A craft store buys 150 feet of satin ribbon for $13.50. The store sells the ribbon by the foot. A customer can purchase 5 feet of ribbon for $0.80. How much profit does the craft store earn on each foot of ribbon?

119 pupils, according to a Venn diagram, prefer Snickers or Reese's Peanut Butter Cups but not Twix.

In the 1880s, John Venn popularized the Venn diagram, a common type of diagram illustrating logical links between sets. In probability, logic, statistics, linguistics, and computer science, diagrams are used to teach basic set theory and to illustrate straightforward set relationships. In a Venn diagram, overlapping circles and other shapes are used to represent the connections between two or more sets of elements. Highlighting similarities and differences between components when organizing information graphically frequently proves beneficial. A space in the middle of a Venn diagram is created by the intersection of two sizable circles.

The group of students that enjoy Snickers is represented by set A.

The students who enjoy Twix are represented by set B.

The students who enjoy Reese's Peanut Butter are represented by set C. All three types of chocolate candies are favorites among 19 students.

Snickers and Reese's Peanut Butter Cups are among the 31.

Reese's Peanut Butter Cups and Snickers alone = 31 - 19 = 12

82 like Twix and Reese's Peanut Butter Cups

149 like Snickers

149 − (51 + 12 + 19) = 67 for Snickers alone.

The number of students who prefer Snickers or Reese's Peanut Butter Cups but not Twix is equal to 67 + 40 + 12.

There are 119 pupils that enjoy Snickers or Reese's Peanut Butter Cups.

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The total cost of the bridge will be (200/2) × 8 × 1000 + 50 × 10 + 500 = $90,000.

The formula for calculating the cost of a bridge is Cost = (Area of Bridge/2) × Unit Weight of Steel × Unit Price of Steel + Cost of Labor + Cost of Other Materials. By using this formula, we can determine the total cost of the bridge by considering the area of the bridge, the weight of the steel used, the price per unit of steel, the cost of labor, and the cost of other materials. For example, if the area of the bridge is 200m^2, the unit weight of steel is 8 tonnes/m^3, the unit price of steel is $1000/tonne, the cost of labor is $50 per hour, and the cost of other materials is $500, then the total cost of the bridge will be (200/2) × 8 × 1000 + 50 × 10 + 500 = $90,000. Thus, by using this formula, we can easily calculate the cost of the bridge and understand why local politicians are dragging their feet in building a new bridge.

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Answer: Editorial is data is the correct answer.

Step-by-step explanation: I took test and it is confirmed correct.

Answer:

........

Step-by-step explanation:

8 feet from the end of the wall is the nearest edge of the picture.

The process of converting phrases into equations and then solving those equations is known as solving algebraic word problems.

We will only need to use one variable and fundamental arithmetic operations to create the equations we require. In a real-world situation, the variable often stands for an unknowable quantity.

We can model and resolve word problems on the test that have two overlapping groups using Venn diagrams.

Let's say that the distance from the picture to the wall is x.

Since that distance will be on both sides of the picture (it's in the exact middle), we can say that:

x+3+x=19

=> 2x+3 = 19

=>2x=16

=>x= 8

Thus, 8 feet from the end of the wall is the nearest edge of the picture.

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The profit in 1973 is 5.56 which is estimated by the given linear model.

The regression equation is used to predict or estimate the value of the response (or dependant) variables based on an understanding of the explanatory (or predictor) variables.

Let Y represent the profit (or loss) for a certain company X years after 1970. Based on the data shown, a statistician calculates a linear model

Y = -0.80X + 7.96 ....(i)

Using the above model to estimate the profit in 1973

Substitute the value of X = 3 in the equation (i),

Y = -0.80(3) + 7.96

Y = -2.4 + 7.96

Y = 5.56

This is the profit in 1973.

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The ratio 1/2 is equal to 0.5.To calculate the ratio 1/2, we need to divide 1 by 2. When we divide 1 by 2, we get 0.5. Therefore, the ratio 1/2 is equal to 0.5.

To calculate the ratio 1/2, we need to divide 1 by 2. When we divide 1 by 2, we get 0.5. Therefore, the ratio 1/2 is equal to 0.5.

To calculate the ratio 1/2, we need to divide 1 by 2. This can be done by using a calculator or by hand. When we divide 1 by 2, we get 0.5. This means that the ratio 1/2 is equal to 0.5. In order to calculate the ratio, we can use the formula a/b = c, where a is the first number, b is the second number, and c is the result. In this case, a is 1, b is 2, and c is 0.5. Therefore, the ratio 1/2 is equal to 0.5.

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Answer:

the equation for the product of 12 x 8 = 96

The local school board should reject the null hypothesis since 0.000034 < 0.05.

There is sufficient evidence that the true proportion of households with school-aged children that would support starting the school year a week early is significantly different from the true proportion of households without school-aged children.

All the components of the data set are included in the population, which also contains quantifiable qualities like mean and standard deviation.

A sample is made up of one or more observations that are taken from the population, and a statistic is what makes a sample quantifiable. The act of sampling is the selection of a sample from a population.

Thus, The local school board should reject the null hypothesis since 0.000034 < 0.05.

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The equation of the line that passes through the points (-6,4) and (-2,2) is y - 4 = -1/2(x + 6)

What is the equation of the line?

To find the equation of a line that passes through two given points, we can use the point-slope form of the equation of a line, which is:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line, and m is the slope of the line.

The slope of the line can be found by using the two points:

m = (y2 - y1) / (x2 - x1)

So,

m = (2 - 4) / (-2 - (-6)) = -2/4 = -1/2

We know that the line passes through the point (-6,4) so we can substitute the values into the equation:

y - 4 = -1/2(x + 6)

Hence, the equation of the line that passes through the points (-6,4) and (-2,2) is y - 4 = -1/2(x + 6)

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At the interval of 0 to 4, the ball was thrown up into the air and allowed to bounce until it reached its peak height. Then, the ball began to decrease in height until it eventually came to a halt.

The ball's height increased from 0 to 4 meters as it was thrown up and allowed to bounce. Then, the ball's height decreased from 4 meters until it eventually came to a halt. The ball's height increased from 0 meters to 4 meters as it was thrown up into the air and allowed to bounce. The ball reached its peak height at the interval of 0 to 4 meters and then began to decrease in height until it eventually came to a halt. As the ball bounced, the energy of the ball was converted to different forms such as sound, heat, and kinetic energy. The force of gravity also played a role in the decreasing of the ball's height until it eventually stopped. The height of the ball fluctuated between 0 and 4 meters during the interval of 0 to 4 meters and then decreased until it reached its resting point.

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For the given data the mean is 180.28 and the modal class is 177 - 185.

First finding mean:

For the class of 150 - 158, the class boundaries are 149.5 - 158.5.

Middle value = (150 + 158)/2 = 154

Frequency = 5

mean= 154 × 5 = 770

For the class 159 - 167, the class boundaries are 158.5 - 167.5

Middle value  = (159 + 167)/2 = 163

Frequency = 16

middle value.  frequency = 163 × 16 = 2608

For the class 168 - 176, the class boundaries are 167.5 - 176.5

Middle value = (168 + 176)/2 = 172

Frequency = 20

middle value.  frequency = 172 × 20 = 3440

For the class 177 - 185, the class boundaries are 176.5 - 185.

Middle value = (177 + 185)/2 = 181

Frequency = 21

middle value.  frequency  = 181 × 21 = 3801

For the class 186 - 194, the class boundaries are 185.5 - 194.5

Middle value (x_m) = (186 + 194)/2 = 190

Frequency = 20

middle value.  frequency  = 190 × 20 = 3800

For the class 195 - 203, the class boundaries are 194.5 - 203.5

Middle value  = (195 + 203)/2 =199

Frequency = 15

middle value.  frequency  = 199 × 15 = 2985

For the class 204 - 212, the class boundaries are 203.5 - 212.5

Middle value  = (204 + 212)/2=208

Frequency = 3

middle value.  frequency  = 208 × 3 = 624

Now in order to determine the mean of this group data all values calculated separately through the product of middle value and frequency will be added together and divided by the total frequency count (i.e 100).

That is

Mean =  ( 770 + 2608 + 3440 + 3801 + 3800 + 2985 + 624 ) = 18028 / 100

Mean  =   180.28

Now determine the model class:

Model class refers to the with the highest occurring frequency. So this is the class "177 - 183" having the frequency 21.

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Step-by-step explanation:

remember, to transform an equation we need to apply any operation to both sides of the equation. otherwise the equality relation is destroyed.

we want to get the equating to look like " x = ..."

so, the "+ 39" is in the way.

we need to subtract 39, but as mentioned, we need to do this on both sides.

x + 39 = 74

x + 39 - 39 = 74 - 39

x = 35 in

the fig tree is therefore 35 in. that is 39 in shorter than 74 in (the orange tree).

Answer:

48

Step-by-step explanation:

Rate of change;

20 seconds 30 turns

30/20 is the number of turns per second.

3/2 x 12 = 18  There were 18 turns in the 12 seconds plus the 30 turns that she did in 20 seconds for a total of 18 + 30 = 48 turns

The coordinate of a point whose distance from both P and Q is exactly 13 is; (15, 24)

Pythagorean theorem:

According to the Pythagorean theorem, in a right triangle (90 degrees), the square of the hypotenuse equals the sum of the squares of the other two sides. Consider the following triangle ABC where BC2 = AB2 + AC2. where AB is the base, AC is the height (height), and BC is the hypotenuse.

The coordinate of a point whose distance from both P and Q is exactly 13 is; (15, 24)

The distance between points, P and Q can be evaluated by the Pythagoras theorem as follows;

Distance, PQ = √(20-10)² + (36-12)²

PQ = √(100+576)

PQ = √676

PQ = 26.

Therefore, a point whose distance from both P and Q is exactly 13 is the midpoint of PQ.

Therefore,

x = (20 + 10)/2

x = 15

y = (36 + 12)/2

y = 24.

The coordinate of a point whose distance from both P and Q is exactly 13 is; (15, 24)

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The distance between the two people is changing at a rate of 3.2 mi/hr.

The distance between the two people can be calculated by using the Pythagorean theorem.

Let one person be at the origin (0, 0) and the other person be at (x, y). After 15 minutes, the first person will be at (3*15, 0) and the second person will be at (2*15*cos45, 2*15*sin45).

Using the Pythagorean theorem, the distance between them can be calculated as:

d = sqrt((3*15 - 2*15*cos45)^2 + (2*15*sin45)^2) = sqrt(225 + 225) = sqrt(450) = 21.213

The rate of change of distance is given by the formula d/t, where d is the distance and t is the time.

Therefore, the rate of change of distance between the two people after 15 minutes is 21.213/15 = 3.2 mi/hr.

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The coordinates of the orthocenter of the triangle J(3,-2) K(5,6) L(9,-2) are (5, -2).

Generally, The orthocenter of a triangle is the intersection of the lines that contain the altitudes of the triangle.

To find the coordinates of the orthocenter, we first need to find the equations of the lines containing the altitudes.

To find the equation of the altitude from vertex J, we need the coordinates of J, K, and L.

Using the given coordinates, we have J(3,-2), K(5,6), and L(9,-2).

The equation of the line containing the altitude from J is:

-2 = (-2-6)/(3-5) (x-5) + 6

The equation of the line containing the altitude from K is:

6 = (-2-6)/(5-9) (x-9) - 2

The equation of the line containing the altitude from L is:

-2 = (6-(-2))/(5-3) (x-3) + 2

Solving the equation of the line containing the altitude from J and L, we get the x-coordinate of the orthocenter is 5 Solving the equation of the line containing the altitude from K and L, we get the y-coordinate of the orthocenter is -2

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Answer:

76
This is because, when you exceed 76 copies, the cost will be greater than 11.50 and you will not be able to afford it.

Step-by-step explanation:

To solve this inequality, you can divide both sides by 0.15: x <= 76.67

In order to have negative correlation between two variables the covariance must be negative.

What is correlation?

The degree to which two variables are linearly related is expressed by the statistical concept of correlation (meaning they change together at a constant rate). It is a typical technique for outlining straightforward connections without stating cause and effect.

The correlation between two variables x and y is,

[tex]r = \frac{Cov(x, y)}{S_x*S_y}[/tex]

where,

Cov(x, y) is the covariance between x and y.

[tex]S_x[/tex] and [tex]S_y[/tex] respectively denotes the standard deviation of x and y.

If the correlation is negative then  r < 0.

Now r < 0

[tex]\frac{Cov(x, y)}{S_x*S_y} < 0\\Cov(x, y) < 0\\Sx > 0, S_y > 0[/tex]

If r < 0 the Cov(x, y) < 0.

In order to have negative correlation between two variables the covariance must be negative.

Hence, in order to have negative correlation between two variables the covariance must be negative.

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As per the permutation method, there are 215,160 different ways are available for making the letters with vowel as the starting letter and s as the ending letter.

The term permutation in math is defined as  a mathematical technique that determines the number of possible arrangements in a set when the order of the arrangements matters

Here we need to find the number of combination for the word that start with a vowel and end with an s.

As we all know that there are 26 letters in alphabets.

so that would be all four letter words - four letter words with no vowel.

Then it can be calculated as the total number of four letter words

=> 26P4 or 26C4*4!

Then the number of four letter words without a vowel is calculated as

=> 21P4

Therefore, it can be written as,

=> 26P4 - 21P4

Then the resulting word count is calculated as,

=> (26 x 25 x 24 x 23) - (21 x 20 x 19 x 18)

=> 215160

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The solution of u in the equation where u is a real number is -10.

In the number system, real numbers are only the fusion of rational and irrational numbers. These numbers can generally be used for all arithmetic operations and can also be expressed on a number line. Imaginary numbers, which are often known as unreal numbers since they cannot be stated on a number line, are frequently used to symbolise complex numbers.

Given that u is a real number and the value of [tex]u^3 = -1000[/tex].

Take cube root on both sides of the equation:

[tex]\sqrt[3]{u^3} = \sqrt[3]{-1000} \\\\u = \sqrt[3]{(-10)(-10)(-10)} \\\\u = -10[/tex]

Hence, the value of u is -10.

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Answer:

a. To find the equation for the median-fit line, we need to first determine the slope (m) and the y-intercept (b) of the line. We can use the following formulas to calculate these values:

m = (nΣxy - ΣxΣy) / (nΣx^2 - (Σx)^2)

b = median y - m(median x)

Where n is the number of data points, x is the independent variable (year), y is the dependent variable (number of students learning English), Σ means to sum, and xy represents the product of x and y.

For this dataset, we have 5 data points, so n = 5.

x = 2003, 2004, 2005, 2006, 2007

y = 1.600, 1.599, 1.592, 1.570, 1.560

Σx = 10,015

Σy = 7,966

Σxy = 31,948

Σx^2 = 40,307

m = (531948 - 100157966)/(5*40307 - 10015^2) = -0.007

median x = 2005

median y = 1592

b = 1592 - -0.007 * 2005 = 1597.014

The equation for the median-fit line is:

y = -0.007x + 1597.014

b. To predict the number of students who were learning English in California in 2001, we can substitute 2001 for x in the median-fit line equation:

y = -0.007(2001) + 1597.014 = 1600.087

c. To predict the number of students who were learning English in California in 2010, we can substitute 2010 for x in the median-fit line equation:

y = -0.007(2010) + 1597.014 = 1590.028

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Answer: 2.5 meters long

Step-by-step explanation: if 2 cm turns into 1 m, that means that the scale factor for the number is 1/2. 5 * 1/2 = 2.5. Then just convert the cm into m.

Answer: The wall is actually 2.5 meters tall.

Step-by-step explanation: Given that in the picture the broom is 2cm long and in reality the broom measures 1 meter long, along with the fact that 100cm equals 1 meter, we can calculate that anything in reality will be 50 times greater than in the picture.

From there, simply multiply the height of the wall by 50 in order to get the real-life height of the wall (5cm), which is 2.5 meters tall.

[tex]0.02*50=1[/tex]

[tex]0.05*50=2.5[/tex]

Hope this helps!

P( X < 9.85 or X > 10.15 ) ≈ 0.3171 up to four decimal places.

P( X < 9.85 or X > 10.15 ) ≈ 0.0027 up to four decimal places.

The simple definition of probability is the likelihood that something will occur. We can discuss the probabilities of different outcomes, or how likely they are if we are unclear about how an event will turn out. Statistics refers to the study of occurrences subject to probability.

According to the question

a) Assuming that X is the random variable that takes the place of the number of defectives and has a normal distribution with a mean of 10 ounces and a standard deviation (σ) of 0.15.

The random variable's values deviate from the mean by 1, causing them to either exceed or fall short of (10 + 0.15) and (10-0.15)

= 10.15 or 9.85.

The following formula may be used to determine the likelihood that there will be either more or lesser defects than the range of 10.15 to 9.85:

P( X < 9.85 or X > 10.15 ) = 1 - P[tex](\frac{9.85-10}{0.15} < \frac{X - 10}{0.15} < \frac{10.15-10}{0.15} )[/tex]

P( X < 9.85 or X > 10.15 ) = 1 - φ(1) - φ(-1)

Now we calculate the value of z for z = 1 and z = -1; we have: 0.841345 and 0.158655 respectively

P( X < 9.85 or X > 10.15 ) = 1 - (0.841345 - 0.158655)

P( X < 9.85 or X > 10.15 ) = 0.31713

P( X < 9.85 or X > 10.15 ) ≈ 0.3171 up to four decimal places.

b) It is possible to lower the process standard deviation to 0.05 by making modifications to the process design.

The following formula may be used to determine the likelihood that the number of defectives is either larger than 10.15 or lesser than 9.85:

P( X < 9.85 or X > 10.15 ) = 1 - P[tex](\frac{9.85-10}{0.15} < \frac{X - 10}{0.15} < \frac{10.15-10}{0.15} )[/tex]

P( X < 9.85 or X > 10.15 ) = 1 - φ(3) - φ(-3)

Now we calculate the value of z for z = 3 and z = -3; we have: 0.99865 and 0.00135 respectively

P( X < 9.85 or X > 10.15 ) = 1 - (0.99865 - 0.00135)

P( X < 9.85 or X > 10.15 ) = 0.00271

P( X < 9.85 or X > 10.15 ) ≈ 0.0027 up to four decimal places.

(c) What is the benefit of increasing the number of standard deviations from the mean for process control limits by minimizing process variation?

As we can see from the reduction from a to b above, the key benefit of minimizing process variance is that it will decrease the likelihood of receiving a defective item.

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The car consumes 3 gallons and 8.2 gallons of fuel respectively.

Milage:

Divide the distance traveled by the amount of gas used. For example, driving 100 miles with a full tank and 5 gallons of gas is 10mpg. When it comes to fuel economy, it's important to know how much your car is costing you each time we drive it.

According to the Question:

The gas mileage is the number of miles that can be covered by a car for a particular amount of fuel.

We are given that the gas mileage of the car is 30 miles per gallon, that means that the car consumes 1 gallon of fuel for each 30 miles covered.

The amount of fuel needed to cover the following distance is:

a) For 90 miles, let x represent the number of gallon of fuel. Hence:

Distance covered / amount of fuel = 30 miles per gallon

  90/x = 30

⇒ x = 90/30

⇒ x = 3 gallons

b) For 246 miles, let x represent the number of gallon of fuel. Hence:

Distance covered / amount of fuel = 30 miles per gallon

⇒ 246/x = 30

⇒ x = 246/30

⇒ x = 8.2 gallons

Therefore, the car consumes 3 gallons of fuel for 90 miles and 8.2 gallons for 246 miles.

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Answer:

i. To calculate the total expenses in Kenya shillings incurred by Wekhomba, we need to first convert the cost of the laptop in Uganda shillings to Kenya shillings using the exchange rate of 1 US dollar = Ush 1016. The cost of the laptop in Kenya shillings is (1,050,000/1016) = 1,032,474.40

We then need to add the transportation cost of 60 US dollars which is (60 * 1016) = 61,596 Kenya shillings.

Taxes in Kenya amounting to 55% of the cost in Uganda is (1,050,000 * 55/100) = 577,500 Uganda shillings which is (577,500/1016) = 567,715.20 in Kenya shillings.

The total expenses in Kenya shillings incurred by Wekhomba is 1,032,474.40 + 61,596 + 567,715.20 = 1,661,785.60

ii. To find the expenditure on transportation and taxes as a percentage of the total expenditure, we need to divide the sum of transportation costs and taxes by the total expenses and multiply by 100.

Expenditure on transportation and taxes is 61,596 + 567,715.20 = 629,311.20.

Expenditure on transportation and taxes as a percentage of the total expenditure = (629,311.20/1,661,785.60) * 100 = 37.9%

iii. To find the total value of the laptop in Tanzanian shillings, we first need to convert Kenya shillings to Tanzanian shillings using the exchange rate of 1Ksh = Ush 24.83 and Tsh 1 = Ksh 0.0714,

1,661,785.60 Kenya shillings is (1,661,785.60/24.83) = 668,817.51 Uganda shillings which is (668,817.51 / 0.0714) = 93,622,817.16 Tanzanian shillings

iv. To find the overall increase in value of the laptop as a percentage of the buying price, we need to divide the increase in value (total value in Tanzanian shillings - buying price) by the buying price and multiply by 100.

Overall increase in value = 93,622,817.16 - 1,050,000 = 92,572,817.16

The overall increase in value as a percentage of the buying price = (92,572,817.16/1,050,000) * 100 = 88.1%

Step-by-step explanation:

Answer:

(1, 1 )

Step-by-step explanation:

choose any value of x to substitute into the equation and solve for y

choosing x = 1 , then

- 1 + 5y = 4 ( add 1 to both sides )

5y = 5 ( divide both sides by 5 )

y = 1

then (1, 1 ) is a solution to the equation

Answer:

- x + 5 y = 4                                     (x = 6)

- ( 6 ) + 5 × 2 = 4                             (y = 2)

- 6 + 10 = 4

 4 = 4

∴ (6, 2) is an ordered pair that is a solution to the given equation .

Each twelve-bar cycle in the twelve-bar blues form is referred to as a chorus, as well as the overall chord remains the same. The three sections of a big band are rhythm, reed, and brass.

What Characterizes a Chord as Minor or Major? One small adjustment—the third in a scale—is all that separates a major chord from a minor chord. Three notes from the major scale—the first, third, and fifth—are found in a major chord. The first, lowered third, and flatted fifth chords of a major scale that is named for are the notes that make up a minor chord.

A significant (A). A minor; C#; E. (Am). Major in A-C-E-C (C). C minor, E, G. (Cm). the key of C, and G. (D). D minor in D-F#-A key. significant in D-F-A-E. (E). E minor in E-G#-B key. E - G - B.

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Answer:

---------------------------------------

Property of a parallelogram:

According to the property we have:

Answer:

standard form:

4×100,000

400,000