Answer:
Explanation:
The kinetic friction between crate and the surface can be calculated as follows: [tex]f_{k}=\mu_{k}N=\mu_{k}mg=(0.24)(2)(10)=4.8 N[/tex]
Assume that the direction of the 10 N constant force is on the right, the kinetic friction will go the left, then:
[tex]\sum F=F_{net}=F-f_{k}=10-4.8=5.2 N[/tex]
A constant force of 10 N is applied to a crate of mass 2 kg on a rough surface, then the net force on the crate is 5.2 N
What is friction?Friction is the resistance to a thing sliding or rolling over another solid object. Although frictional forces can be helpful, such as the traction required to walk without sliding, they also provide a significant level of resistance to motion.
The forces of attraction, also called as adhesion, between both the contact zones of the surfaces, that are always microscopically uneven, seem to be the main contributor to friction among metals.
These "welded" joints are sheared, and friction is created by the irregularities of a harder surface scuffing down against the softer surface.
From the given data in the question,
Firstly, calculate the friction between the crate and the surface,
[tex]f_k\\[/tex] = [tex]\mu_k[/tex]mg
= (0.24)(2)(10)
= 4.8 N
Now, let's calculate the net force,
ΣF = F(N) = F - [tex]f_k[/tex]
= 10 - 7.8
= 5.2 N
Therefore, the net force will be equal to 5.2 N.
To know more about Friction:
https://brainly.com/question/13000653
#SPJ2
A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away from the rod along its perpendicular bisector?
For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as
E1=1.598*10^11v/m
Generally, the equation for the initial electric field intensity is mathematically given as
[tex]dEp=\int{kd/r}cosd\theta[/tex]
Therefore
[tex]e1=kd/r{sin\theta2+sinR1}[/tex]
Hence
[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]
E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]
E1=1.598*10^11v/m
In conclusion, the electric field intensity
E1=1.598*10^11v/m
Read more about Electric field
https://brainly.com/question/9383604
Which of the following examples of the streets Newton second law of motion
Explanation:
Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
Which property of matter is conserved in chemical reactions and shown by balanced equations?
O mass
O volume
O density
O shape
Answer:
Mass.
Explanation:
I took the quiz and got the answer right
What is the effect of the Least Count on the precision/sensitivity of Vernier Callipers?
Answer:
Least count of vernier caliper=.1/50=.002 CM=.02 MM Least count and precision The least count is directly linked with precision. The smaller is the least count number, the more precise the instrument is.
Explanation:
Is a vernier scale accurate or precise? Every instrument has its accuracy defined as the least count of the instrument.As the least count of vernier callipers is 0.01mm,hence it is not accurate beyond the size measurement of 0.01mm.For which it may be called for vernier scale has presize measurement up to 0.01mm.Ans.. What is a vernier caliper?
PLEASE HELP, WILL MARK BRAINLIEST!!!!!!!
A mass m is dropped from height h above the top of a spring of constant k mounted vertically on the floor.
Find the spring's maximum compression.
Express your answer in terms of some or all of the variables: m , h , k , and gravitational constant g .
m*g/k (1 + √(1 + 2k*h/m*g))
Is this answer correct and why? Or is it something else?
I think your answer may be wrong.
The mass's potential energy at the start is mgh; this gets converted to kinetic energy as it falls (assuming no air resistance), so that by conservation of energy,
mgh = 1/2 mv² ⇒ v = √(2gh)
where v is the velocity of the mass when it first comes into contact witht he spring.
As the spring is compressed, it performs work on the mass as it slows to a rest at maximum compression. If x is the maximum compression, then the spring does -1/2 kx² of work. (negative since it opposes the downward fall)
By the work-energy theorem (total work is equal to change in kinetic energy),
-1/2 kx² = 0 - 1/2 mv²
Plug in v and solve for x :
kx² = m (√(2gh))²
x² = 2mgh/k
x = √(2mgh/k)
what’s is the vertical colum of the elements in the periodic table called
it is called groups or families.
Answer:
groups or families
Explanation:
The vertical column of the periodic table are called groups or famileis because of their similar chemical behavior.
Calculate the power developed by a 68.0 kg athlete who, in 20.0 seconds. runs up stairs that have a vertical height of 8.00 m
Potential energy:-
mgh68(8)(10)680(8)5440JNow
time=t=20sSo
Power:-
PE/t5440/20272W1- Show that the equation d=vt2
dimensionally correct or not?
If the intensity of radiation from an x-ray tube at 2 feet is 100 mR/min, the intensity at a distance of 5 feet will
be?
Answer:
100 mR
Explanation:
Two particles each with a charge of 1μC are separated a distance of 0.4 m. A test charge is placed just above them but directly between them. (b) What is the direction of the resultant electric field on the test charge?
Answer:
Forces on the test (test is positive) charge
Σ Fx = 0 net result of x-compoment charges is zero
Σ Fy = 2 F sin θ where F is the force due to the distance of the test charge from one of the charges and sin θ is the component of that force that is perpendicular to the line separating the charges
The direction of the force is perpendicular to the line separating the two given charges
5. What is the potential energy of a spring if the spring constant is 25.0 N/m and it is compressed to .5 m past its resting position?
Explanation:
Given: Required: solution:
k=25N/m PE ? PE= 1/2 × KX²
X= 5m 1/2 × (25)(5)²
= 312.5 J
Jaden rides his motorcycle at an average speed of 21 meters/second for 520 seconds , how far did he ride?
Answer:
10,920 meters
Explanation:
distance = speed × time
which is, d = 21 × 520
Answer:
10920
Explanation:
distance traveled= 21 (speed) ×520 (time)
=10920
How does the scintillation detector work?
Answer:
In scintillation detectors the material of the detector is excited to luminescence (emission of visible or near-visible light photons) by the absorbed photons or particles. The number of photons produced is proportional to the energy of the absorbed primary photon. The light pulses are collected by a photo- cathode.
Explanation:
Hope this helps :-)
Enjoy your day or night!
Have fun with your studies and assignments
ps. please don't give full credit to me I used references from other sites
<3 simplysun
15C of charge flow through the filament of a light bulb in 22 seconds. What is the strength of the current in the filament?
Answer:
Current(I)= charge(q)/time
I=15/22
I=0.680.68A
Explanation:
Current is flow of charge per unit time. Always make sure the time is in seconds. istthe
Which of the following objects would have the greatest: A. momentum if they were all moving with the same velocity? B. Inertia?
A compact car B school bus
C Pick-up truck D road bicycle
determine if a sentence is an argument?
Answer:
The tone really matters and if there are any exclamation marks also.
Explanation:
A wave has a frequency of 5hz and a wave speed of 25m/s what is the wavelength?
25 m
5 m
25 m/s
125 m
7- A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of 4 kg and a cross-sectional area of 35 cm^2. A compressed spring above the piston exerts a force of 60 N on the piston. If the atmospheric pressure is 95 kPa, Determine the pressure inside the cylinder.
What is the kinetic energy of a 1375 kg car that travels at 8.5 m/s
Answer:
49671.875
Explanation:
KE = [tex]\frac{1}{2}m[/tex][tex]v^{2}[/tex]
KE = 0.5(1375)(8.5)
= 49671.875 J
A potter's wheel is spinning with an initial angular velocity of 11 rad/s . It rotates through an angle of 80.0 rad in the process of coming to rest.
What was the angular acceleration of the wheel?
How long does it take for it to come to rest?
Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:
1 rotation = 2π rad1 rps = 2π rad/s1 rpm = [tex] \sf{\frac{1}{60} \: rps}[/tex] = [tex] \sf{\frac{1}{30}\pi \: rad/s}[/tex] Formula UsedThe following equations apply to proportionally changes circular motion:
Relationship between Angular Acceleration and Change of Angular Velocity[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]
With the following conditions:
[tex]\sf{\omega_t}[/tex] = final angular velocity (rad/s)[tex]\sf{\omega_0}[/tex] = initial angular velocity (rad/s)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)Relationship between Angular Acceleration and Change of [tex]\sf{\theta}[/tex] (Angle of Rotation)[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]
Or
[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]
With the following condition :
[tex]\sf{\theta}[/tex] = change of the sudut (rad)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)[tex]\sf{\omega_t}[/tex] = final angular velocity (rad/s)[tex]\sf{\omega_0}[/tex] = initial angular velocity (rad/s) Problem SolvingWe know that :
[tex]\sf{\omega_t}[/tex] = final angular velocity = 0 rad/s >> see in the sentence "in the process of coming to rest."[tex]\sf{\omega_0}[/tex] = initial angular velocity = 11 rad/s[tex]\sf{\theta}[/tex] = change of the sudut = 80.0 radWhat was asked :
[tex]\sf{\alpha}[/tex] = angular acceleration = ... rad/s²t = interval of the time = ... sStep by step :
[tex]\sf{\alpha}[/tex] = ... rad/s²[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]
[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]
[tex] \sf{0 = 121 + 160 \alpha} [/tex]
[tex] \sf{-160 \alpha = 121} [/tex]
[tex] \sf{\alpha = \frac{121}{-160}}[/tex]
[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]
t = ... s[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]
[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]
[tex] \sf{-0.76t = -11}[/tex]
[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]
[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]
ConclusionSo :
The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 5.0 × 10 seconds, what is the value of impulse
A.
0.26 newton seconds
B.
0.58 newton seconds
C.
1.82 newton seconds
D.
2.20 newton seconds
A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is [tex] \sf{5.0 \times 10^{-4}} [/tex] seconds, what is the value of impulse ?
So, the value of impulse is (A). 0.26 newton seconds.
IntroductionHi ! Here, I will help you about the impulse. Impulse is described as a quantity which expresses the integral of the amount force respect to time. The amount of impulse will be proportional to the amount of force or time (the greater value of the force or the value of time, the value of impuls is greater too). The relationship between impulse, force, and time is expressed in this equation :
[tex] \boxed{sf{\bold{I = F \times \Delta t}}} [/tex]
With the following condition:
I = impulse that occurs (N.s)F = force that given (N)[tex] \sf{\Delta t} [/tex] = interval of the time (s) Problem SolvingWe know that :F = force that given = 520 N[tex] \sf{\Delta t} [/tex] = interval of the time = [tex] \sf{5.0 \times 10^{-4} \: s}[/tex]What was asked :
I = impulse that occurs = ... N.sStep by step :
[tex] \sf{I = F \times \Delta t} [/tex]
[tex] \sf{I = 520 \times (5.0 \times 10^{-4}} [/tex]
[tex] \sf{I = 2,600 \times 10^{-4}} [/tex]
[tex] \sf{I = 2.60 \times 10^3 \times 10^{-4}} [/tex]
[tex] \sf{I = 2.60 \times 10^{3 + (-4)}} [/tex]
[tex] \sf{I = 2.60 \times 10^{-1} = \boxed{0.26 \: N.s}} [/tex]
Conclusion :So, the value of impulse is (A). 0.26 newton seconds
A rock is suspended from the lower end of a light string. When the rock is totally immersed in water, the tension in the string is 1.20 N. When the rock is totally immersed in ethanol, the tension in the string is 1.60 N. Calculate the weight of the rock.
For a rock is suspended from the lower end of a light string, the weight of the rock is mathematically given as
W = 3.10 N
What is the weight of the rock.?Generally, the equation for the W = Fh1+ is mathematically given as
W = Fh+T1
Where
PiVg+T1 = P2V9+T
(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6
V = 1.944* 10^-4 m3
In conclusion
W = Fh+T1
W = (1000) (1.944 * 10-4) (9.8) + 1.2
W = 3.10 N
Read more about Weight
https://brainly.com/question/11408596
Hello, please help!
Physics teacher asked us to answer and give explanation to why:
Can light bend around corners?
THNX SO MUCH
Answer:
Yes, light can bend around corners.
Explanation: In fact, light always bends around corners to some extent. This is a basic property of light and all other waves. The amount of light that bends around a corner depends on the exact situation.
Thanks for asking the question!!
You ride your bike north for 100 m at a constant speed of 5 m/Your acceleration is…
Answer:
our acceleration is 0 because there is a constant speed..
a = final speed - initial speed / time
final speed = initial speed ( since speed is constant)
therefore acceleration is 0
In the image, not to scale, which phase of the moon would you observe from earth?
Answer:
The "new" moon phase is being shown because the moon shown is directly between the sun and earth and is not visible from the earth because of the brightess of the sun.
What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second
Answer:
42
Explanation:
P = M × V
so
P = 35 × 1.2
P = 42
Answer:
42kg•m/s
Explanation:
p=m*v
Give Reason during change of state,the temperature remains constant
Answer:
the substance has lost or gained an ion
Explanation:
I say substance be cause I'm referring to the item are the same are similar to the substances that make up make matter like the ones on the periodic table!
what does a snow leopard eat?
Answer:
They eat Himalayan blue sheep, boar, deers, wild mountain goats, pikas etc.
Explanation:
please answer this question
Answer:
The circuits that were made previously were large and bulky, consisting of circuit components like resistor, capacitor, inductor, transistor, diodes, etc., which were connected with copper wires.
Explanation:
I am in confusion with mono electronic circuit and I am not want to made u confused person.
I am really sorry brother.
:-befrank
Find the Product or expression of:
(6x+4)2
Answer:
20 or 12
Explanation:
if it is 20 u will have to multiple 6 by 4 and the answer u will multiple it by2 and when it is 12 u will have to add 6 +4 and the answer u will add it to 2