A count of patients needing a blood transfusion in the emergency room at a city hospital would best be modelled by what
distribution?
A. geometric
B. continuous
C. normal
D. Poisson

You are given the equation

A(t) = P*e^(rt)

Where P = Principal

r = interest rate

t = time

e is a mathematical constant equivalent to approx 2.71828

You're told the initial Principal is $500, the interest rate is 3%, over 6 years. So you have everything that you need to solve the problem, just plug in the values and solve for A(6)

A(t) = P*e^(rt)

A(6) = 500 * e^(0.03 * 6)

A(6) = 500 * e^(0.18)

A(6) = 500 * 2.71828^(0.18)

A(6) = 500 * 1.19721

A(6) = 598.60861

So $500 invested 6 years ago at 3% would be worth $598.61 today.

Plug in the points and see if they satisfy the equation.

y = 2x - 3

(1, -1)

-1 = 2(1) - 3

-1 = 2 - 3

-1 = -1

So (1, -1) satisfies the equation.

(-3, 0)

0 = 2(-3) - 3

0 = -6 - 3

0 = -9

So (-3, 0) does not satisfy the equation.

(5, 4)

4 = 2(5) - 3

4 = 10 - 3

4 = 7

So (5, 4) does not satisfy the equation.

Therefore your answer is (1, -1).

Answer:

the answer is 5,4

The values of x and y at t=3 are -4.95 and 0.423 respectively.

The value of dx/dt and dy/dt are 0.71 and -2.97 respectively.

The value of the tangent slope at t=3 is 4.21.

The speed at t=3 is 3.05 units/sec.

Given the equation of x as the function of t is

x= 5 cos t

similarly, the equation of y as the function of t is

y= 3 sin t

At t=3 the value of x will be

x (at t=3) = 5 cos 3= 5(-0.989)= -4.95

At t=3 the value of y will be

y (at t=3) = 3 sin 3= 3(0.141)= 0.423

The derivative of the function of x with respect to t will be

dx/dt= d(5 cos t)/dt= 5d(cos t)/dt= -5 sin t

at t=3 the value of dx/dt will be

dx/dt (at t=3) = -5 sin 3= -5(0.141)= 0.71

The derivative of the function of y with respect to t will be

dy/dt= d(3 sin t)/dt= 3d(sin t)/dt= 3 cos t

at t=3 the value of dy/dt will be

dy/dt (at t=3) = 3 cos t= 3(-0.989)= -2.97

The tangent slope is dy/dx which can be calculated by

dy/dx= (dy/dt)(dt/dx)= (dy/dt)/(dx/dt)= 3 cos t/ -5 sin t=  (-3/5) cot t

at t=3 the value of tangent slope will be

dy/dx (at t=3) = (-3/5) cot 3= 4.21

The speed at t=3 will be

speed v= [tex]\sqrt{v_{x} ^{2} + v_{y} ^{2} }[/tex]

= √(dx/dt)²+(dy/dt)²

at t=3

= √(0.71)²+(-2.97)²

= √9.325

= 3.05 unit/sec

Therefore the values of x and y at t=3 are -4.95 and 0.423 respectively.

The value of dx/dt and dy/dt are 0.71 and -2.97 respectively.

The value of the tangent slope at t=3 is 4.21.

The speed at t=3 is 3.05 units/sec.

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Answer:

512? xd

Step-by-step explanation:

Answer:

128

Step-1by-step explanation:

An easy way of solving these sort of problems is to set up an equation

Since we have a total, that being 512 burgers, we can set an equation equal to that number.

We can say that hamburgers is represented by x. Since we sold 3 times more cheeseburgers than the amount of hamburgers, we can represent this as 3x.

Since these totals are combined, we can represent this via an equation:

512 = x + 3x

Solve for x accordingly, and we are given 128, which is equal to the amount of hamburgers.

Probability helps us to know the chances of an event occurring. The correct option is A.

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

Dependent events are those events in which the outcome of the first event affects the outcome of the second event. The statement that is correct about the dependent event is that the probability of all dependent events can be calculated using the "OR" formula P(A+B) =P(A) +P(B)-P(A and B).

Hence, the correct option is A.

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Answer:

Hamish earns $20 per hour, and Harry earns $26 per hour.

Step-by-step explanation:

Harry earns

$1+(5/4)•x and also (7/5)•x-$2

$1+(5/4)•x = (7/5)•x-$2

$1+$2= (7/5)•x-(5/4)•x

3=(7•4•x-5•5•x)/20

3=3x/20

3•20=3x

X=20, Hamish earns $20

Substitute x in one of the expressions

1+(5/4)•20=1+25=26, Harry earns $26

Answer:

B

Step-by-step explanation:

1/9 can be simplified to 1/3 as 1/3 x 1/3 = 1/9  and 49/25 can be simplified to 7/5 as 7/5 x 7/5 = 49/25.

Now looking at both the fraction 1/3 and 7/5

1/3 simplifies to 0.34

It is an irrational value as the 3 keeps repeating.

7/5 simplifies to 1.4

It is a rational value as the decimal value is not repeating.

Thus making the second option the answer.

Answer: 597

Step-by-step explanation:

The common difference is 5-1=4, so the explicit formula is [tex]a_{n}=1+(n-1)(4)[/tex]

Substituting in n=150,

[tex]a_{150}=1+(150-1)(4)=\boxed{597}[/tex]

Answer:

1780

Step-by-step explanation:

multiply the length value by 1760

and then divide the length value by 3

Differentiate the function/equation with respect to x and solve for the derivative, dy/dx. The value of dy/dx at the given point is the slope of the tangent line to the curve at that point. Then use the point-slope formula to get the equation of the tangent.

1.

[tex]y = \dfrac{x^2}{x+2} \implies \dfrac{dy}{dx} = \dfrac{2x\times(x+2) - x\times1}{(x+2)^2} = \dfrac{x(x+4)}{(x+2)^2}[/tex]

When x = 2, the derivative is

[tex]\dfrac{dy}{dx}\bigg|_{x=2} = \dfrac{2(2+4)}{(2+2)^2} = \dfrac34[/tex]

Then the equation of the tangent line at (2, 1) is

[tex]y - 1 = \dfrac34 (x - 2) \implies \boxed{y = \dfrac{3x}4 - \dfrac12}[/tex]

2.

[tex]x^3 + 2y^2 = 10y \implies 3x^2 + 4y \dfrac{dy}{dx} = 10 \dfrac{dy}{dx} \implies \dfrac{dy}{dx} = \dfrac{3x^2}{10-4y}[/tex]

When x = 2 and y = 1, the derivative is

[tex]\dfrac{dy}{dx}\bigg|_{(x,y)=(2,1)} = \dfrac{3\times2^2}{10-4\times1} = 2[/tex]

Then the tangent at (2, 1) has equation

[tex]y - 1 = 2 (x - 2) \implies \boxed{y = 2x - 3}[/tex]

The mean and the standard deviation are 16.15 and 12.03, respectively

The table of values is given as:

Work hours           Frequency

0 - <10                        45

10 - <20                      33

20 - <30                     20

30 - <40                       7

40 - <50                      8

Start by rewriting the table using the midpoint of each class

x      f

5     45

15    33

25    20

35    7

45    8

The mean is then calculated as:

[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]

This gives

[tex]\bar x = \frac{5 * 45 + 15 * 33 + 25 * 20 35 * 7 + 45 * 8}{45 + 33 + 20 + 7 + 8}[/tex]

Evaluate the sum and the products

[tex]\bar x = \frac{1825}{113}[/tex]

Divide

[tex]\bar x = 16.15[/tex]

The standard deviation is:

[tex]\sigma =\sqrt{\frac{\sum f(x - \bar x)^2}{\sum f}}[/tex]

This gives

[tex]\sigma= \sqrt{\frac{45 * (5 - 16.15)^2 + 33 * (15 - 16.15)^2 + 20 * (25 - 16.15)^2 + 7 * (35 - 16.15)^2 + 8 * (45 - 16.15)^2 }{45 + 33 + 20 + 7 + 8}}[/tex]

Evaluate the sum and the products

[tex]\sigma= \sqrt{\frac{16350.4425}{113}}[/tex]

Divide

[tex]\sigma= \sqrt{144.694181416}[/tex]

Take the square root

[tex]\sigma= 12.03[/tex]

Hence, the mean and the standard deviation are 16.15 and 12.03, respectively

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Answer:

The first type of solid shapes to be discovered are known as Platonic solids, which include the cube, the tetrahedron, the octahedron, the dodecahedron, and the icosahedron

Answer:

42 ft/s

Step-by-step explanation:

if superman travels 210 feet in 5 seconds, he will travel a fifth of 210 ft in 1 second

a fifth of 210ft is 210/5=42

hence 42ft/s is his rate.

-0.8+1.875+100%

1.05+100%

0.1

Answer:

b

Step-by-step explanation:

2 ml/200 mg so divide and you get 1 ml per 100 mg then multiply that my 3 to get 3ml/300 mg therefore the answer is b

Answer:

b. 3 ml

Step-by-step explanation:

300 mg  / 200 mg/ 2 ml   =   300 * 2  / 200 ml = 3 ml

The value of c is 81/64 for the expression a perfect square trinomial.

An expression can be defined as a mathematical statement that consists of variables, constants and mathematical operators simultaneously.

It is given that an expression

x² +9/4x +c is a perfect square polynomial

c =?

(a+b)² = a² +2ab+b²

2ab = 9/4

b = 9/8

c = b² = 81/64

Therefore the value of c is 81/64 for the expression a perfect square trinomial.

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If the Worker is retrenched, the probability that he is a plumber or a plasterer will be  0.0152.

The chances of an event occurring are defined by probability. Probability has several uses in games, in business to create probability-based forecasts,

The probability that the employee is a plumber;

[tex]\rm P(plumber)= \frac{No \ of \ plumber}{Total \ number \ of \ employ} \\\\ P(plumber)=\frac{12}{108} \\\\\ P(plumber)= 0.11[/tex]

The probability that the employee is a plasterer;

[tex]\rm P(plasterers )= \frac{No \ of \ plasterers }{Total \ number \ of \ employ} \\\\ P(plasterers )=\frac{15}{108} \\\\\ P(plasterers )= 0.13[/tex]

The probability that he is a plumber or a plasterer:

P = 0.13 × 0.11

P= 0.0152

Hence, if the worker is retrenched, the probability that he is a plumber or a plasterer will be  0.0152.

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Answer:

12 + [tex]4\sqrt{5}[/tex] approximates to 20.944

Step-by-step explanation:

VU - 8 units

UW - 4 units

VW - [tex]\sqrt{64+16} = \sqrt{80} =4\sqrt{5}[/tex]

12 + 4sqrt(5)

Answer:

6 (2 + √5) units

Step-by-step explanation:

Finding the length of the 3rd side :

*Applying Pythagorean Theorem*

The perimeter :

Answer:

insectistics a category variable also called various validity variable is a variable that can take on a limited as usually fixed number two possible values assigning each into visual or other unit of the vision 2 a particular group aur nominacle category of the basis some qualitative

do in oder of pemdas....

Answer:

Step-by-step explanation:

Answer:

[tex]\frac{1}{r^4^2}[/tex]  (option B)

Step-by-step explanation:

[tex]\left(a^b\right)^c=a^{bc},[/tex]

So, we need to first multiple -7 × 6 (= -42)

our new value is [tex]r^{-42\\}[/tex]

[tex]\:a^{-b}=\frac{1}{a^b}[/tex]

So, we simplify [tex]r^{-42\\}[/tex] to [tex]\frac{1}{r^4^2}[/tex]

Answer:

=================

Let the initial price be x.

After the first sales quarter the price is reduced by 10% and became:

After the second sales quarter the price is reduced by 20% and became:

The decrease over the two quarters is:

This is equivalent of 28%, hence the correct answer choice is B.

Answer:

1

Step-by-step explanation:

When you graph the functions they intersect at one point

(-3.368119, -31.10436)

Answer:

Let the no. be X and Y

X - Y = (-1)

X + Y = 1

X = (-1)+ Y

X = 1 - y

- 1.+ y = 1 - y

Y + Y = 1 + 1

2y = 2

Y = 1

X = 0

Answer:

x = 0 (first number), y = 1 (second number)

Step-by-step explanation:

x will represent the first number, and y will represent the second.

x - y = -1

x + y = 1

Now, it's time to get y by itself in one equation so that we can substitute.

x - y = -1 (subtract x from both sides)

-y = -1 - x (multiply both sides by -1)

y = x + 1

Plug in x + 1 for y in the second equation.

x + x + 1 = 1 (combine the x with the x)

2x + 1 = 1 (subtract 1 from both sides)

2x = 0 (divide both sides by 2)

x = 0

Since x = 0, we can plug 0 in for x into any equation to solve for y.

0 + y = 1

y = 1

Brainliest, please :)

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:x = 3\sqrt3 [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \tan(60) = \cfrac{x}{3} [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{3} = \dfrac{x}{3} [/tex]

[tex]\qquad \tt \rightarrow \: x = 3 \sqrt{3} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Step-by-step explanation:

[tex] \frac{5 {}^{ - 4x + 7} }{125 {}^{x} } [/tex]

[tex] \frac{5 {}^{ - 4x + 7} }{5 {}^{3x} } [/tex]

[tex]5 {}^{ - 4x + 7 - 3x} [/tex]

[tex]5 {}^{ - 7x + 7} [/tex]

Answer:

ffhjjrhjzxuzdjzdjzsjezjdifi

Let

[tex]I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]tex

Integrate by parts:

[tex]\displaystyle \int u \, dv = uv - \int v \, du[/tex]

with

[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)[/tex]

Then

[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C[/tex]

Integrate by parts again, this time with

[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)[/tex]

so that

[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}[/tex]