A car drives horizontally off a 63-m-high cliff at a speed of 29 m/s . Ignore air resistance.

1. How long will it take the car to hit the ground? (in seconds)
a) 2.9
b) 4.0
c) 3.6
d) 1.9
e) 5.2

2. How far from the base of the cliff will the car hit? (in meters)
a) 54
b) 190
c) 100
d) 210
e) 250

I already know the answers to these questions, but if I could have an explanation as to how to solve these problems I would greatly appreciate it!!

The initial velocity of the cart.

Newton, There can be a mass is four.080, So acceleration might be equal to 2.50 m in step with cent within the rectangular. Initial is that amount that relies upon total mass. The greater mass the more inertia. So Mass is 2000 kg and acceleration is 3 ms square. So this offers us an internet pressure identical to 6000 newtons or 6.0 and 210 to the power

In case you roll a ball, it initially will keep rolling except friction or something else stops it by means of pressure. you could also think about the way that your body maintains transferring ahead when you hit the brake on your bike. Translational Inertia = ma, in which m is the mass, and a is the acceleration of the object. Calculate the rotational inertia or the instant of inertia velocity by way of multiplying the mass of the object with a square of the gap between the item and the axis, the radius of rotation.

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Answer:

wow

Explanation:

Answer: iron

Explanation: yw

Answer:

electron, lightest stable subatomic particle known. It carries a negative charge of 1.602176634 × 10−19 coulomb, which is considered the basic unit of electric charge. The rest mass of the electron is 9.1093837015 × 10−31 kg, which is only 1/1,836the mass of a proton.

Explanation:

I hope this will be helpful for you.

Answer:

1.25 m

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the ball separately.

As the ball rolls off the table with a horizontal velocity only, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 10 ms⁻²

As we need to find the vertical displacement of the ball, resolve vertically, taking ↓ as positive:

[tex]u=0 \quad a=10 \quad t=0.5[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(0)(0.5)+\dfrac{1}{2}(10)(0.5)^2\\s&=0+\dfrac{1}{2}(10)(0.25)\\s&=(5)(0.25)\\ \implies s&=1.25 \; \sf m\end{aligned}[/tex]

Therefore, the vertical displacement of the ball is 1.25 m, and so the table is 1.25 m above the floor.

The sides of a small rectangular box are measured to be 1.80 ± 0.01 cm, 2.05 ± 0.02 cm, and 3.1 ± 0.01 cm long. Its volume and uncertainty is 11.4 ± 0.2 cm³.

While doing certain experiments or calculation we can end a less precise value that what actually it's the answer of the experiment, this exact value of the experiment is called true value.

In physics uncertainty refers to the possible variation from the true value. Variation is calculated for possible increment in the precision of the result.

These are the rules for doing basic operation on uncertainty :

If you're adding or subtracting quantities with uncertainties, you add the absolute uncertainties.

If you're multiplying or dividing, you add the relative uncertainties.

If you're multiplying by a constant factor, you multiply absolute uncertainties by the same factor, or do nothing to relative uncertainties.

Now in the given question we have to multiply the uncertainty, so we will simply add the relative error.

To find volume of the cubic structure we simply multiply the error free values.

Volume of the cuboid = Length × Breadth × Height

Volume of the cuboid = 1.80 cm × 2.05 cm × 3.10 cm

Volume of the cuboid = 11.4 cm³

Uncertainty in the volume[tex]= \frac{0.01\ cm}{1.80\ cm} \times 100\% + \frac{0.02\ cm}{2.05\ cm} \times 100\% + \frac{0.01\ cm}{3.1\ cm} \times 100\%[/tex]

= (0.55 + 0.97 + 0.32) × 11.4

= 1.84 × 11.4

= 20.976

Now,

δA = Percent Uncertainty / 100%

     = 20.976 / 100

     = 0.2 cm³

Thus from the above conclusion we can say that Its volume and uncertainty is 11.4 ± 0.2 cm³.

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Answer:

6.5 km/ h

Explanation:

24 minutes = 24/60 = 0.4 hours

v = 2.6 / 0.4 = 6.5 km/h

Hope this helps

Answer:

equal to the speed of the object.

The particle B will pass particle A in 1.10s.

Using kinematic formula,

d = Vini x t + 1/2 at²

where,

d is distance

Vini is velocity initial

a is acceleration

t is time

So, putting values

7.7 t + 1/2 x 1.8 t^² = 2.9 t + 1/2 x 5.7 t²

7.7 t + 2.7 t² = 2.9 t + 8.55 t²

t + t² / t + t² = 2.9 + 8.55 / 7.7 + 2.7

t = 1.10s

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The potential in the parallel-plate capacitor which has a separation of 3.34mm, and each has an area of 10.0 cm² has a potential of 2.52 giga .

Capacitance of a capacitor is a physical property that refers to the ratio of charge store in the parallel plate capacitor to its potential.

Vacuum permittivity, commonly denoted ε₀, is the value of the absolute dielectric permittivity of classical vacuum. It may also be referred to as the permittivity of free space, the electric constant, or the distributed capacitance of the vacuum.

Given:

Charge in the parallel plate capacitor =  670 micro coulomb

Area of the parallel plate capacitor = 10 cm square

Area of separation between plate = 3.34 mm

First we will find the the capacitor in the parallel plate capacitor using its formula.

Capacitance = 2.65 Pico meter

Using the defination of capacitance we have,

Potential of the parallel plate capacitor = capacitance × charge

Potential of the parallel plate capacitor = 670/2.65

Potential of the parallel plate capacitor = 2.52 giga

Therefore, The potential in the parallel-plate capacitor which has a separation of 3.34mm, and each has an area of 10.0 cm² has a potential of 2.52 giga .

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In the SI unit, the quantity could be measured in amperes per second.

The resistor refers to the opposition that is offered to the flow of current. This opposition to the flow of current is offered by a circuit component that is called the resistor. Technically, any of the circuit components except the cell is able to offer this kind of opposition to the flow of current.

Recall that Ohm's law states that the voltage is directly proportional to the current in the circuit. The constant of proportionality here is the resistor. We can now write;

V = IR

V = voltage

I = current

R = resistance

Note that the SI system is the system that details the correct unit for quantities that is internationally accepted globally. Now from the SI units base, we can see that the resistance could be measured in Amperes per second. This unit is commonly called the ohm.

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The maximum value of the resistance is 105,000 Ω

We are given the following properties of the resistor as;

Resistance =  10,000-Ω

Tolerance = 5%

Now, when we say a tolerance of 5%, it means the value of the resistance can only reduce or increase by a maximum of 5%.

Thus;

For a decrease of 5%, we would get the minimum value of the resistance which is;

Minimum value = (100% - 5%) * 10000

Minimum value = 95000 Ω

Then the maximum value of the resistance is;

Maximum Value = (100% + 5%) * 10000

Maximum Value = 105,000 Ω

Thus, the maximum value of the resistance is 105,000 Ω

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Answer:

a wave that moves along the interface of two different materials, like air and water

Explanation:

The electric potential energy of this charge increase as it moves through the battery is 6.84 J.

The power required to move a charge in opposition to an electric field is known as electric potential energy. A charge must be moved through a stronger electric field with more energy, but it also must be moved through a weaker electric field with more energy. The energy gained when an object moves against an electric field is known as the electric potential energy. The electric potential is calculated for any charge by dividing the potential energy by the charge.

Emf of the battery = 11.4 V

Current used = 0.60 A

Current = Charge / Time

The charge per second is 0.60 C. Therefore, the electric potential energy will be:

U = qv

U = Current used × Emf

U = 0.60 × 11.4

U = 6.84 J

Therefore, the electric potential energy of this charge increase as it moves through the battery is 6.84 J.

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When I started exercising consistently in my late 30s, I experienced firsthand the profound effects exercise has on both the body and the brain. Honestly, these realizations completely changed my inspiration to go to a recovery center.

It started when a powerboat tripped in Peru's mighty Cotahuasi Channel in one of the deepest valleys on earth. On this voyage, I found that although I was healthy, I was not as healthy as my relatives in the channel rafters.

There was a 16-year-old on a school trip who had more endurance than me, and a 60-year-old who had more endurance than me. I realized I had to take care of business. you are balanced These forces cancel each other out and the motion of the bodies they act on remains unchanged.

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Force has four components: its magnitude, its direction, point of application, and course of action.

A force acting on an item causes it to change shape or size, to move, to stop moving, to accelerate or decelerate. When two things come in contact, they exert a force on each other that is equal in size but opposing in direction.

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The normal force acting on the block is 49 N in upward direction

It is given that

mass of block is 5kg

And we have to find the Normal force on block

The force surfaces apply to stop solid objects from passing through one another is known as the normal force.

A contact force is a normal force. A normal force cannot be applied between two surfaces that are not in contact.

Since, block is at rest and no other force is acting on it so only force acting on it is by the table and it is in upward direction

Force = mg = 5 x 9.8 = 49 N in upward direction

Hence, normal force acting on block is 49 N in upward direction

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The impulse of the cart is 18.2 kg-m/s

We are required to find the impulse on the cart

It is given to us that mass of cart is 13kg

It is also given that increase in speed is 1.4 m/s

We are required to find the impulse on the cart

Impulse :

Impulse of a body is defined as change in the momentum of the cart.

Impulse I = m(v-u)/t

Now  (v-u)/t is the change in speed and it is given to us that there is increase in speed and hence it must be positive.

(v-u)/t = 1.4m/s

Therefore,

Impulse of cart is equal to its change in momentum:

Putting the value of mass  in the equation, we get:

I = m(v-u)/t

  = 13 x 1.4 = 18.2 kg-m/s

Therefore, the impulse of the cart is 18.2 kg-m/s

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The mass flow rate of water is 5.146×10³ kg/s

The enthalpy change that occurs during a reaction is the heat that enters or exits the system. A critical factor that determines whether a reaction may occur is whether the enthalpy of the system increases (i.e., because energy is added) or lowers (i.e., because energy is given off).

Elevational difference (Z1-Z2) =15m

V1 = the inlet velocity, V2 = the outlet velocity

Using the equation for steady-state energy Q+m(h1+V2/12+g/z1) =W+m(h2+V22/2+gz2),

m(h1+V21/2+g/z1) m(h2+V22/2+g/z2) =WQ, and m(h1h2+V2/12V22/2+g/z1g/z2) =WQ.

The change in enthalpy and the rate of heat transfer are both zero because the pressure and temperature have barely changed.

m (0−0+0/22−10/22+9.81× (15))

=500×1000m\s

=5.146×10³ kg/s

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The physical stimulation of the sense organs is known as sensation. The act of mentally classifying, interpreting, analyzing, and integrating stimuli from the senses and the brain is known as perception.

Therefore, sensory and perceptual development is very necessary in infants.

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Part A: capacitance =  2.650 × [tex]10^{-12}[/tex] F

Part B: the potential difference between the plates =  2.5250 × 10²  V

Part C: the magnitude of the electric field between the plates = 7.56 × [tex]10^{6}[/tex]  V/m

Given:

distance between plates(d) = 3.34 × [tex]10^{-3}[/tex] m

Area of plates(A) = 10 × [tex]10^{-4}[/tex] m²

Charge(Q) = 6.70 × [tex]10^{-8}[/tex] C

electric constant(εo) = 8.8542× [tex]10^{-12}[/tex]  F/m

The capacitance is given by:

C= εo*A/d

  = (8.8542× [tex]10^{-12}[/tex]  × 10 × [tex]10^{-4}[/tex] )/ 3.34 × [tex]10^{-3}[/tex]

   = 2.650 × [tex]10^{-12}[/tex] F

To calculate the Magnitude of the electric field between the plates

⇒ E=σ/εo ,where σ = Q/A

    σ =  6.70 × [tex]10^{-8}[/tex] /  10 × [tex]10^{-4}[/tex]

       =  6.70 × [tex]10^{-5}[/tex]  C[tex]m^{-2}[/tex]

Now, E =   6.70 × [tex]10^{-5}[/tex] /  8.8542× [tex]10^{-12}[/tex]

             =    7.56 × [tex]10^{6}[/tex]  V/m

To find the potential difference between the plates;

V=E×d

  = 7.56 × [tex]10^{6}[/tex] × 3.34 × [tex]10^{-3}[/tex]

  =   2.5250 × 10²  V

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Answer:

10 N

Explanation:

Newton's Second Law equation: Fnet = ma

Assuming no frictional force, plug in the values to get your answer!

Fnet = 5kg x 2m/s^2 = 10 N

Answer: 45 m/s and 80 m/s

Explanation:

The acceleration due to gravity on an object is 9.8 m/s^2

Simply multiple this my the the time that it has fallen (in seconds) and this will provide you with its velocity at that time.

(4.5 seconds) (9.8) = 44.1 m/s

(8 seconds) (9.8) = 78.4 m/s

Values are rounded off for the final answer.

The average speed in km/h will be 93.342 km/hr for 58 mph.

Speed is defined as the ratio of distance and time, and average speed is defined as the overall distance the object covers in a given amount of time is its average speed. The scalar quantity represents the average speed. It does not have direction; it is represented by magnitude.

Average Speed=[tex]\frac{total distance}{total time}[/tex]

According to the question, the speed is given i.e., 58mph

1 mph=1.61 km/hr

⇒58 mph= 1.61×58

⇒93.342 km/hr

Hence, the speed in km/hr will be 93.342 km/hr for 58 mph.

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Answer:

Measuring a patient's body weight can be done to Assess and monitor fluid and nutrition status as part of a nutrition screening tool. Calculate drug doses. Calculate nutrition and fluid support if required. Monitor the effectiveness of nutritional support.

Explanation:

Answer:

2,000

Explanation:

Answer: 2000 meters would be the distance you walked, but if you need it in feet, it is 6,561.67979.

Explanation: 1 meter = 3.28 feet.

The frequency in Hz if the wavelength is 0.70 X 10-⁶ m is 4.3 × 10¹⁴ Hz.

The frequency of a wave can be calculated by dividing the velocity of the wave by the wavelength as follows:

f = v/λ

Where;

According to this question, the wavelength of a wave is given as 0.70 X 10-⁶ m. The speed of light is 3.00 × 10⁸ m/s. The frequency can be calculated as follows:

f = 3 × 10⁸m/s ÷ 7 × 10-⁷m

f = 4.3 × 10¹⁴ Hz

Therefore, the frequency in Hz if the wavelength is 0.70 X 10-⁶ m is 4.3 × 10¹⁴ Hz.

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Answer:

A

Explanation:

When a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.

According to the question, when a spring is stretched or compressed, the restoring force generated in the spring (towards its mean position) is directly proportional to the length to which it is stretched or compressed.

Mathematically - F = - Kx

Given is a situation in which a stretch of 8 cm is caused by a 100g mass.

From this, we can write -

Mass [m] = 100 g = 0.1 Kg

Displacement [x] = 8 cm = 0.08 m

According to the question -

We will first find the spring constant [K]. Using Hook's law -

F = -Kx

mg = -Kx

K = - mg/x

K = - (0.1 x 9.8) / 0.08

K = - 12.25 N/m

|K| = 12.25 N/m

Now, when mass [M] = 25g = 0.025 Kg, using Hook's law -

|F| = |- kx| = kx

Mg = 12.25x

x = Mg/12.25

x = (0.025 x 9.8)/12.25

x = 0.02

x = 2 cm

Therefore, when a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.

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Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Newton’s third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction. This law is important in analyzing problems of static equilibrium, where all forces are balanced, but it also applies to bodies in uniform or accelerated motion.

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The first law represented in the game would be the candy. If you blow it, it would move but then stop due to friction.

The second law would be represented by blowing the candy. Since the candy was light, it would be easier to blow but if it was heavier, it would be a lot harder.

The final law represented in the game would be if you decided to blow the candy with a ballon instead, the candy would move the opposite direction the ballon is moving.

The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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The charge is obtained as 2.19 * 10^-5 C the electric field is obtained as 1 * 10^-7 N/C.

We know that the electric field is the created as a result of the presence of one charge close to another. The magnitude of the electric charge that would make the particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 650 N/C is required here.

a) Recall that the eight is also a force and counterbalanced the electric force hence;

W = mg = Eq

mg = Eq

g = 9.8 m/s^2

1.45 * 10^-3 Kg * 9.8 m/s^2 = 650 N/C * q

q = 1.45 * 10^-3 Kg * 9.8 m/s^2/650 N/C

q = 2.19 * 10^-5 C

b) The charge on the proton is 1.6 * 10^-19 while the mass of the proton is 1.67 * 10^-27 Kg

F= 1.67 * 10^-27 Kg * 9.8 m/s^2 = 1.6 * 10^-26 N

The electric field is obtained from;  1.6 * 10^-26 N/1.6 * 10^-19

= 1 * 10^-7 N/C

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