A bone taken from a garbage pile buried under a hill-side had 14C/12C ratio 0.477 times the ratio in a living plant or animal. What was the date when the animal was buried?​

The depression in freezing point of water here is 3.33 °C. Then the molality of the solution is 1.79. From number of moles of solute is calculated as 0.0161. Then , the molar mass of the solute is 62.11 g.

The addition of a non-volatile salt into a solvent will decrease the freezing point of the solution than the pure solvent. The change in freezing point is proportional to the molality of the solution.

ΔTf = Kf m

Kf is called molal depression constant.

Kf for water = 1.86 °C Kg/mol

given ΔTf = 3.33 (0 - (-3.33))

then m = ΔTf /Kf =  3.33/ 1.86 °C Kg/mol = 1.79

Now, mass of water= 9 g = 0.009 kg

then number of moles = molality × mass of solvent

n = 0.009 kg × 1.79 = 0.0161.

mass of solute taken = 1 g

then, molar mass = 1/0.0161 = 62.11 g.

Therefore, the molar mass of the solute is 62.11 g.

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Ionization constant of a reaction is the ratio of the molar concentration of product to that of reactants. For the given  reaction, the ionization constant is 155.8 .

A compound or element gets ionized to form its anion or cation by the gain or lose of electrons.

Here, acetic acid, CH₃COOH ionizes to form hydronium ion and acetate ion. The ratio of product of molar concentrations of products to the product of molar concentrations of the reactants is called the reaction constant.

The ionization constant of the given reaction is written as:

K = [H₃O]⁺ [CH₃COO-]/[CH₃COOH]

Given, [CH₃COOH] = 0.8 M

[CH₃COO-] = 16.4 M

and  [H₃O]⁺ = 7.6 M.

then, K = 7.6 M × 16.4 M/ 0.8 M = 155.8

Therefore, the ionization constant of the reaction is 155.8.

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Answer:

it's exothermic reaction, becasue it have negative energy and the temperature increases