The statements "the potential at the center of the sphere is zero", "the potential at the surface of the sphere is the same as the potential at infinity", and "the potential is lowest at the center of the sphere" are all true.
The correct statements about the potential due to this conducting sphere are:The potential at the center of the sphere is zero, The potential at the surface of the sphere is the same as the potential at infinity,The potential is lowest at the center of the sphere.
When a charged particle moves in an electric field, the field exerts a force that can do work on the particle. The work can be expressed in terms of electric potential energy. Electric potential energy depends only on the position of the charged particle in the electric field.
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(hrwc9p104) an old chrysler with mass 2650 kg is moving along a straight stretch of road at 81 km/h. it is followed by a ford with mass 1550 kg moving at 52 km/h. how fast is the center of mass of the two cars moving?
The two automobiles center's of mass are moving at a 19.79 m/s speed. Calculate the system's total mass and canter of mass velocity to get the velocity of the system's center of mass for the two automobiles.
The weighted average of the velocities of each individual object, multiplied by their mass, equals the velocity of the canter of mass.
Let's refer to the center of mass's velocity as V cm. Then:
V cm is equal to (mass of Chrysler times its velocity plus mass of Ford times its velocity) / (total mass of system)
The speeds must first be changed from km/h to m/s:
Chrysler's speed is 81 km/h, or 81 * 1000 / 3600 m/s, or 20.83 m/s.
Ford's speed of 52 km/h is equal to 52 * 1000 / 3600 m/s, or 18.06 m/s.
Then, we may determine the system's overall mass and center-of-mass velocity:
Overall mass equals the sum of the masses of Chrysler and Ford, or 2650 kg plus 1550 kg, totaling 4200 kg.
V cm is equal to (mass of Chrysler times its velocity plus mass of Ford times its velocity) / total mass.
V cm is calculated as (2650 kg at 20.83 m/s and 1550 kg at 18.06 m/s) / 4050 kg.
V cm is equal to 4200 kg / (55,051.5 kg m/s + 25,244 kg m/s).
V cm = 4200 kg / 80,295.5 kg / 19.79 m/s
Hence, the two automobiles center's of mass are moving at a velocity of 19.79 m/s.
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What's the frequency of AC ( alternating current ) ?
The frequency of alternating current (AC) is the number of times the current changes direction per second. It is measured in hertz (Hz).
In most parts of the world, the frequency of alternating current (AC) is 50 Hz, meaning that the current changes direction 50 times per second. However, in some parts of the world, such as the United States and Canada, the frequency of AC is 60 Hz. This means that the current changes direction 60 times per second. It is important to note that the frequency of AC is determined by the power source, and cannot be changed by the user.
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Student 1: The speed of the block at its maximum height is zero because the kinetic energy is a minimum at the top of the trajectory. Student 2: Only the vertical component of the velocity is zero at the maximum height, because the vertical component of the acceleration is zero at the top of the trajectory.
It is true that the maximum speed of a block in a trajectory occurs at its maximum height, where the vertical component of the velocity is zero. This is due to the fact that at that point, the kinetic energy is minimized and the acceleration is zero. At this point, the block is at its highest point, and the velocity of the block is at its lowest. Therefore, the speed is zero at the top of the trajectory.
However, the horizontal component of the velocity is not zero at the maximum height. This is because the block is constantly subject to horizontal acceleration by gravity, even at its highest point. This means that the block has a nonzero velocity in the horizontal direction, even if it is at its maximum height. Therefore, the block is not at rest at the highest point; it is just moving horizontally at a constant speed.
What happens to the number of valence electrons as you move from element 1 to element 18 on the Periodic Table?
When we move from element 1 to element 18 on the periodic table the number of Valence Electrons as we move increases.
The elements 1 to element 18 are located in the group 1-2 and group 13-18 of the periodic table.
Now when we move from element 1 to element 18 we are basically moving from left to right in the periodic table and as we move from left to right we see that the number of valence electrons in the group increases by one from the one element to the next in the periodic table.
This is due to the increasing atomic number of the elements.
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What is the change of GPE for a 8.0 kg object which is lowered from an initial height of 10 m above the floor to a final height of 4.0 m above the floor?
The change in gravitational potential energy, GPE for the 8 Kg object which is lowered from a height of 10 m to 4 m is -470.4 J
How do I determine the change in potential energy of the object?We'll begin by obtaining the initial potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₁) = 10 mAcceleration due to gravity (g) = 9.8 m/s² Initial potential energy (PE₁) = ?PE₁ = mgh₁
PE = 8 × 9.8 × 10
PE = 784 J
Next, we shall determine the final potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₂) = 4 mAcceleration due to gravity (g) = 9.8 m/s² Final potential energy (PE₂) = ?PE₂ = mgh₂
PE = 8 × 9.8 × 4
PE = 313.6 J
Finally, we shall determine the change in the potential energy. This is shown below:
Initial potential energy (PE₁) = 784 JFinal potential energy (PE₂) = 313.6 JChange in potential energy (ΔPE) =?ΔPE = PE₂ - PE₁
ΔPE = 784 - 313.6
ΔPE = -470.4 J
Thus, the change in potential energy is -470.4 J
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if you see the moon directly above a tree from your bedroom window one day, will the moon appear in the same position earlier or later the next day? explain.
The moon will not appear in the same position at the same time the next day, due to the Earth's rotation and the moon's motion in its orbit around the Earth.
The position of the moon in the sky changes due to the rotation of the Earth on its axis, as well as the moon's own motion in its orbit around the Earth. Therefore, if you see the moon directly above a tree from your bedroom window one day, the moon will not appear in the same position at the same time the next day. The time it takes for the moon to return to the same position in the sky is approximately 24 hours and 50 minutes, which is known as a lunar day. This is longer than a solar day (which is 24 hours), because the moon is also moving in its orbit around the Earth, and therefore has to move slightly further in the sky to return to the same position relative to the Sun. So, the moon will appear in a slightly different position in the sky relative to the tree each day, and it will also rise and set at slightly different times each day. The exact amount of change will depend on factors such as the time of year and the location of the observer.
In summary, the moon will not appear in the same position at the same time the next day, due to the Earth's rotation and the moon's motion in its orbit around the Earth.
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Is the rate-limiting step the slowest?
It is not important to the rate-limiting step in a chemical reaction how much energy is released or used. Instead, the slowest step among all the steps that take place in a specific chemical reaction is referred to as the rate-limiting step.
What is the rate-limiting step?One of the fundamental steps in a multistep reaction mechanism moves along much more slowly than the others. The slowest step is the one that limits or determines rate.
This is because the phase that moves slowly needs more time to complete because it may entail numerous other processes.
As an illustration, a reactant would need to diffuse or migrate to a certain reaction site before another reaction can occur, which then immediately creates a product.
Therefore, A reaction can only move through its slowest phase; as a result, the rate-determining step restricts the rate of the entire reaction.
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four different pairs of transverse wave pulses are shown below. in each case the pulses are moving towards each other. at some point in time the pulses meet and interact (interfere) with each other. for which pair will the height of the combined (resultant) pulse be greatest at the center of the combined pulses, at the point where the centers of the pulses coincide?
The resultant pulse's amplitude is the sum of the amplitudes of the two original pulses. This might be two crests or two troughs colliding.
When two waves superimpose in opposite phase, the amplitude of the consequent is equal to the difference in amplitude of the component waves, resulting in the least amount of light intensity; this is known as destructive interference.
When two pulses travelling in opposite directions along a stretched string collide. Because both pulses cause the string to move higher as they travel, the net displacement of the string at that location is equal to the total of the pulse amplitudes. Because the two waves are travelling through the same medium, they have the same speed. The superposition total wave travels in the same direction and at the same speed as the two component waves, but its local amplitude is determined by whether the two individual waves have the same or opposite phase.
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An object 0.1 m tall is placed 0.4 m from a convex mirror with a focal length of 0.3 m. What is the height of the image?
Answer: no exact answer
=
Explanation:
determine the vertical rise h of the load w during 10 seconds if the hoisting drum draws in cable at the constant rate of 180 mm/s.
The vertical rise of the load during 10 seconds is approximately 490.5 meters.
What is uniformly accelerated motion?Uniformly accelerated motion is a type of motion in which an object moves along a straight line with a constant acceleration. This means that the object's velocity changes at a constant rate over time, with equal changes in velocity occurring during equal time intervals.
We can use the kinematic equation for uniformly accelerated motion to determine the vertical rise of the load:
h = vit + (1/2)at²
where:
h is the vertical rise of the load (in meters)
vi is the initial vertical velocity of the load (in meters per second)
a is the vertical acceleration of the load (in meters per second squared)
t is the time interval (in seconds)
Since the load is being hoisted upward, its initial vertical velocity is zero, so vi = 0. The vertical acceleration of the load is equal to the acceleration due to gravity, which is approximately 9.81 m/s².
To use this equation, we need to convert the constant rate of cable draw, 180 mm/s, to meters per second:
180 mm/s = 0.18 m/s
Now we can plug in the values:
h = (0 m/s)(10 s) + (1/2)(9.81 m/s²)(10 s)²
h = 490.5 meters
Therefore, the vertical rise of the load during 10 seconds is approximately 490.5 meters.
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A balloon is inflated with helium at a constant pressure that is 4.3 × 105 Pa in excess of atmospheric pressure. If the balloon inflates from a volume of 1.8 × 10−4 m3 to 9.5 × 10−4 m3, how much work is done on the surrounding air by the helium-filled balloon during this expansion?
Answer: W = 331.1 J
Explanation:
W = pdv
= (4.3 x 10^5 Pa) (9.5 × 10−4 m3 - 1.8 × 10−4 m3)
W = 331.1 J or 3.3 x 10^2 J
The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.
What is meant by pressure-volume work?Pressure-volume work is defined as the work that a fluid does when it is compressed or expanded by an external force factor.
Here,
Pressure of the helium gas, P = 4.3 x 10⁵Pa
Initial volume of the helium gas, V₁ = 1.8 x 10⁻⁴m³
Final volume of the helium gas, V₂ = 9.5 x 10⁻⁴m³
The expression for the pressure-volume work is given by,
Work done, W = PΔV
where ΔV is the change in volume of the helium gas.
Therefore,
W = P(V₂ - V₁)
W = 4.3 x 10⁵(9.5 x 10⁻⁴- 1.8 x 10⁻⁴)
W = 4.3 x 10⁵x 7.7 x 10⁻⁴
W = 331.1 J
Hence,
The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.
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Which statement best describes wavelengths of sunlight that are longer than 700 nanometers? These wavelengths form the infrared part of the spectrum. These wavelengths form the ultraviolet light of the spectrum. These wavelengths are shorter than the wavelengths of visible light These wavelengths are part of the visible light spectrum
Answer:
The statement "These wavelengths form the infrared part of the spectrum." best describes wavelengths of sunlight that are longer than 700 nanometers. Infrared light is a type of electromagnetic radiation with longer wavelengths than visible light, but shorter wavelengths than radio waves. It is typically defined as having wavelengths between 700 nanometers and 1 millimeter.
1. A student measures the mass of a solution before and after a chemical reaction takes place. In both cases the student measures the mass to be 50.25 g on an electronic balance with an uncertainty of 0.05 g. The student realizes that the ranges of uncertainty for each measurement overlap exactly. Which claim can the student make?(a) The mass definitely stayed the same because the ranges of uncertainty overlap exactly.(b) We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.(c) The mass definitely stayed the same because the measurement of 50.25 g was obtained each time.2. In the previous question you learned that a measurement system can be accurate but not precise, precise but not accurate, neither, or both. If an equipment contains a systematic error, then increasing the sample size will in general:(a) improve both accuracy and precision.(b) have no effect on either accuracy and precision.(c) improve accuracy but will not increase precision.(d) increase precision but will not improve accuracy.3. The cloth tape measure that you use to measure the length of an object had been stretched out from years of use. As a result, all of your length measurements were too small. How could you compensate for the incorrect results of using the stretched out tape measure?(a) There is no way to compensate for the incorrect result.(b) This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.(c) This is due to random error. Take more measurements until you get enough data to average and reduce the error.(d) This stretch is due to random error, so it can be ignored.
a) The claim student can make is - We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.
b) increasing the sample size will in general - increase precision but will not improve accuracy.
c) incorrect results of using the stretched out tape measure- This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.
a) Since the pupil used the same electronic balance with an query of0.05 g to weigh the mass of the result ahead and later, we can say that the millions are the same within the query of the balance.
b) Precision is the degree to which unborn measures yield the same results. delicacy, on the other hand, is a measure of how nearly the results agree with a true value. By adding the sample size the standard error is dropped meaning that unborn measures will probably fall near to the average. However, also taking further measures won't address this error and ameliorate delicacy as each dimension will be" off" by the same quantum from the true value, If methodical error is present. rather the methodical error needs to be removed, if possible, and this will ameliorate delicacy.
c) The stretching of the tape recording measure introduces a methodical error which could be corrected by comparing the tape recording with a different tape recording( essence or new). Once the pupil knows how important each dimension is out, the pupil can acclimate the original measures consequently. Performing further measures simply reduces the arbitrary error caused by the person reading the scale and won't affect the delicacy of the dimension.
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How does an object's speed affect its kinetic energy?
Answer: Object's speed affects the Kinetic Energy Quadratically.
Explanation: we have to know that Kinetic Energy is a scalar quantity, that is it doesn't have direction. Kinetic Energy of a moving body is totally dependent upon the body's mass and velocity of it.
The Kinetic Energy of a moving body having mass M and velocity V, then at a certain instant, the body's having Kinetic Energy is equal to:
Kinetic Energy (K.E.) = (MV²)/2
where:
M⇒ Body's mass
V ⇒Velocity of a moving body
It is so Clear that K.E. directly proportional to square of the body's velocity.
Therefore, Object's speed affects the Kinetic Energy Quadratically.
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the energy loss over a ball valve (1/3 closed) has been calculated as 240 j/kg. what is the volumetric average fluid velocity (m/s) through the valve?
The volumetric average fluid velocity (m/s) through the valve of ball valve having energy loss as 240 j/kg is 15.5 m/s.
When energy is converted from one form to another, or moved from one place to another, or from one system to another there's energy loss. This means that when energy is converted to a different form, some of the input energy is turned into a largely disordered form of energy, like heat.
Flow rate is the volume of fluid per unit time flowing past a point through the area A. Then the shadowed cylinder of fluid flows once point P in a invariant pipe in time t. The volume of the cylinder is announcement and the average haste is v =d / t so that the inflow rate is Q = announcement/ t = Av.
Energy loss is given as 240 J/kg
So to find the volumetric average velocity we have,
Energy loss = 1/2 V² J/kg
240 = 1/2 V² J/kg
V = [tex]\sqrt{240}[/tex]
V = 15.49 ≈ 15.5 m/s
Therefore, the volumetric average fluid velocity is V = 15.49 ≈ 15.5 m/s.
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Two stars are of equal luminosity. Star A is 3 times as far from you as star B. Star A appears _________ star B.A. 3 times brighter than
B. 9 times brighter than
C. one-third as bright as
D. the same brightness as
E. one-ninth as bright as
The answer is E. One-ninth as bright as star B if two star are of equal luminosity.
The apparent brightness of a star depends on its distance from the observer. According to the inverse square law, the apparent brightness of a star decreases as the square of the distance from the observer increases. In this case, star A is three times farther away from the observer than star B. Therefore, the apparent brightness of star A will be nine times less than that of star B.
Since the two stars are of equal luminosity, we can conclude that star A appears one-ninth as bright as star B. This is because the apparent brightness of a star is proportional to its luminosity divided by the square of the distance from the observer. Since the two stars have the same luminosity, the ratio of their apparent brightness is equal to the inverse square of the ratio of their distances from the observer.
In summary, the answer is E. One-ninth as bright as star B
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What is the velocity of a skater who is 10 kg, and has a Kinetic energy of 10000 Joules?
Answer:
44.7 meter per second
Explanation:
The formula to find velocity is
V = (2 · KE / m)^1/2
V = velocity
KE = Kinetic energy
m = mass
Let's calculate
(2 · 10000 / 10) ^1/2 = 44.7 meter per second
you measured the length, diameter and mass of two different cylinders. in both cases, you found that the length had 3 significant figures and that length was the measurement with the fewest number of significant digits. if you found the weight densities to be 38123 n/m3 and 38091 n/m3 and you round these values to the correct number of significant figures, can you conclude the two cylinders are made of the same material (do they have the same weight density)?
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38107 N/m³
The formula for volume of cylinder is:
V = πr²l
where,
V = Volume
r = radius
l = length of cylinder
So, if length has the 3 significant figures which is least in all values, Then the volume must also be in 3 significant figures. The formula for weight density is:
Weight Density = Weight/Volume
Here, the volume has the least significant figures of 3, therefore, the weight densities must also have 3 significant figures:
Weight Density 1 = 38123 N/m³
Weight Density 1 = 38124 N/m³
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38123 N/m³
Weight Density 2 = 38124 N/m³
Weight Density 2 = 38107 N/m³
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vision is blurred if the head is vibrated at 29 hz because the vibrations are resonant with the natural frequency of the eyeball held by the musculature in its socket.
There is some scientific evidence to suggest that vibration at certain frequencies can affect visual perception, but the claim that vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball held by the musculature in its socket is not entirely accurate.
What is Eyeball resonance and vision?According to the concept of "eyeball resonance," the eyeball can vibrate at specific frequencies as a result of the tension in the muscles around it, and these vibrations can affect vision. Generally speaking, the natural frequency of the eyeball is thought to be around 20 Hz, however this frequency can change based on a number of variables, including the eyeball's flexibility and the tension of the optic nerve.
There is some evidence to support the idea that being exposed to vibration at particular frequencies can alter vision. For instance, some researchers have discovered that participants who are exposed to 25 Hz vibration may have a reduction in visual acuity, while other studies have found that those who are exposed to 10 Hz vibration may experience an increase in improve visual perception in some people.
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If you apply is 400 N pushing 20 - KG sled what is the acceleration ? solve the following problems
If you apply is 400 N pushing 20 - KG sled. The acceleration is 20 m/s².
What is acceleration?Acceleration is a vehicle's capacity to gain speed within a short time. The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion.
When an item's mass and the net force acting on it are known, the acceleration of that object can be calculated using this equation for acceleration.
Acceleration = force/mass
Force = 400 N
Mass = 20 kg
400 / 20 = 20 m/s²
Therefore, the acceleration is 20 m/s².
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g if the other charges are fixed in place and charge 2q is allowed to move, what will be the kinetic energy k2q of charge 2q when it is very far from the other charges?
A particle with a mass of m/2 and a charge of 2q has kinetic energy of 2K when it is propelled from rest by the same potential difference.
Due to the fact that mass has no impact on kinetic energy, W = K = QV. where,
charge = Q, q
V = potential difference
k = kinetic energy
m = mass
The kinetic energy of a particle with a 2q charge and a v potential difference is given by the equation K = Q V,
where,
K₁ = Q₁V₁
K¹ = 2Q¹ x V¹ = 2(QV).
Due to K = QV, K1 = 2K is obtained by substituting K = QV into 2(QV).
Applying the equation E = (k)(q/r²), If q becomes 2q and r becomes 2r, When an electric charge is present in a specific region of space, its properties are altered and an electric field is generated. The term electric field refers to the physical field that surrounds electrically charged particles and acts to either attract or repel other charged particles in the field.
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If a meteor with a 20 m in diameter impacts Earth on land, approximately how big will the crater be?A. 200-400 m in diameterB. 300-500 m in diameterC. 400-600 m in diameterD. 500-700 m in diameter
If a meteor with a 20 m in diameter impacts Earth on land, approximately the crater will be 200-400m in diameter long.
The size of the crater created by a meteorite impact depends on several factors, such as the composition of the meteorite and the density of the material it impacts. Generally speaking, a 20 m in diameter meteorite would create a crater with a diameter between 200 and 400m. A few meters to several hundred meters can make up the crater's depth. A crater will most likely be created at the point of impact when a meteor impacts a planet. The size of the crater will increase as the object moves faster and becomes larger or heavier. The biggest predictors of impact crater size are the meteor's mass and velocity.
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A student conducts an investigation on a bar magnet with unlabeled poles. To determine which side of the magnet is north (N) or south (S), what steps can the student take?
A. The student can cut the bar magnet in half and observe the direction of the magnetic field on each individual piece.
B. The student can place the bar magnet near a nonmetal surface and observe the direction of the magnetic field on the surface.
C. The student can place the bar magnet near a metallic surface and observe the direction of the magnetic field on the surface.
D. The student can place the bar magnet near the known pole of a second magnet and observe the interaction between the poles.
The student can place the bar magnet near the known pole of a second magnet and observe the interaction between the poles.
option D.
How can the student determine the poles of the magnet?When two magnets are brought near each other, the direction of the magnetic field lines can be used to determine the orientation of the poles.
If the two magnets are brought near each other with the same poles facing each other (north-north or south-south), they will experience a repulsive force and will push away from each other.
On the other hand, if the magnets are brought near each other with opposite poles facing each other (north-south), they will experience an attractive force and will move towards each other.
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at the instant the traffic light turns green, an automobile starts with a constant acceleration of 2.70 m/s2. at the same instant a truck, traveling with a constant speed of 11.30 m/s, overtakes and passes the automobile. (a) how far beyond the traffic signal will the automobile overtake the truck?
The traffic signal will the automobile overtake the truck far away beyond the traffic signal is 2.7 m.
The difference between haste and relative haste is that haste is measured with respect to a reference point which is relative to a different point. While relative haste is measured in a frame where an object is either at rest or moving with respect to the absolute frame.
The relative haste is defined as the haste of an object with respect to another bystander.
It's the time rate of change of relative position of one object with respect to another object.
W.r.t automobile,
u = ut - ua at t=0
= 11.3 - 0
= 11.3 m/s
d = dt - da
= 0 - 2.7 = -2.7m/s²
So, s = ut + 1/2at²
= 11.3(t) - 2.7/2 at²
0 = 11.3t - 2.7/2 t²
= 11.3t - 1.35 t²
11.3t = 1.35t²
t = 11.3/1.35
t = 8.37 sec
They will overtake again at 8.37 s
v = 11.3 m/s and st = vx1 = 11.3 m
both truck and car would travelled 11.3 m
Speed of automobile,
v = u + at
= 0 + 2.7(1)
= 2.7 m/s
Speed of the automobile is : 2.7 m/s
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a light-rail commuter train accelerates at a rate of 1.45 m/s2. how long (in s) does it take to reach its top speed of 80.0 km/h, starting from rest?
The time taken to reach the top speed of the 80 lm/ hours, starting from the rest is 55.17 seconds.
We have rate = 1.45 and final velocity is 80
The formula to find the acceleration is,
a = v - u/t
t = v-u/a
Where, u = initial velocity
v = final velocity
a = acceleration
t = time taken
so,
t = 80 - 0/1.45
= 80/1.45
= 55.17 seconds
Then v is the final haste, u is the original haste, a is the acceleration and t is the time interval during which a body is under acceleration.
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Two large, charged plates with charge density ±30µC/m^2 face each other with a separation of 5.0 mm. The negative plate is grounded, and defined as 0 potential. Find the electric potential at a location 8.0mm from the negative plate, 3.0mm from the positive plate!
V=3.39×10⁶ ×d for 0≤d≤0.005 m, 7.73x10⁷ m/s is the electric potential at a location 8.0mm from the negative plate, 3.0mm from the positive plate
a. Identify the unknown:
The potential everywhere
List the Knowns:
Charge density of the two plates: σ = ±30×10⁻⁶ C/m²
Distance between the two plates: d=5×10⁻³ m
Permittivity of free space: ε₀=8.85×10⁻¹² C²/N⋅m²
Set Up the Problem:
Since the σ are equal and opposite, this means that in the region outside of the two plates, the electric fields cancel each other out to zero: E = 0 The electric field between the plates is this strong:
E = σ/ε₀ = 30×10⁻⁶/8.85×10⁻¹² = 3.39x10⁶N/C
Possible variations between the positive plate and the negative plate include:
ΔV=Ed=3.39×10⁶ ×0.005=1.7×10⁴ V
Assuming the negatively charged plate is at the origin (d=0) and has no potential, the electric field is directed away from the positively charged plate and towards the negatively charged plate, the positive plate is at (d=+0.005 m) and have 1.7×10⁴ V
Solve the Problem:
V=0 for d<0
V=3.39×10⁶×d for 0≤d≤0.005 m
V=1.7×10⁴ V for d>0.005m
b. Identify the unknown:
when an electron leaves a state of rest at the negative plate and strikes the positive plate, how quickly it moves
List the Knowns:
Electron charge: e=1.6×10⁻¹⁹ C
Electron mass: m=9.11×10⁻³¹ kg
Set Up the Problem:
Potential and electric potential energy have the following relationships: = U/q
U=qV
To move the drop, this potential energy is converted to kinetic energy:
1/2mv²=qV
v = √2qV/m
Solve the Problem:
v = √(2×1.6×10⁻¹⁹×1.7×10⁴/9.11×10⁻³¹) = 7.73x10⁷ m/s
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if the distance between two isolated parallel plates that are oppositely charged is doubled, the electric field between the plates is essentially unchanged. however, the:
The charged density of the parallel plates affects the electric field between them. The field between plates is 0 if they are neutral or 0 if they carry charges, depending on which way they are charged. While there is no field inside the sphere.
What is the electric field between the plates?The capacitor's two oppositely charged plates are separated by an electric field that is constant throughout, except the plate edges.
The electric field does not change since the space between the plates is smaller than their combined surface area.
Because the two parallel charged plates are kept apart from one another, a homogenous electric field is created there.
Therefore, Potentially, there will be a double differential between the plates.
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ta student does an experiment to check the mass of a cart. the student sends a 1.0-kg cart with a spring attached at the front end into a collision with a cart of unknown mass. after the collision, the student notes that the 1.0-kg cart moves forward with reduced speed, and the unknown cart moves forward at a faster speed than the 1.0-kg cart. what does this experiment show about the mass of the unknown cart?
The experiment shows about the mass of the unknown cart is The unknown cart is less than 1 kg.
A change in velocity with respect to time is called acceleration. The speed of the cart and the amount of time it needs to accelerate down the plane are two crucial factors.
Keep in mind that the acceleration increases as the height of the slanted plane increases. This demonstrates how crucial it is to understand the inclined plane's height.
The necessity of the timer is based on the fact that we also need to know how long it takes the body to decelerate from the aircraft.
In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
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An airplane flies with a constant speed of
540 miles per hour. How long will it take to travel a distance of 2160 miles?
Answer:
4 hours
Explanation:
2160 miles ÷ 540 miles/hr = 4
PLS ANSWERRR What are the main differences between the carbon flows 300 years ago and today?
The main differences between the carbon flow 300 years ago and today are the amount of carbon dioxide released into the atmosphere and the sources of those emissions.
300 years ago, the majority of carbon emissions came from natural sources, such as volcanic eruptions and forest fires. However, today, the majority of carbon emissions come from human activities, such as burning fossil fuels for energy and deforestation for agriculture and urbanization. Additionally, the amount of carbon dioxide released into the atmosphere has greatly increased in the past 300 years due to the industrialization of society and the increase in the human population. This has led to an increase in greenhouse gases in the atmosphere and has contributed to climate change.
In summary, the main differences between the carbon flow 300 years ago and today are the sources of emissions and the amount of carbon dioxide released into the atmosphere.
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