Answer:
Explanation: To solve this problem, we can use the equation for the force on a current-carrying conductor in a magnetic field:
F = I L x B
where F is the force on the conductor, I is the current flowing through the conductor, L is the length of the conductor, and B is the magnetic field strength.
a) Just after the switch is closed, the circuit is completed and a current starts to flow in the bar. The emf of the battery causes a current to flow in the circuit, which is given by Ohm's Law:
I = V / R = 12 / 5 = 2.4 A
The direction of the current is from the battery, through the bar, and back to the battery. Since the magnetic field is directed into the plane, the force on the bar is perpendicular to both the magnetic field and the current. Therefore, the bar experiences a sideways force that pushes it along the rails. The magnitude of the force is given by:
F = I L B = 2.4 x 0.36 x 2.4 = 2.0736 N
The mass of the bar is 0.90 kg, so the acceleration of the bar is:
a = F / m = 2.0736 / 0.90 = 2.304 m/s^2
Therefore, the acceleration of the bar just after the switch is closed is 2.304 m/s^2.
b) When the bar's speed is 2.0 m/s, the force on the bar is still given by:
F = I L B = 2.4 x 0.36 x 2.4 = 2.0736 N
However, now there is an additional force acting on the bar due to its motion through the air. This force is given by:
F_air = -0.5 ρ C_d A v^2
where ρ is the density of air, C_d is the drag coefficient, A is the cross-sectional area of the bar, and v is the speed of the bar. We can estimate the cross-sectional area of the bar as A = 0.01 m^2, and assume that the drag coefficient is C_d = 1. The density of air is ρ = 1.2 kg/m^3.
Substituting the given values, we get:
F_air = -0.5 x 1.2 x 1 x 0.01 x 2^2 = -0.024 N
The negative sign indicates that the air resistance is acting in the opposite direction to the motion of the bar.
The net force on the bar is therefore:
F_net = F + F_air = 2.0736 - 0.024 = 2.0496 N
Using Newton's Second Law, we can calculate the acceleration of the bar:
a = F_net / m = 2.0496 / 0.90 = 2.2778 m/s^2
Therefore, the acceleration of the bar when its speed is 2.0 m/s is 2.2778 m/s^2.
c) The bar's terminal speed is reached when the air resistance force is equal in magnitude and opposite in direction to the force due to the magnetic field. At this point, the net force on the bar is zero, so the acceleration is zero and the bar moves at a constant speed.
Setting F_net = 0, we can solve for the terminal speed:
F + F_air = 0
I L B - 0.5 ρ C_d A v^2 = 0
2.4 x 0.36 x 2.4 - 0.5
ρ C_d A v^2 = 2.0736
v^2 = (2.0736) / (ρ C_d A)
v^2 = (2.0736) / (1.2 x 1 x 0.01)
v^2 = 172.8
v = sqrt(172.8)
v = 13.142 m/s
Therefore, the bar's terminal speed is 13.142 m/s.
a circuit consist of four resistor in parallel with a battery three resistors have resistance of 1 ohms ,2 ohms and 3 ohms , respectively, the total resistance the circuit is 0,5 ohms and the current through the 1 ohms resistor is 4A
what is the value of fourth resistor
The value of the fourth resistor in the parallel circuit is 6 ohms.
What is the value of the fourth resistor?
The value of the fourth resistor is calculated by applying the formula for effective resistance of a parallel circuit.
1/Re = 1/R₁ +1/ R₂ + 1/R₃ + 1/R₄
where;
R₁, R₂, R₃, R₄ are the individual resistors in parallelRe is the effective resistance1/0.5 = 1/1 + 1/2 + 1/3 + 1/R₄
2 = 1 + 0.5 + 0.333 + 1/R₄
0.167 = 1/R₄
R₄ = 1/0.167
R₄ = 6 ohms
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Can anyone help me answer this question
A 5.0uC charge is located at the origin and a -2.0uC charge is 0.74m away on the x-axis. Calculate the electric field at point P, on the y-axis 0.6m above the positive charge. If a 1.5uC was placed at P, what force would it experience?
Electric field is superposition of 2 charges E=kq/r^2 along joining line k= 9 x 10^9 Nm^2/C^2
The force experienced at P if a 1.5uC was placed is -1.67 N
How to determine force?To find the electric field at point P, first calculate the electric field due to the 5.0 μC charge and the electric field due to the -2.0 μC charge, and then add them together using vector addition.
Electric field due to the 5.0 μC charge:
E1 = kq₁/r₁²
where q₁ = 5.0 μC, r₁ = distance between charge and point P
r₁ = √(0.6²) = 0.6 m
E₁ = (9 x 10⁹ Nm²/C²) x (5.0 x 10⁻⁶ C) / (0.6)²
E₁ = 1.25 x 10⁶ N/C (directed downwards along the negative y-axis)
Electric field due to the -2.0 μC charge:
E₂ = kq₂/r₂²
where q₂ = -2.0 μC, r₂ = distance between charge and point P
r₂ = √(0.74² + 0.6²) = 0.945 m
E2 = (9 x 10⁹ Nm²/C²) x (-2.0 x 10⁻⁶C) / (0.945)²
E2 = -2.36 x 10⁶ N/C (directed upwards along the positive y-axis)
Total electric field at point P:
E = E₁ + E₂
E = 1.25 x 10⁶ N/C - 2.36 x 10⁶ N/C
E = -1.11 x 10⁶ N/C (directed upwards along the positive y-axis)
To find the force on a 1.5 μC charge placed at point P, use the formula:
F = qE
where q = 1.5 μC
F = (1.5 x 10⁻⁶ C) x (-1.11 x 10⁶ N/C)
F = -1.67 N (directed upwards along the positive y-axis)
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Question 1 of 10
A business must decide whether to open a new office in China. If it opens the
branch, it will increase its chances of selling a high volume of its products in
China. On the other hand, the business will have to spend a lot of money to
make the branch operational.
What would be an opportunity cost for the business if it chooses not to open
the new branch in China?
A. The business would lose the chance to make more money in
China.
B. The business would increase its marginal benefits on each
product it makes.
If the velocity of a particle is nonzero, can the particle’s acceleration be zero? Explain.
If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.
What is acceleration?The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.
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Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The
object moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the
displacement of the object?
Answer:
Explanation: To calculate the displacement of an object moving with constant acceleration, we can use the following kinematic equation:
d = (1/2)at^2 + v0t
where d is the displacement of the object, a is the constant acceleration, t is the time elapsed, and v0 is the initial velocity of the object.
In this case, we know the initial velocity v0 = 3 m/s and the final velocity vf = 10 m/s. We also know that the object moves with constant acceleration, so we can use the following equation to relate the initial and final velocities to the acceleration and displacement:
vf^2 = v0^2 + 2ad
Solving for d, we get:
d = (vf^2 - v0^2) / (2a)
Substituting the given values, we get:
d = (10^2 - 3^2) / (2a) = 91 / (2a)
Therefore, to calculate the displacement of the object, we need to determine the value of the acceleration.
We can use the velocity vs. time graph to find the acceleration of the object. The slope of the velocity vs. time graph represents the acceleration of the object, since acceleration is the rate of change of velocity with respect to time.
Since the initial position of the object is zero, the velocity vs. time graph will pass through the origin. Therefore, we can use the part of the graph between the initial time t=0 and the final time when the velocity is 10 m/s. This part of the graph will be a straight line with positive slope, representing the constant acceleration of the object.
We can calculate the slope of this line by finding the change in velocity and dividing by the time elapsed:
a = (vf - v0) / t
Substituting the given values, we get:
a = (10 - 3) / t
Therefore, the acceleration of the object is 7/t, where t is the time elapsed between the initial and final velocities.
Substituting this value for a into the expression for displacement, we get:
d = 91 / (2(7/t)) = (91t) / 14
Therefore, the part of the velocity vs. time graph between t=0 and the final time can be used to calculate the displacement of the object using the equation d = (91t) / 14.
Question 2 (1 point)
What happens to the number of waves when you change the light from green to red?
Increase
decrease
remain the same
there are zero waves
When you change the light from green to red, the number of waves remains the same.
Light waves behave similarly throughout the electromagnetic spectrum. Depending on the nature of the item and the light's wavelength, a light wave can be transmitted, reflected, absorbed, refracted, polarized, diffracted, or dispersed when it strikes a surface.
The number of waves doesn't vary when the light changes from green to red. The distance between each wave's consecutive peaks, or wavelength, determines the color of light. Red and green light both have waves with a set number of peaks and troughs per unit of time, despite green light having a shorter wavelength. As a result, the number of waves is unaffected by changing the colour of the light.
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given the two displacement vector D ( 6i+3j-k) and vector E( 4i-5j+3k) what is the magnitude of displacement. 2D-E
Answer:
The magnitude of displacement vector 2D-E is approximately 14.49 units. The calculation is done using the Pythagorean theorem after finding 2D-E by multiplying vector D by 2 and subtracting vector E.
Explanation:
The value of 2D-E must first be calculated in order to ascertain the displacement 2D-E's magnitude. Vector D may be multiplied by two to accomplish this, and the result can be obtained by deducting vector E:
2D-E = 2(6i + 3j - k) 4i + 5j + 3k = 8i + 11j - 5k - (4i - 5j + 3k) = 12i + 6j - 2k
We can use the Pythagorean theorem to determine the magnitude of the displacement vector now that we know it:
|2D-E| = √(8² + 11² + (-5)²) = √(64 + 121 + 25) = √210 ≈ 14.49
The displacement 2D-E magnitude is therefore 14.49 units or such. From the object's beginning location to its ultimate position, the displacement's entire length is shown by this. Being a scalar variable, the displacement's magnitude does not reveal the displacement's direction.
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A conducting bar is moving west with speed v through a region where a uniform magnetic field of magnitude B is directed into the plane of the page, as shown. Which of following indicates the direction of the electric field inside the conducting bar and provides supporting evidence?
Option c. The electric field in the bar is directed to the south, as indicated by Faraday's law.
As per Faraday's law of electromagnetic enlistment, a changing attractive field initiates an electric field. In this situation, the directing bar is traveling through a uniform attractive field, which is a changing attractive field according to the bar's perspective. In this way, an electric field will be actuated in the bar. The course of the incited electric field not entirely settled by involving the right-hand rule for electromagnetic enlistment. As the bar is moving west, the incited electric field will be coordinated toward the north This is upheld by Faraday's regulation, which expresses that the incited emf is corresponding to the pace of progress of attractive motion. Ampere's regulation isn't relevant in that frame of mind, as it manages the connection between attractive field and electric flow.
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a wire carrying current I is perpendicular to a magnetic field of strenght B. Assuming a fixed lenght of wire, which of the following changes will result in decreasing the force on the wire by a factor of 2?
*the options are in the picture attached
Since the wire is perpendicular to the magnetic field thus
F=I {l{B}
How to solveForce on current carrying wire due to magnetic field is given as
[tex]\vec{F}=I (\vec{l}\times \vec{B})=I lB\sin\theta[/tex]
Since the wire is perpendicular to the magnetic field thus
F=I {l{B}
Let's check the options
If we change the angle between the current flow and the magnetic field from 90 to 75 or 60 degrees, F doesn't become 1/4 of its initial value. Hence options (d) & (e) is incorrect options.
Now if we decrease the current to 1/8 and increase the magnetic field to 4 times then force F becomes 1/2. Therefore option (a) is the incorrect option.
If we decrease the field to B/2 then the force becomes F/2.
Therefore (c) is also an incorrect option.
We are only left with option (b) which is the correct option.
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Two traveling sinusoidal waves are described by the wave functions
Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds
The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].
The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.
The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.
To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:
Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]
Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]
Y = 4.95sin[π(3.80x - 1180t - 0.206)]
The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.
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-- The given question is incomplete, the complete question is
"Two traveling sinusoidal waves are described by the wave functions
Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --
between each pair of vertebrae in the spinal column is a cylindrical disc of cartilage. Typically this dic has a radius of about 2.64cm and thickness about 1.17mm. The shear modulus of cartilage is 1.2*10^7 N/m^2. Suppose a shearing force of magnitude 14 N is applied parallel to the top surface of the disc while the bottom surface remains fixed in the palace. How far does the top surface move relative to the bottom surface
The top surface moves relative to the bottom surface by 1.167 x 10⁻⁶ m.
What is the displacement of the surface?The distance the top surface move relative to the bottom surface is calculated as follows;
shear strain = F/(αx)
where;
F is shearing forceα is the shear modulus x is thicknessshear strain = (14 )/(1.2 x 10⁷ x 0.00117 m)
shear strain = 0.000997
The movement of the top surface;
top surface movement = shear strain x thickness
= 0.000997 x 0.00117 m
= 1.167 x 10⁻⁶ m
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What covers the earth that is found at the upper most layer of the earth's crust
Answer:
The uppermost layer of the Earth's crust is called the soil. It covers the entire Earth and is composed of a mixture of organic matter, minerals, water, and air. The composition and properties of the soil vary depending on the location, climate, and vegetation. Soil plays an essential role in supporting plant life and providing nutrients for crops to grow. It is also critical for water retention and filtration, erosion control, and carbon sequestration. Understanding the properties of soil is important for agricultural, environmental, and industrial practices.
Select one of the agents of socialization as the one that you think has had the
greatest impact on defining who you are and write a well-developed paragraph
explaining how it has impact on your life and helped define who you are.
Among the many agents of socialization, the one that has had the most significant impact on defining a person's identity is the family. Growing up in a family shapes a person's values, beliefs, attitudes, and behavior patterns.
The family provides the foundation for a child's socialization process, and the experiences a child has in the family can determine their outlook on life.
For example, if a child is raised in a family that values education, they are more likely to value education and strive for academic success. Likewise, if a child is raised in a family that values honesty and integrity, they are more likely to uphold these values in their interactions with others. The family is also responsible for providing emotional support, which can impact a child's mental health and self-esteem. Overall, the family is the most critical agent of socialization as it shapes a person's identity from a very young age and sets the foundation for their future relationships and interactions with society.
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Describe the role of reflection and interference in creating standing waves.
Answer:
Explanation:
These incident and reflected waves pass each other, going in opposite directions. Interference results in a standing wave, i.e., a stationary wave pattern equal to the sum of the incident and reflected waves.
A rocket launches into space and continues to travel at a certain speed and a certain direction. Which of the following could alter this rockets speed or direction?
A.) The rocket travels near a planet
B.) The rocket rotates as it travels
C.) The rocket runs out of fuel
D.) The rocket changes shape
Answer:
A, C, and D could alter this rocket's speed or direction.
A) The rocket traveling near a planet could alter its speed or direction due to the gravitational pull of the planet.
B) The rocket rotating as it travels would not change its speed or direction, but it could change the orientation of the rocket's engines or thrust, which could affect its trajectory.
C) The rocket running out of fuel would cause it to slow down or stop moving, which would obviously alter its speed or direction.
D) The rocket changing shape could alter the way air or other particles interact with the rocket, which could affect its speed or direction. For example, if the rocket expanded in size, it would encounter more resistance in its path, which could slow it down or change its direction.
Therefore, the correct answer is A, C, and D.
Answer:
A, C, and D could alter the rocket's speed or direction.
A) The rocket traveling near a planet can alter its speed or direction due to the planet's gravity. This can cause the rocket to speed up, slow down, or change direction as it enters the planet's gravitational field.
C) If the rocket runs out of fuel, it will not be able to continue traveling at its current speed or direction. It may slow down, change direction, or come to a complete stop.
D) If the rocket changes shape, such as losing a piece of its body or encountering debris, this can alter its aerodynamics and affect its speed or direction.
B) The rocket rotating as it travels would not typically alter its speed or direction, as long as the rotation is not significant enough to affect its trajectory. The rocket's rotation could cause some minor changes in its orientation, but it would not significantly alter its speed or direction of travel.
An object that is 3.0 cm high is placed 18.0 cm in front of a concave mirror with a radius of curvature of 52.0 cm. Find the magnification and location of the corresponding image in relation to the mirrors surface.
Answer:
Explanation: To find the magnification and location of the image produced by a concave mirror, we can use the mirror equation:
1/f = 1/do + 1/di
where f is the focal length of the mirror, do is the distance from the object to the mirror, and di is the distance from the image to the mirror.
We can use the sign conventions for mirrors, where distances are positive when measured in the direction of light propagation and negative when measured in the opposite direction.
In this case, the object is located 18.0 cm in front of the mirror, so do = -18.0 cm. The radius of curvature of the mirror is 52.0 cm, so the focal length is f = R/2 = 26.0 cm.
Substituting these values into the mirror equation, we get:
1/26.0 = 1/-18.0 + 1/di
Solving for di, we get:
1/di = 1/26.0 - 1/-18.0
1/di = 0.0385
di = 26.0 cm / 0.0385
di = 675.3 cm
The negative sign for do indicates that the object is located in front of the mirror, while the positive sign for di indicates that the image is located behind the mirror.
To find the magnification of the image, we can use the magnification equation:
m = -di / do
Substituting the given values, we get:
m = -675.3 cm / -18.0 cm
m = 37.5
Therefore, the image produced by the concave mirror is located 675.3 cm behind the mirror and is magnified by a factor of 37.5.
The figure shows a circuit consisting of a 30V battery, a 5Ω resistor, and an open switch in series, with a parallel combination of a 7.5H ideal inductor and a 15Ω resistor. The switch is closed, and the circuit is allowed to reach steady state. What is the resulting steady-state current supplied by the battery?
Answer: E: 6.0
Explanation:
If the switch is closed, and the circuit is allowed to reach steady state. The resulting steady-state current supplied by the battery is 6 A, hence option E is correct.
How to find steady-state current?When the voltage across the resistor is equal to the battery voltage, we can use Ohm's Law to determine the steady state current. Where I is the current in amps and V is the voltage in volts.
At steady state, the equivalent circuit will look like there is no current flowing across the resistor because the inductor has zero resistance and behaves like a piece of wire that is short-circuited.
Due to the same potential difference across, the battery's steady-state current supply is,
i = e ÷ R
= 30 ÷ 5
= 6 A
Therefore, the resulting steady-state current supplied by the battery is 6 A.
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the distance that a body in free fall falls each second is
a. is about 9.8m
b. is about 19.6m
c. increases as time passes
d. none of the above are correct
The distance that a body in free fall falls each second is (A). is about 9.8m is correct option.
The distance that a body in free fall falls each second is about 9.8 meters, which is equivalent to the acceleration due to gravity on the Earth's surface.
This means that in the absence of air resistance, an object dropped from a certain height will fall 9.8 meters during the first second, 19.6 meters during the second second, 29.4 meters during the third second, and so on. The distance increases as time passes, but not at a constant rate, as it is being affected by the acceleration due to gravity.
Therefore, the correct option is (a) .
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A buoyant force acts in the opposite direction of gravity. According to Archimedes' Principle, which of the following is
true of an object completely submerged in water?
a. The magnitude of the upward buoyant force on the object is smaller than the weight of the fluid
displaced by the object.
b.
The magnitude of the upward buoyant force on the object is greater than the weight of the fluid
displaced by the object.
c.
The magnitude of the upward buoyant force on the object is equal to the weight of the fluid
displaced by the object.
d.
The object appears to weigh more than it does in air.
According to Archimedes' Principle, an object completely submerged in water experiences an upward buoyant force that is equal to the weight of the fluid displaced by the object. Therefore,
option C is the correct answer.
This principle states that any object placed in a fluid experiences a buoyant force, which is the result of the difference between the pressure on the top and bottom of the object.
If the buoyant force is greater than the object's weight, the object will rise to the surface, and if the buoyant force is less than the object's weight, it will sink.
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Which best describes a difference between energy transformations in power plants and dams?
Answer:
Only power plants use fossil fuels to transform energy. Only dams use fission to generate thermal energy.
Wayne Gretzky was gliding at 2.00 m/s [W] when he collided with Joel Otto who was gliding at 1.80 m/s [E]. After the head on collision, Gretzky ends up going at 1.00 m/s [E] and Otto at 0.100 m/s [E]. What is the ratio of the mass of Gretzky to the mass of Otto?
Answer:
Mass of Otto is approximately [tex](30 / 17)[/tex] times that of Gretzky.
Explanation:
Let [tex]m_{\text{G}}[/tex] and [tex]m_{\text{O}}[/tex] denote the mass of Gretzky and Otto. Let [tex]u_{\text{G}}[/tex] and [tex]u_{\text{O}}[/tex] denote their velocity before the collision. Let [tex]v_{\text{G}}[/tex] and [tex]v_{\text{O}}[/tex] denote their velocity after the collision.
By the conservation of momentum:
[tex]m_{\text{G}}\, u_{\text{G}} + m_{\text{O}}\, u_{\text{O}} = m_{\text{G}}\, v_{\text{G}} + m_{\text{O}}\, v_{\text{O}}[/tex].
Assume that [tex]m_{\text{O}} = k\, m_{\text{G}}[/tex] for some constant [tex]k > 0[/tex] denoting the ratio of mass between Otto and Gretzky. The equation for the conservation of momentum becomes:
[tex]m_{\text{G}}\, u_{\text{G}} + (k\, m_{\text{G}})\, u_{\text{O}} = m_{\text{G}}\, v_{\text{G}} + (k\, m_{\text{G}})\, v_{\text{O}}[/tex].
[tex]u_{\text{G}} + k\, u_{\text{O}} = v_{\text{G}} + k\, v_{\text{O}}[/tex].
Rearrange and solve for the ratio [tex]k[/tex]:
[tex]\begin{aligned}(v_{\text{O}} - u_{\text{O}})\, k = u_{\text{G}} - v_{\text{G}} \end{aligned}[/tex].
[tex]\begin{aligned}k = \frac{u_{\text{G}} - v_{\text{G}}}{v_{\text{O}} - u_{\text{O}}} \end{aligned}[/tex].
Let the East be the positive direction. Since it is given that the initial velocity of Gretzky is opposite to the East, the initial velocity of Gretzky would be negative: [tex]u_{\text{G}} = (-2.00)\; {\rm m\cdot s^{-1}}[/tex].
It is also given that [tex]u_{\text{O}} = 1.80\; {\rm m\cdot s^{-1}}[/tex], [tex]v_{\text{G}} = 1.00\; {\rm m\cdot s^{-1}}[/tex], and [tex]v_{\text{O}} = 0.100\; {\rm m\cdot s^{-1}}[/tex]. Substitute these values into the equation to find the ratio [tex]k[/tex]:
[tex]\begin{aligned}k &= \frac{u_{\text{G}} - v_{\text{G}}}{v_{\text{O}} - u_{\text{O}}} \\ &= \frac{(-2.00) - 1.00}{0.100 - 1.80} \\ &= \frac{30}{17}\end{aligned}[/tex].
In other words, the mass of Otto was [tex](30 / 17)[/tex] times that of Gretzky.
the student measure the massof he wooden block and found it to be =0.20kg.name the apparatus that can used to measure the mass ofthe wooden block
The apparatus that can used to measure the mass of the wooden block by the student is called beam balance.
A beam balance, often referred to as a double-pan balance, is a straightforward tool for determining an object's weight. Two pans or trays are hung from either end of a horizontal beam that is suspended from a pivot point in the middle.
The thing to be weighed is put on one tray, and then the second tray is filled with standard weights until it balances, showing the weight of the object. From little ones used in laboratories to larger ones used in enterprises, beam balances can be found in a variety of shapes and sizes. Because they are precise and operate without electricity or batteries, they are widely used.
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In the figure, the current Ibat in the battery is equal to:
A. 1₁/2
B. 2I1/3
C. I₁
D. 3I₁/2
E. 2I₁
The current Ibat in the battery is equal to I₁.
option C.
What is Kirchoff's current law ?
Kirchhoff's current law states that the sum of the currents entering any node in a circuit must equal the sum of the currents leaving that node. In other words, the total current flowing into a node or junction in a circuit must equal the total current flowing out of that node.
Based on Kirchhoff's current law, the current leaving I_bat must be equal to current entering R.
Based on the diagram, the current entering R = I₁, so the current that might have left the I_bat is I₁ is as well.
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On average, how much of a substance will decay after 1 half life?
Answer:
1/2 of the substance will decay
Explanation:
According to wikipedia: Half-life is the time required for a quantity (of substance) to reduce to half of its initial value.
So therefore, after one half life, half will decay.
earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________
earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.
What is energy?Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
The term earth's energy budget is also described as the balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.
The earth's energy budget was mainly three types as shown:
shortwave radiation, longwave radiation, and internal heat sources.Learn more about energy at:
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1. Two point charges, q1 and q2, are located 5 cm apart. The magnitude of q1 is 3 μC and the magnitude of q2 is -5 μC. What is the force between these charges, according to Coulomb's law?
The force between these charges, according to Coulomb's law would be -54 N.
We can solve this problem applying "Coulomb's Law" which states-
[tex]\qquad\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ [/tex]
[tex] \qquad\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]
Where-
q₁ and q₂ are the two cahrges.r is the distance between the charges.[tex]\sf \epsilon_{0} [/tex] is the permittivity of free space.K is the Coulomb's Constant.k = 9×10⁹ Nm²/C²According to the given parameters -
Magnitude of q₁= 3 μCMagnitude of q₂= -5 μCDistance,r = 5cmNow that required values are given, so we can plug the values into the formula and solve for Force -
[tex]\qquad\qquad \:\sf\underline{Force = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]
[tex] \longrightarrow \sf Force = 9\times 10^9 \times \dfrac{ 3\times 10^{-6}\times -5 \times 10^{-6}}{\bigg(5\times 10^{-2}\bigg)^2}\\ [/tex]
[tex] \longrightarrow \sf Force = -\dfrac{9\times 5\times 3\times 10^{9} \times 10^{-12}}{25\times 10^{-4}}\\ [/tex]
[tex] \qquad\longrightarrow \sf Force =- \dfrac{135 \times 10^{9-12+4}}{25}\\ [/tex]
[tex] \qquad\longrightarrow \sf Force = - \dfrac{\cancel{135}}{\cancel{25}}\times 10\\ [/tex]
[tex] \qquad\longrightarrow \sf Force = -5.4 \times 10\\ [/tex]
[tex] \qquad\qquad\longrightarrow \sf \underline{Force = \boxed{\sf{-54 N}}} \\ [/tex]
Henceforth, The force between these charges, according to Coulomb's law would be -54 N.'The cosmic microwave background allows us to talk about the "temperature of the universe." What is roughly the temperature of the universe today?
Answer:
Explanation:
The temperature of the universe today is roughly 2.7 Kelvin. This temperature is measured by the cosmic microwave background radiation, which is a remnant from the Big Bang.
Hello please I need help for this exercise
Calculate the electrical power dissipated by Joule effect in a 23 (Ohms) rheostat carrying a current of 5A.
Find the amount of heat, in Joules and Kwh, released in half an hour of operation.
The electrical power dissipated by the circuit is 575 W.
The amount of heat energy released in half hour is 0.2875 kWh.
What is the electrical power?
The electrical power dissipated by the circuit is calculated as follows;
P = IV
where;
I is the current in the circuitV is the voltageP = I²R
where;
R is the resistanceP = 5² x 23
P = 575 W
The amount of heat energy released in half hour is calculated as follows;
E = Pt
where;
P is the power dissipatedt is timeE = 575 W x 0.5 hr
E = 287.5 kW
E = 0.2875 kWh
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Which is the formula that describes the magnitude of an objects momentum?
Answer:
B. momentum = mass x velocity
Explanation:
P = mv
Give reason why relative density of a substance remains the same in both SI and CGS unit
Answer:As relative density is the ratio of similar quantities, it has no unit.So RD remains the same in both CGS and SI unit
Explanation: i did the test
