Answer:
1.25 m
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Consider the horizontal and vertical motion of the ball separately.
As the ball rolls off the table with a horizontal velocity only, the vertical component of its initial velocity is zero.
Acceleration due to gravity = 10 ms⁻²
As we need to find the vertical displacement of the ball, resolve vertically, taking ↓ as positive:
[tex]u=0 \quad a=10 \quad t=0.5[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(0)(0.5)+\dfrac{1}{2}(10)(0.5)^2\\s&=0+\dfrac{1}{2}(10)(0.25)\\s&=(5)(0.25)\\ \implies s&=1.25 \; \sf m\end{aligned}[/tex]
Therefore, the vertical displacement of the ball is 1.25 m, and so the table is 1.25 m above the floor.
Part 2
2.
Besides kinetic energy, potential energy, and mechanical energy, what other forms of
energy might be present as the roller coaster travels over the track?
Answer:
firstly
kinetic and potential are two types of mechanical energy
the model used in studying submarines in different parts of the ocean uses a scale of 1:500. if a submarine is 1,000 m below the surface of the ocean, how far below sea level is the submarine in the model?
Answer: B 2m
Explanation:
I need to understand the question 1 and how to solve for it
The object is moving at a constant velocity between time 4 s to 6 s. The correct answer is option A
Velocity - Time GraphThis is the graph of velocity plotted against time. The slope of the graph is acceleration and the area under the graph is total distance travelled by the body.
Acceleration means increase in speed which is the positive slope of the graph between t = 0 s and t = 4 s
Between t = 4 s and t = 6 s the velocity is constant and acceleration = 0 because the slope of the graph is zero.
Deceleration means decrease in speed. That is, the body is slowing down. This happened between t = 6 s and t = 9 s
Therefore, the object is moving at a constant velocity between time 4 s to 6 s
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urgentt i need help What effect does watering plants have on their growth height?
Blank 1: Independent variable
Blank 2: Dependent variable
Blank 3: "If...then..." hypothesis
Answer:
3
Explanation:
cuz I looked it up
hope you have a good day :)
A train accelerates at a rate of 4.5 meters/s squared. If it starts its acceleration at 15 m/s how far has it gone after 10 seconds?
Answer:
60m/s
Explanation:
Given acceleration, and time of acceleration, the problem is as simple as placing your givens into the proper kinematics equation:
[tex]v_{f} =v_{o} +a t[/tex]
plug in your numbers and:
[tex]v_{f} =(15)+(4.5)(10)[/tex]
[tex]v_{f} =60 m/s[/tex]
A net force of 34 N is applied to accelerate an object at a rate of 2.5m / (s ^ 2) What is the mass of the object?
Answer:
F = M a Newton's Second Law
34 kg m / s^2 = M * 2.5 m / s^2
M = 34 / 2.5 kg = 13.6 kg
1. An object is thrown straight up into the
air with an initial velocity of 20m/s. For how
long will the ball be in the air?
9.81s
O4s
O 18s
O 80s
If the ball is thrown straight up into the air with an initial velocity of 20m/s, it will be in the air for 4.08 s
a = v / t
a = Acceleration
v = Velocity
t = Time
v = 20 m / s
a = 9.81 m / s²
t = 20 / 9.81
t = 2.04 s
This is the time taken to reach the farthest height the ball will raise. It takes the equal amount of time to reach the point from where it was thrown from.
T = 2t
T = Total time taken
T = 2 * 2.04
T = 4.08 s
Therefore, the ball will be in the air for 4.08 s
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A ball accelerates uniformly at −2.00 m/s2.
If the ball was initially moving at 0.20 m/s and the ball travels for 7.00 s, then what was its final velocity?
The final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.
How to calculate final velocity?The final velocity of a moving body can be calculated using the following formula:
a = v - u/t
Where;
a = acceleration (m/s²)v = final velocity (m/s)u = initial velocity (m/s)t = time (s)According to this question, a ball accelerates uniformly at −2.00 m/s². If the ball was initially moving at 0.20 m/s and the ball travels for 7.00 s, the final velocity is as follows:
-2 = (v - 0.2)/7
-14 = v - 0.2
v = 14.2m/s
Therefore, final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.
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A 2-column table with 5 rows. The first column is labeled x with entries negative 3, negative 2, 0, 2, 3. The second column is labeled f of x with entries 33, 17, negative 15, negative 7, 27. Use the table of values to find the function's values. If x = 0, then f(0) = . If f(x) = 27, then x = .
The value of function at x = 0 is -15 while at x = 3 it is 27.
What is a function?A certain kind of relationship called a function binds inputs to essentially one output.
A function can be regarded as a computer, which is helpful.
The machine will only accept specified inputs, described as the function's domain, and will potentially produce one output for each input.
A 2-column table with 5 rows.
x f(x)
-3 33
-2 17
0 -15
2 -7
3 27
At x = 0 value of function is -15
At x = 3 value of function is 27
Hence "The value of function at x = 0 is -15 while at x = 3 it is 27".
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What kind of forces are responsible for the states of aggregation of matter?
The forces responsible for the states of aggregation of matter are the intermolecular forces.
What are intermolecular forces?Intermolecular forces are the interactions that occur between molecules given their nature, this depends on the characteristics of the molecules that are going to join. The types of unions are classified according to the polarity of the molecules and the types of bonds that occur can be covalent or ionic.
Some bonds are stronger than others, this also determines the characteristics and temperatures to which they have to be exposed to change their states of aggregation.
Therefore, we can confirm that the forces responsible for the states of aggregation of matter are the intermolecular forces.
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I need to sketch force diagram
This problem is already solved
The free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.
What is free body diagram?Free body diagram refers to the formation of a system showing all the possible forces that are being exerted on the body isolating it from the surrounding.
What is system and surrounding?System refers to the object of inspection i.e. the thing that is being noted down a system can be anything from an object to multiple objects and even surrounding whereas surrounding is everything else that is not a part of the system.
We have been already given all the required inputs that will help us to create a free body diagram including:
Friction force on the body being = 12 Newton
Weight of the body = 15 Newton
Normal acting on the body = 9 Newton
To create the free body diagram we simply isolate or from the surrounding and consider it to be a system then help of the vectors we will create the system consisting of the body and all the possible forces that acting on it.
We now draw the vectors for friction force weight of the body and normal acting on the body to get our required free body diagram.
Therefore, the free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.
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One of Spider-man’s less talked about powers is that he can jump really high. In the comics Spider-man can jump upwards 3 stories. A) If Spider-man leaves the ground at 13.2 m/s, how high can he get?
If a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .
In this question Equation of Motion under gravity can be used :
v ² - u ² = 2 g h ............. Eq. 1
Here ,
u = 13 . 2 m / s
v = 0 m / s
g = - 9.8 m / s ² ( -ve as motion is against the gravity )
Now , we can use the values of u , v and g in Eq 1 .
v ² - u ² = 2 g h
0² - ( 13.2 ) ² = 2 x ( - 9.8 ) x h
0 - 174.24 = - 19.6 x h
- 174.24 = - 19.6 x h
h = 8.89 m
Hence , if a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .
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Two construction workers are attempting to pull a slab of concrete off of the ground. Each of the workers are pulling up with a force of 225 N, while the
slab of concrete applies a gravitational force of 400 N in the opposite direction, remaining stationary.
If the pulling forces applied to the slab of concrete are assigned a positive value, what is the net force of the scenario, and in which direction will the slab
of concrete move?
(1 point)
O -50 N, the slab will remain stationary
O-175 N; the slab will remain stationary
O 50 N; the slab will move upward
O 175 N; the slab will move upward
The net force of the scenario, and in which direction will the slab of concrete move 50 N the slab will move upward.
What is the gravitational force?Newton's universal law of gravitation states that the force of attraction between any two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
Briefing:The forces acting on the slap concrete are three, namely:
400 N of gravitational force
225 N of pulling force was used by one construction worker.
225 N of pulling force was used by two construction worker.
Thus, the force that results can be calculated as follows:
225 + 225 - 400 = 50 N
50 N of positive force is the outcome. The slab will therefore rise, as a result.
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Can someone help me
Answer:
Because of the wind, did the power lines come down?I was four years old when my brother was born.She welcomed the people who just moved in.When a year has passed, Earth has revolved once around the sun.Turn off the timer that is buzzing in the kitchen.Before I got my shoes, I put on my socks.How many seconds would it take to travel 20 miles at an average velocity of (25miles)/(hour)?
36.7 feet per second
A car going initially with a velocity 13.5 m/s accelerates at a rate of 1.9 m/s2 for 6.2 s. It then accelerates at a rate of minus2.5 m/s2 until it stops. What is the total time from the start of the first acceleration until the car is stopped? (Write your answer to two decimal places and do not write unit)
The total time from the start of the first acceleration until the car is stopped is 16.31 s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the final velocity in the first 6.2 s Initial velocity (u) = 13.5 m/sAcceleration (a) = 1.9 m/s²Time (t) = 6.2 s Final velocity (v) = ?a = (v – u) / t
1.9 = (v – 13.5) / 6.2
Cross multiply
v – 13.5 = 1.9 × 6.2
v – 13.5 = 11.78
Collect like terms
v = 11.78 + 13.5
v = 25.28 m/s
How to determine the time taken for the car to stop Initial velocity (u) = 25.28 m/sFinal velocity (v) = 0 m/sAcceleration (a) = -2.5 m/s² Time (t) =?a = (v – u) / t
Thus,
t = (v – u) / a
t = (0 – 25.28) / -2.5
t = -25.28 / -2.5
t = 10.112 s
How to determine the total timeTime for accelerating = 6.2 sTime for decelerating = 10.112 sTotal time =?Total time = 6.2 + 10.112
Total time = 16.31 s
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Which wave type is a surface wave?
O mechanical
O radio
O light
O electromagnetic
Question 1
Which of the following is NOT a possible reason for personalty differences?
Culture
Experience
Heredity
Diet
Answer:
diet
Explanation:
Jupiter has a mass of 1.9 × 1027 kg and in its orbit around the Sun has a speed of 13 km/s. Calculate the kinetic energy possessed by the Jupiter because of its orbit around the Sun. Give your answer to 2 significant figures.
Answer:
Explanation:
KE = 1/2mv²
KE = 1/2(1.9x1027)(13)
KE = 12683.45 J
KE = 13000 J (2 sig figs)
Music is often used to accompany pictures. What type of music would most likely accompany a photo of a kitten looking lonely and lost in the rain?
A. Staccato, Quick and Lively
B. Fast, Upbeat
C. Slow, Legato, Minor Key
D. Major Key, Light-Hearted
The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.
What are the different types of music?
Music heals the brain and soul. It should listen at the time of stress. There are different types of music such as slow, fast, and retro music.
When the person is feeling very happy and energetic they usually listen to fast songs. When a person is lost he usually listens slow and Legato music.
In the disco usually fast and upbeat music is played. Algerado is a type of quick and lively music.
Therefore, The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.
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How much time in minutes will it take a car driving at 90 km/hr to travel 27 kilometers?
Answer:
18 minutes
Explanation:
There is a speed and distance calculator online so you can check the answer! :) Have a great day!!! >-<
Match the particles with their characteristics,
subatomic particles with a positive charge
subatomic particles with a negative charge
subatomic particles with no charge
made of atoms
neutrons
-
>
electrons
protons
molecules
Any of the different self-contained units of matter or energy that are the building blocks of all matter are considered subatomic particles, also known as elementary particles.
Match the particles with their characteristics.
Subatomic particles with a positive charge. - Protons.Subatomic particles with a negative charge. - Electrons.Subatomic particles with no charge. - Neutrons.Made of atoms. - Molecules.The heavier constituents of the atom's small, but incredibly compact nucleus, the positively charged protons and the electrically neutral neutrons, are subatomic particles, as are the negatively charged, practically massless electrons that make up the majority of the atom's size.
In 1911, Rutherford demonstrated that the majority of an atom's mass is contained in its tiny nucleus, at the center of the atom, revealing the fundamental structure of the atom. Rutherford proposed that the nucleus of the atom, which is dense and positively charged, orbits the lighter, negatively charged electrons in a manner similar to how the planets do around the Sun.
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Suppose that the electric potential in a certain region is given by V (x ,y ,z) = Ax - B(y^2 - z^2) where A and B are constants. Find expressions for the components of the electric field in this region.
Ex =
Ey =
Ez =
a. The electric field component Ex = -A V/m
b. The electric field component Ey = 2By V/m
c. The electric field component Ez = -2Bz V/m
What is electric potential?Electric potential is the work done in moving a unit charge from one point to the other.
What is electric field?Electric field is the force per unit charge acting on a charged particle or at a point.
How to find expressions for the components of the electric field in this region.Given that the electric potential in a certain region is given by V(x ,y ,z) = Ax - B(y² - z²) where A and B are constants.
We know that electric field E(x,y,z) = -gradV(x,y,z)
This implies that the electric field components are
Ex = -dV/dx Ey = -dV/dy and Ez = -dV/dza. The value of Ex componentSince V(x ,y ,z) = Ax - B(y² - z²)
dV(x,y,z)/dx = d[Ax - B(y² - z²)]/dx
= Adx/dx - dB(y² - z²)]/dx
= A - 0
= A
Ex = -dV(x,y,z)/dx
= -A
So, the electric field component Ex = -A V/m
b. The value of Ey componentSince V(x ,y ,z) = Ax - B(y² - z²)
dV(x,y,z)/dy = d[Ax - B(y² - z²)]/dy
= Adx/dy - dB(y²/dy - Bdz²)]/dy
= 0 - 2By - 0
= -2By
Ey = -dV(x,y,z)/dy
= -(-2By)
= 2By
So, the electric field component Ey = 2By V/m
c. The value of Ez componentSince V(x ,y ,z) = Ax - B(y² - z²)
dV(x,y,z)/dz = d[Ax - B(y² - z²)]/dz
= Adx/dz - dB(y²/dz + Bdz²)]/dz
= 0 - 0 + 2Bz
= 2By
Ez = -dV(x,y,z)/dz
= -2Bz
So, the electric field component Ez = -2Bz V/m
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In 8.0 seconds a truck accelerates 5.7 m/s² to 57.7 m/s. How fast was the car going before it accelerated? (Round to one decimal place ex
14.1)
Answer:
12.1 m/s
Explanation:
If the car is gaining 5.7 meters per second of speed for 8 seconds then we need to multiply 5.7 by 8. this gives us 45.6
Now all we need to do is subtract 45.6 from 57.7. This is 12.1
help me pleaseeeeeee
The unit conversion of 1.5 x 10⁸ Gm to m = 1.5 x 10¹⁷ m.
The unit conversion of 2.6 x 10⁻⁵ nm = 2.6 x 10⁻²⁰ Mm.
The unit conversion of 2.72 x 10⁻⁵ μm = 2.72 x 10⁻¹¹ m.
The unit conversion of 2.56 x 10⁻³ cm = 2.56 x 10⁻⁸ km.
The unit conversion of 2 hr = 7,200 seconds.
The unit conversion of 2 h 30 min = 9,000 seconds.
What is unit conversion?Unit conversion involves the change of unit of a substance from one base to another.
Converting 1.5 x 10⁸ Gm to m1.5 x 10⁸ Gm = 1.5 x 10⁸ x 10⁹ m = 1.5 x 10¹⁷ m
Converting 2.6 x 10⁻⁵ nm to Mm2.6 x 10⁻⁵ nm = 2.6 x 10⁻⁵ x 10⁻⁹ x 10⁻⁶ m = 2.6 x 10⁻²⁰ Mm
Converting 2.72 x 10⁻⁵ μm to m2.72 x 10⁻⁵ μm = 2.72 x 10⁻⁵ x 10⁻⁶ m = 2.72 x 10⁻¹¹ m
Converting 2.56 x 10⁻³ cm to km2.56 x 10⁻³ cm = 2.56 x 10⁻³ x 10⁻² m x 10⁻³ km/m = 2.56 x 10⁻⁸ km
Converting 2 hours to seconds2 hr = 2 x 3600 s = 7,200 seconds
Converting 2 h 30min to seconds2 h 30 min = 7,200 seconds + 1800 s = 9,000 seconds
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Newton's third law explains that for every action force there is an equal and opposite reaction force. In the image below, the arrow represents the force of Earth pulling down on the book. This is also called the force of gravity.
Based on Newton's third law and the force represented by the arrow, what is the reaction force in this scenario?
A.
The force of the book pulling down on the table.
B.
The force of the table pushing up on the book.
C.
The force of the table pushing down on Earth.
D.
The force of the book pulling up on Earth.
Explanation:
If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Answer:
The force of the book pulling up on Earth
Explanation:
I did the study island
The arrows in the figure represent the
gravitational force between marbles that have
equal mass.
How should the force arrows look if a marble
that has greater mass replaces one of these
marbles?
A. Both arrows should be drawn longer.
B. Both arrows should stay the same length.
C. The arrow from the marble with less mass
should be longer than the other arrow.
D. The arrow from the marble with less mass
should be shorter than the other arrow.
Option D. The arrow from the marble with less mass should be shorter than the other arrow if a marble that has greater mass replaces one of these marbles.
Force arrows are used to show both the magnitude and direction of forces. The length of the arrow corresponds to the magnitude of the force, longer arrows indicate forces of greater magnitude. The direction of the arrow corresponds to the actual direction of the force.
For example if a man pushes a block then the force exerted by that man and the direction of force can be represented as shown in the picture.
Since given figure shows marbles of equal mass therefore the arrows are equal. Further if the marble is replaced by the heavier marble than the arrow size will definitely change.
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A centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet. What is the radius of its orbit?
______m
PLEASE HELP cant figure it out!!!
If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then the radius of its orbit would be 1.3×10⁸ meters.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then we have to find the radius of its orbit,
The centripetal force acting on the satellite = m×v² / r
185 =1050× 4800² / r
r =1.3×10⁸ meters
Thus, the radius of the orbit would be 1.3×10⁸ meters.
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an object is dropped from a 32m tall building. How fast will it be going when it strikes the ground?
The total velocity of the object which is thrown vertically from a building of 32m tall in the presence of the air will be 25.04 m/sec.
How fast will it be going when it strikes the ground if an object is dropped from a 32m tall building. ?If there is no air resistance means that the air resistance is zero, then the formula of the velocity is given by;
velocity = sqrt(2xgravityxheight)
where v represents velocity, h represents distance , g represents gravitational constant, and m represents meters, so here in this case by putting the values we can get this which is below;
velocity = square(2*(9.8m/sec2)*32m)
velocity = square(627.2 m2/sec2)
velocity = 25.04 m/sec.
So we can conclude that the total velocity of the object which is thrown vertically from a building of 32m tall in the presence of the air will be 25.04 m/sec.
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A rocket, initially at rest, steadily gains speed for 3.30s while traveling upwards
60.0m.
What was the rocket's final speed?
unit
Answer:11 2.5 Motion Equations for Constant Acceleration in One Dimension
Explanation:
