A firm that sells​ e-books - books in digital form downloadable from the Internet​ - sells all​ e-books relating to​ do-it-yourself topics​ (home plumbing,​ gardening, and so​ on) at the same price. At​ present, the company can earn a maximum annual profit of ​$ when it sells copies within a​ year's time. The firm incurs a ​-cent expense each time a consumer downloads a​ copy, but the company must spend ​$ per year developing new editions of the​ e-books. The company has determined that it would earn zero economic profits if price were equal to average total​ cost, and in this case it could sell copies. Under marginal cost​ pricing, it could sell copies.
Part 2
In the short​ run, to the nearest​ cent, what is the​ profit-maximizing price of​ e-books relating to​ do-it-yourself topics? ​$

enter your response here.
Part 3
At the​ profit-maximizing quantity, to the nearest​ cent, what is the average total cost of producing​ e-books? ​$

enter your response here.

By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation [tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex] with y(0) = e is [tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex].

In this question we must separate each variable on each side of the equivalence, integrate each side of the expression and find an explicit expression (y = f(x)) if possible.

[tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex]

[tex](\ln y)^{2}\,dy = -y \cdot \sqrt{x}\, dx[/tex]

[tex]-\frac{(\ln y)^{2}}{y}\, dy = \sqrt{x} \,dx[/tex]

[tex]-\int {\frac{(\ln y)^{2}}{y} } \, dy = \int {\sqrt{x}} \, dx[/tex]

If u = ㏑ y and du = dy/y, then:

[tex]-\int {u^{2}\,du } = \int {x^{\frac{1}{2} }} \, dx[/tex]

[tex]-\frac{1}{3}\cdot u^{3} = \frac{2\cdot x^{\frac{3}{2} }}{3} + C[/tex]

[tex]u^{3} = -2\cdot x^{\frac{3}{2} } + C[/tex]

[tex](\ln y)^{3} = - 2\cdot x^{\frac{3}{2} } + C[/tex]

[tex]C = (\ln e)^{3}[/tex]

[tex]C = 1[/tex]

And finally we get the explicit expression:

[tex]\ln y = \sqrt [3]{-2\cdot x^{\frac{3}{2} }+ 1}[/tex]

[tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex]

By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation [tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex] with y(0) = e is [tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex].

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Answer:

Step-by-step explanation:

(h+k)(1)=h(1)+k(1)=2+(-1)=2-1=1

(k-h)(4)=k(4)-h(4)=0-(-1)=1

(k/h)(3)[tex]=\frac{k(3)}{h(3)} =\frac{-1}{0} =- \infty[/tex]

(h.k)(0)=h(0).k(0)=3(-2)=-6

(k.h)(0)=k(0).h(0)=-2(3)=-6

(h.k)(3)=h(3).k(3)=0(-1)=0

h(k(-2))=h(-3)=0

Answer:

I think the answer is 7

don't blame me if I'm wrong

Answer:

359

Step-by-step explanation:

the prime factors of the numbers are

18 = 2×3×3

20 = 2×2×5

24 = 2×2×2×3

the lowest common multiple is therefore

2×2×2×3×3×5 = 360

the difference between the checked divisor numbers and the expected remainder is constantly 1 :

18 - 17 = 1

20 - 19 = 1

24 - 23 = 1

so, we can deduct this constant 1 from the LCM and get the desired number :

360 - 1 = 359

verify :

359 ÷ 18 = 19 remainder 17

359 ÷ 20 = 17 remainder 19

359 ÷ 24 = 14 remainder 23

Excluyendo el componente de ganancia del coste para el consumidor según (1), la impresora tuvo un coste de $ 211.111,11 para el vendedor.

En el enunciado tenemos el precio de una impresora para el consumidor, el cual comprende el dinero invertido por vendedor más la ganancia esperada. Este indicador observa la siguiente fórmula:

C' = C · (1 + r/100)     (1)

Donde:

Si sabemos que C' = $ 285.000 y r = 35 %, entonces el coste asumido por el vendedor es:

285.000 = 1,35 · C'

C' ≈ 211.111,11

Excluyendo el componente de ganancia del coste para el consumidor según (1), la impresora tuvo un coste de $ 211.111,11 para el vendedor.

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The appropriate expression to identify the amount of formalin is: x = 3200 ÷ 100 × 44%

To calculate the amount of formalin in this substance we must perform the following mathematical operation:

According to the above, the mathematical expression would be:

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The z-score for 81 is 1.75

The given parameters are:

μ = 60 , X=81, and σ = 12

The z scores is calculated using:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

Substitute the given values

[tex]z = \frac{81 - 60}{12}[/tex]

Evaluate the difference

[tex]z = \frac{21}{12}[/tex]

Simplify

z = 1.75

Hence, the z-score for 81 is 1.75

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The baby is 111.3 ounces or 6.96 pounds lighter than an average baby.

Weight is the measurement of Gravitational force on an object.

It can be zero as in the space.

It is given in the question that

A baby weighed only 8.7 ounces at birth

weight of an average baby is 7lb 8 ounces

1 lb = 16 ounce

an average baby weight = 7 * 16 +8 = 120 ounces

The baby weight is just 8.7 ounces

so the baby is 120-8.7 = 111.3 ounces lighter than an average baby.

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The value of the z test statistic will be 2.55.

The z test statistic is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The z test statistics is given as

z = (x – μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

A sample of 25 provided a sample mean μ = 14 and a sample standard deviation σ = 4.32.

Then the value of the z test statistic will be

z = (x – μ) / σ

z = (25 - 14) / 4.32

z = 11 / 4.32

z = 2.546 ≈ 2.55

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Answer:

Relation 3 is not a function, as s has two outputs: tree and desk. Relation 4 is not a function for the same reason. -1 has three outputs: -2, -4, and -7.

Answer: D

Step-by-step explanation:  

6^4 = 6 x 6 x 6 x 6 = 1,296

6^4 = 1,296

Answer:

meight you gotta do better then that

Step-by-step explanation:

a picture is probably necessary

The set that represents the range of the diagram below is given as follows:

B. {3, 5, 7}.

It is the set that contains all possible output values.

In the diagram, we have that:

Hence the set that represents the range of the diagram below is given as follows:

B. {3, 5, 7}.

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The multiplicative rate of change of the function f(x) = 2 × 5ˣ is 5.

An exponential function is a type of function in math that involves exponents. A basic exponential function is of the form f(x) = bˣ, where b > 0 and b ≠ 1.

The function is given as:

f(x) = 2 X 5ˣ

The above function is an exponential function.

An exponential function is represented as:

f(x) = abˣ

Where b represents the multiplicative rate

By comparison;

b = 5

Thus, the multiplicative rate of change of the function is 5.

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Answer:

B!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

Answer: it could be

[tex](10^{4} ) ^{4}[/tex]

Step-by-step explanation:

Answer:  A B C

Step-by-step explanation:

A whole number is like 1,500 and a nonwhole number is like 33.2 or like 55/100.  

And have a good day.

Answer:

I can't answer this if you don't have the answer choices

I'm sorry

Answer:

600

Step-by-step explanation:

Because the tens digit is less than 5, round down to 600

Answer:

115.38 is what I got when I tryed to work it out

Answer:

[tex]x = \frac{y - 1150}{5} [/tex]

Step-by-step explanation:

[tex]y - 1150 = 5x \\ \frac{y - 1150}{5} = x \\ x = \frac{y - 1150}{5} [/tex]

Answer:

8 un^2

Step-by-step explanation:

to find this answer you must find the area of the rectangle and then the triangle

the rectangles area is

2 * 3 = 6 un^2

the traingle is

2 * 2 * 1/2 = 2 un^2

now you add them

6 + 2 = 8 un^2

Step-by-step explanation:

both ends are going to the same direction so the degree is even. the right side is going up so the leading coefficient is positive.

Answer: It is not a right angle.

Answer:

x = +1

x = -1

Step-by-step explanation:

x^4-1=0​

x^4=+1​

fourth root of x^4= fourth root of +1​

x = +1

x = -1

The probability that a random passenger survived is 0.38

The probability that this passenger was in first class and survived is 0.153

The probability that the passenger in the first class survived is 0.620

The probability that the passenger that survived was in first class is 0.402

The probability that the passenger that survived was in third class is 0.362

The probability that a random passenger survived is 500 / 1317 = 0.38

The probability that this passenger was in first class and survived is 201 / 1317 = 0.153

The probability that the passenger in the first class survived is:  201 /324 = 0.620

The probability that the passenger that survived was in first class: 201/500 = 0.402

The probability that the passenger that survived was in third class is: 181 / 500 = 0.362

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The slope of line p is -5, so substitute into point-slope form, we get

[tex]\boxed{y-37=-5(x+2)}[/tex]

Answer:

Two points this line can pass through (1, 4/3) and (2, 8/3)

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

          b represents the y-intercept

where the format of a point is (x, y)

Given:

we can plug in a number for x to find y

when x = 0,

y = 4/3(0)

y = 0

point: (0,0)

when x = 1,

y = 4/3(1)

y = 4/3

point: (1, 4/3)

when x = 2,

y = 4/3(2)

y = 8/3

point: (2, 8/3)

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Answer: -120

Step-by-step explanation:

[tex]2\sum^{4}_{p=1} (p^{2}-9p)=2[(1^{2}-9(1))+(2^{2}-9(2))+(3^{2}-9(3))+(4^{2}-9(4))]=\boxed{-120}[/tex]

Using simple interest, it is found that the present value of the cash inflow is of 947.

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

In this problem, the parameters are given as follows:

r = 0.08, t = 4, A(t) = 1250.

We have to solve for A(0) to find the present value, hence:

A(t) = A(0)(1 + rt)

1250 = A(0)(1 + 0.08 x 4)

A(0) = 1250/1.32

A(0) = 947.

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