A galvanic cell runs for 1 minute with a current of 0.25 a. how much charge passed through the cell in that time? (f = 96,500 c/mol)

The molecules' root-mean-square speed is R = 8.31 J/(mole⋅ K)

Molecules in any object are in constant motion, the speed of that motion being defined by the temperature of the thing . just in case of ideal gases, the speed of motion is that the function of the temperature and the molar mass of the gas only.

The root mean square speed of the molecules in the gas is given by:  vrms =√3 RT/M

Here,

T is the temperature of the gas;

R = 8.31 J/(mole⋅ K) is the universal gas constant;

M is the molar mass of the gas;

Since the molecular mass of the gas A is twice as large and therefore the speed is inversely proportional to the square root of the molar mass, the speed of molecules in B is bigger by the factor √2 ≈ 1.4

What is molar mass?

The molar mass (symbol M, SI unit kg·mol−1) is defined because the mass per unit amount of substance of a given chemical entity. keep with the definition of the mole, the chemical entity in question should be specified

What is molar mass and mole?

The molar mass of a substance is defined because the mass of 1 mol of that substance, expressed in grams per mole, and is adequate to the mass of 6.022 × 10²³ atoms, molecules, or formula units of that substance

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Answer: People may not sweat excessively because of the hypertension or higher blood pressure than 120/80 mm Hg. They are not directly related. It is possible that they get exhausted quicker than others, or they have anxiety (nervousness) and hence they sweat more. Normally excessive sweating comes from excessive activity from thyroid or pituitary glands.

The speed of the block at points just before and just after the midpoint and the time its takes the block to travel between them.

The rate at which speed and direction of movement change over time is referred to as acceleration. When something moves faster or slower, it is said to be accelerating. Motion on a circle increases even while the speed is constant because the vector is always changing.

According to Newton's second law of motion, an object's acceleration is equal to the net force applied to it divided by its mass, or a = F m. Given an object's mass and the net pressure exerted on it, one can use this acceleration equation to calculate its acceleration.

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The mass of the block is 101,700g.

The mass of an object divided by its volume is the formula for determining density. This is expressed mathematically as d = m/v, where d denotes density, m denotes mass, and v denotes object volume. The common measurements are kg/[tex]m^{3}[/tex].

Density = mass / volume

where, volume = l×b×h

volume = 20×30×15

volume = 9000[tex]cm^{3}[/tex]

Now, Density = mass / volume

11.3 = mass / 9000

mass = 101700g

Therefore, the mass of the block is 101,700g.

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The ball dropped from rest from a cliff after one second will have a final velocity of: 9.8 m/s

The free fall formula and the procedure we will use is:

fv = g* t

Where:

Information of the problem:

Applying final velocity formula we get:

fv = g* t

fv = 9.8 m/s² * 1 s

fv = 9.8 m/s

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

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A solution's concentration is a measure of how much solute has been dissolved in a given quantity of solvent or solution. A concentrated solution contains a significant amount of dissolved solute. In other words, it is the number of moles per unit volume of a solution. The standard unit for concentration is Molar or mol/dm3.

Given that:

Mass = x?

molar mass = 122.12

density = 1.27 g/ml

concentration = 100 mM = 0.1 M

volume = 250 ml

Since n = cv

And n = mass/ molar mass

Therefore,

mass/molar mass =concentration * volume

x/122.12 = 0.1 * 250

X = 3,053g

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Answer:

A. affinal

Explanation:

Once a marriage has produced offspring, in-laws become affinal relatives who are defined not only by the order of law but also by their recognition of a biological link to the child.

Explanation:

i hope you can understand my calligraphy :)

The acceleration of the bike is 2 m/s². The distance traveled during acceleration is 100 m. The total distance covered by bike is 700m.

The equations of motion can be described as the relationship between the acceleration (a), velocity, time (t), and displacement of a moving object.

The equations of motions can be demonstrated as follows:

[tex]v = u + at\\S = ut +(1/2)at^2\\v^2-u^2= 2aS[/tex]

Given, the initial speed of the bike, u = 0

The final speed of the bike, v = 40 m/s

The time takes to get this speed, t = 20 s

v = u + at

40 = 0 + a(20)

a = 2 m/s²

The distance traveled during acceleration, v²- u²= 2aS

(20)² - (0) = 2 ×2 ×S

S = 100 m

The total distance covered by the bike:

For the next 15 seconds, Distance = v ×t = 40 × 15 = 600 m

The total distance covered by bike = 100 + 600 = 700 m

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Adiabatic process is the process where a unit of mass of steam is expanded in a cylinder in such a manner that no energy is added or lost as heat.

A thermodynamic process known as an adiabatic process takes place when there is no exchange of mass or heat between the thermodynamic system and its surroundings. An adiabatic process, as contrast to an isothermal process, solely transfers energy as work to the environment.

The adiabatic process is a fundamental idea in thermodynamics and supports the theory behind the first law of thermodynamics.

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Answer:

ρ (density) = M / V         mass / unit volume

ρ = 10 g / 5 cm^3 = 2 g/cm^3        density of the metal

Percentage of the mechanical energy of the oscillator is lost in each cycle is 8%

The mechanical energy can be written as the maximum kinetic energy. Hence,

E=Kmax

=12mv²

|\E=12mA²ω² .........(i)

On differentiating, we get

/dE=mAω²dA…. /(ii)

Dividing eq.(ii)by equation(i), we get

dEE(mechanical energy) =mAω²dA (1/2) mA²ω²

=2dAA

=2(4.0%)

=8.0%

The difference between the mean or equilibrium position and either extreme is the oscillation's amplitude. The particle oscillates completely back and forth from its mean position

Mechanical energy is the energy that is obtained by the things that do the work. The energy that an object possesses as a result of its motion or position is known as mechanical energy. Kinetic energy, or the energy of motion, and potential energy are two types of mechanical energy (stored energy of position)

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the magnitude of the net vertical force (including the effects of gravity) on the airplane is  = 10491.2 N

Magnitude of net vertical force on airplane

= 68 × 16.2 m³/s

volume of air under the surface

= 58 × 16.2 m³/s

total upward thrust by air

=[ 68 + 58 ] × 16.2 m³ /s× 1.20 kg/m³ × 9.81

= 24029 N

Weight =1380 × 9.81

            =13537.8

the magnitude of the net vertical force (including the effects of gravity) on the airplane

                                             = 24029 - 13537.8

                                                  = 10491.2 N

The net force is the vector sum of all the forces that react on  an object. That is to say, the net force is the total  sum of all the forces, taking into account the fact that a force is a vector and two forces of same  magnitude and opposite direction will cancel each other out

In mechanics, the web force is the vector sum of forces acting on a particle or object. the web force is a single force that replaces the effect of the original forces on the particle's motion. It gives the particle the identical acceleration as all those actual forces together as described by Newton's second law of motion.

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Answer:

increasing the speed o

Explanation:

direction change

The graph which shows the position of the object at a particular time is called a position-time graph. The position of the object is increasing with time.

The graph which shows the position of the object at a particular time is called a position time graph.

In the given graph, The position of the object in the 1st minute was 50 m, and the position of the object in the 3rd minute was between 50 to 100. The position of the object at the 5th minute was in the range of 100 to 150 m.

The position-time graph shows the velocity of the object. The slope of the object gives the location of the object.

There are two types of graphs such as straight line graphs and curve graphs. If the graph is curved it is showing the slope of the object keeps on changing.

Therefore, The graph which shows the position of the object at a particular time is called the position-time graph. The position of the object is increasing with time.

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The cannonball will be in the air a time of: 3.6421 s

The horizontal launch formula we will use and the procedure is:

t = √((2 * h) / g)

Where:

Information about the problem:

Applying the time formula we have:

t = √((2 * h) / g)

t = √((2 * 65 m) / 9.8 m/s²)

t = √(130 m / 9.8 m/s²)

t = √(13.2653 s²)

t = 3.6421 s

Is the motion described by an object that has been thrown horizontally with no angle of inclination at a certain height and considers the effect that the force of the earth's gravity has on the thrown object.

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Outer edge of a wheel of radius 0.650 m. the wheel rotates at a constant rate of 230 rev/min. The speed is 15.65 m/s.

The wheel is rotating at a rate of 230rev/min. Convert it into radians per seconds.

1 rev/min = 2πrad/60s

0.1047 rad/s

Now,

To calculate the angular velocity of the wheel rotating at a rate of 230rev/min.

ω=230rev/min × 0.1074 rad/s/rev/min

ω=24.081 rad/s

Now to find the speed

v=rω

where

r = 0.650

ω= 24.081 rad/s

Putting the values

v = 0.650× 24.081

v=15.65 m/s.

The speed is 15.65 m/s.

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If the net force on an object becomes zero and remains zero, the object will continue to move at constant velocity.

The net force acting on a body is the addition or the resultant of all the forces acting on the body. When the net force acting on a body is more than zero, it causes motion, but when it is zero, the object will remain at rest or will continue moving with uniform velocity.

This is in line with Newton's first law of motion which states that "a body will continue in its state of rest or will continue to move with uniform velocity unless it is acted upon by a force".

Thus, when the net force on a moving body becomes zero, it will not slow down or speed up, it will continue to move at the same speed. An example of this is when the passengers of a moving car fall forward when the car suddenly comes to a stop.

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Johannes Rydberg is credited with developing a formula that predicted all of hydrogen's emission lines, including those outside of visible range.

In atomic physics, the Rydberg formula calculates the wavelengths of a spectral line in many chemical elements. The formula was primarily presented as a generalization of the Balmer series for all atomic electron transitions of hydrogen. Rydberg's research was preceded by Johann Jakob Balmer's, who presented an empirical formula for the visible spectral lines of the hydrogen atom in 1885.However, Rydberg's research led him to publish a formula in 1888 which could be used to describe the spectral lines not only for hydrogen but other elements as well. Johann Jakob Balmer's was on developing a formula that predicted all of hydrogen's emission lines within the visible range, but Rydberg’s work took account of hydrogen’s emission lines outside the visible range.

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Answer: 5.91836735

Explanation:

For a problem such as this you would use the equation:

V final = V initial +(A*T)

V final = 58 m/s

V initial = 0 (b/c object begins at rest)

A (acceleration) = 9.8 m/s/s

T (time) = X

Time is our unknown variable so you would begin by plugging in your equation with the variables given, which would be:

58 m/s = 0 + (9.8 m/s/s * X)

Then you isolate X by doing:

58 m/s = 0 + (9.8 m/s/s * X)

-0             -0

58 m/s = 9.8 m/s/s * X

(58/9.8)

Getting: 5.91836735 seconds = X as your answer

The initial velocity of the airplane is 258.3 m/s and then final velocity of the airplane is 408.3 m/s.

When gravity first exerts force on an object, its initial velocity defines how quickly the object moves.

The final velocity, on the other hand, is a vector number that gauges a moving body’s speed and direction after it has reached its maximum acceleration.

According to laws of motion,

x = Vi*t = 1/2 at^2

Substituting all the values we have,

10^4 = vi (30) + 0.5(5)(30)

Simplifying it,

Vi = 258.3 m/s

According to motion equations,

Vf = Vi + at

Substituting all the values,

Vf = 258.3 + (30)(5)

Vf = 408.3 m/s

So, we have Initial velocity = 258.3 m/s and final velocity = 408.3 m/s

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The symbol of the element Iron is Fe, its proton number is 26, its atomic mass is 56, its electron number is 26  and finally Iron belong to period 4 of the periodic table.

This is defined as a substance cannot be further broken down by any chemical reaction and examples include oxygen, nitrogen etc.

Iron is an element and has an atomic number of 26 with a mass number of 56 and is present in period 4 in the periodic table.

For all atoms with no charge, the atomic number is equal to the number of proton. The number of proton is also equal to the number of electron which is why they all have the same value of 26.

Neutron = atomic mass - atomic number

                = 56 - 26 = 30

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Answer:

Gamma rays have the highest energies

Explanation:

please make my answer as brainelist

The force on the car is 1×10^5 N.

The work-energy theorem states that when a force displaces a body, the change in kinetic energy of the body is measured. Conversely, when an opposing force is applied to a body, the kinetic energy of the body decreases by the same amount. It loses kinetic energy. The bodies' loss of kinetic energy is equivalent to the labor they put into resisting the opposing force.

mass of the car, m = 2000 kg

the velocity of car  , v = 20 m/s

distance traveled, s = 4 m

let the force on the car be F

using work-energy theorem

[tex]F\times s\times cos(180) = 0.5 \times m \times ( 0 - v^2)[/tex]

[tex]F \times 4 \times(-1) = 0.5\times 2000 \times ( 0 - 20^2)[/tex]

solving for F

[tex]F = 1 \times 10^5 N[/tex]

the force on the car is [tex]1 \times 10^5 N.[/tex]

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Answer: time is inversely proportional to acceleration and free-falling bodies have acceleration.

Explanation:

according to the first equation of motion ;

a=V-v/t

where V is the final velocity and v is the initial velocity. putting the value of a as g we get;

g=V-v/t

shows the relation of g and t(gravitational acceleration and time) of free-falling bodies.

Answer:

Synthesis(Two substances that react to form one product): A + C -> AC

Decomposition(A compound that breaks down into two+ more substances): AB -> A + B

Single Replacement(replaced by another substance): A + BC -> AC + B

Double Replacement(Two substances replaced): AB + CD -> AD + CB

Combustion(A reaction between oxygen and another substance such as water) : CH + O2 -> CO2 + H2O

So that would mean that

[tex]H_{2}O + SO_{3} - > H_{2}SO_{4}= Synthesis 2H_{2}O_{2} - > 2H_{2}O + O_{2} = DecompositionPb(No_{3})_{2} + 2KI - > 2KNO_{3} + PbIx_{2} = Replacement C_{3}H_{8} + 50_{2} - > 3C0_{2} + 4H_{2}O - Combustion[/tex]

Explanation:

An object is dropped from a roof of a building of height h, the height of the building is 145.5 m.

It is given that

[tex]y_{last}[/tex]= h/3

[tex]t_{last}[/tex]= 1s

g= 9.8 m[tex]s^{-2}[/tex]

In first stage,

t1= (t-1)s  y1 = 2h/3

vi1 = 0

according to the kinematic equation,

y1= v1t1 + 1/2 g[tex]t1^{2}[/tex]

then substituting all the values, we have

2h/3 = 1/2(9.8)[tex](t-1)^{2}[/tex]

⇒ h = 7.35[tex](t-1)^{2}[/tex] → 1

Then the final velocity can be calculated by

vf1=[tex]vi^{2}[/tex]+ g(t - 1)

vf1= 9.8(t - 1)

In the second stage,

t2= 1s

y2= h/3

g=9.5 m[tex]s^{-2}[/tex]

vi2 = vf1 = 9.8(t - 1)

Acoording to kinematic equation,

y2 = vi2 t2 + 0.5g[tex]t1^{2}[/tex]

substituting the values,

h/3 = 9.8(t - 1) + 4.9

⇒ h= 29.4(t - 1) + 14.7 → 2

From equation 1 and 2, we get,

7.35[tex](t-1)^{2}[/tex] = 29.4(t - 1) + 14.7

if we assume (t-1) = R, we get

7.35[tex]R^{2}[/tex] - 29.4R - 14.7 =0

⇒R = 4.45

t = R+1 = 5.45s

substituting the value of t in equation 1, we have

h= 7.35[tex](4.45)^{2}[/tex] = 145.5m

Thus, the height of the building is 145.5m.

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The tension in the rope which a climber, that has a mass of 51 kg, is hang motionless is 499.8 N

The tension formula and the procedure we will use is:

T = m * g

Where:

Information of the problem:

Knowing that the body is in equilibrium the tension of the rope is equal to the gravity force. Applying the tension formula and substituting values we have:

T = Fg

Fg = m * g

Fg = 51 kg * 9.8 m/s²

Fg = 499.8 N

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

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Horizontal component of initial velocity = Vx = Cosθ x 18.75m/s

An object that is given an initial velocity and then affected by gravity is referred to as a projectile. These effects determine the course that the object takes. The object's trajectory is what we refer to as. A projectile's trajectory is determined by velocity in two dimensions. The projectile's x and y components each represent its horizontal and vertical motion, respectively. Meters are the units used to indicate both horizontal and vertical distances (m). Meters per second (m/s) is the unit used to express the horizontal and vertical velocities.

A projectile is in freefall once it has started moving. Gravity's downward acceleration is the sole acceleration that is having an effect on it. The magnitude of the acceleration caused by gravity (on Earth) is

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The baseball with a speed of 89.0 mph, has 8.12 s in flight

The formulas for the downward vertical launch and the procedures we will use are:

Where:

Information about the problem:

Converting the velocity from mph to m/s, we have:

89 mil/h * (1609,34 m / 1 mil) * (1h / 3600 s) = 39.786 m/s

Applying the maximum time formula for a downward vertical launch, we get:

t max= v₀ / g

t max= 39.786 m/s / 9.8 m/s²

t max = 4.06 s

Applying  the time of flight formula, we get::

t(of) =2 * t max

t(of) =2 * 4.06 s

t(of) = 8.12 s

In physics vertical launch is the motion described by an object that has been launched vertically in which the acceleration is the earth's gravitational force.

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