A car increase its speed steadily from 30km/hr to 60km/hr in 1 min A what is the average speed during this time

Answers

Answer 1

Explanation:

initial velocity(u)=30km/hr = 30*1000/60*60=8.33 m/s

final velocity(v) =60km/hr = 60*1000/60*60 =16.67 m/s

time taken(t) = 1 minutes

= 60 seconds

Now,

Average velocity = u+v/2

= 8.33 m/s + 16.67m/s÷2

=12.5 m/s


Related Questions

express in standard form
(I)0.000038​

Answers

Answer:

3.8 x 10^-5

Explanation:

all you doing is putting it in the standard form I hope this help

An open winding in an electric motor means that ____. A. a wire in a winding is broken B. the centrifugal switch to the start winding is open C. the winding is making contact with the motor frame D. one winding is making contact with another winding

Answers

Answer:

A. a wire in a winding is broken.

Explanation:

An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.

Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.

Basically, an electric circuit is considered to be open when there's a broken continuity (broken path), which causes no current to flow through the circuit.

On the other hand, a closed circuit is one in which there's a flow of current due to a complete electrical path.

On a related note, an open winding in an electric motor means that a wire in a winding is broken.

A bullet with a mass mb=13.5 g is fired into a block of wood at velocity vb=245 m/s. The block is attached to a spring that has a spring constant k of 205 N/m. The block and bullet continue to move, compressing the spring by 35.0 cm before the whole system momentarily comes to a stop. Assuming that the surface on which the block is resting is frictionless, determine the mass mw of the wooden block.

Answers

Momentum is conserved, so the sum of the momenta of the bullet and block before collision is equal to the momentum of the combined bullet-block system,

[tex]m_bv_b+m_wv_w = (m_b+m_w)v[/tex]

where v is the speed of the bullet-block system. The block starts at rest so it has no initial momentum, and solving for v gives

[tex]v = \dfrac{m_b}{m_b+m_w} v_b[/tex]

The total work W performed by the spring on the bullet-block system as it is compressed a distance x is

[tex]W = -\dfrac12kx^2[/tex]

where k is the spring constant, and the work done is negative because the restoring force of the spring opposes the bullet-block as it compresses the spring.

By the work-energy theorem, the total work done is equal to the change in the bullet-block's kinetic energy ∆K, so we have

[tex]W_{\rm total} = W = \Delta K[/tex]

The bullet-block starts moving with velocity v found earlier and comes to a stop as the spring slows it down, so we have

[tex]-\dfrac12kx^2 = -\dfrac12(m_b+m_w)v^2 \implies kx^2 = \dfrac{{m_b}^2}{m_b+m_w}{v_b}^2[/tex]

Solve for [tex]m_w[/tex]:

[tex]m_w=\dfrac1k\left(\dfrac{m_bv_b}x\right)^2-m_b[/tex]

[tex]m_w=\dfrac1{205\frac{\rm N}{\rm m}}\left(\dfrac{(0.0135\,\mathrm{kg})\left(245\frac{\rm m}{\rm s}\right)}{0.350\,\rm m}\right)^2-0.0135\,\mathrm{kg}\approx \boxed{0.422\,\mathrm{kg}}[/tex]

A 550N object has a coefficient of .012 against a smooth surface. What
force is needed to keep the object sliding?(ANSWER to 1 decimal place, no
units)

Answers

Vertically, the object is in equilibrium, so that the net force in this direction is

F (vertical) = n - mg = 0

where n is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is mg = 550 N, so n = 550 N as well.

Horizontally, the net force would be

F (horizontal) = p - f = 0

where p is the magnitude of the applied force and f is the magnitude of (kinetic) friction opposing p. Now,

f = 0.012n = 0.012 (550 N) = 6.6 N

so that you need to apply a force of p = 6.6 N to keep the object sliding at a steady pace.

The direction of applied force has to be .............. to the distance in order to say work is done​

Answers

Answer:

Parallel

Explanation:

The work done is defined as the force applied on an object and the displacement in the position of the object in the direction of force.

W = F s cos A

where, F is the force, s is the displacement and A is the angle between force and displacement.

When the angle between the force and the displacement is 90 degree, the work done is zero.

To get the maximum work the angle between the force and the displacement is 0 degree.

So, to get the work done by the force the angle between the force and displacement is 0 degree that means the force and displacement is parallel to each other.

If we aim a radio telescope at a distant spiral arm of the Milky Way Galaxy, we will probably observe a 21-cm line. If we point a large optical telescope at this same region, we will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal. Why not

Answers

Answer:

Because of the interstellar dust and interior location of the solar system.

Explanation:

We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.

Use the equation d=st where d= distance, s= speed, and t= time. If you ride a skateboard at a speed of 8m/s for 12 seconds, how far do you travel

Answers

Answer:

96 meters

Explanation:

d = st

d = (8 m/s)(12 s)

d = 96 m

In a Rutherford scattering experiment, alpha parti- cles having kinetic energy of 7.70 MeV are fired toward a gold nucleus that remains at rest during the collision. The alpha particles come as close as 29.5 fm to the gold nucleus before turning around. (a) Calculate the de Broglie wave- length for the 7.70-MeV alpha particle and compare it with the distance of closest approach, 29.5 fm. (b) Based on this comparison, why is it proper to treat the alpha particle as a particle and not as a wave in the Rutherford scattering experiment

Answers

(a) The de Broglie wavelength is approximately 5.175 × 10⁻¹⁵  meters. The wavelength is lesser than the distance of closest approach

(b) It is proper to treat the alpha particle as a particle and not as wave because the distance of closest approach is much larger than and not comparable to its wavelength for the alpha particle for the alpha particle to be treated as a wave

The given parameters are;

The kinetic energy of the alpha particles = 7.70 MeV = 1.23368 × 10⁻¹² J

The distance from the gold nucleus the alpha particles reach = 29.5 fm

(a) The de Broglie wavelength of a particle is given as follows;

[tex]\mathbf{\lambda = \dfrac{h}{p}}[/tex]

Where;

λ = The wavelength

h = Planck's constant = 6.62607004 × 10⁻³⁴ m²·kg/s

p = The momentum of the particle = Mass of an electron, m × Velocity, v

The mass of an alpha particle, m ≈ 6.645 × 10⁻²⁷ kg

Therefore;

[tex]\lambda = \dfrac{h}{m \times v}[/tex]

The kinetic energy of the alpha particle, K.E. = (1/2)·m·v²

∴ v = √(2 × K.E./m)

Therefore;

[tex]\lambda = \dfrac{h}{m \times \sqrt{2 \times \dfrac{K.E.}{m} } } = \dfrac{h}{ \sqrt{2 \times m \times K.E.} }[/tex]

Plugging in the values of the variables gives;

[tex]\lambda = \dfrac{6.62607004 \times 10 ^{-34} }{ \sqrt{2 \times 6.645 \times 10 ^{-27} \times 1.23368 \times 10^{-12} } } \approx 5.175 \times 10^{-15}[/tex]

The de Broglie wavelength of the alpha particle, λ ≈ 5.175 × 10⁻¹⁵ m

The distance of closest approach = 29.5 fm = 29.5 × 10⁻¹⁵ m

Compared to the distance of closest approach, the wavelength of the alpha particle is lesser than the distance of closest approach

(b)  Given that the distance of closest approach is six times larger than the wavelength of the alpha particle, and alpha particle behaving as waves are expected to approach closer to the gold nucleus in the region of their wavelength before deflection, therefore, the larger distance of closest approach is indicative of a charged particle to charged particle interaction, and therefore, particle behavior of alpha particles.

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Two charges 3*10^-5 C and 5*10^4 C are placed at a distance 10 cm form each other. Find the value of electrostatic force acting between them. a) 13.5 x 10^11N b) 40 x 10^11N c)180 x 10^9N d)13.5 x 10^10 N

Answers

Answer:

13.5 x 10^(11) N

Explanation:

Given :

The magnitude of charge 1 = q1 = 3 × 10^(-5) C

The magnitude of charge 2 = q2 = 5 × 10^(4) C

The distance between charges = d = 10 cm = 0.1 m

To Find :

The magnitude of electrostatic force acting between charges

Solution :

∵ Electrostatic force = F = (k × (q1) x (q2)) / r^(2)

where k = 9 × 10^(9)

i.e    F = 9 × 10^(9) × (3 × 10^(-5) × 5 × 10^(4)) / (0.1)^(2)  

Or, F =  9 × 10^(9) ×  (1.5/0.01)  

∴   F = 9 × 10^(9) × 150

i.e F = 1350 × 10^(9)

or,  Force = F = 1.35 × 10^(12) N

Hence, The magnitude of electrostatic force acting between charges is  1.35 × 10^(12) N => 13.5 x 10^(11)

According to Moseley, the properties of elements are a
periodic function of their

Answers

Answer:

According to Henry Moseley, Atomic number is the fundamental property of the elements because elements are made up of atoms . ... So the physical and chemical properties of elements are periodic functions of their atomic number.

Q- Wheel of a running vehicle has which energy?
(a) Vibrational Kinetic energy
(b) Translational Kinetic energy
(c) Rotational Kinetic energy
(d) All of the above​

Answers

Answer:

Rotational kinetic energy

Explanation:

It is caused by circular motion.

Luis rushes 40m toward his truck. He notices he forgot his shoes and returns back to his house. His total travel time is 60s.

What is Luis’s average speed over the 60s?
What is Luis average velocity over the 60s?

Answers

1. The average speed of Luis over the 60 s is 1.33 m/s

2. The average velocity of Luis over the 60 s is zero.  

1. The average speed can be calculated with the following equation:

[tex] S = \frac{d}{t} [/tex]

Where:

d: is the total distance traveled

t: is the total time = 60 s

The total distance can be calculated by the sum of the distance traveled to the truck (40 m) and the distance traveled to his home (the same 40 m), as follows:

[tex] d = 40 m + 40 m = 80 m [/tex]

So, the average speed is:

[tex] S = \frac{d}{t} = \frac{80 m}{60 s} = 1.33 m/s [/tex]

Hence, Luis's average speed over the 60 s is 1.33 m/s.

 

2. Now, the average velocity is a vector given by:

[tex]v = \frac{\Delta x}{\Delta t} = \frac{x_{f} - x_{i}}{t}[/tex]

Where:

[tex]x_{f}[/tex]: is the final distance traveled (the way to his home) = 40 m

[tex]x_{i}[/tex]: is the initial distance traveled (the way to his truck) = 40 m

Δt: is the total time = t = 60 s

Given that Luis in his journey, returns to the same starting point (his house), the total displacement is zero, and so the average velocity is also zero:                              

[tex]v = \frac{x_{f} - x_{i}}{t} = \frac{40 m - 40 m}{60 s} = 0[/tex]

Therefore, Luis's average velocity over the 60 s is zero.  

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I hope it helps you!                                              

As shown in the figure below, Luis rushes 40 m toward his truck. He notices he forgot his shoes and returns back to his house. His total travel time is 60 s.

Answer:

What is Luis’s average velocity over the 60 s period?

Answer: 0 m/s

What is Luis’s average speed over the 60 s period?

Answer: 1.33  m/s

A large atomic bomb produces around 8.00x1015J of energy. How much matter does that bomb turn into energy?

A)2.67x10^79kg

B)2.67x10^7kg

C)7.20x10^32kg

D)0.0889kg

Answers

Answer:

D)0.0889kg

Explanation:

If a large atomic bomb produces around 8.00x10¹⁵J of energy, then from Einstein's energy law i.e E=mc² we can calculate that the amount of matter is  0.0889kg. The correct option is D.

What is Einstein's energy law?

The Einstein Energy Law, often referred to as Einstein's famous equation relates the energy of a particle (E) to its mass (m) and the speed of light (c). The equation is as follows:

E = mc²

This equation shows that energy (E) and mass (m) are equivalent and interchangeable and that a small amount of mass can be converted into a large amount of energy. This is the basis for understanding nuclear reactions and the energy released in processes like nuclear fusion and fission.

Here in the question,

To calculate the mass that is converted into energy in an 8.00x10¹⁵J nuclear reaction, we can rearrange the equation to solve for m:

m = E / c²

where c = 3 x 10⁸ m/s is the speed of light in a vacuum.

Substituting the values, we get:

m = 8.00x10¹⁵ J / (3 x 10⁸ m/s)²

m = 0.0889kg

Therefore, a large atomic bomb that produces around 8.00x10¹⁵ J of energy converts approximately 0.0889kg of matter into energy. This is a very small amount of matter, but because is such a large number, a huge amount of energy can be released from a small amount of matter in a nuclear reaction.

To learn more about Einstein's energy law click:

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if you add km/ hr with another km/ hr what will you get​

Answers

Answer:

km/hr

Explanation:

Addition and subtraction are commutative

Meaning you can add or subtract in any order because it doesn't change the sum or the difference. So it doesn't change the units.

Answer:

km/ hr + km/ hr =(km+ km)/hr=2km/hr

Explanation:

When the system pressures are lower than the pressure in the refrigerant tank, such as when the system has just been evacuated or if the system is out of refrigerant, refrigerant can be added to both the high and low pressure sides of the system. A. True B. False

Answers

Answer: True

Explanation:

It should be noted that when refrigerant is added in vapor form to the operating refrigeration system, then the addition of the refrigerant should be to the low-pressure side of the refrigeration system.

Furthermore, when system pressures are lower than the pressure in the refrigerant tank as stated in the question, then the refrigerant can be added to both the high and low pressure sides of the system.

Therefore, the correct option is true.

A uniform bridge span of weight 1200 kN and of
length 17.0 m rests on a support of width 1.0 m at
either end. A stationary lorry of weight 60 kN is the
only object on the bridge. Its centre of mass is 3.0m
from the centre of the bridge.
15.0 m

Answers

45-4753that is your answer

personal and unbiased errors belong to​

Answers

personal to systematic errors

unbiased to random errors

We use __force to do different force. 1) pulling 2)pushing 3)gravity 4)muscular

Answers

Answer:

gravity

Explanation:

We use gravity to do different force.

(a) What kind of energy is possessed by an aeroplane flying at a height of 10000 m?​

Answers

Answer:

When the plane is rest position it possess potential energy. But when a aeroplane is flying at the height it possess kinetic energy. No matter what height is given.

mention various medium level and higher level human resources related to engineering.

Answers

Answer:

Higher-level human resources related to engineering are those who:

Assist other engineers with solving complex problems. Work with management to keep the project on track. Mentor younger engineers

Medium Level engineers will normally comprise the following:

They are responsible for developing engineering plans and performing calculations with respect to the same.  Project workflow management Engineering Support facilitation Project Reporting Coordination of Team Members

Cheers

2. ¿Puede haber trabajo en un sistema si no hay movimiento
a. Sí, si hay una fuerza siempre.
b. Sí, ya que el movimiento es sólo relativo.
c. No, ya que un sistema que no se mueve no tiene energía.
d. No, porque la ecuación de trabajo lo define.

Answers

Answer:

d. No, porque la ecuación de trabajo lo define.

Explanation:

En Física, el trabajo realizado se puede definir como la cantidad de energía transferida cuando un objeto o cuerpo se mueve a lo largo de una distancia debido a la acción de una fuerza externa.

Matemáticamente, el trabajo realizado viene dado por la fórmula;

[tex] W = F * d [/tex]

Dónde;

W es el trabajo realizado.F representa la fuerza que actúa sobre un cuerpo. d representa la distancia recorrida por el cuerpo.

Por lo tanto, podemos deducir de la definición de trabajo y su fórmula que el trabajo se realiza cuando un objeto (cuerpo) se mueve una distancia o experimenta cualquier forma de desplazamiento mientras transfiere energía.

define mass defect and binding energy​

Answers

Answer:

About Transcript. Nuclear binding energy is the energy required to split an atom's nucleus into protons and neutrons. Mass defect is the difference between the predicted mass and the actual mass of an atom's nucleus. The binding energy of a system can appear as extra mass, which accounts for this difference.

Explanation:

PLZ MARK AS THE BRAINLIEST

I NEED IT URGENTLY

HAVE A GOOD DAY

MAY GOD BLESS U

: )

Why are houses in hot areas painted in white while those in cold areas painted with dull colours

Answers

Answer:

Because white color reflects back the heat coming from the sun while dull colors absorb the heat.

steel wire 8m long and 4mm in diameter is fixed to two rigid b. [1] supports. Calculate the increase in tension when the temperature falls by 10°C. Given linear expansivity of steel, a 12x10 %/K, Young's modulus for steel, Y = 2x10¹¹ N/m².​

Answers

Answer:

301.6 N

Explanation:

The length of the wire L₀ = 8 m and its diameter, d = 4 mm = 4 × 10⁻³ m. Since its temperature drops by  10°C, it will have a change in length ΔL = L₀αΔθ where α = linear expansivity of steel, a 12 × 10⁻⁶ /K, and Δθ = temperature change = -10°C = -10 K(negative since it is a drop)

So, the strain, ε = ΔL/L₀ = αΔθ = 12 × 10⁻⁶ /K × 10 K = 12 × 10⁻⁵

Now the Young's modulus of steel, Y = σ/ε where σ = stress = T/A where T = increase in tension in steel wire and A = cross-sectional area of wire = πd²/4 where d = diameter of wire = 4 × 10⁻³ m and ε = strain = 12 × 10⁻⁵

So, σ = Yε

Since Y = 2 × 10¹¹ N/m².

Substituting the values of the variables into the equation, we have

σ = Yε

σ = 2 × 10¹¹ N/m² × 12 × 10⁻⁵

σ = 24 × 10⁶ N/m²

Since σ = T/A

T = σA

T = σπd²/4

Substituting the values of the variables into the equation, we have

T = σπd²/4

T = 24 × 10⁶ N/m² × π × (4 × 10⁻³ m)²/4

T = 24 × 10⁶ N/m² × π × 16 × 10⁻⁶ m²/4

T = 24 × 10⁶ N/m² × π × 4 × 10⁻⁶ m²

T = 96 N × π

T = 301.59 N

T ≅ 301.6 N

So, the increase in tension in the steel wire is 301.6 N

Một dây nhôm dài 10 m khi ở 25 độ C. Biết khi nhiệt độ tăng thêm 1 độ C thì chiều dài 1m dây nhôm sẽ tăng thêm 0,024mm.
a) Tính ăng chiều dài của 1m dây nhom khi nhiệt độ tăn thêm 75 độ C
b) Tính chiều dài dây nhôm ở 75 độ C

Answers

Answer:

??????? what language is this. um A then

2. Speed limits on curves help to reduce the effect of ........force on a vehicle
A. enertia
b. centrifugal
c. gravity

Answers

Answer:

enertia

Explanation:

enertia

The correct answer is (B) Centrifugal Force

The centrifugal force on a vehicle on the curves is outwards or can say away from the curve and pulls the out of the track.

the centrifugal force is given by [tex]F=\frac{mv^{2} }{r}[/tex], which is directly proportional to speed v.

Speed limits on the curves help in reducing the centrifugal force by reducing the speed.

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8. What type(s) of motion do the particles in a solid undergo? A. vibrational, rotational, and translational B. vibrational and rotational C. vibrational only D. rotational only​

Answers

Explanation:

Particles in solids are always vibrating (moving back and forth) in place.

power of a lens whose focal length is -40 d.​

Answers

Answer:

as we know

p=1/f

p=1/-40m

p=  -0.025d

you have written the unit of focal length wrong it is the unit of power

please mark as brainliest plzzzzzzzzzz

6x+8=32 kết quả x là bao nhiêu

Answers

Answer:

6x+8=32

6x=32-8

6x=24

x=24:6

x= 4

vậy, x =4

Straight wire of indefinite length (transient) passed by an electric current of 5.0 A. The magnetic field generated around this conductor at point M is 50 μT. Thus the distance from the conductor to point M is:

A. 2π cm

B. 0.2π cm

C. 2.0 cm

D. 0.20 cm​

Answers

Answer:

C. 2.0 cm

Explanation:

The magnetic field around the wire at point M is given by Biot-Savart Law:

[tex]B = \frac{\mu_o I}{2\pi R}[/tex]

where,

B = Magnetic field = 50 μT = 5 x 10⁻⁵ T

I = current = 5 A

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

R = distance of point M from wire = ?

Therefore,

[tex]5\ x\ 10^{-5}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(5\ A)}{2\pi R}\\\\R = \frac{(2\ x\ 10^{-7}\ N/A^2)(5\ A)}{5\ x\ 10^{-5}\ T}\\[/tex]

R = 0.02 m = 2 cm

Hence, the correct option is:

C. 2.0 cm

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In addition, senior leaders found that projects are being delivered between 25% and 50% over budget and late 95% of the time.Note: Project Management overhead includes the PM's time managing the project, attending meetings, and developing the required documentation. SCC Request: SCC has reached out to your team because you are experts in defining project management processes and delivering projects on time. The SCC request includes the following:. The development of a new project management process which at a minimum should include the following: The ability to track issues, risks, changes The ability to view project activities consists of a view of what has been completed and what activities the team is working on over the next reporting period The company must have a view into total life cycle project costs to include what has been spent to date, baseline budget, any changes to the budget, remaining budget, and cost of the project at completion In addition, to the new process request, SCC has a new project they need to complete by the end of the year with a limited budget and no project management staff. 1. Using your defined project management process outlined above, describe the life cycle model for this project2. Create a WBS for the project. Remember your WBS is a deliverable base, so there should be a section of your WBS which outlines our project management deliverables3. Using your defined prioritization process, prioritize each application.4. Using the defined organizational structure, create a pictorial and narrative description of the organizational structure for the project. X = A)6 2/3B)9C)12 A specimane collection helps a scientsist do research by:A. Asembling a large number of sample comparisons B.providing a way to afford even the most expensive equpmentC.creating a realistic depiction of an imaginary undersea worldD.summerizing the results of an other scientists investigations how are ponyboy and sodapop alike?Please give me two ways they are alike!! What were the three large, flightless birds with similar features found on different continents, Australia, Africa, and South America?