Answer:
a= 17.69 m/s^2
Explanation:
Step one:
given data
A car accelerates uniformly from rest to 23 m/s
u= 0m/s
v= 23m/s
distance= 30m
Step two:
We know that
acceleration= velocity/time
also,
velocity= distance/time
23= 30/t
t= 30/23
t= 1.30 seconds
hence
acceleration= 23/1.30
accelaration= 17.69 m/s^2
Fill in the chart with the correct values of F for each change in the system described in questions
Answer:
We know that the gravitational force F between two masses P and Q, that are separated by a distance R is:
[tex]F = G*\frac{P*Q}{R^2}[/tex]
Where G is the gravitational constant.
a) Mass P is doubled, then we have 2*P instead of P, the new force is:
[tex]F' = G*\frac{(2*P)*Q}{R^2} = 2*(G*\frac{P*Q}{R^2} ) = 2*F[/tex]
b) Now R is doubled, then instead of R, we have 2*R:
[tex]F' = G*\frac{P*Q}{(2*R)^2} = G*\frac{P*Q}{4*R^2} = G*\frac{P*Q}{R^2}*(1/4) = F/4[/tex]
c) Now we replace P by 2*P, and Q by 3*Q
[tex]F' = G*\frac{(2*P)*(3*Q)}{R^2} = 2*3*(G*\frac{P*Q}{R^2} ) = 6*F[/tex]
d) The entire mass of the system is increased by a factor of 4, then both of the individual masses are increased by a factor of 4.
Then we need to replace P by 4*P, and Q by 4*Q.
[tex]F' = G*\frac{(4*P)*(4*Q)}{R^2} = 4*4(G*\frac{P*Q}{R^2} ) = 16*F[/tex]
e) Now we replace R by R/2.
[tex]F' = G*\frac{P*Q}{(R/2)^2} = G*\frac{P*Q}{R^2/4}= 4*G\frac{P*Q}{R^2} = 4*F[/tex]
Find the Horizontal (x) vector for these forces.
Answer:
See the explanation below.
Explanation:
The force is a vector therefore we can decompose the force into components x & y. as we need the horizontal component of the force, we must use the cosine function of the angle.
[tex]F_{1x}=30.8*cos(20)\\F_{1x}=28.94[N]\\F_{2x}=34.3*cos(20)\\\\F_{2x}= 32.23[N][/tex]
What happens to the amplitude of the resultant wave when two sound waves with equal amplitude constructively interfere?
Answer:
For two waves of equal amplitude interfering constructively, the resulting amplitude is twice as large as the amplitude of an individual wave. For 100 waves of the same amplitude interfering constructively, the resulting amplitude is 100 times larger than the amplitude of an individual wave.
rank in terms of momentum
A. A 10,000 kg train car at rest
B. A 100 kg person running at 5 m/s
C. A 1200 kg car going 15 m/s
D. A 15 kg meteor going at a speed of 1000 m/s
Answer:
See the explanation below,
Explanation:
Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.
[tex]P=m*v[/tex]
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
A)
[tex]P = 10000*0\\P=0[/tex]
B)
[tex]P=100*5\\P=500[kg*m/s][/tex]
C)
[tex]P=1200*15\\P=18000[kg*m/s][/tex]
D)
[tex]P=15*1000\\P=15000[kg*m/s][/tex]
From higher to lower momentum
C,D,B,A
Suppose you have a string of length LaTeX: LL clamped down on both sides. Is it possible for the wavelength of a standing wave on this string to equal LaTeX: L/3L / 3
Answer:
Explanation:
For a string of length L clamped down on both ends , for fundamental mode of vibration
2 . λ / 4 = L
= λ / 2 = L
λ = 2 L
For other modes , the formula is
n . λ/2 = L where n is an integer .
λ = 2L / n
if n = 6
λ = 2L / 6
= L/3
So wavelength = L/3 is possible .
2. A rock is shot straight up into the air with a slingshot that had been stretched 0.30 m. Assume
no air resistance.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
m= 500 g
A
• Y=0
Position A
Position
System/Flow
O
k=100N
- 100
a 옝
&x=0.30m
Om
KE PE, PE
KE PE, PEe Ethermal
Initial
Final
b. Quantitative Energy Conservation Equation
C
Determine the greatest height the rock could reach.
Answer:
e
Explanation:
Two marbles, one twice as massive as the other, are dropped from the same height. When they strike the ground, how does the kinetic energy of the more massive marble compare to that of the other marble
Answer: The more massive one will have larger kinetic energy.
Explanation:
We know that when we drop an object, the acceleration of the object will be equal to the gravitational acceleration.
a(t) = -9.8m/s^2
And to get the velocity, we need to integrate over time, to get:
v(t) = (-9.8m/s^)*t + v0
Where v0 is the initial speed of the object.
You can see that the mass of the object does not affect the velocity of it.
Then when we drop two marbles of different masses from the same height, we know that the final velocity of them will be equal.
Now, we also know that the kinetic energy can be written as:
K = (m/2)*v^2
where m is the mass, and v is the velocity.
Then the kinetic energy of the marble with less mass can be written as:
k = (m/2)*v^2
And the kinetic energy for the more massive one is:
K = (M/2)*v^2
And we know that both of them have the same velocity, and M is larger than m, then we can conclude that the marble with larger mass will have larger kinetic energy.
At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 300 N/C. At a distance r2 from the charge, the field has a magnitude of 160 N/C. Find the ratio r2/r1.
Answer:
the ratio of r₂/r₁ is 1.37.
Explanation:
Given;
magnitude of electric field strength at a distance r₁, E₁ = 300 N/C
magnitude of electric field strength at a distance r₂, E₂ = 160 N/C
Electric field strength is given as;
[tex]E = \frac{kQ}{r^2} \\\\E_1r_1^2 = E_2r_2 ^2\\\\\frac{E_1}{E_2} = \frac{r_2^2}{r_1^2} \\\\\frac{E_1}{E_2} =( \frac{r_2}{r_1})^2\\\\\sqrt{\frac{E_1}{E_2} } = \frac{r_2}{r_1}\\\\\frac{r_2}{r_1} = \sqrt{\frac{300}{160} }\\\\\frac{r_2}{r_1} =1.37[/tex]
Therefore, the ratio of r₂/r₁ is 1.37.
What is it known as when a force is applied to an object for an amount of time?
momentum
impulse
inertia
acceleration
Answer:
Impulse. Impulse is when a force is applied to an object for an amount of time.
Explanation:
It can't be momentum because momentum is the motion of a moving body, that is measured as a product of its mass and velocity.
It' cant be inertia because inertia is when an object doesn't move/ it does nothing as well as an object remaining unchanged.
And it can't be acceleration because acceleration is when how fast an object can go/ there velocity.
And that leaves us with impulse, so that's the correct one.
Hope this helped!
Answer:
impulse
Explanation:
took the test
You're driving your new sports car at 80 mph over the top of a hill that has a radius of curvature of 540 m. What fraction of your normal weight is your apparent weight as you crest the hill?
Answer:
75.84%
Explanation:
We were given Speed of the sports car, v as 80 mph , we can convert to m/s for unit consistency.
v=80mph= 35.76 m/s
The radius of curvature is given as , r = 540 m
✓ the normal weight can be denoted as Wn
✓ the apparent weight of the person can be denoted as Wa
Wn= normal weight= mg
Wa=apparent weight = (mg - mv^2/r)
g= acceleration due to gravity= 9.8m/s^2
The apparent weightand normal weight has a ratio of
Mn/Ma= [mg - mv^2/r]/mg ........eqn(1)
If we simplify eqn(1) we have
Mn/Ma=[g - vr^2/g].............eqn(2)
Then substitute the given values
Mn/Ma=9.8 - [(35.76^2)/540]/ 9.8
=0.758×100%
Mn/Ma=75.84%
Hence, the required fraction is 75.84%
which two types of potentional energies would be types of mechancial energies
Answer:
Gravitation Potential Energy and Elastic Potential Energy
Explanation:
PE=abbreviation for potential energy
PE is a mechanical energy like KE is. There are two types of PE in high school physics (do not talk about other PE's like chemical PE).
Elastic PE is like the stored energy for example in a pole vault competition, the Elastic PE is stored in the pole before the vaulter goes over the desired height. (Energy stored in ELASTIC object ONLY) (commonly on the 11th grade regents springs are used to represent elastic PE)
Gravitational PE can be calculated through the formula PE=mgh although some people substitute the PE with a U. (ENERGY STORED IN OBJECT'S HEIGHT)
What forces are related to a person pushing a large crate accross the floor?
Answer:
98
Explanation:
Answer:
friction, air resistance
Explanation:
A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?
Answer:
Δp = 620 N.s
Explanation:
Newton's second law, was originally conceived as follows:[tex]F = \frac{\Delta p}{\Delta t} (1)[/tex]
In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.for m= constant, it reduces to F= m*a.
Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:[tex]\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)[/tex]
find the length of the smallest standing wave that can be formed with light having frequency 600 THz
Answer:
[tex]L=2.5*10^-^7m[/tex]
Explanation:
From the question we are told that
Frequency of light [tex]f= 600 THz[/tex]
Generally the equation for wave is mathematically given as
[tex]\lambda=\frac{c}{\gamma}[/tex]
Where
[tex]1THz=10^1^2[/tex]
[tex]\lambda=\frac{3*10^8}{600*10^1^2}[/tex]
[tex]\lambda=0.5*10^-^6m[/tex]
Generally the equation for a fundamental Frequency is mathematically given as
[tex]L=\frac{\lambda}{2}[/tex]
[tex]L=\frac{0.5*10^-^6}{2}[/tex]
Therefore the length of the smallest standing wave
[tex]L=2.5*10^-^7m[/tex]
A 110 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be done on the hoop to stop it
Answer:
the work that must be done to stop the hoop is 2.662 J
Explanation:
Given;
mass of the hoop, m = 110 kg
speed of the center mass, v = 0.22 m/s
The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;
W = ΔK.E
W = ¹/₂mv²
W = ¹/₂ x 110 x 0.22²
W = 2.662 J
Therefore, the work that must be done to stop the hoop is 2.662 J
The amount of work that must be done to stop a hoop of mass 110 kg moving with s speed of 0.220 m/s is 2.662 J
Work can be defined as the ability or the capacity to perform work. Work is also the measure of energy of a body. The S.I unit of work is Joules (J)
From the question, The kinetic energy of the hoop = The energy required to stop the hoop.Formular for kinetic energy of the hoop is
EK = mv²/2.................... Equation 1
Where EK = Kinetic energy of the hoop, m = mass of the hoop, v = velocity of the hoop.
Given: m = 110kg, v = 0.220 m/s.
Substitute these values into equation 1
EK = 110(0.22)²/2
Ek = 2.662 J.
Therefore, The amount of work that must be done on the hoop to stop it is
Learn more about Work here: https://brainly.com/question/12106685
A 0.5 m3 container is filled with a fluid whose specific volume is 0.001 m3/kg. At standard gravitational acceleration, the contents of this container weigh:
Answer: the contents of this container weighs 4905 kg.m/s²
Explanation:
Given that;
volume of a container V = 0.5 m³
we know that standard gravitational acceleration g = 9.81 m/s²
specific volume of liquid filled in the container v = 0.001 m³/kg
now we express the equation for weight of the container.
W = mg
W = (pV)g
W = Vg / ν
so we substitute
W = (0.5 m³)(9.81 m/s ) / 0.001 m³/kg
W = 4.905 / 0.001
W = 4905 kg.m/s²
Therefore, the contents of this container weighs 4905 kg.m/s²
6.A nurse pushes a woman in a wheelchair at a constant acceleration up a ramp for a period of 17.5 s. At the base of the ramp, the wheel chair is at rest, and at the top of the ramp, the
wheelchair has a velocity of 0.50 m/s. The woman and her wheelchair have a combined
mass of 65.0 kg. What is the magnitude of the net force on the woman and her wheelchair
as they acceferate up the ramp?
(A) 0.27 N
(B) 1.9 N
(C) 2.3 N
Answer:
The answer is :(B) 1.9 N
please make my answer brainlist
What needs to happen to make electrical current flow in a generator?
How does water move from the surfaces of lakes, rivers, and the ocean directly back into the atmosphere?
A.precipitation
B.evaporation
C.condensation
Answer:
B. Evaporation
Explanation:
Because I am absolutely positive
Please give Brainlyest
when someone pushes a large crate across floor. what forces act upon the crate
friction, applied, gravity or air resistance?
Answer:
Friction, Applied Force and Gravity
PLEASE HELP (100)
A block M, with mass of 4 kg, is released from rest and slides down a ramp that is angled at 28° above the horizontal (from the bottom of the ramp). The length of the ramp, d, is 3 meters. How much work is done by the gravitational force as the block slides down the ramp?
Answer:
The work done will be [tex]W=55.27\: J[/tex]
Explanation:
The work equation is given by:
[tex]W=F\cdot x[/tex]
Where:
F is the force due to gravity (weight = mg)
x is the length of the ramp (3 m)
Now, the force acting here is the component of weight in the ramp direction, so it will be:
[tex]F_{x-direction}=mgsin(28)[/tex]
Therefore, the work done will be:
[tex]W=mgsin(28)*3[/tex]
[tex]W=4*9.81*sin(28)*3[/tex]
[tex]W=55.27\: J[/tex]
I hope it helps you!
please genuinely help. 15 pts
:(
Two surfaces in contact are moving slowly past each other. As the relative speed between the two surfaces in contact increases, what happens to the magnitude of their coefficient of kinetic friction
Answer:
It begins to increase
Explanation:
As the surfaces move slowly and then increase their relative speeds, the coefficient of kinetic friction begins to increase until it reaches it terminal value in which, it can no longer increase.
What does a negative velocity indicate about an object's motion? Plz help
Answer:
The sign of the velocity depends on the coordinate system chosen to define the position. A positive velocity simply means that the object is moving in the positive direction, as defined by the coordinate system, while a negative velocity means the object is traveling in the other direction.
- Hope this helps!
a projectile is fired so that when it reaches the maximum height h it has speed vtop when the projectile is at h/2 the speed is 2vtop at what angle is the projectile fired
Answer:
Explanation:
Let the velocity of firing be u at angle θ
At maximum height velocity will be equal to horizontal component of initial velocity or vcosθ
So , vtop = v cosθ
At height h/2
vertical component of velocity v₂
v₂² = (usinθ)² - 2 g . h/2
v₂² = u²sin²θ - gh
horizontal component of velocity at height h/2 = u cosθ
velocity at height h / 2
= √ ( u²sin²θ - gh + u² cos²θ)
Given
√ ( u²sin²θ - gh + u² cos²θ) = 2 vtop
u²sin²θ - gh + u² cos²θ = 4 v²top = 4 u² cos²θ
u²sin²θ - gh = 3 u² cos²θ
At height h , vertical component of velocity is zero
0 = u²sin²θ - 2gh
gh = u²sin²θ / 2
u²sin²θ - u²sin²θ / 2 = 3 u² cos²θ
u²sin²θ / 2 = 3 u² cos²θ
Tan²θ = 6
Tanθ = 2.45
θ = 68⁰ .
A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an amplitude of 0.143 mm and a frequency of 76.9 Hz and is traveling in the negative direction of an x axis. If the wave equation is of the form y(x,t) = ym sin(kx + ωt), what are (a) ym, (b) k, and (c) ω, and (d) the correct choice of sign in front of ω?
Answer:
a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s d. +1
Explanation:
a. ym
Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm
b. k
We know k = wave number = 2π/λ where λ = wavelength.
Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.
So, λ = v/f = √(T/μ)/f
substituting the values of the variables into the equation, we have
λ = √(T/μ)/f
= √(19.6 N/0.512 kg/m)/76.9 Hz
= √(38.28 Nkg/m)/76.9 Hz
= 6.187 m/s ÷ 76.9 Hz
= 0.081 m
= 81 mm
So, k = 2π/λ
= 2π/0.081 m
= 77.6 rad/m
c. ω
ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz
So, ω = 2πf
= 2π × 76.9 Hz
= 483.18 rad/s
d. The correct choice of sign in front of ω?
Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.
Why don't we use x-ray to communicate information?
Answer: The difficulty comes in the modulation, and in the fact that X-rays can't be transmitted via wires or fiber.
Explanation: Mark me as brainlisti
glucose+oxygen--->carbon dioxide+water+energy= What reaction??
Fill in the answers to describe this chemical equation.
Name the reactants in this reaction.
Name the products in this reaction.
How many oxygen atoms are involved in this reaction?
Is this equation balanced, and how can you tell?
Is this reaction endothermic or exothermic, and how can you tell?
I REALLY NEED HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
combustion reaction
glucose,oxygen
carbon dioxide,water,energy
8
no. required balanced equation is:
C6H12O6+6O2--->6CO2+6H2O+energy
endothermic as it needs heat in the form of sunlight.
A ball rolls across a smooth surface at a steady 0.5 m/s. What is its acceleration? m/s^2?
Answer:
0m/s²
Explanation:
The acceleration of the given body whose motion has been described will be zero.
This is because the body moves with a constant velocity.
Acceleration is defined as the rate of change of velocity with time.
Since in this problem, the velocity is not changing per time, then the acceleration would be zero.
A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.
Which common characteristic of planets do Saturn and Earth share?
They have rings.
They have moons.
They are made of rock.
They have thick atmospheres.
The common characteristics of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.
What is moons of planets?Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.
The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.
Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.
To find more on saturn, refer here:
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