Answer:
0.4
Explanation:
ω = km
ω = 1000 x 4
ω = 4000 divide this by 10000 and you get 0.4s
suppose the velocity of a particle is given by the equation, V=m+nt2, where m=10cms and n=2cm/s3.
A, find the change in velocity of the particle in the initial time interval b/n t₁=2sec and t₂=5sec
B, find the average acceleration in this time interval
C, find the instantaneous acceleration at time t₁=2sec
Hello!
Begin by plugging in the values for m and n. We get the equation for the velocity of the particle to be:
[tex]v(t) = 10 + 2t^2[/tex]
A.
To find the change in velocity over the interval (2s ≤ t ≤ 5s), we can simply find the difference in the velocities at these times.
[tex]\Delta v= v_f - v_i[/tex]
For this situation:
[tex]\Delta v = v(5) - v(2)[/tex]
Substitute these times for 't' into the equation and solve.
[tex]v(5) = 10 + 2(5^2) = 60 \frac{cm}{s}\\\\v(2) = 10 + 2(2^2) = 18 \frac{cm}{s}\\\\\Delta v = 60 - 18 = \boxed{42 \frac{cm}{s}}[/tex]
B.
To find the average acceleration, we must take the SLOPE of the velocity function over this interval using the slope formula:
[tex]a_{avg} = \frac{v_f - v_i}{\Delta t}[/tex]
Plug in the values for the particle's velocity at t = 2 s and 5 s that we solved for above.
[tex]a_{avg} = \frac{60- 18}{5 - 2}\\\\a_{avg} = \frac{42}{3} = \boxed{ 14 \frac{cm}{s^2}}[/tex]
C.
The instantaneous acceleration can be found by taking the derivative of the v(t) function using the power rule. Recall:
[tex]\frac{dy}{dx} x^n = nx^{n-1}[/tex]
Using this rule:
[tex]a(t) = v'(t) = 2(2t) = 4t[/tex]
Substituting in t = 2 s:
[tex]a(2) = 4(2) = \boxed{8 \frac{cm}{s^2}}[/tex]
The three waves shown in the picture below are equal in wavelength, but are travelling at different speeds. Given this information, which wave has the highest frequency?
Select one:
a. 1
b. 2
c. 3
d. Can't tell from the information given.
Wave 3 will have the highest frequency. Option c is correct.
What is the frequency?
Frequency is defined as the number of repititions of a wave occurring waves in 1 second.
Frequency is given by the formula as,
[tex]\rm v = \lambda \times f[/tex]
If the wavelength of the wave is content the velocity of the wave is directly propotional to the frequency.
The velocity of wave 3 is maximum. So that the wave 3 will have the highest frequency.
Hence option c is correct.
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Helium is the second most abundant element on Jupiter (and in the Universe overall). But it's rare on Earth, being only 0.0005% of the atmosphere. Why is this?
A) Jupiter's stronger gravity results in a faster escape velocity, and almost no helium atoms are moving fast enough to escape its gravity. Earth's escape velocity is lower, so a few helium atoms at a time are moving fast enough to escape, causing Earth to slowly lose its helium.
B) Jupiter's core continually generates helium, while the Earth's core does not.
C) Jupiter has a powerful magnetic field that can attract helium atoms. Earth has a magnetic field as well, but it's not strong enough.
Answer:
Explanation:
Comment
I think the best answer is probably A. It's not the best reason for Earth loosing it's helium, but it is the only one that is close. The Earth derives some of its Helium (most) by the decomposition process of radio active high weight chemical that break down. Helium combines with practically nothing so once it gets moving, very little will stop it. That's the way we loose our Helium.
Still answer A.
A hollow conducting sphere has an inside radius of r1 = 0.17 m and an outside radius of r2 = 0.28 m. The sphere has a net charge of Q = 4.8E-06 C. What is the magnitude of the field, in newtons per coulomb, at a distance of 0.05 m from the center of the sphere?
Explanation:
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all elements in the same group have the same number of?
electrons
energy levels
electrons in the outermost energy level
bonds
All elements in the same group have the same number of electrons in the outermost energy level. Option C is correct.
What is a periodic table?The periodic table is an organization of all known elements in order of increasing atomic number and repeating chemical characteristics.
They are organized in a tabular format, with a row representing an era and a column representing a group. E elements are ordered in increasing atomic number order from left to right and top to bottom.
Thus, Elements of the same group will have the same valence electron configuration and, as a result, will have comparable chemical characteristics.
Each set of elements has an equal amount of electrons in the outer orbital. Valence electrons are another name for the outer electrons.
They are the electrons interacting with other elements in chemical bonding. Each element in group one, the first column, has one electron in its outer shell.
Hence option C is correct.
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suppose a uniform electric field 4 N/C is in the positive x-direction .
The magnitude of the electric field at x =4m on the x axis at this time 1 N/C.
Electric field at position 4 mElectric field at a given distance is calculated as follows;
E = kq/r²
E₂ = (9 x 10⁹ x q)/(2²)
E₂ = 2.25 x 10⁹q
E₂ + E₀ = 0
2.25 x 10⁹q + 4 = 0
2.25 x 10⁹q = - 4
q = -4 / (2.25 x 10⁹)
q = -1.78 x 10⁻⁹
E₄ = (9 x 10⁹ x (-1.78 x 10⁻⁹) ) / (4²)
E₄ = - 1 N/C
|E₄| = 1 N/C
Thus, the magnitude of the electric field at x =4m on the x axis at this time 1 N/C.
The complete question is below:
Suppose a uniform electric field of 4N/C is in the positive x direction. When a charge is placed and at a fixed to the origin, the resulting electric field on the x axis at x =2m becomes zero. What is the magnitude of the electric field at x =4m on the x axis at this time?
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which of the following statements is true about the suns energy and earth
The correct statement about the sun and the earth is that only about half of the suns energy hits the earths surface.
What is the sun?The sun is the source through which energy reaches the earth. The sun is a large star that produces energy by the process of nuclear fusion.
Hence, the correct statement about the sun and the earth is that only about half of the suns energy hits the earths surface.
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How many minutes would be required for a 300.0 W (i.e., power=energy per second=300 J/s)
immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C? (Note: The specific heat of water
is 4184 J/kg°C)
Hence, the time required is approximately equal to 4 minutes and 39 seconds.
Given, Power, P = 300 W= 300J/s
Power= Energy per second
Mass, m= 0.25 kg
Initial Temperature= 20.0°C
Final Temperature= 100.0°C
Temperature difference, T =( 100-20)°C= 80.0°C
Specific heat of water, S= 4184 J/kg°C
Energy can be represented as
E=mST
where E is the energy, m is the mass, S is the specific heat of water and T is the temperature difference.
As Energy can be written as the product of time and power, E=Pt
Pt=mST
So,
t=(msT)/P
t=(0.25×4184×80)/300
Time, t = 278.934 seconds= 4 minutes and 39 seconds.
Hence, 4 minutes and 39 seconds will be required for a 300.0 W immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C.
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5, the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
Explanation:
hi
please help me. ineed answers
Gerund/Infinitive
1. Put the verbs in brackets into the correct infinitive form or the -ing form.
1. Jane went on____(sleep) for another two hours.
2. He told us his name and went on____ (introduce) us to his wife.
3. She tried (finish) her homework, but it was too difficult.
4. You should try (eat) more fruit. It's good for your health.
5. He regrets (argue) with his best friend.
6.We regret (inform) you that tonight's performance will be cancelled.
7. Oh, no! I forgot____(lock) the front door.
8. I'll never forget_(meet) my favourite film star.
9.Claire likes (ski). She says it's very exciting.
10. I like__(go) to the dentist every six months.
11.I must remember (post) these letters today.
12. I remember__(read) the book, but I don't know who wrote it.
13. I'm sorry for___(forget) your birthday. It was awful of me.
14. I'm sorry.(say) that you have failed the exam.
15. She is afraid___(climb) the tree in case she falls.
16.Mary never wears her diamond ring. She is afraid of (lose) it.
17. I have stopped . (buy) some food before continuing our journey.
18. We stopped (watch) horror films because they give me nightmares
19. Tom stopped__(pick up) his washing on the way home.
20 If you don't stop. (smoke), you'll make yourself ill.
21.Will you quit___(complain)! It doesn't help.___(solve) the problem.
22.If you ever decide___(sell) your car, let me____(know).
23.I would like you.__(water) the plants for me at the weekend.
24.I clearly remember__(set) my alarm clock before__(go) to bed last night.
25. These plants require(water) every day.
26. I resent you (speak) to me like that! Have some respect.
27. It would be good for the children__ (play) outdoors more often.
28. I promised __(take) Jill to the party, but I don't feel like__(go) now.
29. Don't waste your time (look for) the document.Ask Mr Gale.
30. Please, excuse his__(leave) so early. He wants __(catch up) with his (study).
31. Try__(phone) John at the office if he's not at home.
32. I tried my best__(finish), but there just wasn't enough time.
33. He was promoted in 1990 and went on__(become) a company director.
34. The band went on__(play) even after the lights had gone out.
35. "Why is the baby crying?" "I think he wants (feed)."
36. Sharon wants__(talk) to you.
37. Jane was afraid__(show) her school report to her parents.
38. I'm afraid of__(lose) my way in the forest.
39. I regret__ (inform) you that your husband has been arrested.
Compute the speed of sound waves in air at room temperature (T=200C) and find the range of wavelengths in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive. The mean molar mass of air (a mixture of principally nitrogen and oxygen) is 28.8 x 10-3kg/mol and the ratio of heat capacity is ϒ = 1.40.
The speed of sound waves in air at room temperature T=20° is 344.035 m/s.
The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is 17.20 m to 0.0172 m.
What is wavelength?The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.
Wavelength λ = c/f
where c is the speed of sound wave.
Given the room temperature T = 20 +273 = 293K
The velocity of sound wave is given by
v = √(γRT/m)
where γ =1.4 , m = 28.8×10⁻³ kg/mol R = 8.31 J/K.mol
Substituting the values, we get
v = 344.035 m/s
Thus, the speed of sound wave is 344.035 m/s
The human ear can hear frequencies in the range of 20 – 20,000Hz.
The wavelength corresponding to 20Hz is
λ = c/f
λ = 344.035 /20
λ = 17.20 m
The wavelength corresponding to 20,000Hz is
λ = 344.035 /20000
λ = 0.0172 m
Thus, the range of wavelength is 17.20 m to 0.0172 m sensitive to human ear.
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A body moves in an x-y plane with a velocity vm/s. The component of v are Vx=5m/s, Vy=7m/s along x and y axis respectively. What is the magnitude and direction of the velocity
the answer is in the picture ok
good luck don't worry it's a correct
#carry on learning
pleaseeeeeee I need HELP in 20 mins,Asap!!!
A 6.00 -kg clay ball is thrown directly against a perpendicular brick wall at a velocity of 22m/s^2 and shatters into three pieces, which all fly backward. The wall exerts a force of 2640N on the ball of for 0.1s. One piece of mass 2kg travels backward at a velocity of 10m/s and an angle of 32° above the horizontal. A second piece of mass 1kg travels at a velocity of 8m/s and an angle of 28° below the horizontal. What is the velocity of the third piece?
The velocity of the third piece is 124.02 m/s at 1.05⁰ below the horizontal.
Velocity of the third piece
The velocity of the third piece is calculated from the principle of conservation of linear momentum.
mu = m₁u₁ + m₂u₂ + m₃u₃
where;
m is mass of the clayu is velocity of the clayu₁ is velocity of first pieceu₂ is velocity of second pieceu₃ is velocity of third piecem₃ is mass of the third piece = 6 kg - (2 kg + 1 kg) = 3 kgMomentum in y - direction6(22)sin(0) = 2(10)sin32 - 1(8)sin(28) + 3u₃y
0 = 6.84 + 3u₃y
u₃y = -6.84/3
u₃y = -2.28 m/s
Change in momentumΔP = Pf - Pi = J
where;
Pf is final momentumPi is the initial momentumJ is impulse2640(0.1) = 2(10)cos32 + 1(8)cos(28) + 3u₃x - 6(22)
264 = -108 + 3u₃x
3u₃x = 372
u₃x = 372/3
u₃x = 124 m/s
Resultant velocityu₃ = √(124² + 2.28²)
u₃ = 124.02 m/s
Direction of the velocitytanθ = u₃y/u₃x
tanθ = 2.28/124
tanθ = 0.018
θ = 1.05⁰ (below the horizontal)
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What is the gravitational potential energy of a 15.0kg object that is 5.00m above the ground relative to a point 8.00m above the ground?
-441J
735J
-735J
441J
Explanation:
an object's gravitational potential energy Eg is m×g×h where:
m=mass
g=9.8m/s²
h=height relative to the closest object below it (because it cannot potentially fall through it
so Eg = 15×9.8×5=735J
A grocery cart is pushed with a force of 21.4 N. If 1,974 J of work is done in pushing the grocery cart through the store, what is the total distance that the grocery cart has traveled?
Answer:
Given - Force = 21.4 N
Work done = 1974 J
To find - Distance
Solution -
Work done = Force * displacement
1974 j = 21.4 N * displacement
1974/21.4 = displacement
92.24
[tex]\\ \rm\Rrightarrow Work=Force\times Displacement [/tex]
[tex]\\ \rm\Rrightarrow 1974=21.4×Displacement[/tex]
[tex]\\ \rm\Rrightarrow Displacement=92.24m[/tex]
Point P is on the rim of a wheel of radius 2.0 m. At time t = 0, the wheel is at rest, and P is on the x-axis. The wheel undergoes a uniform
angular acceleration of 0.01 rad/s² about the centre
Answer:
r = 2.0m
when t = 0, the angular displacement is zero.
Explanation:
When the angular acceleration is 0.01 m/s2, you can calculate
angular acceleration = change in angular velocity/ time
A pendulum swings to and fro every 2.0 s. The period of the swing is.
O 2 Hz
2 s
O 0.5 s
O 0.5 Hz
Answer:
Explanation:
Solution
In physics, a period is a measurement of time. The answer must be either B or C. It is a direct measurement of time, not its reciprocal. So the answer is B. A and D is a measurement of the actual cycle that it takes before the motion begins to repeat itself.
Answer
B
10 precautions for obtaining the refractive index of a triangular glass prism.
Answer:
Following precautions for obtaining the refractive index of a triangular glass prism:-
Explanation:
(1) All the faces of the prism should be neat and clean.
(2) Pins for holding the paper on the drawing board must be pinned perpendicular to the paper for better handling.
(3) While fixing the pins for checking the refractive index of the prism, make sure that the reflective images of the pins should be aligned to your eye to avoid any type of parallax error.
(4) Pins should not be removed or pinned again during the experiment.
(5) Avoid mishandling of the prism.
(6) Same edge of the prism should be taken as vertex for observations.
(7) For drawing the boundary of the prism, a sharp pencil should be used.
(8) Soft board and pointed pins should be used.
(9) The distance between the pins should be 5 cm or more.
(10) Make sure the glass slab or prism taken are polished and not broken.
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Question 3 of 10
The Moon has much less gravitational force than Earth. What would happen
if you went to the Moon?
OA. Your mass would decrease.
O
B. Your weight would increase.
O
C. Your mass would increase.
O
D. Your weight would decrease.
SUBMIT
Answer:
D
Explanation:
Mass is the amount of matter your body has ....does not change on the Moon.
there is less gravity .....so your WEIGHT would decrease
What is the mass of an object if it has 915J of energy when it is 6.50m above the ground?
A.851kg
B0.0696kg
C.583kg
D.14.4kg
Answer:
D
Explanation:
GPE = mgh
GPE / gh = m
m = GPE/gh
m = 915 / 6.5 x 9.8
m = 915 / 63.7
m = 14.4kg
identity the sentence that uses quotas and interviews.
A. let us all learn from the history of our country.
B. the guests arrived on time.
C. "My dream is to build my own mansion, "Adrian answered.
D. Teacher Cellyn Kyre ensures that her classroom is always ready for the face to face classes
Teacher Cellyn Kyre ensures that her classroom is always ready for the face to face classes is the sentence used in quotas and interviews.
What is interview?Interview is the examination of the candidate from which a person identifies the candidate is fit for the organization o r not. Maximum interview happened between the interviewer and the candidate. or sometime more people can also be present.
Thus, option D is correct.
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A rocket is fired with an initial Velocity OF 100m/s at an angle OF 55 above the horizontal, It explodes on the mountain Side 12s after its Firing What is x-and y-coordinates of the rocket relative to its Firing point?
Answer:
( 688.29 , 276.66 ) meters
Explanation:
Break into horizontal and vertical components
x = 100 cos 55 = 57.36 m/s
the x coordinate is then 12 seconds * 57.36 m/s = 688.29 meters
y coordinate is a bit more complex because of the curved path due to gravity
Original y velocity = 100 sin 55
y = vo t - 1/2 (9.81)(t^2)
y = 100 sin 55 (12) - 1/2 (9.81) (12)^2
yf = 276.66 meters
How to magnetic stripes provide evidence of seafloor spreading
Magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.
How to magnetic stripes provide evidence of seafloor spreading?When the Earth's magnetic field reverses, a new stripe starts to form. Such magnetic patterns enable the scientist to recognize the occurrence of sea-floor spreading and provides strongest evidence for the theory of plate tectonics.
So we can conclude that magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.
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A penny is dropped so that it reaches a terminal velocity of 13.3m/s. If the momentum is measured to be 0.0332kgm/s, what is the mass of the penny
Answer:
2.5 grams
Explanation:
p = mv
m = p/v
m = 0.0332 / 13.3
m = 0.0025kg
0.0025 x 1000 = 2.5
m = 2.5g
yhisriyftt
carzy and want one g come 6x 10-1'coulomb or one unit. The ratio, mass for each of the particle is 9.58 x 10" per gram. Hence, the mass
After the terrorist attacks of September 11th, 2001, the National Center on the Psychology of Terrorism was founded to research psychological aspects of terrorism. This is an example of how __________ affect theories and perspectives in psychology.
A.
current events
B.
new discoveries
C.
oppositions
D.
personal ideologies
what are risk factors of an autoimmune disease
Explanation:
Your Sex. Overall, 78% of people affected by autoimmune disease are female (1). ...Genetics. Certain disorders, such as lupus and multiple sclerosis, tend to run in families (3, 4). ...Having an autoimmune disease. ...Obesity. ...Smoking and Exposure to Toxic Agents. ...Certain Medications. ...Infections.
On Earth, a scale shows that you weigh 490 N. What is your mass?
A 50 kg
B 100 kg
c) 75 kg
D 22 kg
Answer:
a
Explanation:
A radioactive contaminant gives an unfortunate lab rat a dose of 1500 rem in just 1 minute. Assuming that the half life of the radioactive isotope in the contaminant is much longer than 1 minute.What would the activity of the contaminant be if the contaminant is 1.1MeV Beta Emitter?
The activity of the contaminant will be 3.5 ×10⁻¹⁰ Bq if the contaminant is 1.1MeV Beta Emitter.
Disclaimer, here the m is taken as 0.5kg.
Given, REM = 1500
Time, t= 1 minute =60 seconds
For beta particles,
RBE (Relative Biological Effectiveness) =2.
Absorbed dose, D =REM/RBE= 1500/2 = 750rad
As 100 rad=1 J/kg,
750 rad=7.5 J/kg
So, D=7.5 J/kg
D= total energy absorbed (E)/mass (m)
7.5 J/kg=E/m
E =7.5 ×0.5 = 3.75J
Therefore, the number of beta particles absorbed is 3.75 J.
The number of beta particles absorbed,
As 1 MeV= 1.6 ×10⁻¹³J
So, converting 1.1 MeV in J, 1.1×1.6 ×10⁻¹³J=1.76×10⁻¹³J
Numbers of beta particles,
n=3.75J/1.76×10⁻¹³J
n=2.13×10⁻¹²
Hence, the number of beta particles is 2.13×10⁻¹².
Activity, A= n/t
where n is the number of beta particles and t is the time.
A= n/t=(2.13×10⁻¹²)/60
A= 3.5 ×10⁻¹⁰ Bq
So, the activity is 3.5 ×10⁻¹⁰ Bq.
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PLEASE HELP!! 50 points. The answer is not 2.6 m/s.
Answer:
A
Explanation:
5.2mm/s
hope this helps
p ⇒ q, r ⇒ s, p ∨r q ∧ s is invalid
Answer:
My explanation and answer are down here↓:
Explanation:
p→q is false only when p is true and q is false.
∴p→(q∨r) is false when p is true and (q∨r) is false, and
q∨r false when both q,r are false.
Hence T,F,F.
