A cubic meter of air was sampled at 1.0 ATM and 40 C.
An ion chromatographic analysis of that sample found it to contain 12 micrograms of NO2.
How many ppb of NO2 is in the air?

Answer:

Topographic maps generally shows Natural features such as Rivers and Lakes.

sometimes they also show some features made by humans like brodges, elevations etc.

Answer:

Topographic maps show contours, elevation, forest cover, marsh, pipelines, power transmission lines, buildings, and various types of boundary lines such as international, provincial, and administrative, and many others.

please give me brainliest

The hybrid orbital of this molecule is [tex]sp^3[/tex]. Hence, option C is correct.

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

In this compound, [tex]sp^3[/tex] a hybrid orbital makes I-O bonds. Due to [tex]sp^3[/tex]hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of [tex]IO^{3-}[/tex] the ion is pyramidal.

The hybrid orbital of this molecule is [tex]sp^3[/tex]. Hence, option C is correct.

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Answer:

3Fe + 4H₂O --> Fe3O4 + 4H2

Answer:

element.....

it is in the periodic table

The compound above is a cyclic (ring) compound.

Organic compounds are compounds which contains carbon and hydrogen.

Some classes of organic compounds include the following:

So therefore, the compound above is a cyclic (ring) compound.

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Answer:

In order to determine the charge of these elements you'll have to look at their placement in the periodic table by group number.

Explanation:

To further explain this, there is 18 groups of the periodic table.  These groups include:

Group 1: The alkali metals have a 1+ charge for their entire group.

For example: Sodium would have a charge of 1+.

Group 2: The earth alkali metals all have a charge of 2+. For example Mg has a charge of 2+.

Group 3-12: The transitions metals are a little harder to figure the charge of each, if given the compound they are bonded with you can use that to figure it out but only a few have distinct charges. Such as Ag (Silver) only have a 1+ charge. If you are still trying to figure the charge, try making an electron configuration to figure out it's spare electron count or charge.

Group 13: These elements in group 13 have a typical charge of 3+. For example Al has a charge of 3+.

Group 14: These elements in group 14 have a typical charge of 4+. For example Carbon has a charge 4+

Group 15: These elements start the shift towards a negative charge in the table, so for group 15 the elements have a 3- charge. For example Nitrogen has a 3- charge.

Group 16: These elements continue with a negative in group 16 with a negative charge of 2-. For example Oxygen's charge is 2-.

Group 17: The halogen elements in group 17 have a charge of 1-. For example Chlorine has a charge of -.

Group 18: The noble gases in group 18 do not have a charge because they are some of the most stable elements so they're not looking to gain or lose an electron (That is what a charge is basicaly). So, they're charge is none.  

Answer:

The moles of H2 is 230-two hundred and thirty

Answer:

15 oxygens

Explanation:

Given the partially balanced reaction: [tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \text{5C} \text{O}_{2}}+\text{5H}_\text{2}\text{O}[/tex]

The subscripts (small number to the right of each element symbol) are the number of atoms of the element within each compound/molecule, and the coefficients (numbers in front of each compound) represent the number of that molecule involved in one full reaction (if the equation were balanced).

The product side of the reaction is on the right of the arrow.

To determine the total number of Oxygens on the product side, we need to identify how many Oxygens are in each molecule (the subscript on the Oxygen), and then multiply times the number of that molecule that would be involved (Coefficient of the compound containing Oxygen).  There are multiple compounds on the right side of the equation that contain Oxygen, so we'll need to add together the number of Oxygens each part contributes.

[tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}[/tex]

[tex]\text{\# reactant-side Oxygens}=\bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}\\=5 \text{ CO}_{\text{2}}\text{ molecules} *\frac{\text{2 Oxygens}}{\text{1 CO}_{\text{2}}\text{ molecule}}+5 \text{ H}_{\text{2}}\text{O molecules} *\frac{1\text{ Oxygen}}{\text{1 H}_{\text{2}}\text{O molecule}}\\=10\text{ Oxygens}+5\text{ Oxygens}\\=15\text{ Oxygens}[/tex]

Answer:

69.6 g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.

Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (LiOH): 23.947 g/mol

2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

75.8 g LiOH          1 mole             1 mole CO₂               44.007 g
------------------  x  ----------------  x  -----------------------  x  -------------------  =
                            23.947 g         2 moles LiOH              1 mole

= 69.6 g CO₂

The mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of LiOH = 75.8g

Moles of LiOH = mass / molar mass

                       = 75.8 / 24 = 3.15 moles

From the reaction,

2 moles of LiOH react with 1 mole of CO₂

1 mole of LiOH needs 0.5 moles of CO₂

thus, 3.15 moles will need 0.5 × 3.15 moles = 1.575 moles of CO₂

Mass of Carbon dioxide = 1.575 × 44

                                       = 69.3g of carbon dioxide

Therefore, the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g

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HgS will precipitate first when tiny amounts of sulfide ion are slowly added to the solution.

The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution. It represents the level at which a solute dissolves in solution.

If Solubility product is greater than the ionic product then no precipitate will form on adding more solute because unsaturated solution is formed.

If Solubility product is lower than the ionic product then excess solute will precipitate out because of the formation of super saturated solution.

Here, Ksp value of HgS is very low. Hence, HgS will precipitate first when tiny amounts of sulfide ion are slowly added to the solution.

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Carbon dioxide + Water Glucose (sugar) + Oxygen CO2 + H2O C6H12O6 + 6O2 Cellular respiration or aerobic respiration is a series of chemical reactions which begin with the reactants of sugar in the presence of oxygen to produce carbon dioxide and water as waste products.

Avogadro's law states that in each mole of a substance, there are [tex]6.022 \times 10^{23}[/tex] particles.

This means that 15000 atoms is equal to [tex]\frac{15000}{6.022 \times 10^{23}}=\boxed{2.4909 \times 10^{-20} \text{ moles (to 5 sf)}}[/tex]

There are 2.49 × [tex]10^{-20}[/tex] moles present in 15000 atoms of iron (Fe).

A mole is the quantity of a material that includes 6.023 x [tex]10^{23}[/tex] of that substance's components.

The smallest component of ordinary stuff that makes up a chemical element would be an atom.

Calculation of mole

It is known that 1 mole =  6.023 x [tex]10^{23}[/tex] particles.

So, the 1500 atoms will be equal to the = 1500 /  6.023 x [tex]10^{23}[/tex]  =  2.49 × [tex]10^{-20}[/tex] moles .

Therefore, there are 2.49 × [tex]10^{-20}[/tex] moles present in 15000 atoms of iron (Fe).

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NaClO₃ ⇒ NaCl + O₂ ⇒ unbalanced

1. O : left 3, right 2

give coefficient left 2, right 3

2NaClO₃ ⇒ NaCl + 3O₂

2. Na and Cl : left 2, right 1

give coefficient right 2

2NaClO₃ ⇒ 2NaCl + 3O₂ ⇒ balanced

For the reactants,

For the products,

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: [tex]\text{H}_{3}\text{AsO}_{4}[/tex]

formula of the reducing agent: [tex]\text{H}_{2}\text{C}_{2}\text{O}_{4}[/tex]

Decreasing the separation between the two magnets will result in increase in the magnetic force between two magnets.

This is referred to a substance which produces magnetic field and result in the attraction and repulsion of certain types  of things.

Increase in the separation will reduce the magnetic force and vice versa which is why option A was chosen.

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Answer:

1.57

Explanation:

moles = mass / molar mass

moles = 69 / 44.013

moles = 1.57

moles N₂O = 69 : 44 g/mol = 1.568

N₂O : 2 moles N, 1 mole O

moles N = 1.568 x 2 = 3.136

Answer:

organic chemistry is chemistry focused on structure and composition, extending to recations and properties of compounds.

often centered around compounds with carbon.

alcohols, amines, and aldehydes are some groups that are studied on organic chemistry

SHORT ANSWER:

a) chemistry focused on the structure qnd composition of compounds

b) alcohols, amines, aldehydes

Explanation:

Organic compounds, which are the compounds associated with life processes, are the subject matter of organic chemistry. Among the numerous types of organic compounds, four major categories are found in all living things: carbohydrates, lipids, proteins, and nucleic acids.

Answer:

nitrogen compounds in the air

Explanation:

In the scientific sense the two examples of people doing work is: A and D

Work can be defined as a result of applying force to a particular object that changes its displacement in the direction of the applied force.

Work can only be done when their is a force that is being applied and a displacement that occurs.

In conclusion, In the scientific sense the two examples of people doing work is: A and D

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Answer:

The answer for this problem would be "b. A 10 mL graduated cylinder".

Explanation:

The reason for this is because with a instrument that is closer to the value you're trying to measure, the more precise it will be.

For example using a teaspoon to measure something rather than a cup.

Answer:

Explanation:

Ok so Proust's Law, better known as the Law of Definite Proportions, states that the components of a compound always exist in a fixed ratio. This means that it does not matter what the source of the components are nor the coefficients in front of them. The ratio your teacher is referring to is most likely mass percent/ percent composition. This ratio is the amount of the component over the amount of the entire compound times 100%.

*I am not very familiar with this law so please do with my answers what you will :)*

7.)

First, you want to find the percent composition (aka mass composition) of Na in NaCl.

 45.89 g Na
---------------------  x 100%  =  39.3%
116.89 g NaCl

So, there must be 39.3% sodium in NaCl. You can find how much chlorine is in NaCl by subtracting that percent by 100 (to find the percent composition of chlorine) then multiplying it by the mass.

100% - 39.3% = 60.7%

60.7% / 100 = 0.0607

116.89 g NaCl x 0.0607 = 70.91 g Cl₂

You could also just subtract the mass of sodium from the mass of sodium chloride to find the mass of chlorine.

116.89 g NaCl - 45.89 g Na = 71 g Cl₂

8.)

10.57 g Mg + 6.96 g O₂ = 17.53 g MgO

  6.96 g O₂
---------------------  x 100%  = 39.7% O₂
17.53 g MgO

9.)

6.46 g Pb = 1 g O₂

68.54 g Pb  =  28.76 g O₂

68.54 g Pb / 28.76 g O₂ = 2.83 g ≠ 6.46 g

No, the two samples are not the same because the proportion of lead to oxygen is not the same for both samples. In the first sample, there is 6.46 g lead for every oxygen. In the second sample, there is 2.38 g lead for every oxygen.

The atomic mass of the unknown element is; 23

We are given that;

Number of protons = 11

Number of Neutrons = 12

Number of Electrons = 11

Now, formula for atomic mass is;

Atomic mass = Number of Neutrons + Number of Electrons

Atomic Mass = 12 + 11

Atomic Mass = 23

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It takes 31 s for 1.27 M H₃PO₄ to decrease its concentration to 7.0% of its initial value following first-order kinetics.

First-order kinetics occur when a constant proportion of a reactant disappears per unit time.

Let's consider the following first-order kinetics reaction with a rate constant k = 0.086 s⁻¹.

2 H₃PO₄(aq) = P₂O₅(aq) + 3 H₂O(aq)

Given the initial concentation is [H₃PO₄]₀ = 1.27 M, the concentration representing 7.0% of this value is:

[H₃PO₄] = 7.0% × 1.27 M = 0.089 M

We can calculate the time elapsed (t) using the following expression.

ln ([H₃PO₄]/[H₃PO₄]₀) = - k × t

ln (0.089 M/1.27 M) = - 0.086 s⁻¹ × t

t = 31 s

It takes 31 s for 1.27 M H₃PO₄ to decrease its concentration to 7.0% of its initial value following first-order kinetics.

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Answer:

A

Explanation:

I'm right I took the test

Answer:

2.06M NaCl

Explanation:

Molarity is defined as a ratio of moles of the solute (the substance you're dissolving) to Liters of solution (the volume of the finished solution).  It uses the letter capital M as an abbreviation for the unit.

We're given values for both numbers (with the correct units already), so substitute, and calculate the number part:

[tex]\dfrac{n_{solute}}{V_{solution}}=\dfrac{3.09 [\text{mol NaCl}]}{1.50 [\text{L solution}]}=2.06\dfrac{[\text{mol NaCl}]}{[\text{L solution}]}=2.06[\text{M NaCl}][/tex]

Answer:

Conducting Experiments