a charged particle with a mass of m and a charge of q is injected midway between the plates of a capacitor that has a uniform electric field of e. what is the acceleration of this particle due to the electric field?

Answers

Answer 1

Eq/m is the particle's acceleration as a result of the electric field, as stated in the preceding sentence.

What is the principle behind a capacitor?

To hold energies in an electrical circuit, a capacitor is a device. The idea behind how a capacitor functions is that if a earthed conductor is moved close to a conductor, its capacitance increases noticeably. In light of this, a capacitor consists of two plates with equal and opposing charges that are spaced apart.

Force is also ma, and the force acting upon that charge is qE. Acceleration a may be calculated by setting qE = ma.

Consequently a = Eq/m

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Related Questions

a 0.5 kg block has an acceleration of 0.2 m/s^2 when a force is exerted on it. a second block has an acceleration of 0.1 m/s^2 when given the same force. what is the mass of the second block?

Answers

The second block weighs one kilogram.

What is mass?

A mass measurement reveals how much matter is there in an object.

Usually, the metric systems of grams, kilograms, and tonnes are used to compute it.

How do you determine it?

As we know that F = ma.

Considering that the force applied to the first block and the second block are equal.

The acceleration of the first block is 0.2 m/s^2 and the acceleration of the second block is 0.1 m/s^2, we can set up the following equation:

F = ma

where F is the force exerted on both blocks, m1 is the mass of the first block (0.5 kg), a1 is the acceleration of the first block (0.2 m/s^2), m2 is the mass of the second block, and a2 is the acceleration of the second block (0.1 m/s^2).

So substituting,

F = m1 * a1 = m2 * a2

Rearranging for m2

m2 = F / a2

m2 = (F / 0.1 m/s^2)

m2 = (F/0.1) = m1 * (a1/a2)

m2 = (0.5kg * (0.2/0.1)) = 1kg

So, the mass of the second block is 1 kg.

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Answer these please and explain. (100 points)



1.A piece of candy dropped from a tall building has gained a velocity of 52.6 m/s. how long has the candy been falling with an acceleration of 9.8m/s2?


2.An object traveling 200m/s slows down to 50 m/s in 5 seconds. calculate the acceleration of the object


3.a runner is accelerating at a rate of 30 m/s2 How fast will he be going 5 seconds after he starts?

Answers

Answer:

Explanation:

1.)  V = V₀ + at

52.6 m/s = 0 + (9.8 m/s²)t

t = (52.6 m/s)/(9.8 m/s²) = 5.37 s

2.) a = ΔV/Δt = (50 m/s - 200 m/s) / 5 s = -30 m/s²

3.)  V = V₀ + at

V = 0 + (30 m/s²)(5 s) = 150 m/s

This assumes he starts from rest. Also, no human can run 150 m/s.  Are you sure the given a is 30 m/s²? You may want to double check.

he centers of a 12 kg lead ball and a 70 g lead ball are separated by 14 cm. part a part complete what gravitational force does each exert on the other? express your answer using two significant figures. f

Answers

5.6 * 10⁻⁷N gravitational force will exert on both lead balls.

Given information:

mass of 1st ball(m₁) = 12kg

mass of 2nd ball (m₂) = 70g

distance between both balls (r)= 14cm

To find gravitational force

 F = Gm₁m₂/r²

    = 5.6 N

The force of attraction between any two bodies is directly proportional to the product of their millions and is equally proportional to the forecourt of the distance between them.

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a 2 kg block is moving at 3 m/sec. a 4.0 nt force is applied in the direction of motion and is then removed after the object has traveled an additional 5.0 m. the work done by this force is

Answers

The work done by this force is 20 J.

Initial velocity Vi =  3m/s

final velocity Vf^2=  Vi^2 +2as =  3^2 +2(2)(5) =29

Vf = 5.3m/s

Now we'll find the kinetic energy which is equal to the work done

K.E = m(Vf-Vi)^2/2

K.E = 2×(5.3-3)^2/2

K.E = 20 J

So the work done by this force is 20 J.

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Determine the average January sea level temperature at the following eight lettered points. A - 70 F B - 55 F C - 80 F D - 72 F E - 80 F F - 50 F G - 25 F

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The average January sea level temperature at points A, B, C, D, E, F, G, and H is 57.75 degrees Fahrenheit.

To find the average temperature of eight points, we added all the temperatures and divided them by the number of temperatures (8).

70 + 55 + 80 + 72 + 80 + 50 + 25 + 60 = 462

Then divide the sum of all temperatures by the number of temperatures (8) to find the average temperature: 462 / 8 = 57.75

So the average January sea level temperature at points A, B, C, D, E, F, G, and H is 57.75 degrees Fahrenheit.

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. (a) how fast must a 3000-kg elephant move to have the same kinetic energy as a 65.0-kg sprinter running at 10.0 m/s? (b) discuss how the larger energies needed for the movement of larger animals would relate to metabolic rates.

Answers

(a) We can find the kinetic energy of the sprinter by:

KE = 1/2 * 65.0 kg * (10.0 m/s)^2 = 3250 J

Then, we can use this same equation to find the speed of the elephant, but with its mass (3000 kg):

KE = 1/2 * 3000 kg * v^2 = 3250 J

Solving for v, we get: v = sqrt(3250 J / (1/2 * 3000 kg))

And the speed of the elephant would be around 4.19 m/s.

(b) In order for a larger animal to move, it requires more energy than a smaller animal because larger animals have more mass, and as a result, more energy is needed to accelerate and maintain their motion. This increased energy demand is met by an increase in the animal's metabolic rate.

How powerful is an elephant?

In strength, elephants are the strongest mammals and the strongest land animals. African elephants can weigh up to 6,350kg and they can carry up to 9,000kg, the weight of 130 adult humans.

What do you mean by kinetic energy?

Kinetic energy is a form of energy that an object or a particle has due to its motion. If work is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

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Angela has a bucket of mass 2 kg tied to a string. She places a drinking glass of mass 0.5 kg in the bucket. She spins the bucket in a vertical circle of radius 1.5 m. You want to find out how fast she must swing the bucket to keep the glass from falling out.
a. Draw the free-body diagram for the glass when it is at the top of the circle.
b. What is the equation for the net force on the glass at the top of the circle in terms of w, FN, m, v, and r?
c. The glass will fall out of the bucket if the normal force between the glass and bucket equals zero. How fast must she spin the bucket to prevent this from happening?
d. The string will break if the tension on it is more than 100 N. Over what range of speeds can she keep the glass in the bucket and prevent the string from breaking?

Answers

The velocity at which the bucket spins is 4.91m/s and the range of speeds is  between 4.91 m/s and 17.3 m/s.

a) The diagram is attached

b) FN - mg = m(v²/r)

c) v = 4.91 m/s

d) (4.91 < v < 17. 3 ) m/s

What is Net Force

a. The free-body diagram for the glass when it is at the top of the circle would show the glass being acted upon by several forces. At the top of the circle, the glass is subjected to its weight (mg) acting downward, the normal force (FN) exerted by the bucket on the glass, and the tension (T) in the string.

b. The net force on the glass at the top of the circle can be represented by the following equation:

FN - mg = m * a

FN - mg = m(v²/r)

where FN is the normal force, m is the mass of the glass, g is the acceleration due to gravity, and a is the acceleration of the glass.

c. To prevent the glass from falling out, the normal force between the glass and the bucket has to be greater than zero, meaning the tension force should be greater than the weight of the glass. So we can use the net force equation.

T = m (v² / r) + mg

T = (0.5 kg)(v² / 1.5 m) + (0.5 kg)(9.8 m/s^2)

T > 0

Solving for v we get:

v > √( 9.8*1.5 ) = 4.91 m/s

d. The tension on the string is given by the equation T = m(v²/r)

Therefore, tension on the string is greater than 100 N when v > √(100*1.5/0.5) = √(300) = 17.3 m/s

Therefore the range of speeds she can keep the glass in the bucket and prevent the string from breaking is between 4.91 m/s and 17.3 m/s.

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Three blocks are connected with each other by two light strings. The blocks have different masses m2 m3m1 The heaviest of the three blocks is placed on a frictionless table The system of three blocks is released from rest. What is the acceleration of block ma? A) (m2-ms- moim mama) B) (mums - m2)/(m mama) C) (ma-mulo/my.me .mg) D) (ma-ma-mulo/im.mpma) E) ( mma)/(m. mama)

Answers

The acceleration of block m1 is (ma-ma-mulo/im.mpma).

What is acceleration?

Acceleration is the rate at which an object's velocity with respect to time changes. It is a vector quantity to accelerate (in that they have magnitude and direction). The direction of the net force acting on an object determines the direction of its acceleration.

How to determine the acceleration of block m1?

The acceleration of block m1 (ma) can be determined by analyzing the net force acting on it, which is equal to the tension in the string connected to it, minus the weight of the block.

Tension in the string connected to m1 is equal to the tension in the string connected to m3, since the two strings are light and inelastic. Therefore, the net force acting on m1 is equal to T - m1g, where T is the tension in the string and g is the acceleration due to gravity.

The tension in the string is equal to the acceleration of m3, since

T = m3a. Therefore, the net force acting on m1 is equal to m3a - m1g.

m1 is connected to m2 and m3, so the acceleration of m1 is dependent on the masses of m1, m2 and m3.

Therefore, the acceleration of block m1 is (m3-m1-m2)/(m1+m2+m3) which corresponds to option D) (ma-ma-mulo/im.mpma).

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a sled weighing 100 n is held in place on a frictionless 20 degree slope a rope attached to a stake at the top. the rope is parallel to the slope. what is the tension in the rope? group of answer choices 34 n 37 n 94 n 47 n

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The tension in the rope is 37 N. the rope is parallel to the slope. what is the tension in the rope.

what is tension ?

Tension is an emotional and mental state that can occur in response to stress, anxiety, fear, or excitement. It is often experienced as a feeling of tightness in the chest and neck area and can be accompanied by physical symptoms such as increased heart rate, sweating, and shallow breathing.

Tension can be triggered by a variety of situations, including conflict, deadlines, public speaking, financial pressures, and changes in relationships. It can also be caused by physical conditions such as pain and fatigue, as well as by negative thoughts and feelings, including worry, fear, and anger.

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Four charges are arranged at the corners of a square, as depicted in the figure. The direction of the electric field at the center of the square due to the four charges at the corners, given that qa = qb = -3.3 μC and qc = qd = 3.3 μC . Calculate the magnitude of the electric field, in newtons per coulomb, at the center of the square (the location of q), given that the square is 4.5 cm on a side.

Answers

The magnitude of the electric field at the center of the square is 8.24 N/C.

What is coulomb?

The International System of Units uses the coulomb (C) as the basic unit of electric charge (SI).

It is the quantity of electrical energy that a 1-ampere (A) current can transport in a second (s). The electrical charge of around 6.24 x 1018 electrons or protons is equal to a quantity of 1 C.

The electric field at the center of the square due to the four charges at the corners will be the vector sum of the electric fields due to each of the charges. Since the charges are located at the corners of a square, the electric fields due to each charge will be oriented perpendicular to the line connecting the center of the square to the charge.

To calculate the magnitude of the electric field, we can use Coulomb's law:

E = k * (q / r^2)

Where k is Coulomb's constant, q is the charge, and r is the distance from the charge to the point where we are calculating the electric field.

The distance from the center of the square to each corner is (4.5 cm) / sqrt(2) = 3.225 cm.

E = 9 * 10^9 * ((3.3 * 10^-6) / (3.225 * 10^-2)^2)

E = 8.24 N/C

So, the magnitude of the electric field at the center of the square is 8.24 N/C.

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the small block shown in the figure above was released from rest at point o and slid down the track such that friction was considered to be negligible. the block reached point p with speed v1. between points o and p, what kind of work did the track do on the block, and why?

Answers

At point O, the little block in the previous diagram was set free from its state of rest and allowed to slide along the track with minimal friction.

What method may a learner use to calculate the total power of the chunk earth system from the graph?

How might a pupil interpret the graph to calculate the system's overall energy Use 12 mv2f where m=2 kg and vf=the object's final velocity as determined from the graph. An object of mass m can travel in any dimension in the xy plane without encountering any resistance when it is initially at rest.

When a youngster uses a swing, what kind of energy transformation takes place?

Potential energy is transformed into kinetic energy by swings,then repeatedly changing from potential energy to kinetic energy. The fast component of swinging is called kinetic energy, and it is the speed at which you run back and forth. The most powerful aspect of swinging is potential energy.

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A car starts moving from a full stop at a traffic light. The car covers a distance of 75 meters at an acceleration of 012 meters per second squared. What is the magnitude of the final velocity of the car?

Answers

Answer:

The final velocity of the car can be calculated using the equation:

v = u + at

where:

v = final velocity

u = initial velocity (since the car starts from a full stop, the initial velocity is 0)

a = acceleration (0.12 m/s^2)

t = time (unknown, but can be calculated using the distance and velocity)

To find the time, we can use the distance and velocity formula:

d = ut + (1/2)at^2

75 = 0 + (1/2)(0.12)(t^2)

t = sqrt(75/(1/2)(0.12))

t = sqrt(625/0.06)

t = sqrt(10416.67)

t = 102.41 seconds

Now we can substitute the values for u, a and t into the first equation to find the final velocity:

v = u + at

v = 0 + (0.12)(102.41)

v = 12.29 m/s

The magnitude of the final velocity of the car is 12.29 m/s.

Please help me solve this.
Use significant figures please.

Answers

Answer:

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a 10-kilogram mass rests on a horizontal frictionless table. how much energy is needed to accelerate the mass from rest to a speed of 5 meters per second?

Answers

125 joules of energy are required to accelerate a 10-kg mass from rest to a speed of 5 meters per second on a horizontal, frictionless surface.

Example of how mass affects acceleration.

When a specific force is applied, an object accelerates less slowly the more mass it has. For instance, the acceleration is halved for a given force when an object's mass is twice.

How do mass and speed relate?

The relationship between mass and acceleration is described by Newton's Second Law of Motion. According to his Second Law, the more mass an item has, the more force is required to accelerate it.

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if you pull the wagon's handle at 30 degrees and the wagon moves at a constant rate, how far can you pull the wagon?

Answers

If the rate of pulling the wagon is increased, then the distance will be shortened as the force will be too great for the coefficient of friction to handle.

What is distance?

Distance is the measure of how far apart two objects are or how long it would take to travel between them. It is typically measured in terms of length, such as kilometers, meters, miles, feet, yards, or other units of length. Though it can also be measured in terms of time, such as hours, minutes, or seconds. Distance can be calculated using a variety of methods, such as using a ruler, using a map, or using a GPS device. Distance can be used to describe both physical and abstract concepts, such as the distance between two people or the distance between two ideas.

The distance that a wagon can be pulled when its handle is pulled at a 30 degree angle depends on a variety of factors, such as the friction between the wagon and the surface it is being pulled on, the weight of the wagon and the force being applied to the handle. Generally speaking, a heavier wagon will require more force to move it the same distance as a lighter wagon when pulled at the same angle.

In order to determine the distance that a wagon can be pulled at a 30 degree angle, it is necessary to calculate the force being applied to the handle and the coefficient of friction between the wagon and the surface. Once these two values are known, it is possible to calculate the maximum distance that can be traveled by applying the equation distance = force * coefficient of friction * cosine (30 degrees).

It is important to note that the distance will only be the maximum distance that can be traveled if the wagon is being pulled at a constant rate. If the rate of pulling the wagon is increased, then the distance will be shortened as the force will be too great for the coefficient of friction to handle.

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A pendulum swings from -10 degrees to +10 degrees

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The range of the pendulum swing is 20 degrees, from -10 degrees to +10 degrees.

What is pendulum swing?

Pendulum swing is a phenomenon in which an object, suspended from a fixed point, swings back and forth in a regular rhythm. The pendulum is a simple mechanical system that has been used in clocks and other timepieces since the 16th century.

Pendulum swings are also used in amusement park rides and scientific experiments. A pendulum is usually made up of a mass, or bob, suspended from a string or wire, and is driven by gravity. As the pendulum swings, the force of gravity causes the bob to move in an arc, oscillating back and forth. The arc of the swing is determined by the length of the string, the mass of the bob, and the strength of the gravitational force pulling on it.

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Consider the case when the constant A=3 and the time constant =4. Plot the graph of y=3e^(-t/4). Make it a position versus time graph.

Answers

The graph of y=3e^(-t/4) is shown below: Position (y) on the vertical axis and time (t) on the horizontal axis.

What is horizontal axis?

The horizontal axis is a reference line on a graph that runs horizontally (left to right) and is used to plot data points. It is also known as the x-axis, and it typically represents the independent variables of a graph. The horizontal axis is used to visually display quantitative values, such as time, distance, or cost. When graphing a mathematical equation, the horizontal axis typically shows the real numbers that are being used in the equation.


The graph starts at y=3 when t=0 and then decreases in a curved line as time increases. This is because the exponent term is negative, so the entire function is decreasing as time increases. Specifically, the graph follows the shape of the exponential decay function e^(-t/4). As time increases, the value of y decreases exponentially, approaching 0 as t approaches infinity.
The formula for the graph is y = 3e^(-t/4)

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For some resistor applications, it is important to maintain a fixed value of resistance over a range of operating temperatures. Explain briefly how you could minimize variations (resulting from changes in temperature) in the resistivity of Si at temperatures near 300K. Assume that you are free to choose the value of resistivity.

Answers

The value of resistivity and conductivity are mentioned below.

What is resistivity ?

A conductor with a unit cross-sectional area and unit length and its electrical resistance. Resistivity, a distinctive quality of any material, is helpful in comparing different materials based on their capacity to conduct electric currents. Poor conductors are identified by high resistance.

What is conductivity ?

A substance or material that permits electricity to flow through it is referred to as an electrical conductor. When voltage is given to a conductor, electrical charge carriers, often electrons or ions, travel easily from atom to atom.

Part a is explained by using the concept of diffusion current density and Einstein's relation

from semiconductor we have

T mobility

V= μE

Drift velocity

I = ncAvl

J also equal to E

σE= nevd

σ= nevd/E

σ= neμ

resistivity is reciprocal of conductivity

S= 1/σ=1/neμ

from Einstein's equation

∫= KT/ ne²Dn

Therefore, value of resistivity and conductivity are mentioned below.

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a bungee jumper of mass 60 kg steps off a 40-m high cliff. it takes approximately 40 n to stretch the cord 1 meter. how close does the jumper get to the ground?

Answers

Assuming the bungee cord is perfectly elastic, the jumper will reach a minimum distance of 14.7 meters from the ground after the cord has stretched.

What is distance?

Distance is the amount of space between two objects or points. It is typically measured in units such as meters, feet, or miles. Distance can also be measured in a more abstract sense, such as the amount of time it takes for something to happen or the amount of effort required to complete a task.

Distance can also refer to the difference between two things, such as the difference between two people’s opinions on a particular topic. Distance can also refer to physical separation, such as the distance between two people who are in different countries or cities. Distance can also be used to express the size of something, such as how far a car can travel on a single tank of gas.

Given: m = mass of jumper = 60kg

            h = height of cliff = 40m

Also,

k = F/x = 40N/1m = 40N/m

Now, when jumper jumps,

F = m×g

= 60×9.8

= 588 N

Therefore,

x = (588N)/(40N/m) = 14.7m

Thus, jumper gets to a close of 14.7 meters to the ground.

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9. Show that the equation for the gravitational potential energy E
GMm is dimensionally
R
correct given that the units for the gravitational constant G are N.m².kg2, M and m are masses of
interacting objects and R is their separation distance.
- is dimensionally homogeneous.

Answers

G is the gravitational constant, M is the mass of the gravitating body, and r is the separation between their centers.

What does R stand for in the gravitational potential energy formula?The gravitational potential energy of mass m can be expressed generally as follows: where G is the gravitational constant, M is the mass of the gravitating body, and r is the separation between their centers.G.P.E can also be written as [M1 L0 T0] [M0 L1 T-2] [M0 L1 T0] = [M1 L2 T-2]. As a result, the dimensional representation of gravitational potential energy is [M1 L2 T-2].For potential energy close to the Earth's surface, a negative potential energy is consistent with mgh. The potential energy change for lifting an object h feet above the ground is given by: U = Uf - Ui = -GmM/(R+h) - (-GmM/R). when h is less than R in size.        

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Half of magnet 1 is blue, and half is green, but the poles are not marked. On magnet 2, the north and south poles are marked. If the blue side of magnet 1 is attracted to the north pole of magnet 2, what is true about magnet 1

Answers

If the blue side of magnet 1 is attracted to the north pole of magnet 2, then the blue side of is the south pole of magnet 1.

Magnet 1 is not labeled with its poles, so we cannot say for certain which pole is north and which is south. However, we know that opposite poles of magnets are attracted to each other.

Since the blue side of magnet 1 is attracted to the north pole of magnet 2, it can be inferred that the blue side of magnet 1 must be the south pole. This is because north and south poles are opposite, and if the blue side of magnet 1 is attracted to the north pole of magnet 2, it means that the green side is opposite to it, which means it is the north pole. In other words, the the green side of magnet 1 is the north pole and blue side of magnet 1 is the south pole.

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Your question seems incomplete, but I suppose the complete question was:

"Half of magnet 1 is blue, and half is green, but the poles are not marked. On magnet 2, the north and south poles are marked. If the blue side of magnet 1 is attracted to the north pole of magnet 2, what is true about magnet 1?

Magnet 1 has neither a north or south pole.

The blue side is the north pole of magnet 1.

The blue side is the south pole of magnet 1.

The green side is the south pole of magnet 1."

an object tends to rotate (spin) if it is pushed on by a force that is not aimed at the center of mass. how do athletes use this fact to initiate spins before they fly through the air, as in gymnastics, skating, and diving events?

Answers

Athletes use this fact to initiate spins by applying a force to the edge of their body, such as their hands or feet, which is not aimed at the center of mass.

This causes their body to rotate rapidly and spin around, giving them the momentum to fly through the air.

Gymnasts use this technique to spin around the high bar or the floor, figure skaters and ice dancers use it to spin around the ice, and divers use it to spin around the diving board before they enter the water.

What is force?

Force is an influence that causes an object to change its velocity or shape.

It can be a push or a pull, and it can be applied by an object, a person, or even gravity.

Force is measured in terms of mass and acceleration, and it is usually expressed in units of Newtons (N).

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determine the electric field inside a parallel plate capacitor in vacuum where one plate has a surface change density

Answers

The electric field inside a parallel plate capacitor in a vacuum can be determined using Coulomb's law and the surface charge density on one of the plates. If one plate has a surface charge density and the other plate is neutral, the electric field between the plates will be in the direction of the plate with the surface charge density.

How can one define an electric field?

The electric field can be defined as the electric force per unit charge. The direction of the field is assumed to be the direction of the force it would exert on a positive test charge. The electric field is radially outward from a positive charge and radially in toward a negative point charge.

Explain Coulomb's law.

According to Coulomb's law, the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

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in newton's second law, f = ma, the mass m is a gravitational mass.T/F

Answers

In Newton's second law, f = ma, the mass m is a gravitational mass is a true statement.

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In equation form this can be written as F = ma,

where,

F is the net force applied

m is the mass of the object

a is the acceleration of the object

This law explains that the larger the force applied, the greater the acceleration of the object.

Also, the larger the mass of the object, the lower the acceleration when the same force is applied to the object.

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what is the magnitude of the momentum |p⃗ a,i| of piece a before the explosion?

Answers

The magnitude of the momentum |p⃗ a,i| of piece a before the explosion is equal to the mass of the piece multiplied by its velocity.

What is the velocity?

Velocity is a physical quantity that describes the rate at which an object moves through space. A vector quantity it, meaning that its size and direction are both present.. Velocity is usually expressed as speed in a given direction, such as 10 meters per second (10 m/s) to the north. The average velocity of an object is its displacement divided by the elapsed time between the two points. Velocity is related to acceleration, which is the rate at which an object changes its velocity over time.

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in another solar system is planet driff, which has 5 times the mass of the earth and also 5 times the radius, how does teh grativtaional accelration on the surface of driff compare to the gravitaitonal accelration for earth

Answers

The gravitational acceleration on the surface of Drift compare to the gravitational acceleration on the surface of the earth is  1/5th.

In physics, gravitational acceleration refers to the speed at which a body falls freely in a vacuum (and thus without experiencing drag). This is the constant acceleration brought on just by the gravitational pull.

In physics, the term "gravitational acceleration" (symbolized "g") is used to describe the strength of a gravitational field. It is measured in m/s2, or meters per second squared. At the earth's surface, 1 g is equivalent to 9.8 m/s 2.

Given,

[tex]M x_{D} = 5Mx_{E} \\R D = 5RE[/tex]

The gravitational acceleration on the surface of planet Drift -

[tex]gD= \frac{GMD}{ (rD)^{2} }[/tex]                                   (1)

The gravitational acceleration on the surface of planet Earth -

[tex]g E= \frac{GM E}{ (rE)^{2} }[/tex]                                    (2)

Divide equation (1) by (2) and we get:

[tex]\frac{gD}{gE} = \frac{ \frac{GMD}{ (rD)^{2} }}{ \frac{GM E}{ (rE)^{2} }}[/tex]

[tex]\frac{gD}{gE} = \frac{M D}{M E} (\frac{r E}{r D})^{2}[/tex]

[tex]g D = g E (\frac{M D}{M E} ) (\frac{e E}{r D} )^{2}[/tex]

Substitute all the known values in the above equation to determine the value of gD

[tex]g D = g E (\frac{5 M E}{M E} ) (\frac{R E}{5 R E} )^{2}[/tex]

[tex]= g E (5) (\frac{1}{5} )^{2}[/tex]

= [tex]\frac{g E }{5}[/tex]

Hence, the gravitational acceleration on the surface of Driff compare to the gravitational acceleration on the surface of the earth is 1/5th.

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1.60 the kinematic viscosity and specific gravity of a liquid are and 0.79, respectively. what is the dynamic viscosity of the liquid in si units? 1.61 a liquid has

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The dynamic viscosity of the liquid is 0.277Ns if the kinematic viscosity and specific gravity of a liquid are and 0.79, respectively.

Given the kinematic viscosity of a liquid = 3.5 x 10^-4 m^2/s

The  specific gravity of a liquid  = 0.79

A conversion between kinematic and dynamic viscosity measurements can be made using density.

We know that, Specific gravity = density of liquid/density of water

The density of water = 1000kg/m^3

The density of liquid = 0.79 x 1000 = 790kg/m^3

Kinematic viscosity x liquid density = dynamic viscosity.

Dynamic viscosity = 3.5 x 10^-4 x 790 = 0.2765Ns

Hence the required dynamic viscosity of the liquid is 0.277Ns.

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complete question: The kinematic viscosity and specific gravity of a liquid are 3.5 x 10^-4 m^2/s and 0.79, respectively. What is the dynamic viscosity of the liquid in SI units?

what effect will change in a wind direction have upon maintaining a 3 degree glideslope at a constant true airspeed

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When ground speed increases, rate of descent must increase.

What is Speed ?

One such measurable metric is speed, which calculates the ratio between the distance an object travels and the time needed to cover that distance. Let's explore speed in-depth in this session.

Speedometers are used to measure speed in moving vehicles. Odometers are used to calculate the distance travelled. A graph can be used to calculate speed as well. The distance-time graph aids in comprehending an object's speed.

The distance travelled in relation to the time it took to travel that distance is how speed is defined. As speed only has direction and magnitude, it is a scalar quantity.

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When ground speed increases, the rate of descent also increases.

What is speed?

Speed is a scalar quantity that represents the rate of change of an object's position with respect to time. It is typically measured in units of distance per time, such as meters per second or miles per hour. Speed can also be represented as velocity, which is a vector quantity that includes both the magnitude of the speed and the direction of motion.Thus, the metre per second (m/s) is the SI unit of speed.

A change in wind direction can have a significant effect on maintaining a 3 degree glideslope at a constant true airspeed because it can affect the aircraft's ground speed and rate of descent.

If the wind direction changes such that it is now blowing from the front, it can cause a headwind component that will decrease the ground speed and increase the rate of descent. The pilot will have to reduce the thrust in order to maintain the constant true airspeed and the 3 degree glideslope.

If the wind direction changes such that it is now blowing from the rear, it can cause a tailwind component that will increase the ground speed and decrease the rate of descent. The pilot will have to increase the thrust in order to maintain the constant true airspeed and the 3 degree glideslope.

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a 2 uc point charge and a 4 uc point charge are a distance l apart. where should a thurd point charge be placed so that the electrical force on that thurd charge is zero?

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This will create a system of three equal-sized point charges, and since the forces between point charges are equal and opposite, the forces on the third charge will cancel each other out and there will be no net force.

What is the charge ?

The charge is the amount of money that a person is asked to pay in exchange for goods or services. Charges can be in the form of a fixed price, a fee based on time spent or a percentage of the total cost. Charges may also be based on the complexity or difficulty of the job. Payment can be in the form of cash, check or credit card. Charges are typically due at the time of service, unless other arrangements have been made in advance.

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(1 point) At a point P in the xy-plane where distances are measured in feet, the unit tangent vector to an object's path is Jo(-3, 1), the curvature of its path at P is 0.8 feet-1, and its acceleration vector is (4,5) feet/second". (a) At what rate is the object speeding up at P? sqrt(25+16) ft/s^2 Include units on your answer. (b) What is the object's speed at P? sqrt(10) ft/s Include units on your answer.

Answers

a) The rate at which the object is speeding up at P can be found by taking the dot product of the acceleration vector and the unit tangent vector.

(4,5) · Jo(-3,1) = 4*(-3) + 5*1 = -12+5 = -7 ft/s^2

The rate of change of speed at P is -7 ft/s^2.

b) The object's speed at P can be found using the formula for curvature and speed:

Speed = Curvature * radius

In this case, the curvature is 0.8 ft^-1 and the radius is not given, so we can't find the exact speed of the object, however, we can use the relation between the curvature and the acceleration vector.

Acceleration vector = curvature * Speed * Unit Tangent vector

√(4^2 + 5^2) = √(25+16) = √(41) = sqrt(41) = 6.4 ft/s

The object's speed at P is 6.4 ft/s.

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