Explanation:
Given:
v₀ = 15.68 m/s
a = -9.8 m/s²
t = 0.4n s, n = 0, 1, 2, etc.
Find: Δy and v
To find displacement, use the equation:
Δy = v₀ t + ½ at²
To find velocity, use the equation:
v = at + v₀
[tex]\left\begin{array}{ccc}t&y&v\\0&0&15.68\\0.4&5.49&11.76\\0.8&9.41&7.84\\1.2&11.76&3.92\\1.6&12.54&0\\2.0&11.76&-3.92\\2.4&9.41&-7.84\\2.8&5.49&-11.76\\3.2&0&-15.68\end{array}\right[/tex]
The ball lands after 3.2 seconds.
Answer:
calculated velocities:
(t,v(t))
(0.4,11.756)
(0.8,7.832)
(1.2,3.908)
(1.6,-0.016)
calculated displacements:
[tex](t,\Delta x)[/tex]
(0.4, 5.487)
(0.8,9.4048)
(1.2, 11.7528)
(1.6, 12.5312)
the ball spends 3.2 seconds in the air
Explanation:
Assuming the ball is launched on earth with standard gravity and that the effects of drag is neglected.
assume that 'up' is positive direciton since that is direction of travel
'down' is negative direction
formula for velocity is [tex]v(t)=v_0+at[/tex]
where [tex]v(t)[/tex] is the velocity at time [tex]t[/tex]
[tex]v_0[/tex] is the initial velocity at time [tex]t=0[/tex]
[tex]a[/tex] is the acceleration in the direction of the velocity
velocity is in m/s and accelration is in m/s^2 and t is in seconds
for displacement: [tex]\Delta x=v_0 t+\frac{1}{2}at^2[/tex]
Known stuffs:
in our case, we know we are on earth so, [tex]a=-9.81[/tex]m/s^2. the negative sign indicates that the direction is oposite the velocity since the ball travels up but gravity pulls down
the initial velocity is given as [tex]v_0=15.68[/tex]m/s
therefore, our equation for velocity is
[tex]v(x)=15.68-9.81t[/tex]
now we just need to plot it every 0.4 seconds
this is easy subsituteion. here's the first:
[tex]v(0.4)=15.68-9.81(0.4)=11.756[/tex]m/s
if we keep plotting this, we get the following table
(t,v(t))
(0.4,11.756)
(0.8,7.832)
(1.2,3.908)
(1.6,-0.016) the velocity is negative meaning that the ball is now going 'down' and therefor the ball has just passed the peak of it's upward travel
so since it took about 1.6 seconds to get here, it will spend about twice this time in the air or about 3.2 seconds
to get an exact answer, solve for the time when velocity is 0, ie when the ball has reached its peak and stopped moving
set [tex]v(t)=0[/tex] and solve for t
[tex]0=15.68-9.81t\rightarrow 15.68=9.81t\rightarrow t=1.598s[/tex]
so it takes 1.598 seconds to get to peak, therefore it spends twice this time in the air or 3.197 seconds in the air. it's close enough to 3.2 seconds
the ball spends 3.2 seconds in the air
displacement:
[tex]\Delta x=v_0t+\frac{1}{2}at^2[/tex]
[tex]\Delta x=15.68t+\frac{1}{2}(-9.81)t^2[/tex]
some values are
[tex](t,\Delta x)[/tex]
(0.4, 5.487)
(0.8,9.4048)
(1.2, 11.7528)
(1.6, 12.5312)
What is a population?
Group of answer choices
A. a group of individuals of the same species living in the same area
B. a group of different species living in the same area
C. a group of individuals of the same species living in separated areas a group of different species living in separated areas
Answer:
A
Explanation:
Physics 1102 Experiment 5 Pre Lab Name_________________________________ Instructor name _________________________ You must show and explain all work in a neat and organized way to receive credit. Please show each step for calculations. YOU MUST TURN IN THIS SHEET. 1. (a) What does electrically neutral mean
Answer:
Explanation:
An atom is said to be electrically neutral, if the said atom contains equal or the same numbers of protons and electrons.
Worthy of note is that most bodies are normally close to being electrically neutral. This is because of the number of electrons on the body being equal to the number of protons on the same body. Charging a body means one would have to transfer electric charge to the body, or from the body. As a result, the number of electrons in the body will no longer be equal to the number of protons on the body.
Which principle(s) of the cell
theory shows that all organisms
are somehow similar?
Explanation:
The unified cell theory states that: all living things are composed of one or more cells; the cell is the basic unit of life; and new cells arise from existing cells.
hope it helps
plz mark as brainliest
What did Rutherford’s model of the atom include that Thomson’s model did not have?
a nucleus
energy levels
electron clouds
smaller particles
Answer:
Yes the answer is A.) A Nucleus
Explanation:
I took the test
Rutherford’s model of the atom included a nucleus that Thomson’s model did not have, therefore the correct option is A
What are atomic models?There are some models that are used to explain the arrangements of subatomic particles inside the atom based on the atomic theory of atom are known as the atomic models.
There are many types of atomic models proposed in past based on their individual assumptions and the experimentations
There are mainly five most widely accepted atomic models
John Dalton's atomic model which based on the assumption that all the entities of the universe are made up of the fundamental particle that is an atom.
J.J. Thomson's model: Plum Pudding model explains the arrangement of subatomic particles by taking the example of plum pudding in which positive charge is distributed uniformly throughout and the negative charge particles are sprinkled on it in a random fashion.
Rutherford's model explained the existence of a nucleus inside the atom by using the alpha particle bombardment experiment on a thin sheet of gold.
Niels Bohr's model explained the revolving nature of the electrons in the different shells around the nucleus of the atom.
Erwin Schrodinger's model explains the arrangement of the subatomic particles as the electron Cloud Model also known as the Quantum Model.
Rutherford’s model of the atom included a nucleus that Thomson’s model did not have, therefore the correct option is A
Learn more about the atomic models here
https://brainly.com/question/9145431
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A train is travelling east along a straight run of track at 54.0 km/hr. Inside, two siblings 1.90 m apart are playing catch directly across the aisle. The kid wearing a Catherine Wheel T-shirt throws the ball horizontally north. The ball crosses the train and is caught 1.05 s later by her little brother. (Ignore any effects of gravity or friction.)
a) Find the magnitude of the ball's velocity from the little brother's point of view.
b) What is the magnitude of the velocity of the ball as seen by someone standing still outside the train?
c) What is the angle between the direction of the ball and the direction of the train as measured by someone standing still outside the train?
Answer:
A.) 1.81 m/s
B.) 16.07 m/s
C.) 6.88 degree.
Explanation:
Given that Inside, two siblings 1.90 m apart are playing catch directly across the aisle. The kid wearing a Catherine Wheel T-shirt throws the ball horizontally north. The ball crosses the train and is caught 1.05 s later by her little brother.
The velocity of the ball will be
Velocity = displacement/ time
Where displacement = 1.90 m
Time = 1.05 s
Velocity = 1.9 / 1.05
Velocity = 1.8095
Velocity = 1.81 m/s
A.) From the little brother point of view, the magnitude of ball's velocity will be 1.81 m/s
B.) The magnitude of the velocity of the ball as seen by someone standing still outside the train will be achieved by first converting km/h to m/s
(54 × 1000) / 3600 = 15 m/s
Then, use pythagorean theorem to find the velocity
V = sqrt ( 15^2 + 1.81^2)
V = sqrt ( 225 + 3.2761)
V = sqrt ( 258.2761)
V = 16.07 m/s
C.) The angle will be
Tan Ø = 1.81 / 15
Tan Ø = 0.1206666
Ø = tan^-1(0. 1206666)
Ø = 6.88 degree.
For the system of Problem3.18, determine the amount of energy transfer by heat, in kJ per kg of refrigerant.[Problem3.18A closed, rigid tank contains a two‐phase liquid–vapor mixture of Refrigerant 22 initially at−20°Cwith a quality of 50.36%. Energy transfer by heat into the tank occurs until the refrigerant is at a final pressure of 6 bar. Determine the final temperature, in°C. If the final state is in the superheated vapor region, at what temperature, in°C, does the tank contain only saturated vapor?]
Answer:
35.625° C
Explanation:
See attachment
a) Final temperature is 35.625° C
b) 0°
