A car drove 200 km east on an interstate highway, then was finally able to make an
exit and drove for another 70 km to the north before reaching their destination.
What was the direction of car's resultant displacement?

Answer:

The term 'mettaloid' is normally applied to a group of between six and nine elements ;

are found near the center of the P-block or main block of the periodic table.

Explanation:

Answer:

D

Explanation:i think but dont get mad if im wrong

Answer:

The answer is C.

Explanation:

Explanation:

Weight of an object is shows the force of gravity acting on it. It is calculated mass times acceleration due to gravity.

lb is the unit of avoirdupois weight. It means that 12 lb shows weight.

gram, kg is the unit of mass. It means 0.34 g and 120 kg shows mass of an object.

m and cm are the units of length. It means 0.34 m and 411 cm shows the length of the object.

N is the unit of weight.

Hence, 12.0 lb and 1600 kN are acceptable representations of weight.

Answer:

when this charged glass rod is brought towards the metal ball it will acquire a charge opposite to that of charge body brought close to it without touching it but it will acquire the same charge if the charged object touches it

Answer:

B.The glass and the paper have different charges.

Explanation:

Explanation:

The force on an object due to it's mass and gravity.

Answer:5

Explanation:

You do change in y over change in X

Answer:

The answer is below

Explanation:

Given that:

y = transverse displacement = 4.2 cm = 0.042 m at x = 0 and t = 0.

Speed = v = 89 m/s, maximum transverse speed of the string particle = [tex]u_m[/tex] = 16 m/s.

ω = [tex]u_m[/tex] / [tex]y_m[/tex] = 16 / 0.42 = 380.95 rad/s

a) Frequency = ω/2π = 380.95 / 2π = 60.63 Hz

b) Wavelength (λ) = speed / frequency

λ = v / f = 89/63.66= 1.468 m

c) Using the wave equation:

[tex]y=y_msin(kx \pm wt \pm \phi)\\y=0.042,t=0,x=0\\\\Hence\\y_m=0.042\ m[/tex]

d) Wave number k is given by:

k = 2π / λ = 2π / 1.468 = 4.28 rad/s

e) The angular velocity is given by:

ω = [tex]u_m[/tex] / [tex]y_m[/tex] = 16 / 0.42 = 380.95 rad/s

f)  Using the wave equation:

[tex]y=y_msin(kx \pm wt \pm \phi)\\\\y=0.042,t=0,x=0,y_m=0.042\\\\Hence\\0.042=0.042sin(4.28(0)\pm 380.95(0)\pm \phi)\\\\sin\phi=1\\\\\phi=\frac{\pi}{2} \\\\y=0.042sin(4.28x\pm 380.95t\pm \frac{\pi}{2})[/tex]

g) Since the wave is in the positive x direction, hence ω is negative

Newton's second law allows us to find the result for the effect of building a lower mass bike is:

Newton's second law states that force is equal to the product of mass and acceleration of the body.

          ∑ F = m a

Where the bold letters indicate vectors, m is the mass and  a the acceleration.

They indicate that the bicycle is made of bamboo, so it has less mass, therefore the acceleration is:

          [tex]a = \frac{\sum F}{m}[/tex]

if the mass decreases, more acceleration is recorded, therefore from the kinematic reactions the bicycle reaches higher speeds.

         v = v₀ + a t

The bicycles parts of the rest.

          v = a t

In conclusion, using Newton's second law we can find the result for the effect of building a bicycle with alower mass is:

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Answer:

4.61 m away

Explanation:

No, the owl will not fall into the nest.

The vertical component of the velocity, v of mouse after travelling vertical distance of 12 m is given by

v² - (4 * sin 32)² = 2 * 9.81 * 12

v² - (4 * 0.53)² = 235.44

v² - 4.494 = 235.44

v² = 235.44 + 4.494

v² = 239.934

v = 15.49 m/s

The time taken to travel the said 12 m downwards =

(15.49 - 4 * sin 32) / 9.81

(15.49 - 4 * 0.53) / 9.81

(15.49 - 2.12) / 9.81

13.37 / 9.81 = 1.36 s

Horizontal distance traveled in this time = 4 * (cos 32) * 1.36

= 4 * 0.848 * 1.36

= 4.61 m

Therefore, the horizontal position of the mouse is 4.61 m away from the point of release.

Answer: las respuestas correctas son b, c y  d.

indican cantidad

Explanation:

observation is something what you could observe from your organs like eyes ears etc and also it is what you observed during an event for an experiment but inference is what you decide to do after observation or an event.

the act of inferring (to derive by reasoning). Observation = an act or instance of noticing or perceiving.

Thank u!

Answer:

1½ hours

Explanation:

Let the amount of time she drove at 85.5 km/hr be t, then

The distance that she rode would be 85.5 * t

This is means Emily has traveled the same distance at 68.8 km/hr without any stoppage whatsoever. Thus, we can create an equation as such

85.5 * t = 68.8 (t + 22/60), the 22/60 being, converting 22 minutes into hours. We proceed further as

85.5t = 68.8t + 1513.6/60, multiplying all sides by 60, we have

5130t = 4128t + 1513.6, now we collect like terms

5130t - 4128t = 1513.6

1002t = 1513.6

t = 1513.6/1002

t = 1.51 hrs, or in minutes, 1.51 * 60

t = 90.63 minutes. 1 hour and 36 minutes

So the total time the trip took, 22 minutes in addition, or say, 1 hour 58 minutes.

Answer:

The  value  is  [tex]t  =29.2  \  s [/tex]

Explanation:

From the question we are told that

Generally the average velocity of the train is mathematically represented as

          [tex]v  =  \frac{u +  v}{2}[/tex]

substituting  82.4 km/h for  u and   16.4 km/h. for  v

       [tex]v  =  \frac{82.4 + 16.4}{2}[/tex]

          [tex]v  =  49.4 \  km/h[/tex]

Generally the time taken is mathematically represented as

     [tex]t  =  \frac{ L}{v}[/tex]

substituting   49.4 \  km/h for  v and  [tex]4.00 * 10^2 \  m  =  0.400 \  km[/tex]

         [tex]t  =  \frac{ 0.400}{49.4}[/tex]

          [tex]t  = 0.00809 \  h [/tex]

converting to seconds

         [tex]t  = 0.00809 * 3600  [/tex]

          [tex]t  =29.2  \  s [/tex]

I think it might be Either A or B im thinking B

The magnetic field is just a unit vector that explains the electromagnetic influence on electric currents, current flow, and magnetic fluids.

Current density [tex]J = ar^2[/tex]

value of the constant is=  [tex]28.5 \ \frac{A}{mm^4}[/tex]

radius = 5.20 mm

magnetic permeability [tex]\mu = 4\pi \times 10^7 \ \frac{N}{A^2}[/tex]

calculating the area element for the straight circular conduction rod
:

[tex]d_A=2\pi r dr[/tex]

Calculating the current, which is carried in the rod

[tex]dI = \int dA \vec{J}[/tex]

Calculating the above equation with the limit value that is 0 to r.

[tex]I^{1}=\int_{0}^{r} ar^2 \times 2 \pi \cdot r d_r[/tex]

    [tex]=2\pi a\int_{0}^{r} r^3 d_r \\\\=\frac{\pi ar^4}{2}[/tex]

The calculated current value which is carried by the rod is [tex]\boxed{\frac{\pi ar^4}{2}}[/tex]

In option (a)

calculating the magnitude of the magnetic field at the point [tex]r_1= \frac{R}{2}[/tex]

[tex]\to B=\frac{\mu_{0} I^{1}}{2 \pi r}\\\\\to B \times 2\pi r= \mu_{0} (\frac{\pi a}{2}r^4)\\\\\to B \times 2\pi = \mu_{0} (\frac{\pi a}{2}r^3)\\\\\to B= \frac{\mu_{0}}{4}r^3 a\\\\[/tex]

Substituting the above value:[tex]\frac{R}{2} \ for \ r[/tex]

[tex]B= \frac{\mu_{0}}{4}(\frac{R}{2})^3 a[/tex]

[tex]B= \frac{4 \pi \times 10^{-7}}{4}(\frac{5.2 \times 10^{-3}}{2})^3 \frac{28.5}{10^{-12}}[/tex]

   [tex]= \frac{4 \pi \times 10^{-7}}{4} \times \frac{140.608 \times 10^{-9}}{8} \times \frac{28.5}{10^{-12}}\\\\= \frac{ 3.14 \times 10^{-7}}{1} \times \frac{140.608 \times 10^{-9}}{8} \times \frac{28.5}{10^{-12}}\\\\=\frac{1572.87624 \times 10^{-16}}{ 10^{-12}}\\\\=0.157 \ \ T[/tex]

Thus, the magnitude of the magnetic field at the point [tex]r_1 =\frac{R}{2}[/tex] is [tex]\boxed{0.157 \ T}[/tex]

In option (b)
In this, we calculate the magnitude of the magnetic field at the point [tex]r_2= 2R[/tex]

[tex]\to B=\frac{\mu_{0} I^{1}}{2 \pi r} \\\\\to B \times 2\pi r= \mu_{0} (\frac{\pi a}{2}R^4)\\\\\to B \times 2\pi 2R = \mu_{0} (\frac{\pi a}{2}R^3)\\\\\to B= \frac{\mu_{0}}{8}R^3 a\\\\[/tex]

Substituting the values  

[tex]B= \frac{4 \pi \times 10^{-7}}{8}(5.2 \times 10^{-3})^3(\frac{28.5}{10^{-12}})[/tex]

   [tex]= \frac{4 \times 3.14 \times 10^{-7}}{8} \times (5.2)^3 \times (10^{-3})^3 \times\frac{28.5}{10^{-12}}\\\\= \frac{ 3.14 \times 10^{-7}}{2} \times 140.608 \times 10^{-9} \times\frac{28.5}{10^{-12}}\\\\= 6291.50495 \times 10^{-4}\\\\= 0.629 \ \ or \ \ 0.63\\[/tex]

Thus, the magnitude of the magnetic field at the point [tex]r_2 = 2R[/tex] is [tex]\boxed{0.63 \ \ T}[/tex]

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Performing experiments that have never been done before is most likely to lead to improving a scientific theory. The correct option is D.

A theory is a well-thought-out elaboration for natural-world observational data that has been built using the scientific process and incorporates many facts and hypotheses.

A theory not only helps to explain established information; it also allows scientists to predict what they will see if the hypothesis is correct.

Scientific theories can be tested. Emerging data should be consistent with an existing theory.

To improve a scientific theory, conduct novel experiments on it. This will provide greater clarity on the theory.

It may reveal the limitations of this theory, as well as aspects of the theory that can be improved.

Thus, the correct option is D.

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Answer:

. the point charge is moved off center (but still inside the sphere) the point charge is moved to allocation just outside the sphere.

Explanation:

Because

Gaussian surface is given as

ϕ= qclose/E0

​So Q enclosed charge will be same if w the charge inside the Gaussian surface is moved, so flux will not change.

​

Answer:

a. Question

Explanation:

The statement above is more of a question rather than a hypothesis or the other options. Consider, the statement has no direct initial assumption or hint of personally researching for answers.

In other words, the speaker could be asking another individual his opinion whether the amount of homework completed has an effect on science test scores.

Answer:

The answer is

Explanation:

The net force acting on an object when given the mass and acceleration can be found by using the formula

From the question

mass of backpack = 12 kg

acceleration = 0.5 m/s²

So the force is

Force = 12 × 0.5

We have the final answer as

Hope this helps you

At the time when the sun pulls on earth should be large so it should be pulled on each other equally.

Here the gravitational force that lies between two masses should be proportional with respect to the product of mass that should be divided via the square of the distance that lies between them. The acceleration should be measured when the force should be divided by the mass. Here the two forces should be equal and opposite

Therefore, the option b is correct.

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Explanation:

1. Given:

v₀ = 0 m/s

a = 2.0 m/s²

t = 1.2 s

Find: v

v = at + v₀

v = (2.0 m/s²) (1.2 s) + 0 m/s

v = 2.4 m/s

2. Given:

v₀ = 0 m/s

v = 9.0 m/s

a = 2.2 m/s²

Find: t

v = at + v₀

9.0 m/s = (2.2 m/s²) t + 0 m/s

t ≈ 4.1 s

Answer:

1.6 secs

Explanation:

In a circus act, an acrobat upwards from the surface of a trampoline

At that same moment another acrobat perched 9.0m above him

A ball is released from rest

While still in motion the acrobat catches the ball

He left the ball with a trampoline of 5.6m/s

Since the ball is falling downwards from a distance then acceleration will be negative

a= -9.8

s= d

s= 1/2at^2

= 1/2 × (-9.8)t^2

= 0.5× (-9.8)t^2

d = -4.9t^2

Therefore the time the acrobat stays in the air before catching the ball can be calculated as follows

9 - 4.9t^2= 5.6t + 1/2(-9.8)t^2

9 - 4.9t^2= 5.6t + (-4.9)t^2

9 - 4.9t^2= 5.6t - 4.9t^2

9= 5.6t

t= 9/5.6

t= 1.6 secs

Answer: His acceleration is -18.66m/s^2

Explanation:

Ok, the initial speed is 2.8m/s. (we can define the initial direction as the positive direction).

And he wants to stop, so he must accelerate in the opposite direction as the initial movement, then we would have:

a(t) = -A.

So we have a constant, and negative acceleration.

Now, if we want to find the velocity we must integrate over time, and we will get:

v(t) = -A*t + V0

where V0 is the initial velocity, we know that it is 2.8m/s, and t is the time in seconds.

Then the velocity is:

v(t) = -A*t + 2.8m/s.

Now we know that John is brought to rest in 0.15 seconds after he starts slowing down, this means that at t = 0.15 seconds, his velocity is equal to zero.

v(0.15s) = 0m/s = -A*0.15s + 2.8m/s

2.8m/s = A*0.15s

2.8m/s/0.15s = 18.66m/s^2 = A.

So his acceleration is -A, then we have that:

His acceleration is -18.66m/s^2

Answer:

a)    x = v₀² sin 2θ / g

b)    t_total = 2 v₀ sin θ / g

c)    x = 16.7 m

Explanation:

This is a projectile launching exercise, let's use trigonometry to find the components of the initial velocity

        sin θ = [tex]v_{oy}[/tex] / vo

        cos θ = v₀ₓ / vo

         v_{oy} = v_{o} sin θ

         v₀ₓ = v₀ cos θ

         v_{oy} = 13.5 sin 32 = 7.15 m / s

         v₀ₓ = 13.5 cos 32 = 11.45 m / s

a) In the x axis there is no acceleration so the velocity is constant

         v₀ₓ = x / t

          x = v₀ₓ t

the time the ball is in the air is twice the time to reach the maximum height, where the vertical speed is zero

          v_{y} = v_{oy} - gt

          0 = v₀ sin θ - gt

          t = v_{o} sin θ / g

we substitute

       x = v₀ cos θ (2 v_{o} sin θ / g)

       x = v₀² /g      2 cos θ sin θ

       x = v₀² sin 2θ / g

at the point where the receiver receives the ball is at the same height, so this coincides with the range of the projectile launch,

b) The acceleration to which the ball is subjected is equal in the rise and fall, therefore it takes the same time for both parties, let's find the rise time

at the highest point the vertical speed is zero

          v_{y} = v_{oy} - gt

          v_{y} = 0

           t = v_{oy} / g

           t = v₀ sin θ / g

as the time to get on and off is the same the total time or flight time is

           t_total = 2 t

           t_total = 2 v₀ sin θ / g

c) we calculate

          x = 13.5 2 sin (2 32) / 9.8

          x = 16.7 m

(a) The horizontal velocity in the projectile motion is always constant.it is the horizontal component of velocity by which the object is thrown. The expression for the football horizontal velocity will be [tex]H = \frac{u^{2} sin^{2}\theta}{2g}[/tex].

(b) The amount of time it takes for the body to project and land is the time of flight.

(c) The horizontal distance traveled by the ball is defined by the ball is called the range of the ball. The horizontal distance traveled will be 16.7 m.

The horizontal distance is covered by the body when the body is thrown at some angle is known as the range of the projectile. It is given by the formula

(a) Let the velocity at which the ball passes will be v. Resolve the velocity components into two components one is the horizontal component

[tex]\rm{u_x = ucos\theta}[/tex]

[tex]\rm{u_y = usin\theta}[/tex]

let the x distance is traveled in the horizontal direction so,

[tex]y = u_y \times t[/tex]

[tex]\rm{H = u_y t+\frac{1}{2} gt^2}[/tex]

[tex]\rm{H = usin\theta (\frac{usin\theta}{g}) +\frac{1}{2} g(\frac{usin\theta}{g}) ^2}[/tex]

[tex]H = \frac{u^{2} sin^{2}\theta}{g} -\frac{u^{2}sin^{2}\theta }{2g}[/tex]

[tex]H =\frac{u^{2}sin^{2}\theta }{2g}[/tex]

This is the required relation for the horizontal velocity.

(b)

Newton's equation of motion

[tex]\rm{v = u +gt}[/tex]

[tex]\rm{v_y = u_y +gt}[/tex]

[tex]\rm{v_y = 0}[/tex]

[tex]{u_y = usin\theta}[/tex]

[tex]\rm{usin\theta = gt}[/tex]

[tex]t= \rm{ \frac{usin\theta}{g} }[/tex]

These are the required relation for time t.

(c)

The range of the projectile is given as

[tex]R =\frac{u^{2}sin{2}\theta }{g}[/tex]

[tex]R =\frac{(13.5)^{2}sin64^0 }{9.81}[/tex]

R = 16.7 m

So the horizontal distance covered will be 16.7 m.

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Answer:

Explanation:

When a body is held against a vertical wall , to keep them in balanced position , normal force is applied on their surface . this force creates normal reaction which acts against the normal force and it is equal to the normal force as per newton's third law . Ultimately friction force is created which is proportional to normal force and it acts in vertically upward direction . It prevents the body from falling down .

Hence normal force = reaction force .

From second law also net force is zero , so if  normal force is N and reaction force is R

R - N = mass x acceleration = mass x 0 = 0

R = N .

Ranking normal force from  highest  to smallest

150 N , 130 N , 120 N

B )

Frictional force is equal to the weight of the body because the body is held at rest .

Ranking of frictional force form largest to smallest

7 kg , 5 kg , 3 kg , 1 kg .

Here frictional force is irrespective of the normal force acting on the body  because frictional force adjusts itself so that it becomes equal to weight in all cases here because it always balances the weight of the body .

Based on the magnitude of normal force acting on them, the ranking from largest to smallest will be:

Based on the masses, the frictional force acting on the boxes will be such that the ranking from largest to smallest will be:

The normal forces acting on the box will depend on the force acting on the box. This means that the larger the force acting on the box, the larger the normal force.

This is why the box with a force of 150 N will be have the highest normal force acting on it.

The frictional force acting on the boxes will depend on the mass. Boxes will lager masses will have more frictional force acting on them.

The boxes of 7kg will therefore have the largest frictional forces acting on them.

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Answer:

Explanation:

For two vectors to be orthogonal (perpendicular) the product of both vectors must be zero. Given the vectors D=(2.0i-4.0j+k)N and G=(3.0i+4.0j+10k)N, to show that they are orthogonal, we will take their dot product as shown;

D.G = (2.0i-4.0j+k).(3.0i+4.0j+10k)

Note that i.1 = j.j = k.k = 1 and dot product of different component is zero.

D.G = 2.0(3.0) (i.i) + (-4.0)(4.0)j.j + 1(10)k.k

D.G = 6.0(1) -(16)(1)+10(1)

D.G = 6-16+10

D.G = -10+10

D.G = 0

Since the dot product of the two vectors is zero, this shows that force vector D is orthogonal to force vector G.