Answer:
100 m
Step-by-step explanation:
because if 50 m in 1.0 a than 2.0 sec it's 100
Alice wants to estimate the percentage of people who own a mountain bike. She surveys 230 individuals and finds that 150 own a mountain bike. What are the sample proportions for successes, p′, and failures, q′?
Round your answers to three decimal places.
The sample proportions for successes, p′, and failures, q′ based on Alice's survey of 230 individuals who own a mountain bike or not are:
p′ = 0.652q′ = 0.348.What are sample proportions?Sample proportions refer to the percentage of successes and failures over the total sample size.
The percentage or proportion is computed as the ratio of the number of successes and failures and the total sample size.
The total number of individuals surveyed by Alice = 230
The number that owns a mountain bike = 150
The number that does not own a mountain bike = 80 (230 - 150)
Sample proportion for successes (those who own a mountain bike), p′ = 0.652 (150 ÷ 230) = 65.2%.
Sample proportion of failures, q′ = 0.348 (80 ÷ 230) = 34.8%
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Consider this figure.
Enter the measure of TOM, in degrees
Answer:
TOM=150
Step-by-step explanation:
The height of Mount Rushmore is 5900 feet. What is the height of Mount Rushmore in centimeters? (1 in = 2.54 cm)
Answer:
The answer would be 179832 Centimeters
Step-by-step explanation:
Answer: mt rushmore is 5,725 ft
Step-by-step explanation:
Which quadratic equation does not have a real solution? a 9x2 + 6x + 1 = 0 b −7x2 + 8x = 0 c −9x2 + 8x − 8 = 0 d 4x2 − 8x + 4 = 0
The quadratic equation that does not have a real solution is −9x² + 8x − 8 = 0. Then the correct option is C.
A quadratic equation does not have a real solution when its discriminant (b² - 4ac) is negative. Therefore, we can find which of the given equations does not have a real solution by calculating the discriminant for each equation.
a) 9x² + 6x + 1 = 0
D = b² - 4ac
D = 6² - 4(9)(1)
D = 36 - 36
D = 0
Since the discriminant is not negative, this equation has two real solutions.
b) −7x² + 8x = 0
D = 8² - 4(-7)(0)
D = 92
Since the discriminant is not negative, this equation has two real solutions.
c) −9x² + 8x − 8 = 0
D = 8² - 4(-9)(-8)
D = -224
Since the discriminant is negative, this equation has two non-real solutions.
d) 4x² − 8x + 4 = 0
D = (-8)² - 4(4)(4)
D = 64 - 64
D = 0
Since the discriminant is zero, this equation has one real solution (a double root).
Therefore, the quadratic equation that does not have a real solution is option (a) 9x² + 6x + 1 = 0.
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The usual cost to ship men's shirts is $16 dozen. A retailer in Peoria bought
6 dozen men's shirts on March 16 from a wholesaler in Chicago at $16.32 per shirt. The terms of the sale were 2/15, n/30; f.o.b. Chicago. The invoice was paid by check on March 29. What was the amount of the check?
The amount of the check is $94.08.
To calculate the amount of the check, we need to consider the cost per dozen shirts, the number of dozens purchased, and any applicable discounts.
Given information:
Cost per dozen shirts: $16
Number of dozens purchased: 6
Cost per shirt from the wholesaler: $16.32
Terms of the sale: 2/15, n/30 (meaning a 2% discount if paid within 15 days, and the full amount is due within 30 days)
Invoice paid on: March 29
Let's break down the calculations step by step:
Cost of 6 dozen shirts:
Cost per dozen shirts = $16
Cost of 6 dozen shirts = 6 * $16 = $96
Applying the discount:
Discount percentage = 2% = 0.02
Discount amount = 0.02 * $96 = $1.92
Total amount after discount = $96 - $1.92 = $94.08
Check the payment due date:
The invoice was paid on March 29, which is within the 30-day period. Therefore, there is no additional penalty or interest.
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How many more values can be represented by one hexadecimal digit than one binary digit?.
Hexadecimal and binary are two numbering systems that are commonly used in computing. Binary is a base-2 numbering system, which means it uses only two digits, 0 and 1, to represent all numbers. Hexadecimal, on the other hand, is a base-16 numbering system, which means it uses 16 digits, from 0 to 9 and A to F, to represent numbers.
One hexadecimal digit can represent 16 different values, while one binary digit can represent only two values (0 or 1). This means that one hexadecimal digit can represent 16 times as many values as one binary digit.
To understand this better, let's consider an example. The binary number 1111 is equivalent to the hexadecimal number F. In binary, 1111 can represent only one value, which is 15 in decimal. However, in hexadecimal, the digit F can represent 16 different values, from 0 to 15 in decimal.
Therefore, using hexadecimal notation can be more efficient and compact than using binary notation, especially when dealing with large numbers. In addition, hexadecimal is often used in computing to represent memory addresses, color codes, and other values that need to be represented in a compact and easily readable format.
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Simplify the expression
After simplifying the given expression 1/5⁻², we get result which is equal to 5² or 25.
To simplify the expression 1/5⁻², we can use the rule that says when a number with a negative exponent is in the denominator, we can move it to the numerator and make the exponent positive.
So, 1/5⁻² can be rewritten as 1 x 5², since 5⁻² = 1/5².
Therefore, 1/5⁻² simplifies to 25.
To explain further, 5⁻² is the same as 1/5², which means we have 1 over the square of 5. Dividing 1 by the square of 5 gives us the decimal value of 0.04, which is equivalent to 25 in percent form. So, 1/5⁻² simplifies to 25 with only positive exponents.
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A log is 16 m long, correct to the nearest metre. It has to be cut into fence posts which must be 70 cm long, correct to the nearest 10
What is the largest number of fence posts that can possibly be cut from the log?
Answer:
22 fence posts.
Step-by-step explanation:
To find the largest number of fence posts that can be cut from the log, we need to first convert the length of the log and the length of each fence post to the same unit of measurement. Let's convert everything to centimeters (cm).
The length of the log is 16 m = 1600 cm (since 1 m = 100 cm).
The length of each fence post is 70 cm.
To find the number of fence posts that can be cut, we divide the length of the log by the length of each fence post and round down to the nearest whole number (since we are told to round to the nearest 10).
So, the number of fence posts that can be cut is:
1600 cm ÷ 70 cm = 22.857...
Rounding down to the nearest whole number, we get:
22 fence posts.
Therefore, the largest number of fence posts that can be cut from the log is 22.
a 98% confidence interval for the mean of a population is to be constructed and must be accurate to within 0.3 unit. a preliminary sample standard deviation is 2.3. the smallest sample size n that provides the desired accuracy is
A sample size of at least 340 is required to construct a 98% confidence interval with a margin of error of 0.3 units, using a preliminary sample standard deviation of 2.3.
What is statistics?
Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of numerical data.
To determine the sample size required to construct a 98% confidence interval with a margin of error of 0.3 units, we need to use the following formula:
n = (Z*σ / E)²
where:
n = sample size
Z = the z-score corresponding to the desired level of confidence (98%)
σ = the population standard deviation (unknown, but we can use the preliminary sample standard deviation of 2.3 as an estimate)
E = the margin of error (0.3)
Plugging in the values, we get:
n = (Z*σ / E)²
n = (2.33 * 2.3 / 0.3)²
n = 339.28
Rounding up to the nearest whole number, we get n = 340.
Therefore, a sample size of at least 340 is required to construct a 98% confidence interval with a margin of error of 0.3 units, using a preliminary sample standard deviation of 2.3.
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cigarette smoking has important health consequences and is positively associated with heart and lung diseases. the consequences of quitting smoking are less well understood. one study enrolled a group of 30 nurses, ages 50-54 years, who had smoked at least 1 pack per day and quit for at least 6 years. the nurses reported their weight before and 6 years after quitting smoking. what test can be used to assess whether the mean weight changed among heavy-smoking women 6 years after quitting smoking?
To assess whether the mean weight changed among heavy-smoking women 6 years after quitting smoking, you can use a paired t-test.
A paired t-test is used to compare the means of two related groups or sets of data, such as the weights of the same group of individuals before and after an intervention (in this case, quitting smoking).
In this study, the nurses served as their own control group, as their weights were measured both before and after quitting smoking. A paired t-test would therefore be an appropriate statistical test to use to assess whether there was a significant change in weight after quitting smoking.
It is important to note that the use of a t-test assumes that the data is normally distributed and that the variances of the two groups being compared are equal. If these assumptions are not met, alternative tests may be necessary.
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2. suppose that a deck of 52 cards contains 26 red cards and 26 black cards (and assume the red cards are numbered 1 to 26, and so are the black cards). say we use the 52 cards to randomly distribute 13 cards each among two players (2 players receive 13 card each). a. how many ways are there to pass out 13 cards to each of the two players?
There are 5,148,644 ways to pass out 13 cards to each of the two players from a deck of 52 cards containing 26 red cards and 26 black cards, assuming that the distribution is random.
To distribute 13 cards each among two players from a deck of 52 cards containing 26 red cards and 26 black cards, we can use the formula for combinations. The number of ways to choose 13 cards from 52 is given by:
52 choose 13 = 52! / (13! * 39!) = 635,013,559,600
This represents the total number of ways to choose 13 cards from the deck, without regard to which player receives which cards.
To determine the number of ways to pass out 13 cards to each of the two players, we need to divide this total number by the number of ways to distribute the cards evenly between the players. Since each player receives 13 cards, we can think of the distribution as dividing the deck into two piles of 26 cards each, and then choosing 13 cards from each pile for each player. The number of ways to do this is given by:
(26 choose 13) * (26 choose 13) = (26! / (13! * 13!)) * (26! / (13! * 13!)) = 5,148,644
Therefore, there are 5,148,644 ways to pass out 13 cards to each of the two players from a deck of 52 cards containing 26 red cards and 26 black cards, assuming that the distribution is random.
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here are the first six terms of a quadratic sequence
10 19 34 55 82 115
Find an expression, in terms of n, for the nth term of this sequence.
Answer:
nth term = 3n² + 7
Step-by-step explanation:
We can represent the nth term of a quadratic sequence asLet R be a ring with identity.
(a) Let u be a unit in R. Define a map iu :R map to R by r map to uru-1. Prove that iu is an automorphism of R. Such an automorphism of R is called an inner automorphism of R. Denote the set of all inner automorphisms of R by Inn(R).
(b) Denote the set of all automorphisms of R by Aut(R). Prove that Inn(R) is a normal subgroup of Aut(R)
(c) Let U(R) be the group of units in R. Prove that the map
phi: U(R) maps to Inn(R)
defined by u maps to iu is a homomorphism. Determine the kernel of phi.
(d) Compute Aut(Z), Inn(Z), and U(Z).
(a) The set of all inner automorphisms of R is denoted by Inn(R).
(b) Inn(R) is a normal subgroup of Aut(R).
(c) [tex]$\phi(uv)=\phi(u)\circ \phi(v)$[/tex] for all [tex]$u,v\in \text{U}(R)$[/tex], which shows that [tex]$\phi$[/tex].
(d) [tex]Aut(\mathbb{Z}) \cong {\pm 1}$, $Inn(\mathbb{Z}) \cong {\mathrm{id}_\mathbb{Z}}$, and $U(\mathbb{Z}) \cong {1,-1}$.[/tex]
What is subgroup?
In abstract algebra, a subgroup is a subset of a group that satisfies the same group axioms as the parent group.
(a) Let u be a unit in R. We need to show that the map [tex]$iu:R\to R$[/tex] defined by [tex]$r\mapsto uru^{-1}$[/tex] is an automorphism of R, i.e., it is a bijective ring homomorphism.
First, note that [tex]$iu$[/tex] is a ring homomorphism since [tex]$iu(ab)=uaubu^{-1}=iu(a)iu(b)$[/tex] and [tex]$iu(a+b)=uau^{-1}+ubu^{-1}=iu(a)+iu(b)$[/tex] for all [tex]$a,b\in R$[/tex].
To show that [tex]$iu$[/tex] is injective, suppose that [tex]$iu(a)=iu(b)$[/tex] for some [tex]$a,b\in R$[/tex]. Then [tex]$ua u^{-1}=ub u^{-1}$[/tex], so [tex]$a=b$[/tex]. Thus, [tex]$iu$[/tex] is injective. To show that [tex]$iu$[/tex] is surjective, let [tex]$r\in R$[/tex] be arbitrary. Then [tex]$iu(u^{-1}ru)=ru$[/tex], so [tex]$ru=iu(u^{-1}ru)\in \text{Im}(iu)$[/tex]. Thus, [tex]$iu$[/tex] is surjective. Therefore, [tex]$iu$[/tex] is a bijective ring homomorphism, and hence it is an automorphism of [tex]$R$[/tex]. Such automorphisms are called inner automorphisms of R. The set of all inner automorphisms of R is denoted by Inn(R).
(b) To show that Inn(R) is a normal subgroup of Aut(R), we need to show that [tex]$gig^{-1}\in \text{Inn}(R)$[/tex] for all [tex]$g\in \text{Aut}(R)$[/tex] and [tex]$i\in \text{Inn}(R)$[/tex]. Let [tex]$g\in \text{Aut}(R)$[/tex] and [tex]$i_u\in \text{Inn}(R)$[/tex], where u is a unit in R. Then for any [tex]$r\in R$[/tex], we have
[tex]g(i_u(r))&=g(ur u^{-1})\&=g(u)g(r)g(u^{-1})\&=(gu)(r)(gu)^{-1}\&=i_{gu}(r).[/tex]
Thus, [tex]$g(i_u(r))=i_{gu}(r)$[/tex] for all [tex]$r\in R$[/tex], which implies that [tex]$gig^{-1}=i_{gu}\in \text{Inn}(R)$[/tex]. Therefore, Inn(R) is a normal subgroup of Aut(R).
(c) Let U(R) be the group of units in R. We need to show that the map [tex]$\phi: \text{U}(R)\to \text{Inn}(R)$[/tex] defined by [tex]$\phi(u)=i_u$[/tex] is a homomorphism and determine its kernel. To show that [tex]$\phi$[/tex] is a homomorphism, let [tex]$u,v\in \text{U}(R)$[/tex]. Then for any [tex]$r\in R$[/tex], we have
[tex]\phi(uv)(r)&=i_{uv}(r)\\\\&=(uv)r(uv)^{-1}\\\\&=u(vru^{-1})u^{-1}\\\\&=u(i_v(r))u^{-1}\\\\&=(i_u\circ i_v)(r)\\\\&=(\phi(u)\circ \phi(v))(r).[/tex]
Thus, [tex]$\phi(uv)=\phi(u)\circ \phi(v)$[/tex] for all [tex]$u,v\in \text{U}(R)$[/tex], which shows that [tex]$\phi$[/tex].
(d) We have [tex]Aut(\mathbb{Z}) \cong {\pm 1}$, $Inn(\mathbb{Z}) \cong {\mathrm{id}_\mathbb{Z}}$, and $U(\mathbb{Z}) \cong {1,-1}$[/tex].
To see why [tex]$Aut(\mathbb{Z}) \cong {\pm 1}$[/tex], note that any automorphism of [tex]$\mathbb{Z}$[/tex] is determined by the image of 1. If [tex]$f:\mathbb{Z}\to\mathbb{Z}$[/tex] is an automorphism of [tex]$\mathbb{Z}$[/tex], then [tex]$f(1)$[/tex] must be an integer [tex]$\pm 1$[/tex], since f preserves the additive and multiplicative structure of [tex]$\mathbb{Z}$[/tex]. Therefore, the map [tex]$f\mapsto f(1)$[/tex] is an isomorphism from [tex]Aut(\mathbb{Z})$ to ${\pm 1}$[/tex].
Since [tex]$\mathbb{Z}$[/tex] is commutative, any inner automorphism of [tex]$\mathbb{Z}$[/tex] is the identity map. Therefore, [tex]$Inn(\mathbb{Z}) \cong {\mathrm{id}_\mathbb{Z}}$[/tex].
Finally, [tex]$U(\mathbb{Z}) = {\pm 1}$[/tex], since the only units in [tex]$\mathbb{Z}$[/tex] are [tex]$1$[/tex] and [tex]$-1$[/tex].
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PLEASE HELP im literally down bad fr
a. The gaps to fill after factorizing the expression is: 2x² + 15x + 7 = (2x + 1)(x + 7).
b. The solution of the expression is: x = 1/2 or x = -7.
How to Factorize an Expression?a. Given the expression 2x² + 15x + 7, we can factorize this expression by first doing the following:
Apply the sum-product pattern:
2x² + 14x + x + 7
Create Pairs and take out common factor from them:
(2x² + 14x) + (x + 7)
2x(x + 7) +1(x + 7)
Rewrite the above in factor form:
2x² + 15x + 7 = (2x + 1)(x + 7)
b. Using the answer in part a, we would solve 2x² + 15x + 7 = 0 as shown below:
(2x + 1)(x + 7) = 0
2x + 1 = 0
2x = 1
x = 1/2
x + 7 = 0
x = -7
Therefore, the solution is: x = 1/2 or x = -7.
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HELP PLEASE ANSWER CORRECTLY FOR BRAINLIST
A spinner with repeated colors numbered from 1 to 8 is shown. Sections 1 and 8 are purple. Sections 2 and 3 are yellow. Sections 4, 5, and 6 are blue. Section 7 is orange.
spinner divided evenly into eight sections with three colored blue, one colored orange, two colored purple, and two colored yellow
Determine P(not yellow) if the spinner is spun once.
75%
37.5%
25%
12.5%
Answer:
6 of the 8 sections are not yellow, so:
P(not yellow) = 6/8 = 3/4 = 75%
When checking the conditions for regression inference, which of the following is evidence that the condition of equal standard deviation of y for each value of x has not been satisfied? (a) The residual plot has a distinctly curved shape. (b) The residual plot shows a group of randomly scattered points. (c) The histogram of residuals is skewed to the right (d) Small values of the explanatory variable are associated with small residuals, and large values of the explanatory variable are associated with large residuals. (e) The scatterplot has a distinctly curved shape.
Option A suggests that a distinctly curved pattern in the residual plot may indicate that the relationship between the explanatory and response variable is not linear, and a non-linear model may be more appropriate.
Hence option A is correct.
(a) The residual plot has a distinctly curved shape:
A curved pattern in the residual plot, resembling a parabola or a
U-shape, usually suggests that the relationship between the explanatory variable and response variable is not linear and that a non-linear model may be more appropriate.
(b) The residual plot shows a group of randomly scattered points:
A randomly scattered pattern in the residual plot indicates that the linear regression model is a good fit for the data, and that there are no obvious patterns or trends left in the residuals.
(c) The histogram of residuals is skewed to the right:
A skewed histogram of residuals suggests that the residuals are not normally distributed and may violate the assumption of normality. This can be problematic for inference and can impact the accuracy of hypothesis tests or confidence intervals.
(d) Small values of the explanatory variable are associated with small residuals and large values of the explanatory variable are associated with large residuals:
This pattern indicates that the model may be exhibiting heteroscedasticity, where the variability of the residuals changes as the explanatory variable changes. This can lead to biased and inconsistent estimates of the regression coefficients.
(e) The scatterplot has a distinctly curved shape:
Similar to option (a), a curved shape in the scatterplot indicates that a non-linear model may be more appropriate for the data.
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lim x→0 (1 - cos x / x)
The limit to the above question is 0.
What is limit?The value that a function approaches when its input value approaches a certain value is known as a limit in mathematics.
To evaluate the limit:
We can use L'Hopital's rule. Taking the derivative of the numerator and denominator with respect to x:
lim x→0 (1 - cos x / x) = lim x→0 [(sin x) / 1]
= sin(0)
= 0
Therefore, the limit is 0.
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The width of a rectangle is 2 units less than the length. The area of the
rectangle is 48 square units. What is the width, in units, of the rectangle?
Answer:
6 units
Step-by-step explanation:
Let's call the length of the rectangle "L" and the width "W".
From the problem, we know that the width is 2 units less than the length, so we can write:
W = L - 2
We also know that the area of the rectangle is 48 square units, so we can write:
A = L * W
Substituting the first equation into the second equation, we get:
48 = L * (L - 2)
Expanding the brackets, we get:
48 = L^2 - 2L
Rearranging, we get:
L^2 - 2L - 48 = 0
Now we can use the quadratic formula to solve for L:
L = (-b ± sqrt(b^2 - 4ac)) / 2a
In this case, a = 1, b = -2, and c = -48. Substituting these values into the formula, we get:
L = (2 ± sqrt(4 + 192)) / 2
L = (2 ± sqrt(196)) / 2
L = (2 ± 14) / 2
So, L = 8 or L = -6. We can ignore the negative solution, so the length of the rectangle is 8 units.
Now we can use the first equation to find the width:
W = L - 2
W = 8 - 2
W = 6
Therefore, the width of the rectangle is 6 units.
PLEASE HELP!!!
y+ 3 =2/3 (x - 5)
point on the line: ?
slope:?
Answer:
2x-3y=19
Step-by-step explanation:
[tex]y + 3 = \frac{2}{3} (x - 5) \\ 3y + 9 = 2x - 10 \\ 0 = 2x - 3y - 9 - 10 \\ 2x - 3y - 19 = 0[/tex]
[tex]2x - 3y = 19[/tex]
I hope it helped you
Please Mark me the brainliest
need help fast its due in 5 minutes write this number in standard form
Answer:
The answer to the question given is 785.639 .
Step-by-step explanation:
According to the rules of mathematics i.e. BODMAS
We'll first multiply,
7x100 = 700
8x10 = 80
5x1 = 5
6x[tex]\frac{1}{10}[/tex] = [tex]\frac{3}{5}[/tex] = 0.6
3x[tex]\frac{1}{100}[/tex] = 0.03
9x [tex]\frac{1}{1000}[/tex] = 0.009
So, after adding.
We get,
700 + 80 + 5 + 0.6 + 0.03 + 0.009 = 785.639
Under what conditions will Excel's Nonlinear Solver be guaranteed to identify the global maximum of a profit function?
I. When profits demonstrate decreasing marginal returns
II. When profit demonstrate increasing marginal returns
III. When the profit function has two or fewer discontinuities
While the conditions described above may increase the likelihood of Excel's Nonlinear Solver finding the global maximum of a profit function, there are no guarantees. The function may have multiple local maxima, or the solver may encounter convergence issues, even under ideal conditions.
Excel's Nonlinear Solver is a tool used to find the optimal solution for a function by iteratively adjusting its parameters. It is not guaranteed to identify the global maximum of a profit function under any conditions. However, there are some conditions that can increase the likelihood of finding the global maximum.
I. When profits demonstrate decreasing marginal returns:
If the profit function has decreasing marginal returns, it means that the additional profit gained from each additional unit of input decreases as the input level increases. In this case, the profit function will have a diminishing slope, and the solver is more likely to converge to a global maximum. However, this is not a guarantee, as there may be multiple local maxima.
II. When profits demonstrate increasing marginal returns:
If the profit function has increasing marginal returns, it means that the additional profit gained from each additional unit of input increases as the input level increases. In this case, the profit function will have an increasing slope, and the solver is less likely to converge to a global maximum. The solver may converge to a local maximum instead.
III. When the profit function has two or fewer discontinuities:
If the profit function has discontinuities, it can cause problems for the solver. If the solver encounters a discontinuity, it may not be able to converge to a solution. Therefore, the fewer the discontinuities, the more likely the solver is to find the global maximum.
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In ΔOPQ, o = 850 cm, q = 800 cm and ∠Q=25°. Find all possible values of ∠O, to the nearest degree
The measure of angle O is 27 degrees
How to determine the valueTo determine the value, we need to know the law of sines
The law of sines is represented as;
sin A/a = sin B/b = sin C/c
Such that the parameters are expressed as;
A and B and C are the angles in the trianglea and b and c are the sides of the triangleFrom the information given, we have that;
o = 850 cm, q = 800 cm and ∠Q=25°.
Substitute the values, we have;
sin O/850 = sin 25/800
cross multiply the values, we get;
sin O = sin 25 (850)/800
find the value and multiply
sin O = 359. 22/800s
sin O = 0.4490
find the inverse
O = 26. 7 degrees
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You arrive into a building and are about to take an elevator to your floor. Let X be the time it will take for the elevator to arrive to you once you've called it. Assume that the elevator arrives uniformly between 0 and 20 seconds after you press the button a. What is the probability that the elevator takes less than 10 seconds to arrive? 6. What is the probability that the elevator takes more than 18 seconds to arrive? c. What is the probability that the elevator takes between 10 and 15 seconds to arrive? d. What is the expected amount of time it will take the elevator to arrive? e. What is the variance of X?
The expected value or the mean of X is 10 and the variance of X is 100/3 sec²
We are given that X is uniformly distributed between 0 and 20 seconds after pressing the elevator button. This means the probability density function (PDF) of X is:
f(x) = 1/20, 0 ≤ x ≤ 20
f(x) = 0, otherwise
a. To find the probability that the elevator takes less than 10 seconds to arrive, we need to integrate the PDF from 0 to 10:
P(X < 10) = ∫[0,10] f(x) dx = ∫[0,10] 1/20 dx = (1/20) * [x]₀¹⁰= 1/2
Therefore, the probability that the elevator takes less than 10 seconds to arrive is 1/2.
b. To find the probability that the elevator takes more than 18 seconds to arrive, we need to integrate the PDF from 18 to 20:
P(X > 18) = ∫[18,20] f(x) dx = ∫[18,20] 1/20 dx = (1/20) * [x]₁₈²⁰ = 1/10
Therefore, the probability that the elevator takes more than 18 seconds to arrive is 1/10.
c. To find the probability that the elevator takes between 10 and 15 seconds to arrive, we need to integrate the PDF from 10 to 15:
P(10 < X < 15) = ∫[10,15] f(x) dx = ∫[10,15] 1/20 dx = (1/20) * [x]₁₀¹⁵ = 1/4
Therefore, the probability that the elevator takes between 10 and 15 seconds to arrive is 1/4.
d. The expected value or the mean of X is:
E(X) = ∫[0,20] x * f(x) dx = ∫[0,20] x * 1/20 dx = (1/40) * [x²]₀²⁰ = 10
Therefore, the expected amount of time it will take the elevator to arrive is 10 seconds.
e. The variance of X is:
Var(X) = E(X^2) - [E(X)]²
We have already found E(X) to be 10. To find E(X²), we integrate x² * f(x) from 0 to 20:
E(X²) = ∫[0,20] x² * f(x) dx = ∫[0,20] x²* 1/20 dx = (1/60) * [x³]₀²⁰ = 200/3
Therefore, the variance of X is:
Var(X) = E(X²) - [E(X)]²= 200/3 - 10² = 200/3 - 100 = 100/3 seconds²
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7
Consider the following table. Find the corresponding percent discount and fill in the blank.
A discount percent is a percent of change. Use the percent of change formula: (change in price
Note: Write your answer using the percent sign (%) as the example shows.
Original Price Sale Price
$90 $54
$79 $75. 84
$50 $20
$51 $47. 84
The corresponding percent discounts for the given original and sale prices are:
40%4%60%6.2%How to solve for the discountsTo find the percent discount, you can use the percent of change formula, which is:
Percent of change = ((Original Price - Sale Price) / Original Price) × 100
For each pair of original and sale prices, we will apply the formula to find the corresponding percent discount:
Original Price: $90, Sale Price: $54
Percent of change = ((90 - 54) / 90) × 100
Percent of change = (36 / 90) × 100
Percent of change = 0.4 × 100
Percent of change = 40%
Original Price: $79, Sale Price: $75.84
Percent of change = ((79 - 75.84) / 79) × 100
Percent of change = (3.16 / 79) × 100
Percent of change ≈ 0.04 × 100
Percent of change ≈ 4%
Original Price: $50, Sale Price: $20
Percent of change = ((50 - 20) / 50) × 100
Percent of change = (30 / 50) × 100
Percent of change = 0.6 × 100
Percent of change = 60%
Original Price: $51, Sale Price: $47.84
Percent of change = ((51 - 47.84) / 51) × 100
Percent of change = (3.16 / 51) × 100
Percent of change ≈ 0.062 × 100
Percent of change ≈ 6.2%
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Describe the data collecting process including the population of interest. For each question, address if there were any of the following biases: Sampling bias, Non-response bias, and Response bias.
Research wants to know what proportion of students graduate of the manicurist class in 2018 from WBI have a California State Board Manicurist License. The researcher asks the following question:
"Are you have a California State Board manicurist License yes or not?". The Source of Bias is Sampling Bias because the technique used to obtain the individuals to be a sample tends to favor one part of the population over another.
The researcher may consider following up with non-respondents to encourage their participation and ensure the sample is as representative as possible.
What is population of interest?The population of interest in this study is the students who graduated from the manicurist class in 2018 from WBI. The data collection process involves asking the question "Are you have a California State Board manicurist License yes or not?" to a sample of these students.
The potential source of bias in this study is sampling bias, as the technique used to obtain the sample may favor one part of the population over another. For example, if the researcher only selects students who were successful in the program, this may not be representative of the entire population of students who graduated from the program.
Non-response bias may also be a concern if some students do not respond to the survey, as their characteristics may differ from those who do respond. For example, if students who did not pass the licensing exam are less likely to respond to the survey, this may affect the accuracy of the results.
Response bias may also be a concern if students provide inaccurate or incomplete information in their responses. For example, if students who did not pass the licensing exam feel embarrassed or ashamed and are more likely to falsely claim that they have a license, this may affect the accuracy of the results.
To minimize these biases, the researcher should aim to obtain a random and representative sample of students who graduated from the program, and ensure that the survey questions are clear and unbiased. Additionally, the researcher may consider following up with non-respondents to encourage their participation and ensure the sample is as representative as possible.
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16) Which system involves the machinery and assembly lines used to create products?
Question 16 options:
packaging
production
supply chain
shipping
Production system involves the machinery and assembly lines used to create products.
The correct option is (b)
Mass Production:The mass production process constitutes assembly lines and automation technology to provide goods in bulk. The main features of mass production include division of labor as each production process requires a different machine, a smooth flow production with product flow clearly defined, standardization to achieve high quality, and high startup costs due to the many resources required before operations.
The manufacturing system is responsible for the production of goods and materials. It is a complex system that involves the coordination of resources, machines, and workers in order to produce finished products.
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(d) what is the probability that a vehicle will weigh more than 4,000 pounds? (round your answer to 2 decimal places.)
The probability that a vehicle will weigh more than 4,000 pounds is 0.20 or 20%.
(a) The mean weight of a randomly chosen vehicle can be calculated as the average of the minimum and maximum weights:
Mean = (2500 + 4500)/(2)
= 3500$ pounds
Therefore, the mean weight of a randomly chosen vehicle is 3500 pounds.
(b) The standard deviation of a uniformly distributed random variable is given by:
SD = (b-a)/√12
where a is the minimum value and b is the maximum value of the distribution. Substituting the given values, we get:
SD = 4500- 2500/ √12
= 433.01$ pounds
Therefore, the standard deviation of a randomly chosen vehicle is approximately 433.01 pounds.
(c) To find the probability that a vehicle will weigh less than 3,000 pounds, we need to calculate the proportion of the total area under the probability density function (PDF) that lies to the left of 3,000 pounds. Since the distribution is uniform, the PDF is a horizontal line with a height of (b-a) over the interval from a to b. Therefore, the probability can be calculated as:
P(X < 3000) = (3000-2500)(4500-2500)
= 1/4
= 0.25$
Therefore, the probability that a vehicle will weigh less than 3,000 pounds is 0.25 or 25%.
(d) To find the probability that a vehicle will weigh more than 4,000 pounds, we need to calculate the proportion of the total area under the PDF that lies to the right of 4,000 pounds. Again, since the distribution is uniform, the PDF is a horizontal line with a height of 1/(b-a) over the interval from a to b. Therefore, the probability can be calculated as:
P(X > 4000) = 1 - P(X >= 4000)
= 1 / (4000-2500)(4500-2500)
= 1/5
= 0.20$
Therefore, the probability that a vehicle will weigh more than 4,000 pounds is 0.20 or 20%.
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Complete question:
Assume the weight of a randomly chosen American passenger car is a uniformly distributed random variable ranging from 2,500 pounds to 4,500 pounds.
(a) What is the mean weight of a randomly chosen vehicle?
(b) What is the standard deviation of a randomly chosen vehicle? (Round your answer to 4 decimal places.)
(c) What is the probability that a vehicle will weigh less than 3,000 pounds? (Round your answer to 2 decimal places.)
(d) What is the probability that a vehicle will weigh more than 4,000 pounds? (Round your answer to 2 decimal places.)
the function f has the property that as x gets closer and closer to 3, the values of f(x) get closer and closer to 5. which of the following statements must be true? responses
At least one of these statements must be true.
What is function?
In mathematics, a function is a relationship between two sets of elements, called the domain and the range, such that each element in the domain is associated with a unique element in the range. In simpler terms, a function is a set of rules that takes an input value and produces a corresponding output value.
There are a few statements that can be inferred from the given information.
The limit of f(x) as x approaches 3 exists and is equal to 5.
The function f(3) is defined and is equal to 5.
The function f(x) is continuous at x = 3.
The function f(x) may or may not be differentiable at x = 3.
So, at least one of these statements must be true. However, without more information about the function f, we cannot determine which of these statements is true for sure.
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a local grocery surveyed customers and found that 25% use coupons, 43% bring their own bags and 12% do both. draw a venn diagram below to illustrate the survey results then answers the questions below about selecting one person from the survey. what is the probability they use coupons but did not bring their own bags? what is the probability that they use coupons or bring their own bags? what is the probability that do not use coupons and do not bring their own bags?
the probability that a randomly selected customer uses coupons but did not bring their own bags is 0.13.
What is probability?
The probability formula enables us to determine the likelihood of an event by dividing the number of favorable outcomes by the total number of possible outcomes. The probability of an event can range from 0 to 1 because the number of favorable outcomes cannot exceed the total number of outcomes.
From the Venn diagram, we can see that the probability of using coupons but not bringing their own bags is the area inside circle C but outside the overlapping region. Therefore, the probability is:
P(C and not B) = P(C) - P(C and B) = 0.25 - 0.12 = 0.13
So, the probability that a randomly selected customer uses coupons but did not bring their own bags is 0.13.
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there are 90 students enrolled in a major. a very important course that students try to enroll in does not have a large enrollment capacity. the number of students that are not able to schedule the elective into their course of study 14. what is the sigma level of the scheduling process?
as a sigma level of less than 99% indicates a high rate of defects.
What is the percentage?
A percentage that represents a tenth of a quantity. One percent, denoted by the symbol 1%, is equal to one-hundredth of something; hence, 100 percent denotes the full thing, and 200 percent designates twice the amount specified. A portion per hundred is what the percentage denotes. The percentage refers to one in a hundred. The % sign is used to denote it.
We can calculate the sigma level of the scheduling process using the formula:
Sigma level = (1 - (Number of defects / Number of opportunities)) * 100%
In this case, the number of opportunities is the total number of students enrolled in the major, which is 90. The number of defects is the number of students who were not able to schedule the elective into their course of study, which is 14. So we have:
Sigma level = (1 - (14 / 90)) * 100% ≈ 84.44%
So the sigma level of the scheduling process is approximately 84.44%. This suggests that there is room for improvement in the scheduling process, as a sigma level of less than 99% indicates a high rate of defects.
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