a courtroom spectator merely looks at the defendant and says, “He’s guilty, i tell you.”

Answer:

P(Y= 0) = 0.1

P(Y= 0) = 0.7

P(Y= 0) = 0.2

Step-by-step explanation:

Let Y be number of impurities that can be found in the well,

Let A denote the event that impurity A is randomly found in the well

Here Y can have three values i.e 0 , 1 and 2

✓It will take take the value of 0 when there is no impurity found in the well

✓It will take the value of 1 when when exactly one impurity vis found in the well

✓It will take the value of 2 when when both impurities vis found in the well

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

Answer:

D. Yes; the graph passes the vertical line test.

Step-by-step explanation:

→The vertical line test is when you hold something (like a pencil), straight up/vertically, and you move it from left-to-right to see if any two points repeat.

→The correct answer is "D. Yes; the graph passes the vertical line test," because the x-values can't repeat, not the y-values, if the graph were to show a function. In this case, the graph passes the vertical line test.

The number line model that represents the expression -2/5 + 4/5 is: Option B

To plot an inequality, such as x > 2, on a number line, first draw a circle over the number (e.g., 2). Then if the sign includes equal to (≥ or ≤), fill in the circle. If the sign does not include equal to (> or <), leave the circle unfilled in.

Now, in this case, the operation to solve is:

-2/5 + 4/5

Solving this gives 2/5

Now, since the operation shows a negative and positive fraction with the solution being positive, then we can easily say that Option B is the correct answer to the problem

Read more about Inequality on number line at: https://brainly.com/question/24372553

#SPJ1

Answer:

B

Step-by-step explanation:

The sum of all angles in a triangle must equal 180 degrees. Knowing this, you can find the values of p and q.

p

80 + 20 + p = 180

100 + p = 180

100 - 100 + p = 180 - 100

p = 80

q

55 + 45 + q = 180

100 + q = 180

100 - 100 + q = 180 - 100

q = 80

Conclusion

That means that p & q are equal to one another.

I hope this helps! Have a great day!

The thing that's true about the values p and q is that p = q.

The total sum of the angles in a triangle is 180°.

From the first triangle, the value of p will be:

80° + 20° + p = 180°

100° + p = 180°

p = 180° - 100°

p = 80°

From the second triangle, the value of q will be:

55° + 45° + q = 180°

100° + q = 180°

q = 180° - 100°

q = 80°

Therefore, p = q.

Read related link on:

https://brainly.com/question/16020981

Answer:

1674 ft²

Step-by-step explanation:

Area S = 65*30

Area A = (65 - x)(30 - x) = (65 - 3)(30 - 3) = 62*27= 1674 ft²

Answer:

For a 45 45 90 triangle

leg = hypotenuse / (square root of 2)

leg = 128 / 1.4142135624

leg = 90.5096679902 cm

Step-by-step explanation:

Answer:

answer is B   64 root 2

Step-by-step explanation:

got it right on edg 2020-2021

Answer:

= ( 82.90, 85.10) points

Therefore at 90% confidence interval (a,b)= ( 82.90, 85.10) points

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 84

Standard deviation r = 4.5

Number of samples n = 45

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

84+/-1.645(4.5/√45)

84+/-1.645(0.670820393249)

84+/-1.10

= ( 82.90, 85.10) points

Therefore at 90% confidence interval (a,b)= ( 82.90, 85.10) points

d-Denis

e-Earl

d+e=42

e+8=d

e+8+e=42

2e+8=42

2e=34

e=17

d=17+8=25

Denis is 25 and Earl is 17

Answer

Earl is 17 years old.

Denis is 25 years old.

See? Easy!

Step-by-step explanation:

Answer:

  14

Step-by-step explanation:

There are 7 elements in each set, and no elements are shared. The number of elements in the union of the sets is then ...

  n(A∪B) = 7+7 = 14

Answer:

x = 15

Step-by-step explanation:

3x = 45

x = 45/3

x = 15

Answer:

15

Step-by-step explanation:

3x = 45

Dividing 3 from both sides gives you

[tex]x = 45/3\\\\[/tex]

Now that isolated x.

[tex]45/3 = 15[/tex]

So x = 15

:D

Answer:

x = -3

Step-by-step explanation:

1.8 - 3.7x = -4.2x +.3

Add 4.2x to each side

1.8 - 3.7x +4.2x= -4.2x+4.2x +.3

1.8 +.5x = .3

Subtract 1.8 from each side

1.8 +.5x -1.8 = .3 -1.8

.5x = -1.5

Divide each side by .5

.5x/.5 = -1.5/.5

x = -3

Answer:

x=-3

Step-by-step explanation:

In order to solve this equation, we have to isolate x. Perform the opposite of what is being done to the equation. Remember to perform everything to both sides.

1.8-3.7x= -4.2x +0.3

3.7x is being subtracted from 1.8 (-3.7x). The inverse operation of subtraction is addition. Add 3.7x to both sides.

1.8-3.7x+3.7x= -4.2x+3.7x+0.3

1.8= -4.2x+3.7x+0.3

1.8= -0.5x+0.3

0.3 is being added to -0.5x. The opposite of addition is subtraction. Subtract 0.3 from both sides.

1.8-0.3= -0.5x+0.3-0.3

1.8-0.3 = -0.5x

1.5=-0.5x

-0.5 and x are being multiplied (-0.5*x= -0.5x). The opposite of multiplication is division. Divide both sides by -0.5.

1.5/-0.5=-0.5x/-0.5

1.5/-0.5=x

-3=x

So if we know the perimeter of the circle we can find it's radius using the formula for perimeter:

[tex]p = 2\pi(r)[/tex]

So we can solve for radius:

[tex]r = \frac{10.71}{2\pi} [/tex]

Then we can plug this radius into the formula for the area of a circle:

[tex]a = \pi {r}^{2} [/tex]

[tex]a = \pi( \frac{10.71}{2\pi} ) ^{2} [/tex]

Then it only wants a quarter of that area so we divide that value by 4 which upon simplification becomes the answer:

[tex]2.28 {ft}^{2} [/tex]

Answer:

[tex] \boxed{Area \: of \: quarter \: circle = 7.065 \: square \: feet} [/tex]

Given:

Perimeter of quarter circle = 10.71 feet

To find:

Area of quarter circle

Step-by-step explanation:

First we need to calculate the radius of quarter circle:

Let the radius of quarter circle be 'r'

[tex]Perimeter \: of \: quarter \: circle = \frac{\pi r}{2} + 2r[/tex]

[tex] \implies 10.71 = \frac{\pi r}{2} + 2r \\ \\ \implies 10.71 = \frac{\pi r}{2} +2r \frac{2}{2} \\ \\ \implies 10.71 = \frac{\pi r}{2} + \frac{4r}{2} \\ \\ \implies 10.71 = \frac{\pi r + 4r}{2} \\ \\ \implies 10.71 \times 2 = \pi r + 4r \\ \\ \implies 21.42 = \pi r + 4r \\ \\ \implies 21.42 = (\pi + 4)r \\ \\ \implies 21.42 = (3.14 + 4)r \\ \\ \implies 21.42 = 7.14r \\ \\ \implies 7.14r = 21.42 \\ \\ \implies r = \frac{21.42}{7.14} \\ \\ \implies r = 3 \: ft[/tex]

[tex] Area \: of \: quarter \: circle = \frac{\pi {r}^{2} }{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{\pi \times {(3)}^{2} }{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{\pi \times 9}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3.14 \times 9}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{28.26}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =7.065 \: {ft}^{2} [/tex]

Answer:

A. V(t) = 40t + 250 B. (HoV)(t) = 24πt/5 + 30π C. The composition in B (above) can be described as the height of the wax in terms of time.

Step-by-step explanation:

A. Let the rate of change of volume V with respect to time be dV/dt = 40 ft³/min

Solving this, V = 40t + C. At the start of the day, that is t = 0, V = 250 ft³

Substituting these values, we have

250 ft³ = 40(0) + C

C = 250 ft³

So, V(t) = 40t + 250

B. Since H(V) = 3πV/25

(HoV)(t) = 3π(40t + 250)/25

= 24πt/5 + 30π

C. The composition in B (above) can be described as the height of the wax in terms of time.

Answer:

I think 4^0 is the answer

Answer:

I think the answer is 282.6 but my answer is 297.33.

Answer:

the answer will be 282.6m^2

but that is not entirely correct

Step-by-step explanation:

Answer:

[tex]y=\frac{(-\frac{4}{x}+1)^2-3 }{4}[/tex]

Step-by-step explanation:

We are given the following information. y have the point [tex](-2,\frac{3}{2} )[/tex] and [tex]\frac{dy}{dx} =\frac{\sqrt{4y+3} }{x^2}[/tex]

First, we need to separate the variables to their respective sides

[tex]\frac{1}{\sqrt{4y+3} } dy=\frac{1}{x^2} dx[/tex]

Now, we need to integrate each side

[tex]\int \frac{1}{\sqrt{4y+3} } dy=\int\frac{1}{x^2} dx[/tex]

But first, let us rewrite these functions

[tex]\int (4y+3)^{-\frac{1}{2} } dy=\int x^{-2} dx[/tex]

Before we can integrate, we need to have the hook for the first function. When we integrate [tex](4y+3)^{-\frac{1}{2} }[/tex], we must have a lone 4 within the integral as well.

[tex]\frac{1}{4} \int4 (4y+3)^{-\frac{1}{2} } dy=\int x^{-2} dx[/tex]

Now we can integrate each side to get

[tex]\frac{1}{4} \sqrt{4y+3} =-\frac{1}{x} + c[/tex]

Now is the best time to use the given point in order to find the value of c.

[tex]\frac{1}{4} \sqrt{4(\frac{3}{2}) +3} =-\frac{1}{-2} + c\\\\\frac{1}{4}\sqrt{6+3} =\frac{1}{2} +c \\\\\frac{3}{4}=\frac{1}{2} +c\\ \\c=\frac{1}{4}[/tex]

Now we can plug in our value for c and then solve for y

[tex]\frac{1}{4} \sqrt{4y+3} =-\frac{1}{x} + \frac{1}{4} \\\\\sqrt{4y+3}=-\frac{4}{x} +1\\ \\4y+3=(-\frac{4}{x} +1)^2\\\\4y=(-\frac{4}{x} +1)^2-3\\\\y=\frac{(-\frac{4}{x} +1)^2-3}{4}[/tex]

Answer:

[tex] P(0.34 <\hat p<0.49)[/tex]

And the distribution for the sample proportion is given by;

[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]

And we can find the mean and deviation for the sample proportion:

[te]\mu_{\hat p}= 0.36[/tex]

[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]

And we can use the z score formula given by:

[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]

[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]

And we can use the normal distribution table and we got:

[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]

Step-by-step explanation:

For this case we know that the sample size is n =195 and the probability of success is p=0.36.

We want to find the following probability:

[tex] P(0.34 <\hat p<0.49)[/tex]

And the distribution for the sample proportion is given by;

[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]

And we can find the mean and deviation for the sample proportion:

[tex]\mu_{\hat p}= 0.36[/tex]

[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]

And we can use the z score formula given by:

[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]

[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]

And we can use the normal distribution table and we got:

[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]

Complete Question:

Amit found and labeled the areas of each of the faces of the triangular prism as shown.

Which area calculation did Amit calculate incorrectly?

Rectangular face with area 30 cm2

Rectangular face with area 40 cm2

Rectangular face with area 50 cm2

Triangular faces with areas 48 cm2

Answer:

Triangular faces with areas 48 cm2

Step-by-step Explanation:

To find out which area calculation Amit got wrong, let's calculate each faces of the given triangular prism attached below:

There area of theb5 faces should be as follows:

Area  of rectangular face with L = 10 and B = 5 would be ==> 10*5= 50cm²

Area  of rectangular face with L = 8 and B = 5 would be 8*5 = 40cm²

Area  of rectangular face with L = 6 and B = 5 would 6*5 = 30cm²

Area  of each of the triangular faces will be ½*8*6 = 48/2 = 24cm²

From our calculations, we'd observe that Amit didn't calculate the area of the triangular faces correctly. Amit got 48cm² instead of 24cm²

Answer:

Triangular faces with areas 48 cm2

Step-by-step explanation:

Answer:

(0. 4)

(-2, 0)

Step-by-step explanation:

As per given graph,

Answer:

given

3/4×1/7

=3×1/4×7

=3/28

thus the answer is 3/28

[tex]answer = \frac{3}{28} \\ solution \\ \frac{3}{4} \times \frac{1}{7} \\ = \frac{3 \times 1}{4 \times 7} \\ = \frac{3}{28} \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment[/tex]

Answer:

Options a, b, c are correct.

Step-by-step explanation:

First let's see the equation that governs the statement, which is the following:

[tex]r = \frac{cov (x, y)}{\sqrt{var(x) var (y)} }[/tex]

Therefore, reading options a, b, c are correct.

Since from the formula we have the correlation coefficient of two variables x and y and here it shows us the correlation between x, y and y, x is the same.

 This means that the 0.4 correlation implies a moderate but positive relationship between the two variables.

 that is, the highest or lowest value of one variable implies a highest or lowest value of the other variable, respectively.

Answer:

[tex]\sqrt{17}[/tex] or ≈4.12

Step-by-step explanation:

Use the distance formula

d= √(x₂ - x₁) ² + (y₂-y₁) ²

d= √(4-0)² + (1-0)²

d= √16 + 1

d= √17

Answer:

40 - 59 ⇒ 6

60 - 79 ⇒ 5

Answer:

40-59: 6

60-79: 5

Step-by-step explanation:

If you just added up, you can find all the values.

[tex]i^{100}=i^{4\cdot25}=\left(i^4\right)^{25}[/tex]

Recall that [tex]i^4=1[/tex], since [tex]i^2=-1[/tex]. Then

[tex]i^{100}=1^{25}=1[/tex]

so that in the form [tex]a+bi[/tex], we have [tex]a=1[/tex] and [tex]b=0[/tex].

Answer:

D) 1

Step-by-step explanation:

Correct on edg

Answer: 50 student in the school

Step-by-step explanation: 5x10=50 so that’s the answer.

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): [tex]\mu \geq 2000[/tex]

Alternative hypothesis (H1): [tex]\mu <2000[/tex]

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): [tex]\mu \geq 2000[/tex]

Alternative hypothesis (H1): [tex]\mu <2000[/tex]

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no

Answer:

Height = 8

Step-by-step explanation:

Area of a triangle = [tex]\frac{Base*Height}{2}[/tex]

Say the height = x

4.5x = 36

x = 8

Answer:

C (0, 10)

Step-by-step explanation:

The point E is (x,y)

The point F is (12,-6).

The midpoint between E and F is M(6,2).

Midpoint

Is the mean between the points of E and F.

x

[tex]\frac{x + 12}{2} = 6[/tex]

[tex]x + 12 = 12[/tex]

[tex]x = 0[/tex]

y

[tex]\frac{y - 6}{2} = 2[/tex]

[tex]y - 6 = 4[/tex]

[tex]y = 10[/tex]

So E(0, 10), which means that the correct answer is C.

Given:

2x -3 > 11 -5x

Simplify both sides:

2x - 3 > -5x + 11

Add 5x to both sides:

2x - 3 +5x > -5x + 11 +5

7x - 3 > 11

Add 3 to both sides:

7x - 3 +3 > 11 + 3

7x > 14

Divided 7 to both sides:

[tex]\frac{7x}{7}[/tex] > [tex]\frac{14}{7}[/tex]

x > 2

Answer:

Any number greater than 2 would be the answer. In Edg, choose 4! Choosing 2 would be incorrect in their system.

Step-by-step explanation:

Question:

A solid lies between planes perpendicular to the​ x-axis at x=0 and x=12. The​ cross-sections perpendicular to the axis on the interval 0≤x≤12 are squares with diagonals that run from the parabola y=-2√x to the parabola y=2√x. Find the volume of the solid.

Answer:

576

Step-by-step explanation:

Given:

Length of diagonal square:

[tex] D = 2\sqrt{x} - (-2\sqrt{x}) [/tex]

[tex] D = 4\sqrt{x} [/tex]

Here, the diagonal is the hypotenus of a right angle triangle, with leg S, where the square has a side of length S.

Using Pythagoras theorem:

[tex] S^2 + S^2 = D^2 [/tex]

[tex] S^2 + S^2 = (4\sqrt{x})^2 [/tex]

[tex] 2S^2 = 16x [/tex]

Divide both sides by 2

[tex] S^2 = 8x [/tex]

Thus,

Area, A = S² = 8x

Take differential volume, dx =

dV = Axdx

dV = 8xdx

Where limit of solid= 0≤x≤12

Volume of solid, V:

V =∫₀¹² dV

V = 8 ∫₀¹² xdx

V = [4x²]₀¹²

V = 4 (12)²

V = 12 * 144

= 576

Volume of solid = 576