a. The estimated value of ∬Rf(x,y)dA is 105
b. The estimated average value of the function f(x, y) is 7.
a. The rectangle R=[−3,6]×[−1,4] is divided into m = 2 subintervals along the x-axis and n = 3 subintervals along the y-axis. Therefore, each subinterval has a width of Δx = (6 - (-3))/2 = 9/2 and a height of Δy = (4 - (-1))/3 = 5/3.
We can calculate the midpoint of each subrectangle using the formula:
[tex]x_i = x_min + (i - 0.5) * \Delta x\\y_j = y_min + (j - 0.5) * \Delta y[/tex]
where i = 1, 2, ..., m and j = 1, 2, ..., n.
Using the midpoint rule, the estimate of the double integral is given by:
∬Rf(x,y)dA ≈ Δx * Δy * ∑∑[tex]f(x_i, y_j)[/tex]
where the double summation is taken over all the midpoints (x_i, y_j) of the subrectangles.
Calculate the midpoints of the subrectangles.
[tex]x_1 = -3 + (1 - 0.5) * (9/2) = -3 + 4.5 = 1.5\\x_2 = -3 + (2 - 0.5) * (9/2) = -3 + 9 = 6\\y_1 = -1 + (1 - 0.5) * (5/3) = -1 + (1/2) * (5/3) = -1 + 5/6 = -1/6\\y_2 = -1 + (2 - 0.5) * (5/3) = -1 + (3/2) * (5/3) = -1 + 5/2 = 9/2\\y_3 = -1 + (3 - 0.5) * (5/3) = -1 + (5/2) * (5/3) = -1 + 25/6 = 19/6[/tex]
Evaluate the function at each midpoint.
[tex]f(x_1, y_1) = 2\\f(x_1, y_2) = -1\\f(x_1, y_3) = 0\\f(x_2, y_1) = 1\\f(x_2, y_2) = 3\\f(x_2, y_3) = 2[/tex]
∬Rf(x,y)dA ≈ Δx * Δy * ∑∑[tex]f(x_i, y_j)[/tex]
= (9/2) * (5/3) * (2 + (-1) + 0 + 1 + 3 + 2)
= (9/2) * (5/3) * 7
= 15 * 7
= 105
b. To estimate the average value of the function f(x, y), we can divide the double integral by the area of the rectangle R, which is A = Δx * Δy * m * n.
The average value is then given by:
f_ave ≈ (∬Rf(x,y)dA) / A
Now let's perform the calculations:
Step 1: Calculate the area of the rectangle.
A = Δx * Δy * m * n
= (9/2) * (5/3) * 2 * 3
= 15
Step 2: Calculate the average value.
f_ave ≈ (∬Rf(x,y)dA) / A
= 105 / 15
= 7
Therefore, the estimated value of ∬Rf(x,y)dA is 105 and the estimated average value of the function f(x, y) is 7.
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