Answer:
w₁ = 0 J
w₂ = -297 J
Explanation:
Step 1: Given data
Initial volume: 266 mL (0.266 L)
Final volume: 983 mL (0.983 L)
Step 2: Calculate the work done (in joules) by the gas if it expands against a vacuum
We will use the following expression.
w₁ = -P₁ × ΔV
Since the gas expands against a vacuum, P₁ = 0. Thus, w₁ = 0 J
Step 3: Calculate the work done (in joules) by the gas if it expands against a constant pressure of 4.09 atm
We will use the following expression.
w₂ = -P₂ × ΔV
w₂ = -4.09 atm × (0.983 L-0.266 L) = -2.93 atm.L
Then, we convert w₂ to Joule using the conversion factor 1 atm.L = 101.325 J.
-2.93 atm.L × 101.325 J/1 atm.L = -297 J
26. Which statements would be expected to be true for Organesson (Og)? Select all that apply.
A It is relatively unreactive.
B. It has a high electron affinity.
C. It has a full valence shell of electrons.
D. It has the largest atomic radius of the four new elements.
E. It has the lowest effective nuclear charge of the four new elements.
The central charge is another name for the effective nuclear charge that an electron experiences.. It has the lowest effective nuclear charge of the four new elements.
What is element ?An element is a type of atoms, including the pure material made entirely of that species, that have a specific number of protons in their nuclei.
Chemical elements, in contrast to chemical compounds, cannot be reduced by any chemical process into simpler molecules. The oxidation number of the atom can be used to calculate the strength of the nuclear charge.
The metals and non-metals are the other two basic categories into which the elements may be separated. Metals are frequently bright, malleable, and carry electricity.
All living and non-living things are made up of elements, which are fundamental building blocks. They serve as the universe's center. Elements make up every particle, no matter how little or large. Our body is composed of five main components are Calcium, Carbon, Hydrogen, Oxygen, and Nitrogen
Thus, option E is correct.
To learn more about element follow the link below;
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When the concentration of A in the reaction A ..... B was changed from 1.20 M to 0.60 M, the half-life increased from 2.0 min to 4.0 min at 25°C. Calculate the order of the reaction and the rate constant.
Answer:
2
[tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]
Explanation:
Half-life
[tex]{t_{1/2}}A=2\ \text{min}[/tex]
[tex]{t_{1/2}}B=4\ \text{min}[/tex]
Concentration
[tex]{[A]_0}_A=1.2\ \text{M}[/tex]
[tex]{[A]_0}_B=0.6\ \text{M}[/tex]
We have the relation
[tex]t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}[/tex]
So
[tex]\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}[/tex]
Comparing the exponents we get
[tex]1=n-1\\\Rightarrow n=2[/tex]
The order of the reaction is 2.
[tex]t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]
The rate constant is [tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]
What kind of ions does metal form?
* ionic bond
* covalent bond
* anions
* cations
* melting point
* boiling point
conductivity
* Polyatomic Ions
* Valence electron
* Metal
* Nonmetal
* Metaloids
Answer:
Option D: Cations
Explanation:
Do you need only one answer .
What would happen if the kinetic energy of the reactants was not enough to provide the needed activation energy
Answer:
The products would not be formed or the reaction could not be carried out.
Explanation:
Sometimes in these situations it is chosen to place a chemical compound that accelerates the reaction and increases the kinetic energy of the reactants, without altering their chemical composition, and this is called a catalyst, which can be anything from a protein to a macromolecule.
If earth is 1.50 x 10^8km from the sun what is the distance in Mm?
The distance of the earth to the sun in Mm = 1.5 x 10⁵
Further explanationGiven
The distance of the earth to the sun : 1.50 x 10⁸ km
Required
The distance in Mm
Solution
In converting units we must pay attention to the conversion factor.
the conversion factor :
1 kilometer(km) = 10⁻³ megameter(Mm)
So the distance conversion :
1.5 x 10⁸ x 10⁻³ = 1.5 x 10⁵ Mm
We made a bowl of jelly. What sort of change is this?
Answer:
Explanation:
It changes from a liquid to a solid. This change occurred due to the change in temperature. As the mixture cooled, the molecules condensed and the mixture formed a solid shape.Which formed the jelly.
Determine the number of valence electrons for the following: [kr] 5s2 4d6
A)5
B)2
C)4
D)7
E)8
F)6
Answer: B) 2 (as indicated by electron distribution shown), but taking into account the real properties of this element, 4,7,8 also occur (see below).
Explanation:
This is the electron complement/atomic number of ruthenium, which actually has the structure [Kr] 5s1 4d7
Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4
Where are valence electrons located in an atom?
Answer:
Valence electrons are the electrons in the outermost shell, or energy level, of an atom.
Answer: The outermost shell
Explanation:
Valence electrons are located in the outermost shell of the atom, or the energy level as it is also known.
An unknown element X has the following isotopes: ²⁵X (80.5% abundant) and ²⁷X (19.5% abundant). What is the average atomic mass in amu of X?
Answer:
25.39
Explanation:
Given parameters:
Abundance of X-25 = 80.5%
Abundance of X - 27 = 19.5%
Unknown:
Average atomic mass of X = ?
Solution:
The average atomic mass of X can be derived using the expression below:
Average atomic mass = (abundance x mass of X - 25) + (abundance x mass of X - 27)
Average atomic mass = (80.5% x 25) + (19.5% x 27) = 25.39
Explain how you know it must be oxygen. Where did the oxygen come from?
Answer:
Copper oxide is the only product, and it contains copper and oxygen.
One of the reactants is copper, so the other reactant must be oxygen.
The copper metal must have combined with something in the air.
Explanation:
classify the sentences based on the chemical reactions they describe.
Given the balanced equation 2C+ 3H2
Answer:
Explanation:
The answer is (4) 4.0 mol. This is a stoichiometry problem. You start with 2.0 mol of C2H6 and obtain the moles of C by multiplying 2.0 by the mole ratio, in this case 2. 2.0*2=4.0mol.
Calculate the mass of butane needed to produce 97.4 g of carbon dioxide. Express your answer to three significant figures and include the appropriate units. g
Answer:
32.1 g
Explanation:
Step 1: Write the balanced combustion reaction
C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O
Step 2: Calculate the moles corresponding to 97.4 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
97.4 g × 1 mol/44.01 g = 2.21 mol
Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide
The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol
Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀
The molar mass of C₄H₁₀ is 58.12 g/mol.
0.553 mol × 58.12 g/mol = 32.1 g
All composites are made up of two main components, a ________ and ___________.
Answer:
Matrix and Fibre.
Explanation:
The two main components composites are made up of are matrix and fibre. The matrix is the base material while the fiber is what reinforces the material.
After 3 half lifes go by, there are 26g of Sodium-24 left. The parent sample of Sodium-24 is
grams.
NUMBERS ONLY FOR THIS ANSWER
Blank 1:
Answer:
208 grams
Explanation:
Half life is the time it takes for a sample to reduce to half it's initial concentration.
In this question, 3 half lives go by. This is given as;
Let original mass be represented by x
First Half life;
Starting mass = X
Remaining mass = X/2
Second Half life;
Starting mass = X/2
Remaining mass = (X/2) / 2 = x/4
Third Half life;
Starting mass = X/4
Remaining mass = (X/4) / 2 = X/8
Since 26g was left, it means;
X/8 = 26
X = 26 * 8 = 208 grams
Environmental Science-JMajors-GEO-220029.001: Mastery Assess It_2 5. Most of the concentration of which gas results from the activity of producer organisms?
Answer: Oxygen
Explanation:
Producer organisms include plants and algae and refer to organisms that are able to produce their own food by synthesizing it from inorganic matter. This is what plants and algae are able to do through the process of photosynthesis.
During photosynthesis, these organisms produce food for themselves and in doing so produce oxygen as a by-product. This is what contributes mostly to the concentration of oxygen in the atmosphere.
Question 3
Which organism in a food web does not get its energy from other organisms?
A. decomposer
O
B. producer
O
C. primary consumer
D. secondary consumer
O
Hi there!
[tex]\large\boxed{\text{B. Producer}}[/tex]
The only organisms in a food web that do not get energy from other organisms are producers. These are autotrophs (ex: plants or phytoplankton) that use photosynthesis to produce energy. This means that these organisms only intake water and sunlight rather than nutrients from other organisms (consumers).
Beth heats a pot of water to cook pasta.
What may happen as a result of adding heat?
Answer: i’m taking a test w this question rn and i think the best answer is D. When the water begins to boil, some of the water molecules will gain enough energy to change into a gas. i could def be wrong tho
What is responsible for the unusual ecosystem of the highlands?
Answer:
volcanoes and volcanic activity
Explanation:
I had the same Question and I got that.
Answer: Volcanoes and Volcanic Activity :)
Explanation: I got the same question :D
Suppose a molecule with six electron groups is confined to two dimensions and has a hexagonal planar electron geometry. A molecule with six electron groups arranged in a hexagonal planar geometry. The top and bottom groups are labeled 1 and 4, respectively. The two groups next to 1 are labeled 2 and the two groups next to 4 are labeled 3. If two of the six groups are lone pairs, where would they located?
Answer:
Above and below the plane of a square
Explanation:
The number of electron groups often determine the shape of a molecule. When we have a coordination number of six, one of the possible arrangement of groups is the hexagonal planar geometry. In this arrangement, six electron groups are arranged in the same plane.
If two among the groups are replaced by lone pairs, the substituents will arrange themselves at the corners of a square while the lone pairs will be found above and below the plane of the square. This is the square planar geometry.
The two lone pairs will be located at the top and at the bottom of the plane.
The VSEPR theory is a model that helps to predict the shape of a molecule based on the repulsions associated with the electron groups on the central atom.
Given that a hexagonal planar electron geometry possibly has 6 electron groups. The description of how the electron groups are arranged can be seen in the first image below.
If two of the six groups are lone pairs, we know that lone pairs repel each other. As such, in this arrangement, the lone pairs will occpy the opposite direction which is the top and the bottom of the plane in order to have minimum repulsion as possible.
Learn more about electronic geometry here:
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How much concentrated solution would you take to prepare 1.30 LL of 0.100 MM HNO3HNO3 by mixing with water
Answer:
8.2mL of the concentrated solution must be taken diluting to 1.30L with water
Explanation:
The concentrated HNO₃ comes in a presentation of 70% = 15.8M
As the concentrated solution is of 15.8M and we want to obtain a 0.100M, the dilution must be of:
15.8M / 0.100M = 158 times must be the concentrated solution diluted
As the total volume we want to prepare is 1.30L, the volume of the concentrated solution must be:
1.30L / 158 = 8.2x10⁻³L =
8.2mL of the concentrated solution must be taken diluting to 1.30L with waterexplain why we do not see this side product. write the reaction that removes side product as its formed
Answer:
See explanation
Explanation:
Looking at the structure of the starting material, we can see that the carbocation intermediate is a tertiary carbocation.
The tertary carbocation is very stable. Indeed, it is the most stable carbocation intermediate. As such, none of this other product is obtained due to this intermediate.
The mechanism of this reaction is shown in the image attached to this answer.
Sometimes atoms form molecules by sharing two pairs of valence electrons. When this occurs, the atoms are said to be joined by...
Answer:
A double covalent bond
Explanation:
A double covalent bond is a situation where we have two pairs of electrons shared together between the atoms instead of just one pair. Oxygen gas is an example of a simple molecule that contains double bonds.
In other words, it is a type of chemical bond that has 2 electron pairs shared between two atoms.
Critical thinking problem: The iron in hemoglobin in our red blood cells is used to bind and carry dioxygen throughout the body. Iron is one of the atoms that can form hybrid orbitals using its d-shell electrons, which allows for a greater number of sigma bonds than just four. When iron is only bound to protein, it forms five sigma bonds with one lone pair. The iron atom is pulled down below the central square plane due to one of the bonds with the hemoglobin protein. The thick lines indicate bonds pointing out of the screen, while dashed lines indicate bonds pointing into the screen, so as to suggest 3-D structure.
When iron binds to dioxygen, it now has six sigma bonds. The geometry changes, even though the hybridization orbitals do not change. The dashed lines are still present, as seen from the top-down view, but the thick lines hide them in the side-on view.
Why would the molecular geometry for iron change in this case? Would this have anything to do with the ability of hemoglobin to bind oxygen tightly?
Answer:
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Contents Home Bookshelves Physical & Theoretical Chemistry Supplemental Modules (Physical and Theoretical Chemistry) Electronic Structure of Atoms and Molecules Expand/collapse global location
Predicting the Hybridization of Simple Molecules
Last updatedAug 16, 2020
Predicting the Bond-Order of Oxides based Acid Radicals
Prediction of Aromatic, Anti Aromatic and Non Aromatic Character of Heterocyclic Compounds along with their Omission Behavior- Innovative Mnemonics
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Prof. Linus Pauling (1931) first developed the Hybridization state theory in order to explain the structure of molecules such as methane (CH4).1This concept was developed for simple chemical systems but this one applied more widely later on and from today’s point of view it is considered an operative empirical for excusing the structures of organic and inorganic compounds along with their related problems. An innovative method proposed for the determination of hybridization state on time economic ground 2,3,4.
Prediction of sp, sp2, sp3 Hybridization state
We Know, hybridization is nothing but the mixing of orbital’s in different ratio to form some newly synthesized orbitals called hybrid orbitals. The mixing pattern is as follows:
s + p (1:1) - sp hybrid orbital; s + p (1:2) - sp2 hybrid orbital ; s + p (1:3) - sp3 hybrid orbital
Formula used for the determination of sp, sp2 and sp3 hybridization state:
Power on the Hybridization state of the central atom = (Total no of σ bonds around each central atom -1)
All single (-) bonds are σ bond, in double bond (=) there is one σ and 1π, in triple bond (≡) there is one σ and 2π. In addition to these each lone pair (LP) and Co-ordinate bond can be treated as one σ bond subsequently.
Eg.:
a. In NH3: central atom N is surrounded by three N-H single bonds i.e. three sigma (σ) bonds and one lone pair (LP) i.e. one additional σ bond. So, in NH3 there is a total of four σ bonds [3 bond pairs (BPs) + 1 lone pair (LP)] around central atom N. Therefore, in this case power of the hybridization state of N = 4-1 = 3 i.e. hybridization state = sp3.
b. In H2O: central atom O is surrounded by two O-H single bonds i.e. two sigma (σ) bonds and two lone pairs i.e. two additional σ bonds. So, altogether in H2O there are four σ bonds (2 bond pairs + 2 lone pairs) around central atom O, So, in this case power of the hybridization state of O = 4-1 =3 i.e. hybridization state of O in H2O = sp3.
c. In H3BO3:- B has 3σ bonds (3BPs but no LPs) and oxygen has 4σ bonds (2BPs & 2LPs) so, in this case power of the hybridization state of B = 3-1 = 2 i.e. B is sp2 hybridized in H3BO3. On the other hand, power of the hybridization state of O = 4-1= 3 i.e. hybridization state of O in H3BO3 is sp3.
d. In I-Cl: I and Cl both have 4σ bonds and 3LPs, so, in this case power of the hybridization state of both I and Cl = 4 - 1 = 3 i.e. hybridization state of I and Cl both are sp3.
e. In CH2=CH2: each carbon is attached with 2 C-H single bonds (2 σ bonds) and one C=C bond (1σ bond), so, altogether there are 3 sigma bonds. So, in this case, power of the hybridization state of both C = 3-1 = 2 i.e. hybridization state of both C’s are sp2.
Prediction of sp3d, sp3d2, and sp3d3 Hybridization States
PLEASE HELPPPOOOOSPO
If an element has three isotopes with known masses, what other information
is needed to find the average atomic mass of the element?
A. The number of neutrons in each isotope
B. The average mass of the isotopes
C. The atomic number of each isotope
D. The abundance percentage of each isotope
Answer: D
Explanation: Hope this helps!
Which of the following combinations would form an atom with no charge (neutral)
A 3 protons, 3 neutrons, 4 electrons
B. 5 protons, 5 neutrons, 4 electrons
C. 4 protons, 3 neutrons, 4 electrons
D. 5 protons, 6 neutrons, 6 electrons
Answer:
C
Explanation:
How can u change cm to dm
Use your periodic table to complete the table below. The first one has been done for you.
Element
Atomic #
Mass
Protons
Neutrons
Electrons
Symbol
Iodine
53
127
53
74
54
I1-
35
17
Cl1-
Hydrogen
1
1
0
35
45
36
5
11
B3+
Oxygen
16
8
10
Element
Atomic #
Mass
Protons
Neutrons
Electrons
Symbol
Nitrogen
7
7
10
Aluminum
27
10
56
26
24
29
35
Cu1+
64
29
27
Match each of the positive ions listed with the total number of electrons that ion contains. Use your periodic table. The same answer may be used more than once.
A) 2 B) 10 C) 21 D) 23 E) 24
F) 25 G) 36 H) 48 I) 76 J) 81
____ Al+3 ____ Fe+3 ____ Mg+2 ____ Sn+2
____ Li+1 ____ Cr+3 ____ Rb+1 ____ Pt+2
Answer: my epic on fortnite is
Explanation:Bookboy24 ok add me and arena or creative
Name some acidic and alkaline substances that you use at home
Answer: write anything given below in the diagram except for the neutral substances
Explanation:
Answer:
Alkaline
1 drain cleaner
2 oven cleaner
3 baking soda
4 drain unblocker
Acid
1 drain cleaner
2 bowl cleaner
3 house bleach
4 diluted soap
Suppose that we continue to work with the gas from the previous problem ( 2 moles of gas occupy 126 L at 346 K, and that the van der Waals constants are a = 6.20 atmL^2/mol^2 and b = 0.0852 L/mol), but consider the molecules to be mathematical points. Calculate the pressure and compare it to the values from the previous problem.
Answer:
0.448 atm
Explanation:
So, we have;
n = 2 moles
V = 126 L
T = 346 K
a = 6.20 atmL^2/mol^2
b = 0.0852 L/mol
R = 0.082 atmLK-1mol-1
P = nRT/V -nb - an^2/V^2
Substituting values;
P=2 * 0.082 * 346/126 -(2 * 0.0852) - 6.20 * 2^2/126^2
P=56.744/125.8296 -24.8/15876
P= 0.45 - 0.001562
P= 0.448 atm
