A car increase its speed steadily from 30km/hr to 60km/hr in 1 min A what is the average speed during this time

Answer:

Because white color reflects back the heat coming from the sun while dull colors absorb the heat.

Answer:

C. 2.0 cm

Explanation:

The magnetic field around the wire at point M is given by Biot-Savart Law:

[tex]B = \frac{\mu_o I}{2\pi R}[/tex]

where,

B = Magnetic field = 50 μT = 5 x 10⁻⁵ T

I = current = 5 A

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

R = distance of point M from wire = ?

Therefore,

[tex]5\ x\ 10^{-5}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(5\ A)}{2\pi R}\\\\R = \frac{(2\ x\ 10^{-7}\ N/A^2)(5\ A)}{5\ x\ 10^{-5}\ T}\\[/tex]

R = 0.02 m = 2 cm

Hence, the correct option is:

C. 2.0 cm

Answer:

6x+8=32

6x=32-8

6x=24

x=24:6

x= 4

vậy, x =4

Answer:

enertia

Explanation:

enertia

The correct answer is (B) Centrifugal Force

The centrifugal force on a vehicle on the curves is outwards or can say away from the curve and pulls the out of the track.

the centrifugal force is given by [tex]F=\frac{mv^{2} }{r}[/tex], which is directly proportional to speed v.

Speed limits on the curves help in reducing the centrifugal force by reducing the speed.

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Answer:

??????? what language is this. um A then

Answer:

96 meters

Explanation:

d = st

d = (8 m/s)(12 s)

d = 96 m

Answer:

About Transcript. Nuclear binding energy is the energy required to split an atom's nucleus into protons and neutrons. Mass defect is the difference between the predicted mass and the actual mass of an atom's nucleus. The binding energy of a system can appear as extra mass, which accounts for this difference.

Explanation:

PLZ MARK AS THE BRAINLIEST

I NEED IT URGENTLY

HAVE A GOOD DAY

MAY GOD BLESS U

: )

Answer:

According to Henry Moseley, Atomic number is the fundamental property of the elements because elements are made up of atoms . ... So the physical and chemical properties of elements are periodic functions of their atomic number.

1. The average speed of Luis over the 60 s is 1.33 m/s

2. The average velocity of Luis over the 60 s is zero.  

1. The average speed can be calculated with the following equation:

[tex] S = \frac{d}{t} [/tex]

Where:

d: is the total distance traveled

t: is the total time = 60 s

The total distance can be calculated by the sum of the distance traveled to the truck (40 m) and the distance traveled to his home (the same 40 m), as follows:

[tex] d = 40 m + 40 m = 80 m [/tex]

So, the average speed is:

[tex] S = \frac{d}{t} = \frac{80 m}{60 s} = 1.33 m/s [/tex]

Hence, Luis's average speed over the 60 s is 1.33 m/s.

2. Now, the average velocity is a vector given by:

[tex]v = \frac{\Delta x}{\Delta t} = \frac{x_{f} - x_{i}}{t}[/tex]

Where:

[tex]x_{f}[/tex]: is the final distance traveled (the way to his home) = 40 m

[tex]x_{i}[/tex]: is the initial distance traveled (the way to his truck) = 40 m

Δt: is the total time = t = 60 s

Given that Luis in his journey, returns to the same starting point (his house), the total displacement is zero, and so the average velocity is also zero:                              

[tex]v = \frac{x_{f} - x_{i}}{t} = \frac{40 m - 40 m}{60 s} = 0[/tex]

Therefore, Luis's average velocity over the 60 s is zero.  

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As shown in the figure below, Luis rushes 40 m toward his truck. He notices he forgot his shoes and returns back to his house. His total travel time is 60 s.

Answer:

What is Luis’s average velocity over the 60 s period?

Answer: 0 m/s

What is Luis’s average speed over the 60 s period?

Answer: 1.33  m/s

Answer:

Parallel

Explanation:

The work done is defined as the force applied on an object and the displacement in the position of the object in the direction of force.

W = F s cos A

where, F is the force, s is the displacement and A is the angle between force and displacement.

When the angle between the force and the displacement is 90 degree, the work done is zero.

To get the maximum work the angle between the force and the displacement is 0 degree.

So, to get the work done by the force the angle between the force and displacement is 0 degree that means the force and displacement is parallel to each other.

personal to systematic errors

unbiased to random errors

Answer:

A. a wire in a winding is broken.

Explanation:

An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.

Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.

Basically, an electric circuit is considered to be open when there's a broken continuity (broken path), which causes no current to flow through the circuit.

On the other hand, a closed circuit is one in which there's a flow of current due to a complete electrical path.

On a related note, an open winding in an electric motor means that a wire in a winding is broken.

Answer: True

Explanation:

It should be noted that when refrigerant is added in vapor form to the operating refrigeration system, then the addition of the refrigerant should be to the low-pressure side of the refrigeration system.

Furthermore, when system pressures are lower than the pressure in the refrigerant tank as stated in the question, then the refrigerant can be added to both the high and low pressure sides of the system.

Therefore, the correct option is true.

Answer:

km/hr

Explanation:

Addition and subtraction are commutative

Meaning you can add or subtract in any order because it doesn't change the sum or the difference. So it doesn't change the units.

Answer:

km/ hr + km/ hr =(km+ km)/hr=2km/hr

Explanation:

Answer:

When the plane is rest position it possess potential energy. But when a aeroplane is flying at the height it possess kinetic energy. No matter what height is given.

Answer:

301.6 N

Explanation:

The length of the wire L₀ = 8 m and its diameter, d = 4 mm = 4 × 10⁻³ m. Since its temperature drops by  10°C, it will have a change in length ΔL = L₀αΔθ where α = linear expansivity of steel, a 12 × 10⁻⁶ /K, and Δθ = temperature change = -10°C = -10 K(negative since it is a drop)

So, the strain, ε = ΔL/L₀ = αΔθ = 12 × 10⁻⁶ /K × 10 K = 12 × 10⁻⁵

Now the Young's modulus of steel, Y = σ/ε where σ = stress = T/A where T = increase in tension in steel wire and A = cross-sectional area of wire = πd²/4 where d = diameter of wire = 4 × 10⁻³ m and ε = strain = 12 × 10⁻⁵

So, σ = Yε

Since Y = 2 × 10¹¹ N/m².

Substituting the values of the variables into the equation, we have

σ = Yε

σ = 2 × 10¹¹ N/m² × 12 × 10⁻⁵

σ = 24 × 10⁶ N/m²

Since σ = T/A

T = σA

T = σπd²/4

Substituting the values of the variables into the equation, we have

T = σπd²/4

T = 24 × 10⁶ N/m² × π × (4 × 10⁻³ m)²/4

T = 24 × 10⁶ N/m² × π × 16 × 10⁻⁶ m²/4

T = 24 × 10⁶ N/m² × π × 4 × 10⁻⁶ m²

T = 96 N × π

T = 301.59 N

T ≅ 301.6 N

So, the increase in tension in the steel wire is 301.6 N

Answer:

13.5 x 10^(11) N

Explanation:

Given :

The magnitude of charge 1 = q1 = 3 × 10^(-5) C

The magnitude of charge 2 = q2 = 5 × 10^(4) C

The distance between charges = d = 10 cm = 0.1 m

To Find :

The magnitude of electrostatic force acting between charges

Solution :

∵ Electrostatic force = F = (k × (q1) x (q2)) / r^(2)

where k = 9 × 10^(9)

i.e    F = 9 × 10^(9) × (3 × 10^(-5) × 5 × 10^(4)) / (0.1)^(2)  

Or, F =  9 × 10^(9) ×  (1.5/0.01)  

∴   F = 9 × 10^(9) × 150

i.e F = 1350 × 10^(9)

or,  Force = F = 1.35 × 10^(12) N

Hence, The magnitude of electrostatic force acting between charges is  1.35 × 10^(12) N => 13.5 x 10^(11)

Vertically, the object is in equilibrium, so that the net force in this direction is

∑ F (vertical) = n - mg = 0

where n is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is mg = 550 N, so n = 550 N as well.

Horizontally, the net force would be

∑ F (horizontal) = p - f = 0

where p is the magnitude of the applied force and f is the magnitude of (kinetic) friction opposing p. Now,

f = 0.012n = 0.012 (550 N) = 6.6 N

so that you need to apply a force of p = 6.6 N to keep the object sliding at a steady pace.

Answer:

Higher-level human resources related to engineering are those who:

Medium Level engineers will normally comprise the following:

Cheers

Answer:

Rotational kinetic energy

Explanation:

It is caused by circular motion.

Answer:

gravity

Explanation:

We use gravity to do different force.

Answer:

Because of the interstellar dust and interior location of the solar system.

Explanation:

We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.

(a) The de Broglie wavelength is approximately 5.175 × 10⁻¹⁵  meters. The wavelength is lesser than the distance of closest approach

(b) It is proper to treat the alpha particle as a particle and not as wave because the distance of closest approach is much larger than and not comparable to its wavelength for the alpha particle for the alpha particle to be treated as a wave

The given parameters are;

The kinetic energy of the alpha particles = 7.70 MeV = 1.23368 × 10⁻¹² J

The distance from the gold nucleus the alpha particles reach = 29.5 fm

(a) The de Broglie wavelength of a particle is given as follows;

[tex]\mathbf{\lambda = \dfrac{h}{p}}[/tex]

Where;

λ = The wavelength

h = Planck's constant = 6.62607004 × 10⁻³⁴ m²·kg/s

p = The momentum of the particle = Mass of an electron, m × Velocity, v

The mass of an alpha particle, m ≈ 6.645 × 10⁻²⁷ kg

Therefore;

[tex]\lambda = \dfrac{h}{m \times v}[/tex]

The kinetic energy of the alpha particle, K.E. = (1/2)·m·v²

∴ v = √(2 × K.E./m)

Therefore;

[tex]\lambda = \dfrac{h}{m \times \sqrt{2 \times \dfrac{K.E.}{m} } } = \dfrac{h}{ \sqrt{2 \times m \times K.E.} }[/tex]

Plugging in the values of the variables gives;

[tex]\lambda = \dfrac{6.62607004 \times 10 ^{-34} }{ \sqrt{2 \times 6.645 \times 10 ^{-27} \times 1.23368 \times 10^{-12} } } \approx 5.175 \times 10^{-15}[/tex]

The de Broglie wavelength of the alpha particle, λ ≈ 5.175 × 10⁻¹⁵ m

The distance of closest approach = 29.5 fm = 29.5 × 10⁻¹⁵ m

Compared to the distance of closest approach, the wavelength of the alpha particle is lesser than the distance of closest approach

(b)  Given that the distance of closest approach is six times larger than the wavelength of the alpha particle, and alpha particle behaving as waves are expected to approach closer to the gold nucleus in the region of their wavelength before deflection, therefore, the larger distance of closest approach is indicative of a charged particle to charged particle interaction, and therefore, particle behavior of alpha particles.

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Answer:

as we know

p=1/f

p=1/-40m

p=  -0.025d

you have written the unit of focal length wrong it is the unit of power

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Explanation:

Particles in solids are always vibrating (moving back and forth) in place.

Answer:

3.8 x 10^-5

Explanation:

all you doing is putting it in the standard form I hope this help

Answer:

D)0.0889kg

Explanation:

If a large atomic bomb produces around 8.00x10¹⁵J of energy, then from Einstein's energy law i.e E=mc² we can calculate that the amount of matter is  0.0889kg. The correct option is D.

The Einstein Energy Law, often referred to as Einstein's famous equation relates the energy of a particle (E) to its mass (m) and the speed of light (c). The equation is as follows:

E = mc²

This equation shows that energy (E) and mass (m) are equivalent and interchangeable and that a small amount of mass can be converted into a large amount of energy. This is the basis for understanding nuclear reactions and the energy released in processes like nuclear fusion and fission.

Here in the question,

To calculate the mass that is converted into energy in an 8.00x10¹⁵J nuclear reaction, we can rearrange the equation to solve for m:

m = E / c²

where c = 3 x 10⁸ m/s is the speed of light in a vacuum.

Substituting the values, we get:

m = 8.00x10¹⁵ J / (3 x 10⁸ m/s)²

m = 0.0889kg

Therefore, a large atomic bomb that produces around 8.00x10¹⁵ J of energy converts approximately 0.0889kg of matter into energy. This is a very small amount of matter, but because c² is such a large number, a huge amount of energy can be released from a small amount of matter in a nuclear reaction.

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Answer:

d. No, porque la ecuación de trabajo lo define.

Explanation:

En Física, el trabajo realizado se puede definir como la cantidad de energía transferida cuando un objeto o cuerpo se mueve a lo largo de una distancia debido a la acción de una fuerza externa.

Matemáticamente, el trabajo realizado viene dado por la fórmula;

[tex] W = F * d [/tex]

Dónde;

Por lo tanto, podemos deducir de la definición de trabajo y su fórmula que el trabajo se realiza cuando un objeto (cuerpo) se mueve una distancia o experimenta cualquier forma de desplazamiento mientras transfiere energía.

Momentum is conserved, so the sum of the momenta of the bullet and block before collision is equal to the momentum of the combined bullet-block system,

[tex]m_bv_b+m_wv_w = (m_b+m_w)v[/tex]

where v is the speed of the bullet-block system. The block starts at rest so it has no initial momentum, and solving for v gives

[tex]v = \dfrac{m_b}{m_b+m_w} v_b[/tex]

The total work W performed by the spring on the bullet-block system as it is compressed a distance x is

[tex]W = -\dfrac12kx^2[/tex]

where k is the spring constant, and the work done is negative because the restoring force of the spring opposes the bullet-block as it compresses the spring.

By the work-energy theorem, the total work done is equal to the change in the bullet-block's kinetic energy ∆K, so we have

[tex]W_{\rm total} = W = \Delta K[/tex]

The bullet-block starts moving with velocity v found earlier and comes to a stop as the spring slows it down, so we have

[tex]-\dfrac12kx^2 = -\dfrac12(m_b+m_w)v^2 \implies kx^2 = \dfrac{{m_b}^2}{m_b+m_w}{v_b}^2[/tex]

Solve for [tex]m_w[/tex]:

[tex]m_w=\dfrac1k\left(\dfrac{m_bv_b}x\right)^2-m_b[/tex]

[tex]m_w=\dfrac1{205\frac{\rm N}{\rm m}}\left(\dfrac{(0.0135\,\mathrm{kg})\left(245\frac{\rm m}{\rm s}\right)}{0.350\,\rm m}\right)^2-0.0135\,\mathrm{kg}\approx \boxed{0.422\,\mathrm{kg}}[/tex]