When a balloon is rubbed with fur, electrons are transferred between the two materials.
The rubbing action causes some of the electrons from the fur to transfer to the balloon, giving the balloon a negative charge.
Electrons have a negative charge, so as they move from the fur to the balloon, the fur loses negative charge and the balloon gains negative charge.
Since the balloon acquires a net charge of -0.960 nC, this means that it has gained 0.960 nC of negative charge.
Therefore, electrons were added to the balloon during the rubbing process.
We know that only electrons are transferred because the balloon and fur are both insulators, meaning that they do not allow charge to flow freely.
If other charged particles (such as protons or ions) were involved in the transfer, they would be repelled from the balloon and the fur due to their like charges, and the charge transfer would not occur.
Therefore, the correct answer is that electrons were added to the balloon during the rubbing process.
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An 80-km/h airplane caught in a 60-km/h crosswind has a resultant speed of
Select one:
a. 141 km/h.
b. 60 km/h.
c. 100 km/h.
d. 80 km/h.
The answer to this question is a. 141 km/h. The airplane's speed and the crosswind speed are not added together to get the resultant speed because they are not in the same direction. Instead, we use the Pythagorean theorem to calculate the resultant speed.
To find the resultant speed, we need to use the Pythagorean theorem because the airplane's speed and the crosswind speed are perpendicular to each other. The Pythagorean theorem states that the square of the hypotenuse (resultant speed) is equal to the sum of the squares of the other two sides (airplane speed and crosswind speed). Using this formula, we can calculate the resultant speed as follows:
Resultant speed = √(80^2 + 60^2)
Resultant speed = √(6400 + 3600)
Resultant speed = √10000
Resultant speed = 100 km/h
Therefore, the answer is not d. 80 km/h, but rather a. 141 km/h.
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Where would the weight of an object be the least?
Where would the weight of an object be the least?
clear 1. At the equator
2. 500 miles above Earth's surface.
3. At the North pole
4. At the South pole.
5. On the Moon.
Answer: 5. On the Moon.
Explanation: Weight is a measure of the force of gravity acting on an object. The weight of an object depends on the mass of the object and the strength of the gravitational force at a particular location.
On Earth, the weight of an object is determined by the mass of the object and the strength of Earth's gravitational force. At the equator, the weight of an object is slightly less compared to the poles due to the centrifugal force caused by the Earth's rotation. This force counteracts a small portion of the gravitational force, resulting in a slightly lower weight.
At the North and South poles, the weight of an object is slightly higher compared to the equator due to the shape of the Earth. The Earth is not a perfect sphere but slightly flattened at the poles, which causes objects at the poles to be closer to the center of the Earth and experience a slightly stronger gravitational force.
However, on the Moon, the weight of an object is significantly less compared to Earth. The Moon has a much smaller mass and weaker gravitational force than Earth, resulting in objects weighing less on the lunar surface.
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a ball of mass m falls vertically, hits the floor with a speed i u , and rebounds with a speed f u . what is the magnitude of the impulse exerted on the ball by the floor?
So, the magnitude of the impulse exerted on the ball by the floor is m(fu + iu).
To calculate the magnitude of the impulse exerted on the ball by the floor, we need to use the impulse-momentum theorem, which states that the impulse experienced by an object is equal to the change in momentum of that object.
The momentum of the ball just before it hits the floor can be calculated as p = m * i, where m is the mass of the ball and i is its initial velocity. Similarly, the momentum of the ball just after it rebounds can be calculated as p' = m * f, where f is its final velocity.
The change in momentum of the ball is then given by the equation Δp = p' - p, which can be simplified to Δp = m * (f - i). This represents the momentum that the ball gains or loses as a result of its collision with the floor.
According to the impulse-momentum theorem, the impulse experienced by the ball is equal to the change in momentum, so we can write:
J = Δp = m * (f - i)
Therefore, the magnitude of the impulse exerted on the ball by the floor is equal to m * |f - i|, where |f - i| represents the absolute value of the difference between the final and initial velocities.
In other words, the impulse exerted on the ball depends on the mass of the ball and the difference between its initial and final velocities. The magnitude of the impulse will be greater if the ball bounces back with a higher speed, and will be lower if it rebounds with a lower speed.
The magnitude of the impulse exerted on the ball by the floor can be calculated using the impulse-momentum theorem, which states that impulse equals the change in momentum.
Impulse = Δmomentum = m(final velocity) - m(initial velocity)
In this case, the initial velocity is -iu (downward direction) and the final velocity is +fu (upward direction). Therefore,
Impulse = m(fu) - m(-iu) = m(fu + iu)
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a 85-gram bouncy ball moving at 8.30 m/s to the right experiences an elastic collision with another ball, resulting in the 85-gram ball moving leftward at 16.0 m/s. the other ball has half the speed at the end as it had at the beginning, and is moving in the opposite direction it was at the beginning. find the mass and the initial speed of the other ball.
The mass of the other ball is 170 g, and its initial speed is 33.5 m/s. To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy.
We know that the momentum before the collision is equal to the momentum after the collision, and that the total kinetic energy before the collision is equal to the total kinetic energy after the collision.
Let m be the mass of the other ball, and v be its initial velocity. Then we have:
Momentum before = Momentum after
85 g * 8.30 m/s = m * (v/2) + 85 g * (-16.0 m/s)
Solving for m, we get m = 170 g.
Next, we can use the conservation of kinetic energy to find v:
Kinetic energy before = Kinetic energy after
(1/2) * 85 g * (8.30 m/s)^2 = (1/2) * m * (v/2)^2 + (1/2) * 85 g * (16.0 m/s)^2
Solving for v, we get v = 33.5 m/s.
Therefore, the mass of the other ball is 170 g, and its initial speed is 33.5 m/s.
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three cars are driving along a road as seen below. the driver of the red car sounds a horn having a frequency of 1100 hz. the speed of sound on this day is 338 m/s. what tone does each driver hear?
The driver of the red car hears the horn at 1100 Hz, the driver of the blue car hears it at a slightly lower frequency, and the driver of the green car hears it at an even lower frequency.
When the red car driver sounds the horn, the sound wave travels through the air at a speed of 338 m/s. However, the blue car is moving towards the red car, so it intercepts the sound wave at a higher frequency, resulting in a slightly lower tone.
On the other hand, the green car is moving away from the red car, so it intercepts the sound wave at a lower frequency, resulting in an even lower tone. This phenomenon is known as the Doppler effect, which occurs when there is a relative motion between the observer and the source of the sound. The frequency heard by the observer depends on the relative motion and the speed of the sound wave.
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two parakeets sit on a swing with their combined center of mass 10.5 cm below the pivot. at what frequency do they swing?
According to the statement the frequency at which the two parakeets swing is approximately 1.35 Hz.
The frequency at which the two parakeets swing on the swing can be calculated using the formula:
f = 1/(2π) * sqrt(g/L)
Where f is the frequency, g is the acceleration due to gravity (9.8 m/s²), and L is the length of the swing.
In this case, we don't know the length of the swing, but we do know that the center of mass of the two parakeets is 10.5 cm below the pivot. This means that the distance from the pivot to the center of mass is half the length of the swing. So:
L = 2 * 10.5 cm = 21 cm = 0.21 m
Plugging this value into the formula, we get:
f = 1/(2π) * sqrt(9.8/0.21) ≈ 1.35 Hz
Therefore, the frequency at which the two parakeets swing is approximately 1.35 Hz.
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why does the interior of an evolved high-mass star have layers like an onion
The interior of an evolved high-mass star has layers like an onion due to the process of nuclear fusion.
As the star ages, it burns through its fuel, causing the core to contract and heat up. This increase in temperature triggers new fusion reactions that produce heavier elements and release even more energy. The resulting pressure and radiation push outwards, creating distinct layers of different elements and densities within the star. This process is known as nucleosynthesis and produces the layers within the high-mass star, similar to the layers within an onion. Each layer is formed by a different fusion reaction and contains a unique composition of elements, leading to the formation of complex structures within the star.
As nuclear fusion processes progress, the inside of an evolved high-mass star layers up like an onion, with each layer designating a location where a particular fusion reaction is occurring. This layering is a product of the star's core's shifting circumstances as it goes through several stages of nuclear burning.
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type ia and type ii supernovae are respectively caused by what types of stars?
Both Type Ia and Type II supernovae are important astronomical events that provide us with valuable information about the life cycle of stars and the formation of the universe.
Type Ia and Type II supernovae are two different types of supernovae that are caused by different types of stars. Type Ia supernovae are caused by white dwarf stars, which are the remnants of stars that have exhausted all of their nuclear fuel and have collapsed to a very small size. These stars are typically in a binary system with another star, and they can accrete matter from their companion star. When a white dwarf reaches a certain mass, it can undergo a runaway nuclear reaction that causes it to explode as a supernova.
On the other hand, Type II supernovae are caused by much more massive stars, which have exhausted their nuclear fuel and can no longer support their own weight. These stars undergo a series of complex nuclear reactions that result in the production of heavier elements, and eventually, they collapse under their own gravity and explode as supernovae.
Overall, both Type Ia and Type II supernovae are important astronomical events that provide us with valuable information about the life cycle of stars and the formation of the universe. By studying these explosions and their remnants, astronomers can learn more about the composition and evolution of the universe, as well as the origins of the chemical elements that make up our world.
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At a given rotational speed, how does linear (or tangential) speed change as the distance from the axis changes?
At a given rotational speed, linear (or tangential) speed increases as the distance from the axis increases.
This relationship is described by the equation:
v = rω
where v is the tangential velocity, r is the distance from the axis (i.e., the radius), and ω is the angular velocity.
This means that for a given rotational speed (i.e., angular velocity), objects farther from the axis will be moving faster than objects closer to the axis. This relationship is demonstrated in everyday examples such as the rotation of a bicycle wheel, where the speed of the outer edge is much greater than the speed of the hub.
It's important to note that this relationship assumes a constant angular velocity. If the angular velocity changes, then the linear speed will also change, regardless of the distance from the axis.
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Find the magnitude of the sum
of these two vectors:
B
3.14 m
2.71 m
30.0°
-60.0°
The magnitude of the sum of two vectors A and B is 4.13 m and the angle of the resultant vector is 10.86°.
From the given,
A = 3.14 m
B = 2.71 m
The resultant vector C= A + B
Vector A is resolved into its vertical and horizontal components,
Aₓ = 3.14 cos(30) = 2.71 m
Ay = 3.14 sin (30) = 1.57 m
Vector B is resolved into its vertical and horizontal components,
Bx = 2.71 cos(60) = 1.355 m
By = ₋2.71 sin (60) = -2.35 m
C = A + B
= (2.71+1.355) x + (1.57 -2.35) y
= 4.064 i - 0.78 j
the magnitude of C = √(4.06)² + ( 0.78)² = 4.13 m
The angle, tan α = 0.78 / 4.06
α = 10.8°
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When a hybrid car brakes to a stop much of its kinetic energy is transformed to a) heat b) work c) electric potential energy
When a hybrid car brakes to a stop, much of its kinetic energy is transformed into different forms of energy. One of the primary forms of energy that is produced during this process is heat. As the brakes of the car are applied, the friction between the brake pads and the wheels creates heat. This heat is then dissipated into the air around the car, resulting in a loss of energy.
Hybrid cars are designed to capture some of this lost energy and convert it into useful forms of energy that can be used to power the car. In many cases, the kinetic energy that is lost during braking is converted into electric potential energy, which is then stored in the car's battery. This energy can then be used to power the car's electric motor, which in turn can help reduce the car's overall fuel consumption.
It is through the conversion of kinetic energy into electric potential energy or the conversion of energy into work, hybrid cars are a great example of how technology can be used to improve the efficiency of vehicles and reduce their environmental impact.
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Molecular spectra, like elemental one, involve only the vibration of the particles. ture or false?
False. While elemental spectra typically involve the emission or absorption of light due to electronic transitions within an atom, molecular spectra involve the vibration and rotation of the constituent atoms within a molecule.
Molecules have more degrees of freedom than atoms, which leads to more complex spectra. In addition to electronic transitions, the energy levels of molecules are also affected by their vibrational and rotational motion. When a molecule absorbs or emits light, it can undergo changes in both its electronic and vibrational/rotational states, leading to a more complex spectrum.
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an impactor with a maximum torino ranking would best be addressed group of answer choices striking the object with a nuclear missile in order to blow it apart. by organizing a regional evacuation to a far removed place on the globe. attempting to alter the orbital path of the potential impactor. all of the above
The objective of such an approach would be to minimize the potential impact and ensure that any damage is contained to the extent possible.would be to minimize the potential impact and ensure that any damage is contained to the extent possible.
A potential impactor with a maximum torino ranking means that there is a significant risk of it hitting the Earth and causing substantial damage. In such a scenario, it would be necessary to take swift and decisive action to prevent or mitigate the impact. While there are various options available, such as striking the object with a nuclear missile or attempting to alter its orbital path, it would be advisable to consider a comprehensive approach that involves all of the above. This means organizing a regional evacuation to a far removed place on the globe while also attempting to alter the trajectory of the potential impactor. The objective of such an approach would be to minimize the potential impact and ensure that any damage is contained to the extent possible. It is essential to recognize that the potential impact of an object with a maximum torino ranking could have far-reaching consequences for the planet, and we must take all necessary measures to prevent such an eventuality.
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select the set of quantum numbers that represents each electron in a ground‑state bebe atom.
The electron configuration of a ground-state Be atom is 1s² 2s². Each electron in the atom is described by a set of quantum numbers, including:
Principal quantum number (n): The first electron has n = 1 and the second electron has n = 2.
Azimuthal quantum number (l): For n = 1, the only possible value of l is 0 (s orbital), and for n = 2, the possible values of l are 0 (s orbital) and 1 (p orbital). Therefore, the first electron has l = 0 and the second electron has l = 0 or l = 1.
Magnetic quantum number (m): For l = 0, the only possible value of m is 0, and for l = 1, the possible values of m are -1, 0, and 1. Therefore, the first electron has m = 0, and the second electron has m = -1, 0, or 1.
Spin quantum number (s): Each electron has s = +1/2 or -1/2.
Thus, the set of quantum numbers for each electron in a ground-state Be atom is:
Electron 1: n = 1, l = 0, m = 0, s = +1/2 or -1/2
Electron 2: n = 2, l = 0 or 1, m = -1, 0, or 1, s = +1/2 or -1/2
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The temperature of an example of CH4 gas (10.34g) in a 50.0L vessel at 1.33atm is___
A. 984
B. -195
C. 195
D. 1260
E. -1260
The temperature of the [tex]CH_4[/tex] gas is 195 K (Option C).
We can use the ideal gas law to solve this problem: PV = nRT
where P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in K.
First, we need to calculate the number of moles of [tex]CH_4[/tex] using its molar mass:
Molar mass of [tex]CH_4[/tex] = 12.01 g/mol (C) + 4(1.01 g/mol) = 16.05 g/mol
Number of moles of [tex]CH_4[/tex] = 10.34 g / 16.05 g/mol = 0.644 mol
Now, we can rearrange the ideal gas law to solve for T:
T = PV / (nR)
Substituting the given values, we get:
T = (1.33 atm) x (50.0 L) / (0.644 mol x 0.0821 L·atm/mol·K) = 195 K
Therefore, the temperature of the [tex]CH_4[/tex] gas is 195 K (Option C).
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a sprinter runs 100.0 m in 9.87 seconds. if he travels at constant acceleration for the first 75.0 m and then at constant velocity for the final 25.0 m, what was his acceleration during the first 75.0 m?
The acceleration of the sprinter during the first 75.0 m was 1.44 m/[tex]s^2.[/tex]
We can use the kinematic equations of motion to solve this problem. Let's assume that the sprinter has an initial velocity of zero at the starting point, and a final velocity of v at the end of the 75.0 m distance. We can also assume that the time taken to cover the first 75.0 m is [tex]t_1,[/tex] and the time taken to cover the last 25.0 m is [tex]t_2[/tex].
For the first 75.0 m, we can use the following kinematic equation:
[tex]d = (1/2)at1^2[/tex]
where d is the distance covered, a is the acceleration, and t1 is the time taken to cover the distance.
For the last 25.0 m, we can use the following kinematic equation:
[tex]d = vt_2[/tex]
where d is the distance covered, v is the final velocity, and [tex]t_2[/tex] is the time taken to cover the distance.
We can also use the following kinematic equation for the entire 100.0 m distance:
[tex]d = (1/2)at^2[/tex]
where d is the distance covered, a is the acceleration, and t is the total time taken to cover the distance.
Using the given values of distance and time, we can write the following three equations:
75.0 m = [tex](1/2)at1^2[/tex] (equation 1)
25.0 m =[tex]vt_2[/tex] (equation 2)
100.0 m = [tex](1/2)at^2[/tex] (equation 3)
Since the sprinter covers the last 25.0 m at constant velocity, we know that his final velocity, v, is the same as his average velocity over the last 25.0 m. Therefore, we can write:
v = 25.0 m / t2
Substituting this expression for v into equation 3, we get:
100.0 m = [tex](1/2)at1^2[/tex] + 25.0 m / [tex]t_2[/tex]
Simplifying this equation, we get:
200.0 m = at1^2 + 50.0 m / [tex]t_2[/tex]
Now we can use equation 1 to eliminate t1:
[tex]t_1 =\sqrt(2d/a)[/tex]
Substituting this expression for t1 into equation 2, we get:
25.0 m = [tex]v(\sqrt(2d/a))[/tex]
Simplifying this equation, we get:
[tex]v^2[/tex]= 50.0ad
Substituting this expression for [tex]v^2[/tex] into the previous equation, we get:
200.0 m = (a/2)(2d/a) + (d/a) [tex]v^2[/tex]
Simplifying this equation, we get:
200.0 m = d(1/2 + 1/2)
or
d = 200.0 m
Substituting this value of d into equation 3, we get:
200.0 m = [tex](1/2)at^2[/tex]
Simplifying this equation, we get:
a =[tex](2d/t^2)[/tex]
Substituting the given values of distance and time, we get:
a = (2 x 75.0 m / (9.87 [tex]s)^2)[/tex]
a = 1.44 m[tex]/s^2[/tex]
Therefore, the acceleration of the sprinter during the first 75.0 m was 1.44 m/[tex]s^2.[/tex]
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the lowest three resonant frequencies that can be produced in a hollow tube are as follows:200 hz, 600 hz, 1000hzwhat kind of tube is it?
The three resonant frequencies provided are in a 1:3:5 ratio, which is characteristic of open-ended tubes. The fundamental frequency (first harmonic) is 200 Hz, while the second and third harmonics are 600 Hz and 1000 Hz, respectively. These harmonics indicate the presence of an open-ended tube.
The tube in question is likely a closed cylindrical tube with one end closed and one end open. This is based on the fact that the lowest resonant frequency of a closed cylindrical tube is approximately 200 Hz, while the second and third resonant frequencies are approximately three times and five times higher, respectively. It's important to understand what resonant frequencies are and how they are produced in a hollow tube. Resonant frequencies are the natural frequencies at which an object vibrates when it is excited by an external force.
The resonant frequencies of a hollow tube depend on the length and shape of the tube, as well as the speed of sound in the medium inside the tube (usually air). The resonant frequencies of a closed cylindrical tube are given by the formula f(n) = n*v/2L, where f(n) is the frequency of the nth resonant mode, v is the speed of sound, L is the length of the tube, and n is an integer representing the number of half-wavelengths that fit inside the tube. For a closed cylindrical tube with one end closed and one end open, the lowest resonant frequency (n=1) is approximately 200 Hz, while the second (n=3) and third (n=5) resonant frequencies are approximately 600 Hz and 1000 Hz, respectively. Based on the given resonant frequencies (200 Hz, 600 Hz, and 1000 Hz), it seems that you are dealing with an open-ended tube
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] Write the equation which links current, potential difference and resistance.
The equation that links current, potential difference, and resistance is known as Ohm's law, and it is given by V= IR
What is Ohm's law?The equation that links current (I), potential difference (V), and resistance (R) is known as Ohm's law, and it is given by:
V = I x R
where
V is the potential difference across the two ends of a conductorI is the current flowing through the conductorR is the resistance of the conductor.Ohm's law equation describes the relationship between these three fundamental electrical quantities, and it states that the potential difference across a conductor is directly proportional to the current flowing through it and inversely proportional to the resistance of the conductor.
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a major-league pitcher can throw a baseball at 41 m/sec. if a ball is thrown horizontally at this speed, how much will it drop by the time it reaches a catcher who is 17 m away from the point of release?
This means the ball drops about 0.87 meters (about 2 feet, 10 inches) by the time it reaches the catcher.
To answer this question, we need to use the equation for projectile motion, which is:
y = yo + voyt + 1/2at^2
where y is the vertical displacement, yo is the initial vertical position, voy is the initial vertical velocity, t is time, and a is the acceleration due to gravity.
In this case, the ball is thrown horizontally, so there is no initial vertical velocity (voy = 0), and the initial vertical position is also zero (yo = 0). We know the distance the ball travels horizontally (17 m) and the initial speed (41 m/s), so we can use the equation:
x = vot + 1/2at^2
where x is the horizontal displacement and vo is the initial horizontal velocity. Solving for t, we get:
t = x / vo = 17 / 41 = 0.4146 s
Now we can use the equation for vertical displacement to find how much the ball drops during that time. Since we know the acceleration due to gravity is -9.8 m/s^2 (downward), we get:
y = 1/2at^2 = 1/2(-9.8)(0.4146)^2 = -0.8735 m
This means the ball drops about 0.87 meters (about 2 feet, 10 inches) by the time it reaches the catcher. It's important to note that this calculation assumes the ball is thrown perfectly horizontally, with no vertical component to its motion. In reality, a pitched ball will have some degree of arc, which will affect its trajectory and how much it drops before reaching the catcher.
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Which state in the United States has the greatest tangential speed as Earth rotates around its axis?
The tangential speed of a point on the Earth's surface due to its rotation about its axis depends on its distance from the axis of rotation.
Points on the equator are farthest from the axis of rotation and therefore have the greatest tangential speed.
Therefore, the state in the United States that has the greatest tangential speed as Earth rotates around its axis is Hawaii. This is because Hawaii is the only state that lies entirely within the tropics, where the circumference of the Earth is greatest and the tangential speed due to rotation is highest. The tangential speed of a point on the equator is approximately 1670 kilometers per hour (1037 miles per hour).
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Hey guys….. anyone knows how to do this?
Answer:
D
Explanation:
A column of alcohol will be longer by a factor which is the ratios of the densities 13600/789.
The length of the mercury column replaced by the alcohol is 75.6 - 73.2 cm.
Hence h = (75.6-73.2) x 13600/789 = 41.4 cm
If arrivals occur according to the Poisson distribution every 20 minutes, then which is NOT true?
a.
λ = 20 arrivals per hour
b.
λ = 3 arrivals per hour
c.
λ = 1/20 arrivals per minute
d.
λ = 72 arrivals per day
If arrivals occur according to the Poisson distribution every 20 minutes, the statement that is NOT true is option, d: λ = 72 arrivals per day.
Given that arrivals occur according to the Poisson distribution every 20 minutes, we need to convert the rate to the appropriate time unit for each option:
a. λ = 20 arrivals per hour: This is true. The rate of 20 arrivals per hour is consistent with arrivals occurring every 20 minutes.
b. λ = 3 arrivals per hour: This is true. The rate of 3 arrivals per hour is consistent with arrivals occurring every 20 minutes.
c. λ = 1/20 arrivals per minute: This is true. The rate of 1/20 arrivals per minute is consistent with arrivals occurring every 20 minutes.
d. λ = 72 arrivals per day: This is NOT true. Since arrivals occur every 20 minutes, we need to convert the rate to arrivals per day. There are 24 hours in a day, and since arrivals occur every 20 minutes, there are 60 minutes / 20 minutes = 3 sets of 20 minutes in an hour. Therefore, there are 24 hours * 3 = 72 sets of 20 minutes in a day. The rate should be λ = 72 arrivals per day, not λ = 72 arrivals per day.
Therefore, option d is the statement that is NOT true.
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100 POINTS NEED HELP ASSAP
What is the advantage of class 3 lever? (1 point)
O It decreases the distance over which force needs to be applied.
O It increases the mechanical advantage compared with other levers.
O It decreases the amount of work that needs to be done.
O It decreases the amount of force that needs to be applied.
Answer:
Explanation:
The advantage of a class 3 lever is that it can increase the distance over which an object can be moved with a relatively small amount of force. This means that the lever can be used to provide a mechanical advantage, allowing the user to exert a greater force on an object than would otherwise be possible. However, this comes at the expense of the lever's mechanical advantage compared to other types of levers, such as class 1 and class 2 levers. Therefore, the correct option is:O It increases the distance over which force needs to be applied.
A 0.6 kg piece of metal displaces 1 liter of water when submerged. What is its density?
The density of the metal can be calculated using the formula:
density = mass / volume
where mass is the mass of the metal and volume is the volume of water displaced by the metal.
Given that the mass of the metal is 0.6 kg and it displaces 1 liter (1000 cubic centimeters) of water, we can substitute these values into the formula:
density = 0.6 kg / 1000 cubic centimeters
Simplifying, we get:
density = 0.0006 kg/cubic centimeter
Therefore, the density of the metal is 0.0006 kg/cubic centimeter.
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the fairly flat, circular part of the galaxy is referred to as the _______.
The fairly flat, circular part of a galaxy is referred to as the "galactic disk" or the "stellar disk."
The galactic disk is one of the main components of a spiral galaxy and contains the majority of a galaxy's stars, as well as various interstellar materials like gas and dust.
The disk has a flattened shape, with stars and other objects orbiting the galaxy's central bulge. It is within the galactic disk that most of the star formation and ongoing stellar activity occur.
The galactic disk is often characterized by spiral arms, where regions of higher star density and star formation are observed.
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The position of a small object is given by x = 34 + 10 − 2t2, where is in seconds and x in meters.
(a) Plot x as a function of t from t = 0 to t = 3.0 s. (b) Find the average velocity of the object between 0 and 3.0 s. (c) At what time between 0 and 3.0 s is the instantaneous velocity zero?
The instantaneous velocity is zero at t = 0 seconds.(a)
To plot x as a function of t, we can substitute values of t from 0 to 3.0 seconds into the equation x = 34 + 10 − 2t2. This gives us the following values of x: at t=0, x=34+10=44; at t=1.0, x=34+10−2(1.0)2=42; at t=2.0, x=34+10−2(2.0)2=30; at t=3.0, x=34+10−2(3.0)2=10. We can then plot these values on a graph to get the graph of x as a function of t.
(b) The average velocity of the object between 0 and 3.0 seconds can be found by dividing the change in position (x) by the change in time (t). The change in position is x(3.0) − x(0) = 10 − 44 = −34 meters, and the change in time is 3.0 − 0 = 3.0 seconds. Therefore, the average velocity is −34/3 = −11.3 m/s.
(c) The instantaneous velocity is given by the derivative of the position function, which is dx/dt = −4t. The instantaneous velocity is zero when −4t = 0, or when t = 0. Therefore, the instantaneous velocity is zero at t = 0 seconds.
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a 500kg roller coaster come over the crest of a hill at 1/s if it is going 25 m/s at the bottom of the hill, how tall was the hill
The height of the hill is approximately 31.9 meters.
Conservation of EnergyThe potential energy of an object is given by the formula:
P.E. = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the object.The kinetic energy of an object is given by the formula:
K.E. = (1/2)[tex]mv^2[/tex], where m is the mass of the object and v is its speed.At the top of the hill, the roller coaster has both potential and kinetic energy, so we can write:
P.E. + K.E. = mgh + (1/2)[tex]mv^2[/tex]
At the bottom of the hill, the roller coaster has only kinetic energy, so we can write:
K.E. = (1/2)[tex]mv^2[/tex]
Since the roller coaster's energy is conserved, we can equate these two expressions:
mgh + (1/2)[tex]mv^2[/tex] = (1/2)[tex]mv^2[/tex]
Simplifying and solving for h, we get:
h = ([tex]v^2[/tex])/(2g)h = (25^2)/(2x9.8) = 31.9 metersThus, the height of the hill is approximately 31.9 meters.
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why plane mirror always give a virtual image (3 reasons})
A plane mirror always forms a virtual image because of the following reasons:
1. When light rays from an object fall on a plane mirror, they get reflected from the mirror. After reflection, they never meet at any point in real but they appear to meet at some point.
2. The image formed by a plane mirror cannot be obtained on a screen.
3. Plane mirrors never focus light into a single converging point.
you are to throw a ball to the top of the leaning tower of pisa from the ground, by throwing it vertically upwards. what should be the initial velocity of the ball, so that it just reaches the top of the tower? take the vertical height of the tower as 154 m. ignore air resistance.
The initial velocity of the ball should be approximately 49.6 m/s to just reach the top of the leaning tower of Pisa when thrown vertically upwards from the ground, ignoring air resistance. To determine the initial velocity of the ball required to reach the top of the leaning tower of Pisa, we can use the formula for vertical motion:
v^2 = u^2 + 2as
Where v is the final velocity (zero, as the ball will reach its highest point and stop), u is the initial velocity, a is the acceleration due to gravity (-9.8 m/s^2), and s is the vertical distance traveled (154 m).
Substituting these values into the equation, we get:
0 = u^2 - 2(9.8)(154)
Simplifying, we get:
u = sqrt(2(9.8)(154))
u ≈ 49.6 m/s
Therefore, the initial velocity of the ball should be approximately 49.6 m/s to just reach the top of the leaning tower of Pisa when thrown vertically upwards from the ground, ignoring air resistance.
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Which of the following would DECREASE the grain size in an aluminum component that was cast from a molten metal melt?
A. Solidify at a different temperature that increases the nucleation rate.
B. Solidify at a different temperature that increases the growth rate for the solid nuclei.
C. Add MORE heterogeneous nucleating agents to the molten melt prior to solidification.
D. Add LESS heterogeneous nucleating agents to the molten melt prior to solidification.
Answer:
C
Explanation:
thats the right answer ksoemdk
Answer:
The correct answer is: A. Solidify at a different temperature that increases the nucleation rate.
Explanation:
The grain size of a metal is determined by the number of nuclei that form during solidification. The more nuclei that form, the smaller the grain size will be. The nucleation rate is increased by decreasing the temperature of the molten metal. This is because the lower temperature reduces the energy barrier for nucleation, making it more likely for nuclei to form.
The growth rate of the solid nuclei is also affected by the temperature. However, the effect of temperature on the growth rate is much smaller than the effect on the nucleation rate. Therefore, the best way to decrease the grain size is to solidify the metal at a lower temperature.
Adding more heterogeneous nucleating agents to the molten melt will also increase the nucleation rate and decrease the grain size. However, this is not as effective as decreasing the temperature. This is because the nucleating agents can only form nuclei at the surface of the molten metal. The lower temperature will cause nuclei to form throughout the molten metal, resulting in a smaller grain size.
Adding less heterogeneous nucleating agents to the molten melt will decrease the nucleation rate and increase the grain size. This is because the nucleating agents provide sites for nucleation to occur. Without the nucleating agents, it is more difficult for nuclei to form, resulting in a larger grain size.
