Answer:
3ohms
Explanation:
From Ohm's Law
V = IR
V is that voltage = 3volts
I = current = 1amp
R = resistance in ohms
Putting those values into the above formula.
3volts = 1amp×R
Making R the subject
R = 3/1
R = 3ohms
The resistance of the light bulb is 3ohms.
A squeeze bottle squeezes when pressed. It regains its shape when pressed .It regains its shape when the pressure from your hand is withdrawn. What may happen if the squeeze bottle is pressed to take the sauce out and then immediately corked tightly? Will it regain its shape? If not, Why?
Answer:
The squeeze will not regain its shape
Explanation:
The squeeze bottle will not regain its shape.
This is because the atmospheric pressure compresses the squeeze bottle. Since the pressure in the squeeze bottle is now not equal to the atmospheric pressure since it has been corked tightly, its internal pressure cannot balance out the atmospheric pressure and thus cancel its effect.
So, the squeeze bottle does not regain its shape due to this imbalance of pressure.
the cylinder of gravity of cylinder is where
Explanation:
In uniform gravity it is the same as the centre of mass. For regular shaped bodies it lies at the centre of the that particular body. Hence for a cylinder centre of gravity lies at the midpoint of the axis of the cylinder.
Explanation:
We developed a spherical harmonic series that represents the gravitational potential and its gravity field due to a buried right vertical cylinder. This series can be used at far- and intermediate-regions, and is fast and accurate, using only a few terms. We compared the values of the fields acquired by this new spherical harmonic series, with ones computed by direct numerical integrations, using a fine-mesh structure for a vertical cylinder. Results of the calculations are shown and performances of the two different methods are compared. Faithfulness of the spherical harmonic series is tested with an inversion example.
The mass of an object is 50 kg. If its weight is 600N on a certain planet. Calculate the
gravitational field strength of the planet.,
Answer: The answer is 700kg
Explanation:
1. A Force of 50N acts uniformly over and at night angles to a surface. When
the area of the surface is 5m2, then the pressure on the area is:
A. 250Pa
B. 10Pa
C. 45Pa
D. 55Pa
Answer:
The answer would be 10 pascal.
Answer:
B. 10Pa
Explanation:
A soccer player kicks a ball with an initial velocity of 10m/s at an angle of 30 degrees above the horizontal. Find the; a) magnitude of the horizontal component b) Vertical component c) The magnitude of the vector.
Answer:
a) V₀ₓ = 8.66 m/s
b) V₀y = 5 m/s
c) Magnitude of velocity vector = 10 m/s
Explanation:
a)
The magnitude of the horizontal component of launch velocity can easily be given by the following formula:
V₀ₓ = V₀ Cos θ
where,
V₀ₓ = horizontal component of velocity = ?
V₀ = Launch Velocity = 10 m/s
θ = Launch Angle of the ball with the horizontal = 30°
Therefore,
V₀ₓ = (10 m/s)(Cos 30°)
V₀ₓ = 8.66 m/s
b)
The magnitude of the vertical component of launch velocity can easily be given by the following formula:
V₀y = V₀ Sin θ
where,
V₀y = vertical component of velocity = ?
V₀ = Launch Velocity = 10 m/s
θ = Launch Angle of the ball with the horizontal = 30°
Therefore,
V₀y = (10 m/s)(Sin 30°)
V₀y = 5 m/s
c)
The magnitude of the velocity vector will be equal to the resultant velocity or net velocity, which is 10 m/s.
Magnitude of Velocity Vector = 10 m/s
