A gardener has a flower pot that he wants to fill with dirt. The flower pot has a radius of 8 cm at its opening and a radius of 7 cm at its base. The flower pot has a height of 10 cm.

Part A:
Provide an estimate for the amount of dirt, in cubic centimeters, that the gardener will need to completely fill the flower pot.

Part B:
Explain how you determined your answer.

Answer:

x=3 and y=4

Step-by-step explanation:

please verify the answer

Answer:

Học sinh nam là 21 học sinh, số học sinh nữ là 15 học sinhH

Step-by-step explanation:

Tỉ số giữa nam và nữ là x/y = 7/5 => x/7 = y/5

áp dụng tính chất của dãy tỉ số bằng nhau, ta được:  

x/7 = y/5 => x-y =/7-5 = 6/2 = 3

Vì x/7 = 3 => x = 21

y/5 = 3 => y= 15

Vậy số học sinh nam là 21 học sinh, số học sinh nữ là 15 học sinh

Given:

The quadratic equation is:

[tex]3x^2+x-5=0[/tex]

To find:

The solution for the given equation rounded to 2 decimal places.

Solution:

Quadratic formula: If a quadratic equation is [tex]ax^2+bx+c=0[/tex], then:

[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

We have,

[tex]3x^2+x-5=0[/tex]

Here, [tex]a=3,b=1,c=-5[/tex]. Using the quadratic formula, we get

[tex]x=\dfrac{-1\pm \sqrt{1^2-4(3)(-5)}}{2(3)}[/tex]

[tex]x=\dfrac{-1\pm \sqrt{1+60}}{6}[/tex]

[tex]x=\dfrac{-1\pm \sqrt{61}}{6}[/tex]

[tex]x=\dfrac{-1\pm 7.81025}{6}[/tex]

Now,

[tex]x=\dfrac{-1+7.81025}{6}[/tex]

[tex]x=1.13504167[/tex]

[tex]x\approx 1.14[/tex]

And

[tex]x=\dfrac{-1-7.81025}{6}[/tex]

[tex]x=-1.468375[/tex]

[tex]x\approx -1.47[/tex]

Therefore, the required solutions are 1.14 and -1.47.

Answer:

x=9

Step-by-step explanation:

4(x-2)=2x+10

<=> 4x-8=2x+10

<=> 2x=18

<=>x=9

Answer:

x=3 the explanation is above

Answer:

X ≥ 3

Step-by-step explanation:

Let the number of grapes you'll buy be X, you need to buy at leaF 3 pounds so:

X ≥ 3

Answered by Gauthmath

Answer:

1) 6а-9b=3(2a-3b)

2)8a-12b=4(2a-3b)

3) 5ab-5ac=5a(b-c)

4) 6ax+6ay=6a(x+y)

Answer:

-14x+4y

this is the correct answer.

Complete question is;

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t – 16t². How long after launch does the projectile return to the ground?

Answer:

2 seconds

Step-by-step explanation:

We are told that the height function is given by;

h = 32t – 16t²

Now, the velocity will be the derivative of the height equation.

Thus;

v(t) = dh/dt = 32 - 32t

Now, for projectiles, at max height, v = 0.

Thus;

32 - 32t = 0

32t = 32

t = 32/32

t = 1 s

It will take the same time it took to get to Max height as it will to get to ground from that height.

Thus, total height = 1 + 1 = 2 seconds

Answer:

24+p=t

Step-by-step explanation:

If he scored 24 points in the first half, and p in the next half, he scored a total of t points.

Step-by-step explanation:

In this problem, all we have to do is replace x and y with the values we've been given.

It can be helpful to think of 3x as 3 * x (which is the same exact thing), so I'll write it out that way.

3*x - 4*y

(replace)

3*4 - 4*3

(multiply (doing this step first because of PEMDAS))

12 - 12

(subtract)

0

Answer:

0

Answer: 0

Step-by-step explanation:

Concept:

Here, we need to understand the idea of evaluation.  

When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.

Solve:

Given

3x - 4y

x = 4, y = 3

Substitute value of x and y

3(4) - 4(3)

Simplify multiplication

12 - 12

Final subtraction

0

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Step-by-step explanation:

The rule is that opposite angles are supplementary. Therefore, angle A plus angle C = 180:

angle A + 43 = 180 and

angle A = 180 - 43 so

angle A = 137

Answer:

Domain = all real numbers

range = -1<= y <= 1

The domain of y=cosx is all real numbers and the range is -1 ≤ y ≤ 1.

The range of 'x' of a function is known as the domain of definition of a function and the range of 'y' of a function is known as the range of the function.

The function is continuous for all real values of 'x'.

Hence, the domain of the function is all real numbers.

The upper limit value of cosx =1 and lower limit value of cosx = -1 .

Hence, the range of the function is -1 ≤ y ≤ 1.

Learn more about domain and range here :

https://brainly.ph/question/42072

#SPJ2

Answer:

A

Step-by-step explanation:

Divide both sides with -16. ALWAYS remember that if you divide any number with a negative number, this "< ≤ > ≥" symbols have to change to the opposite direction

2(x + 3) = 2x + 6

1. Correct - 2 * (x + 3) = 2x + 6

2. Correct - (x + 3)2 = 2x + 6

3. Correct - 2x + 6

4. Incorrect - 2x + 3

5. Incorrect - 2x + 3

6. Incorrect - 3x + 6

Hope this helps!

Answer:

x = 45

Step-by-step explanation:

The angles labeled with the pink x are the same.  Line V and Line X are parallel and alternate interior angles are equal when the lines are parallel.

We know the 3 angles inside the triangle and the sum of the angles of a triangle are 180

x+x+ 2x = 180

4x= 180

4x/4 = 180/4

x = 45

Answer:

Step-by-step explanation:

Function 2 has a slope of 1.1 while function 1 has a slope of just 1.

We have to find the circumference

[tex]\\ \rm\longmapsto C=2\pi r[/tex]

[tex]\\ \rm\longmapsto C=2\dfrac{22}{7}(14)[/tex]

[tex]\\ \rm\longmapsto C=44(2)[/tex]

[tex]\\ \rm\longmapsto C=88cm[/tex]

Answer:

Top right option

Step-by-step explanation:

multiplying the digits, you get the volume, which is 3/4

Answered by GAUTHMATH

Answer:

The domain is the whole R-{0} and the range is R

The question is incomplete. The complete question is :

In a survey of women in a certain country ( ages 20-29), the mean height was 62.9 inches with a standard deviation of 2.81 inches.  Answer the following questions about the specified normal distribution.  (a) What height represents the 99th percentile?  (b) What height represents the first quartile?  (Round to two decimal places as needed)

Solution :

Let the random variable X represents the height of women in a country.

Given :

X is normal with mean, μ = [tex]62.9[/tex] inches and the standard deviation, σ = [tex]2.81[/tex] inches

Let,

[tex]$Z=\frac{X - 62.9}{2.81}$[/tex] , then Z is a standard normal

a). Let the [tex]99th[/tex] percentile is = a

The point a is such that,

[tex]$P(X<a)=0.99$[/tex]

[tex]$P \left( Z < \frac{a-62.9}{2.81} \right) = 0.99$[/tex]

From standard table, we get : [tex]P( Z < 2.3263) =0.99[/tex]

∴ [tex]$\frac{(a-62.9)}{281} = 2.3263$[/tex]

  [tex]$a= (2.3263 \times 2.81 ) +62.9$[/tex]

     = 6.536903 + 62.9

     = 69.436903

     = 69.5 (rounding off)

Therefore, the height represents the [tex]99th[/tex] percentile = 69.5 inches.

b). Let b = height represents the first quartile.

It is given by :

[tex]P( X < b) =0.25[/tex]

[tex]$P \left( Z < \frac{(b-62.9)}{2.81} \right) = 0.25$[/tex]

From the standard normal table,

[tex]P( Z < -0.6745) =0.99[/tex]

∴ [tex]$\frac{(b-62.9)}{2.81}= 0.6745$[/tex]

[tex]$b=(0.6745 \times 2.81) +62.9$[/tex]

  = 1.895345 + 62.9

   = 64.795345

   = 64.8 (rounding off)

Therefore, the height represents the 1st quartile is 64.8 inches.

Answer:

12 minutes

Step-by-step explanation:

Given

[tex]s_1 = 10mi/h[/tex] --- walk speed

[tex]s_2 = 20mi/h[/tex] --- jog speed

[tex]d = 2\ miles[/tex] --- distance

Required

The time to walk the given distance

Time is calculated as:

[tex]Time = \frac{distance}{speed}[/tex]

In this case, the speed is the speed at which she walks.

So, we have:

[tex]Time = \frac{d}{s_1}[/tex]

Substitute known values

[tex]Time = \frac{2mi}{10mi/h}[/tex]

[tex]Time = 0.2hr[/tex]

Convert to minutes

[tex]Time = 0.2 * 60mins[/tex]

[tex]Time =12mins[/tex]

Step-by-step explanation:

x+2>7

x>7-2

x>5

2x+5>_ 15

2x>_ 15-5

2x>_ 10

2x/2>_ 10/2

x>_5

I assume you're supposed to find the limit as n approaches infinity, not x.

You have

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5.3^n+1}{2.4^n+2} = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-\left(\dfrac{5.3}{5.3}\right)^n+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}} \\\\ = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-1+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}}[/tex]

For |x| < 1, we have lim |x|ⁿ = 0 as n goes to infinity. Then each exponential term converges to 0, which leaves us with -1/0. This means the limit is negative infinity.

On the other hand, perhaps you meant to write

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5\times3^n+1}{2\times4^n+2}[/tex]

The same algebraic manipulation gives us

[tex]\displaystyle\lim_{n\to\infty}\frac{\left(\dfrac44\right)^n-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2\left(\dfrac44\right)^n+\dfrac2{4^n}} = \lim_{n\to\infty}\frac{1-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2+\dfrac2{4^n}}[/tex]

Again the exponential terms converge to 0, but this time we're left with the limit 1/2.

Answer: [tex]9\times 11\ ft^2[/tex]

Step-by-step explanation:

Given

Height is [tex]2\ ft[/tex] more than its width

Suppose the width is [tex]x[/tex]. So, height becomes [tex]x+2[/tex]

Area of the painting is [tex]99\ ft^2[/tex]

Area is the product of width and height

[tex]\therefore 99=x(x+2)\\\Rightarrow 99=x^2+2x\\\Rightarrow x^2+2x-99=0\\\Rightarrow x^2+11x-9x-99=0\\\Rightarrow (x+11)(x-9)=0\\\Rightarrow x=-11,9[/tex]

Neglect the negative values

[tex]\text{Width =}9\ ft\\\text{height =}9+2=11\ ft[/tex]

Answer:

4, 7, 14

Step-by-step explanation:

Because it's were it decreases

Answer:

Pentagon = 72°

Octagon = 45°

Step-by-step explanation:

To solve for the measure of one exterior angle in a regular pentagon;

n = number of sides

180 - (180 x n-2/n)

180 - (180 x 5-2/5)

180 - (180 x 3/5)

180 - (540/5)

180 - 108

Exterior angle = 72°

To solve for the measure of one exterior angle in a regular octagon;

n = number of sides

180 - (180 x n-2/n)

180 - (180 x 8-2/8)

180 - (180 x 6/8)

180 - (1080/8)

180 - 135

Exterior angle = 45°

Answer:

it should be 6

Step-by-step explanation:

I could be wrong

Answer:

75 degrees

Step-by-step explanation:

Use trigonometry

we are given opposite(27) and hypotenuse(28), so use sin

sin=opp/hyp

sin(x)=27/28

x=arcsin(27/28)

x=74.64111442