Answer: t = 1.8g
Step-by-step explanation:
Since we are given the information that the tip varies directly with the number of guests, then the formula to use will be:
t = kg
where,
t = wait staff tip
g = number of guests
Therefore, when the number of guests is 10 and the tip is $18, the constant of proportionality will be:
t = kg
18 = 10k
k = 18/10
k = 1.8
Therefore, t = 1.8g
Answer:
A.
Step-by-step explanation:
What will you get when you multiply the two variables?
Answer:
When variables are the same, multiplying them together compresses them into a single factor (variable). ... When multiplying variables, you multiply the coefficients and variables as usual. If the bases are the same, you can multiply the bases by merely adding their exponents.
Step-by-step explanation:
Which is the graph of Y = log(-x)?
5
4
3
3
N
1
1
A++
-4 -3 -2 -11
1 2 3 4 5 6 7 8 9
-2
-3
-4
ASAP
4
5
7
11
19
?
a. 41
b. 35
c. 23
d. 29
Answer:
35
Step-by-step explanation:
The pattern is adding powers of 2.
4+1=5 (exception)
5+2=7
7+4=11
11+8=19
19+16=35
Answer:
35
Step-by-step explanation:
4 + 1 = 5
5 + (1 × 2) = 5 +2 =7
7 + (2×2) = 7 + 4 = 11
11 +(4×2) = 11 + 8 = 19
19 + (8×2) = 19 + 16 = 35
Peaches cost $5 a dozen. Use a table to determine the following:
A. The cost of 3dozen peaches.
B. The cost of 60peaches.
C. The number of peaches you can buy for $35
Answer:
A. $15
B. $25
C. 84 peaches
Answer:
a)3dozenx$5=$15
b)60=5 dozen 5x$5=$25
c)35/5=7,7 dozen, 7 x 12= 84
Step-by-step explanation:
I need help for this math question!
Answer:
D
Step-by-step explanation:
Assuming that the expression is referring to sin²(2πft) and not sin²(2)πft, we can solve as follows:
One trigonometric identity states that sin²x+cos²x = 1. We want to express this in terms of cos²x, so we need to solve for sin²x. Subtracting cos²x from both sides, we get 1-cos²x = sin²x. Plugging (2πft) for x, we get
1-cos²(2πft) = sin²(2πft)
We can plug that into our equation to get
P = I₀²R(1-cos²(2πft)), or D
evaluate 3^2*5^5*3^3*5^3/3^4*3^4
[tex] \frac{{3}^{2} \times {5}^{5} \times {3}^{3} \times {5}^{3} }{ {3}^{4} \times {3}^{4} } \\ = \frac{ {3}^{5} \times {5}^{8} }{ {3}^{8} } \\ = \frac{ {5}^{8} }{ {3}^{3} } \\ = \frac{390625}{27} \\ = 14467.592592......[/tex]
This is the solution.
Find the missing side of the triangle
Answer:
x = 2[tex]\sqrt{5}[/tex]
Step-by-step explanation:
Pytago:
[tex]2^2 + 4^2 = x^2\\x = \sqrt{2^2 + 4^2} \\x = 2\sqrt{5}[/tex]
Answer:
4.47
Step-by-step explanation:
x²= 2² + 4²
x² = 4 + 16
x²= 20
x = √20
x= 4.47
What is 0.25% of K2 000?
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\text{When you hear/see the word of in mathematics, it usually means }\\\large\text{\bf multiplication. }[/tex]
[tex]\large\text{So, when you think of think of the word \underline{of} think of its asking you to}\\\large\text{\bf multiply }[/tex]
[tex]\large\text{Now that we got that run down out of the way lets answer your given}\\\large\text{question}[/tex]
[tex]\large\textsf{0.25\% of 2,000}[/tex]
[tex]\large\textsf{= 0.25\%} \times \large\textsf{2,000}[/tex]
[tex]\large\textsf{0.25\%} = \mathsf{\bf \dfrac{25}{100}}[/tex]
[tex]\mathsf{= \dfrac{25}{100} \times 2,000}[/tex]
[tex]\mathsf{\dfrac{25}{100}= \bf 0.0025}[/tex]
[tex]\large\textsf{= 0.0025} \times \large\textsf{2,000}[/tex]
[tex]\large\text{= \bf 5}[/tex]
[tex]\boxed{\boxed{\huge\text{Therefore, your ANSWER is: \textsf 5}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Round to the nearest whole number.
6.4
Answer:
6
Step-by-step explanation:
number
5. Thesum of a two-digit number a
(CBSE 2002]
Find the numbers.
If the two digits differ by 2, find the number. I
6. The sum of two numbers is 1000 and the difference between their squares is 256000.
7. The sum of a two digit number and the number obtained by reversing the order of its
digits is 99. If the digits differ by 3, find the number.
8. A two-digit number is 4 times the sum of its digits. If 18 is added to the number, the digits
are reversed. Find the number.
(CBSE 2001C]
[CBSE 2001C]
9. A two-digit number is 3 more than 4 times the sum of its digits. If 18 is added to the
(CBSE 2001C]
number, the digits are reversed. Find the number.
10. A two-digit number is 4 more than 6 times the sum of its digits. If 18 is subtracted from
the number, the digits are reversed. Find the number.
11. A two-digit number is 4 times the sum of its digits and twice the product of the digits.
[CBSE 2005]
Find the number.
[CBSE 2005]
12. A two-digit number is such that the product of its digits is 20. If 9 is added to the number,
the digits interchange their places. Find the number.
13. The difference between two numbers is 26 and one number is three times the other. Find
them.
14. The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the
Let the numbers are x and y
According to the question
⇒x+y=1000.....eq1⇒x 2 −y 2
=256000∵x 2 −y 2
=(x+y)(x−y)
⇒1000∗(x−y)=256000
⇒x−y=256.....eq2
Adding eq1 and eq2
⇒2x=1256⇒x=628
Put the value of x in eq1
⇒628+y=1000⇒y=372
The numbers are 628 and 372
Hi I'm From PHILIPPINES
I'm here to help USA users like you
The word "theory" is composed of the letters of the split alphabet. Three cards are taken out at random and stacked in a row one after another in order of appearance. How many possible compounds can be made up of the letters of this word?
Answer:
There would be [tex]120[/tex] of them.
Step-by-step explanation:
There are [tex]6[/tex] distinct letters in the word "[tex]\verb!theory![/tex]".
Hence, there would [tex]6[/tex] possible choices for the first letter that was selected.
Since the chosen card won't be placed back in the pool, there would be only [tex](6 - 1) = 5[/tex] possible choices for the second letter.
Likewise, there would be [tex](6 - 2) = 4[/tex] choices for the third letter.
[tex]6 \times 5 \times 4 = 120[/tex]. In other words, there are [tex]120[/tex] possible ways to draw three cards out of [tex]6[/tex] one after another.
Since the question states that the order of the cards matters, it won't be necessary to eliminate repetitions such as "[tex]\verb!the![/tex]" and "[tex]\verb!het![/tex]" from the number of combinations.
an electric pole of height 25 m casts a shadow of 20 m.find the height of a tree, if it casts a shadow of 12 m under similar conditions
Answer:
9.6
Step-by-step explanation:
20 divided by 25 = 0.8
Then, 0.8 times 12 = 9.6
I bet that helped! :D
3（6x+3）=63 How to do it
What is the minimum perimeter of a rectangle with an area of 625 mm^2
180 °
X °
26 °
X = ? °
Answer:
X = 64
Step-by-step explanation:
All of the angles are right angles (because of the square at one of the angles shown above). This means each angle equals 90 degrees. If X + 26 = 90, then X = 64 because 90 - 26 = 64. I hope this helps!
Answer: X = 64
Step-by-step explanation:
According to Runzheimer International, a typical business traveler spends an average of $281 per day in Chicago. This cost includes hotel, meals, car rental, and incidentals. A survey of 50 randomly selected business travelers who have been to Chicago on business recently is taken. For the population mean of $281 per day, what is the probability of getting a sample average of more than $268 per day if the population standard deviation is $47?
Answer:
The correct answer is - 97.74%.
Step-by-step explanation:
Given:
sample mean = 281
Std Dev = 47 ==> Sample
Std Dev (s) = std dev/sqrt(n) = 6.0677
Solution:
Find : P( x > 268 )
z = ( x - u )/s = ( 268 - 281 )/6.0677
= -1.9558
then, P( x > 270) = P( Z > -1.9558)
= P( Z <1.9558)
= 0.9747
change into percentage:
= 97.471%
F(x)=-2x^2+4x+5
Find the critical numbers
Answer:
To find critical points, take the first derivative and set it equal to zero:
f(x) = -2x^2 + 4x + 5
f'(x) = -4x + 4
-4x+4 = 0
-4x = -4
x = 1
Critical point at x = 1
Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.
what is the hcf of 40,50???
Answer:
10
Step-by-step explanation:
10
A student majoring in accounting is trying to decide on the number of firms to which he should apply. Given his work experience and grades, he can expect to receive a job offer from 70% of the firms to which he applies. The student decides to apply to only four firms.
(a) What is the probability that he receives no job offer?
(b) How many job offers he expects to get?
(c) What is the probability that more than half of the firms he applied do not make him any offer?
(d) What assumptions do you need to make to find the probabilities? To increase the chance of securing more job offers, the student decides to apply to as many companies as possible, he sent out 60 applications to all different accounting firms.
(e) What is the probability of him securing more than 3 offers?
Answer:
a) 0.0081 = 0.81% probability that he receives no job offer
b) He expects to get 2.8 job offers.
c) 0.0837 = 8.37% probability that more than half of the firms he applied do not make him any offer.
d) Each job must be independent of other jobs. Additionaly, if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal approximation to the binomial distribution can be used.
e) 0.2401 = 24.01% probability of him securing more than 3 offers.
Step-by-step explanation:
For each application, there are only two possible outcomes. Either he gets an offer, or he does not. The probability of getting an offer for a job is independent of any other job, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
He can expect to receive a job offer from 70% of the firms to which he applies.
This means that [tex]p = 0.7[/tex]
The student decides to apply to only four firms.
This means that [tex]n = 4[/tex]
(a) What is the probability that he receives no job offer?
This is [tex]P(X = 0)[/tex]. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{4,0}.(0.7)^{0}.(0.3)^{4} = 0.0081[/tex]
0.0081 = 0.81% probability that he receives no job offer.
(b) How many job offers he expects to get?
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
In this question:
[tex]E(X) = 4(0.7) = 2.8[/tex]
He expects to get 2.8 job offers.
(c) What is the probability that more than half of the firms he applied do not make him any offer?
Less than 2 offers, which is:
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{4,0}.(0.7)^{0}.(0.3)^{4} = 0.0081[/tex]
[tex]P(X = 1) = C_{4,1}.(0.7)^{1}.(0.3)^{3} = 0.0756[/tex]
Then
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.0081 + 0.0756 = 0.0837[/tex]
0.0837 = 8.37% probability that more than half of the firms he applied do not make him any offer.
(d) What assumptions do you need to make to find the probabilities? To increase the chance of securing more job offers, the student decides to apply to as many companies as possible, he sent out 60 applications to all different accounting firms.
Each job must be independent of other jobs. Additionaly, if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal approximation to the binomial distribution can be used.
(e) What is the probability of him securing more than 3 offers?
Between 4 and n, since n is 4, 4 offers, so:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401[/tex]
0.2401 = 24.01% probability of him securing more than 3 offers.
A sample of 38 babies in the zinc group had a mean birth weight of 3328 grams. A sample of 31 babies in the placebo group had a mean birth weight of 3406 grams. Assume that the population standard deviation for the zinc group is 640 grams, while the population standard deviation for the placebo group is 851851 grams. Determine the 99% confidence interval for the true difference between the mean birth weights for "zinc" babies versus "placebo" babies.
Required:
Find the point estimate for the true difference between the population means.
Answer:
-78
Step-by-step explanation:
Zinc group :
Mean, x1 = 3328
σ1 = 640
Sample size, n1 = 28
Placebo group :
Mean, x2 = 3406
σ2 = 851
Sample size, n2 = 31
The point estimate for the true difference between the population means is obtained as :
Mean difference between population :
x1 - x2 = 3328 - 3406 = - 78
In how many ways can 10 people be divided into three groups with 2, 3, and 5 people respectively?
Answer:
2100
Step-by-step explanation:
In how many ways can a group of 10 people be divided into three groups consisting of 2,3, and 5 people?
First, you need to choose 4 people to fill the first group.
The number of ways is (104) which equals to 210.
Then, pick 3 more people out of the remaining 6 to be in the second group. And then, pick 3 more out of the remaining 3.
However, we need to divide it by 2, since we don’t really care on the order of selection of group.
(63)(33)/2=10
So, there are 210 x 10 = 2100 ways
Answer:
hmmm I read JeremyBrooks answer... I think that it might be different...
i think it is 2520
of the 10 you first choose 2
10 choose 2 = 45 ways
in each of the 45 "chooses" you now
pick a group of 3 of the 8 left
8 choose 3 = that is 56
of the five people left you choose 5
5 choose 5 = 1
so the possibilities are 45*56 * 1 = 2520
Step-by-step explanation:
In a car lot, the ratio of the number of new cars to the number of preowned cars is 6 to 5. The total number of new and preowned cars on the lot is 66. If 4 new cars and 2 preowned cars are sold and are removed from the lot, what fraction of the remaining cars on the lot are preowned?
The fraction of the remaining cars in the lot that are preowned is 7/15
In order to determine the fraction of the remaining cars in the lot that are preowned, we have to first determine the total number of new cars and preowned cars before the sale occurred.
Total number of preowned cars before the sales = (ratio of preowned cars / total ratio) x total number of cars
ratio of preowned cars = 5
total ratio = 6 + 5 = 11
total number of cars = 66
(5/11) x 66 = 30 cars
Total number of new cars before the sale = (ratio of new cars / total ratio) x total number of cars
ratio of new cars = 6
total ratio = 6 + 5 = 11
total number of cars = 66
(6/11) x 66 = 36 cars
Total number of new cars after the sale = total number of new cars before the sale - number of new cars sold
36 - 4 = 32
Total number of preowned cars after the sale = total number of preowned cars before the sale - number of preowned cars sold
30 - 2 = 28
The fraction of the remaining cars on the lot that are preowned = number of preowned cars after the sale / total number of cars on the lot after the sale
total number of cars on the lot after the sale = 28 + 32 = 60
28/60
to convert to the simplest term, divide the numerator and the denominator by 4
7/15
To learn more about fractions, please check : https://brainly.com/question/15898494?referrer=searchResults
There are 52 cards in a deck, and 13 of them are hearts. Four cards are dealt, one at a time, off the top of a well-shuffled deck. What is the percent chance that a heart turns up on the fourth card, but not before
Answer:
10.97%
Step-by-step explanation:
There are 52 cards.
13 of them, are hearts.
Then
52 - 13 = 39 cards are not hearts.
4 cards are drawn, we want to find the percent chance that the fourth card is a heart card, but no before.
So the first card can't be a heart card.
because the deck is well-shuffled, all the cards have the same probability of being drawn.
Then the probability of not getting a heart card, is equal to the quotient between the number of non-heart cards (39) and the total number of cards (52), then the probability is:
p₁ = 39/52
The second card also can't be a heart card, the probability is calculated in the same way than above, but now there are 38 non-heart cards and a total of 51 cards (because one card was already drawn) then the probability here is:
p₂ = 38/51
For the third card the reasoning is similar to the two above cases, here the probability is:
p₃ = 37/50
The fourth card should be a hearts card, the probability is computed in the same way than above, as the quotient between the number of heart cards in the deck (13) and the total number of cards in the deck (now there are 49 cards)
then the probability is:
p₄ = 13/49
The joint probability (the probability of these 4 events happening together) is equal to the product between the individual probabilities:
P = p₁*p₂*p₃*p₄
P = (39/52)*(38/51)*(37/50)*(13/49) = 0.1097
The percent chance is the above number times 100%
Percent = 0.1097*100% = 10.97%
PLZ HELP QUESTION IN PICTURE
Answer: [tex]-\frac{9}{2}, -4, -3, -\frac{11}{4}, -2[/tex]
Step-by-step explanation:
slope = m
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-7-9}{-1-(-5)}=-4[/tex]
y = mx + b, (-5,9), (-1,-7), m = -4; (does not matter which point you plug in)
[tex]y=mx+b\\9=-4(-5)+b\\9=20+b\\b=-11\\y=-4x-11[/tex]
(now plug in each y value into the equation above)
[tex]7=-4x-11\\18=-4x\\x=-\frac{9}{2}\\\\5=-4x-11\\16=-4x\\x=-4\\\\1=-4x-11\\12=-4x\\x=-3\\\\0=-4x-11\\11=-4x\\x=-\frac{11}{4} \\\\-3=-4x-11\\8=-4x\\x=-2[/tex]
PLease Help! I will give you the brainiest and a lot of points
A survey of 104 college students was taken to determine the musical styles they liked. Of those, 22 students listened to rock, 23 to classical, and 24 to jazz. Also, 10 students listened to rock and jazz, 8 to rock and classical, and 8 to classical and jazz. Finally, 6 students listened to all three musical styles. Construct a Venn diagram and determine the cardinality for each region. Use the completed Venn Diagram to answer the following questions.
a. How many listened to only rock music?
n(only rock)
b. How many listened to classical and jazz, but not rock?
n(classical and jazz, not rock)
c. How many listened to classical or jazz, but not rock?
n(classical or jazz, not rock)
d. How many listened to music in exactly one of the musical styles?
n(exactly one style)
e. How many listened to music in exactly two of the musical styles?
n(exactly two styles)
f. How many did not listen to any of the musical styles?
n(none)
Answer:
A. 22
B. 8
C. 23 + 24
D. 22 + 23 + 24
E. 8 + 8 + 10
F. 104 - (sum of all the given numbers) = 3
HELP. Use the grouping method to factor the polynomial below completely.
x^3 – 5x^2 + 3x - 15
A. (x^2 + 5)(x-3)
B. (x^2 - 3)(x+5)
C. (x^2 - 5)(x+3)
D. (x^2 + 3)(x - 5)
Answer:
D
Step-by-step explanation:
(x^2+3)(x-5)
That's the answer
Question
Alice drove her car 279 miles in 6 hours. Write this rate as a reduced fraction.
Answer:93/2 or 46.5 mph
Step-by-step explanation:
Answer:
93/2Step-by-step explanation:
•Form the given into a fraction using m/hrs format279/6•Reduced the fraction279 ÷ 3----------- 6 ÷ 3•Final answer93/2[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
jess wants to buy a car but she cannot decide if she should buy a Honda or a Kia. The Honda costs $16,000 and depreciates at an annual rate of 8%. The Kia costs $12,000 and depreciates at an annual rate of 12%. What will each car be worth in 5 years? In 10 years? Which car should she buy and why?
Answer:
Step-by-step explanation:
Honda : 16,000
each year depreciates 8% from 100% so will be left with 100-8 =92% or 0.92
in 5 years : 16,000* 0.92^5 ≈ $10,545.30
in 10 years : 16,000* 0.92^10 ≈ $6,950.22
Kia : $12,000
each year depreciates 12 % from 100% so will be left with 100-12 =88% or 0.88
in 5 years : 12,000* 0.88^5 ≈ $6,332.78
in 10 years : 12,000* 0.88^10 ≈ $3,342.01
Jess should buy the Honda if wants to use it for 5 years or less because although is more expensive than Kia, it depreciates less in 5 years.
In 5 years the difference in depreciation is 10,545.30 -6,332.78= $ 4,212.52 this is greater that the difference in the actual price 16,000-12,000 =$ 4,000
Jess should buy the Kia if wants to use the car for 10 years or more because Kia will depreciates less than Honda in 10 years.
In 10 years the difference in depreciation is 6,950.22 -3,342.01 =$ 3, 608.21 this is lower that the difference in the actual price 16,000-12,000 =$ 4,000
A vending machine dispenses coffee into a twelve ounce cup he amount of coffee dispensed into the cup is normally distributed with a standard deviation of 0.006 ounce. You can allow the cup to overfill 4â% of the time. What amount should you set as the mean amount of coffee to beâ dispensed?
Answer:
this mean amount of coffee to be dispensed would be 11.99, approximately 12
Step-by-step explanation:
first of all we have this information available to answer this question.
standard deviation σ = 0.006 ounces
prob(x > 12) = 0.04
we use this formular to find the mean
z = x - μ/σ
the value of the z score at 4% is equal to 1.7507
such that
[tex]1.7507 = \frac{12-u}{0.006}[/tex]
we cross multiply from this stage
1.7507*0.006 = 12-μ
0.0105042 = 12-μ
μ = 12 - 0.0105042
herefore, the mean amount μ = 11.99 this can be approximated to 12
Four wires (red,green, blue and yellow) need to be attached to a circuit board. A robotic device will attach the wires. The wires can be attached in any order, and the production manager wishes to determnine which order would be the fastest for the robot to use.
Required:
Use the multiplication rule of counting to determine four choices for the first wire, three for the second wire, two for the third and only one for the fourth.
Answer:
24
Step-by-step explanation:
The topic here is COMBINATORICS.
The parent topic is PERMUTATIONS & COMBINATORICS.
Permutation deals with arrangement in a definite order while, as stated in the question here, definite order in not needed in Combinatorics.
Now, the multiplication rule of counting, also known as the rule of product, talks about the multiplication of the figures that represent the different ways of doing something.
For example, in this question, the robot needs to attach 4 wires to a circuit board. If you know how Physics or Electricity works, you'll that truly this is a combination matter and not permutation.
Putting/Connecting the 4 wires together (in a square shaped circuit for instance), the arrangement RGBY is different from RGYB or RBGY.
So there will be more ways to connect or combine these wires, than if we were to follow a definite rule like: "Red and Green must always stay together".
So using the multiplication rule of counting to determine 4 choices for the Red wire, 3 choices for the Green wire, 2 choices for the Blue wire, and 1 choice for the yellow wire, we have:
R4 x G3 x B2 x Y1 = 4 x 3 x 2 x 1 = 4! = 24
The term "4!" means "Four Factorial".
