A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?

Answers

Answer 1

The ratio of time of flight for inelastic collision to elastic collision is 1:2

The given parameters;

mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂

Considering inelastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]

The time of motion of the system form top of the table is calculated as;

[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]

Considering elastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]

Apply one-directional velocity

[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]

Substitute the value of [tex]v_1[/tex] into the above equation;

[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]

where;

[tex]v_2[/tex] is the final velocity of the block after collision

Since the bullet bounces off, we assume that only the block fell to the ground from the table.

The time of motion of the block is calculated as follows;

[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]

The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;

[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]

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Related Questions

a car is travelig at 20.0 m/s when the driver applies the brakes and comes to a stop. if the car slows down uniformly with an acceleration of -4.20 m/s, about how far does the car travel before coming to a rest

Answers

Since acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then

0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x

⇒   ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m

HELP ASAP WHOEVER ANSWERS FIRST WITH BE BRAINIEST PLEASE HELP!

Answers

The answer is : A₃ = A₁ - A₂ = 3.0 - 2.0 =  1.0A

Ok done. Thank to me :>

Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s

Answers

Answer:

The car that is hald as massive

Explanation:

We can use the eqation for kinetic energy to solve this problem

KE = 1/2mv^2 (where m is mass and v is velocity/speed)

Lets give the original car a mass of 100kg and use the equation

KE = 1/2(100kg)(16m/s)^2 = 12800J

and now lets find kinetic energy of the half as massive car

KE2 = 1/2(50kg)(32m/s)^2 = 25600J

From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity

If the half-life of iodine-131 is 8 days, how much of a 5.00 sample is left after 32 days?

A) 0.31

B) 2.5

C) 1.25

D) 0.62

Answers

Answer:

Option A, 0.31

Explanation:

n = Time taken / half life

n = 32/ 8

= 4

Remaining fraction = 1/2^n

= 1/2⁴

= 1/16

Amount of iodine-131 left = 1/16 × 5

= 0.3125

A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of the stone if it hit the plane a distance L down the slope from the point of launch?

Answers

Answer:

S = V t     where S is the horizontal distance traveled

1/2 g t^2 = H       where H is the vertical distance traveled

t^2 = 2 H / g

V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations

tan theta = H / S

V^2 = S g / (2 tan theta)

Using S = L cos theta

V^2 = L g cos theta / (2 tan theta)

Giving V in terms of L and theta

Explain why the formation of sand is a physical change.

Answers

In chemical changes new substances are formed and the process is often difficult to reverse. During chemical changes particles do change with atoms or ions regrouping.Bonds between atoms break and new ones
form and energy is either given out or
taken in. Some chemical changes are
initiated by mixing

Answer:

The formation of sand is a physical change because some of the physical properties of the rocks change, but their identities do not. The particles of rock are rearranged as their sizes and shapes change, but their identities and total mass remain the same.

Jeremiah rides his bicycle 4 miles in 30 minutes. If he maintains this rate, how far will he ride in 3 hours?

Answers

Answer:

24 miles.

Explanation:

3 hours=180 minutes

180÷30=6

6x4=24

NEES HELP!!!!
Which of the following is "NOT" a theory of the formation of the universe?
A. Steady State Theory
B. Doppler Theory
C. Oscillating Theory
D. Big Bang Theory

Answers

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

How much force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m?

Answers

Answer:

95 N

Explanation:

The magnitude of acceleration due to gravity is

Select one:
a. 9.8 m/s

b. 8.9 m/s?

c. 4.6 m/s?

d. 9.8 m/s2

Answers

Answer:

The magnitude of acceleration is 9.8 m/s

Explanation:

Its not always in m/s^2 but in m/s due to the unit of distance and time

Why are movie scenes in outer space often unrealistic?

Answers

Answer:

see explanation

Explanation:

by my calculations, i believe it may be because they have to pretend to be in space.

one of them is Space & Interstellar Travel

Two parents are having a child The father has freckles which are a dominant trait The mother does not have trecktes Find the possibility of the chad having tracks. ​

Answers

Answer:

2:3

Explanation:

mathqway

a car collides with a wall. compare the forces exerted by the car on the wall and the wall on the car​

Answers

Answer:

Newton’s third law states that for every action there is an equal and opposite reaction. Based on this you can say that the car crashing into the wall would put force into the wall. However, because the wall didn’t move it gives an equal force back to the car, probably causing it to crumple.

Explanation:

Mass multiplied by acceleration produces force.

The acceleration is (v - 0)/t in this situation, where t seems to be the time it takes automobile A to come to a stop. According to Newton's third law of motion, the automobile produces this turning force of the wall, however the wall, which really is static and indestructible, forces an equal force back on the car.

According to Newton's third law, each action has an equal and opposite response. On this basis, you may deduce that a car driving into a wall would exert force on the wall. However, since the wall did not move, the automobile receives an equivalent force, causing it to collapse.

Learn more:

https://brainly.com/question/13952508?referrer=searchResults

will mark brainliest if answer​

Answers

I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.

the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled points on the graph is the magnitude of the acceleration of the particle greatest?

Answers

Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.

The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

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Convert: 12 km/hr =
m/s

Answers

[tex]12~ \text{km} ~ \text{h}^{-1} = \dfrac{12 \times 1000}{3600} ~~ \text{m s}^{-1} = 3.33 ~~ \text{m s}^{-1}[/tex]

Answer:

3 1/3 or 3.3333....

Explanation:

You multiply the kilometres by 1,000 because there are 1,000 metres in a kilometre. Then you divide by 60 because there are 60 minutes per hour, and then again by 60 because 60 seconds per minute.

12,000 / 60 = 200

200 / 60 = 3.333

If a category 6 hurricane would exist how fast do you think it would be?

Answers

My Answer:The scale starts with a Category 1, which ranges from 74 to 95 mph (119 to 153 km/h). A Category 5 storm has winds of 156 mph (251 km/h) or stronger. An extrapolation of the scale suggests that if a Category 6 were created, it would be in the range of 176-196 mph.

After the series of powerful storm systems of the 2005 Atlantic hurricane season, as well as after Hurricane Patricia, a few newspaper columnists and scientists brought up the suggestion of introducing Category 6, and they have suggested pegging Category 6 to storms with winds greater than 174 or 180 mph (78 or 80 m/s).

There is no such thing as a Category 6 hurricane. When Hurricane Irma was headed toward the coast of southern Florida in August, it had maximum wind speeds of 185 mph, according to the New York Times. But the Saffir-Simpson scale only goes up to 5.Hope it helps(◠ᴥ◕ʋ)

Anyone please.??????​

Answers

Answer:

468.42572 Wavelength In Metres

Explanation:

Answer:

[tex]\huge\boxed{\sf Wavelength= 470\ m}[/tex]

Explanation:

Given Data:

Speed of light = c = 3 × 10⁸ m/s (Constant)

Frequency = f = 640 kHz = 6.4 × 10² × 10³ Hz = 6.4 × 10⁵ Hz

Required:

Wavelength = λ = ?

Formula:

λ = c / f

Solution:

λ = 3 × 10⁸ / 6.4 × 10⁵

λ = 0.47 × 10³

λ = 4.7 × 10² m

λ = 470 m

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

What should you do before inserting a wire into an outlet box?
A. Place a bushing inline.
B. Remove a foot of the outer covering.
C. Clean the terminals.
D. Strip at least three inches and re-twist the strands to retighten.

Answers

The first thing that you should do before inserting a wire into an outlet box is to remove a foot of the outer covering.

What is an outlet box?

The outlet box is sometimes called the junction box. It is from this point that  power is distributed to appliances in the home. Its main function is to protect against short circuits.

The first thing that you should do before inserting a wire into an outlet box is to remove a foot of the outer covering.

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#SPJ1

If you have a train traveling 750 m in 63
seconds how fast is the train travelling?

Answers

Answer:

The train would be moving 47,250 mph

A car that's initially traveling at 10 m/s acceleration uniformly for 4 seconds at a rate of 2 m/s?in a straight line. How far does the car travel during this time?

Answers

Answer:

Explanation:

The answer is -2m/s²

Explain the function and the difference between figure 1 and 2

Answers

Answer:

figure one (step up transformer) helps in increasing the output voltage

figure two (step down transformer) helps in decreasing the output voltage

Need
Help answering the questions

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Ummm, can’t really answer the questions if we can’t see them. You need to post more than the photos of the files my man

A dart is thrown at a target that is supported by a wooden backstop. It strikes the backstop with an initial velocity of 350 m/s [E] The dart comes to rest in 0.0050 s.

a. What is the acceleration of the dart?
b. How far does the dart penetrate into the backstop?​

Answers

Answer:u=350m/sec

v=0m/sec

t=0.005sec

a=v-u/t

=0-350/0.005

= -350/0.005

= -350×1000/5

= -70×1000

= -70000 m/sec^2

Explanation: i think this will help you thankyou

please help me please please, i will brainliest the right answer

Answers

help with whatttt? there’s nothing

a car travels at a constant speed of 20m/s and yet it does not have a constant velocity. explain how this could be

Answers

Answer:

HOPE THIS HELPS!!

Explanation:

Velocity is speed as well as distance mentioned.

The car is traveling at a constant speed of 20m/s but it may not be traveling in any particular direction. It would be taking many turns (left and right) or it would be moving in a circular manner.

So,it is at constant speed but not constant velocity.

Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.

Which part of the statement is not true?

Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.

Answers

Primary clarifiers removing biological nutrients is not true. Primary clarifiers

involves the use of processes such as sedimentation in order to remove

particles floating or other inorganic solids from the waste water.

Biological nutrients such as nitrogen and  phosphorus are found in waste

water and removal of these important nutrients for other uses is a part of

waste water management.

The secondary clarifiers are the ones responsible for the removal of

biological nutrients in the waste water through biofiltration etc.

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Your friend has a rubber band stretched between two fingers. When you pluck the rubber band, it vibrates and makes sound. What would you have to do to make the sound a higher pitch?

To make a higher pitch, stretch the rubber band more.


To make a higher pitch, pluck the rubber band less hard.


To make a higher pitch, stretch the rubber band less.


To make a higher pitch, pluck the rubber band harder.

Answers

Answer:

I think it is   To make a higher pitch, stretch the rubber band more

Explanation:

I'm not too sure. Sry if u got it wrong

Answer:

To make a higher pitch ,pluck the rubber band more

a 1.0 kg ball falls from rest a distance of 15 m. what was its change in potential energy?

Answers

Answer:

147 J

Explanation:

PE = mgh

PE = (1.0)(9.8)(15)

PE = 147 joules

a flashlight operates with a current of 3.0 a and a power of 4.5 W. what is the voltage of the flashlights battery?

Answers

Answer:

V=1.5V

Explanation:

p=I×V

4.5=3×V

[tex]v = \frac{4.5}{3} [/tex]

[tex]v = \frac{3}{2} [/tex]

v=1.5

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