35.15 m maximum height will a 301.5 m drive each if it is launched at an angle of 25.0" to the ground.
What exactly is meant by velocity?The accurate measurement of an object's position and speed is its velocity. It is the distance that an item travels in one unit of time. The displacement of the item in one unit of time is the concept of velocity.
Briefing:Using the formula for the horizontal range, we will first determine the ball's projectile motion's launch velocity:
R = u²sin 2θ/g
where,
R = horizontal range = 301.5 m
u = launch speed = ?
θ = launch angle = 25°
Gravity's acceleration, or g, is 9.81 m/s2²
Therefore,
301.5 m = u²sin 50 /9.81 m/s²
u = √(301.5 m)(9.81m/s²) / sin 50
u = 62.14 m/s
Now, using the following formula, we will determine the projectile motion's maximum height (H):
H = u²sin²θ
H = (62.14m/s²) sin²(25⁰) / 2(9.81 m/s²)
H = 35.15 m
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If the average distance from Venus to the Sun is given to be 0.7AU, what is its period?
If the average distance from Venus to the Sun is given to be 0.7AU, its time period is 208.49 days.
Kepler's laws of planetary motion :
According to this law, the semi-major axes of the planets' orbits are directly proportional to the squares of the planets' orbital periods.
radius of the venus = 0.7AU
radius of the earth = 1 AU
orbital period of the earth = 365 days
According to the Kepler's 3rd law of planetary motion :
T² ∝ R³
T² = k R³
k = T²/ R³
[tex]k = \frac{T^2_v}{R^3_v} = \frac{T^2_e}{R^3_e}[/tex]
T² /(0.7)³ = (365)² /(1)³
T = [tex](0.7/1)^{\frac{3}{2}}[/tex] X 365
T = 208.49 days
If the average distance from Venus to the Sun is given to be 0.7AU, its time period is 208.49 days.
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7. Using the idea of Impulse, explain why a field goal kicker should 'kick through the ball', meaning extend their foot
as high up as possible at the end of the kick.
Answer:
Impulse is the amount of force put on an object in a certain amount of time. Therefore when kicking a ball and "kicking through it" it extends the period of time this force is applied in turn increasing its impulse. Impulse is equal to change in momentum. momentum is equal to mass times velocity and since mass of the ball doesn't change therefore the velocity is increased and performance increased.
A dog sits 2.2 m from the center of a merry- go-round.
a) If the dog undergoes a 1.6 m/s2 cen- tripetal acceleration, what is the dog’s linear speed?
Answer in units of m/s.
second part
What is the angular speed of the merry-go- round?
Answer in units of rad/s.
The dog’s linear speed will be 1.88 m/s
The angular speed of the merry-go- round will be 0.85 rad/sec
centripetal acceleration = [tex]v^{2} / r[/tex]
given
r = 2.2 m
linear speed = ?
centripetal acceleration = 1.6 [tex]m/s^{2}[/tex]
centripetal acceleration C(a) = [tex]v^{2} / r[/tex]
linear speed = [tex]\sqrt{C(a) * r}[/tex]
= [tex]\sqrt{1.6 * 2.2 }[/tex] = [tex]\sqrt{3.52}[/tex] = 1.88 m/s
The dog’s linear speed will be 1.88 m/s
angular speed = linear speed / radius
= 1.88 / 2.2 = 0.85 rad/sec
The angular speed of the merry-go- round will be 0.85 rad/sec
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Two insects A and B fly in space with a uniform velocity VA= i+4j+3k and VB =4i+2j-4k in m/s. With respect to a stationary observer at the origin. Show the insect fly at right angles to each other and determine their distance apart after 50
Distance travelled by insects A and B is respectively 50√26 unit and 300 unit.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given parameters:
Uniform velocity of insect A: [tex]\bold{v_A}[/tex] = i+4j+3k unit.
Uniform velocity of insect B: [tex]\bold{v_B}[/tex] = 4i+2j-4k unit.
Now dot product of two velocity vector is:
[tex]\bold{v_A}[/tex]·[tex]\bold{v_B}[/tex] = 50 (i+4j+3k)·50( 4i+2j-4k).
= 2500(4 + 4×2 + 3×(-4))
= 0.
Hence, the velocity vectors of two insects are perpendicular to each other. So, the insect fly at right angles to each other.
After time t = 50 unit, Position of insect A: [tex]\bold{X_A}[/tex] = time* velocity
= 50 (i+4j+3k) unit.
After time t = 50 unit, Position of insect B: [tex]\bold{X_B}[/tex] = time* velocity
= 50( 4i+2j-4k).
So, After time t = 50 unit, insect A travels a distance = 50 ×√(1²+4²+3²) = 50√26 unit.
After time t = 50 unit, insect B travels a distance = 50 ×√(4²+2²+(-4)²) = 300 unit.
Hence, distance travelled by insects A and B is respectively 50√26 unit and 300 unit.
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You stand in front of a mirror. How tall does the mirror have to be so that you can see yourself entirely?
a. same as your height
b. less than your full height but more than half your height
c. half your height
d. less than half your height
e. any size will do
If you stand in front of a flat mirror. The one-half of your height will be seen yourself entirely. Option C is the correct answer.
What is height?A person or anything can be measured from head to toe or from the bottom up by their height. In other words, a person's height indicates how tall they are. Distance units, such as meters, centimeters, millimeters, etc., are used to measure height. We may assess how much taller we get as we age. We frequently contrast the average heights of men and women in various nations.Take a look at your room's four walls. The height of a wall is measured from the ground to the ceiling. Remember how your class is organized in the school assembly, with the tiniest child in the front and the tallest youngster at the back.
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An experimenter would like to construct a 99% confidence interval with a width at most 0. 5 for the average resistance of a segment of copper cable of a certain length. If the experimenter knows that the standard deviation of such resistances is 1. 55. How big a sample should the experimenter take from the population? what happens if the standard deviation and the width of the confidence interval are both doubled?.
Sample should be 256 , which the experimenter can take from the population . If the standard deviation and the width of the confidence interval are both doubled , the size will be same .
What is resistance ?
Resistance is the resistance that a substance offers to the flow of electric current. Represented by a capital R. The standard unit of resistance is the ohm, sometimes written as a word or represented by the Greek letter omega. If a current of 1 ampere flows through a component with a potential difference (voltage) of 1 volt, the resistance of that component is 1 ohm. The electrical resistance per unit length, area, or volume of matter is known as resistance. Resistance values are often given in ohms per kilometer of copper and aluminum wire.
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A decibel meter reads a sound intensity of 80 dB when you stand 2 m from a loudspeaker. What will the meter read (in dB) if you stand 40 m away?
Answer:
Explanation:
L₁ =80 dB
S₁ = 2 m
S₂ = 40 m
__________
L₂ - ?
The intensity of the site is nearby:
ΔL = 10·lg(S₂/S₁)²
ΔL = 10·lg(40/2)² = 10·2·lg(20) = 20·1.3 = 26 dB
L₂ = L₁ - ΔL = 80 - 26 = 54 dB
using references websites or maps and a different color line, draw the major crystal plates of the earth on your world map. label the names of the plates neatly
Answer:
The Earth's major plates are the African plate, the Antarctic plate, the Eurasian plate, the North American plate, the South American plate, and the Pacific plate.
Explanation:
a 4500 kilogram truck travels in a straight line at 10 ms what is its momentum
40,000 kg m/s will be the momentum if the truck at a truck mass of 4500kg and velocity of 10 m/s.
Given mass of a truck = 4000 kg
truck mass = 4 grams
velocity = 10 m/s
The formula of momentum will be:
p = mv
where, p = momentum
m = truck mass
v = velocity
substituting the values, we get:
momentum = 4000 × 10
momentum = 40000 kg m/s
Thus the momentum of the truck is 40,000 kg m/s
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Speculate on the different social dynamics behind lower - class drug use and middle -class drug use. For example , are there likely to be differences in motivation for use ? In the way individuals are introduced to drugs ? In the consequences for drug use ?
Social dynamics behind lower -class drug use is homelessness, criminal behaviors, association with gangs and unemployment whereas social dynamics behind middle -class drug use is peer relationships, extramarital relations and distortion of interpersonal family relationships.
What are the social dynamics behind drug use?Social factors that increase the risk for adolescent drug use can include popularity, bullying, peer relationships, and association with gangs.
Other possible factors can be social and familial influences. This can result in financial hardships due to job loss. It may also lead to certain behavior that can put family at risk and can also cause domestic violence within relationships.
Other social problems linked with SUDs can be housing instability, homelessness and unemployment.
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Edward swings his tennis racket to return a serve. His 10 kg racket swings forward with a speed of 8 m/s and after colliding with the tennis ball it is
slowed to 4 m/s. The 1 kg tennis ball was served toward Edward with a speed of 20 m/s. How fast was the tennis ball moving after the collision with
the racket?
The final velocity of the tennis ball after the collision is 20 m/s in opposite direction.
What is the final velocity of the tennis ball?
The final velocity of the tennis ball is determined by applying the principle of conservation of linear momentum as shown below.
Mathematically, the formula is given as;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the racket = 10 kgu₁ is the initial velocity of the racket = 8 m/sm₂ is the mass of the tennis ball = 1 kgu₂ is the initial velocity of the tennis = 20 m/sv₁ is the final velocity of the racket = 4 m/sv₂ is the final velocity of the tennis ball = ?(10 x 8) + (-20)(1) = 10(4) + (1)v₂
80 - 20 = 40 + v₂
80 - 20 - 40 = v₂
20 m/s = v₂
Thus, the final velocity of the tennis ball is in opposite direction.
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Calculate the speed at the edge of a disc of radius 8.5 cm that rotates at the rate of 2.5 rev/s.
Answer in units of m/s.
The speed at the edge of a disc of radius 8.5 cm that rotates at the rate of 2.5 rev/s will be 21.25 m/s
Angular velocity is the rate of change of angular displacement
Mathematically it can also be calculated as linear speed divided by radius
linear speed = omega * radius
= 2.5 * 8.5
= 21.25 m/s
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The speed of light in vacuum is 3*10^8m/s what it's speed in glass of refractive index1.5
Answer:
Speed of light in glass V = 2·10⁸ m/s
Explanation:
Given:
c = 3·10⁸ m/s - The speed of light in vacuum
n = 1.5 - Refractive index of glass
__________
V - ?
Speed of light in glass:
V = c / n
V = 3·10⁸ / 1.5 = 2·10⁸ m/s
name two different objects you could use to light a room if you have a power cut. for each object describe the energy transfer and changes to energy stores that occur when it lights up the room
Answer:
candle and hand torch
Explanation:
we can find a light energy and heat energy from the candle but only light energy for hand torch
a) You are trying to lift a woolly mammoth (5000 kg). You put a long piece of metal under the mammoth and place a large rock 2 m from the mammoth to serve as a fulcrum. You can supply about 2000 N of force. How far away from the fulcrum will you have to apply your force?
b) With the answer in part a), what is the practical issue with this answer (think about how a long thin rod behaves mechanically)? What might you do to be able to lift the mammoth, if you have friends to help? Be specific.
a. The force should be applied 5 m from the fulcrum
b. The issue is that deformation of the rod will occur.
In order to avoid this deformation, with the help of friends, the distance from the can be reduced and more force applied.
What is the principle of moments?The principle of moments states that for a system in equilibrium, the sum of the clockwise moments about a point of rotation is equal to the sum of the anticlockwise moments about that point.
Mathematically;
clockwise moments = anticlockwise momentsThe moment of a force is the product of the force and the perpendicular distance from its point of action.
Moment = force * perpendicular distanceFrom the data provided:
Let the woolly mammoth move in a clockwise direction and the applied force in an anticlockwise direction.
Let d be the perpendicular distance of the applied force from the fulcrum
5000 * 2 m = 2000 * d
d = 5 m
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Which of these has 28 protons and 26 electrons?
O Fe
O Fe2+
Ο Ni
O Ni2+
Answer:
here, if you have an iron which has 28 protons and 26 electrons, and we have to find the charge on the iron, the element and the symbol of the iron. So For 28 protons charge is 28 e. And for 26 electrons, charge will be -26 E. So total charges 28 E minus 26 E. Equal to two E. On I N S, plus two. No, we have to find the element. So atomic number is equal to Number of protons, which is 28, and this is atomic number four nickels. So the element is nickel and we have to find the symbol of iron. So the iron has to positive child. So the symbol will be and I took place So this completes the solution. Thank you.
Explanation:
If a 2.5 m long pendulum has a bob of 75 g. Calculate its Period, Frequency, and velocity at
equilibrium after its bob is pulled 10 cm above equlibrium and then released.
Time period and frequency of the pendulum are respectively 3.17 second and 0.315 second⁻¹. The velocity of its bob at the equilibrium is
140 cm/s.
Given parameters:
Length of the pendulum, L = 2.5 m = 250 cm.
Mass of the bob, m = 75 g
And, bob is pulled 10 cm above equilibrium and then released.
acceleration due to gravity, g = 9.8 m/s².
Hence, time period of the pendulum is, T = 2π√(l/g)
= 2π√( 250/980) second.
= 3.17 second.
Frequency of the pendulum , n = 1/T = 1/3.17 second⁻¹ = 0.315 second⁻¹.
Let v be the velocity of the bob at equilibrium,
Kinetic energy at equilibrium = potential energy at the highest point
⇒ 1/2 × 75 × v² = 75 × 980 × 10
⇒ v = √(2×980×10)
= 140 cm/s.
So, the velocity at equilibrium after its bob is pulled 10 cm above equilibrium and then released is 140 cm/s.
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____is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid____
to a temperature below___F.
Impact ice is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid water to a temperature below 32°F.
What is meant by impact ice ?Impact ice, a kind of induction icing, may form wherever that the temperature is close to or below zero degrees Celsius. Even on a fuel-injected engine, impact ice can clog the air filter and prevent the engine from getting the necessary air for combustion. As instructed by your POH/AFM, turn on alternative air or carburetor heat if you detect impact ice.Carburetor icing (ice that forms in the carburetor) happens when the venturi's decline in air pressure causes the moisture-filled air to cool quickly or as a result of gasoline evaporation.The ensuing ice buildup in the intake tube of the carburetor can significantly lower engine performance. In extreme circumstances, the intake flow might be so low that the engine can stall.Learn more about Liquid water refer to :
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If relativistic effects are to be less than 6%, then must be less than 1.06. At what relative velocity is = 1.06?
If relativistic effects are to be less than 6%, then must be less than 1.06. Hence, at a relative velocity (v) of 0.33c, gamma is = 1.06. This problem is solved using the Lorentz Factor.
What is the Lorentz Factor?The Lorentz factor is a correction parameter used to calculate relativity. Without this component, relativistic motion calculations simply fail, and we can obtain speeds that surpass the speed of light, which cannot be.
The calculation to the above solution is given as follows
Given:
γ = 1/ √1-(v²/c²)
It is logical to simplify by squaring both sides
⇒ γ² = 1/ 1-(v²/c²)
Taking the reciprocal of both sides, we have
1-(v²/c²) = 1/γ²
Transposing we have
v²/c² = 1 - 1/γ²
Since we are looking at v, lets us isolate it:
v = √[1 - (1/γ²) · c]
Inserting the Lorentz factor which is
γ = 1.06, we have
v = √[1 - (1/1.06²) · c]
Hence,
v = 0.33c
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Full Question:
If relativistic effects are to be less than 6% then gamma must be less than 1.06. At what relative velocity is gamma = 1.06?
a 2kg box with some initial velocity slides up a frictionless ramp which is at a 15-degree angle to the ground until the box comes to rest 1-sec later. Find the work done on the box.
Answer:
Approximately [tex](-6)\; {\rm J}[/tex], assuming that [tex]g = 9.81\; {\rm m \cdot s^{-2}}[/tex].
Explanation:
Let [tex]m[/tex] denote the mass of this box.
Decompose the weight [tex]m\, g[/tex] of the box into two components: perpendicular to the slope [tex](-m\, g)\, \cos(15^{\circ})[/tex] and parallel to the slope [tex](-m\, g)\, \sin(15^{\circ})[/tex]. The perpendicular component is balanced with the normal force of the slope on the box. In contrast, since there is no friction between the box and the slope, the parallel component isn't balanced and will be equal to the net force on the box:
[tex]F_{\text{net}} = (-m\, g) \sin(15^{\circ}})[/tex].
Note that [tex]F_{\text{net}}[/tex] is constant during this [tex]t = 1\; {\rm s}[/tex].
The acceleration [tex]a[/tex] of this box will be:
[tex]\begin{aligned}a &= \frac{F_{\text{net}}}{m}\\ &= \frac{(-m\, g) \sin(15^{\circ})}{m} \\ &= (-g)\, \sin(15^{\circ})\end{aligned}[/tex].
Let [tex]u[/tex] denote the initial velocity of this box. Since after the [tex]t = 1\; {\rm s}[/tex] of acceleration at [tex]a = (-g)\, \sin(15^{\circ}})[/tex] the velocity of the box is [tex]v = 0\; {\rm m\cdot s^{-1}}[/tex], the initial velocity of this box will be:
[tex]\begin{aligned} u &= v - a\, t \\ &= 0 - (-g)\, \sin(15^{\circ})\, t \\ &= g\, t\, \sin(15^{\circ}})\end{aligned}[/tex].
Initial kinetic energy of this box would be:
[tex]\begin{aligned} (\text{KE}) &= \frac{1}{2}\, m\, u^{2} \\ &= \frac{1}{2}\, m\, (g\, t\, \sin(15)^{\circ}})^{2}\end{aligned}[/tex].
The kinetic energy of this box is [tex]0[/tex] when the box is at rest. The change in kinetic energy was [tex](1/2)\, m\, (g\, t\, \sin(16^{\circ}))^{2}[/tex]. That energy change should be the opposite of the work the external force weight did on this box.
Substitute in [tex]m = 2\; {\rm kg}[/tex], [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], [tex]t = 1\; {\rm m\cdot s^{-1}}[/tex] to find the change in kinetic energy and hence the work that the net force did on the box:
[tex]\begin{aligned} (\text{Work Done}) &= -(\text{Kinetic energy change}) \\ &= -\frac{1}{2}\, m\, (g\, t\, \sin(15)^{\circ}})^{2} \\ &= -\frac{1}{2}\times 2\; {\rm kg} \times (9.81\; {\rm m\cdot s^{-2}} \times 1\; {\rm s} \times \sin(15^{\circ})^{\circ} \\ &\approx (-6)\; {\rm J}\end{aligned}[/tex].
What two forces keep stars in equilibrium?
A. cosmic microwave background radiation
B. self gravity
C. thermal pressure
D. dark energy
According to the given information self gravity two forces keep stars in equilibrium.
The correct option is B.
What you mean by forces?The push or pull on a mass-containing item alters its velocity. An external force is an agent that has the power to alter the rest or flowing condition of a body. It has a direction and a magnitude. Like we discovered in a previous session, forces are significant because they create motion changes.
What is effect of force?An object can change its dimensions or shape, begin moving, stop moving, accelerate, or decelerate as a consequence of the a force acting on it. When two things contact, they exert pressures on each other that are identical in size but directed in the opposite direction.
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Question 2:
mark each, 3 marks total)
A box is at rest,the reading on the scale is 250 newtons. Assum that the
acceleration due to gravity remains constant over the entire distance the
elevator can move.
A) When the elevator is moving upward at constant speed, what is the reading on the
scale?
B) When the elevator is accelerating downward at 5 meters per second squared,
what is the reading on the scale?
C) If the elevator cables broke and the elevator fell freely, what would be the reading on
the scale?
A) The reading on the scale is 250 N.
B) The reading on the scale is 122.45 N.
C) The reading on the scale is 0 N.
Given parameters:
Weight of the box is : W = 250 N.
As the acceleration due to gravity is 9.8 m/s², the mass of the box be: m = W/g = 250/9.8 kg = 25.51 kg
A) When the elevator is moving upward at constant speed, there has no acceleration. the reading on the scale remains same and it be 250 N.
B) When the elevator is accelerating downward at 5 meters per second squared, the apparent weight of the box be, W₁ = W -ma = 250 -25.51×5 N = 122.45 N. So, the reading on the scale is 122.45 N.
C) If the elevator cables broke and the elevator fell freely, the elevator is accelerating downward at the same magnitude of acceleration due to gravity, so the apparent weight of the box be, W₁ = W -mg = 0. So, the reading on the scale is 0 N.
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A car moving with an initial velocity of 45 ms¹ is brought to a stop in 5 s. Find:
a) the deceleration of the car
b)the distance needed to stop the car
Answer:
a) -9 [tex]m/s^2[/tex]
b) 112.5 meters
Explanation:
Here is a formula for acceleration.
[tex]a=\frac{V_{f} -V_{o} }{t}[/tex]
We are given
[tex]V_o=45[/tex] m/s
[tex]V_f=0[/tex] m/s
[tex]t=5[/tex] s
Lets solve for [tex]a[/tex].
[tex]a=\frac{0-45}{5}[/tex]
[tex]a=\frac{-45}{5}[/tex]
[tex]a=-9[/tex] [tex]m/s^2[/tex]
Here is a formula for displacment.
[tex]x=V_o t+\frac{at^2}{2}[/tex]
[tex]V_o=45[/tex] m/s
[tex]t=5[/tex] s
[tex]a=-9[/tex] [tex]m/s^2[/tex]
Lets solve for [tex]x[/tex].
[tex]x=45*5+\frac{-9*5^2}{2}[/tex]
[tex]x=225+\frac{-9*25}{2}[/tex]
[tex]x=225+\frac{-225}{2}[/tex]
[tex]x=225+-112.5[/tex]
[tex]x=225-112.5[/tex]
[tex]x=112.5[/tex]
A hot air balloon weighs 3100kg. The hot air in the balloon creates an upward force of 30,000N. What is the magnitude AND direction of the acceleration of the air balloon?
The magnitude and direction of the acceleration of the air balloon, with a mass of 3100 kg and a force of 30000 N acting on it is 9.68 m/s² upward.
What is acceleration?Acceleration can be defined as the rate of change of velocity.
To calculate the magnitude and direction of the acceleration, we use the formula below.
Formula:
a = F/m............. Equation 1Where:
F = Upward forcem = Mass of the balloona = Acceleration of the ballonFrom the question,
Given:
F = 30000 Nm = 3100 kgSubstitute these values into equation 1
a = 30000/3100a = 9.68 m/s² upward.Hence, the magnitude and the acceleration of the air balloon is 9.68 m/s² upward.
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1. A child sits on a dock and notices that 8 wavelengths pass the end of the dock in 4 seconds. What is the
frequency of the waves passing the dock?.
2. What is the period of the waves in question 1?
Answer:
Explanation:
Given:
n = 8
t = 4 s
______
f - ?
T - ?
Frequency:
f = n /t = 8 / 4 = 2 Hz
Period:
T = 1 / f = 1 / 2 = 0.5 s
In the periodic table in the image below, which of the following atoms is
classified as a metalloid?
OA. Fluorine (F)
OB. Antimony (Sb)
OC. Cadmium (Cd)
OD. Radon (Rn)
Answer:
OB
Explanation:
Antimony is a chemical element with as symbol Sb and atomic number 51
While cycling, the athlete can go up to a maximum of 30 km/h. If his/her acceleration is 9 m/s2, then calculate the time the athlete takes to reach the maximum speed.
The time the athlete takes to reach the maximum speed will be 0.93 seconds
acceleration = change in speed / time
initial speed = 0
final speed = 30 km / h = 8.33 m/s
acceleration = 9 [tex]m/s^{2}[/tex]
acceleration = change in speed / time
time = change in speed / acceleration = 8.33 / 9 = 0.93 seconds
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6. A constant net force acts on a magnitude of all of the following quantities pertaining to
the body EXCEPT
(A) Acceleration
(B) Kinetic Energy
(C) Momentum
(D) Speed
(E) Velocity
An athlete at the gym holds a 4. 0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4. 0 kg.
τ=Fd
In this instance, it will
τ=Fballdball+Farmdcenter of mass
τ = 4*9.81*.7 + 4*9.81*.35 = 41.2
and both of our forces have a magnitude of 4g*cos(55), but they are located in different places.
τ = 4g*cos(55)*(.35+.7) = 23.6
The term "magnitude" refers to an object's greatest size and direction. Scalar and vector quantities both use magnitude as a common factor.
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Must two bodies of equal momentum be moving in the same direction?
Yes, if two bodies have the same momentum, the velocities of the two objects needs to be equal to be moving in the same direction.
What is momentum?Momentum is the product of mass and velocity of a body in motion. It is a vector quantity.
Two bodies of equal momentum can only move in the same direction if their velocities are equal. This is because both the velocity and the momentum are vector quantities. Momentum is the product of mass, which is a scalar quantity and the velocity, which is a vector.
In conclusion, for two objects to have the same momentum and for their directions to be the same, they need to have the same velocity.
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Yes, two bodies of equal momentum must be moving in the same direction.
What is momentum?We know that momentum is the product of the mass and the velocity of the object, In fact, momentum is a vector quantity and it should be clearly stated here that the direction of the momentum vector have to be the direction of the velocity vector.
With this said, when we say that two object have the same momentum we are essentially saying that the velocity vector of the two bodies have to pointing in the same direction. Once the direction is not the same, the momentum of the objects can not ever be the same!
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