A construction worker earns and average biweekly net pay of $1,764. Which compound inequality correctly shows the amount of money, t, the worker can spend if the monthly budget for food is between 10% and 20% ?

Answer:

x= 40 degree

y = 80 degree

Step-by-step explanation:

where is z?

The population in the year 2000 is 395.808

Exponential Function

Exponential functions have the form f(x) = bx, where b > 0 and b ≠ 1. Just as in any exponential expression, b is called the base and x is called the exponent. An example of an exponential function is the growth of bacteria. Some bacteria double every hour

Where t is the number of months since the population was first recorded. And the population after 36 months so we need to replace t=36 months into the function

Probability

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates certainty.

So then can conclude that after 38 months the population of mouse is between 1963 and 2000.

A(t)=336e^(0.031t)

The population can be represented with this formula:

A(38)=336e^(0.031*38)

Where t is the number of months since the population was first recorded. And  the population after 38 months so we need to replace t=38 months into the function and we got:

A(38)=336e^(0.031*38)

A(38)=336e^(1.178)

       =395.808

So then can conclude that after 38 months the population of mouse is between 1963 and 2000.

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the inverted coefficient matrix is

[tex]\left[\begin{array}{ccc}2&-1&-5\\3&-2&5\\-3&5&2\end{array}\right][/tex]

1. The inverted coefficient matrix is found by taking the inverse of the coefficient matrix.

3x1 + x2 = 4

5x1 + 2x2 = 7

3. Therefore, the inverted coefficient matrix is

2 -1 -5

3 -2 5

-3 5 2

It is used to represent and manipulate complex data, such as linear equations, vectors, and polynomials. A matrix can also be used to represent a system of linear equations or to graph a function. Matrices are key elements in linear algebra, a branch of mathematics that studies vector spaces, linear transformations, and systems of linear equations.

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The equivalent fraction of 1/2 is 2/4 and equivalent fraction of 1/3 is 2/6.

Given that,

Why are the fractions 1/2 and 2/4 referred to as identical, and what fractional value does 1/2 equal? What is 1/3's equivalent in fractions

The fractions 2/4, 3/6, 4/8, etc. are identical to 1/2. Reduced fractions of equivalent fractions have the same value. Simply multiplying or dividing both the numerator and the denominator by the same number produces equivalent fractions.

By multiplying the numerator and denominator of each fraction by the same number, we can determine the equivalent fraction for each fraction. For instance, we must multiply 2/3 by 3/3 after determining the third equivalent fraction of 23. Consequently, 2/3 (3/3) = 6/9 is the fraction that equals 2/3.

As a result, the equivalent fractions of 1/2 and 1/3 are 2/4 and 2/6, respectively.

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The circle equation in standard form is (X - 3)² + (Y - 1)² = 2²

How to change the circle equation into standard form?

We must transform the current polynomial to circle standard form:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

We will do so by completing the square, which produces a perfect square trinomial that can be factored into a square binomial in the form of the circle standard form.

According to the given question:

Equation of circle in polynomial form is X²+ Y²- 6X - 2Y + 6 = 0

Converting to standard form using completing the square method

X²+ Y²- 6X - 2Y + 6 = 0

(X² - 6X) + (Y² - 2Y) = -6

(X² - 6X + 9) + (Y² - 2Y + 1) = -6 + 9 + 1

(X - 3)² + (Y - 1)² = 4

(X - 3)² + (Y - 1)² = 2²

The circle is now in standard form.

Coordinates of the center (h,k) = (3, 1)

Coordinates of the vertices = (3, 1), (3, -6), (2, -4), (8, -1)

Domain = [2, 8]

Range = [-6, 1]

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1. Using division operations, Amy's monthly budget for textbooks and course supplies is $100.

2. Amy's monthly budget for rent, utilities, and food is $1,422.

3. Amy's monthly budget for personal and miscellaneous costs is $251.

4. Amy's total monthly budget is $1,825

The total monthly budget is the total budget divided by the period (nine months).

We can use division operations to determine the individual monthly budgets for each expense class.

Textbooks and Course Supplies =         $900      $100

Rent, Utilities, and Food =                   $12,798   $1,422

Personal & Miscellaneous Expense = $2,259     $251

Transportation =                                      $468       $52

Total non-tuition expenses =             $16,425  $1,825 ($16,425/9)

The number of months = 9 months

Monthly expenses = $1,825

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9482.7 must Joe invest today to receive $22,000 each year for the next 22 years.

percentage, a relative value indicating hundredth parts of any quantity.

Given,

Joe Jan wants to receive $22,000 each year for the next 22 years.

6% interest rate compounded annually.

Convert 6% to decimal value

6/100=0.06

A=P(1+rt)

22000=P(1+0.06(22))

22000=P(1+1.32)

22000=P(2.32)

Divide both sides by 2.32

P=9482.7

Hence, 9482.7 must Joe invest today to receive $22,000 each year for the next 22 years.

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Answer:

Yes

Step-by-step explanation:

y-8= -8(x-2)  ==> solve for y

y = -8(x - 2) + 8  ==> add 8 on both sides to isolate y

y = (-8 * x - 2(-8)) + 8  ==> distribute -8 to x and -2 using the distribution

                                         property

y = (-8x - (-16)) + 8 ==> simplify

y = (-8x + 16) + 8  ==> subtracting by a negative number is equivalent to

                               adding by a positive number.

y = -8x + 16 + 8

y = -8x + 24  ==> Degree of x in the equation is 1, so the function is linear

The right tail of the chi-square distribution curve's value for 19 degrees of freedom and an area of 0.010 is 3.162.

To find the value of chi-square for 19 degrees of freedom and an area of 0.010 in the right tail of the chi-square distribution curve, we need to consult a chi-square distribution table. The table will list the chi-square values corresponding to different degrees of freedom and areas of the right tail of the distribution. In this case, the table should list the chi-square value corresponding to 19 degrees of freedom and an area of 0.010 in the right tail of the distribution. The value of this chi-square is 3.162, which is the exact answer from the chi-square distribution table.

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The function is increasing for all real values of x where

x < –1 and where x > 4.

What is increasing and decreasing functions?

Calculus uses a function's derivative to determine whether a function is increasing or decreasing at various intervals in a specific domain. For a given function, y = F(x), the function is known as an increasing function if the value of y increases as the value of x increases, and the function is known as a decreasing function if the value of y decreases as the value of x increases.

Given function is

f(x) = (x - 4)(x + 1)

If f(x) = 0,  x=4 & x=-1

f'(x) = 0, x=3/2

So, we will check the behavior of the function in the neighborhood of  x=4,-1, 3/2.

What is the increasing and decreasing function?

A function is said to be an increasing function if its slope is continuously increasing in a given interval.

A function is said to be a decreasing function if its slope is continuously decreasing in a given interval.

If x>4

Let us check at x=5

f(5) =6(+ve)

f(x) >0 for x>4

So, the function is increasing in x>4

Similarly, If x <-1

f(x) >0 for  x <-1

So, function is increasing in x <-1

If -1<x<3/2

f(x)<0 for -1<x<3/2

So, function is decreasing in -1<x<4

If 3/2<x<4

f(x)>0 for 3/2<x<4

So, the function is increasing in 3/2<x<4

From the graph too, we can see the behavior of the given function

by observing the slope.

We can see that for x<-1 and x>4, the slope is continuously increasing

So, the function is increasing in x<-1 and x>4.

Therefore, the function is increasing for all real values of x where

x < –1 and where x > 4.

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fn is an integrable function on [a, b]. further, assume that the sequence (fn) converges uniformly to f on [a, b]. f is integrable on integral [a, b].

Let ε > 0. Since (fn) converges uniformly to f on [a, b], there exists an N such that |fn(x) - f(x)| < ε for all x ∈ [a, b] and all n ≥ N.

Since fn is integrable on [a, b], it follows that

∫a b|fn(x)|dx < ∞ for all n ≥ N.

We have

∫a b|f(x)|dx ≤ ∫a b|fn(x)|dx + ∫a b|fn(x) - f(x)|dx

Since |fn(x) - f(x)| < ε, it follows that

∫a b|f(x)|dx ≤ ∫a b|fn(x)|dx + ε(b - a)

Since the right hand side is finite, it follows that ∫a b|f(x)|dx is finite. Hence, f is integrable on integral [a, b].

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The congruency of the right triangles by the Hypotenuse-Leg Congruency Theorem can be made true by the following sides.

1. [tex]\overline{RP}[/tex] ≅ [tex]\overline{MF}[/tex] and   [tex]\overline{DP}[/tex] ≅ [tex]\overline{QF}[/tex]

2. [tex]\overline{CI}[/tex] ≅ [tex]\overline{CE}{}[/tex] and    [tex]\overline{AI}[/tex] ≅ [tex]\overline{GE}[/tex]

3. [tex]\overline{TR}[/tex] ≅  [tex]\overline{RT}[/tex]  and  ;[tex]\overline{TQ}[/tex] ≅ [tex]\overline{RS}[/tex]

4. [tex]\overline{DG}[/tex] ≅  [tex]\overline{KN}[/tex] and  [tex]\overline{AD}[/tex] ≅ [tex]\overline{HK}[/tex]

Two right triangles are congruent if  the hypotenuse side and one leg  of one triangle is congruent to  the hypotenuse side and one leg of the other triangle.

The hypotenuse leg congruency theorem states that two right triangles are congruent if the hypotenuse and one leg of one triangle are congruent to the hypotenuse and one leg of the other triangle

The hypotenuse side of ΔDPR = [tex]\overline{RP}[/tex]
The hypotenuse side of ΔQMF = [tex]\overline{MF}[/tex]

The corresponding legs of both triangles are;

[tex]\overline{DP}[/tex] corresponds to [tex]\overline{QF}[/tex]

[tex]\overline{DR}[/tex] corresponds to [tex]\overline{MQ}[/tex]

Therefore, ΔDPR is congruent to ΔQFM if  [tex]\overline{RP}[/tex] ≅ [tex]\overline{MF}[/tex]

And the leg  [tex]\overline{DP}[/tex] ≅ [tex]\overline{QF}[/tex] or  [tex]\overline{DR}[/tex] ≅ [tex]\overline{MQ}[/tex]

2. The sides that makes the congruency statement, ΔACI ≅ ΔGCE are found as follows;

The hypotenuse side of  ΔACI = [tex]\overline{CI}[/tex]

The hypotenuse side of triangle ΔGCE = [tex]\overline{CE}{}[/tex]

Therefore,

ΔACI ≅ ΔGCE ican be proved when    [tex]\overline{CI}[/tex]  is congruent to [tex]\overline{CE}{}[/tex], and

 [tex]\overline{AI}[/tex]  is congruent to [tex]\overline{GE}[/tex] or    [tex]\overline{AC}[/tex]  is congruent to [tex]\overline{CG}[/tex]

3. In the figure the specified information are;

[tex]\overline{TR}[/tex] is congruent to [tex]\overline{RT}[/tex] by reflexive property

The triangles are congruent if either;[tex]\overline{TQ}[/tex] iis congruent to [tex]\overline{RS}[/tex] or;[tex]\overline{TS}[/tex] iis congruent to [tex]\overline{RQ}[/tex]

4. The appropriate sides that can be used to prove that  ΔADG ≅ ΔHKN  are the hypotenuse side of both triangles;[tex]\overline{DG}[/tex] and  [tex]\overline{KN}[/tex]

and either the legs; [tex]\overline{AD}[/tex] and [tex]\overline{HK}[/tex] or  [tex]\overline{AG}[/tex] and  [tex]\overline{HN}[/tex]

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,

Correct option is A

Independent variable

Independent variable is manipulated by the researcher to determine the effect of its change relative to a change in dependent variable.

Independent Variables

An independent variable is exactly what it sounds like. It is a variable that stands alone and isn't changed by the other variables you are trying to measure. For example, someone's age might be an independent variable.

In an experiment the independent variable is the variable that is varied or manipulated by the researcher. The dependent variable is the response that is measured. One way to think about it is that the dependent variable depends on the change in the independent variable.

Qualitative research consist in observing some variables and obtaining information. Usually the qualitative research does not involve the manipulation of independent variables, these types of researches focuses more in collecting answers in groups of people, and making statistics with those answers or information. So the variables are not manipulated.

Correct option is A

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Equations are not equivalent because the values are found to be different.

What is an expression?

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Expressions are:

(9a - 27) - 4 = 9a  - 31 -------(I)

and -3(- 4 - 3) = -3(-7) = 21 -----(II)

From (I) and (II), expressions are not equivalent.

Hence, equations are not equivalent because the values are found to be different.

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On solving the provided question we got to know that - Thus, the temperature will be 14°C below zero at midnight.

Since equations are essentially questions, efforts to systematically find answers to those questions have been the driving force behind the development of mathematics. From straightforward algebraic equations that just require addition or multiplication to differential equations, exponential equations that use exponential expressions, and integral equations, there are many different types of equations that range in complexity.

The answer to the query is provided as,

Temperature at the start, or at midday, is 10°C.

Temperature change at a rate of 2°C per hour

Then,

[tex]Temperature at 1 PM = 10 + (-2) = 10 - 2 = 8[/tex] °C

[tex]Temperature at 2 PM = 8 + (-2) = 8 -2 = 6\\[/tex]°C

[tex]Temperature at 3 PM = 6 + (-2) = 6 - 2 = 4\\[/tex]°C

[tex]Temperature at 4 PM = 4 + (-2) = 4 - 2 = 2\\[/tex]°C

[tex]Temperature at 5 PM = 2 + (-2) = 2 - 2 = 0\\[/tex]°C

[tex]Temperature at 6 PM = 0 + (-2) = 0 -2 = -2\\[/tex]°C

[tex]Temperature at 7 PM = -2 + (-2) = -2 -2 = -4\\[/tex]°C

[tex]Temperature at 8 PM = -4 + (-2) = -4 – 2 = -6\\[/tex]°C

[tex]Temperature at 9 PM = -6 + (-2) = -6 – 2 = -8[/tex]°C

At nine o'clock at night, it will be eight degrees below zero.

Then,

the temperature at 12 AM, or midnight

Temperature change over 12 hours = -2°C divided by 12 equals - 24°C

Therefore, the temperature at midnight will be 10 + (-24)

= - 14°C

Thus, the temperature will be 14°C below zero at midnight.

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The function that represents how much more water can be added to the bucket before it overflows is given as follows:

c(x) = 6x³ + 3x² - 2x - 2.

The function to calculate the space remaining in the pool is given by the subtraction of the capacity function by the function representing the current amount of water in the pool.

The functions in this problem are defined as follows:

Then the capacity function is obtained as follows:

c(x) = f(x) - g(x)

c(x) = 8x³ + 4x² - 6x + 5 - (2x³ + x² - 4x + 7)

Then the distributive property is applied to the negative sign as follows:

c(x) = 8x³ + 4x² - 6x + 5 - 2x³ - x² + 4x - 7.

Finally, the like terms are combined, that is, the terms that have the same variable and exponent, as follows:

c(x) = 6x³ + 3x² - 2x - 2.

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Answer:0

Step-by-step explanation:

By adding like terms,

4√13 and -4√13 equal to 0, and √17 and -√17 equal 0

The magnitude of u + v is 6.08 and the direction of the vector u + v is 4.7°.

What is rounded to the nearest tenth?

To write a decimal number up to one decimal place, round it to the nearest tenth. This is done in a way that leaves one digit after the decimal point after rounding.

Given that vector u is 7 (cos 330°, sin 330°)

Vector v equal to is 4 (cos 90°, sin 90°)

Calculating the value of cos 330° and  sin 330°:

cos 330°

= cos (3×90° + 60°)

= sin 60°

= √3/2

sin 330°

= sin (3×90° + 60°)

= -cos 60°

= -1/2

The vector u can be written as 7 (cos 330°, sin 330°) = 7(√3/2, -1/2) =(7√3/2, -7/2) = 7√3/2 i - 7/2j

The vector v can be written as 4 (cos 90°, sin 90°) = 4(0,1) = (0,4) = 0i + 4j

Add vector u and v:

u + v

= 7√3/2 i - 7/2j +  0i + 4j

= 7√3/2 i + 1/2 j

= 6.06 i + 0.5 j

The magnitude of the vector  u+v is √( 6.06² + .5²) = 6.08

The angle is

tan θ = y/x

tan θ =0.5/6.06

θ = 4.7°

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Answer: 980

Step-by-step explanation: 20 = 2 x 2 x 5

245 = 5 x 7 x 7

70 = 2 x 5 x 7

= 2 x 2 x 5 x 7 x 7

= 980.

Greatest common divisor: 5

The difference operation in set removes every common element between the set and give the remaining element of first set. The answer is True.

In mathematics, a set is a logically arranged group of items that can be represented in either set builder or roster form.

The set that contains the items of S that are not elements of T is the difference between the two sets, denoted by the symbol S-T.

set1={1,2,3,4,5}

set2={4,5,6,7}

Set Difference= set1-set2 = {1,2,3}

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Answer:

warmth

Step-by-step explanation:

they migrate to stay warm I hope you do good (:

Answer:

To find a warmer place for nesting grounds or migration.

Step-by-step explanation:

Answer:

It will take approximately 36.4 weeks for Melissa and Chris to have the same amount of money.

Step-by-step explanation:

To determine how many weeks it will take for Melissa and Chris to have the same amount of money, you can set up an equation based on the information given. Let W be the number of weeks it takes for Melissa and Chris to have the same amount of money.

Melissa's total amount of money after W weeks will be 5000 + 20W.

Chris's total amount of money after W weeks will be 6820 - 50W.

Therefore, you can set up the equation 5000 + 20W = 6820 - 50W and solve for W.

First, you can add 50W to both sides of the equation to get 50W + 5000 = 6820.

Next, you can subtract 5000 from both sides of the equation to get 50W = 1820.

Finally, you can divide both sides of the equation by 50 to get W = 36.4.

If the owner's beliefs are correct,  Event A and Event B are not mutually exclusive and are independent and must be true for event A and event B.

Simply put, the probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes.

By simply dividing the favorable number of possibilities by the entire number of possible outcomes, the probability of an occurrence can be determined using the probability formula. Because the favorable number of outcomes can never exceed the entire number of outcomes, the chance of an event occurring might range from 0 to 1. Additionally, the proportion of positive outcomes cannot be negative. In the sections that follow, let's go into greater detail on the fundamentals of probability.

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The table which represents the equation of the proportional relationship as described is;

Sugar Flour

two fifths 1

four fifths 2

It follows from the task content that the table which represents the proportional relationship is to be identified among the given answer choices.

Since the given relationship is defined by the equation;

s = (2/5) f.

Hence, when f = 1; s = (2/5) • 1; s = 2/5.

Also, when f = 2; s = (2/5) • 2 = 4 / 5.

Therefore, the table which represents the equation of the proportional relationship is;

Sugar Flour

two fifths 1

four fifths 2

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The values of v for the electric impulse model in the Fitzhugh-Nagumo model are 0, 1, and a.

The strength of the field is shown by the distance between the lines; the closer they are to one another, the stronger the field.

In this scenario, the field weakens as we travel away from the charge because the distance between the lines widens (it actually obeys an inverse square law,

The electric field, which is pointed away from the core charge, is indicated by the direction of the lines.

This is due to the fact that a positive test charge would be repelled away from the electric field if it were placed there because the direction of the electric field corresponds to the direction of the force that a positive test charge would experience when immersed in the electric field.

Hence, The values of v for the electric impulse model in the Fitzhugh-Nagumo model are 0, 1, and a.

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The value for  given trigonometric functions are csc 30° = 2, cot 60°  = √3/3, cos 30 ° = √3/2, and cot 30° = √3.

A branch of mathematics called trigonometry examines correlations between side lengths and angles of the triangle. Trigonometric Identities are equality conditions that apply to all values of the variables in the equation and which require trigonometry functions.

Given, sin 30° = 1/2 and tan 30° = √3/3.

The formula for csc or cosec x = 1/sinx.

Then,

[tex]\begin{aligned}\csc 30^{\circ} &=\frac{1}{\frac{1}{2}}\\&=2\end{aligned}[/tex]

The formula for cot θ = tan(90°- θ)

Then,

[tex]\begin{aligned}\cot 60^{\circ} & = \tan(90^{\circ}-60^{\circ}) \\&= \tan 30^{\circ}\\&=\frac{\sqrt{3}}{3}\end{aligned}[/tex]

The formula for cos θ = sin θ/tan θ.

Then,

[tex]\begin{aligned}\cos 30^{\circ} &= \frac{\sin 30^{\circ}}{\tan 30^{\circ}}\\&= \frac{\frac{1}{2}}{\frac{\sqrt{3}}{3}}\\&=\frac{3}{2\sqrt3}\times \frac{\sqrt3}{\sqrt3}\\&=\frac{\sqrt3}{2} \end{aligned}[/tex]

The formula for cot θ = 1/tan θ.

Then,

[tex]\begin{aligned}\cot 30^{\circ}&=\frac{1}{\tan30^{\circ}}\\&=\frac{1}{\frac{\sqrt3}{3}}\\&=\frac{3}{\sqrt3}\times\frac{\sqrt3}{\sqrt3}\\&=\sqrt{3}\end{aligned}[/tex]

Therefore, the answers are 2, √3/3, √3/2, and √3.

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The angle between the two sides of lengths a and b that maximizes the area of the triangle is θ = π/2.

The area of a triangle whose sides of lengths a and b with an angle θ between them is

A = 1/2ab sinθ

The given triangle has two sides of lengths a and b.

Consider θ is the angle between the a and b sides. Then the area of the triangle is

A = 1/2ab sinθ

For maximizing the area of the triangle, derivating the area we have and equate to zero i.e.,

dA/dθ = 0

⇒ dA/dθ = 1/2 ab cosθ = 0

⇒ cosθ = 0

∴ θ = π/2

And the condition for the maximum area is d²A/dθ² < 0.

I.e., d²A/dθ² = -1/2ab sinθ

⇒ d²A/dθ² = -1/2ab sin(π/2) = -1/2ab < 0

So, the maximum area is  

Δ(max) = 1/2 ab sin(π/2) = 1/2ab

Thus, the angle between the two sides of lengths a and b of a triangle is π/2 when its area is maximum.

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Answer:

y - 2.5 = 2(x - 1)

Step-by-step explanation:

Here given slope is 2 and the point through which the straight line passes is (1, 2.5)

Let the equation be y = mx + c where m and c represent slope and y intercept respectively.

We know the slope, so we input that in our equation

y = 2x + c ------- i

This straight line also passes through (1, 2.5)

Putting the values in place of x and y we get,

2.5 = (2X1) + c

⇒ 2.5 = 2 + c

⇒ c = 2.5 - 2

⇒ c = 0.5

Now, putting value of c in i, we get

y = 2x + 0.5 -------- ii

It can also be written as y - 2.5 = 2(x - 1) ------- iii

this equation and ii are same and you can verify that by simplifying iii, by multiplying 2 and then shifting the -2.5 from LHS to RHS

The difference between living with family and on campus is 27299 and she will be able to save an average of $4549.9 every month.

To determine how much she will save, we have to find the total cost of living with parents or relative and the cost of living on/off campus and then divide it by the total number of months which is six and the find their difference.

The total cost of living with parents or relative for 6 months is = 900 + 4158 + 2259 + 675 + 11205 + 19197 + 36587 + 44579 = 119560

The cost of living on or off campus for 6 months = 900 + 12798 + 2259 + 468 + 11205 + 27630 + 36587 + 55012 = 146859

The average cost of living with relative or family for 6 months = 119560 / 6 = 19926.6

The average cost of living on or off campus for 6 months = 146859 / 6 = 24476.5

The difference is = 24476.5 - 19926.6 = 4549.9

Amy will save approximately $4549.9 monthly

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if a polygon layer and a line layer are intersected, the geometry of the output feature class may be chosen as either a polygon or a line.

If the line layer is used to clip the polygon layer, the output feature class will be a polygon feature class that contains the part of the polygon layer that intersects with the line layer. The output will be a polygon feature class that contains the same attributes as the input polygon layer, plus a new attribute field indicating the line layer's object ID (OID) that was used to clip the feature. If the line layer is used to split the polygon layer, the output feature class will be a line feature class that contains the line features that were used to split the input polygon layer. The output will be a line feature class that contains the same attributes as the input line layer, plus a new attribute field indicating the polygon layer's OID that was used to split the features.

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