Which of the rays drawn above would be correct as the light goes from the air into the water?
Answer:
the answer to this question is option c
there process which eventually takes place is called refraction
Explanation:
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Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3P4 (s) → 3P4O10 (s) + 10 KCI (s) How much of each reactant will be needed to produce 105.8 g of tetraphosphorus decaoxide (P4O10)?
Answer:
m(P4) = 46.175 (grams)
m (KClO3) = 149 (grams)
Explanation:
1) n(P4) = n(P4O10);
m(P4)/M(P4) = m(P4O10)/M(P4O10);
m(P4) = M(P4)*m(P4O10)/M(P4O10)
= 123.90*105.8/283.89
= 46.175 (grams)
2) Analogously, 10n(P4O10) = 3n(KClO3)
m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
= 10*122.55*105.8/283.89/3
= 149 (grams).
149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .
What do you mean by reactant?In a chemical equation, the substance or substances to the left of the arrow are referred to as reactants. A substance that is present when a chemical reaction first begins is known as a reactant.
Products refer to the material or substances to the right of the arrow. A substance that is present after a chemical reaction is complete is called a product.
Given Data:
m(P4) = 46.175 (grams)
m (KClO3) = 149 (grams)
Then it is given by:
1) n(P4) = n(P4O10);
m(P4)/M(P4) = m(P4O10)/M(P4O10);
The equation becomes :
m(P4) = M(P4)*m(P4O10)/M(P4O10)
= 123.90*105.8/283.89
= 46.175 (grams)
2) Analogously, 10n(P4O10) = 3n(KClO3)
m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
= 10*122.55*105.8/283.89/3
= 149 (grams).
Thus, 149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .
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Calculate the frequency of a sound wave produced when a tennis racquet string is plucked. The tension of the string is 274 N, the mass of the string is 28 kg and the length of the string is 0.74 m.
Answer:
Explanation:
The velocity of sound from the plucked string in the tennis racquet is:
[tex]v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}[/tex]
Then the frequency will be:
[tex]f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz[/tex]
Physics Help anyone?
Hi there!
A)
At this point, the pilot is experiencing a DOWNWARD NET centripetal force (ALWAYS points towards the center of the circle) as well as a downward force due to gravity. Additionally, we can say that the normal force exerted by the seat on the pilot is its apparent weight.
[tex]\Sigma F = F_g + F_N[/tex]
**The net force is the centripetal force.
We can assign both to be positive since they work in the same direction. (Assigning down as positive in THIS situation will make things easier).
We know that:
[tex]F_c = \frac{mv^2}{r}[/tex]
Fc = Centripetal force (N)
m = mass (kg)
v = velocity (m/s)
r = radius (m)
[tex]F_g = mg[/tex]
Fg = Force due to gravity (N)
m = mass (kg)
g = acceleration due to gravity (9.81 m/s²)
Solve for mass. (Given weight)
[tex]m = \frac{F_g}{g}\\\\m = \frac{719}{9.8} = 73.367 kg[/tex]
Now, we have everything we need to solve.
[tex]\frac{mv^2}{r} = F_g + F_N \\\\\frac{mv^2}{r} - F_g = F_N\\\\F_N = \frac{(73.367)(225^2)}{3110} - 719 = \boxed{475.278 N}[/tex]
B)
Weightlessness is achieved when the pilot is in free fall. In this instance, FN (Normal force by the seat) = 0 N.
We can use the same setup as above.
[tex]\frac{mv^2}{r} = F_g + 0 (F_N)[/tex]
[tex]\frac{mv^2}{r} = mg[/tex]
Solve for 'v'.
[tex]\frac{v^2}{r} = g\\\\v = \sqrt{gr} = \sqrt{(9.81)(3110)} = \boxed{174.669 \frac{m}{s}}[/tex]
C)
At the BOTTOM, we have the force of gravity working DOWNWARD (Negative in this instance), while the centripetal force (NET FORCE) and normal force are upward (Positive). Do another summation of forces:
[tex]\Sigma F = F_N - F_g\\\\\\frac{mv^2}{r} + F_g = F_N \\\\F_N = \frac{(73.367)(225^2)}{3110} + 719 = \boxed{1913.278 N}[/tex]
The three types of cones in the human eye are
a
red, yellow, green
b
red, green, blue
c
red, blue, cyan
d
yellow, cyan, magenta
Answer:
the answer is B I hope it helps out
An aquarium heater transfer 1200kJ of the heat to 75000g of water. What is the increase in the waters temperature?
Answer:
Energy = mcΔt
where m the mass , c specific heat capacity
Δt is the change in temperature
1200x10^3=75x4184xΔt
Δt=3.82°
Explanation:
QUESTION 9
What determines the evolutionary path a star takes through its life?
O a. Diameter
O b. Who made it
O c. Color
O d. Mass
Answer:
Mass
Explanation:
In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015
a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported
Answer:
Explanation:
You can calculate the total electric charge that passes through the conductor as [tex]q=It=(180\times 10^{-3})(5\times 60)= 54 C[/tex]. It means that the number of electron that passes through the conductor is:
[tex]n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}[/tex]
A 10-cm long solenoid has 100 turns and a radius of 5 cm. If it carries a current of 2 A, What is the magnetic field B inside the solenoid
Hi there!
We can use Ampère's Law:
[tex]\oint B \cdot dl = \mu_0 i_{encl}[/tex]
B = Magnetic field strength (B)
dl = differential length element (m)
μ₀ = Permeability of free space (T/Am)
Since this is a closed-loop integral, we must integrate over a closed loop. We can integrate over a rectangular-enclosed area of the rim of the solenoid - ABCD - where AD and BC are perpendicular to the solenoid.
Thus, the magnetic field is equivalent to:
[tex]\oint B \cdot dl = \int\limits^A_B {B} \, dl + \int\limits^B_C {B} \, dl + \int\limits^C_D {B} \, dl + \int\limits^D_A {B} \, dl[/tex]
Since AD and BC are perpendicular, and since:
[tex]\oint B \cdot dl = B \cdot L = BLcos\phi[/tex]
[tex]BLcos(90) = 0[/tex]
If perpendicular to the field, the equation equals 0.
Additionally, since AB is outside of the solenoid, there is no magnetic field present, so B = 0. The only integral we integrate now is:
[tex]\oint B \cdot dl = \int\limits^C_D {B} \, dl[/tex]
Which is horizontal and inside the solenoid. Let the distance between C and D be 'L', and the enclosed current is equivalent to the number of loops multiplied by the current:
[tex]B L = \mu_0 Ni[/tex]
N = # of loops per length multiplied by the length, so:
[tex]BL = \mu_0 nL i \\\\B = \mu_0ni[/tex]
Plug in the given values and solve. Remember to convert # of loops to # of loops per unit length.
[tex]B = \mu_0 (100/0.1)(2) = (4\pi *10^{-7})(1000)(2) = \boxed{0.00251 T}[/tex]
An object moving in a straight line has a velocity v in m/s that varies with time t in s according the following function. v= 8+2.5 12 to 11. The instantaneous acceleration of the object at t = 2 sis (A) 2 m/s (B) 4 m/s (0) 6 m/s2 D) 8 m/s2 (E) 10 m/s2 12. The displacement of the object between t = 0 and t = 6 s is (A) 120 m (B) 180 m (C) 228 m (D) 242 m (E) 260 m
The instant acceleration of the object is 10 m/s² and the displacement of the object is 228 m.
Instantaneous acceleration
The instant acceleration of the object is determined by taking the derivative of the velocity as follows;
v = 8 + 2.5t²
a = dv/dt
a = 5t
a(2) = 5(2)
a(2) = 10 m/s²
Displacement of objectThe displacement of the object is determined by taking the integral of velocity as follows;
v = 8 + 2.5t²
x = ∫v
x = 8t + 2.5t³/3
x(0) = 0
x(6) = 8(6) + 2.5(6)³/3
x(6) = 228 m
Thus, the displacement of the object is 228 m.
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a bag of rocks has a mass of 16.4 kg what is it weight here on the earth
find the half life of a radioactive natural which decays to 6.25% of it's original no. of nuclei in 50 seconds.
Answer:
After 1 decay it has .9375 of its value left
.9375^n = 1/2
What is the value of n (number of decays)
n log .9375 = -.693
n =.693 / .0645 = 10.7
After 10.7 periods of 50 sec it will have 1/2 of its original nuclei left
1/2 life = 10.7 * 50 sec = 537 sec = 8.95 min
- A teenage male is removing clothes from the dryer and is having difficulty because the items are
sticking together.
-What force is causing the clothes to stick together?
-What two factors in the dryer operation has produced this situation?
-What will misting the clothes with a light spray of water do?
We can confirm that the clothes are sticking together due to static forces created by the heat and friction of the dryer.
How will water help with this situation?The clothes are stuck together due to static forces that arise when these materials are heated and the friction from the dryer cycle. Adding a light spray of water can help with this situation given that water is a strong conductor of electricity, which will help to dispel the charges that hold the clothes together.
Therefore, we can confirm that clothes are sticking together due to static forces created by the heat and friction of the dryer, which a light spray of water can help to dispel and separate the clothes.
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When a speeding truck hits a stationary car, the car is deformed and heat is generated. What can you say about the kinetic energy of the system after the collision?
nothing
Explanation:
we can say that it was certainly bad for the shopkeeper obviously and we should not be making questions about the physics behind that accident and should call the cops or 911
How long does it take a photon to escape the sun?
Answer:
About 5000 years.
Explanation:
Answer:
Explanation:
it will take more than half a million years for the photon to escape the sun. If you think it's about a centimeter, then it will take about 5,000 years for the photon to get outside the su
The reasoning question please i need help
Answer:
speed of the friend that is 8m from the center:
0.8π m/s
the distance she will travel in one rotation is:
10
Her speed compared to you is faster because, she is farther away from the axis compared to you.
Explanation:
for the speed, it says the farther you are from the axis the greater your speed is, and for the person who was 4m from the axis of rotation their speed was 0.4 because they are closer to the axis so therefore their speed is slower. so for the friend that is 8m from the axis of rotation its most likely their speed would be 0.8 m/s.
in one revolution you travel 8m your original distance from the axis was 4m so, 8-4 = 4, which means one revolution is plus 4 to your original distance. since the question is asking for rotation and not revolution you can do 4 ÷ 2 which is 2, so for rotation you need to add 2 to your original distance, so 8 + 2 = 10
During a phase change,the temperature remains constant although heat is still being added. what is the best explanation for what the heat energy is being used to do
During the phase change in which heat is being added but the temperature remains constant, the heat energy is used to break the bonds in the molecules.
What is a phase change?A phase change is the conversion of one state of matter to another. e.g. solid to liquid or liquid to gas.
Substances can exists in three states namely;
solidgaseousliquidIn a change of phase, heat energy is needed to break the existing bonds between the molecules of the initial state. For example, heat energy is needed to break the bonds of ice to form water.
However, during this phase change, the temperature remains constant.
Therefore, during the phase change in which heat is being added but the temperature remains constant, the heat energy is used to break the bonds in the molecules.
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Q19. Convert 2.05 x 10^5 seconds into years
Explanation:
no. of seconds in a year = 60 × 60 × 24 × 365
= 31,536,000 seconds
so 2.05 × 10⁵ into years = 0.0065 years (approximately)
why do fennec fox have big ears? explain why in big detail!
Answer:
Explanation:
The fennec may be the world's smallest fox, but it sports outlandishly large ears! In fact, relative to body size, it has the largest ears of any member of the canid family. It uses those big ears to listen for sounds of prey in the sand. The ears also help dispel body heat to keep the fox cool.
A simple circuit has a voltage of 8V and a current of 3A. Find the resistance (R) in the
circuit.
Answer:
2.67 ohm
Explanation:
V=IR
R=V/I
In which V is voltage and I is current and R is resistance
Mrs. Martin is holding a ball from a height of 3.2 m that has the potential energy of 23 J, calculate the mass of the ball.
Answer:
0.73kg
Explanation:
Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.
Substitute:
[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]
Difine Ripple Factor
-,- ty!!
Answer:
The answer is in the picture above.
Two children are playing tetherball, in which a ball at the end of a cord spins around a pole. After a really good hit, the ball makes three complete revolutions in 2.0 s. What is the angular speed of the ball?
Answer:
3 pi R / s or 9.42 R/s or 540 degrees/sec
Explanation:
Ball covers 2 pi radians each rotation
2 pi * 3 R / 2 s = 3 pi R / s
the angular speed of the ball is 3 pi R / s or 9.42 R/s or 540 degrees/sec
What is angular speed ?Angular speed can be defined as the measures of speed of how fast the central angle of a rotating body changes with respect to time
Angular speed mainly implies how quickly the rotation of an object occur means it is described as the change in the angle of the object per unit of time.
To calculate the speed of a rotational motion the angular speed value need to be known, hence The angular speeds formula is used to calculate the distance traveled by an object in terms of rotation and revolutions per unit of time.
The unit of angular speed of an object is radian per second and Both angular speed, angular velocity are determined by using the same formula, angular velocity is vector quantity which describes both magnitude and direction.
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Two horses pull horizontally on ropes attached to a stump. The two forces Fu and F2 that they apply to the stump are such that the net (resultant) force R has a magnitude equal to that of Fu and makes an angle of 90° with Fu. Let F1 = 1300 N and R = 1300 N also. Find the magnitude of F and its direction (relative to Fi)
For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as
F=1711 N
dF= 135 degrees
What is the magnitude of F and its direction?
Generally, the equation for the components of F1 is mathematically given as
For The x axis
1210 - F2x = 0
F2x = 1210
For the y axis
F2y = R
F2y = 1210
In conclusion
F = sqrt(2)*1210
F=1711 N
Fopt the direction of F2
dF= 90 + 45
dF= 135 degrees
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Yesterday you walked 20 meters to the right from your house to the bus stop, which took you 20 seconds. You waited at the bus stop for 1 minute before realizing you forgot your Mathematics homework at home. You ran back to your house in 5 seconds. It took you 10 seconds to find your homework, and then you ran back to the bus stop in 5 seconds just in time to catch the bus. What was your average velocity for the entire period of motion?
a.
0.2 m/s
b.
1 m/s
c.
100 m/s
d.
20 m/s
average velocity= tot displacement/total time
avg v = 20/(20+60+5+10+5)=20/100=0.2 m/s
What is the average acceleration of a me
that reaches 24 m/s in 5.5 seconds?
F 0.20 m/s2
G 2.5 m/s
H 10 m/s2
J 208 m/s
Answer:
See below
Explanation:
Assuming starting from zero velocity
vfinal = at
24 = a (5.5)
a = 4.36 m/s^2 I think part of your question is missing....what was the initial velocity?
A single coil of wire, with a radius of 0.13 m is rotated in a uniform magnetic field such that the angle between the field vector and the area vector obeys θ=ωt. If the strength of the field is 3.746 T, and the angular frequency is 524.7 rad/s, what is the induced emf in the loop at t=1.16 s?
The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.
The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.
emf = N(dФ/dt)
where;
N is number of turns of the wireФ is magnetic fluxФ = BA
where;
B is magnetic field strengthA is the area of the loopemf = NBA/t
A = πr²
A = π x (0.13)²
A = 0.053 m²
emf = NBA/t
emf = (1 x 3.746 x 0.053)/(1.16)
emf = 0.171 V
Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.
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3. Hahn determined that barium (atomic number 56) was one of the elements created when a uranium atom (atomic number 92) split . Use a periodic table to determine the other element that was created during this process.
According to a periodic table, Krypton was created during the fission of Uranium.
What is the atomic number?
Atomic number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.
Thus, the fission of uranium is led by two elements with atomic numbers 56 and 36. According to a periodic table, those atomic numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.
According to a periodic table, Krypton was created during the fission of Uranium. [tex]\blacksquare[/tex]
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a 56-kg student runs at 6.2m/s, grabs a hanging 10.0m long rope, and swings out over a lake. He releases the rope when his velocity is zero.
a) what is the tension in the rope just before he releases it?
b) what is the maximum tension in the rope during the swing?
Answer:
0.52 8.9
Explanation:
calc.
The tension in the rope just before the student releases it is 576 N.
What is tension?Tension is defined in physics as the pulling force transmitted axially by a string, rope, chain, or similar object.
Just before the student releases the rope, his velocity is zero. At this point, all of his kinetic energy has been converted into potential energy. Therefore, we can write:
1/2 m [tex]v^2[/tex] = mgh
h = [tex]v^2[/tex] / (2g) = [tex](6.2 m/s)^2[/tex] / (2 x 9.8 [tex]m/s^2[/tex]) ≈ 1.95 m
m g = 56 kg x 9.8 [tex]m/s^2[/tex] ≈ 549 N
The tension required to keep the rope taut is equal to the horizontal component of the force due to the weight of the student, which is:
T = m g / cos(θ)
tan(θ) = h / L
tan(θ) = 1.95 m / 10.0 m ≈ 0.195
θ ≈ 10.9°
So, T = m g / cos(θ) ≈ 576 N
To find the maximum tension in the rope during the swing, we can use conservation of angular momentum.
L = I ω
I = (1/3) m [tex]L^2[/tex]
I = (1/3) x 10.0 kg x [tex](10.0 m)^2[/tex] ≈ 3333.3 kg[tex]m^2[/tex]
The angular velocity of the rope just after the student releases it is:
ω = v / L
ω = 6.2 m/s / 10.0 m ≈ 0.62 rad/s
L = I ω ≈ 2070 N m s
Thus, the angular momentum of the system just after the student releases the rope is 2070 N m s.
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When is an object positively charged?
Answer:
when it has a fewer amount of electrons than protons
