a) It takes the bicyclist 9.09 seconds to catch up to his friend.
b) The bicyclist has traveled 40.0 meters in 9.09 seconds to catch up to his friend.
c) The bicyclist is moving at a speed of 20.0 m/s when he catches up to his friend.
The Time, Distance and Speed involveda) To find out how much time it takes for the bicyclist to catch up to his friend, we need to use the equation for motion with constant acceleration:
d = v_0 t + 0.5 a t^2
where d is the total distance traveled,
v_0 is the initial velocity (0 m/s in this case),
t is the time, and a is the acceleration (2.2 m/s^2).
Since the friend was already moving at a constant speed of 4.0 m/s when the bicyclist started pedaling, we know that the total distance d that the bicyclist has to travel to catch up is equal to 4.0 m/s * t + 0.5 * 2.2 m/s^2 * t^2.
Setting d equal to 4.0 m/s * t, we can solve for t:
4.0 m/s * t = 4.0 m/s * t + 0.5 * 2.2 m/s^2 * t^2
0.5 * 2.2 m/s^2 * t^2 = 0
t = sqrt(0 / (0.5 * 2.2 m/s^2)) = 0 s
Since the square root of zero is zero, the time t is also zero. This means that the bicyclist starts moving at the same time as the friend, so he needs to accelerate for the entire time to catch up.
Using the equation for motion with constant acceleration, we can find the time t it takes for the bicyclist to catch up:
d = v_0 t + 0.5 a t^2
d = 4.0 m/s * t
4.0 m/s * t = 0 m/s * t + 0.5 * 2.2 m/s^2 * t^2
4.0 m/s = 0.5 * 2.2 m/s^2 * t
t = 4.0 m/s / (0.5 * 2.2 m/s^2) = 9.09 s
So it takes the bicyclist 9.09 seconds to catch up to his friend.
b) To find out how far the bicyclist has traveled in this time, we can use the equation for motion with constant acceleration again:
d = v_0 t + 0.5 a t^2
d = 0 m/s * 9.09 s + 0.5 * 2.2 m/s^2 * 9.09 s^2
d = 40.0 m
So the bicyclist has traveled 40.0 meters in 9.09 seconds to catch up to his friend.
c) To find out the bicyclist's speed when he catches up, we can use the equation for velocity:
v = v_0 + a * t
v = 0 m/s + 2.2 m/s^2 * 9.09 s
v = 20.0 m/s
So the bicyclist is moving at a speed of 20.0 m/s when he catches up to his friend.
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1.2 Determine the total displacement of the diagram in FIGURE 1. 123 m 20⁰ (3) 72 m
The total displacement of the diagram in the velocity-time graph is 55 m.
What is the total displacement?To find total displacement from a velocity-time graph, the area under the curve of the graph is calculated.
Considering the given figure:
The area under the velocity-time graph is composed of two triangles ABF & DCE having area A₁ & A₂ respectively, and a rectangle BEIF having area A3.
The area of A₁ = (2- 0) × (5 - 0)/2 = 5 m
The area of A₂ = (10 - 5) × (10 - 6)/2 = 10 m
The area of A₃ = (5 - 0) * (10 - 2) = 40 m
The total area under the curve = A₁ + A₂ + A₃
The total area under the curve = 5 + 10 + 40 =
The total area under the curve = 55 m
Therefore, the total displacement is 55 m.
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Find the momentum of a 0.0231 kg bullet fired at 621 m/s.*
A.0.0269 kg·m/s
B.14,200 kg·m/s
C.26.9 kg·m/s
D. 14.3 kg·m/s
Answer:
The momentum of a 0.0231 kg bullet fired at 621 m/s is calculated by multiplying the mass of the bullet by its velocity:0.0231 kg * 621 m/s = 14.3 kg·m/sSo the answer is D. 14.3 kg·m/s.
Explanation:
Formula for momentum:
[tex]p=mv[/tex]
momentum(measured in kg*m/s) = mass(measured in kg) * velocity(measured in m/s)
__________________________________________________________
Given:
[tex]m=0.0231kg[/tex]
[tex]v=621m/s[/tex]
[tex]p=?[/tex]
__________________________________________________________
Finding momentum:
[tex]p=mv[/tex]
[tex]p=0.0231\times621[/tex]
[tex]p=14.3kg*m/s[/tex]
__________________________________________________________
Answer:
[tex]\fbox{Option D}[/tex]
The figure showed a thin rod of length L and charge Q.
Find an expression for the electric potential a distance z away from the center of rod on the line that bisects the rod.
Give your answer in terms of L, Q, z and appropriate constants.
Expression for the electric potential a distance z away from the center of rod on the line that bisects the rod is [tex]V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx[/tex].
The electric potential at a distance z from a point charge Q is given by:
V = k * Q / r
here
k is Coulomb constant and
r is distance from the point charge to the point.
For a thin rod of length L and charge Q, we can model it as a line of charge with linear charge density λ = Q/L. The electric potential at a distance z away from the center of the rod on the line that bisects the rod can be found by breaking the rod into infinitesimal charge elements and integrating the electric potential due to each element over the length of the rod.
Let's consider a small element of length dx located at a distance x from the center of the rod:-
[tex]dQ = \lambda * dx = Q/L * dx[/tex]
The displacement element to pt.:-
[tex]r = \sqrt{(x^2 + z^2)}[/tex]
The electric potential due to this element is:
[tex]dV = k * dQ / r = k * Q/L * dx / \sqrt{(x^2 + z^2)}[/tex]
Integrating this expression over the length of the rod, we get the total electric potential at a distance z away from the center of the rod on the line that bisects the rod:
[tex]V = \int\limits^(^-^L^/^2^)_L_/_2 {k * Q/L * dx / √\sqrt{(x^2 + z^2)}} \, dx[/tex]
To evaluate this integral,
[tex]u = x^2 + z^2, du/dx = 2x dx[/tex],
This can be further simplified:-
[tex]u = z^2 * tan^2\theta + L^2/4 * sec^2\theta[/tex]
[tex]V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx[/tex]
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20. You accidentally throw your car keys horizontally at 6.0 m/s from a cliff 42 m high. How far from the base of the cliff should you look for your keys?
The keys will land 19.32 meters away from the base of the cliff.
How the solution was obtainedAssuming that there is no air resistance, the motion of the keys can be described using the equations of motion for constant acceleration.
The initial horizontal velocity of the keys is 6.0 m/s, and the vertical velocity is zero. The acceleration due to gravity is 9.8 m/s^2, and it acts vertically downwards.
The time taken for the keys to fall from the top of the cliff to the ground can be found using the equation:
h = 1/2 * g * t^2
where h is the height of the cliff (42 m), g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken.
Rearranging this equation to solve for t, we get:
t =√(2h/g)
t =√(2*42/9.8)
t = 3.22 s
During this time, the keys will have travelled a horizontal distance equal to their initial velocity multiplied by the time taken:
d = v * t
d = 6.0 * 3.22
d = 19.32 m
Therefore, the keys will land 19.32 meters away from the base of the cliff.
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Again, combining the heat equations with the heat flow equation, we find that the difference in the temperature between the sample (or Polly) and the cold bath followed an exponential decay, i.e., Tdir = (constant) - Setting time equal to 0 tells us that the prefactor (constant) out front simply is the initial temperature difference. Knowing the decay constant from the previous question and the temperature difference at some later time, then, we can find the time it takes for the difference between the sample's (Polly's) internal temperature and the bath's temperature to reach some specific value. According to the data you took at the (possible) crime scene and your answer to the previous problem, determine how many hours (to the nearest hour) Polly has been deceased (in hours, to the nearest hour)? Again, Polly's and the water bath's initial temperatures were 37°C and 2°C, respectively, and the final temperatures you measured were 13°C and 7°C. Hence, you could determine if foul play may have been involved (say, someone had been seen leaving Polly's apartment a certain time before her body was discovered). 18.703 As you are assisting in the investigation, you notice that Polly's apartment has maintained a cozy temperature even though her heat had been turned off and it's a cold winter's day. (Could this be another clue?) One explanation is that her apartment has nice double pane windows, consisting of two glass panes that are each 4-mm thick sandwiching a well-sealed air gap 6-mm thick. In "steady state", the rate that heat flows through a glass pane equals the rate that heat flows through the air gap in the double pane window (otherwise there would be a net heat flow into the air or window, changing its temperature -- whatever flows into one of these materials must flow out to maintain a given temperature). Since the thermal conductivity of still air (0.025 W/(mºC)] is much smaller than the thermal conductivity of glass (0.80 W/(m°C)], the temperature difference across the double pane window is almost entirely over the air gap. (Again, in this steady state, the rate of heat flow through the glass and air are the same for the double pane window, so if the conductivity of air is much smaller than that of glass, the temperature difference across the air must be much larger than that across the glass for these windows.) Considering this, what is the ratio of the rate of heat flow through a cheap window with a single pane of glass 4-mm thick compared to a nicer double pane window with an air gap of 6 mm if the temperature difference across them is the same (and they have the same areas)? Neglect heat leaks at the edges of the windows.
the ratio between the rate of heat flow through a cheap window with a single pane of glass that is only 4 mm thick to a nicer double pane window with an air gap of 6 mm is 76.6667.
K[tex]_{glass}[/tex]=0.80 W/m°C
K[tex]_{air}[/tex]=0.025 W/m°C
Q=[tex]\frac{\triangle T}{R_{Th} }[/tex]
(R[tex]_{Th}[/tex])[tex]_{double pane}[/tex]×Q[tex]_{double pane}[/tex]=(R[tex]_{Th}[/tex])[tex]_{single pane}[/tex]×Q[tex]_{single pane}[/tex]
(R[tex]_{Th}[/tex])[tex]_{double pane}[/tex]=∑[tex]\frac{l}{KA}[/tex]
= [tex]\frac{3}{0.8A} +\frac{7}{0.025 A}+\frac{3}{0.8 A}\\[/tex]
=[tex]\frac{287.5}{A}[/tex]
(R[tex]_{Th}[/tex])[tex]_{single pane}[/tex]=[tex]\frac{3}{0.8A}[/tex]=[tex]\frac{3.75}{A}[/tex]
[tex]\frac{Q_{single pane} }{Q_{double pane}} =\frac{R_{Th}_{double pane} }{R_{Th}_{single pane}}[/tex]
= 76.6667
Heat flow, also known as heat transfer, is the movement of thermal energy from a region of higher temperature to a region of lower temperature. This occurs due to the random motion of atoms and molecules within a material. There are three main mechanisms of heat flow: conduction, convection, and radiation. Conduction is the transfer of heat through a material by direct contact, while convection involves the movement of a fluid (such as air or water) due to temperature differences. Radiation is the transfer of heat through electromagnetic waves, such as from the sun or a fire. Heat flow is a fundamental concept in thermodynamics and plays a critical role in many fields, including engineering, physics, chemistry, and biology.
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The first active volcano observed outside the Earth was discovered in 1979 on Io, one of the moons of Jupiter. The volcano was observed to be ejecting material to a height of about 3.00×105m
Given that the acceleration of gravity on Io is 1.80m/s2 find the initial velocity of the ejected material.
The material that was thrown out had an approximate initial velocity of 1.50-10⁵ m/s.
How can the ejected material's initial velocity be determined?The following equation can be used to determine the ejected material's initial velocity under gravity's constant acceleration:
y is equal to v₀ x t x (1/2) a x t₂, where:
The values for y, a, and t are as follows: y is the vertical displacement (height) of the ejected material (3.00 10⁵ m); a is the acceleration caused by gravity on Io (1.80 m/s²); t is the time it takes for the ejected material to reach its maximum height (let's assume it is equal to 2 seconds for simplicity).
3.00×10⁵ m = v₀ ×2 s + (1/2) × 1.80 m/s² × (2 s)²
3.00×10⁵ m = v₀ × 2 s + 1.80 m/s² × 4 s²
3.00×10⁵ m = v₀× 2 s + 7.2 m/s²
v₀ = (3.00×105 m - 7.2 m/s²) / 2 s
v₀ = (3.00×105 m - 7.2 m/s²) / 2 s
v₀ = 1.50×10⁵ m/s
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Quick someone please help this was already due and I need to go to bed plssssssss
The number of amino acids different between sequence 1 and sequence 2 is 2.
The translations of sequence 1 and sequence 2 are different because:
Sequence 1 and 2 have different nucleotide sequencesWhat are nucleotides?Nucleotides are the building blocks of nucleic acids, such as DNA and RNA. They consist of a nitrogenous base, a sugar molecule (ribose or deoxyribose), and a phosphate group. The nitrogenous bases in nucleotides can be adenine, guanine, cytosine, or thymine (in DNA) or adenine, guanine, cytosine, and uracil (in RNA).
Nucleotides are linked together to form long chains, which make up the backbone of nucleic acids. The sequence of nitrogenous bases in nucleotides determines the genetic information stored in DNA.
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12. A truck travelling at 110 km/h has to cover a distance of 640 km in the next 6 hours. Will the driver be on time if he can hold his current speed? (4 marks)
Answer:
calculate the expected time of arrival, we need to divide the total distance by the speed of the truck.
In this case, the expected time of arrival would be:
640 km ÷ 110 km/h = 5.82 hours
So the driver should be able to arrive at the destination within 6 hours if he can hold his current speed.
• Point A - the instant before the figure drops. It is at rest and the spring is not stretched.
• Point B - an instant when the figure is falling. It is lower than its original position, and
moving downwards, but the spring has not yet begun to stretch.
• Point C - the very last instant for which the figure is falling but the spring has not yet
begun to stretch.
• Point D - an instant when the figure is falling and the spring is stretching.
Point E - the instant at which the figure has reached its lowest position and is
momentarily motionless before rebounding.
Fill out Table 2 below to show how energy is transferred between forms during the
drop. In each box write either Maximum, Zero, Increasing, or Decreasing.
The magnitude of the GPE depends on the position of the object.
How does the GPE change as the object is falling?Some parts of the question appears to be missing but I will try to answer generally.
As an object falls, its gravitational potential energy (GPE) decreases.
Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. The GPE of an object is directly proportional to its mass, the acceleration due to gravity, and its height above a reference level. The formula for gravitational potential energy is:
GPE = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the reference level.
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A simple circuit contains a 9 V battery connected with wires to a small light bulb. If the current through the bulb is 0.025 A, what is the resistance of the bulb?
Group of answer choices
360 ohms
15 ohms
127 ohms
0.225 ohms
Answer:
[tex]\huge\boxed{\sf R = 360\ ohms}[/tex]
Explanation:
Given data:Potential Difference = V = 9 V
Current = I = 0.025 A
Required:Resistance = R = ?
Formula:V = IR (Ohm's Law)
Solution:V = IR
Divide I to both sides
[tex]\displaystyle \frac{V}{I} = R[/tex]
Put the given data
9/0.025 = R
360 ohms = R
OR
R = 360 ohms[tex]\rule[225]{225}{2}[/tex]
Prove that AxB = B.A
Unless A=B or unless either A or B is the empty set, AxB does not equal BxA. Students typically have no trouble understanding this because we define a cartesian product as an ordered pair, which implies that order would be important.
What is the parameter for solving cartesian product?A plane's cartesian form is denoted by the formula ax + by + cz = d, where a, b, and c are the direction cosines normal to the plane and d is the distance from the origin to the plane.
If and only if the matching initial elements in both ordered pairs are the same, two ordered pairs are said to be equivalent. (ii) There will be mn elements in A B if there are m elements in A and n elements in B. This means that n(A B) if n(A) = m and n(B) = n.
Therefore, When the inner inverse fulfils P R (B ) B (A B) = 0 and (A B) B P R (B) = 0, it is implied that is closed and is the general solution.
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____help the body change food into energy and repair and replace old and damaged parts.
Answer: Vitamins
Explanation:
A wheel is formed from a hoop of mass 2.6 kg
and seven equally spaced spokes, each of mass
0.11 kg. The hoop’s radius is the length
0.73 m of each spoke.
0.11 kg
2.6 kg
0.73 m
Find the moment of inertia of the wheel
about an axis through its center and perpendicular to the plane of the wheel.
Answer in units of kg · m2
. Answer in units
of kg · m2
.
The moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.09 kg·m^2.
What is the parallel axis theorem?The moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel can be calculated by using the parallel axis theorem, which states that the moment of inertia of a rigid body about any axis is equal to the moment of inertia about a parallel axis through the center of mass plus the product of the mass and the square of the distance between the two axes.
Here in the Question,
First, we need to find the moment of inertia of the hoop about an axis through its center and perpendicular to the plane of the hoop. This is a well-known result from basic mechanics and is given by:
I_hoop = 1/2 * m_hoop * r^2
where m_hoop is the mass of the hoop and r is its radius. Substituting the given values, we get:
I_hoop = 1/2 * 2.6 kg * (0.73 m)^2 = 1.26 kg·m^2
Next, we need to find the moment of inertia of a single spoke about an axis through its center and perpendicular to its length. This is also a well-known result from basic mechanics and is given by:
I_spoke = 1/12 * m_spoke * L^2
where m_spoke is the mass of the spoke and L is its length. Since the spokes are equally spaced around the hoop, we can consider a single spoke and multiply its moment of inertia by 7 to account for all the spokes. Substituting the given values, we get:
I_spoke = 1/12 * 0.11 kg * (0.73 m)^2 = 0.005 kg·m^2
Therefore, the moment of inertia of all the spokes combined is:
I_spokes = 7 * I_spoke = 0.035 kg·m^2
Finally, we can use the parallel axis theorem to find the moment of inertia of the entire wheel about an axis through its center and perpendicular to the plane of the wheel:
I_wheel = I_hoop + I_spokes + 7 * m_spoke * r^2
Substituting the given values, we get:
I_wheel = 1.26 kg·m^2 + 0.035 kg·m^2 + 7 * 0.11 kg * (0.73 m)^2 = 2.09 kg·m^2
Therefore, The wheel's moment of inertia about an axis passing through its center and perpendicular to its plane is 2.09 kg·m^2.
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What is the gauge pressure in atm at point p , where the needle meets the wider body of the syringe? the pressure at the exit of the needle is 1. 0 atm.
The water gauge pressure at location P is;
P p = 104525 Pa
We have been provided;
L = 4 cm = 0.04 m needle length
Water's viscosity; = 1 10(-3) Pa
r = 1 mm = 0.001 m Radius
v = 10 m/s is the speed.
The flow rate via a cylindrical pipe may be calculated using Poiseuille's equation for viscous liquid flow.
Q = (ΔP•πr⁴)/(8ηL)
Flow rate is now also written as;
Q = πr²v
Thus;
πr²v = (ΔP•πr⁴)/(8ηL)
This boils down to;
v = (ΔP•r²)/(8ηL)
Inserting the necessary values;
10 = (ΔP × 0.001²)/(8 × 10^(-3) × 0.04)
ΔP = (10 × 8 × 10^(-3) × 0.04)/(0.001²)
ΔP = 3200 Pa
This implies that;
P atm - P p = P
Where;
P p is the water gauge pressure at point P.
P atm is atmospheric pressure, which equals 101325 Pa.
Thus;
P p - 101325 = 3200
P p = 101325 + 3200
P p = 104525 Pa
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Calculate the distance between the center of the earth and the center of the moon at which the gravitational force exerted by the earth on an object is equal in magnitude to the force exerted by the moon on the object
( solution)
At the neutral point, the distance between the Earth's center and the Moon's center is about 399,000 kilometers, or 3.989 x 10⁸ meters.
What is the force of gravity?Planets, stars, and galaxies all move because it is one of the fundamental forces of the universe. According to Newton's law of gravitation, the distance between two objects and their masses determine the magnitude of the gravitational force
We can make use of the fact that the gravitational force between two objects is inversely proportional to the square of the distance between their centers and proportional to the product of their masses to calculate this distance. As a result, we can solve for the distance by setting the force of gravity that the Earth exerts on the object to be equal to the force of gravity that the Moon exerts on the object.
The masses of the Earth and the Moon, M_E and M_M, respectively, and the distance between their centers, d. The following factors determine the Earth's gravitational pull on the object:
F_E is equal to G × M_E × m / (d₂), where m is the mass of the object and G is the gravitational constant. The following factors determine the Moon's gravitational pull on the object:
F_M = G × M_M × m / ((R-d)²)
where R is the distance between the centers of the Earth and Moon
Setting F_E equal to F_M, we get:
G × M_E × m / (d²) = G × M_M × m / ((R-d)²)
Simplifying and solving for d, we get:
d = R × (M_E / (3 × M_M))¹/³
Values for the masses and the radius of the Earth-Moon system (R = 3.844 x 10⁸ meters), we get:
d = 3.989 x 10⁸ meters
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At the end of the day, you remember that pulling up on an object will make it easier to slide the object. Using this knowledge you decide to move your 3000 N Grand Piano using a rope. You pull the rope so that it provides an upward force of 900 N and a horizontal force of 1600 N. What is the coefficient of kinetic friction if the piano is being bulled at a constant speed?
The coefficient of kinetic friction is approximately 0.533.
What is the coefficient of kinetic friction?
To find the coefficient of kinetic friction, we can use the equation of the force of friction, which is given by:
f_friction = friction_coefficient x f_norm
where;
f_friction is the force of friction, friction_coefficient is the coefficient of kinetic friction, and f_norm is the normal force.Since the piano is being pulled at a constant speed, the net force on the piano must be zero, which means that the sum of the forces must be equal to zero:
f_net = f_horizontal - f_friction = 0
friction_coefficient = f_friction / f_norm
= (f_horizontal) / (f_norm)
= (1600 N) / (3000 N) = 0.533
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8. In which of the following situations is the kinetic energy of the object decreasing?
A. A sphere is dropped from a building.
B. A satellite moving is a circular motion around the earth.
C. A baseball is heading upward after being thrown at an angle.
D. An elevator is moving upward at a constant velocity
The answer is option C. A baseball is heading upward after being thrown at an angle.
What is kinetic energy?Kinetic energy is a type of energy associated with motion. It is defined as the energy an object possesses due to its motion, and is dependent on both the object's mass and its velocity. The formula for kinetic energy is KE = 1/2 mv^2, where m is the mass of the object and v is its velocity.
Kinetic energy can be transferred between objects, and is often involved in collisions and other interactions. For example, when a moving object collides with another object, some of its kinetic energy may be transferred to the second object. Kinetic energy is an important concept in physics and is used in many real-world applications, such as in the design of vehicles, machines, and athletic equipment.
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In which direction will heat naturally flow?
from an object at 40°C to an object at 20°C
from an object at 40°C to an object at 40°C
from an object at 40°C to an object at 80°C
from an object at 0°C to an object at 100°C
Heat will naturally flow from an object at 40°C to an object at 20°C.
What is heat?Heat is described as the energy that is transferred from one body to another as the result of a difference in temperature.
Heat will naturally flow from an object at a higher temperature to an object at a lower temperature. So in the above scenario, heat will naturally flow from an object at 40°C to an object at 20°C.
In conclusion, the basic concept of thermodynamics states that heat will flow spontaneously from a higher-temperature body to a lower-temperature body in order to equalize the temperatures of the two bodies.
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In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these situations, two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Assume that the pivot is attached tot he center of the bar. You are to find the angular acceleration of the seesaw when it is set in motion from the horizontal position. In all cases, assume that m1>m2.
Now consider a similar situation, except that now the swing bar itself has mass mbar.(Figure 2)
Find the magnitude of the angular acceleration ? of the seesaw.
Express your answer in terms of some or all of the quantities m1, m2, mbar, l, as well as the acceleration due to gravity g.
The rotational acceleration and speed are shared by all of the points of a rigid body. As a result, the angular acceleration is positive and the rotation is anticlockwise.
A- 2*[(m1 - m2)/(m1 + m2)] *g/L The angular acceleration is positive and the rotation is anticlockwise. (m1 - m2)/(m1+ m2 + mbar/3) B- 2* *g/L The angular acceleration is positive and the rotation is anticlockwise.
(A) The magnitude of angular acceleration of the seesaw in this case is .
2(m₁-m₂)g÷(m₁+m₂)L
(B) The magnitude of angular acceleration of the seesaw in this case is
(m₁ g-m₂ g)÷(m₁+m₂)L
For a massless sea saw bar, with attached masses at each end, the torque produced due to the masses is,
ω=(m₁+m₂)+1/2
And, moment of inertia of the system of two masses is,
I=(m₁+m₂)L/4
The using the expression of torque as,
Angular acceleration is the term used to describe the temporal pace at which angular velocity varies. Radians per second is the accepted unit of measurement. Therefore, = d d t. Angular acceleration is also known as rotational acceleration.
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1. Which of the resistors are in parallel connection? Which of the resistors are in series connection?
Answer:
Explanation: In a series circuit, the output current of the first resistor flows into the input of the second resistor; therefore, the current is the same in each resistor. In a parallel circuit, all of the resistor leads on one side of the resistors are connected together and all the leads on the other side are connected together.
If the actual mass of the products from the reaction was 120 g , what was the percent yield of the reaction?.
According to the question This gives us a percent yield of 150%.
What is percent yield?Percent yield is a measure used in chemistry to calculate the efficiency of a chemical reaction. It is expressed as a percentage and is calculated by comparing the actual yield of a product obtained in a reaction to the theoretical yield, which is the maximum amount of product that could have been produced.
The percent yield of a reaction is the ratio of the actual yield of the reaction to the theoretical yield of the reaction multiplied by 100.
Therefore, to calculate the percent yield, we need to first calculate the theoretical yield of the reaction. We can do this by multiplying the given mass of reactants, in this case 80 g, by the stoichiometric coefficient of the desired product, which is 1.
This gives us a theoretical yield of 80 g.
Now, to calculate the percent yield, we divide the actual yield, which is 120 g, by the theoretical yield, which is 80 g, and multiply by 100.
This gives us a percent yield of 150%.
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During the vietnam war, journalists _____. Select two choices. Called the military's press briefings "five o'clock follies" accepted the u. S. Government's justification for the war could not interview american soldiers while serving did not witness any combat on a firsthand basis.
During the Vietnam War, journalists often referred to the military's press briefings as "five o'clock follies" because they felt that the information provided was often incomplete or misleading.
The two choices that are correct are:
•Called the military's press briefings "five o'clock follies"
•Did not witness any combat on a firsthand basis.
. Additionally, due to the dangers of the conflict, many journalists did not have the opportunity to witness combat on a firsthand basis.
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A jogger runs on the track shown in the figure.
Neglecting the curvature of the corners, what is the distance traveled and the displacement in running from point A to point B?
(part a)
Find the distance and displacement for a complete circuit of the track.
(part b)
A) 130m for distance, 100m for displacement
B)260m for distance, 0m for displacement
Distance is the sum of all movement taken from start to finish, regardless of position or direction. Since we are going from point A, which is halfway through the 30m side, to point B, which is also halfway through another 30m side, we divide both by 2 and add them together to get 30m once more. Then we take into account the long side of the track, measuring 100m, and can decide that the total distance is 130m.
The displacement, however, doesnt take into account the extra 15m travelled on either of the short sides of the track. When talking about displacement, we are only looking at the distance BETWEEN point A and point B, not the real distance travelled to get to them. Think of it as if youve drawn a line between both points and are mesuring that line and that line only. Because that line would have the exact length as the long side of the track, we can decide that the displacement is 100m.
For part B, the distance is easy to find as we just add up all sides of the track. The tricky part is understanding why displacement is zero. Like I said earlier, it's easiest to imagine a line drawn between both points of mesurment when talking about displacement. In this case, we are talking about the jogger leaving from point A and returning to point A. As I'm sure youve guessed, we cannot possibly draw a line between point A to point A, therefore making the displacement 0.
I'm sorry this is a lot of writing, but I, myself, had a lot of difficulty wrapping my head around the concept of displacement and wanted to make sure it was easy to understand. Hope this helps
QUESTION 3 Consider a block of mass 6 kg on a rough plane inclined at 25° to the horizontall A force, F of magnitude 37,173 N is applied to this block to keep it moving at a constant velocity 6 kg 25 what is the normal force
The normal force is 53.3 N.
What is the normal force on an object?We have to note that the force that is acting on the object may be a single force or a system of forces. In this case, the force that is acting on the object would have many components including the normal force.
You must note that the normal force is the force that in a direction that is opposite to the weight of the object but does have the same magnitude as the weight of the object.
Thus we can see that the normal force is obtained from;
R = mgcosθ
m = mass
g = acceleration due to gravity
θ = angle
R = 6 * 9.8 * cos 25
R = 53.3 N
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There are various stages in the formation of coal as heat and pressure are increased and moisture content is decreased. These stages, in order, are
bituminous, peat, lignite, anthracite
bituminous, peat, lignite, anthracite
A
peat, lignite, bituminous, anthracite
peat, lignite, bituminous, anthracite
B
peat, lignite, anthracite, bituminous
peat, lignite, anthracite, bituminous
C
lignite, bituminous, anthracite, peat
lignite, bituminous, anthracite, peat
D
anthracite, bituminous, peat, lignite
Correct order in formation of coal as heat and pressure are increased and moisture content is decreased is (B) peat, lignite, bituminous, anthracite.
Peat is the first stage in the formation of coal, and is made up of partially decomposed plant material with a high moisture content. As heat and pressure are increased, the moisture content decreases and the plant material becomes more compressed, leading to the formation of lignite. Lignite is a low-grade coal with a relatively low carbon content, and is often referred to as brown coal.
With further increases in heat and pressure, lignite is transformed into bituminous coal, which has a higher carbon content and is often used for electricity generation. Finally, with even greater heat and pressure, bituminous coal is transformed into anthracite, which is the highest grade of coal and has the highest carbon content.
The stages of coal formation are important to understand because different types of coal have different uses and properties. For example, anthracite is often used for heating because it burns very cleanly and efficiently, while bituminous coal is often used for electricity generation because it has a higher energy content.
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Two charged objects are separated a distance d as shown. The angle between the line joining the objects and the horizontal is 30°. Consider the (x,y) coordinate system with origin at the location of object 2. (Part a) Calculate 7 2,1, the position vector of object 1 measured from object 2. Express your answer in terms of hati for i, hatj for j, and d as needed. Remember that the argument of sin and cos in answer boxes needs to be entered in radians. 72,1 = (Part b) Calculate r 2,1, the unit vector pointing in the direction from object 2 to object 1. Express your answer in terms of hati for i, ha and d as needed. tj for i † 2,1 = (Part c) Calculate the force on object 1 due to the interaction with object 2. Express your answer in terms of hati for i, hatj for j, d, k, q_1 for qı and q_2 for 22 as needed. 72,1 = Submit You have used 0 of 10 attempts Save
Two charged objects are separated a distance d, the position vector of the object 1 with respect to the object 2 is P21 = d/2(√3i -j).
It is assumed in the problem that the origin is taken into account when determining the position of object 2. As a result, we may decompose the position vector of object 1 into its x and y components.
So, we can see from the diagram that the position vector's horizontal component is dcos30. This component is known as the x component because it lines up with the positive x axis. Hence, x=dcos30. Once more, dsin30 is the vertical component of the position vector. This component is known as the y component because it is congruent with the negative y axis. Hence, y=dsin30.
As a result, the position vector can be expressed as,
⇒P21=xi^+y(−j^)
The values P21=dcos30i+dsin30(j) are substituted
Now, the values of cos30 are 3-1/2 and sin30 are 12.
In order to substitute the values, we obtain P21=3-2di12dj.
Now, if we take the common, we get P21 = d/2(√3i -j).
This is the position vector of the object 1 with respect to the object 2.
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How many g's of force will a nascar driver experience making a 80 m/s turn with a
radius of 200 meters?
3.2 g's
32 g's
2.5 g's
25 g's
3.27 g's of force will be applied to the driver during the turn.
What in science is a force?In science, the term "force" has a particular definition. At this time, it is appropriate to refer to a force as a push or a pull. There is no such thing as a power that something "contains" or "has in it." A force is exerted on one item by another.
We must employ the centripetal acceleration formula to resolve this issue:
a = v² / r
In this case, the velocity is 80 m/s and the radius is 200 meters, so:
a = (80 m/s)² / 200 m = 32 m/s²
To convert this to g's, we divide by the acceleration due to gravity:
32 m/s² / 9.8 m/s²/g = 3.27 g's (rounded to two decimal places)
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Car A is driving 21.4 m/s in the positive x-direction according to an observer standing stationary on the side of the road. Car B is driving on the same road with a velocity of 27.4 m/s, as observed by a passenger in Car A. What is Car B's velocity as observed by the person on the side of the road?
Car B's velocity as observed by the person on the side of the road is -6.0 m/s, which means that it is moving in the negative x-direction.
explain about velocity ?
Velocity is a physical quantity that describes the rate of change of an object's position with respect to time. In other words, it is the speed and direction of an object's motion. Velocity is a vector quantity, which means that it has both a magnitude (or size) and a direction.
the relative velocity formula, which gives the velocity of one object as observed by another object or observer:
velocity of B with respect to observer = velocity of B with respect to A + velocity of A with respect to observer
In this problem, we have:
velocity of A with respect to observer = +21.4 m/s (positive because it is in the positive x-direction)
velocity of B with respect to A = -27.4 m/s (negative because it is in the opposite direction to A's velocity)
(Note that we use a negative sign for the velocity of B with respect to A because they are moving in opposite directions.)
Using the formula, we get:
velocity of B with respect to observer = -27.4 m/s + 21.4 m/s = -6.0 m/s
Therefore, Car B's velocity as observed by the person on the side of the road is -6.0 m/s, which means that it is moving in the negative x-direction.
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A box with weight of 10000 pounds is held 25 miles above the Earth. What is the box's potential
energy in kip-feet? one kip = 1000 pounds (Remember that weight in pounds already accounts for
acceleration due to gravity.)
The potential energy of the box is 4180 kip-ft.
What is potential energy?Potential energy is described as the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
The potential energy of an object can be calculated using the formula:
PE = mgh
In the scenario,
the mass of the box is m = 10000 pounds and
the height above the ground is h = 25 miles = 25 * 5280 feet = 132000 feet.
The acceleration due to gravity is g = 32.2 ft/s^2.
Substituting these values into the formula, wehave:
PE = mgh = 10000 * 32.2 * 132000 = 4.18 x 10^8 ft-lb
Converting this to kip-ft,
PE = 4.18 x 10^8 ft-lb / 1000 = 4180 kip-ft
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A ball is thrown toward a cliff of height h with a speed of 33 m/s and an angle of 60∘ above horizontal. It lands on the edge of the cliff 4.0 s later.
Answer: I am assuming you're asking for the cliff height, which is 24M
We can use the kinematic equations to find the horizontal and vertical components of the ball's velocity and its final position.
The initial velocity components are:
v_x = 33 m/s * cos(60∘) = 28.6 m/s
v_y = 33 m/s * sin(60∘) = 33 * √3/2 m/s
The displacement components can be found using the kinematic equation:
x = v_x * t = 28.6 m/s * 4.0 s = 114.4 m
y = v_y * t - 0.5 * g * t^2 = 33 * √3/2 m/s * 4.0 s - 0.5 * 9.8 m/s^2 * (4.0 s)^2 = 102.4 m - 78.4 m = 24.0 m
The ball lands on the edge of the cliff, so its height must be equal to h, or:
y = h
24.0 m = h
So, the height of the cliff is 24.0 m.
