Answer:
Empirical formula is C₄H₁₀O
Explanation:
Values for C, H and O are determined as centesimal composition.
64.80 g of C in 100g of compound
13.62g of H in 100 g of compound
21.58 g of O in 100 g of compound.
We convert the mass to moles:
64.80 g . 1mol/ 12g = 5.4 moles of C
13.62 g . 1 mol /1g = 13.62 moles of H
21.58 g . 1 mol/16g = 1.35 moles of O
We pick the lowest value and we divide:
5.4 moles of C / 1.35 = 4 C
13.62 moles of H / 1.35 = 10 H
1.35 moles of O / 1.35 = 1 O
Empirical formula is C₄H₁₀O, it can be the diethyl ether.
We confirm, the excersise is well done.
Molar mass = 74g/mol
74 g of compound we have (12 . 4)g of C
In 100 g of compound we may have (100 . 48) / 74 = 64.8 g
18. Predict the products for this single replacement reaction.
Cuso, + ALS
AL(S03)2 + Cu
Al(S0.)2 + Cu
O Al(SO.), + Cu
NR
19. Predict the products for this double replacement reaction.
Baci, + H,PO->?
BaPO4 + HCI
BaPO. + HCl
Ba(POJZ + HCI
Ba,(PO.)2 + HCI
PLEASE HELP ITS FOR A TEST I WOULD APPRECIATE IT !!
Answer:
3rd response
4th response
Explanation:
i lowkey feel like im doing this whole chem exam for u lol. good luck anyway! u rock!
A gas has a volume of 200. mL at 350. mm Hg. What will its volume be if the pressure is changed to 555. mm Hg
Answer:
The final volume when pressure is changed is 126.1mL
Explanation:
Based on Boyle's law, in a gas the volume is inversely proportional to its pressure when temperature remains constant. The equation is:
P₁V₁ = P₂V₂
Where P is pressure and V volume of 1, intial state and 2, final state.
Computing the values of the problem:
350mmHg*200mL = 555mmHgV₂
126.1mmHg = V₂
The final volume when pressure is changed is 126.1mLWhat type of boundary exists at letter b?
Answer:
Convergent boundaries
Explanation:
HELP ASAP ILL MARK BRAINLIEST
A room that is 500 cm x 400 cm x 250 cm contains 65 kg of air. Determine the volume of air in the room and its density.
Answer:
1.3g/L is the density of the air
Explanation:
The room is full of air, the space that the air occupy is:
500 cm x 400 cm x 250 cm = 5.00x10⁷ cm³
The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of air in g/L:
Grams air:
65 kg * (1000g / 1kg) = 65000g
Liters:
5.00x10⁷ cm³ * (1L / 1000cm³) = 50000L
Density:
65000g / 50000L =
1.3g/L is the density of the airA pair of students standard a sodium hydroxide solution using KHP and obtain the following concentrations: 0.1028 M, 0.1031 M, 0.1200 M, 0.1030 M and 0.1026 M. The students suspect that 0.1200 M is an outlier. Is 0.1200 M an outlier and what is the average concentration of the sodium hydroxide solution
Answer:
0.1200M is an outlier.
Average = 0.1063M
Explanation:
An outlier is defined as a value that is atypical based on the other observations.
We can define an outlier as a value that is out of the average ± Standard desviation.
The average of the values is:
(0.1028 M + 0.1031 M + 0.1200 M + 0.1030 M + 0.1026 M) / 5
Average = 0.1063MComputing the standard desviation, σ:
σ = 0.0077
The interval of accepted values is between:
0.1063 + 0.0077 = 0.1140M
0.1063 - 0.0077 = 0.0986M
As 0.1200M is out of this intercal, this value is an outlier
The definition of outlier depends of the author and the values you are studying.
can y’all please help me
10) Give two example of where you would find elements in our daily lives.
please help with this
Chlorhexidine gluconate is available in different products in concentrations of 4% w/v and 0.12% w/v. How many milliliters of the more dilute product may be prepared from each fluidounce of the more concentrated product
Answer:
From each fluidounce, 985.78 milliliters of the more dilute product can be produced.
Explanation:
From the given information:
4% w/v = 4g of solute in 100 mL of solution
0.12% w/v = 0.12g of solute in 100 mL of solution
Since 1 fluidounce = 29.5735 ml
∴
100 mL of solution contains 4g of solute
29.95735 ml will have [tex]\dfrac{4}{100} \times 29.5735[/tex]
= 1.18294g solute
Thus, 1 fluidounce contains 1.18294g solute
So, for the dilute solution, 0.12 g solute yields 100 mL solution
∴ 1.18294g will have [tex]\dfrac{100}{0.12} \times 1.18294[/tex]
= 985.78 ml
How are protons and neutrons similar? How are they different?
how many grams in 6.20 x 10^25 atoms of bromine (Br) ? image attached , will give brainliest
Answer:
8239.2g
Explanation:
Given parameters:
Number of atoms in Br = 6.2 x 10²⁵atoms
Unknown:
Mass of Br = ?
Solution:
From mole concepts, we know that:
1 mole of a substance contains 6.02 x 10²³ atoms/mol
Molar mass of Br = 80g/mol
6.2 x 10²⁵atoms x [tex]\frac{1}{6.02 x 10^{23} }[/tex] [tex]\frac{mol}{atoms}[/tex] x 80 x [tex]\frac{g}{moles}[/tex]
= 8239.2g
Indicate which categories apply to nitrogen.
Check all that apply.
metal
nonmetal
transition element
main group element
noble gas
What happens to frequency as wavelength
decreases across the electromagnetic
spectrum?
A. Frequency increases.
B. Frequency decreases.
C. Frequency stays the same.
D. Frequency and wavelength are not
related.
Answer:
B. Frequency decreases
When sound waves move through a medium, in what direction to do the particles in the medium move?
how to solve stoichiometry problem in a synthesis reaction with iron metal and oxygen gas, what mass of iron metsl is required to produce 456.0g of ferric oxide?
Answer:
319.2 g of iron metal
Explanation:
We'll begin by writing the balanced equation for the reaction between iron (Fe) and oxygen (O₂) to produce ferric oxide (Fe₂O₃). This is illustrated below:
4Fe + 3O₂ —> 2Fe₂O₃
Next, we shall determine the mass of Fe that reacted and the mass of Fe₂O₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 4 × 56 = 224 g
Molar mass of Fe₂O₃ = (56×2) + (16×3)
= 112 + 48
= 160 g/mol
Mass of Fe₂O₃ from the balanced equation = 2 × 160 = 320 g
SUMMARY:
From the balanced equation above,
224 g of Fe reacted to produce 320 g of Fe₂O₃.
Finally, we shall determine the mass of iron metal, Fe, required to produce 456 g of ferric oxide, Fe₂O₃. This can be obtained as follow:
From the balanced equation above,
224 g of Fe reacted to produce 320 g of Fe₂O₃.
Therefore, Xg of Fe will react to produce 456 g of Fe₂O₃ i.e
Xg of Fe = (224 × 456)/320
Xg of Fe = 319.2 g
Thus, 319.2 g of iron metal, Fe is required to produce 456 g of ferric oxide, Fe₂O₃.
Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to effuse through a tiny hole at 0.28 times the rate of effusion of Ar atoms under the same conditions of temperature and pressure. What is the molecular formula of arsenic(III) sulfide in the gas phase?
The molecular formula : As₄S₆
Further explanationGiven
Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms
Required
The molecular formula
Solution
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
[tex]\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }[/tex]
or
[tex]\rm M_1\times r_1^2=M_2\times r_2^2[/tex]
Input the value :
1 = Arsenic(III) sulfide
2 = Ar
MM Ar = 40 g/mol
0.28 = √(40/M₁)
M₁=40 : 0.28²
M₁=510 g/mol
The empirical formula of arsenic(III) sulfide = As₂S₃
(Empirical formula)n = molecular formula
( As₂S₃)n = 510 g/mol
(246.02 g/mol)n = 510 g/mol
n = 2
So the molecular formula : As₄S₆
Rearrange this expression into quadratic form, 2++=0 , and identify the values of , , and . 0.20=^2/65−
Explanation:
0.20 equal to 2/65
2/65-0.20
-0.1692
Which element is represented by the following:
1s22s22p63s23p64s23d104p1?
Write the symbol.
Answer:
Gallium (Ga)
Explanation:
Gallium (Ga) is the element which is represented by the given electron configuration since the total number electron is 31.
A material that cannot be destroyed chemically is referred to as a chemical element. Although chemical processes cannot modify an atom, nuclear reactions can create new elements. The quantity of protons an element has defines it. An element's atoms all contain the same amount of protons, but its electron and neutron counts might vary. Ions are produced by altering the electron to proton ratio, whereas isotopes are produced by altering the neutron count. Since there are 31 total electrons in the universe, gallium (Ga) gets the element that is denoted by the specified electron configuration.
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What happened to the missing neutron?
•it will turn into a proton and an electron
•it became gamma radiation
•it got absorbed by the electrons
Answer:
it became gamma radiation, it will turn into a proton and an electron
Explanation:
PLEASE HELP I WILL GIVE YOU BRAINLIEST Provide the chemical formula for the following
Provide the chemical name for the following
1. Calcium Dichromate
2. Na2SO3
3. Ammonium Sulfite
4. Cu(NO2)2
Step 1: H2(g) + → ICI(9) HI(g) + HCl(g) (slow)
Step 2: HI(g) +ICI(g) → + HCl(g) + I2 (g) (fast)
The reaction is carried out at constant temperature inside a rigid container. Based on this mechanism, which of the following is the most likely reason for the different rates of step 1 and step 2?
a. The only factor determining the rate of step 2 is the orientation of the HI and ICl polar molecules during a collision, but it has a negligible effect when H, and ICl molecules collide.
b. The amount of energy required for a successful collision between H, and ICl is greater than the amount of energy required for a successful collision between HI and ICI.
c. The fraction of molecules with enough energy to overcome the activation energy barrier is lower for HI and ICl than for H2, and ICI.
d. The frequency of collisions between H2, and ICl is greater than the frequency of collisions between HI and ICI.
Answer:
B
Explanation:
Step 1 occurs at a slower rate than Step 2.
The fraction of molecules with enough energy to overcome the activation energy barrier is lower for HI and ICl than for H2, and ICI.
We must bear in mind that the rate determining step in a reaction is the slowest step in the chemical reaction. As such, we can clearly see that step 1 is the rate determining step in the reaction.
The fast reaction must have a minimum energy barrier between the reactants and the products. Hence, the fraction of molecules with enough energy to overcome the activation energy barrier is lower for HI and ICl than for H2, and ICI.
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Classify these bonds as ionic, polar covalent, or covalent, and give your reasons: (a) the SiSi bond in Cl3SiSiCl3, (b) the SiCl bond in Cl3SiSiCl3, (c) the CaF bond in CaF2, (d) the NH bond in NH3.
Answer:1-1 equakls
Explanation:
A 25.0 g sample of nitrogen reacts with 4.02 g of hydrogen to form ammonia (NH3) in the equation N2 + 3 H2 = 2 NH3 If ammonia is the only product, what is the mass of ammonia formed?
Answer:
Mass = 22.1 g
Explanation:
Given data:
Mass of nitrogen = 25.0 g
Mass of hydrogen = 4.02 g
Mass of ammonia formed = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Number of moles of nitrogen:
Number of moles = mass/molar mass
Number of moles = 25.0 g/ 28 g/mol
Number of moles = 0.89 mol
Number of moles of nitrogen:
Number of moles = mass/molar mass
Number of moles = 4.02 g/ 2 g/mol
Number of moles =2.01 mol
now we will compare the moles of nitrogen and hydrogen with ammonia.
H₂ : NH₃
3 : 2
2.01 : 2/3×2.01 = 1.3 mol
N₂ : NH₃
1 : 2
0.89 : 2/1×0.89 = 1.78 mol
hydrogen produced less number of moles of ammonia it will act ae limiting reactant.
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 1.3 mol × 17 g/mol
Mass = 22.1 g
10 points
All of the following are some things that can decrease the rise in global
temperatures EXCEPT:
using more solar energy
using more fossil fuels
using more biofuels
going Vegan
Answer: Using more fossil fuels
Explanation: Burning fossil fuels releases Green House gasses into the atmosphere, such as carbon dioxide. The carbon dioxide in the atmosphere traps in heat, which causes global temperatures to increase.
What is the edge length of a 369-g iron cube?(The density of iron is 7.86 g/cm3, and the volume of a cube is equal to the edge length cubed.)
Answer:
edge length = 3.61 cm
Explanation:
Givens
m = 369 gm
d = 7.86 gm / cm^3
v = ?
Formula
v = m / d
Solution
v = 369 / 7.86
v = 46.95 cm^3
============
That's not the answer. You must take the cube root of the volume
side = cube root (46.95)
side = 3.61 cm
The Edge length of the iron cube will be "3.61 cm".
Given values,
Weight of iron cube,
m = 369 g
Density of iron,
d = 7.86 g/cm³
The volume of iron cube will be:
→ [tex]V = \frac{m}{d}[/tex]
[tex]= \frac{369}{7.86}[/tex]
[tex]= 46.95 \ cm^3[/tex]
As we know that the volume of cube is "[tex]a^3 \ cm^3[/tex]".
hence,
→ [tex]a^3 = 46.95 \ cm^3[/tex]
or,
→ [tex]a = (46.95 \ cm^3)^{\frac{1}{3} }[/tex]
[tex]= 3.61 \ cm[/tex]
Thus the above answer is correct.
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Give the product expected when the following alcohol reacts with pyridinium chlorochromate (PCC). (Assume that PCC is present in excess.) The starting material is H O C H 2 C H 2 C H 2 O H. THis reacts with P C C and C H 2 C L 2 to give the product.
Answer:
Explanation:
From the information given, we are to show the product of the reaction between the alcohol (stick formula) with pyridinium chlorochromate. The reaction starts with the nucleophilic addition of Cr with oxygen molecule on the alcohol. Then, deprotonation of oxygen occurs, this process is followed by the removal of hydrogen ion to yield the final product. The reaction mechanism can be seen from the attached image below.
A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the final volume of the solution is 508 mL. Group of answer choices
Answer:
[tex]x_{suc}=0.00406[/tex]
Explanation:
Hello!
In this case, since the mole fraction relates the moles of solute and the moles of solution, and for sucrose it is:
[tex]x_{suc}=\frac{n_{suc}}{n_{suc}+n_{water}}[/tex]
Whereas we need to compute the moles of both sucrose and water based on their molar masses (342.3 and 18.02 respectively) as shown below:
[tex]n_{suc}}=\frac{38.6g}{342.3g/mol}=0.113mol\\\\ n_{water}}=\frac{495g}{18.02g/mol}=27.5mol\\[/tex]
Thus, the mole fraction sucrose turns out:
[tex]x_{suc}=\frac{0.112}{0.112+27.5}\\\\x_{suc}=0.00406[/tex]
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What is the stored energy of an object called?
Kinetic energy
Mechanical energy
Potential energy
Translational energy
Answer: Potential energy
Explanation:
BRAINLIEST?
1. Scientists have evidence that the universe is [expanding/shrinking].
2.Objects moving away from Earth appear [blue/red], and objects moving toward Earth appear [blue/red].
3. Light from most other galaxies appears [blue/red], which makes sense if the universe is [collapsing inward/spreading out].
Consider a gaseous mixture consisting of 5 kmol of H2 and 3 kmol of O2. Determine the H2 and O2 mole fractions, the molecular weight of the mixture, and the H2 and O2 mass fractions
Answer:
Mole fraction H2: 0.625
Mole fraction O2: 0.375
Molecular weight: 13.25g/mol
Mass fraction H2: 0.094
Mass fraction O2: 0.906
Explanation:
Moles fraction is defined as the ratio between moles of a substance and total moles presents in a mixture:
Mole fraction H2 = 5kmol / (5kmol + 3kmol) = 0.625
Mole fraction O2 = 3kmol / (5kmol + 3kmol) = 0.375
Molecular weight is defined as the mass per mole of substance:
Mass H2 = 5kmol * (2kg / kmol) = 10kg
Mass O2 = 3kmol * (32kg / kmol) = 96kg
Molecular weight:
106kg / 8kmol = 13.25g/mol
In the same way, mass fraction is the ratio between mass of a substance and total mass of the mixture:
Mass fraction H2 = 10kg / (10kg + 96kg) = 0.094
Mass fraction O2 = 96kg / (10kg + 96kg) = 0.906