A class is made up 15 girls and 12 boys. If a group is made up 3 girls and 3 boys, then how many groups can be created?

this is a COUNTING PRINCIPLE problem :")

Answer:

Slope = 3/2

y-intercept = -4

x  |  y

0  -4

2   -1

Step-by-step explanation:

Answer:

the anser od 20(d-4)+4d is5

If they together at the same rate for the same amount of time, they will solve 48 math problems,

From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:

In order to determine the number of problems for 3 mathletes, this is expressed as:

DIvide both expressions:

Cross multiply

2x = 3* 32

x = 3 * 16

x = 48math problems

Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,

Learn more on proportion here: https://brainly.com/question/1496357

Answer:

$2.5/game

Step-by-step explanation:

To find Slope, Change of rate

find two points on the graph

I selected : (4,14) and (8, 24)

Slope: y2-y1/x2-x1

24-14/8-4

10/4

5/2

=2.5

so the rate of change is $2.5/game

Answer:

y=1.25x+5

Step-by-step explanation:

Answer:

A) .9423

Step-by-step explanation:

The chance of getting at most 13 heads is 0.9423

[tex]4(2x-11) \leq -12 +2(x-4)\\\\\implies 8x - 44 \leq -12 + 2x -8\\\\\implies 8x -44 \leq 2x -20\\\\\implies 4x - 22 \leq x - 10~~~~~~~~~~~~~~~~~~~;[\text{Dividing both sides by 2}]\\\\\implies 4x -22 +22 \leq x -10 +22~~~~~~;[\text{Adding 22 to both sides}]\\\\\implies 4x \leq x+12\\\\\implies 4x -x \leq x+12-x~~~~~~~~~~~~~~~~;[\text{Subtracting x from both sides}]\\\\\implies 3x \leq 12\\\\\implies x \leq 4 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;[\text{Dividing both sides by 3}][/tex]

[tex]\text{Interval solution,} ~(-\infty, 4][/tex]

Answer:

its c

Step-by-step explanation:

Answer:

Step-by-step explanation:

3

+

1

−

1

=

1

0

−

1

3

=

9

3

3

=

9

3

=

3   answer

Answer:

0.024

Step-by-step explanation:

75, 15, 3, ...

Now, let's take a look at thus pattern.

You'll notice how the numbers decrease.

Divide 75 by 5.

We get 15

Divide 15 by 5.

We get 3.

Then we have the pattern now.

3 ÷ 5 = 0.6 (4th term)

0.6 ÷ 5 = 0.12 (5th term)

0 12 ÷ 5 = 0.024 (6th term)

I hope it helps.

Answer:

B) 26%

Step-by-step explanation:

The yellow part of the graph represents Rock, which is 15%, and the red part of the graph represents Classical. So, you simply add them together.

Answer:

B) 26%.

Step-by-step explanation:

Find the Rock percentage in the chart. (15%)

Find the Classical percentage in the chart. (11%)

Add the Rock and Classical percentages together. (26%)

Answer:

[tex]x=-9\pm6i[/tex]

Step-by-step explanation:

[tex]6x^2+108x+707=5[/tex]

[tex]6x^2+108x+702=0[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-108\pm\sqrt{(108)^2-4(6)(702)}}{2(6)}[/tex]

[tex]x=\frac{-108\pm\sqrt{-5184}}{12}[/tex]

[tex]x=\frac{-108\pm72i}{12}[/tex]

[tex]x=-9\pm6i[/tex]

15*X/100=12

15x=1200

X=1200/15

x=80

See attachment for answer and math work.

The angles, 60°, [tex]\displaystyle \frac{\pi}{4}[/tex] and [tex]\displaystyle \frac{\pi}{6}[/tex] are special angles that have known trigonometric ratio values.

First part;

Second part;

Third part;

Reasons:

First Part;

Considering a unit circle with the center at the origin of the graph, we have;

The sine of the angle, θ, rotated by the radius is the vertical distance of a point P on the circle which is the location of the radius, from the horizontal axis.

The cosine of the angle, θ, is the horizontal distance of P from the vertical axis, such that we have;

The coordinates of point P = (cos(θ), sin(θ))

In the four quadrant, we have;

First Quadrant; All trigonometric ratios are positive

Second Quadrant; sine is positive

Third Quadrant; Tan is positive

Fourth Quadrant; Cosine is positive

Second part;

We have; At 120°, the point P is the same elevation from the horizontal axis, therefore;

sin(60°) = sin(120°) = 0.5·√3

However, the x-coordinate of the point P is in the negative direction, therefore, we get;

cos(120°) = -cos(60°) = -0.5

Similarly from the quadrant relationship, we have;

240° is in the third quadrant, and it is 60° below the negative horizontal line, therefore;

sin(240°) = -sin(60°) = -0.5·√3

cos(240°) = -cos(60°) = -0.5

300° is in the fourth quadrant, and it is 60° below the positive x-axis, therefore;

sin(300°) is negative and cos(300°) is positive

Which gives;

sin(300°) = -sin(60°) =  -0.5·√3

cos(300°) =  cos(60°) = 0.5

Third part;

[tex]\displaystyle \frac{\pi}{4} =45^{\circ}[/tex]

[tex]\displaystyle \frac{\pi}{6} =30^{\circ}[/tex]

The sine and cosine of 45° can be used to find the sine and cosine of (180° + 45°) = 225°, (360° - 45°) = 315°

Also, due to the mid location of the angle 45° on the quadrant, we have;

Another angles is the sines and cosine of (90° + 45°) = 135°

Therefore, [tex]\displaystyle \frac{\pi}{4}[/tex], can be used to find the sine and cosine of 135°, 225°, and 315°

[tex]\displaystyle 135^{\circ} = \mathbf{\frac{3 \cdot \pi}{4}}[/tex], [tex]\displaystyle 225^{\circ} = \frac{5 \cdot \pi}{4}[/tex], [tex]\displaystyle 315^{\circ} = \frac{7 \cdot \pi}{4}[/tex]

Therefore,

[tex]\displaystyle \frac{\pi}{4}[/tex] can be used to find the sine and cosine of [tex]\displaystyle \mathbf{\frac{3 \cdot \pi}{4}}[/tex], [tex]\displaystyle \mathbf{\frac{5 \cdot \pi}{4}}[/tex], and [tex]\displaystyle \mathbf{ \frac{7 \cdot \pi}{4}}[/tex]

Similarly, the sine and cosine of, [tex]\displaystyle \frac{\pi}{6}[/tex]  = 30° can be used to find the sine and cosine of 150°,  210°, and 330°.

[tex]\displaystyle 150^{\circ} = \frac{5 \cdot \pi}{6}[/tex], [tex]\displaystyle 210^{\circ} = \frac{7 \cdot \pi}{6}[/tex], and [tex]\displaystyle 330^{\circ} = \frac{11 \cdot \pi}{6}[/tex]

[tex]\displaystyle \frac{\pi}{6}[/tex], can be used to find the sine and cosine of [tex]\displaystyle \mathbf{ \frac{5 \cdot \pi}{6}}[/tex], [tex]\displaystyle \mathbf{ \frac{7 \cdot \pi}{6}}[/tex], and [tex]\displaystyle \mathbf{\frac{11 \cdot \pi}{6}}[/tex]

Learn more about the sine and cosine of angles here:

https://brainly.com/question/4372174

Answer:

Step-by-step explanation:

The cosine value of an angle is the x coordinate of the point the angle corresponds to on the unit circle, and the sine value of an angle is the y coordinate of that point. 120, 240, and 300 all form 60 degree reference angles which in turn forms 30-60-90 triangles which help to find the sine and cosine of these corresponding angles. Pi/4 radians converts to 45 degrees which forms a 45-45-90 special triangle on the unit circle which has its own known trigonometric ratio. Pi/6 radians converts to 30 degrees which forms a 30-60-90 triangle on the unit circle which also has a known trigonometric ratio. These ratios help find the sine and cosine of the angles on the unit circle which corresponds to a point on the coordinate plane.

Answer:

This is what i got

Answer:

x=-8/3

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

∠ ABC = 90° ( angle in a semicircle )

Using the cosine ratio in right triangle ABC and the exact value

cos30° = [tex]\frac{\sqrt{3} }{2}[/tex] , then

cos30° = [tex]\frac{adjacent }{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{10}{AC}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )

AC × [tex]\sqrt{3}[/tex] = 20 ( divide both sides by [tex]\sqrt{3}[/tex] )

AC = [tex]\frac{20}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ( rationalising denominator )

AC = [tex]\frac{20\sqrt{3} }{3}[/tex]

radius AO = [tex]\frac{1}{2}[/tex] AC = [tex]\frac{1}{2}[/tex] × [tex]\frac{20\sqrt{3} }{3}[/tex] = [tex]\frac{10\sqrt{3} }{3}[/tex] → C

Answer:

Step-by-step explanation:

The answer is "Impossible to solve" , because there is no rule for function at point x = 7 . The given function has domain ( - ∞ , 2 ) ∪ { 2 } ∪ ( 2 , 7 ) ⇒ 7 is not a part of domain!!!

Answer:

  4.21747×10^-5

Step-by-step explanation:

Your calculator can do the division for you. The ratio is about 4.21747×10^-5.

__

This is approximately 10/237109.

Answer:

OK so a triangle has 3 sides and the perimeter around it is 20.6 cm to find the unknown for the length of a side it would be 20.6 ÷3 which is = to 6.86 to 2 decimal places

Step-by-step explanation:

20.6÷3

= 6.86 cm to 2 dp

It would be √2 x n - 5 = 10.

Julian factored the expression of 2x^4 + 2x³ - x²- x, the step 2 ( x (2x² (x + 1)) - 1(x − 1)) is wrong statement.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We have been given an expression as;

2[tex]x^{4}[/tex] + 2x³ - x²- x

Step 1;

x(2x³ + 2x²- x − 1)

Step 2;

x (2x² (x + 1)) - 1(x − 1)

Step 3;

x²(2x²-1) (x + 1)(x - 1)

Hence, Julian incorrectly factored -1 from the second group of terms.

we can write the correct factored as;

x (2x²- 1))(x + 1)

Therefore, Julian factored the expression of 2[tex]x^{4}[/tex] + 2x³ - x²- x, the step 2 ( x (2x² (x + 1)) - 1(x − 1)) is wrong statement.

To know more about an expression follow;

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x/2 = -0.73

To solve for x multiply both sides by 2:

x = -1.46

Answer:

Andre has 4 pounds of Broccoli and 6 pounds of Zucchini.

Step-by-step explanation:

Answer:

A and C

Step-by-step explanation:

6 pounds of Zucchini, and 4 pounds of broccoli equals to $17 and 2 pounds of Zucchini, and 7 pounds of broccoli equals to $17. Hope this helps.

Answer:

true

Step-by-step explanation:

Line l and line m are parallel to each other which means the statement is true.

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

The statement is True !

In the given figure, the two lines are parallel to one another ~ because pair of corresponding angles are equal.

Area =[tex]\pi r^{2}[/tex]

The diameter is double the length of the radius

7 ÷ 2 = 3.5

3.5 × 3.5 = 12.25

[tex]12.25\pi[/tex] = 38.4845100064751

38.4845100064751 rounded to the nearest tenth is 38.5

Answer:

A = 38.5 sq meters

Step-by-step explanation:

A = πr²

since diameter is 7, then radius is 7/2

A = π(7/2)²

A = 38.48

A = 38.5 rounded to nearest tenth

Answer:

to confusing

Step-by-step explanation:

Answer:

The nightly rate at Stargazer Suites is $25 more than the nightly rate at Retro Retreat.

Step-by-step explanation: