a bolt is dropped from a bridge under construction, falling 90 m to the valley below the bridge. (a) in how much time does it pass through the last 20% of its fall? what is its speed (b) when it begins that last 20% of its fall and (c) when it reaches the valley beneath the bridge?

The direction of the force on the particle due to the magnetic field a charged particle is moving is perpendicular to the plane.

Glamorous fields ply forces on moving charges. This force is one of the most introductory known. The direction of the glamorous force on a moving charge is vertical to the aeroplane formed by v and B and follows right hand rule – 1( RHR- 1). The magnitude of the force is commensurable to q, v, B, and the sine of the angle between v andB.

still, or is zero, the glamorous force will be zero, If the flyspeck haste happens to be aligned resemblant to the glamorous field. This differs from the case of an electric field, where the flyspeck haste has no bearing, on any given moment, on the magnitude or direction of the electric force.

The angle dependence of the glamorous field also causes charged patches to move vertical to the glamorous field lines in a indirect or spiral fashion, while a flyspeck in an electric field will move in a straight line along an electric field line.

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Option A: pressure is described as the collision of the molecules of a fluid inside the surface of the container.

Fluids are the liquids or gases whose particles move around in random motion and constantly collide with each other. When enclosed in a container, the continuous collision impart a pressure on the walls of the container. Since the particles are moving in constant and a quick motion, they keep bouncing-off the container.

A pressurised container experiences significantly more impacts from the pressured gas inside than from the lower pressure environment outside at any given time. Collisions inside a container can also be influenced by temperature at a given instant.

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Correct question is:

What is described as the collision of the molecules of a fluid inside the surface of their container? responses:

pressure

volume

gravity

water

Two like masses are attracted to one another by gravitational forces.

Is the force of gravitation between two masses always alluring?

Any two bodies in our world will gravitationally attract one another, according to Newton's law of gravitation. Therefore, the gravitational attraction between two masses is constant.

The gravitational force created by one mass would be better represented by the electromagnetic field of a negative charge. This is thus because both the field representation of a negative charge and the gravitational force between two masses are attractive forces. When placed in an electric field, a positive charge will often move in the direction of the electric field lines, while a negative charge would typically move in the opposite way.

When a positive charge and a negative charge interact, their forces move from the positive to the negative charge in the same manner. The electric field and consequent forces produced by two electrical charges of opposing polarity cause opposite charges to attract one another. Compared to gravitational forces, electrostatic forces are substantially stronger. This is due to the fact that gravity is dependent on mass, and since atoms have such little masses, there is almost no gravitational pull between them. The electrostatic force, however, is greater when there are charges present.

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The natural frequency (in hertz) of oscillations of the second floor

(a) To find the natural frequency of oscillation of the second floor, we can use the formula:

ω_n = √(k/m)

where ω_n is the natural frequency, k is the spring constant, and m is the mass of the second floor.

The spring constant k can be found by using the given information that a horizontal force of 5 tons (10,000 lbs) is required to displace the second floor by 1 ft. This means that the spring constant is:

k = F/x = (10,000 lbs) / (1 ft) = 10,000 lb/ft

Converting the mass of the second floor to slugs, we get:

m = 32,000 lbs / g = 32,000 / 32.2 = 994.4 slugs

Substituting the values of k and m, we get:

ω_n = √(k/m) = √(10,000 lb/ft / 994.4 slugs) ≈ 10.05 rad/s

Converting to Hertz, we get:

f_n = ω_n / 2π ≈ 1.6 Hz

Therefore, the natural frequency of oscillation on the second floor is approximately 1.6 Hz.

(b) The amplitude of the forced oscillations of the second floor can be found using the formula:

x = (F_0 / m) / √(ω² - ω_n²)

where x is the amplitude of the forced oscillations, F_0 is the amplitude of the external force, ω is the circular frequency of the ground oscillations, and ω_n is the natural frequency of the second floor.

Substituting the given values, we get:

x = (F_0 / m) / √(ω² - ω_n²)

= (10,000 lbs / 994.4 slugs) / √((2π/2.25 s)² - (10.05 rad/s)²)

≈ 0.11 ft

Converting to inches, we get:

x ≈ 1.3 in

Therefore, the amplitude of the forced oscillations of the second floor is approximately 1.3 inches.

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The force exerted by the seat on the child at the lowest point is approximately 242 N.

(a) To find the child's speed at the lowest point, we can use conservation of energy. Assuming that the swing is released from rest at the highest point, we have:

Initial potential energy = mgh

Final kinetic energy = (1/2)mv^2

v is the speed of the child at the lowest point.

Since the height of the swing at the highest point is equal to the length of the chains, h = 2.9 m. We can solve for v by equating the two expressions for energy:

mgh = (1/2)mv^2

Solving for v, we get:

v = sqrt(2gh)

v = sqrt(2 × 9.81 m/s^2 × 2.9 m) ≈ 6.26 m/s

Therefore, the child's speed at the lowest point is approximately 6.26 m/s.

(b) At the lowest point, the child is moving in a circular path with a centripetal acceleration given by:

a = v^2/r

And,

T = mg + ma

Solving for a, we get:

a = (T - mg)/m

Substituting the given values, we get:

a = (352 N - 41.0 kg × 9.81 m/s^2)/(41.0 kg) ≈ 3.70 m/s^2

Substituting this value into the expression for centripetal acceleration, we get:

a = v^2/r

(3.70 m/s^2) = (6.26 m/s)^2/r

Solving for r, we get:

r = (6.26 m/s)^2/3.70 m/s^2 ≈ 10.6 m

Using Newton's second law, the force exerted by the seat is given by:

F = ma = m(v^2/r) = (41.0 kg)(6.26 m/s)^2/10.6 m ≈ 242 N

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The pressure transmitted in the hydraulic system is 4.20 x 10^5 Pa or 4.15 atm.

The principle of Pascal's Law states that pressure applied to a fluid in a closed container is transmitted equally to every part of the fluid and the walls of the container.

The force applied to the master cylinder can be expressed as:

F = A * P

where

We know that the force applied to the brake pedal is 100 N, and the force exerted on the master cylinder is 500 N. Therefore, the force amplification factor is:

FA = F_slave / F_master = 500 N / 100 N = 5

We can use this factor to calculate the pressure in the system:

P_slave = P_master / FA

The area of the master cylinder can be calculated as:

A_master = pi * (d_master/2)^2 = pi * (0.55 cm / 100 cm/m)^2 = 2.38 x 10^-4 m^2

The area of each slave cylinder can be calculated as:

A_slave = pi * (d_slave/2)^2 = pi * (2.50 cm / 100 cm/m)^2 = 4.91 x 10^-3 m^2

The pressure in the master cylinder can be calculated as:

P_master = F_master / A_master = 500 N / 2.38 x 10^-4 m^2 = 2.10 x 10^6 Pa

The pressure in each slave cylinder can be calculated as:

P_slave = P_master / FA = 2.10 x 10^6 Pa / 5 = 4.20 x 10^5 Pa

Converting to atmospheres, we get:

P_slave = 4.20 x 10^5 Pa / 101325 Pa/atm = 4.15 atm

Therefore, the pressure transmitted in the hydraulic system is 4.20 x 10^5 Pa or 4.15 atm.

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The resistance of the wire will increase by a factor of 8.

When the length of a wire is doubled, its resistance also doubles because resistance is directly proportional to the length. On the other hand, when the diameter of the wire is halved, the cross-sectional area of the wire reduces by a factor of 4 (πr^2 -> π(r/2)^2). As a result, the resistance decreases by a factor of 1/4.

So, when both changes are made, the resistance of the wire increases by a factor of 8 (2 x 4). This is because the effect of doubling the length is greater than the effect of halving the diameter. Thus, the net effect is an increase in resistance. This relationship between resistance, length, and cross-sectional area is described by the formula for resistance, which is R = ρL/A, where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is its cross-sectional area.

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During the brief time interval when the elevator is descending with free-fall acceleration, the scale would show your weight to be zero.

Free-fall acceleration is the acceleration that an object experiences due to the force of gravity, assuming no other forces are acting on the object. In the absence of air resistance or any other resistance, all objects near the surface of the Earth, regardless of their mass or composition, will experience the same constant free-fall acceleration due to gravity, which is denoted by the symbol "g" and has a value of approximately 9.8 meters per second squared (m/s²) or 32.2 feet per second squared (ft/s²).

This means that if an object is dropped from rest near the surface of the Earth, it will fall with a constant acceleration of g, and will increase its velocity by 9.8 m/s or 32.2 ft/s every second. Similarly, if an object is thrown upwards, it will experience a deceleration of g due to gravity until it comes to rest at the highest point of its trajectory, after which it will begin to fall downwards with free-fall acceleration.

If the elevator is in free-fall acceleration, it means that the only force acting on you is the force due to gravity, and there is no normal force acting on you from the scale. In this case, according to Newton's second law of motion, your weight is equal to the force due to gravity acting on your mass.

So, during the brief time interval when the elevator is descending with free-fall acceleration, the scale would show your weight to be zero. This is because your body is in a state of weightlessness, as you and the scale are accelerating downwards at the same rate.

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To find the elongation of the spring, we can use Hooke's Law, which states that the force exerted by a spring is proportional to its elongation. The formula for Hooke's law is:

F = -kx

where F is the force, k is the spring constant, and x is the elongation.

In this case, the force is equal to the weight of the object (10 kg), which can be calculated as:

F = m * g

where m is the mass of the object (10 kg) and g is the acceleration due to gravity (9.8 m/s^2).

So, the force can be calculated as:

F = 10 kg * 9.8 m/s^2 = 98 N

Using Hooke's law, we can find the elongation of the spring:

F = -kx

98 N = -250 N/m * x

x = 98 N / 250 N/m = 0.392 m

So, the elongation of the spring is 0.392 m.

_________________________________________________________

Hey brother, no problem for the answer but could you give 5 stars and a thanks!

All love, Johnny Sins :)

To appear as though the sun is stationary with respect to the passengers, the plane must travel at a speed of about 1670 km/h along the equator of the planet.

How fast must the plane fly in order to make the sun appear to be stationary in the sky? is the query. This is the same as the plane moving in such a way that it cancels out the Earth's axis rotation, which causes the sun to appear to move across the sky.

At the equator, the Earth's circumference is around 40,000 km, and it rotates once every 24 hours. This indicates that the linear speed of a place on the equator of the Earth is roughly 1670 km per hour. So, in order to make the sun appear, the plane must fly at this speed in the same direction as the Earth's rotation, or to the east.

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If today the sun appears to be located in the middle of the constellation Virgo. therefore, tomorrow the sun will be in the constellation Virgo. Hence, option D is correct.

An arrangement of stars is a constellation. Others have observed patterns in the stars that are used to classify the groups. A lion's form, for instance, appears to be traced by the stars of the constellation Leo.

The western zodiac consists of the 12 constellations Aries, Taurus, Gemini, Cancer, Leo, Virgo, Libra, Scorpio, Sagittarius, Capricorn, Aquarius, and Pisces is one constellation tradition.

Thus, if today the sun appears to be located in the middle of the constellation Virgo. Then, tomorrow the sun will be in the constellation Virgo. Hence, option D is correct.

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The type of radioactivity that has a negative charge is beta rays.

Alpha rays consist of particles which have two protons and two neutrons identical to a positively charged helium nucleus. They get attracted towards the negatively charged plate as they possess a charge of +2. They have very high ionization power.

Beta radiation has a negative charge because it contains particles similar to an electron. It contains the same mass as an electron, and the mass is lower than proton and neutron masses. Also, each particle contains a single negative charge, making the radiation negatively charged.

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Approximately 1.12 x 10^18 electrons would have to pass through the given point in a wire in 3.00 seconds to produce a current of 60 mA.

Electrons are subatomic particles that have a negative charge and are fundamental components of atoms. They are located in shells or orbitals around the atomic nucleus and play a crucial role in many physical and chemical processes.

Electrons are the carriers of electric charge in materials and are responsible for the flow of current in electrical conductors. They also play a key role in chemical bonding and reactions, as they are involved in the sharing and transfer of electrons between atoms.

Electrons are extremely small and have a mass of approximately 9.11 x 10^-31 kilograms, which is about 1/1836th the mass of a proton.

To determine the number of electrons that pass through a given point in a wire, we can use the equation:

I = Q/t

where I is the current in amperes, Q is the charge in coulombs, and t is the time in seconds.

We can rearrange this equation to solve for the charge Q:

Q = I*t

Now, use the elementary charge of an electron, which is approximately 1.602 x 10^-19 coulombs, to calculate the number of electrons that pass through the wire in 3.00 seconds:

Q = (60 mA) * (3.00 s) = 0.18 C

Number of electrons = Q / e = 0.18 C / (1.602 x 10^-19 C/e) = 1.12 x 10^18 electrons

Therefore, approximately 1.12 x 10^18 electrons would have to pass through the given point in the wire in 3.00 seconds to produce a current of 60 mA.

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The number of pixels subtended by the optical point spread function (PSF) depends on several factors, including the aperture size of the optical system, the wavelength of the light, and the pixel size of the imaging sensor.

The smallest object that an optical system is capable of resolving is known as the diffraction limit, and it depends on the size of the aperture and the length of the light's wavelength. A circular pattern roughly proportionate to the aperture diameter represents the diffraction-limited PSF.

Assuming a diffraction-limited optical system with an aperture diameter of D, the diameter of the PSF can be approximated as:

d = 1.22 * λ / D

where λ is the wavelength of the light.

If we assume that the pixel size of the imaging sensor is equal to the diameter of the PSF, then the number of pixels subtended by the PSF can be approximated as:

N = (d / p)^2

where p is the pixel size.

So, for example, if we assume a visible light wavelength of 500 nm, an aperture diameter of 50 mm (which would correspond to a large camera lens), and a pixel size of 5 µm (which is typical of many digital cameras), we can calculate:

d = 1.22 * 500 nm / 50 mm = 12.2 µm

N = (12.2 µm / 5 µm)^2 = 58 pixels

In this case, the PSF would therefore be subtended by 58 pixels approximately. This is only a very rough approximation, and the precise number of pixels covered by the PSF will vary depending on a variety of elements, such as the unique characteristics of the optical system and the imaging sensor.

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By the help of Kinetic energy ,the ratio of the brick's mass to the pebble's mass is [tex]\frac{9}{25}M = m[/tex]

A moving item or particle might have power of a certain sort called kinetic energy. An object gains kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. Kinetic energy is a characteristic of motion that depends on the mass and speed of an object or particle. Motion includes all combinations of vibration, axis rotation, translation, and movement (along a path from one location to another).

M should represent the brick mass.

Let m represent the pebble's mass.

.[tex]\frac{1}{2} M(v)^2[/tex] =KE

[tex]\frac{1}{2} M(3)^2[/tex]=KE

[tex]\frac{1}{2} m(5)^2[/tex]= KE

[tex]\frac{1}{2} M(3)^2= \frac{1}{2} m(5)^2[/tex]

9M = 25m

[tex]\frac{9}{25}M = m[/tex]

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The correct answer is option b) high temperatures correspond to faster average molecule speeds.

The term "average molecule speed" describes the typical speed of a gas's molecules. The root-mean-square (rms) velocity formula can be used to determine the average speed of all the molecules in a gas. Individual molecules in a gas move at different speeds as a result of collisions with other molecules.

[tex]\sqrt{3kT/m} = v[/tex]

Where T is the gas's temperature in kelvins, v is the gas molecules' average speed, k is the Boltzmann constant, and m is the mass of a single gas molecule.

The relationship between the gas's molecular mass, pressure, and temperature govern the average molecule speed. The Maxwell-Boltzmann distribution states that as the gas's temperature rises, so does its average molecular speed. Similar to this, while temperature and pressure are constant, gases with lower molecular masses move molecules more quickly on average than gases with greater molecular masses.

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For a snowy winter day, it is best to wear dark colored jacket because, it helps to absorb heat and make us warm in the cold condition.

A black colored body absorbs all colors but reflect no color. Hence, energy it absorbs will be emitted as heat. This is called black body radiation. The white light will absorbs all lights and reflects all light. Thus no energy is emitted as heat.

In the summer season, it is better to wear light colored dresses and uses white painted umbrellas because, they does not make us warmer and trap the heat from the surroundings.

But, in winter seasons, we need some warmth and it is better to use dark colored or black jackets to warm up ourselves. Therefore, option 1 is suit for a winter season.

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Answer:

[tex]F = \boxed{3.53002 \times 10^{22} \;N}[/tex]

Explanation:

The formula used to calculate the gravitational force between two objects
[tex]F = G \dfrac{m_1m_2}{r^2}[/tex]

where

m₁ and m₂ are the masses of the two objects

G  is the universal gravitational constant =6.6743 × 10⁻¹¹ m³/kg·s²

r is the average distance between the two objects

We are given
mass of earth = m₁  = 5.98 X 10²⁴ kg

mass of sun = m₂ = 1.99 x 10³⁰ kg

r = 1.5 x 10¹¹ m

Therefore

[tex]F\:=\:6.6743\:\times \:10^{-11}\times \dfrac{\left(5.98\:\times 10^{24}\times 1.99\:\times 10^{30}\right)}{\left(1.5\:\times \:10^{11}\right)^2}[/tex]

[tex]F = \boxed{3.53002 \times 10^{22} \;N}[/tex]

Dark nebulae are thought not to contain stellar nurseries because they are primarily composed of gas and dust, which are the building blocks of stars, but they are too cold and dense to collapse and form stars.

A nebula is a distinctively luminous region of the interstellar medium, which may be made up of cosmic dust, neutral, neutrally ionized, or molecular hydrogen.

Because dark nebulae are predominantly made of gas and dust, the raw materials for stars, but are too cold and dense to collapse into stars, it is believed that they do not contain stellar nurseries.

In other words, the gas and dust in a black nebula are not in an ideal environment to start the star-forming process.

The quantity of light that is accessible for star formation may be diminished by the dust particles in dark nebulae that can absorb and scatter light.

Thus, despite the fact that black nebulae may contain a lot of gas and dust, they are not suitable for the formation of new stars, and are unlikely to contain stellar nurseries.

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According to the problem the wavelength of the light is 5.67 μm.

Wavelength is the distance between one point on a wave and the next corresponding point of the same phase on the wave. It is usually measured in meters (m) or nanometers (nm). Wavelength is closely related to frequency, as the frequency of a wave is equal to the speed of the wave divided by the wavelength. Wavelengths are used to measure various forms of electromagnetic radiation, such as visible light, radio waves, and x-rays. The wavelength of a wave determines its color, as visible light is made up of a spectrum of different wavelengths.

The angle of diffraction of a given wavelength of light through a grating is given by the equation: θ = (m*λ)/d

where θ is the angle of diffraction, m is the order of diffraction, λ is the wavelength of the light and d is the line spacing of the grating.
In this case, m = 2 (second order principle maximum), d = 300 lines/mm and θ = 18.9 degrees.
Solving for λ gives us: λ = (d*θ)/m
Substituting in the values gives us: λ = (300*18.9)/2 = 5670 nm = 5.67 μm

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The time interval is 0.15 s

The frequency of oscillation refers to the number of cycles of a periodic waveform that occur per unit of time, usually measured in hertz (Hz), which represents cycles per second.

Based on the information that can get in the question that has been put before us here and now;

Note that;

Frequency = Number of oscillations/Time

3 * 10^3 = 440/time

Time = 440/3 * 10^3

Time = 0.15 s

Thus we can see from the calculation that the time that is taken is 0.15 s

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The friction force experienced by the box is approximately 77.96 N.

Frictional force is a force that opposes the motion or attempted motion between two surfaces in contact. It is caused by the irregularities in the surfaces of objects that come into contact with each other, and it acts in the direction opposite to the direction of motion or attempted motion.

We can begin by drawing a diagram of the situation and labeling the forces acting on the box:

where:

Fp is the force applied by Chasadie.

Ff is the force of friction.

mg is the weight of the box (mass times gravity)

We can then use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:

ΣF = ma

where ΣF is the sum of all the forces acting on the box.

In the vertical direction, we have:

ΣFy = N - mg = 0

where N is the normal force, which is equal and opposite to the weight of the box.

Since the incline is at an angle of 85.61 degrees, we can use trigonometry to find the components of the weight and normal force:

N = mg cos θ = (3.68 kg)(9.81 m/s²) cos (85.61°) ≈ 18.77 N

mg sin θ = (3.68 kg)(9.81 m/s²) sin (85.61°) ≈ 36.24 N

In the horizontal direction, we have:

ΣFx = Fp - Ff - mg sin θ = ma

Plugging in the given values and solving for Ff:

Ff = Fp - ma + mg sin θ

= (217.41 N) - (3.68 kg)(11.63 m/s²) + (3.68 kg)(9.81 m/s²) sin (85.61°)

≈ 77.96 N

Therefore, the friction force is approximately 77.96 N.

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The diagram for the solution of the question is as follows:

The amount of heat required to vaporize a certain amount of water is given by:

Q = ml

where Q is the amount of heat, m is the mass of water, and l is the specific latent heat of vaporization.

In this case, the heat energy supplied to the water is:

Q = Pt

where P is the power supplied and t is the time taken.

Since the water is at its boiling point, its temperature remains constant while it is vaporizing. Therefore, the energy supplied to the water is solely used for vaporization.

Equating the two expressions for Q, we have:

Pt = ml

Solving for t, we get:

t = ml / P

where m = 250 g and l = 2260 J/g.

Substituting the values, we get:

t = (250 g) x (2260 J/g) / (3000 W) = 0.1883 hours

Converting to minutes, we have:

t = 0.1883 hours x (60 minutes/hour) = 11.3 minutes (approx.)

Therefore, it will take approximately 11.3 minutes for 250 g of water to vaporize.

Every new and full moon, when the sun, moon, and earth are in alignment, spring tides occur. When lunar and solar tides align, they reinforce one another and create a larger overall tidal.

The Earth's tides are significantly influenced by the elliptical orbits of the moon around the planet and the planet around the sun. The largest spring tides happen when the moon is close to perigee and the sun is close to perihelion.

Every month, at perigee, when the moon is closest to Earth, tidal-generating forces are stronger than usual, resulting in tide ranges that are higher than typical.

Therefore, When the sun, earth, and moon are at a straight angle and the moon is in its first or third quarter, neap tides happen.

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The symmetric peak divides the lights of short wavelength and long wavelength lights, which occurs at the green light boundary.

A symmetric peak refers to a peak that is roughly the same shape on both sides of the highest point. This means that the left and right sides of the peak are mirror images of each other.

Symmetric peaks are often seen in graphs or charts that represent data such as intensity versus wavelength graph as shown in the diagram.

At the the symmetric peak, the wavelength of the particle is 500 mm which corresponds to wavelength of green light.

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The charge will not change if the capacitor is not connected to the battery. When the plates of a capacitor are shifted further apart, the capacitance Cd1 drops.

The energy stored by capacitor U(=2Cq) grows when the battery is disconnected because the charge on the capacitor stays constant.

The capacitor, which we were informed was entirely depleted, has zero voltage across it when the switch is first closed, making it appear as though there is a short circuit.

The capacitor will eventually operate as an open circuit because the voltage of the capacitor will eventually equal the voltage of the battery.

Therefore, after a capacitor is simply connected across a battery, its voltage will be the same as the battery terminal voltage when the battery is disconnected, and it will have an energy reserve equal to capacitance times voltage divided by two.

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When a star is rising straight up in the east, it will be high in the south when it is at its peak point over the horizon.

In both hemispheres, the star ascends in the east and sets in the west. This results from the rotation of the earth. Also, they circle the north celestial pole in a clockwise way whereas the south celestial pole is in a counterclockwise direction.

Nonetheless, the south celestial pole will be visible above the southern horizon at an angle proportional to your latitude. Toward the northern sky, rising stars in the east will go higher and to the left. As you travel farther south, the celestial equator will likewise pass across the northern sky, getting progressively lower.

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The kinetic energy of each ejected electron is 3.31 x 10⁻⁴² J/electron, and its velocity is 8.51 x 10³ m/s.

Minimum thermodynamic work needed to remove electron from solid to the point in vacuum immediately outside the solid surface is called work function.

E = hf

hc/λ = hf + Φ

K.E. = hf - Φ

E is energy of a photon, h is Planck's constant, f is frequency of the photon, c is speed of light, λ is wavelength of the photon, Φ is work function, K.E. is kinetic energy of  ejected electron.

E = hf = Φ + hc/λ

hf = Φ + hc/λ

f = (Φ + hc/λ) / h

E = hc/λ = h((Φ + hc/λ) / h) = Φh/h + hc/λh

E = Φ + hc/λ

Given, Φ = 483.4 kJ/mol photons = (483.4 kJ/mol photons) / (6.022 x 10²³ photons/mol) = 8.03 x 10⁻¹⁹ J/photon

c = 3.00 x 10⁸ m/s h = 6.626 x 10⁻³⁴ J·s  λ = 225.0 nm = 225.0 x 10⁻⁹ m

So, E = Φ + hc/λ = (8.03 x 10⁻¹⁹ J/photon) + (6.626 x 10⁻³⁴ J·s x 3.00 x 10⁸ m/s) / (225.0 x 10⁻⁹ m) = 2.79 x 10⁻¹⁸ J/photon

K.E. = hf - Φ = E - Φ

K.E. = (2.79 x 10⁻¹⁸ J/photon) - (8.03 x 10⁻¹⁹ J/photon) = 1.99 x 10⁻¹⁸  J/photon

K.E. = (1.99 x 10⁻¹⁸  J/photon) / (6.022 x 10²³ photons/mol) = 3.31 x 10⁻⁴² J/electron

K.E. = 1/2 mv²

m = 9.109 x 10⁻³¹ kg

K.E. = 3.31 x 10⁻⁴² J/electron

3.31 x 10⁻⁴² J/electron = 1/2 (9.109 x 10⁻³¹ kg) v²

v² = (2 x 3.31 x 10⁻⁴² J/electron) / (9.109 x 10⁻³¹ kg)

v^2 = 7.26 x 10⁷ m²/s²

v = √(7.26 x 10⁷m²/s²) = 8.51 x 10³ m/s

Therefore, the kinetic energy of each ejected electron is 3.31 x 10⁻⁴²J/electron, and its velocity is 8.51 x 10³ m/s.

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The tilt of Earth's axis causes the ecliptic to intersect the celestial equator at two points, creating the seasons.

The ecliptic is the unmistakable method of the Sun on the heavenly circle as seen from Earth. It isn't concurred with the magnificent equator, which is the projection of the World's equator onto the heavenly circle, considering the way that the World's center is moved by around 23.5 degrees relative with the plane of its circle around the Sun. Consequently, over the range of a year, the World's Northern and Southern Parts of the globe then again slant towards and away from the Sun, causing the seasons. The ecliptic meets the eminent equator at two spots, known as the equinoxes, where the length of every day of the week is generally same. The inclination of the World's turn, got together with the World's circle around the Sun, prompts the changing seasons and the moving spot of the ecliptic near with the superb equator.

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When a circuit is finished and current can flow, it is said to be in a closed-circuit condition. In the closed position, the current has a clear passage.

The light bulb turns on when the switch is closed because current passes through the circuit. The bulb receives its full 120 volts and the intended current flow, which allows it to operate at maximum brightness.

There is a closed (or full) circuit with the bulb when the circuit's wires are attached to the metal casing and metal tip of the lightbulb. The filament will be able to conduct electricity, which will result in the bulb lighting up.

Therefore, in this case, both bulbs receive the same amount of electricity both before and after the switch is closed. Consequently, the brightness doesn't change.

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