A garage hoist lifts a truck up 2 m above the ground in 15seconds.Find the power delivered to the truck (given 1000kg as the mass of the truck and gas 9.81m/s​

Answers

Answer 1

The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

What is power?

Power can be deifned as the rate at which work is done.

To calculate the power delivered to the truck, we use the formula below.

Formula:

P = mgh/t.............. Equation 1

Where:

P = Power delivered to the truckm = Mass of the truckh = Heightg = Acceleration due to gravityt = time

From the question,

Given:

m = 1000 kgh = 2 mt = 15 secondsg = 9.81 m/s²

Subsitute these values into equation 1

P = (1000×2×9.81)/15P = 19620/15P = 1308 W

Hence, The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

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Related Questions

Physics Help anyone?

Answers

Hi there!

A)

At this point, the pilot is experiencing a DOWNWARD NET centripetal force (ALWAYS points towards the center of the circle) as well as a downward force due to gravity. Additionally, we can say that the normal force exerted by the seat on the pilot is its apparent weight.

[tex]\Sigma F = F_g + F_N[/tex]

**The net force is the centripetal force.

We can assign both to be positive since they work in the same direction. (Assigning down as positive in THIS situation will make things easier).

We know that:
[tex]F_c = \frac{mv^2}{r}[/tex]

Fc = Centripetal force (N)
m = mass (kg)
v = velocity (m/s)

r = radius (m)

[tex]F_g = mg[/tex]

Fg = Force due to gravity (N)
m = mass (kg)
g = acceleration due to gravity (9.81 m/s²)

Solve for mass. (Given weight)

[tex]m = \frac{F_g}{g}\\\\m = \frac{719}{9.8} = 73.367 kg[/tex]
Now, we have everything we need to solve.

[tex]\frac{mv^2}{r} = F_g + F_N \\\\\frac{mv^2}{r} - F_g = F_N\\\\F_N = \frac{(73.367)(225^2)}{3110} - 719 = \boxed{475.278 N}[/tex]

B)
Weightlessness is achieved when the pilot is in free fall. In this instance, FN (Normal force by the seat) = 0 N.

We can use the same setup as above.

[tex]\frac{mv^2}{r} = F_g + 0 (F_N)[/tex]

[tex]\frac{mv^2}{r} = mg[/tex]

Solve for 'v'.

[tex]\frac{v^2}{r} = g\\\\v = \sqrt{gr} = \sqrt{(9.81)(3110)} = \boxed{174.669 \frac{m}{s}}[/tex]

C)
At the BOTTOM, we have the force of gravity working DOWNWARD (Negative in this instance), while the centripetal force (NET FORCE) and normal force are upward (Positive). Do another summation of forces:
[tex]\Sigma F = F_N - F_g\\\\\\frac{mv^2}{r} + F_g = F_N \\\\F_N = \frac{(73.367)(225^2)}{3110} + 719 = \boxed{1913.278 N}[/tex]

The reasoning question please i need help

Answers

Answer:

speed of the friend that is 8m from the center:

0.8π m/s

the distance she will travel in one rotation is:

10

Her speed compared to you is faster because, she is farther away from the axis compared to you.

Explanation:

for the speed, it says the farther you are from the axis the greater your speed is, and for the person who was 4m from the axis of rotation their speed was 0.4 because they are closer to the axis so therefore their speed is slower. so for the friend that is 8m from the axis of rotation its most likely their speed would be 0.8 m/s.

in one revolution you travel 8m your original distance from the axis was 4m so, 8-4 = 4, which means one revolution is plus 4 to your original distance. since the question is asking for rotation and not revolution you can do 4 ÷ 2 which is 2, so for rotation you need to add 2 to your original distance, so 8 + 2 = 10

write about Archimedes principle​

Answers

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics.

Answer:

When a body is immersed fully or partially in a fluid, it experience is an upward force that is equal to the weight of the fluid displaced by it.

Applications:In designing ships and submarines.Lactometers used to determine the purity of sample of milk.Hydrometer is used to determine the density of liquids.

QUESTION 9
What determines the evolutionary path a star takes through its life?
O a. Diameter
O b. Who made it
O c. Color
O d. Mass

Answers

Answer:

Mass

Explanation:

In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015

The answer would be mass

find the half life of a radioactive natural which decays to 6.25% of it's original no. of nuclei in 50 seconds.

Answers

Answer:

After 1 decay it has .9375 of its value left  

.9375^n = 1/2

What is the value of n (number of decays)

n log .9375 = -.693

n =.693 / .0645 = 10.7

After 10.7 periods of 50 sec it will have 1/2 of its original nuclei left

1/2 life = 10.7 * 50 sec = 537 sec = 8.95 min

Calculate the frequency of a sound wave produced when a tennis racquet string is plucked. The tension of the string is 274 N, the mass of the string is 28 kg and the length of the string is 0.74 m.

Answers

Answer:

Explanation:

The velocity of sound from the plucked string in the tennis racquet is:

[tex]v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}[/tex]

Then the frequency will be:

[tex]f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz[/tex]

What is the magnitude of the electric field 3m away from the source if the electric potential is described by the function f(x)=2x+3, where x=2?

Answers

Hi there!

Recall the following relationship between the electric field and electrical potential:
[tex]E = -\frac{dV}{dx}[/tex]

Begin by taking the derivative of the electric potential function using basic power and constant rules.

Remember:
[tex]\frac{dy}{dx}x^n = nx^{n - 1}[/tex]

[tex]\frac{dy}{dx}(C) = 0[/tex]

Differentiate the function, and take its negative.

[tex]-\frac{dV}{dx} = -(2(1)(x^{1-1}) + 0 )\\\\-\frac{dV}{dx} = -2[/tex]

The magnitude is the absolute value, so:
[tex]|\frac{dV}{dx} = |-2| = \boxed{2 \frac{V}{m}}[/tex]

Mrs. dela Vega had 27 students in her class last year and this year she had 30 students in her math class. What is the percent of difference?

Answers

The class grew by (30-27) = 3 students.

3 is (3/27) = 1/9 of its original size.

The class grew by 1/9 or 11.1 % .

a bag of rocks has a mass of 16.4 kg what is it weight here on the earth

Answers

Answer
160,72N
Explanation
W=mg
=(16.4)(9.8)

help me solve the following question below in the attachment

Answers

Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

[tex]E_{1}=\frac{kQ_{1}}{R_{1}^{2}}[/tex]

[tex]E_{2}=\frac{kQ_{2}}{R_{2}^{2}}[/tex]

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = [tex]k=9\times 10^{9}[/tex] in [tex]Nm^{2}/C^{2}[/tex], we can obtain:

[tex]E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}[/tex] N/C (+)

[tex]E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}[/tex] N/C (-)

So: the Electric Field at P : [tex]E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}[/tex] N/C in magnitude

A particle (q = +5.0 µC) is released from rest when it is 2.0 m from a charged particle which is held at
rest. After the positively charged particle has moved 1.0 m toward the fixed particle, it has a kinetic
energy of 50 mJ. What is the charge on the fixed particle?
a. –2.2 µC
b. +6.7 µC
c. –2.7 µC
d. +8.0 µC
e. –1.1 µC

Answers

The answer to your question is A. Have a great day

The kinetic energy of the charged particle is equal to the work done to bring it from the distance of 1 m. Hence, the total electric force here is 0.025 N. Therefore, the charge on the fixed particle is  approximately + 6.7 µC.

What is Coulomb's law ?

According Coulomb's law the electrostatic force between two charges is given by ,

F =  k q1 q2 /r²

Where q1 and q2 be the charges and r be the distance between them, k be the constant equal to 8 × 10⁹ N m²/C².

Given q1 = + 5  µC

r = 1 m.

the kinetic energy in bringing the charge of  5 µC from 2 m is given 50 mJ.

then F = 0.05 J/2 m = 0.025 N

Then q2 = F r²/ (q1 K)

q2  = 0.025 N / ( + 5  µC × 8 × 10⁹ N m²/C²)

      =  6 µC.

Therefore, option b is the approximate charge of the fixed particle.

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(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Answers

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

[tex]90 [/tex]

so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint

curd is made from milk... t or f​

Answers

Explanation:

Curd is made from milk . ( True )

Curd is made by bacterial fermentation of milk.

Answer:

very true

curd is made from warm milk and a bacterial youghurt starter and it aslo has been used for many years

pleaseee pretty please put me as brainliest

Find the Product or expression of: (4x-2)2​

Answers

Answer:

8x-4

Explanation:

Distributive property:

A(B+C)=AB+AC

(4x-2)2

Switch sides.

→ 2(4x-2)

Multiply.

⇒ 2*4x=8x

⇒ 2*2=4

Rewrite the problem down.

⇒ = 8x-4

[tex]\Longrightarrow: \boxed{\sf{8x-4}}[/tex]

Hence, the final answer is 8x-4.

I hope this helps you! Let me know if my answer is wrong or not.

Answer: 8x - 4

Explanation:

(4x -2)*2

apply distributive property

2* 4x - 2 * 2

Multiply the monomials = 8x

2*4x - 2*= 8x-2*2

calculate =

8x-4

Answer: 8x - 4

Two horses pull horizontally on ropes attached to a stump. The two forces Fu and F2 that they apply to the stump are such that the net (resultant) force R has a magnitude equal to that of Fu and makes an angle of 90° with Fu. Let F1 = 1300 N and R = 1300 N also. Find the magnitude of F and its direction (relative to Fi)

Answers

For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as

F=1711 N

dF= 135 degrees

What is the magnitude of F and its direction?

Generally, the equation for the components of F1   is mathematically given as

For The x axis

1210 - F2x = 0

F2x = 1210

For the y axis

F2y = R

F2y = 1210

In conclusion

F = sqrt(2)*1210

F=1711 N

Fopt the direction of F2

dF= 90 + 45

dF= 135 degrees

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ture or false
A land breeze is when the cooler air over the ocean moves in toward land.

Answers

Answer:

False

Explanation:

A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.

a boat travels 500 m down a strait river. if starts from the rest accelerates uniformly to a velocity of 5m/s. how long does this take?
PLSSSS HELPPPPP NOWWW!!!!!

Answers

Answer: 200 seconds

Explanation:
Initial Velocity = 0 m/s
Final Velocity = 5 m/s
Displacement = 500 m

Average Velocity = (Vo + Vf) / 2
(0 + 5) / 2 = 2.5

Time = Displacement / Average Velocity
Time = 500 / 2.5 = 200

A 0.60- m -tall barrel is filled with water (with a weight density of 9800 N/m3 ). Find the water pressure on the bottom of the barrel. Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

P =  ρ g H       explains the pressure of a uniform column of density ρ

P = ρ H            where ρ is given as a weight density

P = 9800 N/m^3 * .60 m = 5880 (5900) N / m^2

Note N/m^2 = Force / Area      the definition of pressure

The three types of cones in the human eye are

a

red, yellow, green


b

red, green, blue


c

red, blue, cyan


d

yellow, cyan, magenta

Answers

Answer:

the answer is B I hope it helps out

I’ve tried my hardest n just keep blowing my head please help!!

Answers

Answer:

Forces

Explanation:

1) A Force

2) Balanced

3) Unbalanced

4) Any object moving at a constant speed, Any object in 0 motion, A balanced see-saw (no net torque/forces)

5) Any object accelerating, Someone pushing a box

3. Hahn determined that barium (atomic number 56) was one of the elements created when a uranium atom (atomic number 92) split . Use a periodic table to determine the other element that was created during this process.​

Answers

According to a periodic table, Krypton was created during the fission of Uranium.

What is the atomic number?

Atomic number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.

Thus, the fission of uranium is led by two elements with atomic numbers 56 and 36. According to a periodic table, those atomic numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.

According to a periodic table, Krypton was created during the fission of Uranium. [tex]\blacksquare[/tex]

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A 10-cm long solenoid has 100 turns and a radius of 5 cm. If it carries a current of 2 A, What is the magnetic field B inside the solenoid

Answers

Hi there!

We can use Ampère's Law:

[tex]\oint B \cdot dl = \mu_0 i_{encl}[/tex]

B = Magnetic field strength (B)
dl = differential length element (m)
μ₀ = Permeability of free space (T/Am)

Since this is a closed-loop integral, we must integrate over a closed loop. We can integrate over a rectangular-enclosed area of the rim of the solenoid - ABCD - where AD and BC are perpendicular to the solenoid.

Thus, the magnetic field is equivalent to:
[tex]\oint B \cdot dl = \int\limits^A_B {B} \, dl + \int\limits^B_C {B} \, dl + \int\limits^C_D {B} \, dl + \int\limits^D_A {B} \, dl[/tex]

Since AD and BC are perpendicular, and since:
[tex]\oint B \cdot dl = B \cdot L = BLcos\phi[/tex]

[tex]BLcos(90) = 0[/tex]

If perpendicular to the field, the equation equals 0.

Additionally, since AB is outside of the solenoid, there is no magnetic field present, so B = 0. The only integral we integrate now is:
[tex]\oint B \cdot dl = \int\limits^C_D {B} \, dl[/tex]

Which is horizontal and inside the solenoid. Let the distance between C and D be 'L', and the enclosed current is equivalent to the number of loops multiplied by the current:

[tex]B L = \mu_0 Ni[/tex]

N = # of loops per length multiplied by the length, so:
[tex]BL = \mu_0 nL i \\\\B = \mu_0ni[/tex]

Plug in the given values and solve. Remember to convert # of loops to # of loops per unit length.

[tex]B = \mu_0 (100/0.1)(2) = (4\pi *10^{-7})(1000)(2) = \boxed{0.00251 T}[/tex]

Mrs. Martin is holding a ball from a height of 3.2 m that has the potential energy of 23 J, calculate the mass of the ball.

Answers

Answer:

0.73kg

Explanation:

Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.

Substitute:

[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]

When is an object positively charged?

Answers

Answer:

when it has a fewer amount of electrons than protons

A single coil of wire, with a radius of 0.13 m is rotated in a uniform magnetic field such that the angle between the field vector and the area vector obeys θ=ωt. If the strength of the field is 3.746 T, and the angular frequency is 524.7 rad/s, what is the induced emf in the loop at t=1.16 s?

Answers

The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.


Induced emf

The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.

emf = N(dФ/dt)

where;

N is number of turns of the wireФ is magnetic flux

Ф = BA

where;

B is magnetic field strengthA is the area of the loop

emf = NBA/t

A = πr²

A = π x (0.13)²

A = 0.053 m²

emf = NBA/t

emf = (1 x 3.746 x 0.053)/(1.16)

emf = 0.171 V

Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.

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Yesterday you walked 20 meters to the right from your house to the bus stop, which took you 20 seconds. You waited at the bus stop for 1 minute before realizing you forgot your Mathematics homework at home. You ran back to your house in 5 seconds. It took you 10 seconds to find your homework, and then you ran back to the bus stop in 5 seconds just in time to catch the bus. What was your average velocity for the entire period of motion?



a.
0.2 m/s


b.
1 m/s

c.
100 m/s

d.
20 m/s

Answers

average velocity= tot displacement/total time

avg v = 20/(20+60+5+10+5)=20/100=0.2 m/s

The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?

Answers

Answer:
11300 kgm3

Hope this helps

Which of the rays drawn above would be correct as the light goes from the air into the water?

Answers

Answer:

the answer to this question is option c

there process which eventually takes place is called refraction

Explanation:

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Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3P4 (s) → 3P4O10 (s) + 10 KCI (s) How much of each reactant will be needed to produce 105.8 g of tetraphosphorus decaoxide (P4O10)?​

Answers

Answer:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)


Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
          = 123.90*105.8/283.89
          = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
                = 10*122.55*105.8/283.89/3
                = 149 (grams).

149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .

What do you mean by reactant?

In a chemical equation, the substance or substances to the left of the arrow are referred to as reactants. A substance that is present when a chemical reaction first begins is known as a reactant.

Products refer to the material or substances to the right of the arrow. A substance that is present after a chemical reaction is complete is called a product.

Given Data:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)

Then it is given by:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

The equation becomes :

m(P4) = M(P4)*m(P4O10)/M(P4O10)

         = 123.90*105.8/283.89

         = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)

               = 10*122.55*105.8/283.89/3

               = 149 (grams).

Thus, 149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .

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- A teenage male is removing clothes from the dryer and is having difficulty because the items are
sticking together.
-What force is causing the clothes to stick together?
-What two factors in the dryer operation has produced this situation?
-What will misting the clothes with a light spray of water do?

Answers

We can confirm that the clothes are sticking together due to static forces created by the heat and friction of the dryer.

How will water help with this situation?

The clothes are stuck together due to static forces that arise when these materials are heated and the friction from the dryer cycle. Adding a light spray of water can help with this situation given that water is a strong conductor of electricity, which will help to dispel the charges that hold the clothes together.

Therefore, we can confirm that clothes are sticking together due to static forces created by the heat and friction of the dryer, which a light spray of water can help to dispel and separate the clothes.

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