A force is applied to a 2. 2 kg mass and pro- duces 2. 8 m/s² acceleration. 2 What acceleration would be produced by the same force applied to a 9. 1 kg mass? Answer in units of m/s². ​

Answers

Answer 1

The acceleration would be produced by the same force applied to a 9. 1 kg mass is 0.68 m/s².

Newton's second law states, the acceleration of an object depends directly on the net force acting on the object, and inversely on the mass of the object. The formula F = ma

F = force (Newton)m = mass of the object (kg)a = acceleration (m/s²)

Perimeter

Mass of the first object = m₁ = 2.2 kgAcceleration of the first object = a₁ = 2.8 m/s²Mass of the second object = m₂ = 9.1 kgThe same force applied to both objects F₁ = F₂

F₁ = F₂

m₁ × a₁ = m₂ × a₂

2.2 × 2.8 = 9.1 × a₂

6.16 = 9.1 × a₂

[tex]a_2 = \frac{6.16}{9.1}[/tex]

a₂ = 0.68 m/s²

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Related Questions

The sun is almost 22 million times as massive as the moon but it is nearly 400 times as far from earth. Which celestial body, the sun or the moon, exerts the greatest amount of gravitational force on you as you sit in class?.

Answers

Answer:

Explanation:

Stronger to the Sun 138 times

F = G·M·m / D²

22 000 000 / 400² ≈ 138

What is the total number of subatomic particles found in the nucleus of an atom of argon?.

Answers

The subatomic particles in the nucleus of an atom of argon depend on the nucleus and proton.

What subatomic particles?

A particle that is smaller than an atom is what is known as a subatomic particle. Protons, electrons, and neutrons are the three subatomic particles that make up an atom in most cases.

40Ar

18 protons, 22 neutrons, 18 electrons

There are 18 protons from the argon element. These 18 electrons because it is neutral, and 22 neutrons because 40 - 18 = 22.

Hence the total number of subatomic particles present in the nucleus is 22.

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Explain what type of conformity the subjects in muzafer sherif's moving light experiment were most likely experiencing, using evidence from the text to justify your answer.

Answers

The conformity most likely experienced by subjects in Muzaffar Sheriff's Moving Light experiment was internalization.

Internalization is defined as a group of people sharing similar thoughts and behaviors purely with little or no influence from one part on the other, without falsifying their behavior just to collect The type of affinities to adopt. This type of affinity is seen in those who participated in Muzaffar Sherif's Moving Light Trial.

Conformity means that people make their beliefs attitudes behaviors or perceptions more conformable to those of the group to which they belong aspire to belong or to which they desire approval. It is the process of changing to Conformity has important social implications and continues to be actively investigated.

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you are analyzing a video of a moving object and want to calculate its average velocity. the video has a frame rate of 15 fps. as you are analyzing the video frame by frame, you see that the object moves a distance of 39 cm in 9 frames. what is the average velocity of the object in m/s?

Answers

Let Distance moved by objects x = 45cm.

Velocity can be easily calculated by multiplying the centroid distance between the previous frame and the current frame by the frame rate of the video and scaling the units to meters pixels. Average velocity is defined as the change in position or displacement divided by the time interval over which the displacement occurs.

Average velocity can be positive or negative depending on the sign of the shift. From a particle's velocity versus time graph, its average velocity can be found by calculating the total area under the graph and dividing it by the appropriate time interval. For particles with uniform acceleration, the velocity-time graph is a straight line. Calculate acceleration by dividing the change in velocity by the change in time.

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Two carts, a and b, are connected by a rope 39 ft long that passes over a pulley p. Two carts on a horizontal surface are connected by a rope that passes over a pulley. The distance between the pulley p and the point q on the horizontal surface is 12 ft. Cart a is to the left of point q, and cart b is to the right of point q. Both carts are traveling from right to left. The point q is on the floor 12 ft directly beneath p and between the carts. Cart a is being pulled away from q at a speed of 4 ft/s. How fast (in ft/s) is cart b moving toward q at the instant when cart a is 5 ft from q? (round your answer to two decimal places. ).

Answers

The velocity of cart B is 1.73 ft/sec moving towards Q at instant when cart A is 5 ft away from Q .

We have given in question that,

length of rope (l) = 39 ft

the distance between pully point P and horizontal point Q = 12 ft

velocity of cart A = 4 ft/sec

let a = position of cart A relative to Q =0

b = position of cart B relative to Q =0

we want to find out value of db/dt when a = 5 ft .

da/dt = velocity of cart A = 4 ft/sec

Now, consider right angle triangle PQB,

(PB)² = 12² + b² ---(1)

(PA)² = 12² + a² (right angle triangle PQA)

39 = (PA)² + P² = √144+b² + √ 144+a²

so, 39 = √144+b² + √144+ a² ---(2)

differenating equation (2) with respect to time t

we get,0 = b/√144+b² × db/dt + a/√144+a² ×da/dt -----(3)

from equation (2) put a = 5 (given)

39 = √144+b² + √144+25 = 13 + √144+b²

144 + b² = (39-13)² = 676 => b² = 532

=> b = +√532 , b= -√532 but b is on negative side of Q= 0 so, b = -√532

Now, putting value of b, a, da/dt in equation (3)

0 = (-√532 /√144+532 )× db/dt + (5√144+25 )× 4

=> 0 = (-√532/26) × db/dt + 20/13

=> db/dt = ( 20/13 )(26/√532) = 40/√532

= 1.73 ft/sec

Hence , the velocity of cart B moving towards Q is 1.73 ft/sec when cart A is 5 ft away from point Q.

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a 2.92 kg particle has a velocity of (2.99 i hat - 3.94 j) m/s. (a) find its x and y components of momentum. px

Answers

The momentum of x 8.731 kgms⁻¹ i and y is 11.5 kgms⁻¹ components of momentum.

Momentum is the product of the mass and pace of an item. it's miles a vector quantity, owning importance and a path. Momentum may be the notion of as the "energy" when a frame is moving, which means how a whole lot pressure it can have on any other frame.

A pressure acting for a given quantity of time will change an item's momentum. positioned some other way, an unbalanced force constantly hastens an object - either speeding it up or slowing it down. If the force acts opposite the item's movement, it slows the item down.

Calculation:-

Momentum = mass × velocity

                   = 2.92 × (2.99 i)

                   = 8.731 kgms⁻¹ i

Momentum = mass × velocity

                   = 2.92 × (3.94 j)

                   = 11.5 kgms⁻¹

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Where is the sun located on Earth’s elliptical orbit?(1 point)
at a focus?
at the perihelium
at the aphelium
at the center of the two foci

Answers

Answer:

(C)

Explanation:

i took the test and please make me the brainlest

A light year is approximately 9. 5 trillion km long. 'barnard's star' is 6 light years away from earth. Calculate how many trillions of kilometres this is.

Answers

Using the theories of light year, we got that 57.0 trillion km is  'Barnard's star' away from earth.

Light is the fastest-moving stuff in the our universe. It actually travels at 186,000 miles per second (300,000 km/sec). And thus a light-year is about 5.88 trillion miles (9.46 trillion kilometers).

We know very well that ,

1 light year=9.5 trillion km

Therefore,6 light year=6×9.5 trillion km

               =>6 light year=57.0 trillion km.

Hence, if a light year is approximately 9. 5 trillion km long, 'Barnard's star' is 6 light years away from earth which is equivalent to 57 trillion of kilometres

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a certain lake, filled with fresh water, is 40 m deep and located at sea level. what is the absolute pressure (in kpa) at the bottom of the lake?

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A certain lake, filled with fresh water, is 40 m deep and located at sea level. The absolute pressure (in kpa) at the bottom of the lake will be 492.1 kPa

P1 = rho * g * h

rho = density of water

g = acceleration due to gravity

h = depth

P1 = rho * g * h

   = 997 * 9.8 * 40 = 390824  N / [tex]m^{2}[/tex] = 390.8 kPa

P(absolute pressure) =  Po + P1

  =   101.3 + 390.8  = 492.1 kPa

The absolute pressure (in kPa) at the bottom of the lake will be 492.1 kPa

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suppose the outer radius ra of a cylindrical capacitor was tripled, but the charge was kept constant. by what factor would the stored energy change?

Answers

The outer radius Ra of a cylindrical capacitor was tripled, The new stored energy will increase ( [tex]\frac{ln(3Ra/Rb)}{ln(Ra/Rb)}[/tex] ) times the initial stored energy .

Capacitance of a cylindrical capacitance = 2π∈o l / ln (Ra / R b)

U = [tex]Q^{2} / 2C[/tex]

U2 / U1 = [tex]\frac{\frac{Q^{2} }{2C2} }{\frac{Q^{2} }{2C1} }[/tex] = C1 / C2

             =    [tex]\frac{\frac{2*pi*epsilon*l }{ln(Ra/Rb)} }{\frac{ 2*pi*epsilon*l}{ln(3Ra/Rb)} }[/tex]

             =    [tex]\frac{ln(3Ra/Rb)}{ln(Ra/Rb)}[/tex]

             

U2 = U1   ( [tex]\frac{ln(3Ra/Rb)}{ln(Ra/Rb)}[/tex] )

The new stored energy will increase ( [tex]\frac{ln(3Ra/Rb)}{ln(Ra/Rb)}[/tex] ) times the initial stored energy .

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If the current in a a wire is 2. 0 amperes and the voltage across the wire is 10 volts, what is the resistance of the wire?.

Answers

The resistance of the wire will be 5 ohm.

Resistance is nothing but the opposing force applied during charges moving from one side of the wire to the another side of the wire.

According to the ohm's law we have

V ∝ I

or we can write

V = IR

where, V is the voltage applied and I is the current applied and the R is the resistance of the wire.

so we can write,

R = V/I

R = 10/2

R = 5 Ohm

Hence the resistance of the wire will be 5 ohm.

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Paint spills onto a floor in a circular pattern. The radius of the spill increases at a constant rate of 2. 5 inches per minute. How fast is the area of the spill increasing when the radius of the spill is 18 inches?.

Answers

The correct answer is 90pi in ^2/min.

Area of the spill

Area of the spill=S=πr²

dS/dr=(πr²)=2πr

Radius change with speed=dr/dt =2.5(m/s)

Area of the spill will increase with speed

dS/dt = dS/dr × dr/dt =2πr ×dr/dt

=2π×18×2.5

=282.74

Therefore the area in which the paint spilled is increasing with speed. The rate at which the area of spill is increasing is 90pi in²/min.

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a ball of mass 0.800 kg is carefully balanced on a shelf that is 2.50 m above the ground. what is its gravitational potential energy?

Answers

A ball of mass 0.800 kg is carefully balanced on a shelf that is 2.50 m above the ground. The gravitational potential energy isWhen an item is placed at a height 'h' above the ground, its potential energy is given as[tex]P.E. = mg*h[/tex]where the acceleration brought on by gravity is equal to [tex]9.8 m/s2[/tex][tex]9.8 m/s^2[/tex].To determine the solution, substitute the numbers.The conservation of energy principle mandates that all potential energy be transformed into kinetic energy when the ball hits the ground.Consequently, it is K.E = P.E right before impact (on the shelf)

         K.E. is supplied by

        [tex]K.E. = 1/2. mv2[/tex]

         [tex]KE = PE[/tex] because

         [tex]1/2*mv2 = mg*h[/tex]

         So,[tex]v = \sqrt{(2g/m)}[/tex]

What is potential energy?

An item may store energy according to its location, as we all know. In the instance of a bow and arrow, the bow stores some energy as it is drawn, and this energy is what gives the arrow its kinetic energy when it is released.Similar to this, a spring accumulates energy as it is moved away from its equilibrium state, which we can notice by the tension our hands experience when we stretch it. Potential energy is a type of energy that is created when anything changes position or condition.

However, Let's study the definition of potential energy and its formula before moving on to instances and the potential energy unit.

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Jacob and David devise an experiment to determine how tall the school building is. They stand on the roof of the school where Jacob drops a rock to the ground while David times it. From the time Jacob drops the rock to the time they hear it hit the ground, it takes 0.81 s. If the speed of sound is 340 m/s how tall is the school? Remember that it takes time for the rock to fall to the ground AND time for the sound of it to come back up for them to hear it.

Answers

Answer:

The school is 3.40 meters tall.

Explanation:

You need to equations to solve this question. You need to know the time it takes to reach the ground and the time it takes for the two observers to hear it. The distance in both cases is the same, so the two conditions can be equated to each other.

Equations.

d = the height of the buildings

a is the acceleration due to gravity and is a constant 9.8i1 m/s^2

t1 is the time it takes to hit the ground

The initial velocity = 0 because the rock was dropped

Equation One

d = vi*t + 1/2 a t^2

Equation Two

d = v * t2

v is the velocity of sound

t2 is the time it takes for the sound to come back from hitting the ground.

d is the height of the school

Solution

vi*t + 1/2 a t1 ^2 = v * t2

t2 = 0.81 - t1

The times are separate, but they add up to 0.81 so

t1 I+ t2 = 0.81

t2 = 0.81 - t1

Rewrite the equation putting in the givens. Remember vi = 0

1/2 9.81  t1^2 = 340 * (0.81 - t1)        Remove the brackets

4.91* t1^2 = 275.4 - 340 t1               Transfer the right side to the left

4.91*t1^2 + 340t1 - 275.4 = 0           Use the quadratic formula to solve

a = 4.91

b = 240

c = -275.4

t1 = (-240 +/- sqrt(240^2 - 4*4.91*-275.4))/(2*4.91)

t1 = .8007 = 0.80

t1 + t2 = 0.81

0.80 + t2 = 0.81 - 0.80

t2 = 0.01

What you have found is the time it takes for the sound to come back to the two observers which is 0.01 seconds

d(height of school) = 340 * 0.01 = 3.4 meters

       

Suppose a pv farm requires 2,000 panels to generate power at 40% efficiency. If a new panel were invented that was 50% efficient, how many panels would be required?.

Answers

The number of panels required when the efficiency of the machine changes to 50% is 1,600 panels.

What is the efficiency of a machine?

The efficiency of a machine or any device is the measure of the ratio of the output energy or output work of the machine or device to the input work or energy of the device.

The efficiency of the PV farm describes how well it converts solar energy from the sun into useful energy.

The smaller the number of panels required by the PV farm, the more efficient the PV farm is and vice versa.

The number of panels required when the efficiency of the machine changes is calculated as follows;

40% ------> 2,000 panels

50% --------> ?

= (40 x 2000) / 50

= 1,600 panels

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6. A book that weighs 48N and is lifted 11.6m from the floor to a tabletop. How much work is required to
accomplish this task?

Answers

When work=Force x distance
Therefore,48x11.6= 556.8 joule

Please help I’ll give points crown and thanks very argent Thank you

Answers

Answer:

See below

Explanation:

1A 2D 3B 4C

The random variable x is known to be uniformly distributed between 70 and 100. The probability of x having a value between 80 to 95 is.

Answers

The probability density function (pdf) for the uniform distribution has the basic formula: f(x) = 1/ (B-A) for A x B.

A continuous probability distribution, the uniform distribution is concerned with equally likely outcomes. It is referred to as having a rectangular distribution on the interval [a,b] or having a uniform distribution for the continuous random variable X. Above is a representation of the probability density function of a continuous uniform distribution. The probability of drawing a heart, club, diamond, or spade is equally likely; hence, the area under the curve is 1, which makes sense given that the total of all probabilities in a probability distribution is 1.

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A sine wave is offset 1/6 cycle with respect to time 0. What is its phase in degree and radians?.

Answers

The phase in degree and radians is 2π/6 radian.

Solution:

1/6 cycle

1/6 cycle = 1/6 × 2π = 2π/9 radian

Phase angles are measured in radians. A radian is an angle whose arc length equals its radius. One rotation is equivalent to 2π radians or 360 degrees. In electronic signals, phase is the position of the wave at a particular point in time in the waveform cycle. It measures exactly where the wave is within its cycle.

Phase is the position of the instant in the cycle of the waveform. Phase is a dimensionless quantity. A complete cycle is called a phase. Phase is also expressed in radians. Phase is a measure of the relative time difference between two sine waves. Phase is actually a time difference but is most often measured in degrees or radians.

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What net force is necessary to accelerate a 300 kg object at 3m.s^-2?

Answers

Answer:

900 N

Explanation:

Simple to remember formula:

F = m * a

  = 300 * 3  = 900  N

a car is moving with a constant speed of 20 meters per second. what total distance does the car travel in 2.0 minutes?

Answers

Answer:

2400 m

Explanation:

Dimensions in units need to match so

 2 min = 120 sec

then rate X time = distance

       20 m/s  X 120 s  = 2400 m

Answer:

Explanation:

it is 43km

According to the rutherford model, which force keeps electrons in orbit around the nucleus?.

Answers

The correct answer is centripetal force keeps electrons in orbit around the nucleus.

What is Rutherford model?

Rutherford Atomic Model - J. J. Thomson's "plum pudding" model was unable to account for some experimental findings related to the atomic structure of elements. British scientist Ernest Rutherford carried out an experiment, and using the results of this experiment, he proposed Rutherford's Atomic Model and explained the atomic structure of the elements.

Thus, in the Rutherford model, the centripetal force that maintains the electron in orbit is produced by the electrostatic attraction between the (positive) nucleus and the (negative) electron.

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A family uses the microwave to prepare their cat’s food. The cat comes running into the room when the microwave timer sounds, but not when it hears the oven timer. The cat is demonstrating the concept of.

Answers

Each cat get 3 ounces of food .

What is ounces?

Ounces is a unit of weight of one sixteenth of a pound approximately 28 gram.

An ounce is also a very small amount.

Sol-

all together there is 24 ounces

(4×6=24)

The divide 24 by 8 to see how much each cat gets

24÷8=3

3 ounces each

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f the acceleration voltage in a television tube is 13.2 kv , what are the shortest-wavelength x rays produced by the television?

Answers

1.016 nm is  the shortest-wavelength x rays produced by the television

E = hc/λ

13200×1.6×10-19 = 6.62×10-34 ×3×108 /λ

2.11×10^-17=2.144×10^-31/λ

λ = 1.016 nm

Since the relationship between wave frequency and wavelength is inverse, gamma rays have extremely tiny wavelengths that are only a small portion of the size of atoms, whereas other wavelengths can extend as far as the universe. No of the medium they are passing through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, but this isn't always stated explicitly.

The wavelength of electromagnetic radiation affects how it behaves. Speed of light = wavelength x frequency Energy = Planck's constant x frequency Wave number = 1/wavelength in cm. The wavelengths of different parts of the electromagnetic spectrum are displayed together with a rough approximation of the wavelength size.

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Clocks on a spaceship moving at high speed relative to the earth run more slowly when viewed from.

Answers

According to relativity, the clocks on the spaceship move more slowly when viewed from the spaceship.

What is relativity?

Relativity is the measure of relative motion of objects.

How to decide which clock runs more slowly?

According to Einstein's theory of relativity in 1905 its postulates state that

The speed of light is constantObjects moving near the speed of light measure a shorter length called length contractionObjects moving near the speed of light measure a shorter time called time dilation

Now, since Clocks on a spaceship moving at high speed relative to the earth. Since the clock on the spaceship is moving, using the third postulate, we see that the clock on the spaceship runs more slowly when viewed from the spaceships moving frame, since it is moving relative to the earth.

So, we can see that the clocks on the spaceship move more slowly when viewed from the spaceship.

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A cyclist starts from rest and accelerates at 1.0 m/s2
for 20 seconds. He then travels
with constant velocity for 1 minute and finally decelerates at 2.0 m/s2 until he stops. Find
his maximum velocity and the total distance travelled

Answers

The maximum velocity and the total distance traveled are equal to 20 m/s and 1500 m.

What is the velocity?

Velocity can be defined as the vector measurement of the direction and magnitude motion of an object. The velocity of an object can be determined by the rate of change in the position w.r.t. time.

From the equation of motion, we can calculate the velocity of the cyclist:

v = u +at

v = 0 + (1) (20)

v = 20 m/s

v = 20 × (3600/1000)

v = 72 Km/h

The distance covered from t = 0 to t = 20 will be:

[tex]S = ut+\frac{1}{2}at^2[/tex]

S = 0 + 0.5 ×1×(20)²

S = 200m

Then travel for  1 minute with a constant speed of 20 m/s:

Distance = v × t = 20 × 60 = 1200 m

Then decelerates at 2 m/s² calculate time:

v = u -at

0 = 20 - (2) t

t = 10 s

The distance covered in t= 10 s and u = 20 here,

S = 20 × 10 - 0.5 ×2 × (10)²

S = 100 m

Therefore, total diatance travlled = 200 + 1200 + 100 = 1500 m

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If Jenny has a mass of 45 kg, and is on Earth. What is Jenny's weight?

Answers

Answer:

441kg

Explanation:

Lets assume Jenny is on Earth, if she is on the Earth, we time 45kg by 9.8

which means her weight on Earth would be 441kg.

Answer:

441 N is Jenny's weight

Explanation:

Given:

m = 45 kg

g = 9.8 m/s²

___________

P - ?

P = m·g

P = 45·9.8 = 441 N

Please help with one of these questions or both I need it asap it’s argent

Answers

Answer:   A

Explanation:

loss and degradation of habitat (mainly deforestation), over exploitation (hunting, overfishing), invasive species, climate change, and nitrogen pollution.

A 3.5 m long frictionless pendulum of mass 2.0 kg is released from point A at an angle θ of 10 degrees. What is the speed of the pendulum at point D, half the height up to point E?

Answers

Answer:

5

Explanation:

melsun slemalawkew melsun asawkecn

An object of mass 6 kg accelerates from 5 m/s to 9 m/s in 8 s. How much work was done on the object during this time? how much power was applied? what is its change in momentum?

Answers

Answer:

(1)540 J

(2)67.5 J/s or 67.5W

(3)look at underline statement in explanation

Explanation:

(1) acceleration = change in speed ÷ time

= (9-5)m/s ÷ 8s

= 0.50 m/s²

resultant force of object during motion

= mass(in kg) × acceleration

= 6 × 0.50 = 3 N

displacement of force applied

= area under speed time graph(when sketched out, it's a trapezium)

= ½ × (5+9) × 8

= 180m

work done is measured in joules

= force × displacement of force applied

= 3N × 180m

= 540 J

detailed explanation:

altho the final unit for the work done should be Nm, but J is equal to Nm.

(2) Power is measured by J/s

therefore power = 540 J ÷ 8s = 67.5 J/s or 67.5 W

(3) the object accelerates constantly along a straight road

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