response force mean?

A building experiences a reaction force when it rests against another object. Calculating the reaction forces at the supports as a result of the forces operating on the beam is a necessary step in the analysis of a beam structure. The reaction forces can be calculated using a free body diagram of the entire beam.

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When a golf club hits a 0.0459 kg ball (initially at rest), it exerts a 2380 N force for 0.00100 s. What is the momentum of the ball afterwards?
PLEASE I NEED HELP! ​

Answers

The momentum of the ball after being hit by the club can be calculated using the formula p = mv, where p is momentum, m is mass, and v is velocity. Since the force exerted on the ball is known (2380 N) and the time over which the force is exerted is also known (0.00100 s), we can use the formula F = ma to find the acceleration of the ball, where F is force, m is mass, and a is acceleration.

F = m*a

a = F/m

a = 2380 N / 0.0459 kg

The acceleration of the ball is 51760 m/s^2

Next, we can use the kinematic equation v = u + at to find the velocity of the ball, where v is final velocity, u is initial velocity and t is time.

v = u + at

u = 0 m/s (initial velocity)

t = 0.00100 s (time)

v = 0 + (51760 m/s^2)*(0.00100 s)

v = 5.176 m/s

Finally, we can use the momentum formula

p = m*v

p = (0.0459 kg)*(5.176 m/s)

p = 238.64 Ns (Newton second)

Therefore, the momentum of the ball after being hit is 238.64 Ns.

Define the following terms.
1.ignition temperature.
2.combustion.
3.fuel.
4.calorific value of a fuel.

Answers

Answer:

1) ignition temperature- the minimum temperature that is required to start or cause combustion.

2) combustion - a chemical process in which a substance reacts rapidly with oxygen and gives off heat.

3) fuel - material such as coal, gas, or oil that is burned to produce heat or power.

4) calorific value of a fuel - the quantity of heat produced by its combustion – at constant pressure and under “normal” (standard) conditions

. a scuba diver is diving into lake superior, a deep freshwater lake. at what depth below the surface is the absolute pressure 2 atm? freshwater has a density of 1000 kg/m3 . show your work.

Answers

The density of seawater is 1025 kg per meter cube, the G is 9.8 m per second square, and the depth is 40 m, thus we switched to the power three pascal plus.

Why is it important for scuba divers to practice and be well-prepared before venturing into the ocean's depths?

You run the risk of passing out. The bends decompression sickness. If you rise from deep water to the surface too rapidly, this syndrome may develop. Your body emits nitrogen gas, which causes bubbles to form in your blood.

What pressure exists 100 meters under the water's surface?

Water pressure is 10bar at 100 meters below the surface. Although atmospheric pressure is 1 bar, the absolute pressure is 11 bar.

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A microwave oven operates at 2.4 GHz with an intensity inside the oven of 2800 W/m2 .

a) What is the amplitude of the oscillating electric field?

b) What is the amplitude of the oscillating magnetic field?

Answers

a) The amplitude of the oscillating electric field is 2.34453×10⁻⁶T.

b) The amplitude of the oscillating magnetic field is 703.359V/m.

Describe a magnetic field.

The area in which magnetism acts, called the magnetic field, is where a magnetic substance or a moving electric charge is located. An illustration of the magnetic field that shows how a magnetic force is distributed both inside and outside of a magnetic material

µ₀ = Vacuum permeability = 4π×10⁻⁷H/m

I = Flux = 2800 W/m²

c = Speed of light is 3×10⁸m/s

The magnetic field's oscillation's amplitude

B₀ = √2µ₀I/c

B₀ = √2× 4π×10⁻⁷×2800/ 3×10⁸

B₀ = 2.34453×10⁻⁶T

The oscillating magnetic field's amplitude is 2.34453×10⁻⁶T

The electric field's oscillation's amplitude

E₀ = c ×B₀

E₀ = 3×10⁸× 2.34453×10⁻⁶

E₀ = 703.359V/m.

The oscillating electric field's amplitude is 703.359V/m.

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An unfingered guitar string is 0.73 m long and is tuned to play E above middle C (330 Hz).
(a) How far from the end of this string must the finger be placed to play B above middle C (494 Hz)?
?m
(b) What is the wavelength on the string of this 494 Hz wave?
?m
(c) What are the frequency and wavelength of the sound wave produced in air at 20

Answers

a) The distance from the end of the string is calculated to be 0.24 m.

b) The wavelength of the string is 0.98 m.

c) The wavelength of the sound produced is 0.69 m.

Given that,

Length L₁ = 0.73 m

Frequency F₁ = 330 Hz

Frequency F₂ = 494 Hz

Let us find out L₂ using the relation, L₁ F₁ = L₂ F₂

Making L₂ as subject, we have,

L₂ = L₁ F₁/F₂ = (0.73 × 330)/494 = 240.9/494 = 0.49 m

The length from the end is said to be 0.73-0.49 = 0.24 m

Wavelength of the string is given by the formula, Δ = 2 L₂ = 2(0.49) = 0.98 m

Frequency of the wave = 494 Hz

We know the relation, V = Δ × f

where, Δ is wavelength

f is frequency

V is velocity

As we know, V = 343 m/s

Let us make Δ as subject, as place f value.

Δ = V/ f = 343/494 = 0.69 m

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Which statement about scientific notation is true?
A. It provides a way of measurement without units.
B. It is a system of mathematical symbols used to describe energy
and matter.
mangelen
ADMINIS
PARENT
O C. It allows scientists to invent new units of measurement.
D. It allows scientists to make calculations more easily.

Answers

Answer:

D.It allows scientists to make calculations more easily

Explanation:

For example; the number 0.00236 is written in scientific notation as 2.36×10−3 or as 2.36E-3. This helps mathematicians and scientists work easily with too large or too small numbers.

A small polyester ball and a piece of polyvinyl chloride (PVC) pipe are given the same negative charge. The ball is then placed over the PVC pipe, where it is observed to remain at rest 20 cm from the pipe. The mass of the polyester ball is 5.0 grams. Determine the charge on the ball.
The charge is ___uc
Also, solve using significant figures.

Answers

The magnitude of the charge on the ball is 0.467 μC.

What is the charge on the ball?

The magnitude of the charge on the ball is calculated by applying Newton's second law of motion Coulomb's law as follows;

Mathematically, the formula for Newton's second law of motion and coulomb's law is given as;

F = mg

F = kq²/r²

where;

m is the mass of the ballq is the charge of the ballg is acceleration due to gravityr is the distance of the ballk is Coulomb's constant

kq²/r² = mg

q² = ( mgr² ) / ( k )

q = √ ( mgr² / k )

The magnitude of the charge on the ball is calculated as follows;

q = √ ( 0.005 x 9.8 x 0.2² / 9 x 10⁹ )

q = 4.67 x 10⁻⁷ C

q = 0.467 x 10⁻⁶ C = 0.467 μC

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As you walk away from a vertical plane mirror, your image in the mirror O decreases in height. O is always a real image, no matter how far you are from the mirror. O may or may not decrease in height, depending on where the observer is positioned. o changes from being a virtual image to a real image as you pass the focal point. is always the same height.

Answers

The vertical plane mirror is a flat, vertical surface, usually made of glass or metal.

What is virtual image?

Virtual image is an optical illusion created by a lens or mirror. It is a two dimensional representation of an object which appears to be the same distance away from the lens as the original object. It is formed by the convergence of light rays that are not actually present, but seem to be originating from the image. Virtual images can be viewed on a screen or projected onto a wall. Virtual images cannot be projected onto a surface for viewing.

When you stand in front of it, the light from the object that you are looking at reflects off the mirror and creates an image of the object in the mirror. This is because light travels in straight lines and when it meets the mirror it bounces off it in the same direction.

When you are standing close to the mirror, the image of the object in the mirror is upright and appears to be the same height as the original object. This is because the light from the object is reflected off the mirror and reaches your eyes in a straight line. As you move away from the mirror, the distance between the object and the mirror increases and the light is no longer traveling in a straight line. The light is now traveling at an angle and this causes the image to appear tilted in the mirror. This tilt causes the image to appear shorter than the original object.

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the earth travels around the sun once a year in approximately circular orbit with a radius of 1.50*10^11m Using the orbital speed of the earth, calculate the mass of the sun

Answers

The sun has a mass of 1.9891 x 10^30 kg. The planet's orbital speed causes the earth to orbit the sun in an approximately circular orbit with a radius of 1.50*10^11m once every year.

A essential quality of a body is its mass. It was widely believed to be connected to the volume of matter in a physical body before to the atom's discovery and the development of particle physics. Theoretically, the same chemical might be included in different atoms and elementary particles. In celestial physics, an orbit is a curved path. Orbital velocity equals (9.424 x 1011 m)/31536000 s orbital velocity is 29883.307 m/s.

The Earth's orbital speed is therefore 29883.307 m/s.

There are 1.9891 x 10^30 kilogrammes in the sun.

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the type of system in which mass and energy are constantly transferred in form, quantity, and location is a(n) blank system

Answers

The type of system in which mass and energy are constantly transferred in form, quantity, and location is a(n) open system.

An open system is a system that allows the exchange of energy and matter with its surroundings. The energy and matter can flow in and out of the system, and can change its form, quantity, and location. An open system is also known as a non-isolated system.

questionwhich statement is true about the trends shown on the electromagnetic spectrum?responses as frequency decreases, radiant energy and wavelength increase. as frequency decreases, radiant energy and wavelength increase. as frequency increases, radiant energy and wavelength decrease. as frequency increases, radiant energy and wavelength decrease. as wavelength decreases, radiant energy and frequency increase. as wavelength decreases, radiant energy and frequency increase. as wavelength increases, radiant energy and frequency increase.

Answers

This statement is accurate for the patterns seen on the electromagnetic spectrum, which reveal patterns in which the frequency of radiation increases as the wavelength decreases.

What patterns do the electromagnetic spectrum show?

The wavelengths are smaller and the vibrations are greater as you move from left to right. The relation among both wave and frequency is inverse in this case. (As one rises, the other falls.) This is due to the fact that the frequency of ALL electromagnetic waves is 300,000 km/s.

The electromagnetic spectrum is what, exactly?

In increasing frequency and decreasing wavelength order, radio waves, microwaves, infrared, white spectrum, ultraviolet radiation, X-rays, gamma rays, and cosmic rays make up the full electromagnetic spectrum.

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What causes friction between two surfaces? How can friction be reduced?

Answers

Answer:

Explanation:

Friction between two surfaces is caused by the contact between them. When two surfaces interact, the roughness of the surfaces combine with the contact force to create a force that resists the motion of the surfaces. When two surfaces are moving relative to each other, the contact force must overcome the friction force in order for the surfaces to move.

Friction can be reduced by either reducing the contact force, or by making the surfaces smoother. One way to reduce the contact force is by using a lubricant, such as oil or grease, to reduce the amount of contact between the surfaces. This reduces the force of friction and allows the surfaces to move more easily. Another way is to make the surfaces smoother, which reduces the amount of roughness and therefore reduces the friction. This can be done with sandpaper or other abrasive materials.

a 1,217 kg suv moving at 20.8 m/s strikes a 1,087 kg car moving at 14 m/s. their bumpers become locked and they continue to move as one mass. what is their final velocity as they move as a single mass?

Answers

The final velocity of the two vehicles as they move as a single mass is 18.42 m/s.

The total momentum of the two vehicles before the collision is:

momentum_initial = mass_suv ×velocity_suv + mass_car × velocity_car

The total momentum of the two vehicles after the collision is:

momentum_final = (mass_suv + mass_car) ×velocity_final

Since momentum is conserved, the initial momentum is equal to the final momentum:

momentum_initial = momentum_final

mass_suv × velocity_suv + mass_car × velocity_car = (mass_suv + mass_car) ×velocity_final

By substituting the given values, we can solve for the final velocity_final:

1217 kg * 20.8 m/s + 1087 kg * 14 m/s = (1217 kg + 1087 kg) * velocity_final

velocity_final = (1217 kg * 20.8 m/s + 1087 kg * 14 m/s) / (1217 kg + 1087 kg)

velocity_final = 18.42 m/s

The final velocity of the two vehicles as they move as a single mass is 18.42 m/s.

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In the circuit shown in the figure (Figure 1) find.
A) the current in resistor R
B) the resistance R
C) the unknown emf E
C)If the circuit is broken at point x, what is the current in resistor R?

Answers

From the given circuit the current in resistor R is 2A, the resistance R is 5ohm,  the unknown emf E is 42V and if the circuit is broken at point x, the current in resistor R is zero.

Given the diagram, the voltage passing through resistor R (V) =  28V

The current passing through resistor R is = I1

The resistance of second resistor (R2) =6 ohm.

The current passing through R2 = 4A

The resistance of third resistor (R3) = 3 ohm

The current passing through R3 = 6A

The emf at resistor R2 = e

Here we can see that current passing through R3 is split into I1 and I2 such that I1 + I2 = I3. Then, I1 + 4 = 6A

I1 = 2A

(a) The current in resistor R = 2A

(b) From ohms law we know that V = IR. Then V1 - I3R3 -I1R1 = 0

28 - (3 x 6) - (2 x R) = 0. then R = 5ohm.

The resistance R = 5 ohm

(c) Similarly, e - (3 x 6) - ( 6 x 4) = 0

Then e = 42V

The unknown emf = 42V

(d) When the circuit is broken at x, that branch is eliminated from the circuit. It will stop carrying current. The distribution of currents and voltages in the other portions of the circuit will vary as a result.

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A 54-g tennis ball is in contact with the racket for a distance of 40 cm as it leaves the racket with a velocity of 48 m/s. What is the average force on the ball?
Need to know ASAP

Answers

Answer:

Explanation:  First list the parameters

m = 54 g, d = 40 cm, v = 48 m/s, f =?

Then, convert the distance to meters

That is d = 40/ 100

d = 0.4 m

Now, let's find the force

f = ma

From the question, a is not given

Therefore, we find a

a = v/ t

a = 48 / 0.4

a = 120 m/s^2

Now, back to f

f = ma

f = 54 x 120

f = 6480N

what happened when you pushed the magnets together? what happens when you let go? when i pushed the magnets together, i felt when i let go, the spacecraft magnet

Answers

When magnets are pushed together, the north poles of one magnet will repel the north pole of the other magnet, and the south pole of one magnet will repel the south pole of the other magnet. This is known as repulsion.

When magnets are let go after being pushed together, they will naturally move away from each other as the repulsion force is no longer being applied. This is known as "releasing."

When two magnets are brought close to each other, the invisible lines of magnetic force, called magnetic fields, interact with each other. Opposite poles, such as the north pole of one magnet and the south pole of another magnet, are attracted to each other. This phenomenon is known as attraction. On the other hand, similar poles, such as the north pole of one magnet and the north pole of another magnet, will push away from each other. This is known as repulsion.

When magnets are pushed together, the repulsion force between them is greater than the attraction force. This is why they will move away from each other when they are let go. However, if the magnets are very strong or if they are physically prevented from moving away from each other, they will not move away from each other when they are let go.

In addition to this, the strength of the magnetic field decreases as you move farther away from the magnet, so the farther apart the magnets are, the weaker the force of attraction or repulsion between them will be.

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A vertical spring scale can measure weights up to 240 N . The scale extends by an amount of 14.5 cm from its equilibrium position at 0 N to the 240 N mark. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.50 Hz .

Ignoring the mass of the spring, what is the mass m of the fish?

Express your answer in kilograms. My ans is 408396.82 kg and it is wrong

Answers

The mass of the fish is 6.71kg.

First, we will calculate the angular speed of the system:

w = 2πf

where,

ω = angular speed = ?

f = frequency = 2.50 Hz

Therefore,

w = 2 π * 2.50

w = 15.7 rad/s

Now, we will use Hooke's Law to find out the spring constant of the spring:

K=f/Δx

where,

K = spring constant =?

F = force applied = maximum weight = 240 N

Δx = extension = 14.5 cm = 0.145 m

Therefore,

K=1655N/m

Now, we will use the formula for the angular speed of a spring-mass system to find out the mass of the fish:

w = [tex]\sqrt{k/m}[/tex]

m = k/w²

m = 1655/(15.7)²

m = 6.71kg

What is Hooke's law in simple terms?

Hooke's law states that the amount of force applied to an elastic object is proportional to how far it stretches. However, if the object is overstretched it will not spring back. Hooke's Law only applies if an elastic object is not overstretched.

What is the spring constant k value?

The letter k represents the “spring constant,” a number that essentially tells us how “stiff” a spring is. If you have a large value of k, that means more force is required to stretch it a certain length than you would need to stretch a less stiff spring the same length.

Thus, the mass of the fish is 6.71kg

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can velocity be negative with respect to the direction?

Answers

Answer: Yes!

Explanation: Think of a number graph. If we go right it will be positive and if we go left it'll be negative. Like this the velocity can me negative or positive based on the direction.

Two consecutive harmonics of air column in a pipe closed at one end are frequency 150Hz and 250Hz ccalculat the fundamental frequency

Answers

The fundamental frequency of the air column is 150 Hz.

How to calculate the fundamental frequency?

The fundamental frequency of an air column in a pipe closed at one end is related to the frequency of the first harmonic (also known as the first overtone or the fundamental mode) by the equation:

f1 = (2Lc)/n

where L is the length of the air column, c is the speed of sound in air, and n is the harmonic number (1 for the fundamental frequency, 2 for the second harmonic, etc.).

If two consecutive harmonics of an air column have frequencies of 150Hz and 250Hz, we can use these frequencies to calculate the fundamental frequency by solving the equation for n=1 and n=2.

For n=1:

150Hz = (2Lc)/1

For n=2:

250Hz = (2Lc)/2

Dividing the two equations:

(250Hz * 2) = (150Hz * 1)

Lc = (150Hz * 1) / 2

And now we can calculate the fundamental frequency

f1 = (2Lc) / 1 = 2 * (150Hz * 1) / 2 = 150Hz

The fundamental frequency of the air column is 150 Hz.

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) If qa and qb are positive, and qc and qd are negative, and the magnitude of all charges is the same, the net force on the positive charge q is

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If qa and qb are positive, and qc and qd are negative, and the magnitude of all charges is the same,then the net force on the positive charge q is zero

What is charge?

Charged material feels a force when it's exposed to a magnetic wave because of the physical property of electric charge. You can carry a positive or negative electric charge. Unlike charges attract each other while like charges repel one another.

What causes electrons to be charged?

Negatively charged electrons is pulled to positive-charged protons because opposing charges attract. Because of how they behave in an electric field, electrons are considered to be negative particles.

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depending on the wavelength, laser energy is emitted in very specific portions of the electromagnetic spectrum. where in the spectrum do most dental lasers operate?

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With emission wavelengths ranging from 500 to 10,600 nm, all dental lasers now on the market can be classified as either visible or invisible (infrared) nonionizing radiation.

Most dental lasers work in the visible and ultraviolet ranges of the electromagnetic spectrum. The sign, with nm units, stands for the laser wavelength. It is dictated by the resonator length of the chip structure and the crystal material's bandgap. The wavelengths of ultraviolet radiation used in lasers range from 180 to 400 nanometers (nm). Radiation with wavelengths between 400 and 700 nm makes up the visible range. A particular kind of laser made for use in oral surgery or dentistry is known as a dental laser.

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a force acts on a particle that undergoes a displacement. find the work done by the force on the particle. what is the angle between f and r

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To determine the work done by a force on a particle, we need to consider the displacement of the particle and the angle between the force and the displacement vector.

When the force acts on a particle, it causes the particle to undergo a displacement. The work done by the force is equal to the magnitude of the force multiplied by the magnitude of the displacement vector, and then multiplied by the cosine of the angle between the force and displacement vector.

To find the work done by the force, you must first calculate the magnitude of the force, the magnitude of the displacement vector, and the angle between the force and displacement vector.

Once these three components have been calculated, the work done by the force can be calculated using the equation W = F * r * cos(θ).

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An 65 kg Olympic runner leaps over a hurdle. The acceleration of gravity is 9.81 m/s 2 . If the runner’s initial vertical speed is 2.9 m/s, how much will the runner’s center of mass be raised during the jump? Answer in units of m.

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The vertical height in which the runner’s center of mass is raised during the jump is 0.43 m.

What is the vertical height reached by the runner?

The vertical height reached by the runner is calculated by applying the third kinematic equation as shown below.

Mathematically, the formula is given as;

v² = u² - 2gh

where;

v is the final velocity of the runner at the maximum heightu is the initial velocity of the runnerg is acceleration due to gravityh is the height reached by the runner

at maximum height, the final velocity, v = 0

The vertical height reached by the runner is calculated as;

0 =  u² - 2gh

2gh = u²

h = u² / 2g

h = ( 2.9² ) / ( 2 x 9.8 )

h = 0.43 m

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