A boy having a mass of 75 kg holds in his hands a bag of flour weighing 40N. With what force does the floor push
up on his feet?

The forces are balanced because Jasper weighs the same as Gemma.

Force:

A force is an influence that can alter an object's motion according to physics. A force can cause an object with mass to accelerate when it changes its velocity, such as when it moves away from rest. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F.Since forces are perceived as pushes or pulls, this can offer a simple explanation of how forces are described.

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Moons that display few craters presumably. They all pass straight over the equator of the globe. Uranus's five biggest moons. have the closest magnetic field axis.

There are many fascinating moons around the globe, but the Galilean satellites—Io, Europa, Ganymede, and Callisto—the first four moons identified beyond Earth—hold the most scientific curiosity.

Moon and Earth

The basic explanation is that Earth only has one moon, that we name “the moon”. It is the biggest and brightest object in the night sky, and the only solar system body except Earth that humanity have visited in our space travel activities.

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The spring constant for storing the same amount of energy is given as x = 0.707 cm.

What does a string mean?

A string is a computer data type that is similar to an integer and a floating point unit, except it represents text instead of numbers. It is made up of a series of symbols that may also include spaces and numerals.

briefing :

E = /kx2 is the energy that has been stored.

E1 = E2

1/2 k(1.0)² = 1/2 (2k)x²

x^2 = 1/2 (1.0)²

x = 1.0/√2 cm

x = 0.707 cm

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According to the question the far point in m of a person's eye is 0.30m.

In terms of the space the eye can accommodate, this refers to the farthest distance from which an item can be positioned for its picture to be mirrored on the retina. It can also be thought of as the distance from the eyes at which pictures are clearly visible. The units are meters, or m.

P = relaxed power of the eye

F =far point

Given in the question:

The power of the eye is given as

P = 1/di + 1/do

P is power of the eye

di is the distance between eye lens and the image

d₀ is distance between eye lens and image

Given that,

P =53.3d

Take note that the power unit "d" stands for "dioptre," which means "per meter."

If the person can see clearly, the separation between the eye lenses and the picture (di), which is 2 cm, must be identical to that distance.

Thus, di = 2cm = 0.02m

P = 1/di + 1/d₀

1/d₀ = P — 1/di

1/d₀ = 53.3 — 1/0.02

1/d₀ = 53.3—50

1/d₀ = 3.3m

taking reciprocal

d₀ = 1/3.3

d₀ =0.3030m

Then, d₀ = 0.3030m

d₀≈ o.30m

The far point the person can see is 0.30m

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Answer:

Hubble's law is considered a fundamental relation between recessional velocity and distance. However, the relation between recessional velocity and redshift depends on the cosmological model adopted and is not established except for small redshifts.

Explanation:

The relationship between recessional distance and velocity is thought to be governed by Hubble's law. Although it is not confirmed save for minor redshifts, the relationship between recessional velocity and redshift relies on the cosmological model used.

Although Hubble was a real person, a spacecraft that was launched into space was given his name. He found that the galaxies that seem to be farthest from us are accelerating their distance from us, while the galaxies that are nearer to us are lagging.

Hubble's law is therefore that. If you study higher-level astronomy, you can do a mathematical operation known as Hubble's law. You can determine a mathematical relation that says that anything moves quicker the further distant it is from you.

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The final speed of the motorcycle is: 67 m/sec

Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route. In other words, although velocity is a vector, speed is a scalar quantity.

Given that,

initial speed of the motorcycle, u=25 m/sec

Acceleration of the motorcycle, a = 7 m/sec²

According to the equation of motion,

v = u + at

v = 25 m/sec + (7m/sec²) × (6 sec)

v = 67 m/sec

Thus, final speed of the motorcycle is: 67 m/sec

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The kinetic energy of the object with a mass of 10 kilograms traveling at a speed of 10 meters per seconds is 500 Joules.

Newton’s laws are encapsulated in what may be the second most famous equation in physics: F = ma, which states that a force F applied to a mass m results in an acceleration a.

Since the mass is accelerating, its velocity v is not constant, but since the acceleration is constant, and acceleration is the rate of change of velocity, the rate at which v is changing is constant and is equal to the acceleration a.

Since the work done by the force is just the energy imparted to the mass, we will use the letters K.E to stand for this work. Then we get,

K.E = ½ × m × v²

Where;

K.E = kinetic energy

m = mass

v = speed

K.E = ½ × 10 × 10²

K.E = 5 × 100 =  500 J

Hence, the correct option is b.

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The electric field at x = 1.0 m is 12.18.

The electric field at x = 2.0 m is 0.135.

The electric potential at a point is a scalar quantity that is used to describe the electric potential energy per unit charge at that point. In the equation you provided, V is the electric potential at a point along the x-axis and x is the position along the x-axis. To find the electric field, which is denoted by Ex, you can use the equation Ex = -dV/dx, where dV is the change in electric potential and dx is the change in position along the x-axis.

To find the electric field at x = 1.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*1.0) = 50e^(-2) = 12.18.

To find the electric field at x = 2.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*2.0) = 50e^(-4) = 0.135.

In both cases, the electric field is positive, indicating that the electric field is directed away from the origin.

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The speed at the bottom of the incline is  6.87 m per second.

The conservation of the energy is a fundamentally law of physics, chemistry stating that the total of the energy of an isolated by the system is constant despite internally changes. It is mostly common expressed as “energy can neither to be created nor destroyed”, and it is the basis of the first-ever law of the thermodynamics.

As per the given question

The length of the inclined plane L= 8.00m

angle of inclination is = 37°

Height of the inclined plane h= L sin ø

     (8.00m) sin 37°

     =4.814 m

Let's take m= mass of hoop

Let's take r=radius of hoop

Let's v be the velocity of the hoop bottom to the inclined plane.

Now we can apply conservation of energy at the top of the inclined plane  and at to the bottom of the inclined plane.

mgh = ¹/₂ mv²

mgh = ¹/₂ mv² + ¹/₂ Iω²

Where, I = moment of inertia

ω = angular velocity

I = L/ω

mgh = ¹/₂ mv² + ¹/₂ (L/ω)ω²

mgh = ¹/₂ mv² + ¹/₂ Lω

mgh = ¹/₂ mv² + ¹/₂ mvrω

ω = vr

mgh = ¹/₂ mv² + ¹/₂ mvrvr

gh = ¹/₂ v² + ¹/₂ (vr)²

gh = ¹/₂v² (1 + r²)

v=gh

v=√(9.8m/s^2)(4.814m)

v=6.87 m/s

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The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

What is acceleration?

An item is said to be accelerated if there is a change in its velocity. The change in the velocity of an item could be an increment or decrement in speed or a change in the direction of motion. A few examples of acceleration are the falling of an orange, the earth orbiting around the sun, or when a car is stopped at the traffic lights. Through these examples, we can deem that when there is a change in the direction of a moving item or an increment or decrement in speed, acceleration occurs.

The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

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The gravitational force between the large ball and the small ball, given their respective masses is 1.2×10¯¹³ N

Gravitational force between two objects is given as shown below:

F = GM₁M₂ / r²

Where

Using the above formula, we can obtain the gravitational force between the the large and small ball as follow:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.0×10⁻³ × 9.0×10⁻²) / 0.5²

F = 1.2×10¯¹³ N

Thus, the gravitational force is 1.2×10¯¹³ N

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In both cases, y and x components are solved and added. The resulting speed hypotenuse is then computed and its direction calculated.

Airplane:

Ф = 270 - 265 = 5°

Hypotenuse, h = 400 mph

y component = 400 Sin Ф = 400 Sin 5 = 36.61 mph

x component = 400 Cos Ф = 400 Cos 5 = 418.40 mph

Wind

Ф = 315 -210 = 60°

Hypotenuse, h = 30 mph

y component = 30 Sin 60 = 25.98 mph

x component = 30 Cos 60 = 15 mph

Total y = 36.61+25.98 = 62.59 mph

Total x = 418.40+15 = 433.40 mph

Resulting speed of airplane = Sqrt (y^2+x^2) = Sqrt (62.59^2+433.40^2) = 437.9 mph

Direction = 270 -[tan^-1 (y/x)] = 270 -[tan^-1(62.59/433.40)] = 261.78°

Therefore, the resulting speed is 437.9 mph in the direction of 261.78°

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Making a few assumptions like uniformity and flatness of the universe we have :

A. [tex](\frac{a}{a} )^{2} = \frac{8\pi gs+\pi }{3}[/tex]

B. [tex]\frac{a}{a} = - \frac{4\pi G}{3} (S+3P)+\frac{\pi }{3}[/tex]

where is 'a' is a scale factor which tells us how expanded the Universe is. And it's the first derivative gives the rate of expansion and its second derivative gives the acceleration of the universe.

So if G increases, due to the mass of neutrons. Then the acceleration would have a negative value which would mean slowing down.

All the above however does not consider dark energy, which would modify the equations. We still have to understand the nature of dark matter to be able to predict how much in the long run would gravity affect acceleration.

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The volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

According to Bernoulli's principle of fluid dynamics, a fluid's speed increases at the same time as its static pressure or potential energy decreases. The Bernoulli equation is regarded as the definition of energy conservation for flowing fluids. This is thought to be the qualitative behaviour that reduces pressure in high-velocity zones. Also, referred to as the Bernoulli effect.

Calculations:

Using continuity equation, Bernoulli's equation.

A1×V1 = A2×V2

Where,

A1 = area of the supply pipe

V1 = volume of supply pipe

A2 = area of sprinkler

V2 = volume of sprinkler

Given,

Diameter of supply pipe = 2.5cm therefore radius = 1.25cm.

Diameter of sprinkler = 0.5cm therefore radius = 0.25cm.

V1 = (A2×V2) /A1

V1 = (π [tex]r_{2}[/tex]²× V2) / (π [tex]r_{1}[/tex]²)

V1 = {π (0.25) ² × 8} / { π (1.25) ²}

V1 = 0.32m/s.

Hence, the volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

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Shifting gears correctly is important when driving a vehicle to ensure that the car is operating at its most efficient level.

By selecting the correct gear, you can ensure that the engine works at its optimal speed, allowing it to produce the most power with the least fuel. This helps you save money on fuel costs and reduces your car’s environmental impact.

Shifting gears correctly allows you to control the speed of your car. When accelerating, you need to select a higher gear so that the engine produces more torque, enabling your car to accelerate faster. When slowing down, you should select a lower gear to reduce the engine’s revolutions per minute (RPM), allowing you to slow down quickly and safely.

Finally, correctly shifting gears also ensure your passengers' safety, including yourself. If you shift gears too quickly or at the wrong time, you increase the risk of your car stalling, which can be dangerous in certain situations. In addition, selecting the wrong gear for your traveling speed can lead to acceleration and braking, leading to an uncomfortable and potentially difficult ride.

In conclusion, it is important to shift gears correctly when driving a vehicle to ensure efficient fuel use, control the speed of the car, and keep you and your passengers safe.

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16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force. Work is accomplished when we push a block with some force; the body moves more rapidly.

Distance is the sum of an object's movements, regardless of direction. The distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

Calculation:

Given,

Distance= 38m

Rate = 25mL/s = 0.25L/s

To find work done in 2.5mins Or 150seconds

Potential energy (P.E) = (mgh) /t

P.E = (mgh) /t

     = (0.25 Ls-¹ * 9.81 * 38m) / 1sec

     = 93.195 Watts

For 1 sec 93.195 watt is used

For 2.5mins Or 180 seconds = 93.195 × 180= 16775 watts or 16.7kW power is used for the work done.

Hence, 16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

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A typical problem of becoming an adult is getting along with our partner.

Adulthood is the stage of life when a person has fully developed physically and intellectually. Adulthood is typically assumed to start around 20 or 21 years old. Old age begins at the age of 60 and follows middle age, which starts around the age of 40.

The topic of adult development is briefly discussed after that. See human development and human behaviour for a comprehensive discussion.

Early and middle adulthood are physically characterised by slow, steady losses in body functioning, which quicken when old age is reached. Through the mid-20s, muscular mass continues to rise before progressively declining after that. Up until around age 30, the skeletal mass grows; after that, it starts to diminish, first in the core skeleton (the pelvis and spine), then in the peripheral skeleton.

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Skin is the largest organ in the body and covers the body's entire external surface. It is made up of three layers, the epidermis, dermis, and the hypodermis, all three of which vary significantly in their anatomy and function.

Give a brief about layers of skin?

The skin is the largest organ of the body and covers the entire outer surface of the body. It consists of her three layers of epidermis, dermis and hypodermis, all three of which differ greatly in anatomy and function. The structure of the skin consists of a complex network and serves as the body's first barrier against pathogens, ultraviolet radiation, chemicals, and mechanical damage. It also regulates temperature and the amount of water released into the environment. This article describes the relevant anatomy of the epidermal layer of the skin, its structure, function, embryology, vasculature, innervation, surgical considerations, and clinical relevance.

Therefore, Skin is the largest organ in the body and covers the body's entire external surface. It is made up of three layers, the epidermis, dermis, and the hypodermis, all three of which vary significantly in their anatomy and function.

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Answer:

bhai what is yhis? i dont understand

A. In the ideal Amp, V⁺ = V⁻

B. [tex]V_{out} = -2v[/tex]

C. [tex]P_{8K} = 4.5 m watts[/tex]

Solution:

[tex]V_{out} = 3-5 = -2v = V_{out} = -2v\\\\I_{y} = \frac{V_{out} }{500} = \frac{-2}{500} = I_{y} = -4ma[/tex]

Power delivered by 6v = P6v = (6)(1) (6)(m) -6mworth = = 6 V Vgk = (8k) (a) = (8k) (0,75 mA)

Power dissipated in the 8k = P₁₁ = (6v) (ia) = (6) (0.75 m) = 4.5 mwatts.

A schematic is a graphical representation of an electrical circuit. Schematics uses simple images of components, and schematics use standardized symbolic representations to show circuit components and connections. A schematic is a simplified representation of the components of an electrical circuit using either pictures of individual parts or standard symbols.

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The magnitude of the force at this distance of 2.0 m is 25.6 N.

The force between two charges q1 and q2 separated by a distance r is given by Coulomb's law:

F = k (q1 q2)/r^2

where k is the electrostatic constant (9 x 10^9 Nm^2/C^2).

In this problem, the distance is 1.0 m and the magnitude of the force is 104 N, so we can solve for the charge on each particle:

104 N = (9 x 10^9 Nm^2/C^2) (q1 q2) / 1.0 m^2

q1 q2 = 104 N / (9 x 10^9 Nm^2/C^2)

q1 q2 = 1.2 x 10^-7 C^2

Since the magnitudes of the charges are equal, q1 = q2 = q, so we can solve for q:

q^2 = 1.2 x 10^-7 C^2

q = 3.4 x 10^-4 C

Now that we know the charge on each particle, we can calculate the force when the separation is doubled to 2.0 m:

F = (9 x 10^9 Nm^2/C^2) (q1 q2) / (2.0 m)^2

F = (9 x 10^9 Nm^2/C^2) (3.4 x 10^-4 C)^2 / (2.0 m)^2

F = 25.6 N

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When then the ball is stopped by the hand due to reaction force by the hand which is equal in magnitude but is opposite in direction to the force applied by the ball.

According to Newton's third law of motion, the reaction would be equal and opposite to the person pushing on the ball, so the ball pushing on the person.

When a ball is thrown on the floor or a wall, it bounces back. The force exerted by the ball on the ground or wall is the action force. The force that the ground or wall exerts on the ball in response to the action force causes the ball to jump or bounce back.

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To solve this problem, we can use the equations of motion and Newton's second law of motion. The equation of motion for an object moving at constant speed is:

x = x0 + v0t + (1/2)at^2

where x is the final position, x0 is the initial position, v0 is the initial velocity, t is the time, and a is the acceleration.

In this case, the initial position is 0 m (since the crate starts at the beginning of the 12 m distance), the initial velocity is 0 m/s (since the crate starts at rest), and the time is 12 s (since the crate moves at a constant speed of 1.50 m/s).

We can use these values to solve for the acceleration:

12 m = (1/2)(a)(12 s)^2

a = 0.5 m/s^2

Now that we know the acceleration, we can use Newton's second law of motion to find the normal force:

F = ma

N = (20 kg)(0.5 m/s^2)

N = 10 N

This is the magnitude of the normal force on the crate. Note that this is the normal force exerted by the floor on the crate, not the force of tension in the rope. To find the force of tension in the rope, we would need to consider the angle of the rope and the direction of the force.

Plane polarized light consists of waves that has magnetic field in which the direction of vibration is the same for all waves.

Plane polarized light consists of waves in which the direction of vibration is the same for all waves.The process of transforming unpolarized light into polarized light is known as polarization.

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A 90 kg goaltender celebrate by jumping 110 cm into the air after defending the goal. 970.20 J was work done throughout the celebration.

The sum of the displacement as well as the components of the force applied of the object in the displacement direction is the work done by a force. The body moves with certain acceleration when we push a blocks with certain force, and work is completed.

m = mass of the body = 90 kg

g = gravitational force

h = height = 110cm

Formula -

work done = mgh

                   = 90 × 9.8 × 110

                   = 970.20 J

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Cash in dollars. Fiat money refers to any forms of currency that are issued by governments or central banks but are not backed by anything.

When money is used as a medium of exchange, it speeds up transactions between buyers and sellers because it is commonly accepted as payment for goods and services. Although most societies use money, other exchange methods have included tobacco, salt, gold, and stones.

A medium of exchange is a device or system that acts as a middleman in transactions involving the exchange of goods between parties. Currency serves as the primary means of exchange in modern economies.

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speed of the electron is v= 1.371 x 10⁶ m/s.

briefly:-

wavelength of the ultraviolet light beam ARE , λ = 130 nm = 130 x 10⁻⁹ m

the work function of molybdenum surface IS, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

energy of the incident light is :-

E = hf

where;

Planck's constant h= 6.626 x 10⁻³⁴ J/s

f = c / λ

E = hν = hc/λ

E =15.29810-19 J

Photo electric effect equation is;-

E = W₀ + K.E

Where;

K.E =the kinetic energy of the emitted  are electron K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J *- 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of  emitted electron is ;

K.E = ¹/₂mv²

where;

m =mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

K.E. = 1/2 m v2.

V=1.371 x 10⁶ m/s.

speed of the electron is v=1.371 x 10⁶ m/s.

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The final momentum will be the sum of the initial momentum of the two vehicles. The final velocity of the combined mass will be 5.9 m/s.

Collision is a short range force exerted by an object on other object make them move either to the same side or opposite sides based on their mass.

Momentum of a moving body is the product of its mass and velocity. During a collision, the initial momentum will be equal to the final momentum.

The momentum of the car  = mass × velocity

                                             = 1193 Kg × 27.6 m/s

                                             = 32926 kg m/s

The initial momentum of the truck is zero because it was stationary.

The final momentum with the velocity v, of the combined mass is equal to the total initial momentum i.e. 32926 kg m/s.

32926 kg m/s =  (1193 Kg  + 4302 Kg) v

v = 32926 kg m/s /   (1193 Kg  + 4302 Kg)

  = 5.9 m/s.

Therefore, the final velocity of the vehicles when they stuck together is 5.9 m/s.

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The possible wavelengths that appear In the emission spectrum of the system are [tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Given:

The quantum energy levels allowed In the system are:

[tex]$$\begin{aligned}& E_1=1.0 \mathrm{eV} \\& E_2=2.0 \mathrm{eV} \\& E_3=4.0 \mathrm{eV} \\& E_4=7.0 \mathrm{eV}\end{aligned}$$[/tex]

What is wavelength of the emission?

As the transition of electron takes from one energy level to another, there is an emission of particular wavelength from the transition. The relation between the wavelength of the emission and the energy of the energy level Is expressed as:

[tex]$$E_f-E_i=\frac{h c}{\lambda}$$[/tex]

Here, [tex]$E_f$[/tex] is the final energy level, [tex]$E_i$[/tex] is the Initlal energy level and [tex]$\lambda$[/tex] is the wavelength of emlsslon.

(1). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_2$[/tex] energy level:

[tex]$$\begin{aligned}E_2-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(2-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =1.244 \times 10^{-6} \mathrm{~m} \\& \approx 1200 \mathrm{~nm}\end{aligned}$$[/tex]

(2). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

(3). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-31}\right) \times\left(3 \times 10^8\right)}{(7-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.207 \times 10^{-6} \mathrm{~m} \\& \approx 210 \mathrm{~nm}\end{aligned}$$[/tex]

(4). Transition of electron from [tex]$E_2$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.621 \times 10^{-6} \mathrm{~m} \\& \approx 620 \mathrm{~nm}\end{aligned}$$[/tex]

(5). Transition of electron from[tex]$E_2$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_1-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.248 \times 10^{-6} \mathrm{~m} \\& \approx 250 \mathrm{~nm}\end{aligned}$$[/tex]

(6). Transition of electron from [tex]$E_3$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_3 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-4)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

Thus, The posslble wavelengths that appear in the emisslon spectrum of the system are[tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Complete question: The allowed energies of a quantum system are 1.0 ev, 2.0 ev, 4.0 ev, and 7.0 ev. what wavelengths appear in the system's emission spectrum

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According to Charles' Law, the V/T = k, V1/T1=V2/T2, in case v1= 4.39, T1= 44C=317 K (being O C= 273 K) V2=3.78 L T2=?. Charles law, 4.39L/317K = 3.78L/T2. T2x=4.39L/317K = 3.78 L. T2= 3.78L/4.39/317k, T2=273K=0 C

Place the bucket into the larger container, fill it with water, then submerge the inflated balloon completely. After that, remove the bucket, pour the water from the larger container into the measuring container, and measure the volume of the water.

The basic formula for volume is length, breadth, and height, as opposed to length, width, and height for the area of a rectangular shape. The calculation is unaffected by how you refer to the various dimensions; for instance, you can use "depth" instead of "height."

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