A cyclist bikes with an average velocity of 20\, \dfrac{\text{m}}{\text{s}}20
s
m
​
20, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction for 5\, \text{seconds}5seconds5, start text, s, e, c, o, n, d, s, end text.
What is the magnitude of the cyclist’s displacement?
Your answer should have one significant figure.
\text{m}mstart text, m, end text

The distance d travelled by in object is 68.58 m

What is velocity ?

velocity is defined as rate of change of displacement d of the object with respect to rate of change in time t. In mathematics It is written as :

v = d/t

it should be noted that, velocity is nothing but speed in particular direction. That is velocity is vector quality having both magnitude and direction where as speed is just the magnitude of velocity.

1 feet = 0.3048 m

15 feet = 4.572 m

Now, calculating the distance d travelled by in object :

d = vt

d = 4.572 x 27

d = 68.58 m

Therefore, the distance d travelled by in object is 68.58 m

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The density of a 4.5 g cube with an edge length of 5.5 cm is 0.027 g/mL

The formulas and the procedures we will use are:

Where:

Information about the problem:

Calculating the volume of the cube, we get:

v = s³

v = (5.5 cm)³

v = 166.38 cm³

Converting the volume of the cube from cm3 to mL, we get:

1 cm3 is equivalent to 1 mL, so

166.38 cm³ is equivalent to 166.38 mL

Applying the density formula, we get:

ρ = m/v

ρ = 4.5 g/166.38 mL

ρ = 0.027 g/mL

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

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When a force of 200.0 n is exerted on a 1,000 n object. The object moves a distance of 30.0 m. 24,000J work was done on the car.

Work=Force × Distance is a formula that describes the relationship between work, force, and distance. While distance is expressed in meters, force is expressed in Newtons (N). The result is Joule.

So, total force is 1000-200 = 800N

Work=Force × Distance

Work=800 × 30

Work=24,000J

So, when a force of 200.0 n is exerted on a 1,000 n object. The object moves a distance of 30.0 m. 24,000J work was done on the car.

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The glass of water weigh once the antacid pill has dissolved will be less than the 219 grams due to evolution of carbon dioxide.

Mass of effervescent antacid pill = 4.00 g

Mass of water = 110 g

Mass of glass = 105 g

Total mass of the substances  together : 4.00 g + 110 g + 105 g = 219 g

Effervescent antacid pill , moment it will get dissolved in water carbon dioxide gas is evolves and hide from the solutions.

This states  that mass of the weight of the glass of water with antacid dissolved in it will be less than 219 grams.

Effervescent antacid tablets are made up of aspirin, acid and sodium bicarbonate. When bicarbonate of soda dissolves in water, it reacts with hydrogen ions from the acid and forms carbon dioxide. Because CO₂ is a gas, it forms bubbles inside the water that you simply can see as foam on the surface

Antacids are weak bases that act by neutralizing gastric acid . Raising the pH of the stomach contents leads to suppression of the action of pepsin that exacerbates ulceration due to acid.

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By using uniform motion, the time taken is 1.25 seconds.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

F = 8 N

m = 2 kg

vo = 2 m/s

vt = 7 m/s

Find the acceleration by second Newton's Law

F = m.a

8 = 2 . a

a = 4 m/s²

Find the time taken

vt = vo + a . t

7 = 2 + 4t

4t = 5

t = 1.25 seconds

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If the sound intensity goes up by 40 db, the amplitude of wave as measured gets increases by a factor of 100.

The sound level in decibels can be formulates as

[tex]\beta[/tex] = (10dB) log (I/Io)

Here Io = 10⁻¹²W/m² is specified as the reference intensity

If we assume β₁ as initial sound intensity and β₂ as final sound intensity. Therefore, change in sound intensity can be formulated as

β₁-β₂=40 dB

(10dB) log (I2/Io) - (10dB) log (I1/Io) = 40 dB

(10dB) [log (I2/Io) - log (I1/Io)] = 40dB

log( (I2/Io) / (I1/Io) ) = 40/10 dB

log (I2/I1) = 4dB

I2/I1 = 10^4

The intensity of sound is said as directly proportional to the amplitude of wave squared.

Therefore,

I ∝ A²

I1/I2 = (A1/A2)^2

A2/A1 = [tex]\sqrt{I2/I1}[/tex]

A2/A1 = 100

Therefore, the amplitude of wave increases by a factor of 100.

A sound wave’s amplitude measures the height of the wave. When a sound is made, the maximum displacement of the medium’s vibrating particles from their mean position determines the amplitude of the sound wave.

In physics, amplitude refers to the greatest displacement or distance that a point on a vibrating body or wave can move relative to its equilibrium location. It is equivalent to the vibration paths half-length.

The maximum displacement of a sound wave’s constituent particles is its amplitude. The number of vibrations a sound wave makes per second is known as frequency.

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Explanation:

Given Data,

Amount of charge transferred to the ground by the lightening bolt, q = 35 C

Amount of charge transferred to the ground by the lightening bolt, q = 35 C

Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d

Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d = 2.0 km = 2000 m

Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d = 2.0 km = 2000 m

Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d = 2.0 km = 2000 m Magnitude of electric field, E = 1.0 × 10⁶ N/C

Now, finding PE(∆U) in lightning bolt,

ΔU = -q×E×dΔU = −35

C × 1.0 × 10⁶

N/C × 2000 m

ΔU = −7.0×10¹⁰ J

(a) Let's start by calculating the helium's weight. We'll apply the well-known weight equation:

W helium =m helium ⋅g

where m helium is the mass of the helium and g is the gravity.

=>W helium =ρ helium ⋅V⋅g

putting the values we get

ρ helium =0.183 kg/ m^3

Therefore, W helilum =76.2 kN

(b) The weight of the air will also be determined in the same manner:

W air =ρ air ⋅V⋅g

=> ρ air =1.205 kg/ m^3

Therefore after substituting the values we get,

W air = 501.35 kN

​

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Answer:

How much velocity changes in a given amount of time

(A) The direction of electric field in given region is to the left.

(B) The potential difference is -0.46×[tex]10^{3}[/tex].

(A) When charge is present in any form, a point in space has an electric field that is connected to it. The value of E, often known as the electric field strength, electric field intensity, expresses the strength and direction of the electric field.

Therefore, the direction of electric field in given region is to the left.

(B) The amount of work required to move a unit charge from one point to another point is equal to the potential difference between two points in an electric circuit.

[tex]V_{B} -V_{A}[/tex] = W / Q

[tex]V_{B} -V_{A}[/tex] = 2.30×[tex]10^{-3}[/tex] / -4.9×[tex]10^{-6}[/tex]

[tex]V_{B} -V_{A}[/tex] = -0.46×[tex]10^{3}[/tex]

Therefore,  the potential difference is -0.46×[tex]10^{3}[/tex].

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The km of the enzyme for the substrate a is determined as 5000mM, and the value of V0 would be calculated as 0.682nM/minute as per the calculations done.

The relationship between KM and the enzyme’s affinity for its substrate is inverse.

Low enzyme substrate affinity is correlated with high levels of KM (it takes more substrate to get to Vmax). An enzyme with a low KM value has a strong substrate affinity.

Vmax is the reaction’s maximum rate at the specified enzyme concentration.

The reaction’s speed increases when the concentration of the substrate rises, but after a while, when the enzyme becomes saturated with the substrate, the reaction speed does not continue to rise.

As seen after 10000mM concentration of substrate velocity of enzyme becomes constant attain maximum velocity i.e., Vmax

Therefore, we have Km = Vmax/2

= 10000/2 = 5000mM

Then by applying the equation

V = Vmax[S/S+km]

V = 80[43/43+5000]

= 0.682nM/minute

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Answer: 2.5

Explanation: cause it is

The symbol of the element helium is He, its proton number is 2, its atomic mass is 4, its neutron number is 2 and finally; helium belong to period 1 of the periodic table.

However, helium is a noble gas, meaning it has a stable octet electronic configuration ( having 8 valence electrons)

According to the periodic table, helium belong group 0 of the periodic table which is the 8th group. It belongs to period 1

A chemical element refers a chemical substance which cannot be split into simpler units by chemical ordinary means.

Elements in the periodic table are generally categorized as metals, nonmetals and metalloids.

In addition, an atom is the smallest part of element which can take part in a chemical reaction.

Some examples of elements are as follows including their symbols

So therefore, the symbol of the element helium is He, its proton number is 2, its atomic mass is 4, its neutron number is 2 and finally; helium belong to period 1 of the periodic table.

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Answer:

Доброе утро, ответ 5+5="4

Explanation:

During the flame test, an atom emitting a green color with a wavelength of roughly 550 nm would have a frequency of 5.45 1014 Hertz.

It may be explained in terms of the separation between any two identical succeeding locations on a wave, such as how the wavelength can be determined by calculating the separation between any two successive crests.

Speed of light = frequency of the green light ×wavelength of the light

3×10⁸ = 550×10⁻⁹ × frequency

frequency = 3×10⁸ / 550×10⁻⁹

                 = 5.45 ×10¹⁴ Hertz

Thus, the correct answer is option D.

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The refractive index of the mirror immersed in the water is 1.33. There is no change in its focal length. The focal length of mirrors will not depend on the external medium in which the mirror is immersed.

Focal length is defined as the distance of the pole of the mirror from the point on the axis of the mirror at which the beams, parallel to the principle axis, show up to merge. In other words, the distance between the pole of the mirror and the centre point is called the focal length

A concave mirror converges all the rays of light falling on this, so it is called converging mirror

A convex mirror diverges all the rays of light falling on this, so it is called diverging mirror

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a. Your speed after 2 seconds is 4 m/s.

b. your speed after 10 seconds is 20 m/s.

To find the speed after 2 seconds, we use the equation of motion v = u + at where

Given that You start from rest and ski down a hill with an acceleration of 2 m/sec².

So, substituting the values of the variables into the equation for the speed, v, we have

v = u + at

v = 0 m/s + 2 m/s² × 2 s

v = 0 m/s + 4 m/s

v = 4 m/s

So, your speed after 2 seconds is 4 m/s.

To find the speed after 10 seconds, we use the equation of motion v = u + at where

Given that You start from rest and ski down a hill with an acceleration of 2 m/sec².

So, substituting the values of the variables into the equation for the speed, v, we have

v = u + at

v = 0 m/s + 2 m/s² × 10 s

v = 0 m/s + 20 m/s

v = 20 m/s

So, your speed after 10 seconds is 20 m/s.

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Answer:by cooking

Explanation: because he use energy and everything like transfer

The velocity of the car was 4.93m/s and the direction was northeast.

It is given,

time of the trip = t = 3 minutes = 180 seconds

1st distance A = 1500ft = 457.2m east

2nd distance B = 2500ft = 762m north

We are asked to find the average velocity.

First, we get the resultant distance magnitude by applying Pythagoras theorem to find the hypotenuse.

[tex]A^{2} + B^{2} =C^{2} \\C=\sqrt[]{A^{2} +B^{2} } \\C=\sqrt{457.2^{2} +762^{2} } \\C= 888.63m[/tex]

Then we have

Velocity = Distance/time

Velocity = 888.63/180

Velocity = 4.93 m/s

Then the direction is northeast.

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There are 10 bonding orbitals

10 antibonding orbitals

2 nonbonding orbitals

Each of the lone pairs on the oxygen is contained in a nonbonding molecular orbital.

In acetone, there are ten antibonding orbitals.

What percentage of molecular orbitals have a N value of two?

The two 2s orbitals and all three 2p orbitals are the atomic orbitals with a n value of 2.

Eight molecular orbitals, of which half are bonding and the other half are antibonding, are created when these four orbitals from one atom interact with these four orbitals from another atom.

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The capacitance of capacitor is 6.44 μF.

We need to know about the capacitance of the air-filled capacitor to solve this problem. The capacitance of the air-filled capacitor depends on the charge and voltage. It can be written as

C = Q/V

where C is capacitance, Q is charge and V is voltage.

Capacitance also can be calculated by the area and distance between the capacitor plate

C = εo . A / d

where εo is vacuum permittivity (8.85 x 10¯¹² F/m), A is the area of the plate and d is distance.

From the question above, we know that

A = 0.8 m²

d = 1.1 x 10¯⁶ m

By substituting the given parameters, we can calculate the capacitance

C = εo . A / d

C = 8.85 x 10¯¹² . 0.8 / 1.1 x 10¯⁶

C = 6.44 x 10¯⁶ F

C = 6.44 μF

Hence, the capacitance of capacitor is 6.44 μF.

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The rate of change of the area of the triangle if the height is 7cm is 38.5 cm/s

What is Rate of change?

A rate is anything that can be measured over time. Common rates include velocity (which is the rate of distance traveled), power (rate of work being done), etc. All these have one thing in common which is that they are all divided by the amount of time it took to obtain a certain measurement.

Let the base of the triangle be b,

the height of the triangle = h

and the area of the triangle = A

Area of a triangle, A is = bh/2

Rate of change of the area, A is :

dA/dt = d(1/2(bh))/dt = 1/2 (db/dt)h + 1/2(bdh/dt)

At constant height, dh/dt = 0

that is

dA/dt = 1/2(db/dt)h

It is given that :

db/dt = 11 cm/s

h = 7cm

dA/dt = (11x7)/2  = 38.5 cm/s  

Therefore, the rate of change of the area of the triangle if the height is 7cm is 38.5 cm/s

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Answer:

5.7 seconds

Explanation:

1. We know that :

acceleration  = change in velocity / time

2. We have been given the following :
acceleration = - 3.7 m/s^2
initial velocity = 21.1 m/s
final velocity = 0 (at the rock's max greatest height its velocity is 0)
time = ?

3. Subsitute the values + rearrange for t :
-3.7 = 0 - 21.1/t
t = 0-21.1/-3.7
t = -21.1/-3.7
t = 5.7 seconds (1.d.p)

By ideal gas approximation, the pressure will rise until 1.25 times greater than the initial pressure.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

T1 = 25 ⁰C = 298 K

T2 = 100 ⁰C = 373 K

Assume that P1 = P

When the initial and final temperature is the same, we can use the ratio of pressure and temperature as

P1 / T1 = P2 / T2

P / 298 = P2 / 373

P2 = 1.25 P

Hence, the pressure will rise until 1.25 times greater than the initial pressure.

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The height of the cliff is 8.26 m.

Time taken by a rock to reach the ground from the cliff is t.

t = 2.35 seconds

The initial velocity at which rock is thrown straight up is u.

u = 8 m/s

The gravity of the earth is g.

g = 9.8 m/s²

The height of the cliff from where is rock is thrown straight up at the initial velocity of 8 m/s is,

[tex]Height= Initial \: velocity × Time - \frac{1}{2} Gravity \: of \: the \: earth ×( Time) ^{2} [/tex]

[tex]h = 8 \times 2.35 - \frac{1}{2} \times 9.8 \times (2.35) ^{2} [/tex]

h = -8.26 m

Therefore, the height of the cliff is 8.26 m.

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The total displacement of the person will be 15 km.

If we move in a straight path means that moves towards 5 km north and then a person moves towards the 5 km west, so the total displacement of the person will be 15 km and the reason behind this is given below;

For example a car moves towards the north 5km and then directly he want to go towards the 5km west, so the total displacement will be 15 km because the car first moves towards the north so he covered 5 km and then the car directly goes towards the west 5 km, so for coming this he will again come to his initial stage and then the car will go towards the west and covers 5 km. So therefore the total displacement will be 15 km.

So we can conclude that the total displacement of the person will be 15 km.

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When the pilot reverses the propeller in a boat moving north, the boat moves with an acceleration directed south. Assume the acceleration of the boat remains constant in magnitude and direction. The boat will eventually stops and then speeds up in the reverse direction.

As the pilot reverses the propeller in a boat moving north, the boat moves with an acceleration directed south. This is because the propeller is pushing against the water in the opposite direction to the boat's motion. The acceleration of the boat remains constant in magnitude and direction until the boat reaches its maximum speed in the reverse direction. At this point, the boat will eventually stop and then speed up in the reverse direction.

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