Answer:
A downward force of magnitude 5 N is exerted on the book by the force of ... Do the downward force in Part A (gravity) and the upward force in Part B ...
what is the speed of a wave that has a frequency of 11.5Hz and a wavelength of 1.7m?
Answer:
19.55 m/s
Explanation:
Here is HOW to get the answer:
Speed = wavelength * freq
= 1.7 * 11.5 = 19.55 m / s
How many degrees is the maximum and minimum variation between the true and magnetic poles?
The maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.
What are the true and magnetic poles?The poles of the earth are the North and South poles.
The North is taken as the reference point.
The true north is a fixed point on the globe and gives the true North and South poles.
The Magnetic north is the direction that a compass needle points to as it aligns with the Earth's magnetic field and gives the magnetic North and South poles.
The maximum maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.
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Avery sees a UFO out her bedroom window and calls to report it to the police. She says, "The UFO moved 20.0 m east, 10.0 m north, and 30.0 m west before it disappeared." What was the displacement of the UFO while Avery was watching?
Answer:
10^2 + 10^2 = x^2
x = 14.2 m NW
The ball is in contact with the bat for 0.001s use the equation in the box to caluclate the force exerted by the bat on the ball
Answer:
Force = 9600N
Explanation:
If this is the right question, there should have been a question before about the what the change in the momentum of the ball was. The answer to that was 9.6kg m/s. For this part, we divide this by the time taken which was 0.001s which give us the resultant force.
resultant force = change in momentum ÷ time
= 9.6kgm/s ÷ 0.001s
= 9600N
When does a driver have to stop for a school bus
A driver have to stop for a school bus when the red lights are flashing and there is no barrier between his/her vehicle and the bus.
What are traffic rules?Traffic rules are rules that are expected to follow by the road users for the safety of everyone using the road.
For instance, when the red lights are flashing , it simply means to stop, while the green light means that the vehicle can continue to move, and yellow light means to be at alert to move.
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Two 2.0-mm diameter beads, c and d, are 12mm mm apart, measured between their centers. bead c has mass 1.0 g and charge 2.5nc nc . bead d has mass 1.7g g and charge -1.0 nc. if the beads are released from rest.
a. what is the speed vc at the instant the beads collide?
b. what is the speed vd at the instant the beads collide?
The speed of Vc at the instant bead collide is 1.38 m/s and the instant speed of Vd at the instant bead collide is 0.106 m/s.
The force of attraction on the beads are due to both gravitational force and electrostatic force
As gravitational force is very weak force as compared to electrostatic force the net force will be due to electrostatic force only.
Net Force = Electrostatic force
Net Force = K q1 q2 / r²
Net Force = (9 × 10⁹) (2.5 × 10⁻⁹) (1 × 10⁻⁹) / (14 × 10⁻³) (as distance between there centre of mass is 14 mm)
Net Force = (9 × 2.5 × 10⁻⁶) / 14
Net Force = 1.6 × 10⁻⁶
For bead c
Force = Mc × Ac = 1.6 × 10⁻⁶
(1 × 10⁻³) × Ac = 1.6 × 10⁻⁶
Ac = 1.6 × 10⁻³
Acceleration of bead C is 1.6 × 10⁻³ m/s²
For bead d
Force = Md × Ad = 1.6 × 10⁻⁶
(1.7 × 10⁻³) × Ad = 1.6 × 10⁻⁶
Ad = 0.94 × 10⁻³
Acceleration of bead D is 0.94 × 10⁻³ m/s²
Let us suppose bead C travels y distance before collision
So bead D should travel 12-y distance before collision
So speed of both the beads before the collision can be find out by using newton third law of motion
For bead C
Vc² - Uc² = 2 Ac s
Vc² = 2 × 1.6 × 10⁻³ × y
Vc² = 3.2 × 10⁻³ × y
Vc = √(3.2 × 10⁻³ × y)
For bead D
Vd² - Ud² = 2 Ad s
Vd² = 2 × 0.94 × 10⁻³ × (12-y)
Vd² = 1.88 × 10⁻³ × (12-y)
Vd = √(1.88 × 10⁻³ × (12-y))
Applying energy conservation
initial = final
0 + 0 = (1/2)McVc² - (1/2)MdVd²
(1/2)McVc² = (1/2)MdVd²
McVc² = MdVd²
1 × 10⁻³ × 3.2 × 10⁻³ × y = 1.7 × 10⁻³ × 1.88 × 10⁻³ × (12-y)
3.2 × y = 3.2 × (12-y)
y = 12-y
2y = 12
y = 6
Putting the value of y in Vc and Vd
Vc = √(3.2 × 10⁻³ × y)
Vc = √(3.2 × 10⁻³ × 6)
Vc = √(19.2 × 10⁻³)
Vc = √0.0192
Vc = 1.38 m/s (approximately)
Vd = √(1.88 × 10⁻³ × (12-y))
Vd = √(1.88 × 10⁻³ × (12-6))
Vd = √(1.88 × 10⁻³ × 6)
Vd = √(11.28 × 10⁻³)
Vd = √0.01128
Vd = 0.106 m/s (approximately)
So the speed of Vc at the instant beads collide will be approximately 1.38 m/s and Vd at the instant speed the beads collide will be approximately 0.106 m/s.
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calculate the heat energy required to increase the temperature of 10 kg of water from 25 degrees Celsius to 115 degrees Celsius
Answer:
3 767 400 joules
Explanation:
4.186 J/g-C is the specific heat of water
25 to 115 is 90 degrees C change
10 000 g is 10 kg of water
10 000 * 90 * 4.186 = 3 767 400 Joules
A body at rest is given an initial uniform acceleration of 8m/s2 for 30s after which the acceleration is reduced to 5m/s2 for the next twenty seconds. The body maintains the speed attained for 60s, after which it is brought to rest in 20s.
Explanation:
v=u+at, where v,u,a and t are the final velocity, initial velocity, acceleration and time, respectively.
For t=0 s to t=30 s , a =8 m/s 2.
For t=30 s to t=50 s , a = 5 m/s 2.
For t=50 s to t=110 s , a = 0 m/s 2.
For t=110 s to t=130 s , a is such that the body comes to rest at the end of this period.
For t=0 s to t=30 s ,v=0+8t⇒v=8t m/s.
At t=30s,v=8×30=240 m/s.
For t=30 s to t=50 s ,v=240+5(t−30)⇒v=90+5t m/s
At t=50s,v=90+5×50=340 m/s.
For t=50 s to t=110 s ,v=340 m/s.
For t=110 s to t=130 s ,v=340+a(t−110).
The body comes to a halt at t=130 s ⇒0=340+a(130−110).
0=340+20a⇒a=−34020=−17 m/s2.
For t=110 s to t=130 s ,v=340−17(t−110)=2210−17t m/s.
The chart lists four different kinds of atoms.
A chart titled Different Kinds of Atoms with the entries calcium, gold, argon, iodine.
What is true about all of these atoms?
They cannot be solids.
They are the largest units of matter.
They are the only types of atoms that exist.
They cannot be divided and still keep the properties of the element.
They cannot be divided and still keep the properties of the element true about all of these atoms. Option D is corect.
What is an atom?The atom consists of matter that may be split without releasing electrical charges.
It's also the smallest unit of matter with chemical element features. As a result, the atom is the fundamental unit of science.
In the nucleus proton and the neutron is exists. The condition of the atom to be electrically neutral is that the number of the proton and electron should be the same.
They cannot be separated while still maintaining the element's characteristics for each and every one of these atoms.
Hence, option D is corect.
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Answer:
The correct answer is d, they cannot be divided and still keep the properties of the element.
Explanation:
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durning which type of process does pressure remain consistent
A.Isothermal
B.isolated
C.Adiabatic
D.Isobaric
Answer:
[tex]\fbox {D. Isobaric}[/tex]
Explanation:
The process during which pressure remains constant is called an isobaric process.
as time passes the sound wave
Answer:
Loud to soft while pitch increases
Explanation:
Sound waves shown graphically display their amplitude (height of the graph) and their wavelength (the horizontal distance from peak to peak, or valley to valley... one full cycle).
Instead of wavelength, alternatively, one can observe the frequency of the wave (how many cycles are completed for a given unit of horizontal distance) which is in an inverse relationship with the wavelength (as a wavelength gets shorter, the frequency gets higher, and as the wavelength gets longer, the frequency gets lower).
The amplitude of a wave corresponds to how loud the sound is.
The frequency of a wave corresponds to the pitch of the sound.
Notice that on the graph, the height of the graph decreases over time (the peaks get shorter and shorter). So, the sound volume will get quieter and quieter. Using terminology that matches the answer choices, the sound will start loud and get soft.
Notice that on the graph, the wavelength decreases over time (starts with a pretty long distance between peaks, and then the distance between peaks gets shorter and shorter). Alternatively, looking at frequency, notice that the frequency gets higher and higher (on the left, one finger-width doesn't is less than one full cycle, but on the right, the same finger-width is wider than multiple cycles). So, the pitch of the sound will get higher and higher.
Thus, for this graph, the sound goes from loud to soft, and the pitch increases.
In a game of Tug-of-War,
when are the forces
unbalanced?
A. when one side lets go of the rope
B. when the net force is o N
C. when both sides pull with 55 N
a note of frequency 200Hz has a velocity of 400m/s. what is the wavelength of the note
Answer:
[tex]\huge\boxed{\sf \lambda = 2 m}[/tex]
Explanation:
Given data:Frequency = f = 200 Hz
Velocity = v = 400 m/s
Required:Wavelength = λ = ?
Formula:v = fλ
Solution:Put the givens in the formula
400 = (200)λ
Divide 200 to both sides
400/200 = λ
2 m = λ
λ = 2 m
[tex]\rule[225]{225}{2}[/tex]
Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is________________. the same. greatest to the left of the charge. greatest below the charge. greatest to the right of the charge. greatest above the charge.
Electric field strength decreases as the distance from the source increases.
How the distance from the charge affects the magnitude of the electric field?The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.
So we can conclude that Electric field strength decreases as the distance from the source increases.
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Tabitha knows the redshift value of a particular celestial object. What can she use this information most directly to find out?
the age and distance of the object
the volume and mass of the object
the material composition of the object
the life expectancy of the object
She can use the information of redshift of a celestial body is to find the age and distance of the object.
What is red shift?'Red shift' is a critical idea for astronomers. The frequency of the light is increased, so the light is observed as moving towards the red side of the range.
Tabitha knows the redshift value of a particular celestial object. She uses this information to observe the consequence of the redshift.
Thus, the red shift value is used to determine the age and distance of the object.
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Answer:
A (the age and distance of the object)
Explanation:
The Volume Of a Body weighing is 1200 kg is 250000 [tex]cm^{3}[/tex] Find ITs density.
Write With Formula
Answer:
[tex]\boxed {Density = 4800 kg/m^{3}}[/tex]
Explanation:
Formula :
[tex]\boxed {Density = \frac{Mass (kg)}{Volume (m^{3})}}[/tex]
Convert volume into standard unit :
⇒ 250000 cm³ × 10⁻⁶
⇒ 0.25 × 10⁶ × 10⁻⁶
⇒ 0.25 m³
Solve for density :
⇒ Density = 1200 kg / 0.25 m³
⇒ Density = 1200 × 4 kg/m³
⇒ Density = 4800 kg/m³
where do automatically generated statements that set the properties of the labels, buttons, and forms end up?
The generated statements that set the properties of the labels, buttons, and forms end up automatically within the InitializeComponent() method.
What is InitializeComponent?The InitializeComponent method in programming is the that have code that works with codes that creates and initializes the creates and initializes the user interface objects .
Conclusively, when a statement is generated, to when set the properties of the labels , it will definitely been felt in the InitializeComponent() method automatically.
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What local group of galaxies is the Milky Way part of?
Quasar Cluster
Andromeda Mini-Cluster
Virgo Supercluster
Hubble Open Cluster
The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C
What are Virgo Supercluster?The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.
Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.
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a protostar will continue to collapse due to gravity until it reaches the main sequence, and then gravitational collapse will stop when _____ begins.
a protostar will continue to collapse due to gravity until it reaches the main sequence, and then gravitational collapse will stop when fusion of hydrogen begins.
What is a protostar and how does gravity affect it?A protostar serves as a very young star which is very small in mass and still developing its mass from parent molecular cloud.
However, it can be affected by gravity because , when there is not collapse on the gravity, if there is fusion of hydrogen begins in it.
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If your mass is 63.7 kg, and you are standing 7.5 m away from a boulder with
a mass of 9,750.6 kg, what is the gravitational force between you and the
boulder? Newton's law of gravitation is F
Gm m₂. The gravitational
=
gravity
constant G is 6.67 x 10-11 N-m²/kg².
A. 1.10 x 104 N
B. 7.37 x 10-7 N
C. 9.82 x 10-8 N
D. 5.52 x 10-6 N
Please help me!
Answer:
B
Explanation:
F=[tex]\frac{Gm1m2}{r^2}[/tex]
F=(6.67 x 10^-11)[tex]\frac{63.7X9,750.6}{7.5^2}[/tex]
F=7.36502254e-7
The quotient of 8.4x10° and a number n results in 5.6x 1027. What is the value of n?
1.5x10-18
O 1.5x10
O 1.5x10³
1.5x10¹8
Discuss the path that light takes through the human eye
The cornea is shaped like a dome and bends light to help the eye focus. Some of this light enters the eye through an opening called the pupil (PYOO-pul). The iris (the colored part of the eye) controls how much light the pupil lets in. Next, light passes through the lens (a clear inner part of the eye).
Draw a ray diagram for a diverging lens that has a focal length of -10 cm when an object is placed 30 cm from the lens's surface. Calculate the position of the image and list the characteristics of the image.
Explanation:
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this answer will help for you
According to Newton's 2nd law of motion, if you hit a baseball with a bat it will
-hurt your hand from the reaction force
-accelerate according to the applied force
-fly in a straight line unless an outside force changes its course
-fall to the ground because of gravitational pull
Answer:
Newton's second law states that force is directly proportional to the product of mass and acceleration.
so if you hit a baseball with a bat it will accelerate according to the applied force.
Question 4 of 25
Which two chemical equations are balanced?
A. Na+ MgCl₂ → NaCl + Mg
B. 2LIOH + H₂S → Li₂S + 2H₂O
C. AgNO3 + NaCl → NaNO3 + AgCl
-
D. 3PBr3 + 2Cl2 → 3PCl3 + 2Br2
Answer:
To check whether a chemical equation is balanced or not we usually look if elements on the product side are numerically equal to the reactant side or not.
A. Na + MgCl₂ → NaCl + Mg
Reactant Product
Na = 1 1
Mg = 1 1
Cl = 2 1
Unbalanced
B. 2LiOH + H₂S → Li₂S + 2H₂O
Reactant Product
Li = 2 2
S = 1 1
O = 2 2
H = 4 4
Balanced
C. AgNO₃ + NaCl → NaNO₃ + AgCl
Reactant Product
Ag = 1 1
N = 1 1
Na = 1 1
Cl = 1 1
O = 3 3
Balanced
D. 3PBr₃ + 2Cl₂ → 3PCl₃ + 2Br₂
Reactant Product
P = 3 3
Br = 9 4
Cl = 4 9
Unbalanced
Therefore, equations B and C are balanced chemical equations.
does anyone know this whole distance and displacement concept it makes zero sense
Answer:
Distance is the total length travelled, or in other words, it is a measure of how far apart two objects are.
Displacement, on the other hand, the difference between the starting and and ending positions of an object.
For example, if a person walks 10m forwards, then 7m backwards, thereby ending up where he started, he will have travelled a distance of
10 + 7 = 17m .
But the difference between his starting and finishing positions is
10 - 7 = 3m.
If, however, the man walked 10m forwards and then 10m backwards, the distance he covered would be 10 + 10 = 20m, but the displacement would've been 0 as there would be no difference between his starting and ending positions.
Let me know if you still don't understand.
The Voyager spacecraft is moving at 17 000 m/s. How far will it travel in one year? Give your answer in km.
Explanation:
first change m/s to km/hr and time 1 year to hour b/c we are asked the to give in km. so,
v=17,000 m/s = 17000×3600/1000 = 61,200 km/hr
t= 1 year= 365 days =365day×24 hr/day = 8,760hr
therefore, V = s/t from this s = v×t =61200×8760 =536,112,000 Km
What are the characteristics of the image formed by the object?
Answer:
The image is formed by a convex lens with the object at 2F.
Image will be of same size as the objectImage will be real and upside down.Sample Response: The image created by the object is located on 2F behind the lens, real, inverted, and the same size as the actual object.
Explanation: EDGE.
Refer to the attached image!!!
The time of motion of the track star is determined as 0.837 s.
Time of motion of the track star
The time of motion of the track star is calculated as follows;
T = (2u sinθ)/g
where;
T is time of motiong is acceleration due to gravityθ is angle of projectionT = (2 x 12 x sin20)/9.8
T = 0.837 s
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a compact car is about 1289 kg and its engine has the ability to generate 183831 W. if all that power is applied from a stand still and no energy is dissipated, how fast will the car be moving after 7 seconds.
The speed of the car moving after 7 seconds will be 31.5 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
m is the mass of the car = 1289 Kg.
u is the initial velocity = 0 m/sec
a is the acceleration in m/sec²
v is the velocity after 7 seconds =?
The power developed is;
P =FV
F=ma
P=maV
183831=1289 kg × a × V
a = 142.61 / V
From Newton's second equation of motion;
V=u+at
V=0+at
V=(142.61/V)t
V²=142.61 × 7
V=31.5 m/sec
Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.
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