A cylinder has a radius of 3 ft and a height of 5 ft. Find the volume

Answers

Answer 1

Question :-

A Cylinder has a Radius of 3 Ft and a Height of 5 Ft . Find the Volume .

Answer :-

Volume of Cylinder is 141.42 Ft³ .

Explanation :-

As per the provided information in the given question, we have been given that the Radius of the Cylinder is 3 Ft . The Height is given as 5 Ft . And, we have been asked to calculate the Volume of Cylinder .

For calculating the Volume , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Volume \: _{Cylinder} \: = \: \pi {r}^{2}h \: }} [/tex]

Where ,

R denotes to RadiusH denotes to Height

Therefore , by Substituting the given values in the above Formula :-

[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \pi {r}^{2}h } [/tex]

[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac {22}{7} \: \times \: ({3})^{2} \: \times \: 5 } \\ [/tex]

[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac {22}{7} \: \times \: 9 \: \times \: 5 } \\ [/tex]

[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac {22\: \times \: 9 \: \times \: 5 }{7}} \\ [/tex]

[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac { \: 990 \: }{7}} \\ [/tex]

[tex] \Longrightarrow \: \: \: \bf { Volume \: _{Cylinder} \: = \: 141.42 } [/tex]

Hence :-

Volume of Cylinder = 141.42 Ft³ .

[tex] \underline {\rule {180pt}{4pt}} [/tex]

Answer 2

Answer:

Volume of cylinder is 141.3 ft³ ( Taking value of π as 3.14 )

Step-by-step explanation:

Question : -

A cylinder has a radius of 3 ft and a height of 5 ft. Find the volume .

Given : -

Radius of cylinder = 3 ft

Height of cylinder = 5 ft

To Find : -

We have to , volume of Cylinder .

Formula Used : -

[tex] \boxed{ \sf{Volume \: of \: Cylinder = \pi r {}^{2} h }}[/tex]

Where ,

π = 3.14

r = radius of cylinder

h = height of cylinder

Solution : -

[tex] \longrightarrow \: \pi r {}^{2} h[/tex]

Now , substituting values of radius and height :

[tex]\longrightarrow \: 3.14 \times (3) {}^{2} \times 5[/tex]

Now , calculating :

[tex] \longrightarrow 3.14 \times 9 \times5 [/tex]

Firstly , multiplying 9 and 5 :

[tex]\longrightarrow \: 3.14 \times 45[/tex]

Atlast , multiplying 3.14 and 45 :

[tex] \longrightarrow \: \bold{ 141.3}[/tex]

[tex] \red{ \boxed{ \rm{Therefore , \: volume \: of \: cylinder \: is \: 141.3 \: ft {}^{3} }}}[/tex]

#Keep Learning

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=============================================================

Further Explanation:

A general exponential equation is

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-------------

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There are 10 zeros between the decimal point and the '2' in the number 0.0000000000237The number 0.0000000000237 is so small that it probably makes sense to use scientific notation to write [tex]0.0000000000237 = 2.37 \times 10^{-11}[/tex] meaning we move the decimal point 11 spots to the left to go from 2.37 back to 0.0000000000237The number 0.0000000000237 is read out as "237 ten-trillionths". Imagine splitting an object into ten trillion tiny pieces, and then shading 237 of those pieces to represent this decimal number.

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