We looked at the fundamental ideas behind circular motion. Another of the race cars displayed at the start of the chapter is an example of an item moving in a circular path that must be accelerating. We established that the centrifugal acceleration, also known as centripetal acceleration
What does the term "centrifugal acceleration" refer to?To start, there is the actual gravitational acceleration, which is constantly pointing in the direction of the Earth's center and is of magnitude. Next, there is the alleged centrifugal acceleration. The direction of this acceleration, which is always directly away from the axis of rotation of the Earth, is normal.
What do centripetal & centrifugal acceleration mean?Centripetal force is really the portion of a force exerted on an item moving curvilinearly and is pointed in the direction of the axis od rotation or the center of curvature. The centrifugal force, that acts along the circle's radius and therefore is directed away of its center, is a fictitious force that moves in a circle.
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what is the direction of the electric force on the charge at the bottom left-hand vertex of the triangle due to the other two charges? caution: there are two vectors in each quadrant. compare their relative orientations.
The direction of the electric force on the charge at the bottom left-hand vertex of the triangle due to the other two charges (k * q 2)/(a 2)
What is the direction of the electric force?The amount of the charge at the triangle's top vertex, which is responsible for the charge at the bottom left corner, will act along the +ve x-axis and the +ve y-axis.
According to Coulomb's law, the forces acting on the charge at the triangle's top vertex are cos 60 and the forces acting on the charge at the bottom-left corner are
Since they resist one another, the amount of the charge caused by the charge in the bottom-right corner will only affect the -ve x-axis (like charges repel). There is a magnitude.
The top charge makes a 60° angle with the charge that we're thinking about.
F x = (k * q 2)/(a 2) * cos 60 represents the overall force acting on the charge along the x-axis.
The two x-axis forces and the y-axis force share some elements in common.
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the 500 kg engine is suspenderd from the crane boom in fig determine the resultant internal loadings acting on the cross section of the boom at point e
The resultant internal loadings acting on the cross section of the boom at point E is -2.54kN·m, force equilibrium equations.
What is equilibrium?The notion of equilibrium or balance is a very fundamental concept when dealing with forces. An object can typically be affected by multiple forces at once. A force is a vector quantity, meaning it has both a magnitude (size) and a direction.
There is no net force acting on an object and it is said to be in equilibrium if the size and direction of the forces acting on it are exactly balanced. The first law of motion states that an object at rest will remain at rest and an object in motion will remain in motion because there is no net force acting on an object in equilibrium.
We will consider segment AE of the boom, so we must first determine the pin reactions at A. Notice that member CD is a two-force member. The free-body diagram of the boom is shown in Fig. 1–5 b . Applying the equations of equilibrium,
[tex]$$\begin{gathered}\circlearrowleft+\Sigma M_A=0 ; \quad F_{C D}\left(\frac{3}{5}\right)(2 \mathrm{~m})-[500(9.81) \mathrm{N}](3 \mathrm{~m})=0 \\F_{C D}=12262.5 \mathrm{~N} \\+\Sigma F_x=0 ; \quad A_x-(12262.5 \mathrm{~N})\left(\frac{4}{5}\right)=0 \\A_x=9810 \mathrm{~N} \\+\uparrow \Sigma F_y=0 ; \quad-A_y+(12262.5 \mathrm{~N})\left(\frac{3}{5}\right)-500(9.81) \mathrm{N}=0 \\A_y=2452.5 \mathrm{~N}\end{gathered}[/tex]
The free-body diagram of segment A E is shown in Fig. 1-5 c.
Equations of Equilibrium
[tex]$$\begin{array}{ll}\rightarrow \Sigma F_x=0 ; & N_E+9810 \mathrm{~N}=0 \\& N_E=-9810 \mathrm{~N}=-9.81 \mathrm{kN} \\+\uparrow \Sigma F_y=0 ; & -V_E-2452.5 \mathrm{~N}=0 \\& V_E=-2452.5 \mathrm{~N}=-2.45 \mathrm{kN}\end{array}$$$$\begin{aligned}\circlearrowleft+\Sigma M_E=0 ; & M_E+(2452.5 \mathrm{~N})(1 \mathrm{~m})=0 \\& M_E=-2452.5 \mathrm{~N} \cdot \mathrm{m}=-2.45 \mathrm{kN} \cdot \mathrm{m}\end{aligned}$$[/tex]
Thus, The resultant internal loadings acting on the cross section of the boom at point E is -2.54kN·m.
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Full question:
The 500-kg engine is suspended from the crane boom in Fig. 1–5 a . Determine the resultant internal loadings acting on the cross section of the boom at point E .
You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 tall, is walking along side the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor's head, how far from the building should the professor be when you release the egg? Assume that the egg is in free fall.Take the free fall acceleration to be 9.80 m/s^2
The physics professor should be 3.60m far from the physics building for the egg to successfully fall on professor's head, assuming freefall motion of the egg and acceleration to be 9.80 m/s^2.
The height of the building = 46 m
The height of the professor = 1.80 m
The effective height for freefall of the egg = 46.00 - 1.80 = 44.2 m
As S = ug + 1/2a[tex]t^{2}[/tex]
44.2 = 0 + 1/2 × [tex]t^{2}[/tex] × 9.8
[tex]t^{2}[/tex] = (2 × 44.2) / 9.8
[tex]t^{2}[/tex] = [tex]\sqrt{9.02}[/tex]
[tex]t[/tex] = 3.003 s
Let the distance travelled by the professor be x
The time taken by the egg to fall is equal to the time taken by the professor to reach the building through distance x
Speed with which the professor is walking = 1.20 m/s
Now as Distance = Speed × Time,
x = 1.20 × 3.003
x = 3.6036 meters.
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The most predominant direction from which the wind blows is from the Northeasteast (NEE,which is part of the northeast but nearer to the east side). The percentage of time that the windblows from this direction is about 36.5-37% of the time.
The NEE directional component is quite consistent throughout the year, with the exception of the summer months.
What is NEE direction?The wind direction from NEE is more frequent in the winter and spring, when cold air masses dominate the region.
The other predominant direction from which the wind blows is the Southwest (SW). The percentage of time that the wind blows from the SW is approximately 31%. The SW directional component is quite consistent throughout the year, and tends to be more frequent in the summer and fall months. This direction of wind is usually associated with warm air masses, which can bring rainfall and storms.
The remaining wind directions, from the North (N), South (S), East (E), and West (W), make up the remaining 32-33% of the time. These directions are usually associated with different weather patterns and are more variable throughout the year. For example, during the summer months, the N and S directional components will be higher than the E and W directional components.
The variability in wind direction throughout the year is caused by a combination of large-scale weather patterns and local terrain. The large-scale weather patterns that affect wind direction are the prevailing winds and global circulation patterns. Local terrain also plays a role, as some areas may have more of a particular direction of wind due to their location.
Overall, the NEE and SW directions are the most predominant wind directions in the region. Although the other four directions make up the remaining portion of the wind patterns, they are usually associated with different weather patterns and are more variable throughout the year.
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Match the following data collection methods with its definition by filling in the blank with the letter of the definition.
Definitions
A. This method observes subjects with little interference in their "natural habitat".
B. This method is an intensive study of a person or a group.
C. This method uses questionnaires and interviews to collect information about people's attitudes, beliefs, feelings, behaviors, and lifestyles.
Case Studies
HELP ME!
The answers include the following:
A. This method observes subjects with little interference in their "natural habitat" - Naturalistic observation.
B. This method is an intensive study of a person or a group - Case study.
C. This method uses questionnaires and interviews to collect information about people's attitudes, beliefs, feelings, behaviors, and lifestyles - Survey.
What is Observation?Thus us referred to as the active acquisition of information from a primary source and involves the use of our senses.
Naturalistic observation is a type which involves observing subjects with little or no interference in their "natural habitat" which was why it was chosen as the correct choice,
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For each of the situations given, state whether frictional forces do positive, negative, or zero work on the italicized object.
A person exerts a horizontal force on a banana at rest on a counter top. The banana remains at rest.
a. positive
b. negative
c. zero
A person exerts a horizontal force on a banana at rest on a counter top. The banana remains at rest is zero.
What do you mean by frictional forces?When two surfaces come into contact with one another, frictional force acts to move them either in the same direction or in the opposite way. Since friction is a force that opposes or resists an object's ability to glide against another when they come into contact. As a result, the force of friction is a contact force. A force called friction always works against motion. The texture of the surfaces of the items that made contact with each other and the amount of force applied to them both have a significant impact on the frictional forces. Rolling, sliding, static, and kinetic friction are the four main categories under which frictional forces are categorised. Fluid friction is yet another significant type of friction.
Frictional forces exist between the banana and the countertop. These forces resist the motion of the banana, and it remains at rest because the force applied to it is not enough to overcome the force of friction. In this scenario, the frictional force does zero work on the banana because the banana does not move, and work is defined as force applied over a distance.
The force exerted by the person is equal and opposite to the force of friction, so the net force on the banana is zero, and no work is done on the banana.
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a 56.5 kg skateboarder starts out with a speed of 1.75 m s he does 80.0 j of work on himself by pushing with his feet against the ground in addition friction does 265 j of work on him in both cases the forces doing the work are non conservative the final speed of the skateboarder is 6.00 m s. (a) Calculate the change (ΔPE = PEf-PE0) in the gravitational potential energy. (b) How much has the vertical height of the skater changed?
(c) Is the skater above or below the starting point?
a)The gravitational potential energy has changed by 1536.92 joules.
b) The skateboarder's vertical height fluctuated by 2.919 meters.
How to apply the law of conservation of energy and the law of work?Energy to a skateboarder (a) - 1620.8J
The skateboarder's initial kinetic energy is given by K i = 1/2 * mu 2 = 1/2 * (56.5kg) * (2.44m/s) 2 = 165.5J, whereas his final kinetic energy is given by K f = 1/2 * m * v 2 = 1/2 * (56.5kg) * (7.24m/s) 2 = 1457.2J, where v is his final speed.
The kinetic energy shift is therefore Delta*K = K f - K i = 1457.2J - 166.5.J = 1290.6J.
The change in the skateboarder's mechanical energy (kinetic plus potential) is equal to the work done on
it: W = 80.0J is the effort the skateboarder did on himself, therefore Delta*K + Delta*E p = W + W f
The amount of work done by friction is W f = 265J.
The shift in gravitational potential energy is represented by the formula Delta*E p =E pf -E pi.
Delta*K = 80.0J - 265J - 1457.2J = - 1620.8J, where Delta*E p = W + W f - Delta*K.
(b) 2.97 m
The skateboarder's shift in potential energy may be expressed mathematically as Delta*E p = mg*Delta*h.
where g = 9.8m / (s 2) is the acceleration of gravity and m = 56.5 kg is the mass.
The skateboarder's change in vertical height is measured by delta*h.
Delta*h is calculated as (Delta*E p)/(mg) = (- 1620.8J)/((56.5kg)(9.8m / (s 2))) = - 2.99m.
Where the skateboarder has descended as indicated by the negative symbol. Because we are only concerned with the absolute value, the solution is h = 2.99m.
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which way and by what angle does the accelerometer in (figure 1) deflect under the following conditions?
This law can be expressed as follows: force (F) equals mass (m) times acceleration (a); F = m * a.
Calculate the object's acceleration in terms of the angle the string makes with the vertical ?
It is a frame of reference problem that requires us to exert a pseudo-force on the item.
If an object is accelerating, such as a car, the pendulum's motion must be measured in relation to the accelerating car.
On the pendulum, a pseudoforce equal to ma will be applied in the direction that the automobile is accelerating against.
Here, the pendulum's mass is m, and the car's acceleration is a.If T is the string's tension and it forms an angle of with the vertical,
T sin = mg
Ma = tsin
tanθ = a/g
θ = tan⁻¹ (a/g)
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which system element converts a sensor's minute actions into a usable indication or signal? select the best answer transducer transmitter indicator rotameter
Transducer element converts a sensor's minute actions into a usable indication or signal.
A transducer which is known as thermocouple, is able to sense changes in temperature and it produce the output voltages representative of those changes. A lot of the sensors which is used in HVACR are also transducers since they generate the electrical signal while monitoring another signal as input.
The circuit which is to be measured and the ammeters must be linked in series and it measures the current. The entire circuit where current can pass through an ammeter at relatively low currents (up to a few amperes).
Power readings are taken with a power meter. The potential difference between two locations in a circuit is measured using a voltmeter.
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which of the following are correct pairings when considering physical quantities and si units used in physics?\
The SI unit for length is the meter, The correct abbreviation for kelvins is K.
What are the SI units and physical quantities?S.I. Unit SymbolDistance (l) in meters.kilograms (kg) of mass (M).Minute (M) Second (s).Amperes of electric current (I). A.Temperature thermodynamic () Kelvin. K.Size of the material (N) It's mole.Temperature-kelvin is the proper pairing of a physical quantity and a SI unit.The length, mass, time, electric current, temperature, quantity of a substance, and luminous intensity are the seven fundamental physical units that make up the International System of Units (SI), which is used to express all physical values.Pressure and force do not share a single SI unit.The newton is the SI unit of force (N). The pascal is the pressure unit in SI (Pa).To learn more about SI unit refer to:
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students want to use the setup above to make measurements that will allow them to determine the charge-to-mass ratio q/m of the particles using a best-fit line to a linear graph. i. describe a procedure the students could use, including what quantities are varied and what measurements are recorded. also include any steps to reduce experimental uncertainty.
A procedure the students could use to determine the charge-to-mass ratio of the particles includes the following steps:
1.Obtain a sample of the particles of interest.
2.Set up a parallel plate electrostatic apparatus with a known voltage difference across the plates.
3.Measure the distance between the plates and the electric field strength between the plates.
4.Introduce the sample of particles between the plates, and use a detector to measure the current that flows between the plates.
5.Vary the voltage difference across the plates and record the corresponding current for each voltage.
6.Plot a graph of current versus voltage. The slope of this graph represents the charge-to-mass ratio of the particles.
7.To reduce experimental uncertainty, the students should use a high-precision voltmeter to measure the voltage and a high-precision ammeter to measure the current. They should also take multiple measurements at each voltage and take the average. They should also use a large number of particles to get a more accurate result.
8.Also, the students should ensure that the electrodes are clean, and the electric field is uniform across the gap, as any non-uniformity would affect the results.
9.They should also try to minimize the environmental effects such as temperature and humidity, which could affect the results.
10.Finally, repeat the experiment multiple times and take the average of the results to get the most accurate value of charge-to-mass ratio of the particles.
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A ball falls from height of 18.5 m, hits the floor, and rebounds vertically upward to height of 15.0 m. Assume that m = 0.360 kg. (a) What is the impulse (in kg. m/s) delivered to the ball by the floor? magnitude kg. m/s direction up (b) If the ball is in contact with the floor for 0.0400 seconds, what is the average force (in N) the floor exerts on the ball? magnitude direction up
(a) Impulse delivered to the ball by the floor is 3.8 kg.m/s, and direction is upward. (b) average force exerted on the ball by the floor is 95 N, and the direction is upward.
What is impulse?Amount of force applied for a certain amount of time to cause the change in momentum is called impulse.
(a) impulse delivered to ball by the floor is;
As, impulse = change in momentum = m(vf - vi)
where m is mass of the ball, vf is final velocity of the ball after the collision and vi is initial velocity of the ball before collision.
Since the ball falls from a height of 18.5 m and rebounds to a height of 15.0 m, we know that the final velocity of the ball is upward, and the initial velocity of the ball is downward.
final velocity ; vf = sqrt(2gh)
where g is acceleration due to gravity and h is height of the rebound.
initial velocity; vi = sqrt(2gh)
where g is acceleration due to gravity and h is height of the fall.
vf = sqrt(29.815) = 7.68 m/s
vi = sqrt(29.818.5) = -10.26 m/s (upwards)
So, impulse = m(vf - vi) = 0.360 kg * (7.68 m/s - (-10.26 m/s)) = 3.8 kg.m/s
The impulse delivered to the ball by the floor is 3.8 kg.m/s, and direction is upward.
(b) The average force exerted on the ball by the floor;
average force = impulse / time of contact = 3.8 kg.m/s / 0.0400 s = 95 N
direction of force is upward.
The average force exerted on the ball by the floor is 95 N, and the direction is upward.
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Based on the data in the graph, which of the following represents the total electricity production in the United States from all energy sources, in billions of kilowatt-hours, in 2017?
3.8×1012kWh represents the total electricity production in the United States from all energy sources, in billions of kilowatt-hours, in 2017.
What is meant by electricity?
The collection of physical phenomena known as electricity are those that are connected to the presence and movement of matter that possesses an electric charge.Maxwell's equations describe the phenomenon of electromagnetism, which includes both magnetism and electricity as components.Lightning, static electricity, electric heating, electric discharges, and many other common phenomena have an electrical component.An electric field is created by the existence of an electric charge, which may be positive or negative.Electric current, which results from the movement of electric charges, also creates a magnetic field.A force will act on a charge when it is positioned in an area with an electric field that is not zero.To learn more about electricity refer to
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estion 7 of 12
Macmillan Learning
A fox locates rodents under the snow by the slight sounds they make. The fox then leaps straight into the air and burrows its
nose into the snow to catch its meal. If a fox jumps up to a height of 91 cm, calculate the speed at which the fox leaves the snow
and the amount of time the fox is in the air. Ignore air resistance.
The fox spends 0.91 seconds in the air after leaving the snow at a speed of 3.84 m/s.
which the fox leaves the snow and the amount of time the fox is in the air?h = 91 cm = 0.91 m is provided.
Locate: vi, t
We may apply the formulae v = vi - 9.81 t and y = vi t - 4.905 t2.
There is a further fact that we are aware of. The fox has zero velocity at height h, the highest point of the jump:
0.91 = vi tp - 4.905 tp2 where 0 = vi - 9.81 tp
There are now two equations and two unknowns remaining. The starting velocity, vi, may be solved for.
vi = 9.81 tp - 4.905 tp2 - 9.81 tp2 - 4.905 tp2 tp = 0.391 seconds
vi=9.81 tp=3.84 m/s.
That is one response. Applying the second equation once more:
t = 3.84 t - 4.905 t2 0 = t = y = vi t - 4.905 t2 0 (3.84 - 4.905 t)
t = 0, 0.91 s
The fox spends 0.91 seconds in the air after leaving the snow at a speed of 3.84 m/s.
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Consider the proposition below.
The composition of ocean water has
remained constant for thousands of
years.
If the following statements are true,
which one provides the most support for
this proposition?
A Salt deposits that were formed
thousands of years ago by the
evaporation of ocean water have the
same composition as salt deposits
formed today.
B The composition of salt deposits formed
by the evaporation of ocean water is
similar everywhere in the world.
C The shells of marine animals that
lived thousands of years ago have
the same composition as the shells of
marine animals that live today.
D The types of marine animals living
in different parts of the world have
stayed the same for thousands of years.
Answer:
A Salt deposits that were formed thousands of years ago by the evaporation of ocean water have the same composition as salt deposits formed today would provide the most support for the proposition that the composition of ocean water has remained constant for thousands of years. This statement directly supports the idea that the composition of ocean water has not changed over time, as the salt deposits that were formed in the past have the same composition as those formed today. The other statements provide supporting evidence but not as strong as statement A.
The diagram shows the electric field due to point charge Q. Which statements are correct? Check all that apply.The electric field is nonuniform.The electric field is uniform.Charge Q is negative.Charge Q is positive.If charge A moves toward charge Q, it must be a negative charge.If charge A moves toward charge Q, it must be a positive charge
The following are correct statements about the diagram that shows the electric field due to point charge Q:
The electric field is non-uniform.Charge Q is positive.What is electric field?The attraction and repulsion of electrical charges, which is what causes electric flow, create an electric field, which is an invisible force field and is measured in Volts per metre (V/m).
This question requires us to discuss what the electric field due to point charge Q is.
As a result, we can see that the electric field, which serves as the physical field that surrounds electrically-charged particles, has a nonuniform electric field and a positive charge Q.
As a result, in terms of the electric field caused by point charge Q;
The electric field is nonuniform.Charge Q is positive.Learn more about electric field
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Complete question:
The diagram shows the electric field due to point charge Q. Which statements are correct? Check all that apply.
The electric field is nonuniform.The electric field is uniform.Charge Q is negative.Charge Q is positive.If charge A moves toward charge Q, it must be a negative charge.If charge A moves toward charge Q, it must be a positive charge.the expression indicates that under these specific conditions the work done on the particle depends on the magnitude of the force, the displacement of the particle, and the angle between the direction of the force and the direction of the displacement.
The magnitude of the force is directly related to the amount of work done; the greater the force, the greater the amount of work done on the particle.
The scalar or dot productMathematically, this is expressed as:Work = Force × Displacement × cos (θ),where θ is the angle between the force and the displacement.When a force is applied to a particle, the work done on the particle is determined by a combination of the magnitude of the force, the displacement of the particle, and the angle between the direction of the force and the direction of the displacement. The displacement is also directly related to the amount of work done; the greater the displacement, the greater the amount of work done on the particle. The angle between the direction of the force and the direction of the displacement is also related to the amount of work done; when the angle between the two is perpendicular, the amount of work done is maximised, while when the angle is parallel, the amount of work done is minimised. In conclusion, the amount of work done on a particle is determined by the magnitude of the force, the displacement of the particle, and the angle between the direction of the force and the direction of the displacement. The combination of these three factors must be taken into account when calculating the amount of work done on a particle.To learn more about the scalar or dot product refer to:
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when you drive to work on a winding road, the odometer of your car changes from 27123 km to 27134 km.
The distance traveled by car is exactly equal to the 11 km, so option B is correct, and the displacement traveled by car is less than 11 km, so option A is correct.
What do you mean by displacement?It is defined as the difference in position of an object from its initial position to its final position. The displacement vector points from the initial position to the final position, and its magnitude is equal to the distance between the two positions.
For example, if an object is moving in a straight line, its displacement can be described as the change in its position along that line. The unit of displacement is typically meters (m) or kilometers (km).
In addition, displacement is a scalar quantity in that it has only magnitude, it does not have a direction.
Given information:
The odometer's initial readout is [tex]d_i[/tex] = 27123 kilometres
The odometer's final readout is: [tex]d_f[/tex] = 27134 kilometers
Step (1)
An odometer is a device that is mounted to the dashboard of an automobile to track the miles driven.
The longest path the car has taken is the distance.
The following statement describes how far the car traveled on the winding road:
D = [tex]d_f -d_i[/tex]
Change the value in the equation above.
D= 27134km-27123km
D= 11km
As a result, the distance driven by car is exactly 11 kilometers.
Thus, choice (B) is the right one.
Step (2)
The distance between the final point and the starting point is measured as displacement. Displacement is never greater than the distance or equal to it. The displacement's expression is given as
SD
S(df-di)
Change the value in the equation above.
S<( 27134km-27123km)
S<11km
The displacement driven by car is therefore less than 11 kilometers.
Thus, choice (A) is the right one.
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The complete question is:
When you drive to work on a winding road, the odometer of your car changes from 27123 km to 27134 km.
1) The distance your car traveled is ________.
A. less than 11 km B. exactly 11 km
C. greater than 11 km
2) The magnitude of your car's displacement is ________.
A. less than 11 km B. exactly 11 km
C. greater than 11 km
A solid sphere of mass m and radius R rolls down an inclined plane from rest without slipping as shown in the figure. What will be the maximum velocity of the sphere when it will reach the ground?
A √10gh/7
B √gh/7
C √10gh/3
D √gh/3
The maximum velocity of the sphere when it will reach the ground will be [tex]\sqrt{\dfrac{10gh}{7} }[/tex]. Thus, option A is correct.
What are the lowest and highest speeds?A minimum velocity is present at a position where acceleration is both negative to the left and positive to the right. A maximum velocity is at a location where acceleration is positive to the left and negative to the right.
The displacement diminishes as the mass comes closer to the equilibrium position, which also results in a decrease in the restoring force and acceleration. There is no restoring force when the mass reaches the equilibrium position. Since there is no acceleration, the mass is travelling at its fastest possible rate.
For the maximum velocity of the sphere when it reaches the ground, the loss in gravitational potential energy is equal to the gain in translational kinetic energy and rotational kinetic energy,
[tex]$ \Rightarrow \text{ mgh} = \frac{1}{2} mv^2 + \frac{1}{2} I \omega^2[/tex]
[tex]$ \Rightarrow \text{ mgh} = \frac{1}{2} mv^2 + \frac{1}{2} \left(\frac{2}{5}mR^2\right) \omega^2[/tex]
[tex]$ \Rightarrow \text{ mgh} = \frac{1}{2} mv^2 + \frac{1}{2} \times \frac{2}{5}m \times R \times R \times \omega \times \omega[/tex]
From the no-slip condition:
v = Rω
So, [tex]\mathrm{ R \times R \times \omega \times \omega = v \times v = v^2 }[/tex]
[tex]$ \Rightarrow \text{ mgh} = \frac{1}{2} mv^2 + \frac{2}{10} mv^2[/tex]
[tex]$\mathrm{ \Rightarrow \text{ mgh} = \frac{5}{10} mv^2 + \frac{2}{10} mv^2}[/tex]
[tex]$\mathrm{ \Rightarrow \text{ mgh} = mv^2\left(\frac{5 + 2 }{10} \right)}[/tex]
[tex]$\mathrm{ \Rightarrow \text{ mgh} = mv^2\left(\frac{7 }{10} \right)}[/tex]
[tex]$\mathrm{ \Rightarrow \frac{ mgh}{mv^2} = \left(\frac{7 }{10} \right)}[/tex]
[tex]$\mathrm{ \Rightarrow 7{v^2} ={10} gh }[/tex]
[tex]$\mathrm{ \Rightarrow {v^2} = \frac {10 gh} {7}}}[/tex]
[tex]$ \Rightarrow \text v = \sqrt{\frac{10gh}{7} }[/tex]
Thus, the maximum velocity of the sphere when it will reach the ground will be [tex]\sqrt{\dfrac{10gh}{7} }[/tex]. Thus, option A is correct.
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Consider the falling object of mass 10 kg in Example 2,but assume now that the drag force is proportional to the square of the velocity.(a) If the limiting velocity is 49 m/s, show that the equation of motion can be written as dv/dt=[(49)2−v2]/245.Also see Problem 25 of Section 1.1.(b) Ifv(0)=0, find an expression for v(t )at any time.(c) Plot your solution from part (b) and the solution (26) from Example 2 on the same axes.(d) Based on your plots in part (c), compare the effect of a quadratic drag force with that of a linear drag force.(e) Find the distance x(t)that the object falls in time t.(f) Find the time T it takes the object to fall 300 m.
G = -9.81 m/s2 is the gravitational acceleration close to the earth. Simply multiply the acceleration of gravity by the length of time since anything was released to determine its speed (or velocity) after that period of time. Velocity is calculated as follows: V = gt = -9.81 m/s2 * time.
How do you find the velocity of an object falling down?Because of the gravitational attraction of the earth, an object falls faster as it descends. In close proximity to the earth, gravity accelerates at a rate of g = -9.81 m/s2. The acceleration of gravity is simply multiplied by the period of time since the object was released to determine the speed (or velocity) of the object. V = gt is the result of velocity being equal to -9.81 m/s2 * time. Just that the thing is traveling downwards is shown by the negative sign. It would be climbing the ladder if it were positive. Simply omit the negative sign if referring to velocity rather than speed.If you tossed the ball up or down rather than just letting go, you would have an initial velocity, thus you would also need to factor that into the calculation, giving you: Vo is the object's initial speed, and V equals Vo plus gt. The only difference is that this equation will only give you the up-down velocity, not the total velocity, if you tossed the ball to the side rather than straight up or down. The object's initial up-down velocity remains the value you should use for Vo.To Learn more About gravitational acceleration refer to:
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the correct, general definitions of velocity and acceleration, in terms of position vector ~r, are ~v
Velocity is a vector quantity that describes an object's change in position over time. The general definition of velocity is the derivative of the position vector ~r with respect to time, denoted as v = dr/dt. This means that velocity is the rate of change of position with respect to time. It is also a measure of how fast an object is moving in a particular direction.
Acceleration is another vector quantity that describes an object's change in velocity over time. The general definition of acceleration is the derivative of the velocity vector ~v with respect to time,
denoted as a = dv/dt. This means that acceleration is the rate of change of velocity with respect to time. It is also a measure of how quickly an object's velocity is changing.
In summary, velocity is a measure of how fast an object is moving in a particular direction, while the acceleration is a measure of how quickly an object's velocity is changing. Both are vector quantities and can be described in terms of position vector ~r.
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For each of the cases described below, draw the total acceleration vector, the radial acceleration vector, and the tangential acceleration vector.
A car is accelerating from 55 km/h to 70 km/h as it rounds a curve of constant radius... Draw the vectors sstarting at the black dot. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.
A car is going a constant 65 km/h as it rounds a curve of a constant radius... Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.
A car slows down while rounding a curve of constant radius... Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.
The circle's center is where the acceleration is pointed radially.
What is acceleration?The square of the body's speed along the wind divided by the radius (r) from the circle's center to the moving body gives rise to the centripetal acceleration, or a(centripetal), whose magnitude is equal to that.The total acceleration vector, the radial acceleration vector, and the tangential acceleration vector.v 2/r = a(centripetal).The equation for tangential acceleration is a(tangential) = r, where r is the circle's compass and is the angular acceleration. It comes from the fact that the bow length is equal to the circle's compass times the angle in radians.The circle's center is where the acceleration is pointed radially.To learn more about acceleration refer to:
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What is an Aerobic Exercise?
Responses
An exercise that makes your body use a large amount of oxygen over a long period of time
An exercise that makes your body use a large amount of oxygen over a long period of time
The ability to move and change directions
The ability to move and change directions
The ability to use your body parts and senses together
The ability to use your body parts and senses together
Ability to move and bed your body easily
An exercise that makes your body use a large amount of oxygen over a long period of time is an aerobic exercise.
What is aerobic exercise?The word "aerobic" literally means "with oxygen," meaning that the amount of oxygen that can reach the muscles to support their ability to burn fuel and move depends on how much air is breathed in. The cardiovascular system is strengthened by aerobic exercise. A great way to lose weight is through aerobic activity. Along with helping you lose weight, these exercises also improve your muscles' stamina.
Furthermore, aerobic exercise is the most effective strategy to shed extra fat since it increases the amount of oxygen that your body receives. A warm-up and cool-down should be done before and after every aerobic activity session. Individual exercise tolerance should be the foundation for advancing to higher intensities of exercise. The intensity should also be increased very gradually.
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under normal conditions, with good brakes, you can bring a car to a controlled stop from 50 m.p.h. in approximately:
Total stopping distance is more complicated than how quickly your car stops after you press the brakes.You have a minimum 268 foot total stopping distance at 50 mph.
How far will it take a car with decent brakes traveling at 50 mph to stop completely on dry pavement? The length of time it takes for your car to stop once you apply the brakes is not the same as the total stopping distance.You have a minimum 268 foot total stopping distance at 50 mph.55 Feet for Perception are included in the total of 268 feet.In the best case scenario, the braking distance is the maximum distance your car will go.It may take around 158 feet at 50 mph on dry pavement with decent brakes.It will take roughly 6 seconds to stop your car if you are moving at 55 mph.Prior to coming to a stop, the vehicle will have traveled around 302 feet.A football field's length is greater than that.To learn more about stopping distance refer
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V2
V3- 31.00 V, 13= ?, R3= 20.00 Ohms
Solve for all the necessary parts of the circuit to answer the followin
question:
What is the current (13) which is flowing through resistor three?.
HELP PLEASE GIVING BRIANLEST
620V current I3, Electric circuits can be simple or sophisticated, but they all consist of the same three fundamental parts:
The Ohm's Law: How to Solve It?V = I*R is the equation for Ohm's Law. Voltage, or V, is an abbreviation for that term. In terms of amps, I stands for current. Ohms are the units used to measure resistance, or R.Electric circuits can be simple or sophisticated, but they all consist of the same three fundamental parts: wires that transport the current through the circuit; a device, like a lamp or motor, that uses the electricity to perform some type of work; and a power source, like a battery or generator.V = I*R is the equation for Ohm's Law. Voltage, or V, is an abbreviation for that term. In terms of amps, I stands for current. Ohms are the units used to measure resistance, or R.V = I * R = 31.00 * 20.00 = 620V.
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A sperm whale can accelerate at about 0.100 m/s2 when swimming on the surface of the ocean. How far will a sperm whale travel if it starts at a speed of 1.10 m/s and accelerates to a speed of 2.44 m/s? Assume the whale travels in a straight line.
The distance traveled by the sperm whale traveling at an initial speed of 1.10m/s to 2.44m/s is 23.7m.
How to calculate distance?The distance traveled by the sperm whale can be estimated using one of the equations of motion as follows:
v² = u² + 2as
Where;
v = final velocityu = initial velocitya = accelerations = distanceAccording to this question, a sperm whale can accelerate at about 0.100 m/s² when swimming on the surface of the ocean. The distance traveled by the whale can be calculated as follows:
2.44² = 1.10² + 2(0.10)(s)
5.95 = 1.21 + 0.2s
4.74 = 0.2s
s = 23.7m
Therefore, 23.7m is the distance of the sperm whale.
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micah is cooking a pork roast for his family. he wants to be sure the pork roast has an internal temperature of at least 145 degrees fahrenheit. he uses a thermometer to measure the internal temperature at three randomly chosen places. the minimum reading in the sample is 152 degrees fahrenheit. identify the population, the parameter, the sample, and the statistic. population, minimum temperature of 145 degrees fahrenheit; parameter, all pork temperature readings; sample, three random
The population in this particular problem is the pork roast. The parameter on which the population is being evaluated is 142 degrees Fahrenheit. The sample is the three random places in the pork roast where the temperature was checked. The statistic is 152 degrees Fahrenheit, which was the minimum temperature recorded during sampling.
1. The population is the object or group on which the evaluation is being done. In this scenario, the population is the pork roast.
2. Parameter is a bar which is set for measuring a feature in the population. In this problem, Micah wants the pork roast, i.e., the population, to have a minimum temperature of 142 degrees Fahrenheit.
3. A sample is chosen at random from a given population to check if the parameter matches. In this problem, Micah checked the temperature of the pork roast at three random places to deduce the average temperature of the population.
4. The statistic is the actual measurement of the sample which is compared to the parameter. In this case, the statistic would be the average minimum temperature of 152 degrees Fahrenheit.
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LINEAR DYNAMICS, WORK ENERGY & POWER, SYSTEM OF
(PARTICLES, CONSERVATION OF MOMENTUM
Okoro and Okafor weigh 70kg and 50kg respectively and push against each
other. If Okoro pushes Okafor by a force of 700N, Okafor has pushed Okoro
with.lumo)
loops to insnog
A. 500N
enA
B. 0
C. 700N
(noitutile
D. 250N
The principle of conservation of momentum states that if two objects collide, then the total momentum before and after the collision will be the same if there is no external force acting on the colliding objects.
What is the conservation of linear momentum?The conservation of linear momentum is a general law of physics which states that the overall momentum of a system is constant and that the quantity called momentum which characterises motion never changes in an isolated collection of objects.
For a system to have its momentum conserved, it must satisfy two conditions: During the interaction, the system's mass must not change. The objects may transmit mass to one another as they interact (apply forces to one another), but any mass one object gets is offset by the loss of that mass from another.
On the reasonable assumption that space is uniform—that is, that there is nothing in the rules of physics that prevents the conservation of linear momentum—the law of conservation of linear momentum is amply supported by experiment and can even be analytically inferred.
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A rocket accelerates from rest at a rate of 66 m/s2. (a) What is its speed after it accelerates for 27 s?
A car travels at constant speed up a hill from point A to point B, as shown in the diagram below. As the car travels from A to B, its gravitational potential energy
answer choices
remains the same and its KE remains the same
increases and its KE decreases
remains the same and its KE decreases increases and its KE remains the same
A car travels at constant speed up a hill from point A to point B. As the car travels from A to B, its gravitational potential energy (b) increases and its KE decreases.
Gravitational potential energy:
If a mass (m) moves from infinity to a point within the gravitational influence of the source mass (M) without acceleration, then in transferring it to the source field. The amount of work done is stored in the form of potential energy. This is known as gravitational potential energy. It is denoted by the symbol Ug.
We know that the potential energy of an object at a position is defined as the energy stored in the object at that position. When the position of the body changes due to the influence of an external force, the change in potential energy equals the work done by the force on the body.
Under the action of gravity, the force is conservative because the work done is independent of the path of position change. Also, all these forces have potential. Since the effect of gravity on an object at infinity is zero, it has zero potential energy, which we call the reference point.
The equation for gravitational potential energy is:
GPE = m × g× h
where, m is the mass in kilograms
g is the acceleration due to gravity.
h is the height above the ground in meters.
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