Answers
Answer:
Mass of wood = .209^3 m^3 * 655 kg/m^3 = 5.98 kg
area of wood = ,209^2 = .04368 m^3
.04368 * h * 1000 = 5.98 where h is water displaced
h = .137 m = 13.7 cm
a) distance from wood to water = 20.9 - 13.7 = 7.2 cm
Mass of 7.2 cm of wood (wood out of water)
M = 655 kg /m^3 * .209^2 m^2 * .0072 m = .206 kg
.206 kg of Pb must be added to wood for submersion
Related Questions
The gravitational force exerted on a solid object is 5.05 N as measured when the object is suspended from a spring scale as in Figure a. When the suspended object is submerged in water, the scale reads 3.88 N (Figure b). Find the density of the object. Answer is in kg/m^3.
Answers
Answer:
Here are the steps to solve this problem:
Determine the weight of the object in air:
F = ma
Weight (W) = Force (F) x gravitational field strength (g)
W = 5.05 N x 9.8 m/s^2 = 49.5 N
Determine the weight of the object submerged in water:
W' = 3.88 N x 9.8 m/s^2 = 38.0 N
The difference in weight is due to buoyant force:
Fb = Wa - W
Fb = 38.0 N - 49.5 N = 11.5 N
The buoyant force is equal to the weight of the water displaced:
Fb = ρwVg (where ρw is the density of water and V is the volume)
11.5 N = (ρwV)(9.8 m/s^2)
Solve for the volume and density of the object:
V = Fb/( ρwg) = 11.5 N/(1000 kg/m^3)(9.8m/s^2)
= 1.17 x 10^-3 m3
Density of object = mass/volume
ρ = W/V = 49.5 N/(1.17 x 10^-3 m3)
= 4.22 x 104 kg/m3
= 4220 kg/m3
So the density of the object is 4220 kg/m3.
In summary, by using Newton's second law, Archimedes' principle and definitions of weight, buoyant force and density, we were able to determine the density of the object based on measurements in air and water.
Explanation:
Chapter 3
#1) State Kepler's three laws in your own words.
#2) Write out Newton's three laws of motion in terms of what happens with the momentum of objects.
3) According to Kepler's second law, where in a planet's orbit would it be moving the fastest?
Where would it be moving the slowest?
#4) The gas pedal, the brakes, and the steering wheel all have the ability to accelerate a car- how?
#5) Explain how a rocket can propel itself using Newton's third law.
#6) A certain material has a mass of 565 g while occupying 50 cm³3 of space. What is this material?
(Hint, Use Table 3.1)
#7) What was the great insight Newton had regarding Earth's gravity that allowed him to develop the
universal law of gravitation?
Answers
Kepler's three laws are:
Law 1: Planets move in oval-shaped paths around the Sun, and the Sun is at one of the special points inside this oval shape.Law 2: When a planet gets closer to the Sun, it moves faster. When it gets farther away, it moves slower.Law 3: When a planet takes longer to orbit the Sun, its average distance from the Sun increases.What is Newton's three laws of motionThe Newton's three laws of motion is one that how momentum works.
Law 1: If an object is not moving, it will stay still, and if it is moving, it will keep moving in the same way unless something outside of it makes it stop or change direction.
Law 2: When you push or pull on an object, the object's momentum changes. The faster you push or pull, the more the momentum changes.
Law 3: When you push or pull something, it pushes or pulls back with the same amount of force.
Read more about laws of motion here:
https://brainly.com/question/26083484
#SPJ1
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform acceleration towards (-)direction, Uniform deceleration towards (+) direction and Uniform deceleration towards (-) direction in displacement time graph.Can you draw the shapes for each type ?
Answers
Explanation:
Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:[tex]\hrulefill[/tex]
(1) - Uniform acceleration towards the positive direction:
In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.
(2) - Uniform acceleration towards the negative direction:
In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.
(3) - Uniform deceleration towards the positive direction:
In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.
(4) - Uniform deceleration towards the negative direction:
In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.
Hector stretches a spring with a spring constant of 3 N/m until it is extended by 50 cm. What is the elastic potential energy stored by the spring?
Answers
The elastic potential energy stored in the spring is 0.375 J.
The formula for elastic potential energy is:
E = 1/2 * k * x^2
where:
* E is the elastic potential energy in Joules
* k is the spring constant in N/m
* x is the distance the spring is stretched or compressed from its equilibrium position in meters
In this problem, we have:
* k = 3 N/m
* x = 0.5 m (50 cm)
Substituting these values into the formula, we get:
E = 1/2 * 3 * 0.5^2 = 0.375 J
Therefore, the elastic potential energy stored in the spring is 0.375 J.
A collapsible plastic bag (figure below) contains a glucose solution. If the average gauge pressure in the vein is 1.21 103 Pa, what must be the minimum height h of the bag in order to infuse glucose into the vein? Assume the specific gravity of the solution is 1.01. Answer is in h = _ m.
Answers
The minimum height (h) of the bag needed to infuse glucose into the vein is approximately 0.1235 meters.
How to solve for the minimum heightThe hydrostatic pressure is given by:
P = ρgh
Where:
P is the pressure,
ρ is the density of the fluid,
g is the acceleration due to gravity, and
h is the height of the fluid column.
Then we will have
h = P / (ρg)
h =[tex](1.21 * 10^3 Pa) / (1.01* 10^3 kg/m^3 * 9.8 m/s^2)[/tex]
h = 0.1235 meters
Therefore, the minimum height (h) of the bag needed to infuse glucose into the vein is approximately 0.1235 meters.
Read more on gauge pressure here https://brainly.com/question/30425554
#SPJ1
If you feel pain during weight training, what should you do?
Answers
Answer:
Explanation:
Stop. Take a 5-10 minute breather, stretch out like you're doing your pre-workout (warmups). Drink some water, lay down for 3 minutes.
Answer: I hope this helps you
Explanation:
If you experience pain during weight training, it’s important to stop the exercise immediately and assess the source of the pain. If the pain is localized and mild, you can try taking a short break and then continuing with a lighter weight or modified exercise. However, if the pain is severe or spreading, you should stop the workout altogether and seek medical attention as soon as possible. Remember to always listen to your body and use proper form and technique to prevent injury.
What must be your car's average speed in order to travel 225 km in 3.35 h ?
Answers
Explanation:
Rate X Time = Distance
Distance / Time = Rate
225 km / 3.35 hr = 67.2 km/hr
A 73-g ice cube at 0°C is heated until 65.1 g has become water at 100°C and 7.9 g has become steam at 100°C. How much energy was added to accomplish the transformation? Answer is in kJ.
Answers
Q = m * ΔH
where Q is the energy required, m is the mass of the substance, and ΔH is the enthalpy of transformation.
First, we need to calculate the energy required to melt the ice cube:
Q1 = 65.1 g * 334 J/g = 21783.4 J
Next, we need to calculate the energy required to vaporize the water:
Q2 = 7.9 g * 2260 J/g = 17894 J
The total energy required is:
Q = Q1 + Q2 = 39677.4 J = 39.6774 kJ
Therefore, the energy required to accomplish the transformation is 39.6774 kJ.
what impact does liberal arts have on ensuring continued innovation
Answers
Answer:
Liberal arts education is important for ensuring continued innovation. It helps students think creatively, solve problems, collaborate effectively, and consider ethical factors. By exploring various subjects and adapting to new situations, liberal arts education equips individuals with the skills needed to generate new ideas and drive progress in different fields.
What is Moral subjectivism?
Answers
Answer:
What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.
The temperature of a aluminum bar rises by 10.0°C when it absorbs 4.73 kJ of energy by heat. The mass of the bar is 525 g. Determine the specific heat of aluminum from these data. Answer is in kJ/kg · °C.
Answers
Answer:
Certainly! We can use the formula:
q = mcΔT
where q is the amount of heat absorbed, m is the mass of the aluminum bar, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.
Substituting the given values, we get:
4.73 kJ = (0.525 kg) x c x (10.0°C)
Solving for c, we get:
c = 0.901 kJ/kg · °C
Therefore, the specific heat of aluminum is 0.901 kJ/kg · °C.
Explanation:
Question 1
At one section of a long pipe the velocity of the fluid is 1.6 m/s. At another section of the pipe the diameter is three times greater.
What is the velocity of the fluid at this section?
O 0.533 m/s
○ 4.80 m/s
O Not enough information to tell
O 0.178 m/s
Question 2
Three thermometers are placed in a closed, insulated box and are allowed to reach thermal equilibrium. One is calibrated in
Fahrenheit degrees, one in Celsius degrees, and one in Kelvins. If the Celsius thermometer reads -40 °C the Fahrenheit
thermometer would read -40°F.
True
False
Answers
Answer:
Answer 1: The answer is O 0.178 m/s.
Answer 2: True: But in this specific case where the Celsius temperature is -40, the Fahrenheit temperature will also be -40.
So, in short, the answer is:
-40 Celsius is equal to -40 Fahrenheit
A liquid ( = 1.65 g/cm^3) flows through a horizontal pipe of varying cross section as in the figure below. In the first section, the cross-sectional area is 10.0 cm^2, the flow speed is 293 cm/s, and the pressure is 1.20 * 10^5 Pa. In the second section, the cross-sectional area is 3.00 cm^2. Answer parts a-b.
Answers
Answer:
a) What is the flow speed in the second section? Assume the pressure remains constant.
Given:
Section 1 area = 10.0 cm^2
Section 1 flow speed = 293 cm/s
Section 2 area = 3.00 cm^2
Pressure = 1.20 x 105 Pa (constant)
Since pressure remains constant, by Bernoulli's equation:
P1/ρ + 1/2*v12 = P2/ρ+ 1/2*v22
Since P1 = P2 and ρ (density) is constant:
v22 = 2*(v12 - v22)
v22 = 2*(293^2 - v22)
Solving for v2:
v2 = √(2*293^2) = 846 cm/s
b) What is the kinetic energy loss per second between the two sections?
Kinetic energy = 1/2 * mass * velocity^2
Mass flow rate = density * area * velocity
= 1.65 g/cm^3 * 10.0 cm^2 * 293 cm/s = 485.5 g/s
Kinetic energy loss = 1/2 * (485.5 g/s) * (293^2 - 846^2) cm^2/s^2
= 1/2 * (485.5)*(86124 - 716256)
= 20617 J/s
So the kinetic energy loss per second between the two pipe sections is 20617 J/s.
Explanation:
Shannon and Chris push on blocks with identical force. SHannon's block is twice as massive as Chris'. After pushing for 5 seconds, who did more work?
Answers
Since Shannon and Chris push with identical force, the only difference between the two is the mass of the blocks.
The work done by Shannon is equal to the force she applied multiplied by the distance her block moved.
The work done by Chris is equal to the force he applied multiplied by the distance his block moved.
Since the force applied is the same, the only difference is the distance moved by each block.
Since Shannon's block is twice as massive as Chris', it will move half as far as Chris' block for the same amount of force applied.
Therefore, after pushing for 5 seconds, Chris did more work than Shannon.
The work of forensic engineers who investigate fires _____. identifies what started the fire and where it stated identifies what started the fire and where it stated does not consider explosions does not consider explosions is relatively simple is relatively simple is usually done by the firefighting team
Answers
The work of forensic engineers who investigate fires involves identifying what started the fire and where it originated, and it does not solely focus on explosions. This process is not relatively simple and is typically conducted by specialized forensic teams rather than firefighting personnel.
Forensic engineers play a crucial role in investigating fires to determine their cause and origin. Their primary objective is to gather evidence and analyze it in order to understand the circumstances surrounding the fire incident.
1. Scene Assessment: Forensic engineers begin by assessing the fire scene. They examine the area to gather initial information about the fire's intensity, pattern, and potential sources.
2. Evidence Collection: Next, the investigators collect physical evidence from the fire scene. This may involve gathering debris, examining burn patterns, and documenting any signs of accelerants or other substances that could have contributed to the fire.
3. Documentation: Forensic engineers meticulously document their findings through photographs, sketches, and written notes. This documentation serves as a crucial reference throughout the investigation process.
4. Laboratory Analysis: Collected evidence is then analyzed in specialized laboratories. Forensic experts employ various techniques such as chemical analysis, microscopy, and other scientific methods to determine the cause of the fire.
5. Report Preparation: Once the analysis is complete, forensic engineers prepare detailed reports outlining their findings. These reports serve as valuable resources for insurance companies, legal proceedings, and future fire prevention efforts.
It is important to note that the work of forensic engineers primarily focuses on identifying the cause and origin of the fire. While they consider various possibilities, including explosions, their investigation is not limited to solely investigating explosions.
Moreover, the process of investigating fires is complex and requires specialized knowledge and expertise. It is typically carried out by dedicated forensic teams rather than the firefighting personnel.
For more such questions on , click on:
https://brainly.com/question/542401
#SPJ8
Suppose a distant world with surface gravity of 6.32 m/s^2 has an atmospheric pressure of 9.00 ✕ 10^4 Pa at the surface. Answer parts a-c.
Answers
The Force ≈ [tex]1.13 * 10^6 N[/tex]
The Weight ≈ [tex]1.66 * 10^5 N[/tex]
Pressure ≈ 6.32 × 10⁴Pa
How to solve for the force(a)
Force = Pressure × Area
Force = (9.00 × 10⁴ Pa) × (π × (2.00 m)²)
Force ≈ [tex]1.13 * 10^6 N[/tex]
(b)
Weight = Density × Volume × g
Weight = (415 kg/m³) × (π × (2.00 m)² × 10.0 m) × (6.32 m/s²)
Weight ≈ 1.66 × 10⁵ N
(c)
Pressure = Pressure at the surface + Density × g × depth
Pressure = [tex](9.00 * 10^4 Pa) + (415 kg/m^3)* (6.32 m/^2)* (10.0 m)[/tex]
Pressure ≈ 6.32 × 10⁴Pa
Read more on force and pressure here https://brainly.com/question/16839775
#SPJ1
What is indicated by the following displacement time graph ?
Answers
Answer:
The object in motion is deaccelerating in the negative direction.
Explanation:
Interpret the given position-time graph.
Observing the graph we can determine the slope is negative and is gradually flattening out. Thus, we can conclude the object in motion is deaccelerating in the negative direction.
A roller coaster, travelling with an initial speed of 15 meters per second, decelerates uniformly at -7.0 meters per second squared to a full stop. Approximately how far does the roller coaster travel during its deceleration
Answers
The distance traveled by the rollercoaster during the deceleration is 16.1 m.
What is the distance travelled by the roller coaster?The distance traveled by the rollercoaster during the deceleration is calculated by applying the following formula.
v² = u² + 2as
where;
v is the final velocity of the rollercoasteru is the initial velocity of the rollercoastera is the acceleration of the rollercoasters is the distance traveled by the rollercoasterWhen the rollercoaster stops, the final velocity, v = 0
0 = u² + 2as
-2as = u²
s = u² / -2a
s = (15 m/s) ² / (-2 x - 7 m/s²)
s = 225 / 14
s = 16.1 m
Learn more about distance traveled here: https://brainly.com/question/24283318
#SPJ1
A simple harmonic oscillator (SHO) has a spring constant of 280 N/m, Total energy of 150 J, and a mass of 4.00 kg. What is its
maximum velocity?
Numerical answer is in units of m/s
Answers
The maximum velocity is 8.66 m/s²
As we know, simple harmonic motion refers to a to-and-fro motion in a periodic manner and spring constant refers to the force required to stretch or compress a spring.
The spring constant for a simple harmonic oscillator is given as 280 N/m, the total energy is 150 J and the mass is 4 kgs. We have to find the maximum velocity of the given simple harmonic motion.
We know that Energy = force x perpendicular distance
In an SHM, energy is in the form of Kinetic Energy. Hence, we use the formula for kinetic energy.
To find the maximum velocity, we will apply the formula for kinetic energy.
Since Kinetic Energy = 1/2 mass x velocity²
Therefore, 150 = 1/2 mass x velocity² ; velocity = 8.66 m/s²
Hence, the maximum velocity for the given system of SHM is 8.66 m/s²
To know more about simple harmonic oscillators,
https://brainly.com/question/30262862
HELPP PLEASEEE!! Now, for each time period, look at the graphs of x, vx, and ax. Briefly describe what is happening for each of these variables during your identified time periods. To view any of these graphs in detail, double-click the graph. You’ll be able to view it in the Data Tool window.
Answers
We can see here that to briefly describe what is happening for each variable during the identified time periods, you can follow these steps:
Identify the variablesDefine the time periodsGather data: Collect the necessary data or information for each variable during the identified time periods.Analyze the dataDescribe the variable's behaviorWhat is variable?A variable is a characteristic, property, or quantity that can vary or change in value. In the context of data analysis, research, or experimentation, variables are used to represent the different factors or elements that are being studied or observed.
Variables can take on different types and play various roles in a study or analysis.
Learn more about variable on https://brainly.com/question/28248724
#SPJ1
A fish is swimming in the ocean at a depth with 14 atm of absolute pressure. If the fish swims up towards the surface, to a depth
that is now one third where it started, what is the gauge pressure at this depth?
4.67 atm
O 5.67 atm
3.67 atm
1.25 pts
O 4.33 atm
Answers
The gauge pressure at the new depth is determined as 3.67 atm.
What is the gauge pressure?The gauge pressure at the new depth is calculated by applying the following formula.
The absolute pressure at the new depth is;
abs P = (1/3) x 14 atm
abs P = 4.67 atm
The gauge pressure at the new depth is calculated as;
Gauge pressure = Absolute pressure at the new depth - Atmospheric pressure
G P = 4.67 atm - 1 atm
G P = 3.67 atm
Therefore, the gauge pressure at the new depth is 3.67 atm.
Learn more about gauge pressure here: https://brainly.com/question/30425554
#SPJ1
A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures
Answers
Explanation:
You want N/m
N = 66 * 9.81
m = 2.3 x 10^-2 m
66* 9.81 / 2.3 x 10^-2 = 28150 = 28 000 N/m to two S D
1.5 A man with a mass of 90,6 kg walks to the back of a train at a velocity of 1m/s while the train moves at a constant velocity of 36 km/h in a easterly direction 1.5.1 The weight of the man 1.5.2 The velocity of the train in m/s 1.5.3 The resultant velocity of the man 1.5.4 The distance the train has travelled in ten (10) minutes (1) (1) (2) (2)
Answers
The weight of the man is approximately 888.6 Newtons.
The velocity of the train is approximately 10 m/s.
The resultant velocity of the man is 11 m/s.
The train has traveled a distance of 6000 meters in ten (10) minutes.
To solve this problem1.5.1 The weight of the man can be calculated using the formula:
Weight = mass * acceleration due to gravity
Given:
Mass of the man (m) = 90.6 kg
Acceleration due to gravity (g) ≈ 9.8 m/s²
Weight of the man = 90.6 kg * 9.8 m/s² ≈ 888.6 N
Therefore, the weight of the man is approximately 888.6 Newtons.
1.5.2 The velocity of the train in m/s can be converted from its given velocity in km/h. Since 1 km/h is equal to 1000/3600 m/s, we can calculate:
Velocity of the train (v) = 36 km/h * (1000/3600) m/s ≈ 10 m/s
Therefore, the velocity of the train is approximately 10 m/s.
1.5.3 By taking into account the relative motion of the man and the train, it is possible to determine the man's final velocity. The resultant velocity will equal the vector sum of the man's walking velocity and the train's velocity because the man is traveling toward the rear of the train, which is moving eastward.
Given:
Velocity of the man relative to the train (v_man) = 1 m/s (backwards)
Resultant velocity of the man (v_resultant) = v_man + v_train
v_resultant = 1 m/s + 10 m/s = 11 m/s
Therefore, the resultant velocity of the man is 11 m/s.
1.5.4 The distance the train has traveled in ten (10) minutes can be calculated using the formula:
Distance = velocity * time
Given:
Time (t) = 10 minutes = 10 * 60 seconds = 600 seconds
Velocity of the train (v) = 10 m/s
Distance = 10 m/s * 600 seconds = 6000 meters
Therefore, the train has traveled a distance of 6000 meters in ten (10) minutes.
Learn more about velocity here : brainly.com/question/25905661
#SPJ1
A satellite weighing 5,400 kg is launched into orbit 3.6400 x 107 m above the center of the earth.
The mass of Earth is 6.0 × 1024 kg. The gravitational constant is 6.673 × 10–11 N•m2/kg2.
The gravitational force of Earth on the satellite is ___
Group of answer choices
9.1 x 10^4
1.6 x 10^3
2.1 x 10^6
Answers
Answer:
[tex]\tt F=1.63*10^3 N[/tex]
Explanation:
Gravitational force is defined as the force of attraction between two objects with mass. It is a fundamental force of nature, and it is what keeps us on the ground and what keeps the planets in orbit around the Sun.
The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers
For the Question:
We can use the following formula to calculate the gravitational force between the Earth and the satellite:
[tex]\boxed{\tt F =\frac{ G * M * m }{ r^2}}[/tex]
Where:
F is the gravitational force
G is the gravitational constant[tex]\tt (6.673 * 10^{-11} Nm^2/kg^2)[/tex]
M is the mass of the Earth [tex]\tt (6.0 * 10^24 kg)[/tex]
m is the mass of the satellite[tex]\tt (5,400 kg)[/tex]
r is the distance between the satellite and the center of the Earth [tex]\tt (3.6400 * 10^7 m)[/tex]
Plugging in these values, we get the following:
[tex]\tt F = \frac{6.673 * 10^{-11} * 6.0 * 10^{24}* 5,400 }{ (3.6400 * 10^7 )^2}[/tex]
[tex]\tt F=1.63*10^3 N[/tex]
Therefore, answer is [tex]\tt F=1.63*10^3 N[/tex]
Joe is painting the floor of his basement using a paint roller. The roller has a mass of 2.4 kg and a radius of 3.8 cm. In rolling the roller across the floor, Joe applies a force F = 16 N directed at an angle of 35° as shown. Ignoring the mass of the roller handle, what is the magnitude of the angular acceleration of the roller?
Answers
The magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².
To find the magnitude of the angular acceleration of the roller, we can use the rotational analog of Newton's second law: τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.
First, let's calculate the moment of inertia of the roller. The moment of inertia of a solid cylinder rotating about its central axis is given by the formula: I = (1/2)mr², where m is the mass and r is the radius.
Given:
Mass of the roller (m) = 2.4 kg
Radius of the roller (r) = 3.8 cm = 0.038 m
Moment of inertia (I) = (1/2) * 2.4 kg * (0.038 m)² = 0.0021744 kg·m²
Next, we need to calculate the torque (τ) applied to the roller. Torque is given by the formula: τ = rFsin(θ), where r is the distance from the axis of rotation to the point of application of the force, F is the magnitude of the force, and θ is the angle between the force and the line connecting the axis of rotation and the point of application.
Given:
Force applied (F) = 16 N
Angle (θ) = 35°
Distance from the axis of rotation to the point of application (r) is equal to the radius of the roller, so r = 0.038 m.
Torque (τ) = (0.038 m) * (16 N) * sin(35°) = 0.2366 N·m
Now, we can use the equation τ = Iα and solve for the angular acceleration (α):
0.2366 N·m = (0.0021744 kg·m²) * α
α = 0.2366 N·m / 0.0021744 kg·m² ≈ 108.8 rad/s²
Therefore, the magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².
Know more about magnitude here:
https://brainly.com/question/30337362
#SPJ8
At time t = 0, a vessel contains a mixture of 14 kg of water and an unknown mass of ice in equilibrium at 0°C. The temperature of the mixture is measured over a period of an hour, with the following results: During the first 45 min, the mixture remains at 0°C; from 45 min to 60 min, the temperature increases steadily from 0°C to 2.0°C. Neglecting the heat capacity of the vessel, determine the mass of ice that was initially placed in the vessel. Assume a constant power input to the container. Answer is in kg.
Answers
The mass of ice that was initially placed in the vessel of neglected heat capacity was found to be 1.135 kg.
Given that,
Mass of water = 14 kg
Mass of ice = m kg
P = Power of the burner = dQ/dt
Rate of the heat given by the burner is constant.
In the first 45 min,
dQ/dt = mL/t1 = m x (80 x 4.2 x 10³)/45 min. (1)
From 45 to 60 min,
dQ/dt = (m+14) x δ(Η₂Ο) x Δθ / t2 =(m+14) x (4.2 x 10³) x 2/ 15 min. (2)
From (1) and (2)
m x (80 x 4.2 x 10³)/45 min = (m+14) x (4.2 x 10³) x 2/ 15 min
80m/3 = (m+14) x 2
80m = 6m + 84
m = 1.135 kg
To know more about heat capacity, refer:
https://brainly.com/question/28302909?referrer=searchResults
A small ferryboat is 4.50 m wide and 6.70 m long. When a loaded truck pulls onto it, the boat sinks an additional 4.70 cm into the river. What is the weight of the truck? Answer is in kN.
Answers
Explanation:
Volume of water displaced = 4.5 m x 6.7 m x .047 m = 1.417 m3
mass of displaced water =
1.417 m3 x 1000kg / m3 = 1417 kg = 13900 N = 13.9 kN
Here's how to calculate it:
1. Calculate the volume of water displaced by the boat:
V = lwh = (6.70 m)(4.50 m)(0.047 m) = 1.439 m^3
2. Calculate the weight of the water displaced by the boat:
F = mg = (1.439 m^3)(1000 kg/m^3)(9.81 m/s^2) = 14.10 kN
3. Calculate the weight of the boat:
Fb = mg = (6.70 m)(4.50 m)(0.047 m)(1000 kg/m^3)(9.81 m/s^2) = 14.84 kN
4. Calculate the weight of the truck:
Ft = F + Fb = 14.10 kN + 14.84 kN = 28.94 kN
5. Convert the weight of the truck from N to kN:
Ft = 28.94 kN
Therefore, the weight of the truck is approximately 187.8 kN.
Acceleration
Quiz Active
1 2 3 4 5 6 7 8 9 10
Study the motion map shown. Some of the vectors have been circled.
X
What do the circled vectors represent?
distance
speed
velocity
acceleration
Mark this and return
Save and Exit
Next
TIME REMAINING
29:41
e:
Submit
Answers
The circled vectors represents acceleration.
The last option is correct.
How do we explain?
We see in the first motion diagram the length of velocity vector is increasing this shows that the velocity is increasing in the magnitude with time so this is an accelerated motion in which a uniform acceleration must be in the same direction of velocity must be there.
We also notice in the second motion diagram the length of velocity vector is decreasing with time which shows the velocity is decreasing me magnitude which shows a constant deceleration and the direction of acceleration must be opposite to that of velocity.
Learn more about velocity at:
https://brainly.com/question/80295
#SPJ1
The diagram below shows snapshots of an oscillator at different times . What is the frequency of the oscillation ?
Answers
In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.
How to calculate the periodThe period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,
Period of oscillation = 1.80s.
From here, finding the frequency is simple as, Frequency = 1/Period. Hence,
Frequency = 1/1.80
= 0.555 Hz (3 sf).
The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.
Learn more about oscillation on
https://brainly.com/question/14628852
#SPJ1
a thin, very light wire is wrapped around a drum that is free to rotate, the free end of the wire is attached to a ball of mass m, the drum is initially a solid disk with a mass M and radius R. you let the mass go at height h above the ground. if you switch out the solid disk and use a hollow disk instead with the same mass and radius, how will the final speed when the mass hits the ground when using a hollow disk compare to the final speed when using a solid disk?
a-greater than the original
b-less than the original
c-cant be determined
d-same as the original
Answers
Answer:
a-greater than the original (solid disk)
Explanation:
The hollow drum's lower rotational inertia allows it to rotate faster as the wire unwinds. This absorbs more potential energy, leaving less to translate into the speed of the falling mass. Therefore, the final speed when using a hollow disk will be:
a-greater than the original (solid disk)
