A company has recently learned of a person trying to obtain personal information of employees illegally. According to which act will be the person punished?

I-SPY
CFAA
Digital Millennium Act
SOPA

Answer:

The type of b is bool ( B )

The type of c is int ( C )

The type of d is int ( D )

Explanation:

The options that must hold zero are: The type of b is bool,The type of d is int and The type of c is int.

If b is true then c or d is true because c and d are int. this is because b been a true/false means that d and c are boolean int. because d and c are assigned to integers  

The statements that must hold are:

The definition is given as:

let fabcd = a.(if b then c else d)

From the above definition, we have the following if condition

if b then c else d

This means that:

Variable b can only take either true or false, as its value.

So, b is of Boolean type

Variables c and d can take any numerical data type such as int, floats, and any character type such as char and string.

This means that:

Options (c) and (d) can also hold.

Hence, the true options are: (b), (c) and (d)

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Answer:

false

Explanation:

If the condition is false at the start, the contents of the loop should never be executed. If the CMP is at the end, you cannot prevent the code to run at least once. So this approach will work for a DO { ... } WHILE() loop, but not for a regular WHILE() { ... }

Answer:

This program is written in Python

inputtime = input("HH:MM:SS AM/PM: ")

splittime = inputtime.split(":")

secondAM = splittime[2].split()

if secondAM[1] == "AM":

   print(splittime[0]+":"+splittime[1]+":"+secondAM[0])

elif secondAM[1] == "PM":

   HH = int(splittime[0])

   HH = HH + 12

   print(str(HH)+":"+splittime[1]+":"+secondAM[0])

Explanation:

This line prompts user for input

inputtime = input("HH:MM:SS AM/PM: ")

This line splits the input string to HH, MM and "SS AM/PM"

splittime = inputtime.split(":")

This line splits "SS AM/PM" to SS and AM/PM

secondAM = splittime[2].split()

This line checks if time is AM

if secondAM[1] == "AM":

This line prints the equivalent time

   print(splittime[0]+":"+splittime[1]+":"+secondAM[0])

Else;

elif secondAM[1] == "PM":

The equivalent 24 hour is calculated

   HH = int(splittime[0]) + 12

This line prints the equivalent time

   print(str(HH)+":"+splittime[1]+":"+secondAM[0])

Answer:

state_sales_tax_rate = 0.04

county_sales_tax_rate = 0.02

sales = float(input("Enter the total sales for the month: "))

county_sales_tax = sales * county_sales_tax_rate

state_sales_tax = sales * state_sales_tax_rate

total_sales_tax = county_sales_tax + state_sales_tax

print("The amount of county sales tax is " + str(county_sales_tax))

print("The amount of state sales tax is " + str(state_sales_tax))

print("The total sales tax is " + str(total_sales_tax))

Explanation:

*The code is in Python.

Set the  state_sales_tax_rate and county_sales_tax_rate

Ask the user to enter the sales

Calculate the county_sales_tax, multiply sales by county_sales_tax_rate

Calculate the state_sales_tax, multiply sales by state_sales_tax_rate

Calculate the total_sales_tax, sum county_sales_tax and state_sales_tax

Print the results

Answer:

content aggregator

Explanation:

:)

Answer:

Assignment is the operation of a variable to a value

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

    Scanner in = new Scanner(System.in);

    System.out.print("Enter a sentence: ");

    String sentence = in.nextLine();

    String[] words = sentence.split("\\s");

    for(String s : words)

     System.out.println(s + " -> " + s.length());

}

}

Explanation:

Ask the user to enter a sentence

Get each word in the sentence using split method and put them in words array

Loop through the words. Print each word and number of characters they have  using the length method in required format

Answer:

d. A syntax error, if aquarium.db does not already exist on our computer.

Explanation:

The SQLite database is a relational database used readily in python backend web frameworks to store and retrieve data. The python packages like the sqlite3 are extensions of python proving its flexibility and power as a multi-purpose programming language.

The sqlite3 package is first installed and imported in the python file and a sqlite connection is made to the database which is automatically saved in the aquarium.db file ( created if it doesn't already exist ).

regulates and integrates the operations of the computer. It selects and retrieves instructions from the main memory in proper sequence and interprets them

Answer:

   See explanation

Explanation:

Given:

Processors:

P1  

P2

P3

Clock Rate of Processors:

Clock rate of P1 = 3 GHz

Clock rate of P2 = 2.5 GHz  

Clock rate of P3 = 4.0 GHz  

CPI of Processors:

Cycles per instruction = CPI of P1 = 1.5  

Cycles per instruction = CPI of P2 = 1.0

Cycles per instruction = CPI of P3 = 2.2

To find:

a) Which processor has the highest performance expressed in instructions per second

Solution:

Performance = clock rate / CPI  

The performance of processor depends on instructions count and CPU time.  

As we know that  

CPU time = Instructions * Cycles Per Instruction / clock rate  

CPU time = Instructions * CPI / clock rate

Instructions per second = Instruction count / CPU time  

As:    

CPU time = Instructions * CPI/ clock rate  

Instructions/CPU time = clock rate/CPI  

Instructions per second = clock rate / CPI

IPS = clock rate/ CPI  

Hence

Performance = Clock rate / CPI = clock rate/ CPI

Compute Performance of P1:

Performance for P1 = IPS of P1 = clock rate of P1 / CPI of P1 = 3 GHz / 1.5 = 2

As we know that 1 GHz = 10⁹ Hz. So:  

Performance of P1  expressed in instructions per second is  2 x 10⁹

Compute Performance of P2:

Performance for P2 = IPS of P2= clock rate of P2 / CPI of P2 = 2.5 GHz / 1.0 = 2 .5

As we know that 1 GHz = 10⁹ Hz. So:  

Performance of P1  expressed in instructions per second is  2.5 x 10⁹

Compute Performance of P3:

Performance for P3 = IPS of P3= clock rate of P3 / CPI of P3 = 4.0 GHz / 2.2 = 1.82

As we know that 1 GHz = 10⁹ Hz. So:  

Performance of P1  expressed in instructions per second is 1.82 x 10⁹

From the above computed performances of each processor it can be seen that Processor 2 (P2) has the highest performance expressed in instructions per second i.e. 2.5 x 10⁹

b) find the number of cycles and the number of instructions.

Given:

processors each execute a program in 10 seconds, So,

CPU time = 10 sec

Solution:

Compute number of cycles:

As we know that:

CPU time = cycles count / clock rate   = clock cycles/clock rate

So

clock cycles = CPU time x clock rate

Compute number of cycles of P1:

clock cycles  = 10 x 3 GHz

                     = 30

As we know that 1 GHz = 10⁹ Hz. So:  

clock cycles of P1 = 3 x 10¹⁰

Compute number of cycles of P2:

clock cycles  = 10 x 2.5 GHz

                     = 25

As we know that 1 GHz = 10⁹ Hz. So:  

clock cycles of P2 = 2.5 x 10¹⁰

Compute number of cycles of P3:

clock cycles  = 10 x 4.0 GHz

                     = 40

As we know that 1 GHz = 10⁹ Hz. So:  

clock cycles of P3 = 4 x 10¹⁰

Now as we know that:

Instructions per second = Instruction count / CPU time  

IPS = IC + CPU time

So to find number of instructions:

instruction count = Instructions per second x CPU time

Compute number of instructions of P1:

instructions of P1 = Instructions per second of P1 x CPU time

                            = 2 x 10⁹  x 10

                            = 2 x 10¹⁰

Compute number of instructions of P2:

instructions of P2 = Instructions per second of P2 x CPU time

                            = 2.5 x 10⁹  x 10

                            = 2.5 x 10¹⁰

Compute number of instructions of P3:

instructions of P3 = Instructions per second of P3 x CPU time

                            = 1.82 x 10⁹  x 10

                            = 1.82 x 10¹⁰

c) What clock rate should we have to reduce the execution time by 30%

As we know

CPU time = Execution time = instructions x CPI / clock rate

We have to find new clock rate to reduce execution time by 30%

This means we have to find:

New Execution Time = 70% of Old Execution Time

According to formula of Execution time:

instructions(new) x CPI(new) / clock rate(new) = 0.7 [instructions(old) x CPI(old) / clock rate(old)]

As the instructions(new)  = instructions(old)

So,

CPI(new) / clock rate(new) = 0.7 [CPI(old) / clock rate(old)]

When trying to reduce the execution time by 30%, this leads to an increase of 20% in the CPI.

CPI(new) = 1.2 CPI(old)

New CPI of P1:

CPI(new P1) = 1.2 CPI(old P1)

                    = 1.2 x 1.5

CPI(new P1) = 1.8

New CPI of P2:

CPI(new P2) = 1.2 CPI(old P2)

                    = 1.2 x 1.0

CPI(new P2) = 1.2

New CPI of P3:

CPI(new P3) = 1.2 CPI(old P3)

                    = 1.2 x 2.2

CPI(new P3) = 2.6

1.2 / clock rate (new) = 0.7 / clock rate(old)

So new clock rate is computed as:

clock rate (new)  = (1.2 / 0.7 ) x clock rate(old)

clock rate (new)  = 1.71 x clock rate(old)

clock rate (new)  = 1.71 x clock rate(old)

Hence the clock rate should be increased by 71% approx.

Now new clock rate for each processor is:

clock rate (new) for P1 = 3 GHz x 1.71     = 5.13 GHz

clock rate (new) for P2 = 2.5 GHz x 1.71 = 4.27 GHz

clock rate (new) for P3 = 4.0 GHz x 1.71 = 6.84 GHz  

In this exercise we have to use CPU and processor knowledge, so we can say that:

A)Processador 2

B) Processador 3

C) Processador 3

From the information given in the text we have:

a) With the formula bellow, we find:

[tex]Performance = clock \ rate / CPI[/tex]

The performance of processor depends on instructions count and CPU time.  

[tex]P= 3 GHz / 1.5 = 2*10^9[/tex]

[tex]P = 2.5 GHz / 1.0 = 2 .5*10^9[/tex]

[tex]P = 4.0 GHz / 2.2 = 1.82 *10^9[/tex]

b) Processors each execute a program in 10 seconds, So:

[tex]10 * 3 GHz = 30*10^{10}[/tex]

[tex]10 * 2.5 GHz= 25*10^{10[/tex]

[tex]10 * 4.0 GHz = 40*10^{10[/tex]

c) So for reduce we have:

[tex]CPI = 1.2 CPI = 1.2 * 1.5CPI = 1.8[/tex]

[tex]CPI= 1.2 CPI = 1.2 * 1.0\\CPI= 1.2[/tex]

[tex]CPI= 1.2 CPI = 1.2 *2.2\\CPI = 2.6[/tex]

Now new clock rate for each processor is:

[tex]clock rate (new) for P1 = 3 GHz x 1.71 = 5.13 GHz\\clock rate (new) for P2 = 2.5 GHz x 1.71 = 4.27 GHz\\clock rate (new) for P3 = 4.0 GHz x 1.71 = 6.84 GHz[/tex]

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Answer: A. Registers

Explanation:

Option A is correct. The CPU stores its computations in the Registers

The CPU is known as the Central Processing Unit.

Hence we can conclude that the CPU store its computations in the Register.

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Answer:

The RTP (real time protocol) which uses the UDP ( user datagram protocol) and Real-time control protocol.

Explanation:

The RTP of a voice over IP protocol (VoIP) which is used to prioritise the transfer of video and audio data over text data. It is used for video conferencing and telephony services in an enterprise.

It uses the user-datagram protocol to transfer or access videos and audio data for its real time effect and the real-time control protocol for quality of service analysis and maintenance.

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

Hence the output is:

The (shortest) distance between the cars is: 222.56        

Answer:

I think secure digital is needed

Answer:

Film

Explanation:

I chose Film and got it correct

Answer:

255

Explanation:

1 byte has 8 bits, that is, 8 combinations of binary inputs, which can result in calculations up to the number 2 ^ 8-1 = 255 (-1 because 0 will always be the first number), a computer nowadays has 64 bits (8bytes ), thus being able to calculate numbers up to 2 ^ 64-1, an integer file has 4 bytes, being able to calculate up to 2 ^ 32-1, and so on.

# Using the input function

# Prompt the user to input some number

# Convert the input to a float - this will cater for both floating

# numbers and integers

# Store the result in a variable called my_number

my_number = float(input('Please enter some number '))

#Create a variable named calculation which equals my_number plus 9

calculation = my_number + 9

#Multiply calculation by 2

calculation *= 2

#Subtract 4 from calculation

calculation -= 4

#Divide calculation by 2

calculation /= 2

#Subtract my_number from calculation

calculation -= my_number

#Print calculation

print('calculation = ' + str(calculation))

>> Please enter some number 8

calculation = 7.0

The above program has been written in Python and it contains comments explaining each line of the code. Please go through the comments. A sample output has also been provided.

Answer:ajax

Explanation:

Answer:

1. t is a function used to transpose a matrix object. The object is passed as an argument to the function.

2. matplot is a graphical function in R used for data visualization.

3. The c function is used to combine arguments.

4. seq is an R function used to derive a range of numbers, optionally specifying a start, stop and step argument or simply a single numeric argument.

5. legends are used in data visualization to list and define items in the graphical presentation.

6. matrix is a function in R used to create and work with matrix and data frame objects.

7. rownames and colnames are functions used to label the row and columns of a data frame in R.

8. The typeof function return the data type of an object.

Explanation:

The R programming language is a dedicated programming language for data analysis and visualization.

Answer:

WPA2 allows users to provide authentication via a pre-shared network key / password

Explanation:

The WPA mode that allows users to provide authentication via a pre-shared key or password is the personal mode. The correct option is a.

The most recent and secure Wi-Fi protocol at the moment is WPA3 Personal. A pre-shared key is used by Personal WPA to verify users' first login information.

Wi-Fi security access All users on 2 pre-shared key (WPA-PSK) networks use the same passphrase. A security standard for computing devices using wireless internet connections is called Wi-Fi Protected Access (WPA).

It was created by the Wi-Fi Alliance to provide stronger user authentication and data encryption than the original Wi-Fi security standard, Wired Equivalent Privacy (WEP).

Therefore, the correct option is a. Personal mode.

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The question is incomplete. Your most probably complete question is given below:

a. Personal mode

b. Enterprise mode

c. Extensible Authentication Protocol mode

d. Wired Equivalent Privacy mode

The best statement that best describes the differences between the painting itself and the photo of the painting stored on the smartphone is that the photo is a digital representation of the analog painting.

For better Understanding, we have to know about analog and digital terms means

From the above, we can therefore say that the answer that the photo is a digital representation of the analog painting is true.

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Explanation:

==================  

lin_spaced_vector.m  

==================  

function out=lin_spaced_vector(in1,in2)%defining function

out=linspace(in1,in2,200);%200 spaced numbers between in1 and in2

end​

===================  

Executable File

===================

clear all%clears history

clc%clears screen

lin_spaced_vector(1,10)%calling function​

clear all

clc

lin_spaced_vector(1,10)

Answer:

D. I think

Explanation:

Horizontal scaling of a client/server architecture means adding more workstations. Thus the correct option is D.

A computing model which  places the majority of the services and features that the client requests on the server, which also hosts, delivers, and manages them are known as client-server architecture 

Most applications that call for a division of labor between the client and the server benefit from the client-server architecture. The accessibility performance of applications is improved.

Both horizontal and vertical scaling is possible for client/server architectures. If a network is scaled vertically, more powerful, faster servers are added to the network, whereas horizontal scaling involves adding additional workstations (clients).

Therefore, option D is appropriate.

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Answer:

The answer is below

Explanation:

In order to carry out the basic method for implementing paging, the following processes are involved:

1. Both physical and logical memories are broken into predetermined sizes of blocks otherwise known as FRAMES and PAGES respectively

2. During processing, Pages are loaded into the accessible free memory frames from the backing store. The backing store is however compartmentalized into predetermined sizes of blocks whose size is equal to the size of the memory frames

Answer:

See explanation

Explanation:

First let us find what this algorithm compute:

Algorithm Mystery(n) {

        S = 0;

        for i = 1 to n do

             { S = S + i * i; }

         return S }

1)

Let suppose n = 3

S = 0

The algorithm has a for loop that has a loop variable i initialized to 1

At first iteration:

i = 1

S = S + i * i;

   = 0 + 1 * 1

S = 1

At second iteration:

i = 2

S = 1

S = S + 2 * 2;

   = 1 + 2 * 2

   = 1 + 4

S = 5

At third iteration:

i = 3

S = 5

S = S + 3 * 3;

   = 5 + 3 * 3

   = 5 + 9

S = 14

Now the loop breaks at i=4 because loop iterates up to n and n =3

So from above example it is clear that the algorithm computes the sum of squares of numbers from 1 to n. Or you can say it compute the sum of first n squares.  Let us represent this statement in mathematical form:

∑[tex]\left \ {{n} \atop {i=1}} \right.[/tex] i²

2)

From above example we can see that the basic operation is multiplication. At every iteration loop variable i is multiplied by itself from 1 to n or till n times. However we can also say that addition is the basic operation because at each iteration the value of S is added to the square of i. So it takes the same amount of time.

3)

In the for loop, the basic operation executes once. We can say that at each iteration of the loop, multiplication is performed once. Suppose A(n) represents the number of times basic operation executes then,

A(n) = ∑[tex]\left \ {{n} \atop {i=1}} \right.[/tex] 1 = n

4)

Since for loop executes once for each of the numbers from 1 to n, so this shows that for loop executes for n times. The basic operation in best, worst or average case runs n times. Hence the running time of Θ(n) . We can say that A(n) = n ∈ Θ(n)  

If b is the number of bits needed to  represent n then

b = log₂n + 1

b = log₂n

So

n ≈ [tex]2^{b}[/tex]

A(n) ≈ [tex]2^{b}[/tex] ≈ Θ( [tex]2^{b}[/tex] )  

5)

One solution is to calculate sum of squares without using Θ(n) algorithm.  So the efficient algorithm that takes less time than the previous algorithm is:

Algorithm Mystery(n) {

        S = 0;

        S = (n * ( n + 1 ) (2n + 1) ) / 6 ;

        return S}

Now the sum can be calculated in Θ(1)  times. This is because regardless of the size and number of operands/operations, the time of arithmetic operation stays the same. Now lets find out how this algorithm works for

n = 3

S = (n * ( n + 1 ) (2n + 1) ) / 6 ;

 = (3 * ( 3 + 1 ) * (2(3) + 1) ) / 6

 = (3 * (4) * (6+1)) / 6

= (3 * (4) * (7)) / 6

= (3 * 4 * 7) / 6

= 84 / 6

S = 14

Answer:

It could be that an ssh virtual terminal has not been configured for the port connected to PC-A

Explanation:

The computer network is an interconnection and intercommunication of computer devices to share resources. Intermediate devices like the Router and Switches are used to create physical and virtual connections between networks and nodes.

virtual connections like the default Telnet and the and more secure SSH are used to remotely communicate with intermediate devices for management purposes. For example, to use the ssh, the line vty and the specified virtual port range must be configured with a username, a password, an encryption key and other ssh features before a connection can be made.

Answer:

rv = "hello"

num_chars = len(rv)

print(num_chars)

Explanation:

*The code is in Python.

Initialize the string rv, in this example I set it to "hello"

Use the len() method to get the number of characters in the rv and set it to the num_chars

Print the num_chars

Note that the result will be 5 in this case, because hello consists of five characters

Answer:

I believe its confidentiality

Explanation:

confidentiality means the state of being kept secret or private

A loss of confidentiality is the unauthorized disclosure of information. The correct option is c).

Confidentiality is a set of rules or a promise that limits access to specific information. There aren't enough boundaries in confidential information. One shouldn't give your information to random people, but you also shouldn't give it to people close to you because not everyone is trustworthy.

One should only give out one's information when it is absolutely necessary, which is if you are. Unless there is a compelling reason not to, request consent to share information.

Unless it is going to hurt you or another person, a counselor will keep all of the information you give them confidential. When a detective keeps all crime-related clues and information confidential and hidden from civilians.

Therefore, the correct option is c) confidentiality.

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Try restating system software and delete anything that may have caused the online fraud then remove all credit cards and info on the device. Tell the authorities and get a new device and email with a software protector. When doing this DO NOT DO WHAT YOU ORIGINALLY DID TO GET VICTIMIZED AND (DON'T TRY TO SIGN INTO YOUR PREVIOUS EMAIL ON A NEW DEVICE)