A certain drug is made from only two ingredients: compound A and compound B. There are 7 millimeters of compound A used for every 5 millimeters of compound B. If a chemist wants to make 900 millimeters of the drug, how many millimeters of compound A are needed?

P (W or Z) if W and Z are independent, would be 0.673.

Independent events are the events that the outcome of one event does not affect the outcome of the other event, so the probability of one event happening doesn't change the probability of the other event happening.

If W and Z are independent, it means that the probability of W occurring has no effect on the probability of Z occurring, and vice versa.

In this case P(W or Z) can be calculated using the formula for the probability of the union of two independent events:

P(W or Z) = P(W) + P(Z) - P(W and Z)

P(W and Z) = P(W) x P(Z)

= 0.42 x 0.35

= 0.147

Therefore:

P(W or Z) = P(W) + P(Z) - P(W and Z)

= 0.42 + 0.35 - 0.147

= 0.673

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Answer:

Ali's mark= 40

Ahmad's mark= 85

Step-by-step explanation:

Let x be Ali's mark and y be Ahmad's mark.

y=2x+5

x+y=125

x+2x+5=125

3x=120

x=40

y=85

Answer: 26

Step-by-step explanation:

Since we are given the value of y, all we need to do is plug it into the equation and solve it. Make sure if you plug this into a calculator that you put the substituted number in parenthesis that way it squares the number correctly without a negative sign.

(-3)²-5(-3)+2

9 - 5(-3) +2

9 - -15 + 2

9 + 15 + 2

24 + 2

26

Hope this helps!

The area of the octagon is 40 + 40√(2) in simplest radical form.

What is the area of the octagon?

The area of a regular octagon can be calculated using the formula:

Area = (2 + 4 * √2) * s^2

where s is the length of one of the sides.

An equiangular octagon is an octagon in which all of the angles are congruent. In addition, all the side lengths are also congruent. However, in the case of the side lengths of the octagon are given as 1, 2, 3, 4, 1, 2, 3, and 4 in clockwise order.

To find the area of the octagon, we can use the following formula:

Area = 2(1 + 2 + 3 + 4)(4) * (1 + √(2))/4

Area = 2(10)(4) * (1 + √(2))/4

Area = 80 * (1 + √(2))/2

Area = 40 + 40*√(2)

Hence, the area of the octagon is 40 + 40√(2) in simplest radical form.

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The range of a set of data is the difference between the highest and lowest values. In this case, the graph shows that the relative humidity changes between 30% and 80% during a 24 hour period in New York City. To find the range, we subtract the lowest value (30%) from the highest value (80%):

Range = 80 - 30 = 50%

So, the range of the relative humidity during this 24 hour period in New York City is 50%.

The range of this set of data is 30 ≤ y ≤ 80.

The correct option is 3.

A relation between a collection of inputs and outputs is known as a function. A function is a connection between inputs in which each input is connected to precisely one output. Each function has a range, co-domain, and domain.

Given:

A meteorologist drew the accompanying graph to show the changes in relative humidity during a 24-hour period in New York City.

The graph is given in the attached image.

The function is not exceeding the value 80.

And more than the value 30.

So, the range is,

= 30 ≤ y ≤ 80.

Therefore, the range is 30 ≤ y ≤ 80.

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Answer:

5

Step-by-step explanation:

To find the median in a set of data, we first need to arrange the numbers in ascending order.

2,3,3,5,5,5,5,7,8

The median is the middle value of the set. Since there is an even number of data points in this set, the median is the average of the two middle values, which are 5 and 5.

So the median = (5+5)/2 = 5.

The base of Octagon Towers has 135-degree inside angles on each side.

The formula: can be used to determine the size of each inner angle of a regular octagon.

(n-2) x 180 / n

where n is the polygon's number of sides.

n=8 for Octagon.

As a result, we can change n in the formula to 8:

(8-2) x 180 / 8 = 6 x 180 / 8

The base of the Octagon Towers is a regular octagon, the measure of each interior angle of the base of the Octagon Towers will be

135-degree

The base of Octagon Towers has 135-degree inside angles on each side.

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Full question

Octagon Towers is an octagon-shaped condominium building in Miami, Florida. Assuming the base of the Octagon Towers is a regular octagon, find the measure of each interior angle of the base of the Octagon Towers.

Each interior angle measures?

The angles for the triangle are 42°, 68° and 70° and x=21.

What is a triangle?

In Geometry, triangles are the type of polygons, which have three sides and three vertices. This is a two-dimensional figure with three straight sides. A triangle is considered a 3-sided polygon. The sum of all the three angles of a triangle is equal to 180°. The triangle is contained in a single plane. Based on its sides and angle measurement, the triangle has six types.

Based on the sides of a triangle, a triangle is classified into 3 types, namely:

Scalene Triangle – All the sides are of different measures.

Isosceles Triangle – Two sides of a triangle are of the same measure and the remaining side has a different measure.

Equilateral Triangle – All the 3 sides of a triangle are of the same measure.

Based on the angles of a triangle, a triangle is classified into 3 types, namely:

Acute Angle Triangle – All the angles of a triangle is less than 90°.

Obtuse Angle Triangle – One of the angles of a triangle is greater than 90°.

Right Angle Triangle – One of the angles of a triangle is equal to 90°.

Now,

As sum of all angles of a triangle is 180°

2x+3x+5+4x-14=180

x=21

hence,

         The angles for the triangle are 42°, 68° and 70° and x=21.

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Right question:-

Angles in the question are 2x°,(3x+5)° and (4x-14)° of a triangle.

Answer:

y = 48

Step-by-step explanation:

14 x 2 = 28

28 + 20 = 48 = y

16 x 2 = 32

80 - 32 = 48 = y

The shaded region in a standard normal distributive property corresponds to values between -1 and 1, which represent 68.27% of the area under the curve.

The shaded region in a standard normal distribution corresponds to values between -1 and 1, which represent 68.27% of the area under the curve. This is because the standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The cumulative probability of a standard normal distribution can be found using the cumulative distribution function (CDF). The CDF of a standard normal distribution is equal to 0.6827 or 68.27%. Therefore, the shaded region in a standard normal distribution represents the cumulative probability from -1 to 1, which is equal to 0.6827 or 68.27%. This means that the shaded region corresponds to 68.27% of the area under the curve. This is important to note because it indicates that the majority of values in a standard normal distribution are located between -1 and 1.

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The complete question is

the shaded region under a normal distribution with mean 0 and standard deviation 1 (standard normal distribution) is shown. which of the following is the best choice that corresponds to the shaded region? select one Values between -1 and 1

The standard deviation of the Age variable is 8.2195 years. 95% of the data observations fall between 18.8 and 31.1.

1) The standard deviation of the Age variable is 8.2195 years.

2) Between 18.8 and 31.1.

1) To calculate the standard deviation of the Age variable, first calculate the mean of the variable. To do this, add up all of the values and divide by the total number of observations (in this case, 12). The mean is then 24.75. To calculate the standard deviation, subtract the mean from each observation, square the result, and sum the squared differences. Divide the sum by 11 (the total number of observations minus 1), then take the square root of the result. The standard deviation of the Age variable is 8.2195 years.

2) To find the values between which 95% of the data observations fall, calculate the standard deviation multiplied by 1.96. This will give the range for the 95% of the data observations. To find the lower value, subtract the standard deviation multiplied by 1.96 from the mean. For the upper value, add the standard deviation multiplied by 1.96 to the mean. In this case, the lower value is 18.8 and the upper value is 31.1.

The standard deviation of the Age variable is 8.2195 years. 95% of the data observations fall between 18.8 and 31.1.

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Answer:

$427

Step-by-step explanation:

Sam expects to make $7 for every $100 he invests, which is a 7% return. To determine how much he expects to make on an investment of $6100, we can use the following formula:

investment amount * (return rate / 100) = expected return

$6100 * (7 / 100) = $427

So Sam expects to make $427 on an investment of $6100 if he makes $7 for every $100 he invests.

Answer:

$427

Step-by-step explanation:

$6100/$100=61

61 ×7=427

The credit term 3/15, n/45 states that the buyer will receive a 3% discount if the payment is made within 15 days. Otherwise, full payment is expected within 45 days from the invoice date.

This term can be expressed as a formula and calculation as follows:

Discount = 3% of Invoice Total

Payment due within 15 days = Invoice Total - Discount

Payment due within 45 days = Invoice Total

For example, if the invoice total is $500, then the buyer will receive a 3% discount (Discount = 3% x $500 = $15) if the payment is made within 15 days. The payment due within 15 days is then equal to the invoice total minus the discount ($500 -$15 = $485). On the other hand, if the payment is not made within 15 days, the buyer is expected to pay the full invoice total within 45 days ($500).

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If C(x) = 0.001x² + 1000 dollars is the cumulative cost of running the Acme factory, we can find the cumulative profit of the Acme factory by subtracting the cumulative cost from the total revenue. Let's assume that the total revenue is a constant value of R dollars.

Therefore, the cumulative profit function P(x) can be written as:

P(x) = R - C(x)

Where R is the total revenue and x is the number of days since the start of 2018. The unit of the function's output will be dollars, since both the total revenue and the cumulative cost are measured in dollars.

Therefore, P(x) = R - (0.001x² + 1000) dollars

It is important to note that the value of R is not given in the problem statement and it is unknown, thus the function P(x) is not complete without the value of R. In addition, a proper function would have the start date of the factory and the end date, but it's mentioned to be since the start of 2018.

The answer in interval notation is (-∞,-6] u [4+∞)

An interval on a number line can be represented using interval notation. It is a method of representing subsets of the real number line, in other words. The numbers in between any two particular provided numbers are referred to as an interval. For instance, the interval containing 0, 5, and all values between 0 and 5 is the set of numbers x satisfying 0 x 5.

A subset of real numbers can be expressed using interval notation by the integers that bound them. Inequalities can be represented using this notation. We are aware that a range of numbers between 1 and 5 is represented by the interval 1 x 5.

Based on the numbers in the set, intervals can be categorised. Some sets have the endpoints indicated in the notation, but others may only contain them partially or not at all. There are generally three different sorts of intervals:

To represent the interval notation for various sorts of intervals, we can adhere to a set of rules and symbols. Let's examine the various symbols that can be used to represent a specific kind of interval.

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The Ordinary integral of the Line integral [tex]\int _c {(y-z)} \, ds[/tex] where C is the helix ⟨7cos t, 7sin t, t⟩ is [tex]\int\limits^0 _{-2\pi} \sqrt{50}{(7sin\ t -t)} \, dt[/tex] and its value in the range -2π ≤ t ≤ 0 is 10√2 π²

We have x = 7cos t, y = sin t and z = t.

We also need ds =[tex]\sqrt{(\frac{dx}{dt})^{2} +(\frac{dy}{dt})^{2} +(\frac{dy}{dt})^{2} }dt[/tex]

     ds  = [tex]\sqrt{(-7sin\ t)^{2} +(7cost\ t)^{2} +(1)^{2} }dt[/tex]

           = [tex]\sqrt{49sin^{2}t +49cos^{2}t+1 }dt[/tex]

           = [tex]\sqrt{49(sin^{2}t +cos^{2}t)+1 }dt[/tex]

     ds  = [tex]\sqrt{50}dt[/tex]

Now,  [tex]\int _c {(y-z)} \, ds[/tex] =  [tex]\int\limits^0 _{-2\pi} {(7sin\ t -t)}\sqrt{50} \, dt[/tex]

Evaluating the integral [tex]\int\limits^0 _{-2\pi} {(7sin\ t -t)}\sqrt{50} \, dt[/tex]

[tex]\int\limits^0 _{-2\pi} {(7sin\ t -t)}\sqrt{50} \, dt[/tex]   =  [tex]\sqrt{50}\ {[-7cos\ t -\frac{t^{2} }{2} ]}\limits^0 _{-2\pi}[/tex]

                                     =  [tex]\sqrt{50}\ {[-7+7+2\pi ^{2}]}[/tex]

                                     =  [tex]10\sqrt{2}\pi ^{2}}[/tex]

The question is incomplete, the complete question is

" Convert the line integral to an ordinary integral with respect to the parameter and evaluate it.[tex]\int _c {(y-z)} \, ds[/tex] ; C is the helix ⟨7cos t, 7sin t, t⟩, for -2π ≤ t ≤ 0 "

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The expression in terms of xx that represents the total amount that Elizabeth paid is - xx + 0.07xx + 0.2(xx + 0.07xx) = 1.47xx

This question uses the concepts of percentages and algebraic expressions.

The expression that is used to calculate the total amount that Elizabeth paid is an example of an algebraic expression.

It uses the percentage tax rate of 7% and the percentage tip rate of 20%, which are both represented by decimal numbers.

Step 1: Calculate the tax by multiplying the subtotal (xx) by the tax rate (0.07): 0.07xx

Step 2: Calculate the tip by multiplying the subtotal (xx) plus the tax (0.07xx) by the tip rate (0.2): 0.2(xx + 0.07xx)

Step 3: Calculate the total by adding the subtotal (xx), the tax (0.07xx), and the tip (0.2(xx + 0.07xx)): xx + 0.07xx + 0.2(xx + 0.07xx)

Step 4: Simplify the expression to 1.47xx.

xx + 0.07xx + 0.2(xx + 0.07xx) = 1.47xx

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The x-axis at (2, 0) and point P work out the x-coordinate of the turning point the y-axis at (0, -14)  of the graph x is 9/2.

The turning point's x-coordinate will be "9/2."

The answer to the query is

y = [tex]x^{2}[/tex] + bx + c

curving goes by.

(2 , 0)

and,

(0 , 14)

Putting (0, 14) results in

→ 14 = 0 +  0 + c

c = 14

then,

→ y = [tex]x^{2}[/tex] + bx + 14.

Putting in (2, 0) gives us

→0 = 4 + 2b + 14

-2b = 18

b =  - 18 /2

= -9

then,

→ y = [tex]x^{2}[/tex] - 9x + 14.

the discovery of

→ dy / dx = 0

dy/dx = 2x - 9

turning point

→ dy / dx = 0

2x - 9 = 0

x = 9/2.

The curve intersects

The x-axis at (2, 0) and point P work out the x-coordinate of the turning point the y-axis at (0, -14)  of the graph x is 9/2.

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The slope of the graph changes from -3 to 3 and the y-intercept changes from -2 to -4.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

The given equations are f(x)= -3x-2 to f(x)=3x-4.

The slope of the equation changes from -3 to 3 which is shown in the graph similarly the y-intercept of the graph changes from -2 to -4.

The graph of the two lines f(x)= -3x-2 and f(x)=3x-4 is attached with the answer below.

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A Type I error would occur if the HOA falsely rejects the null hypothesis that only 45% of homeowners support the fee increase when in reality more than 45% supports the increase.

A Type I error occurs when a null hypothesis is rejected when it is actually true. In this case, the null hypothesis is that only 45% of homeowners support the fee increase. To test this hypothesis, the HOA surveys a sample of 50 homeowners and uses the results to test the hypotheses H0: p = 0.45 and Ha: p > 0.45. If the HOA finds evidence that more than 45% of homeowners support the fee increase, when in reality only 45% or less of the homeowners support the fee increase, then a Type I error has occurred. On the other hand, if the HOA does not find evidence that more than 45% of homeowners support the fee increase, when in reality more than 45% of the homeowners do support the increase, then a Type I error has also occurred. In both cases, the HOA has incorrectly rejected the null hypothesis and a Type I error has occurred.

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Therefore ,as a result, the total surface area is 64 + 16 = 80 square units.

The amount of space it occupies on the surface is a decent indication of its overall size. The complete surroundings is taken into account when calculating the area of a tri shape. Something's total size is determined by its surface area. The volume of water inside a cuboid is equal to the total of the volumes on each and every six of its rectangular sides. To calculate the box's measurements, use the formula below: In 2lh, 2lw, and 2hw, the region is identical (SA). The surface area of the multipurpose shape represents the region.

Here,

Imagine a line running from 8m to 4m at the intersection. As a result, a rectangle and a triangle are formed.

Simple

=> is the square's area

=> 8 *8  = 64 square units.

Use the formula

=> (1/2)b*h to determine the triangle's area 

We need to enter the hieght, which is already known to be 4, and the base, which is already known to be 8, into the equation.

=> Triangle area unit = 1/2 * 8 * 4

Therefore ,as a result, the total area is 64 + 16 = 80 square units.

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After the first randomization,  μ₁ is 12.5,  is μ₂ 11.46 and μ₁-μ₂ is 1.04. After the second randomization, μ₁ is 11.36, μ₂ is 12.6 and μ₁-μ₂ is -1.24. After the third randomization, μ₁ is 11.98, μ₂ is 11.98 and μ₁-μ₂ is 0.

Randomization is the process of placing a group of objects, persons, etc. in an unpredictable, illogical, or random order. The sum of all observations in a data set divided by the total number of observations is the data set's mean. The subtraction of two variables is the result of subtracting the means of the two variables. Each randomization in this problem consists of two sets of five observations.

For the first randomization:

μ₁=  [tex]\frac{13.6+12.1+15.9+11.2+9.7}{5}[/tex] = 12.5            [ μ₁ = Group A      

μ₂=[tex]\frac{9.2+8.2+11.5+13.8+14.6}{5}[/tex] = 11.46                μ₂ = Group B]

μ₁-μ₂ = 1.04

Similarly solve for the second and third randomizations

The complete question is:

A random number generator assigned each pepper to one of two groups. The weights of the peppers in each group, given three randomizations, appear in the tables.

First randomization

group a

13.6

12.1

15.9

11.2

9.7

group b

9.2

8.2

11.5

13.8

14.6

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The correct option is (c) a Mean of 5 inches with a standard deviation of 5 inches for the question

Given,

         The average height of policemen, μ[tex]_{x}[/tex] = 71 inches

          The standard deviation for policemen, SD[tex]_{x}[/tex] = 4 inches

          The average height of a policewoman, μ[tex]_{y}[/tex] = 66 inches

          The standard deviation for policewomen, SD[tex]_{x}[/tex] = 3 inches

We know that,

When policemen and policewomen have paired, the mean for the difference in height can be given by:

                              μ = μ[tex]_{x}[/tex] - μ[tex]_{y}[/tex]

On substituting the value in the above equation, we get:

                              μ = 71 - 66

                              μ = 5 inches

When policemen and policewomen have paired, the standard deviation for the difference in height can be given by:

                              [tex]SD = \sqrt{SD_{x}^{2} + SD_{y}^{2} } \\\\SD = \sqrt{4^{2} + 3^{2} }\\\\SD = \sqrt{ 16 + 9 }\\\\SD = \sqrt{25}\\\\SD = 5[/tex]

Thus, the required mean is 5 inches and the standard deviation is 5 inches.

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Arrays are a fundamental data structure, and an important part of most programming languages.

Method :

Employ two loops. Pick elements one at a time in the outer loop, and then in the inner loop, compare each element's difference to every other element in the array and the largest difference ever calculated. The application of the aforementioned strategy is seen below:

Here i attached the programs

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[tex](3x+2)(3x^{2} +4)[/tex]

This equation can be solved using the distributive is by multiplying each term by the other term.

First, multiply [tex]3x[/tex] by [tex]3x^{2} +4[/tex]

[tex]3x(3x^{2} +4)=(3x*3x^{2} )+(3x*4)[/tex]

Then, multiply [tex]2[/tex] by [tex]3x^{2} +4[/tex]

[tex]2(3x^{2} +4)=(2*3x^{2} )+(2*4)[/tex]

Summary the two equations

[tex](3x*3x^{2} )+(3x*4)+(2*3x^{2} )+(2*4)[/tex]

The correct expansion of [tex](3x+2)(3x^{2} +4)=(3x*3x^{2} )+(3x*4)+(2*3x^{2} )+(2*4)[/tex] (C)

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Let's see how the while loop functions for n = 2345. Inside the loop, the reversed number is calculated using the formula reverse = reverse * 10 + remainder. n. n != 0.

Given,

arr: [7, 234, 58100]

Expected Output:

7 + 432+ 18500 = 18939

Input:

arr: [0, 100, 220]

Expected Output:

0 + 100 + 220 = 320

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The area of ∆PQR is 42 [tex]cm^{2}[/tex]

We can use Heron's Formula to find the area of a triangle when we have the length of its three sides. Heron's Formula states that the area of a triangle with sides p, q, and r is:

Heron's Formula :

Area =[tex]\sqrt(s(s-p)(s-q)(s-r))[/tex]

where s is the semi-perimeter of the triangle (half of the perimeter).

In this case, we know that the perimeter of the triangle is 24 cm and p+q = 18 cm, and q+r = 14 cm. We can use these equations to find the length of the third side, r.

p+q+r = 24 cm

r = 24 - (p+q) = 24 - 18 = 6 cm

Now we can use this information to find the semi-perimeter of the triangle:

s = (24 cm) / 2 = 12 cm

Now we can substitute the values of p, q, r, and s into Heron's formula to find the area of the triangle:

Area = √(12 x (12-18) x (12-14) x (12-6))

Area = √(12 x (-6) x (-2) x 6)

Area = √(12 x (-12) x (-12))

Area = √(12 x 144)

Area = √(1728) = 42 [tex]cm^{2}[/tex]

Therefore, the area of ∆PQR is  42[tex]cm^{2}[/tex]

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The function's domain and range are [tex]$x \leq-2, f(x) \leq-8$[/tex]. a part of the job

[tex]$f(x)=-\frac{8}{6}(x+2)^2-8$[/tex] .

Domain of [tex]$-\frac{5}{6}(x+2)^2-8:\left[\begin{array}{cc}\text { Solution: } & -\infty < x < \infty \\ \text { Interval Notation: } & (-\infty, \infty)\end{array}\right]$[/tex]

Range of [tex]$-\frac{5}{6}(x+2)^2-8:\left[\begin{array}{cl}\text { Solution: } & f(x) \leq-8 \\ \text { Interval Notation: } & (-\infty,-8]\end{array}\right]$[/tex]

Axis points of interception [tex]\frac{-5}{6}(x+2)^2-8: \quad[/tex] Y Intercepts: [tex]$\left(0,-\frac{34}{3}\right)$[/tex]

Vertex of [tex]$-\frac{5}{6}(x+2)^2-8:$[/tex] Maximum (-2,-8)

A graph's inflection point is a location where the second derivative changes sign and is equal to 0 or undefined.

If [tex]$f^{\prime \prime}(x) > 0$[/tex] after which f(x) concave upward.

If [tex]$f^{\prime \prime}(x) < 0$[/tex] after which f(x) concave downward.

[tex]$f^{\prime \prime}(x)=-\frac{5}{3}$[/tex]

Therefore the correct answer is Domain [tex]$x \leq-2$[/tex] ,range  [tex]f(x) \leq-8$[/tex] .

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