A balloon is inflated to a pressure of 0.2 bar. A 5.0 kg book is balanced on top of the
balloon. With what surface area does the balloon contact the book? (Hint: Remember that
1 bar = 100 000 Pa.)

Answers

Answer 1

Answer: THE ANSWER IS 0.0555

Explanation:

BECAUSE A^2 + B^2 + C^2 IS THE ANSWER TO THE HYPOTENUSE OF THE PA 100000


Related Questions

in a grocery store, you push a 15.5 kg shopping cart, such that it feels a horizontal net force of 14.0 n. if the cart starts at rest, how far does it move in 3.00 s?

Answers

The shopping cart moves a distance of 4.57 meters in 3.00 seconds.

Using Newton's second law, which relates force, mass, and acceleration we can solve this problem

F = ma

where F is the net force acting on the object, m is its mass, and a is its acceleration.

In the given problem, the net force acting on the shopping cart is 14.0 N, and its mass is 15.5 kg. We can rearrange the equation above to solve for the acceleration of the cart:

a = F/m

a = 14.0 N / 15.5 kg

a = 0.9032 [tex]m/s^2[/tex]

Now we can use the kinematic equation that relates distance, acceleration, and time:

d = 1/2 * a * [tex]t^2[/tex]

where d is the distance traveled, a is the acceleration, and t is the time.

Plugging in the values we have:

d = 1/2 * 0.9032 [tex]m/s^2[/tex] * [tex](3.00 s)^2[/tex]

d = 4.57 meters

Therefore, the shopping cart moves a distance of 4.57 meters in 3.00 seconds.

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According to the laws of thermodynamics, all energy transformations are inefficient because every reaction loses some energy to the surroundings as ________.

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According to the laws of thermodynamics, all energy transformations are inefficient because every reaction loses some energy to the surroundings as heat

The second law of thermodynamics states that entropy in a system always has a tendency to rise. It claims that because some energy is constantly lost as heat with each energy transfer, no energy transfer mechanism is ideal. The system's entropy rises as a result of the energy wasted. Due to this, only 10% of the energy from one tropic level gets transferred to the next, with the remaining 90% being wasted as heat.

According to the second rule of thermodynamics, some energy is transferred as heat. Numerous biological processes include this ineffective energy transfer.

This indicates that part of the input energy gets transformed into a highly disordered form of energy when energy is transformed into a different form.

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A force F is exerted on a 2.0 kg block to move it across a rough surface. The magnitude of the force is initially 5 N, and the block moves at constant velocity. While the block is movingthe force is instantaneous increases to 12 N. How much kinetic energy does the block now gain at it moves a distance of 2 m?

Answers

The block gains 4.49 J of kinetic energy as it moves a distance of 2 m

What is kinetic energy of the block?

The increase in kinetic energy of an object can be calculated using the equation:

ΔKE = 1/2 (m)(Δv^2)

where;

m is the mass of the object, Δv is the change in velocity, and ΔKE is the change in kinetic energy.

To find the change in velocity, we can use the equation of motion, which states that the net force on an object is equal to its mass times its acceleration:

F = ma

Rearranging this equation, we can find the acceleration:

a = F / m

The acceleration is the same before and after the force increases, so we can equate the two and solve for Δv:

F1 / m = F2 / m

F1 / m = (F1 + ΔF) / m

ΔF / m = F2 / m - F1 / m

ΔF / m = (12 N) / (2 kg) - (5 N) / (2 kg)

ΔF / m = 4.5 m/s^2

Δv = √(2 * ΔF / m)

Now that we have Δv, we can plug this value into the equation for ΔKE:

ΔKE = 1/2 * m * Δv^2

ΔKE = 1/2 * 2 kg * (2.12 m/s)^2

ΔKE = 4.49 J

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What would happen if you tried using a road bike to ride across a soft surface. explain your answer?

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If you tried using a road bike to ride across a soft surface, such as sand or mud, it would likely be difficult to maneuver and make forward progress. The tires of a road bike are designed for hard surfaces, such as pavement or concrete, and would not be able to provide enough traction on a soft surface. Additionally, the frame of a road bike is typically made from lightweight materials, which would make it difficult to keep on track and push through any obstacles.
Answer:riding a road bike across a soft surface can be challenging and may result in reduced traction, increased resistance, increased wear and tear, and damage to the terrain. For this reason, it is typically best to avoid using a road bike for off-road adventures and to use a bike specifically designed for rough or soft terrain instead.

Explanation:Using a road bike to ride across a soft surface, such as sand or mud, can present several challenges and can result in various outcomes.
1.Reduced Traction
2.Increased Resistance
3. Increased Wear and Tear
4.Damage to the Terrain
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Select the gas with the highest average kinetic energy per mole at 298 K.
a. carbon dioxide
b. all have the same kinetic energy
c. hydrogen
d. water
e. oxygen

Answers

Hydrogen (H2) has the highest average kinetic energy per mole at 298 K. So, the correct option is (c) hydrogen.

What is average kinetic energy?

The average energy of gas particles as a result of their mobility is measured by the gas's average kinetic energy. It is closely related to the gas's temperature, which is a gauge of the system's average particle kinetic energy. The following equation provides a gas's typical kinetic energy:

KEavg = kT (3/2)

where T is the absolute temperature of the gas in Kelvin, k is Boltzmann's constant, and KEavg is the average kinetic energy of a gas.

According to question:

Since a gas's average kinetic energy is directly correlated with its temperature, the gas with the lowest molar mass will have the highest average kinetic energy per mole at any given temperature.

Our calculations based on the molar masses of the given gases at standard conditions (298 K, 1 atm) show that hydrogen (H2) has the lowest molar mass at 2.016 g/mol, followed by carbon dioxide (CO2), water (H2O), and oxygen (O2), which have molar masses of 44.01 g/mol, 18.02 g/mol, and 32.00 g/mol, respectively.

In light of this, at 298 K, hydrogen (H2) has the highest average kinetic energy per mole. Hydrogen is the proper response, which is (c).

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mass of 3 kg of a saturated liquid-vapor mixture of water is contained in a piston-cylinder device at 160 kpa. initially, 1 kg of the water is in the liquid phase and the rest is in the vapor phase. heat is now transferred to the water, and the piston, which is resting on a set of stops, starts moving when the pressure inside reaches 500 kpa. heat transfer continues until the total volume increases by 20%, while the pressure maintains at 500 kpa. determine (a) the initial and final temperatures, (b) the mass of liquid water when the piston first starts moving, and (c) the work done during this process. also, on your local computer, observe the process on a p-v diagram.

Answers

a) initial is 80.12°C and final temperature is 181.28°C b) Initial vapor mass is 2kg and liquid water is 0.7923 kg c) Heat transfer is 324.09 kJ

Law of thermodynamics:

ΔU = Q - W

Find initial state:

Specific volume of the mixture from the tables, which is [tex]0.9505 m^3/kg[/tex].

(a) Water has gone pressure condition (assumption). We can use the steam tables to find the specific volume of the water at the end of the process:

The specific volume of the water:  [tex]0.9505 m^3/kg.[/tex]

Volume increases by 20%, so final: [tex]1.1406 m^3/kg[/tex].

Pressure: 500 kPa.

Saturation temperature: 500 kPa is 153.97°C.

Therefore, water is superheated region.

Specific volume water is: [tex]1.1406 m^3/kg.[/tex]

Temperature 181.28°C.

Initial temperature: 80.12°C

Final temperature: 181.28°C.

(b) Water is in pressure under piston.

The specific volume of water: [tex]0.9505 m^3/kg[/tex].

The pressure increases to 500 kPa: superheated vapor region:

Vapor specific volume: [tex]1.4074 m^3/kg[/tex].

Use ideal gas law:

V = m * v

V = [tex]2 kg * 1.4074 m^3/kg = 2.8148 m^3[/tex]

Since volume increases by 20%, initial volume is[tex]2.3457 m^3[/tex].

Use ideal gas law:

P * V = m * R * T

m = P * V / (R * T)

where R: gas constant

At 500 kPa and 181.28°C, the value of R * T is 298.48 kJ/kg.

Substituting:

m = [tex]500 kPa * 2.3457 m^3 / (0.4615 kJ/kg-K * 298.48 K) = 7.5768 kg[/tex]

Therefore, the mass of liquid water when the piston first starts moving is 3 - 7.5768 = -4.5768 kg.

It cannot be negative so therefore, some liquid water is present.

The specific enthalpy of the liquid water is 334.28 kJ/kg.

For saturated vapor =  2779.2 kJ/kg.

Initial enthalpy: 334.28 kJ.

Final pressure: 500 kPa

Final enthalpy:

[tex]H_final = H_initial + m_evap * (h_vap - h_liq)[/tex]

Substituting:

[tex]334.28 kJ + m_evap * (2779.2 kJ/kg - 334.28 kJ/kg) = H_finalH_final = 334.28 kJ + m_evap * 2444.92 kJ/kg[/tex]

Vapor specific volume: 1.4074 m^3/kg

Total volume:

[tex]V_final = V_initial + m_evap * v_vap[/tex]

Substituting:

[tex]2.3457 m^3 + m_evap * 1.4074 m^3/kg = V_final[/tex]

As 20% increase,

1.2 * V_initial = V_final

Substitute:

[tex]1.2 * 2.3457 m^3 = 2.8148 m^3 + m_evap * 1.4074 m^3/kgm_evap = (1.2 * 2.3457 m^3 - 2.8148 m^3)[/tex]

[tex]m_evap = (1.2 * 2.3457 m^3 - 2.8148 m^3) / 1.4074 m^3/kg = 0.2077 kg[/tex]

Mass of liquid when piston moves: 0.7923 kg.

c) To find work, use Thermodynamics 1st law:

Q = deltaU + W

Assume it is adiabatic process.

[tex]deltaU = m_evap * (u_vap - u_liq)[/tex]

The specific internal energy of the liquid water is 334.28 kJ/kg.

For saturated: 2594.2 kJ/kg.

Substitute:

deltaU = 0.2077 kg * (2594.2 kJ/kg - 334.28 kJ/kg) = 468.69 kJ

Work done is:

W = -P * deltaV

The specific volume of the liquid water is 0.0010441 m^3/kg.

The specific volume is 1.4074 m^3/kg.

Substitute:

deltaV = m_evap * (v_vap - v_liq)

Substituting:

deltaV = [tex]0.2077 kg * (1.4074 m^3/kg - 0.0010441 m^3/kg) = 0.2892 m^3[/tex]

Work done:

W = [tex]-500 kPa * 0.2892 m^3 = -144.6 kJ[/tex]

Heat transfer:

Q = [tex]deltaU + W = 468.69 kJ - 144.6 kJ = 324.09 kJ[/tex]

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PLEZS HELP I DON'T GET IT WILL MARK BRANILEST FOR THE BEST ANSWER :) Imagine that you were flying a small aircraft alone and had to
make an emergency landing in the forest below. Being the
amazing pilot that you are, you land safely, but your aircraft
is badly damaged and will not fly. It will be several days before
help can make it out to you, and you only have five items in
your emergency survival kit.
Would you rather land in a taiga or a temperate coniferous
forest? Why? What would you want in your survival kit and why?
What would you need from the forest to survive? What would the
dangers be?
Write your response in complete sentences.

Answers

In an emergency situation like this, it's important to choose the best possible environment for survival. In terms of the type of forest, a temperate coniferous forest may be a better option because it typically provides a more diverse range of resources, such as food, water, and building materials, than a taiga.

In terms of the five items in the emergency survival kit, a good mix of essential items would be:

A multi-tool or knife for building shelter, starting fires, and procuring food.
A water filtration system, such as a water bottle with a built-in filter, to ensure access to clean drinking water.
A portable shelter, such as a tent or tarp, to protect from the elements.
A fire starter, such as waterproof matches or a lighter, to provide warmth and a means to cook food.
A signaling device, such as a whistle or flares, to attract attention and signal for help.
From the forest, the survivalist would need food, water, and shelter to survive. Edible plants, berries, and small animals can provide sustenance, while streams or rivers can provide clean drinking water. Natural materials, such as branches, leaves, and moss, can be used to construct a shelter.

The dangers in the forest include exposure to the elements, wildlife, and potential injury while procuring resources. It's important to be aware of one's surroundings, and to use caution and good judgement when gathering food, water, and materials for shelter

Steady precipitation preceding a front is an indication of:a) stratiform clouds with moderate turbulence
b) cumuliform clouds with little or no turbulence
c) stratiform clouds with little or no turbulence

Answers

Steady precipitation preceding a front is most likely an indication of stratiform clouds with little or no turbulence.

The steady precipitation preceding a front is an indication of stratiform clouds with little or no turbulence. Stratiform clouds are layered and cover a large area, producing a wide, steady, and uniform precipitation that can last for many hours. These clouds form when moist air is lifted and cooled, resulting in a broad cloud layer with a relatively uniform base and top.

The steady precipitation ahead of a front is often caused by the uplift of warm air over cooler air, which creates a wide, relatively stable front. This stable front tends to produce stratiform clouds that extend over a large area and produce steady precipitation. On the other hand, cumuliform clouds are characterized by vertical development, producing showers and thunderstorms with a lot of turbulence.

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a clown 1.88 m tall looks at himself in a full-length mirror (floor-to-ceiling). at what point on the mirror must he look to see his feet (distance measured up from the floor)?

Answers

This is the same height as the clown, so if he looks up at the mirror from the floor he should be able to see his feet reflected in the mirror.

What is mirror?

Mirror is a reflective surface, typically of glass, which displays images of objects placed in front of it. Mirrors are used in a variety of different applications, including personal grooming, decoration, interior design, viewing art, scientific uses, and more. A mirror is composed of a flat, smooth surface that reflects light in a specific direction. This reflection is what produces the image we see in the mirror. The reflective surface is usually made of glass, although other materials such as metal, plastic, and wood can also be used. Mirrors can be manufactured in a variety of shapes and sizes, from small hand-held makeup mirrors to large wall-mounted mirrors. Some mirrors are also designed with special coatings or treatments to enhance their reflective properties.

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if two points are at the same potential, does this mean that no net work is done in moving a test charge from one point to the other? does this imply that no force must be exerted? explain.

Answers

Not necessarily. If two points are at the same potential, then no net work is done in moving a charge from one point to the other, but work (both positive and negative) could be done at different parts of the path.

a sledge (including load) weighs 5000 n. it is pulled on level snow by a dog team exerting a horizontal force on it. the coefficient of kinetic friction between sledge and snow is 0.05. how much work is done by the dog team pulling the sledge 1000m at constant speed?

Answers

On light snow and hard snow, the coulomb friction coefficients were estimated to be 0.03 and 0.05, respectively. In this investigation, the intermediate and final phases of the coulomb friction coefficient were between 0.03 and 0.04. Thus, option B is correct.

What coefficient of kinetic friction for sledge and snow?

The snow exerts kinetic frictional force on the sled's runners, slowing down and ultimately stopping the sled from moving. The coefficient of kinetic friction is 0.050.

Determine the value of the friction force.

[tex]F=uN = [0.05] [5000N] = 250N[/tex]

Here, N is the sledge's normal reaction force.

Write the expression for the work done.

[tex]F = f *d[/tex]

Here, d represents the horizontal distance.

[tex]W= (250)N (1000m) = 2.5 * 10^5 J[/tex]

Therefore, 2.5 * 10^5 The dog team pulls the sledge 1000 meters at a consistent speed to complete the task.

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The given question is incomplete. The complete question is given below:

A sledge (including load) weighs 5000 N. It is pulled on level snow by a dog team exerting a horizontal force on it. The coe�cient of kinetic friction between sledge and snow is 0.05. How much work is done by the dog team pulling the sledge 1000 m at constant speed?

A. 2.5×10^4J

B. 2.5×10^5J

C. 5.0×10^5J

D. 2.5×10^6J

E. 5.0×10^6J

a 0.20 kg mass on a horizontal spring is pulled back 2.0 cm and released. if, instead, a 0.40 kg mass were used in this same experiment, the total energy of the system would

Answers

By the help of potential energy of the spring, so option A) 0.21 m/s is the correct answer.

There is no energy in the spring in its normal state, which is when it is not stretched. However, the spring can store energy when it is in a position that is different from its normal position because of the position. Potential energy is the name for this accumulated energy. The accumulated potential energy as a result of a specific elastic item, such as a spring, deforming is known as the potential energy of the spring. It reflects the labor involved in stretching the spring and is dependent on both the length of the stretch and the spring constant, k.

the energy of the spring = [tex]\frac{1}{2} kx^2[/tex]

so it depends on spring's constant

and change  in length

so it is independent of mass

so, A) remains the same is the correct answer

B) total energy =[tex]0.5mv^2= 0.5\times0.2\times0.3^2[/tex]

total energy =  [tex]9\times10^-3 J[/tex]

v = 0.21 m/s

so 0.21 m/s is the correct answer

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As a boat travels at 43. 0 km/h across the surface of a still lake, the waves it creates in the water have a speed of 25. 3 km/h

Answers

The waves created by the boat have a speed of 25.3 km/h, a period of approximately 0.37 hours, and a frequency of approximately 0.027 h⁻¹

When a boat travels at a certain speed across the surface of a still lake, it creates a series of waves that spread outwards from the boat. The speed of these waves depends on the properties of the water, such as its depth and temperature.

In this case, the boat is traveling at a speed of 43.0 km/h across the surface of a still lake, and the waves it creates in the water have a speed of 25.3 km/h.

The speed of the waves created by the boat can be calculated using the formula:

v = sqrt(gλ/2π)

where v is the speed of the waves, g is the acceleration due to gravity (9.81 m/s^2), λ is the wavelength of the waves, and π is the mathematical constant pi (approximately equal to 3.14).

Assuming that the wavelength of the waves is proportional to the speed of the boat, we can use the following formula to relate the wavelength of the waves (λ) to the speed of the boat (vb) and the speed of the waves (v):

λ = (v + vb) T

where T is the period of the waves, which is the time it takes for one complete wavelength to pass a fixed point.

We can rearrange this formula to solve for the period:

T = λ / (v + vb)

Substituting the given values, we get:

T = λ / (v + vb) = (25.3 km/h) / (43.0 km/h + 25.3 km/h)

T ≈ 0.37 hours

Finally, we can use the period of the waves to calculate their frequency (f), which is the number of waves that pass a fixed point in one second:

f = 1 / T

f = 1 / 0.37 hours ≈ 0.027 h⁻¹

Therefore, the waves created by the boat have a speed of 25.3 km/h, a period of approximately 0.37 hours, and a frequency of approximately 0.027 h⁻¹.

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the two factors that determine gravitational attraction are mass and what else?

Answers

Answer:

The distance between the two objects

The force is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between them

Explanation:

the distance from one trough to another trough is called a _____

Answers

the distance from one trough to another trough is called a wavelength.

What is wavelength?

Wavelength is a measure of the distance between consecutive peaks of a waveform. It is a fundamental physical property of all waveforms and can be used to describe the properties of light, sound, and other forms of energy. Wavelength is most often expressed in units of meters (m). Wavelengths of different types of radiation can range from extremely short distances (nanometers) to extremely long distances (kilometers). The shorter the wavelength, the higher the energy of the radiation. Wavelengths are important for determining the behavior of waveforms, such as the speed and direction of travel, the amount of energy the wave carries, and the way in which the wave interacts with other forms of matter. Wavelengths are also important in communication technologies, such as radio and television transmission.

Therefore, the distance from one trough to another trough is called a wavelength.

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what is the surface charge density on the inner surface of the conducting shell?express your answer in terms of some or all of the variables q , a , b , and appropriate constants.

Answers

The surface charge density on the inner surface of the conducting shell can be expressed as: σ = q / (4πb^2), or σ = εq / (4πb^2).

To find the surface charge density on the inner surface of the conducting shell, we can use the formula:

σ = Q / A

where σ is the surface charge density, Q is the charge enclosed by the surface, and A is the area of the surface.

In this case, the charge enclosed by the surface is the charge q, since the conducting shell is neutral and does not contribute to the charge. The area of the inner surface of the shell is 4πb^2. Therefore, we have:

σ = q / (4πb^2)

Alternatively, we can use the fact that the electric field just outside the inner surface of the shell is E = q / (4πεb^2), where ε is the permittivity of free space. The electric field just inside the inner surface of the shell is zero, since the electric field inside a conductor is zero. Therefore, the charge density on the inner surface of the shell is given by:

σ = εE = εq / (4πb^2)

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determine which variables are known and which are not. an air-filled pipe is found to have successive harmonics at 480 hz , 800 hz , and 1120 hz . it is unknown whether harmonics below 480 hz and above 1120 hz exist in the pipe. what is the length of the pipe?

Answers

Below are the variables known and unknown of an air-filled pipe that have successive harmonica at 480hz, 800hz, 1120hzKnown. Successive harmonics at 480 Hz, 800 Hz, and 1120 Hz Unknown.

What are harmonics?

Harmonics are overtones that are multiples of the fundamental frequency of a sound. They are produced when a sound wave is reflected from a surface, such as a wall or floor, and create a pleasant, ringing sound.

They are often used in music to create a fuller, richer sound. Harmonics can also be used to create a variety of effects in sound production, such as reverberation and echo.

For example, if a guitar is plucked, the note being played has a fundamental frequency but also has overtones which are produced by the guitar's body and strings.

To calculate the length of the pipe, it would be necessary to know the frequency of the first harmonic (the fundamental) and the frequency of the last harmonic. Without knowing this, it is not possible to calculate the length of the pipe.

Therefore, These overtones create a richer sound and are known as harmonics. The length of the pipe is unknown because the known harmonics do not provide enough information to calculate it.

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Nichrome wire is used as heating element why?​

Answers

Answer:

Explanation:

Nichrome wire is generally used as a heating element in heating appliances because it has the following features: It offers a very large resistance. So a large amount of electric energy is converted into a large amount of heat energy. It has a high melting point such that it can be heated till red hot without melting.

Nichrome is used for making heating element of electrical appliances. Because nichrome does not oxidize and burn easily at high temperature i.e.it has higher melting and boiling point than metals. Thus it does not melt even when a large amount of heat is produced due to passage of current. Moreover, It has higher resisistivity and consequently a higher resistance.Therefore, it will resist the flow of charges more, and lead to development of heat faster.

what is the value of n for the electron following the emission?

Answers

The value of n for the electron emissions will be refer in each of the photoelectric effect, radioactivity. electron microscopy.

Photoelectric effect: In this process, electrons are emitted from a metal surface when light is shone on it. The energy of the incident light is absorbed by electrons in the metal, causing them to be ejected from the surface. "n" could refer to the energy level of the electron in the metal before it is ejected, which would determine the kinetic energy of the emitted electron.

Radioactive decay: Some radioactive isotopes undergo a process called beta decay, in which a neutron in the nucleus decays into a proton, emitting an electron in the process. "n" could refer to the energy level of the electron in the nucleus before it is emitted.

Electron microscopy: In electron microscopy, a beam of electrons is used to image a sample at high resolution. "n" could refer to the number of electrons emitted from the source, which would determine the intensity of the electron beam.

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HELP PLEASE! THIS IS DUE SOON!

Answers

The statement is consistent with the Stefan- Boltzmann law

What is Stefan Boltzmann law?

Stefan-Boltzmann law is a physical law that states that the total amount of radiation emitted by a blackbody per unit time and per unit surface area is proportional to the fourth power of its absolute temperature. Mathematically, the law can be expressed as:

E = σT^4

where E is the total radiant emittance, σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4), and T is the absolute temperature in Kelvin. The law is important in understanding the behavior of thermal radiation and plays a crucial role in many areas of science and engineering.

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Why does an iceberg have more total internal energy than a pan of boiling water, even though the iceberg has a lower temperature? In your answer, use the words “potential,” “kinetic,” and “thermal.”

Answers

An iceberg has more total internal energy than a pan of boiling water due to its greater potential energy and the greater amount of thermal energy contained in its larger mass.

What is total internal energy?

Total internal energy is the sum of the kinetic energy of the molecules in a system and the potential energy of their interactions. It is a measure of the energy contained within a system and is typically expressed in joules.

The total internal energy of an object is the sum of its potential and kinetic energies, as well as any thermal energy it contains. Even though the temperature of an iceberg is lower than that of a pan of boiling water, an iceberg has more total internal energy for two reasons: potential energy and the amount of thermal energy. Potential energy is energy that is stored in an object due to its position relative to other objects. An iceberg floating in water is at a higher position than the water in the pan, so it has more gravitational potential energy. Thermal energy is the energy that is associated with the random motion of particles in a system. The internal energy of a system is proportional to the temperature, but it also depends on the number of particles in the system, which is referred to as its mass. Since an iceberg is much larger than a pan of boiling water, it contains more particles and therefore has more thermal energy.

Therefore, greater potential energy and the greater amount of thermal energy contained in its larger mass.

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for a person wearing these shoes, what??s the maximum angle (with respect to the horizontal) of a smooth rock that can be walked on without slipping?

Answers

The maximum angle (with respect to the horizontal) of a smooth rock that can be walked on without slipping is 50°.

Friction is a force that acts between two rough shells, whenever one tries to move one face against the other. When a force F pushes an object in one direction, there appears a disunion force in the contrary direction. Before stir thresholds, we're in the governance of static disunion.

Once the applied force is increased, the static disunion increases at the same rate, until it's reached a outside, denoted by maximum static disunion, and defined by the formula

[tex]f_s = \mu_s N[/tex]

The static measure between the shoe and the smooth gemstone is μs= 1.2

and hence the maximum static disunion is given by,

[tex]f_s = \mu_s N[/tex]

where N is the magnitude of the normal force. The forces acting on the shoe are

The gravitational force wielded by the Earth, of magnitude

F = mg

The normal force N wielded by the face of the gemstone, directed typically outwards from the gemstone.

The( static) disunion, wielded by the gemstone, in the direction overhead the gemstone( opposed to the tendency of slipping).

N - Fcosθ

N = Fcosθ

f = μFcosθ,

μFcosθ = Fsinθ

μ = sinθ/cosθ

Given by is the maximum (or critical) angle.

[tex]\theta_m_a_x = arctan\mu_s = arctan(1.2) = 50^0[/tex]

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Complete question:

Shoes made for the sports of bouldering and rock climbing are designed to provide a great deal of friction between the foot and the surface of the ground. Such shoes on smooth rock have a coefficient of static friction of 1.2 and a coefficient of kinetic friction of 0.90. For a person wearing these shoes, what is the maximum angle (with respect to the horizontal) of a smooth rock that can be walked on without slipping?


The soil sample was contaminated with equal amounts of caesium-137 and
iodine-131
Explain how the risk linked to each isotope has changed between 1986 and 2018
Both isotopes emit the same type of radiation.

Answers

Both caesium-137 and iodine-131 emit ionizing radiation, which can damage living tissue and increase the risk of cancer.

What are isotopes?

Isotopes are members of the same element's family but have variable numbers of neutrons despite having the same number of protons.

Iodine-131 and caesium-137 both produce ionizing radiation, which can harm living things and raise the risk of cancer.

Due to their varied half-lives and processes of decay, each isotope's danger has changed between 1986 and 2018 despite this.

Caesium-137 degrades gradually over time since it has a longer half-life of roughly 30 years. Iodine-131, on the other hand, degrades swiftly because of its significantly lower half-life of only around 8 days.

Thus, the risk has diminished over time as a result of radioactive decay.

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at what angle above the horizontal should the ball be thrown so that the runner will catch it just before it hits the ground? express your answer in degrees.

Answers

at the velocity of 60 degree angle above the horizontal should the ball be thrown so that the runner will catch it just before it hits the ground

For the person to be able to catch the ball, the horizontal component of velocity of the ball should be same as the speed of the person, i.e.,

v 0 cosθ= 2v 0

​  or cosθ= 21

​  or θ=60 ∘ .

Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

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the sun, with its diameter of 1.4 x 106 kilometers, is how many orders of magnitude larger than the earth, with its diameter of 1.3 x 104 kilometers. group of answer choices two orders of magnitude (i.e., a factor of 100 times bigger). four orders of magnitude (i.e., a factor of 10,000 times bigger). three orders of magnitude (i.e., a factor of 1,000 times bigger). one order of magnitude (i.e., a factor of 10 times bigger).

Answers

The sun is approximately two orders of magnitude (i.e., a factor of 100 times) larger than the Earth in terms of diameter.

To determine how many orders of magnitude larger the sun is than the Earth, we need to calculate the ratio of their diameters and take the logarithm (base 10) of that ratio.

The ratio of the sun's diameter to the Earth's diameter is:

1.4 x 10^6 km / 1.3 x 10^4 km = 107.7

Taking the logarithm (base 10) of this ratio gives:

log10(107.7) = 2.03

So the answer is that the sun is approximately two orders of magnitude (i.e., a factor of 100 times) larger than the Earth in terms of diameter.

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part (a) what is the magnitude of the z -component of the magnetic field, in units of teslas, at the origin of the coordinate system due to charge q1 ?

Answers

1. The z-component of the magnetic field due to charge one at the origin of the coordinate system, in teslas is (4π x [tex]10^{-7}[/tex] T m/A).

2. The z-component of the magnetic field due to charge two at the origin of the coordinate system, in teslas is 6.06 x [tex]10^{-5}[/tex] T.

3. The total magnetic field, in the z-direction, at the origin, due to the two charges, in teslas is 6.05 x [tex]10^{-5}[/tex] T.

1. To calculate the magnetic field at the origin of the coordinate system due to the two moving charges, we can use the Biot-Savart law, which relates the magnetic field at a point to the current or the moving charges producing it.

Let's first calculate the magnetic field at the origin due to charge one:

The magnitude of the magnetic field at a point due to a moving charge can be calculated using the equation:

B = (μ0/4π) x (q v sinθ / r²).

2. In this case, charge one has a charge of 0.15 C and is moving at a speed of 18.5 x [tex]10^6[/tex] m/s. The distance between charge one and the origin is 0.65 m.

B1 = (μ0/4π) x (0.15 x 18.5 x [tex]10^6[/tex] / 0.65²) = 6.06 x [tex]10^{-5}[/tex] T

The z-component of this magnetic field is zero since the field is perpendicular to the z-axis.

3. Next, let's calculate the magnetic field at the origin due to charge two:

B2 = (μ0/4π) x (5.50 x 2.5 x 10 / 0.65²) = -1.26 x [tex]10^{-7}[/tex] T

The negative sign indicates that the magnetic field due to charge two is directed along the negative z-axis.

Finally, let's calculate the total magnetic field at the origin due to both charges:

Since the magnetic fields due to the two charges are perpendicular to each other, we can simply add their magnitudes to obtain the total magnetic field in the z-direction:

Btot = B1 + B2 = 6.06 x [tex]10^{-5}[/tex] - 1.26 x [tex]10^{-7}[/tex] = 6.05 x [tex]10^{-5}[/tex] T

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The question is -

Consider the two charges, which are moving in opposite directions and located at a distance of 0.65 m on either side of the origin of the given coordinate system. Charge one is 0.15 C and is moving at a speed of 18.5 x 106 m/s, and charge two is 5.50 and is moving at a speed of 2.5 x 10 m/s.

What is the z-component of the magnetic field due to charge one at the origin of the coordinate system, in teslas?What is the z-component of the magnetic field due to charge two at the origin of the coordinate system, in teslas?What is the total magnetic field, in the z-direction, at the origin, due to the two charges, in teslas?

the sun continues to shine today because of two kinds of balance. what are they and how do they work?

Answers

The two kinds of balance that keep the Sun shining are thermal equilibrium and hydrostatic equilibrium.

Thermal Equilibrium: The Sun shines by nuclear fusion, a process in which hydrogen atoms combine to form helium and release energy in the form of light and heat.

Hydrostatic Equilibrium: The Sun is also in hydrostatic equilibrium, which is the balance between the inward gravitational force and the outward pressure force.

These two balances are delicately intertwined and any disturbance to them could result in a catastrophic event such as a supernova or a collapse.

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a thermometer is taken from a room where the temperature is 72o f to the outside where the temperature is 32o f. after 2 minutes, the thermometer reads 48o f. how many minutes does the thermometer have to be outside for it to read 36o f?

Answers

A thermometer is taken from a room where the temperature is 72° F to the outside where the temperature is 32° F. 1.26 minutes does the thermometer have to be outside for it to read 36° F.

If an item is heated to a greater temperature, T is transferred to a lower temperature environment, cooling rate ​is directly proportional to the temperature differential. By separating the variables, rewrite the equation. In the derived equation, substitute 0 for t and 72 for T.

If an item is heated to a greater temperature,

T is transferred to a lower temperature environment, T then the cooling rate.

By Newton's Law of Cooling

[tex]T(t) = T_{s} + Ce^{tr}[/tex]

Here, the ambient temperature, [tex]T_{s} = 32^{\circ} F[/tex]

The temperature to the outdoor, T(0) = 72°F

Use the equation [tex]T(t) = T_{s} + Ce^{tr}[/tex] to obtain that,

[tex]T(0) = T_{s} + Ce^{k - 0}[/tex]

72 = 32 + C

C = 40

So, [tex]T(t) = 32 + 40 e^{kt}[/tex]

After half minute, the temperature reads 48°F,

so, T(1/2) = 48

Then,

[tex]T(1/2) = 32 + 40e^{k \times \frac{1}{2}}[/tex]

[tex]48 = 32 + 40e^{\frac{k}{2}}[/tex]

[tex]40e^{\frac{k}{2}} = 16[/tex]

[tex]e^{\frac{k}{2}} = \frac{16}{40}[/tex]

[tex]e^{\frac{k}{2} = \frac{2}{5}[/tex]

[tex]\frac{k}{2} = \ln \left(\frac{2}{5} \right )[/tex]

k = 2 ln (2/5)

Therefore,

[tex]T(t) = 32 + 40e^{2 \ln \left(\frac{2}{5} \right) t}[/tex]

[tex]T (t) = 32 + 40 \left[ e^{\ln (\frac{2}{5} ) \right ]^{2t}[/tex]

[tex]T (t) = 32 + 40 \left(\frac{2}{5} \right)^{2t}[/tex]

Now find the time t when T(t) = 36

[tex]32 + 40 (\frac{2}{5})^{2t} = 36[/tex]

[tex]40 (\frac{2}{5})^{2t} = 4[/tex]

[tex](\frac{2}{5})^{2t} = \frac{4}{40}[/tex]

[tex]2t\ \ln (\frac{2}{5}) = \ln (\frac{1}{10})[/tex]

[tex]t = \frac{\ln (\frac{1}{10})}{2 \ln (\frac{2}{5})}[/tex]

[tex]t = \frac{-2.30}{2 \times (-0.91)}[/tex]

t = -2.30/-1.82

t = 1.26 min

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a). Show that the average speed of Leslie is 10 km/h when she runs to the store 5 km away in 30 min.


(b) How fast is this in m/s?


6. (a) Calculate the acceleration for a ball that starts from rest and rolls down a ramp and gains a speed of 30 m/s in 4 s.



(b) What would acceleration be if the ball rolls at 60 m/s?






Answers

Acceleration is a physical quantity that describes the rate of change in velocity of an object over time. It is a vector quantity, which means it has both magnitude and direction, and is measured in units of meters per second squared (m/s²).

Describe Acceleration

When an object is accelerating, its velocity is changing, either by increasing or decreasing in speed or changing direction. The magnitude of the acceleration depends on the force applied to the object, which can come from a variety of sources such as gravity, friction, or electromagnetism.

The formula for acceleration is:

a = (v2 - v1) / t

where a is the acceleration, v2 is the final velocity, v1 is the initial velocity, and t is the time it takes to go from v1 to v2.

If an object is moving in a straight line with a constant acceleration, its velocity can be calculated by the following equation:

v = v0 + at

where v is the final velocity, v0 is the initial velocity, a is the acceleration, and t is the time.

Acceleration is a fundamental concept in physics and is used to describe the motion of objects in a wide variety of situations, including free-fall, projectile motion, circular motion, and the behavior of fluids. It is also essential in engineering and design, where it is used to calculate the performance and efficiency of machines and vehicles.

(a) To find the average speed of Leslie, we can use the formula:

average speed = total distance / total time

Leslie runs to the store 5 km away in 30 minutes (0.5 hours), so the total distance is 5 km and the total time is 0.5 hours.

average speed = 5 km / 0.5 hours = 10 km/h

Therefore, the average speed of Leslie is 10 km/h when she runs to the store 5 km away in 30 minutes.

(b) To convert km/h to m/s, we can use the conversion factor:

1 km/h = 0.2778 m/s

So, the speed of Leslie in m/s is:

10 km/h × 0.2778 m/s/km/h = 2.78 m/s

Therefore, Leslie's speed is 2.78 m/s.

(a) To calculate the acceleration of the ball, we can use the formula:

acceleration = (final velocity - initial velocity) / time

The ball starts from rest, so the initial velocity is 0 m/s. After 4 seconds, it gains a speed of 30 m/s.

acceleration = (30 m/s - 0 m/s) / 4 s = 7.5 m/s²

Therefore, the acceleration of the ball is 7.5 m/s².

(b) If the ball rolls at 60 m/s, we can use the same formula to find the acceleration:

acceleration = (60 m/s - 0 m/s) / 4 s = 15 m/s²

Therefore, the acceleration of the ball would be 15 m/s² if it rolls at 60 m/s.

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a uniform beam with a mass of 120 kg and a length of 5.0 m rests on two supports, one at the left edge and one 3.0 m from the left edge. how close to the right edge can a 68-kg person walk along the beam without causing it to tip over?

Answers

If uniform beam with a mass of 120 kg and a length of 5.0 m rests on two supports, one at the left edge and one 3.0 m from the left edge then 1.6 m close to the right edge can a 68-kg person walk along the beam without causing it to tip over.

What is mass?

A body's mass is an innate characteristic. Prior to the discovery of the atom and particle physics, it was widely considered to be connected to the amount of matter in a physical body. It was found that different atoms and elementary particles had varying masses even if they theoretically contain the same quantity of stuff. In modern physics, there are a number of theoretically distinct but physically equal theories of mass. Experimentally, the mass of a body can be used to quantify its resistance to acceleration (change in velocity) in the presence of a net force.

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