Given the egg has hatched, the egg was kept warmer than room temperature.
Given:Cool Room temperature Warm Total
Hatched 5 16 21 42
Unhatched 18 10 4 32
Total 23 26 25 74
To fill the blank we need to analyse the temperature carefully if see the table then cool hatched eggs are 5 , unhatched cool eggs are 18, eggs on room temperature and hatched are 16, eggs on room temperature and unhatched are 10, warm hatched eggs are 21 and warm unhatched eggs
So we can notice that hatched eggs are more in room temperature.
Hence hatched eggs are more in room temperature.
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Answer:
Given the egg has hatched the egg was kept warmer than room temperature.
Hope this helped!
3x-1=2(x+34) in inches=feet. inches
Answer:
-69
Step-by-step explanation:
inches:-69
-5 9/12 (-5 3/4 clearer) feet
Explanation in detail:
Write the equation down and distribute it.
3x - 1 = 2(x + 34)
3x - 1 = 2x + 68
Remove the variable on one side first (it makes solving the equation less complicated.)
3x - 1 = 2x + 68
-3x -3x
-1 = -x + 68
On all sides, subtract 68.
-1 = -x + 68
-68 -68
-69 = x
I'm guessing the answer in feet and inches is...
inches:-69
-5 9/12 (-5 3/4 simplified) feet
The mass of a box of bolts is 3/4 kg and the mass of a box of screws is 3/5 kg.
a Which box has the greater mass?
b Calculate the difference in mass between the 2 boxes.
Answer:
a) The mass of a box of bolts is greater.
b) 3/20 kg
Step-by-step explanation:
a) Firstly, you have to make the denominators of the two fractions the same (by finding the LCM of the denominators).
The LCM of 4 and 5 is 20.
Converting 3/4 into denominator 20:
[tex]\frac{3 * 5}{4 * 5}[/tex]
= 15/20
Converting 3/5 into denominator 20:
[tex]\frac{3 * 4}{5 * 4}[/tex]
= 12/20
Now comparing the numerators:
15 > 12
Hence,
3/4 > 3/5
b) Difference of the boxes can be done by subtracting the numbers with the same denominator:
15/20 - 12/20
= 3/20 kg
Hope this helps and feel free to give me brainliest! :)
Point G is on line segment FH. Given FH=4x+8,FH=4x+8, FG=x,FG=x, and GH=5x,GH=5x, determine the numerical length of \overline{GH}. GH .
The numerical length of GH is 20.
Given, FH=4x+8, FG=x and GH=5x.
We need to determine the numerical length of GH.
What is a line segment?In geometry, a line segment is a part of a line that is bounded by two distinct end points and contains every point on the line that is between its endpoints.
Given Point G is on the line segment FH, then FG + GH = FH.
Now, substitute the given values into the formula as shown:
x + 5x = 4x + 8
6x = 4x + 8
6x - 4x = 8
2x = 8
x=4
To get the length of GH substitute x=4 for 5x
That is, GH = 5(4)= 20
Hence, the numerical length of GH is 20.
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Step 1: We know that Angle A B C Is-congruent-to Angle F G H because all right angles are congruent. Step 2: We know that Angle B A C Is-congruent-to Angle G F H because corresponding angles of parallel lines are congruent. Step 3: We know that Line segment B C is-congruent-to line segment G H because it is given. Step 4: Triangle A B C Is-congruent-to Triangle F G H because of the
Triangles FGH and ABC are congruent because of the: AAS congruence theorem.
What is the AAS Congruence Theorem?
The AAS congruence theorem states that when two angles and one non-included side in one triangle are congruent to corresponding two angles and one non-included side in another triangle, then both triangles are congruent.
In the proof given, it is established that both triangles have two corresponding congruent angles, and also, BC ≅ GH which are non-included sides.
Therefore, both triangles are congruent because of the AAS congruence theorem.
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Which of the graphs below represents the equation 4x + y =7?
Answer:
Graph C
Step-by-step explanation:
Rearrange the terms so the equation is in slope-intercept form:
4x + y = 7
y = -4x + 7
The slope is -4, and the only graph that has a slope of -4 is graph C.
The graphs below are both absolute value functions. The equation of the red
graph is f(x) = xl. Which of these is the equation of the blue graph, g(x)?
a. g(x)=|x-2|
b.g(x)=|x+2|
c. g(x)=1/2|x|
d. g(x)=2|x|
Answer:
c
Step-by-step explanation:
please help asap Part of the proceeds from a garage sale was $540 worth of $5 and $20 bills If there were 3 more bills $5 bills than $20 bills, find the number of each denomination.
Answer:
15 ($20 dollar bills) and 19 ($10 dollar bills) ! Pretty sure this is correct, if wrong let me know and i'll make a question for you to give your points back, i dont know if i can do that but i can try!! Have a good day.
PLEASE ANSWER ASAP!!!!!!
What is the component form of the vector represented by 2a when a⃗ =<−2,3>?
Enter the answer in the boxes.
2a= <__,__>
The complete question is
"What is the component form of the vector represented by 2a when a =⟨−2,3⟩?"
The Component form of the vector represented by 2a is (-4,6)
What is the component form of a vector?The component form of a vector is represented by (x, y) that has gone x units left to the origin and y units up from the origin.
Given, a=(-2,3)
By using scalar multiplication,
2a = (2(-2), 2(3))
2a = (-4,6).
Therefore the component form of 2a=(-4,6)
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Which figures are polygons?
x
Figure A
Select each correct answer.
Figure B
O Figure A
O Figure B
O
Figure C
O
Figure D
Figure C
Figure D
Answer:
The answer is figure A, B, C, D.
Step-by-step explanation:
Because, polygon means a shape with more then 1 side, and in your pic all of the figures have more than one side, so that's the answer.
Considering the activity series given below for metals and nonmetals, which reaction will occur? al > mn > zn > cr > fe > cd > co > ni > sn > pb > h > sb > bi > cu > ag > pd >hg > pt f > cl > br > i 2nabr i2 right arrow. 2nai br2 2fe al2o3 right arrow. 2al fe2o3 2agno3 ni right arrow. ni(no3)2 2ag pb zn(c2h3o2)2 right arrow. zn pb(c2h3o2)2
The activity series is an arrangement of species in order of reactivity.
What is the activity series?The activity series is an arrangement of species in order of reactivity. The position of a specie in the series determines the possibility of certain reactions.
The following are the fates of these reactions;
2NaBr + I2--------->2NaI + Br2 - Not possible2Fe + Al2O3 ----------> 2Al + Fe2O3 - Not possible2AgNO3 + Ni ----------> Ni(NO3)2 + 2Ag - possiblePb + Zn(C2H3O2)2 ----------> Zn + Pb(C2H3O2)2 - Not possibleLearn more about activity series:https://brainly.com/question/18080147
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LCM of 18 , 25 , 35, 40 ,80 81 , and 72
Answer:
the LCM of 18 25 40 80 81 and 72 is 226800
i hope this helps you
Step-by-step explanation:
by which method
prime factorization , division or defination method
consider the series 1/4 1/16 1/64 1/256 which expression defines sn
This is a geometric progression
Common ratio=1/16÷1/4 =1/4first term =a=1/4So
The general formUla is
[tex]\\ \rm\Rrightarrow a(n)=ar^{n-1}[/tex]
[tex]\\ \rm\Rrightarrow a(n)=\dfrac{1}{4}\left(\dfrac{1}{4}\right)^{n-1}[/tex]
Answer:
[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]
Step-by-step explanation:
Series: the sum of the elements of a sequence.
Therefore, as the numbers have been defined as a series and we need to find [tex]S_n[/tex]:
[tex]\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{1}{64}+\dfrac{1}{256}+...[/tex]
First determine if the sequence is arithmetic or geometric.
If it is an arithmetic sequence, there will be a common difference between consecutive terms.
if it is a geometric sequence, there will be a common ratio between consecutive terms.
From inspection of the terms, we can see that there is a common ratio of 1/4, as each term is the previous term multiplied by 1/4, so it is a geometric series.
Sum of the first n terms of a geometric series:
[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]
Given:
[tex]a=\dfrac{1}{4}[/tex]
[tex]r=\dfrac{1}{4}[/tex]
Substitute the values of a and r into the formula:
[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{1-\frac{1}{4}}[/tex]
[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{\frac{3}{4}}[/tex]
[tex]\implies S_n=\dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]
Therefore:
[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]
If f(x) = 2x^2+3 and g(x)= 5x, evaluate the following: a. f(g(x)) b. g(g(3)) c. g(f(-2))
Answer:
A = 50x^2+3
B = 75
C = 55
Step-by-step explanation:
[tex]f(x)=2x^2+3\\g(x)=5x[/tex]
A. f(g(x))
[tex]2(5x)^2+3\\2(25x^2)+3\\=50x^2+3[/tex]
B. g(g(3))
[tex]5(5(3))\\5(15)\\=75[/tex]
C. g(f(-2))
[tex]g(2(-2)^2+3)\\g(8+3)\\g(11)\\5(11)\\=55[/tex]
A regular polygon is drawn in a circle so that each vertex is on the circle and is connected to the center by a radius. Each of the central angles has a measure of 40°. How many sides does the polygon have?
8
9
10
12
Answer:
9
Step-by-step explanation:
Find the slope of the line that goes through (2, 8) and (5, 13).
Answer:
1 (2/3) or 1.66666667
Step-by-step explanation:
The slope of a line is found by using the equation :
y2 - y 1 / x2 - x1
So all we have to do is plug in our values given.
To find which belongs with which variable (such as x2 or y1), we do the following:
We know that the coordinates of a point are represented by (x, y). So we must assign a number to each points number.
(2, 8) will be x1 and y1.
(5, 13) will be x2 and y2
Plug in the values :
13 - 8 = 5
5 - 2 = 3
5 / 3 = 1 (2/3)
So, the slope of the line is 1.66666667 or 1 and (2/3)s
Hey can I have some help with this. Just the answer is fine
Step-by-step explanation:
4.500 mm³ → cm³
1 cm³ = 1.000 mm³
= 4.500 ÷ 1.000
= 4,5 cm³ IS THE ANSWER
B varies inversely with c. when b is 2, c is 8. find the value of c when b is 5.
Answer:
3.2
The value of C when B is 5 is 3.2
Step-by-step explanation:
Match each expression with its value 2,-9,-1, or undefined
G(-0.0001)
G(0)
G(0.0001)
G(9)
By looking at the graph of the piecewise function, we can see that:
G(-0.001) = -9G(0) = -1G(0.0001) = -1G(9) is not defined.How to evaluate the piecewise function?
On the graph, we have a piecewise function, which we want to evaluate in some different values.
First we have x = -0.0001
This value belongs to the interval (-5, 0), and by looking at the graph, you can see that the function on that interval is equal to -9, then:
G(-0.0001) = -9
x = 0
x = 0 belongs to the interval [0, 9). On that interval the function values -1. (x = 0 belongs to that interval because we have a closed dot). Then we conclude
G(0) = -1
x = 0.0001
This value also belongs to the interval [0, 9)
Then G(0.0001) = -1
Finally, x = 9.
If you look at the domain of the function, you can see that there is an open dot at x = 9.
This means that x = 9 does not belong to that domain, so:
G(9) is not defined.
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Sven makes bread rolls, he uses rye flour and wheat flour to the ratio 2:3. sven makes bread rolls using 250 g of rye flour, what mass of wheat flour does he use
Factor the expression below.
36x² - 49
A. (6x + 7)(6x - 7)
B. (4x-7)(9x - 7)
C. (4x+7) (9x-7)
D. (6x-7)(6x-7)
Answer:
A. (6x + 7)(6x - 7)
Step-by-step explanation:
use difference of squares, which says a^2 - b^2 =(a+b)(a-b)
take the square roots of the two numbers, 6x and 7, and use them as a and b
Does someone mind helping out with this ?
please help me solve this HCF
Answer:
(x+y)
Step-by-step explanation:
[tex] {x}^{2} - {y}^{2} = (x + y)(x - y)[/tex]
Thus, the HCF is (x+y).
Answer:
(x + y)
Step-by-step explanation:
Factorizing both terms :
x² - y² = (x + y)(x - y)(x + y)² = (x + y)(x + y)The HCF of the terms is (x + y).
If T(x) = x + 0.14x, then find the value of T(290).
Answer:
330.6
Step-by-step explanation:
You have to enter 290 for x.
T(290) = 290 + 0.14(290)
T(290) = 290 + 40.6
T(290) = 330.6
The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. the tangential speed of the satellite is m/s. (round to the nearest whole number, do not add any punctuation.)
Answer:
7,853.982
Step-by-step explanation:
Edg 2022
algebra 2 pls help ill give brainliest
Answer:
Step-by-step explanation:
Find the area of triangle DFG.
A. 5.3 square units
B. 34.3 square units
C. 420.0 square units
D. 424.2 square units
Answer:
34.3 square unit.
Step-by-step explanation:
[tex]calculate \: df \: using \: pythagoras \\ theorem \\ df {}^{2} = 8 {}^{2} + 6 {}^{2} \\ df {}^{2} = 64 + 36 \\ df {}^{2} = 100 \\ df = \sqrt{100} \\ df = 10 \\ calculating \: for \: the \: area \: of \: \\ angle \: \: dfg \\ using \: heros \: formular \\ \\ area = \sqrt{s(s - a)(s - b)(s - c)} \\ s = \frac{a + b + c}{2} \\ s = \frac{10 + 11 + 7}{2} = \frac{28}{2} = 14 \\ area = \sqrt{14(14 - 10)(14 - 11)14(14 - 7)} \\ area = \sqrt{14(4)(3)(7)} = \sqrt{14 \times 84} \\ area = \sqrt{1176} = 34.2928564 \\ to \: the \: nearest \: tenth \: = 34.3[/tex]
Here it is stated that, side DE = 8 units, side EF = 6 units, side FG = 7 units and side GD = 11 units. We have to find area of ∆DFG, here we will use heron's formula which is given by:
Area of ∆ = √[s(s – a) (s – b) (s – c)]
Here a, b, and c are sides of ∆. We have;
b = FG = 7 unitsc = GD = 11 unitsa = DF = ?s = semi - perimeter = ?So firstly lets calculate a i.e DF by using Pythagoras theorem on ∆DEF:
➸ DF² = 8² + 6²
➸ DF² = (8 × 8) + (6 × 6)
➸ DF² = 64 + 36
➸ DF² = 100
➸ DF = √(100)
➸ DF = √(10 × 10)
➸ DF = 10 units
Now, lets calculate s i.e semi - perimeter:
s = (a + b + c)/2s = (10 + 7 + 11)/2s = 28/2s = 14 unitsNow, using heron's formula on ∆DFG to calculate its area:
➸ Area(∆DFG) = √[14(14 – 10) (14 – 7) (14 – 11)]
➸ Area(∆DFG) = √[14(4) (7) (3)
➸ Area(∆DFG) = √(14 × 4 × 7 × 3)
We can write it as;
➸ Area(∆DFG) = √(2 × 2 × 2 × 7 × 7 × 3)
➸ Area(∆DFG) = 2 × 7√(2 × 3)
➸ Area(∆DFG) = 14√(6)
➸ Area(∆DFG) = 14 × 2.449
➸ Area(∆DFG) = 34.28
➸ Area(∆DFG) = 34.3 square units (approx)
Hence, area of ∆DFG is option B. 34.3 square units.can someone please help me
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: f(0) = -3 [/tex]
[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]
[tex]\qquad \tt \rightarrow \: f(4) = 1 [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
F(x) represents the value of y on curve for given value of x
[tex] \textsf{\large First -} [/tex]
[tex]\qquad \tt \rightarrow \: f(0) =( 0) {}^{2} - 3[/tex]
[ since 0 < 2 ]
[tex]\qquad \tt \rightarrow \: f(0) = 0 {}^{} - 3[/tex]
[tex]\qquad \tt \rightarrow \: f(0) = - 3[/tex]
[tex] \textsf{\large Second} [/tex]
[tex]\qquad \tt \rightarrow \: f(2) = (2) {}^{2} - 3[/tex]
[ since 2 = 2 ]
[tex]\qquad \tt \rightarrow \: f(2) = 4{}^{} - 3[/tex]
[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]
[tex] \textsf{\large Third -} [/tex]
[tex]\qquad \tt \rightarrow \: f(4) = - 4 + 5[/tex]
[ since 4 > 2 ]
[tex]\qquad \tt \rightarrow \: f(4) = 1[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
find lim x->2 for f(x)=
{2x+1, x greater than or equal to 2
{x^2, x>2
a. 5
b. 4
c. 5 or 4
d. dne
LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)
What is the limit of a function ?The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.
It is given that
lim x->2 for f(x)
[tex]\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)[/tex]
f(x) = 2x+1 x ≤2
f(x)= x² , x >2
When both the function tends to 2
Left Hand Limit
f(x) = 2 *2 +1
f(x) = 5
Right Hand Limit
f(x) = x² ,
f(x) = 4
LHL in not equal to RHL , Therefore the limit does not exists.
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If a = 6, then the value of c is...
Answer:
[tex]\boxed{\bf B. \: c = 4 \sqrt{3} }[/tex]
Step-by-step explanation:
Since a = 6, then, b = 3.47 ( opposite of 30°).
By applying the pythagoras theorem..
[tex] \boxed{\bf {h}^{2} = {p}^{2} + {b}^{2}} [/tex][tex]\bf {(c)}^{2} = {(a)}^{2} + {(b)}^{2} [/tex][tex] \bf {c}^{2} = {(6)}^{2} + {(3.47)}^{2} [/tex][tex] \bf {c}^{2} = 36 + 12[/tex][tex]\bf {c}^{2} = \sqrt{48} [/tex][tex]\bf c = 4 \sqrt{3} [/tex]______________________Answer:
4√3 or B
Step-by-step explanation:
which of the following are NOT classified as a trapezoid? Select all that apply
a) rhombuses
b) parallelograms
c) rectangles
d) squares
e) quadrilaterals
Answer:
[tex]\boxed {a, b, c, d}[/tex]
Step-by-step explanation:
Rhombuses, parallelograms, rectangles, and squares cannot be classified as trapezoids as they have 2 pairs of parallel sides each. But quadrilaterals can be classified as trapezoids if they have a pair of parallel sides and a pair of non-parallel sides.
a) rhombuses
b) parallelograms
c) rectangles
d) squares