Answer: required tensile stress is 0.889 MPa
Explanation:
Given that;
tensile load is oriented along the [1 1 1] direction
shear stress is 0.242 MPa along [1 0 1] in the (1 1 -1) plane
first we determine
λ which is Angle between [1 1 1] and [1 0 1]
so
cosλ = [ 1(1) + 1(0) + 1(1) ] / [ √(1² + 1² + 1²) √(1² + 0² + 1²)]
= 2 / √3√2 = 2/√6
Next, we determine ∅ which is angle between [1 1 1] and [1 1 -1]
so,
cos∅ = [ 1(1) + 1(1) + 1(-1) ] / [ √(1² + 1² + 1²) √(1² + 1² + (-1)²)]
cos∅ = [ 2-1] / [√3√3 ]
cos∅ = 1/3
Now, we know that;
σ = T_stress/cosλcosθ
so we substitute
σ = 0.242 / ( 2/√6 × 1/3 )
σ = 0.242 / 0.2721
σ = 0.889 MPa
Therefore, required tensile stress is 0.889 MPa
Basic engine conponents
An engine is composed of several major components; the block, the crank, the rods, the pistons, the head (or heads), the valves, the cams, the intake and exhaust systems and the ignition system. These parts work together in an exacting manner to harness the chemical energy in gasoline.
The engine block consists of a cylinder block and a crankcase. An engine block can be produced as a one-piece or two-piece unit. The cylinder block is the engine component that consists of the cylinder bore, cooling fins on air-cooled engines, and valve train components, depending on the engine design.
hope this helps
have a good day
:)
_______________ is an effective way to manage waste in a shop.
Answer:
To reduce waste.
Explanation:
An air-standard Carnot cycle is executed in a closed system between the temperature limits of 350 and 1200 K. The pressures before and after the isothermal compression are 150 and 300 kPa, respectively. If the net work output per cycle isPage 529 0.5 kJ, determine (a) the maximum pressure in the cycle, (b) the heat transfer to air, and (c) the mass of air. Assume variable specific heats for air.
This question is incomplete, the complete question is;
An air-standard Carnot cycle is executed in a closed system between the temperature limits of 350 and 1200 K. The pressures before and after the isothermal compression are 150 and 300 kPa, respectively. If the net work output per cycle is 0.5 kJ, determine (a) the maximum pressure in the cycle, (b) the heat transfer to air, and (c) the mass of air. Assume variable specific heats for air.
Answer:
a) the maximum pressure in the cycle is 30.01 Mpa
b) the heat transfer to air is 0.7058 KJ
c) mass of Air is 0.002957 kg
Explanation:
Given the data in the question;
We find the relative pressure of air at 1200 K (T1) and 350 K ( T4)
so from the "ideal gas properties of air table"
Pr1 = 238
Pr4 = 2.379
we know that Pressure P1 is only maximum at the beginning of the expansion process,
so
now we express the relative pressure and pressure relation for the process 4-1
P1 = (Pr2/Pr4)P4
so we substitute
P1 = (238/2.379)300 kPa
P1 = 30012.6 kPa = 30.01 Mpa
Therefore the maximum pressure in the cycle is 30.01 Mpa
b)
the Thermal heat efficiency of the Carnot cycle is expressed as;
ηth = 1 - (TL/TH)
we substitute
ηth = 1 - (350K/1200K)
ηth = 1 - 0.2916
ηth = 0.7084
now we find the heat transferred
Qin = W_net.out / ηth
given that the net work output per cycle is 0.5 kJ
we substitute
Qin = 0.5 / 0.7084
Qin = 0.7058 KJ
Therefore, the heat transfer to air is 0.7058 KJ
c)
first lets express the change in entropy for process 3 - 4
S4 - S3 = (S°4 - S°3) - R.In(P4/P3)
S4 - S3 = - (0.287 kJ/Kg.K) In(300/150)kPa
= -0.1989 Kj/Kg.K = S1 - S2
so that; S2 - S1 = 0.1989 Kj/Kg.K
Next we find the net work output per unit mass for the Carnot cycle
W"_netout = (S2 - S1)(TH - TL)
we substitute
W"_netout = ( 0.1989 Kj/Kg.K )( 1200 - 350)K
= 169.065 kJ/kg
Finally we find the mass
mass m = W_ net.out / W"_netout
we substitute
m = 0.5 / 169.065
m = 0.002957 kg
Therefore, mass of Air is 0.002957 kg
An example of Analog Data would be:
A-Light Switch
B-computer system
C-digital clock
D-Fuel Tank Sensor in Car
Help please
Answer:
B
Explanation:
The speed of sound is 1150 ft/s convert to mile/h
Answer:
784.090909mph
Explanation:
1ft/s=0.681818 mph
1150ft/s=0.681818 x 1150=784.090909
Home safety and security is an _________
process. (7 Letters)
Answer
Electric
Answer
Explain
Home safety and security is an electric process as there are some devices that have electric involvement.
What is the function of Systems in house safety?The systems in house safety are which consist of sensors and regular cameras or sirens, are armed via way of means of inputting a code at the keypad, the usage of a voice command, urgent a key fob, or doing it via an app.
Electronic protection gadget refers to any digital device that might carry out protection operations like surveillance, get right of entry to manage, alarming or an intrusion manage to a facility or a place which makes use of energy from mains and additionally an energy backup like a batter.
Read more about the Home safety :
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Water is a great eroder. Man-made levees must be tough. They are often built of
A. rock and concrete.
B. packed mud and dirt.
C. sandbags and gravel.
Water is a great erode. Man-made levees must be tough. They are often built of rock and concrete. The correct option is A.
What are Man-made levees?Man-made levees are designed to withstand the erosive power of water and prevent flooding in areas near bodies of water.
As such, they are constructed using strong and durable materials, such as rock and concrete, that can resist the forces of water and prevent erosion.
These materials provide a solid and stable foundation for the levees, which is important for ensuring their effectiveness in protecting against flooding.
Packed mud and dirt or sandbags and gravel may not provide sufficient strength and durability to withstand the erosive power of water and may not be suitable for building effective levees.
Thus, the correct option is A.
For more details regarding levees, visit:
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order of Design Process steps ?
Answer:
The five stages of Design Thinking, according to d.school, are as follows: Empathise, Define , Ideate, Prototype, and Test. Let's take a closer look at the five different stages of Design Thinking
Explanation:
An aluminum bar 125 mm long with a square cross section 16 mm on an edge is pulled in tension with a load of 66,700 N and experiences an elongation of 0.43 mm. Assuming that the deformation is entirely elastic, calculate the modulus of elasticity of the aluminum. (Please leave a space between the number and the unit, and use correct capitalization and lower case for units - for example: MPa, not Mpa.)
Answer: the modulus of elasticity of the aluminum is 75740.37 MPa
Explanation:
Given that;
Length of Aluminum bar L = 125 mm
square cross section s = 16 mm
so area of cross section of the aluminum bar is;
A = s² = 16² = 256 mm²
Tensile load acting the bar p = 66,700 N
elongation produced Δ = 0.43
so
Δ = PL / AE
we substitute
0.43 = (66,700 × 125) / (256 × E)
0.43(256 × E) = (66,700 × 125)
110.08E = 8337500
E = 8337500 / 110.08
E = 75740.37 MPa
Therefore, the modulus of elasticity of the aluminum is 75740.37 MPa
An annealed 65 - 45- 12 cast iron structural member is non-destructively hardness tested. In the hardness test, a 10 mm diameter tungsten carbide sphere created a 4.48 mm diameter impression under a 3000 kg load. What is the yield strength (to 2 significant figures) of the structural member
Answer: The required yield strength YS is 350 MPa
Explanation:
Given that;
for an annealed 65 - 45- 12 cast iron structural member,
indenter used : WC ball
Diameter of the indenter D = 10 mm
Diameter of impression d = 4.48
Load = 3000 kg
Now, the Brinell Hardness Number BHN can be determined by using the following formula;
BHN = 2P / (πD[ D - √( D² - d²))
we substitute
BHN = 2(3000) / (π×10[ 10 - √( 10² - 4.48²))
BHN = 6000 / 10π[ 10 - 8.9403]
BHN = 6000 / 33.2914
BHN = 180.22 ≈ 180
Corresponding values to BHN = 180
Yield Strength Y.S = 350 MPa
Tensile Strength T.S = 490 Mpa
. In your own words, write a definition of the term "urban sprawl." What are some common characteristics?
Answer:
kindly check the explanation section.
Explanation:
The word ''sprawl'' as it is related to people and population simply means an irregular expansion and the word ''urban'' simply means a city. So, putting both together as "urban sprawl" simply means an irregular expansion of cities or town.
Urban sprawl is majorly caused by race and land and the characteristics of urban sprawls are: [1]. there is High dependency on automobiles, [2]. the development is dispersed, and [3]. there is low density.
On vehicles with rear drum brakes and front disc brakes the metering valve ensures that the drum brakes receive hydraulic pressure
Answer:
The answer is "slightly before the disc brakes".
Explanation:
This dose appropriate secondary that perhaps the brake pads get hydrostatic fluid slightly even before brake discs on vehicles of rear trumpet brake and front disc brakes.
These same brakes are far more powerful and efficient than brake pads. It's why the brakes of disc-brakes could be found fading as much as on drum breaks.
Corrections for curvature and refraction (c r) are applied to: ____________.
a. benchmark elevations (BM)
b. both foresight rod readings (FS) and backsight rod readings (BS)
c. foresight rod readings (FS)
d. backsight rod readings (BS)
Answer:
b.
Explanation:
Foresight rod reading is any measurement taken at a given sight to determine a particular elevation. The backsight rod readings are usually used to a point of certain elevation. It is added to the elevation to determine the height of the instrument. These are phenomena are used in differential leveling and are applied to corrections for curvature and refraction.
how many buttons in an airbus a380 cockpit
Explanation:
It depends on the cockpit. A glider for instance wouldn't have many buttons at all, whereas something like an Airbus A330 has over 200 buttons on the overhead panel, not including the circuit breakers. Generally the larger the aircraft, the more buttons it has.
Answer:
Explanation:
A330 has over 200
A conventional steering system has all of the following except
Describe the differences between case hardening and through hardening, insofar as engineering applications of metals are concerned.
Answer:
The answer is below
Explanation:
Case hardening is a form of steel hardening that is applied on mild steel with a high temperature of heat.
It results in material forming a hard surface membrane, while the inner layer is soft.
It is mostly used for universal joints, construction cranes, machine tools, etc.
On the other hand, Through hardening is a form of steel hardening in engineering that involves heat treatment of carbon steel.
It increases the hardness and brittleness of the material.
It is often used for axles, blades, nuts and bolts, nails, etc.
2. Solve for the unknown variable:
C = 16in
a =
b = 12in
Answer:
I don't Know what it is supposed to equal.
Explanation:
Tell me this, and consider it done
Do heavier cars really use more gasoline? Suppose a car is chosen at random. Let x be the weight of the car (in hundreds of pounds), and let y be the miles per gallon (mpg)
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
Note: This question is incomplete and lacks necessary data to solve. But I have found the similar question on the internet. So, I will be using the data from that question to solve this question for the sack of concept and understanding.
Data Given:
x = 27 , 44 , 32 , 47, 23 , 40, 34, 52
y = 30, 19, 24, 13 , 29, 19, 21, 14
It is given that,
∑x = 299
∑y = 167
∑[tex]x^{2}[/tex] = 11887
∑[tex]y^{2}[/tex] = 3773
We are asked to verify the above values manually in this question.
So,
1. ∑x = 299
Let's verify it:
∑x = 27 + 44 + 32 + 47 + 23 + 40 + 34 + 52
∑x = 299
Yes, it is equal to the given value. Hence, verified.
2. ∑y = 167
Let's verify it:
∑y = 30 + 19 + 24 + 13 + 29 + 19 + 21 + 14
∑y = 169
No, it is not equal to the given value.
3. ∑[tex]x^{2}[/tex] = 11887
Let's verify it:
For this to find, first we need to square all the value of x individually and then add them together to verify.
∑[tex]x^{2}[/tex] = [tex]27^{2}[/tex] + [tex]44^{2}[/tex] + [tex]32^{2}[/tex] + [tex]47^{2}[/tex] + [tex]23^{2}[/tex] + [tex]40^{2}[/tex] + [tex]34^{2}[/tex] + [tex]52^{2}[/tex]
∑[tex]x^{2}[/tex] = 11,887
Yes, it is equal to the given value. Hence, verified.
4. ∑[tex]y^{2}[/tex] = 3773
Let's verify it:
Again, for this we need to find the squares of all the y values and then add them together to verify it.
∑[tex]y^{2}[/tex] = [tex]30^{2}[/tex] + [tex]19^{2}[/tex] + [tex]24^{2}[/tex] + [tex]13^{2}[/tex] + [tex]29^{2}[/tex] + [tex]19^{2}[/tex] + [tex]21^{2}[/tex] + [tex]14^{2}[/tex]
∑[tex]y^{2}[/tex] = 3,845
No, it is not equal to the given value.
A new construction firm completed its first project of a residential building. But a few months later, the building developed cracks, and eventually the entire building crumbled to the ground. What caused the building to fall?
A. Poor air conditioning
B. Weak walls
C. External force
D. Furniture
Answer:
it is weak walls
Explanation:
At what angle should you place your elbows while at your workstation? Above 120 degrees At 60 degrees Below 90 degrees Between 90 and 110 degrees
Answer:
Between 90 and 110 degrees
Explanation:
Ideally, the angle should not be less than 90° so that your elbows could be parallel to the workstation. This will in turn mean that the shoulders will be relaxed and it will make it a lot less stressful to keep the wrists in a straight manner.
Looking at the options, there is no exact figure of 90°, however, it could be between 90° to 110° because the difference is not going to be much in terms of making the shoulders relaxed.
Answer:
90 degrees i did the test and i also looked it up to make sure i was right.
Explanation:
A train starts from rest at station A and accelerates at 0.4 m/s^2 for 60 s. Afterwards it travels with a constant velocity for 25 min. It then decelerates at 0.8 m/s^2 until it is brought to rest at station B.
Determine the distance between the stations. ?s^Delta s = _______.
[tex]\\[/tex]
Explanation:
Given:[tex] a_1 \:=\:0.4\:m/s²[/tex]
[tex] t_1 \:=\:60\:s[/tex]
[tex] v_{i1} \:=\:0\:m/s[/tex]
[tex] a_2 \:=\:0\:m/s²[/tex]
[tex] t_2 \:=\:25\:min\:=\:1500\:s[/tex]
[tex] a_3 \:=\:-0.8\:m/s²[/tex]
[tex] v_{f3} \:=\:0\:m/s[/tex]
[tex]\\[/tex]
Required:Distance from Station A to Station B
[tex]\\[/tex]
Equation:[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]\\[/tex]
Solution:Distance when a = 0.4 m/s²Solve for [tex]v_{f1}[/tex]
[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]0.4\:m/s²\:=\:\frac{v_f\:-\:0\:m/s}{60\:s}[/tex]
[tex]24\:m/s\:=\:v_f\:-\:0\:m/s[/tex]
[tex]v_f\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{ave1}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v_{ave}\:=\:\frac{0\:m/s\:+\:24\:m/s}{2}[/tex]
[tex]v_{ave}\:=\:12\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]d_1[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]12\:m/s\:=\:\frac{d}{60\:s}[/tex]
[tex]720\:m\:=\:d[/tex]
[tex]d_1\:=\:720\:m[/tex]
[tex]\\[/tex]
Distance when a = 0 m/s²[tex]v_{f1}\:=\:v_{i2}[/tex]
[tex]v_{i2}\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{f2}[/tex]
[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]0\:m/s²\:=\:\frac{v_f\:-\:24\:m/s}{1500\:s}[/tex]
[tex]0\:=\:v_f\:-\:24\:m/s[/tex]
[tex]v_f\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{ave2}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v_{ave}\:=\:\frac{24\:m/s\:+\:24\:m/s}{2}[/tex]
[tex]v_{ave}\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]d_2[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]24\:m/s\:=\:\frac{d}{1500\:s}[/tex]
[tex]36,000\:m\:=\:d[/tex]
[tex]d_2\:=\:36,000\:m[/tex]
[tex]\\[/tex]
Distance when a = -0.8 m/s²[tex]v_{f2}\:=\:v_{i3}[/tex]
[tex]v_{i3}\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{f3}[/tex]
[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]-0.8\:m/s²\:=\:\frac{0\:-\:24\:m/s}{t}[/tex]
[tex](t)(-0.8\:m/s²)\:=\:-24\:m/s[/tex]
[tex]t\:=\:\frac{-24\:m/s}{-0.8\:m/s²}[/tex]
[tex]t\:=\:30\:s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{ave3}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v_{ave}\:=\:\frac{24\:m/s\:+\:0\:m/s}{2}[/tex]
[tex]v_{ave}\:=\:12\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]d_3[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]12\:m/s\:=\:\frac{d}{30\:s}[/tex]
[tex]360\:m\:=\:d[/tex]
[tex]d_3\:=\:360\:m[/tex]
[tex]\\[/tex]
Total Distance from Station A to Station B[tex]d\:= \:d_1\:+\:d_2\:+\:d_3[/tex]
[tex]d\:= \:720\:m\:+\:36,000\:m\:+\:360\:m[/tex]
[tex]d\:= \:37,080\:m[/tex]
[tex]d\:= \:37.08\:km[/tex]
[tex]\\[/tex]
Final Answer:The distance between the two stations is 37.08 kmE85 means that the fuel is made from A). 85% gasoline, 15% ethanol
B) 85% ethanol, 15% gasoline
C)Ethanol that has 15% water
D)Pure ethyl alcohol
Answer:
a
Explanation:
a
A separately excited DC motor turns at 1200 r/min when the armature is connected to 115V source. Calculate the armature voltage required so that the motor runs at 1500 r/min. At 100 r/min.
Answer:
The armature voltage required to run the motor at 1500 RPM is 143.75 V
The armature voltage required to run the motor at 100 RPM is 9.58 V
Explanation:
Given;
angular speed of the DC motor, ω = 1200 RPM
source voltage, V = 115 V
The armature voltage required to run the motor at 1500 RPM;
[tex]V_a = 115V \ \times \ \frac{1500 \ RPM}{1200 \ RPM} \\\\V_a = 143.75 \ V[/tex]
The armature voltage required to run the motor at 100 RPM;
[tex]V_a = 115V \ \times \ \frac{100 \ RPM}{1200 \ RPM} \\\\V_a = 9.58 \ V[/tex]
A cylindrical metal specimen of initial diameter d0 =14 mm, initial length L0=53 mm, strain hardening exponent n=0.31, strength coefficient K=665 MPa and reduction of area at fracture Arf=0.53 - Determine the true strain at maximum load and true strain at fracture - Determine the length of specimen at maximum load and diameter at fracture - Determine the maximum load force - Determine the Load (F) on the specimen when a true strain Ɛt=0.25 is applied during the tension test
Answer:
a) Ef = 0.755
b) length of specimen( Lf )= 72.26mm
diameter at fracture = 9.598 mm
c) max load ( Fmax ) = 52223.24 N
d) Ft = 51874.67 N
Explanation:
a) Determine the true strain at maximum load and true strain at fracture
True strain at maximum load
Df = 9.598 mm
True strain at fracture
Ef = 0.755
b) determine the length of specimen at maximum load and diameter at fracture
Length of specimen at max load
Lf = 72.26 mm
Diameter at fracture
= 9.598 mm
c) Determine max load force
Fmax = 52223.24 N
d) Determine Load ( F ) on the specimen when a true strain et = 0.25 is applied during tension test
F = 51874.67 N
attached below is a detailed solution of the question above
Recent research has identified mold-surface textures that will either (a) inhibit a solidified steel from separating from the mold or (b) force it to stay in contact in continuous casting. What is the advantage of a mold that maintains intimate contact with the steel
Answer:
faster heat conduction
Explanation:
The advantage of mold that maintains intimate contact with the material is that thermal contact resistance between the two is going to be reduced. That is, it would be lower.
Consequently, what would be happening would be heat getting conducted faster, this would then allow for higher traverse speeds or it could allow for the usage of shorter molds.
How do you decode/breakdown
METAR KATL 142417Z
METAR KAGS 231616Z
METAR KFAY 031847Z
METAR KDTT 101326Z
METAR KTLA 282436Z
Answer:
Use a special chart to do so
Explanation:
I would search updecoding charts
Answer: Use a chart or ask a pilot(like me). The z stands for Zulu which is the standard aviation time and the 4 letter code stands for the airport it was issued at. (Fun fact. Metars are very convenient in untowered airports because they broadcast the baro pressure that the tower would usually give you in a towered airport.)
Explanation:
This set of Fluid Mechanics focuses on "Types of Fluid Flow". Which method is used exclusively in fluid mechanics?
a. Lagrangian method
b. Eulerian method
c. Both Lagrangian and Eulerian methods
d. Neither Lagrangian nor Eulerian method
Answer:pp
Explanation:
Give me source code of Simple openGL project. ( without 3D or Animation) simple just.
Answer:
Use GitHub or stackoverflow for this answer
Explanation:
It helps with programming a lot
Waste that is generated by a business is called a _____________.
Answer:
Waste stream
Explanation:
trust
According to a snack cracker manufacturer, a batch of butter crackers has a defect rate of 8%. Suppose a quality inspector randomly inspects 500 crackers. Complete the following statement: The quality inspector should expect defective crackers, give or take how many crackers?
A. 40; 16
B. 60; 16
C. 40; 6
D. 60; 12
Answer:
C
Explanation:
I believe this should b corretc
